Passing input value with array name in onchange to javascript - javascript

I have search everywhere and learn that input tag can have an array name attribute like writing name="mark_delete[ ]" as array PHP post by form. But what I'm struggling of is the javascript part (I only use simple javascript anyway) to work.
I have 3 input name: prize[ ], quantity[ ], total[ ];
I want the total get the prize times the quantity.
The prize is fixed
The quantity is where the user's input
The total is read only.
Using onchange in input tag with array name
The 2 code show below work successfully in PHP:
Sample code 1 (using foreach): *You may skip this code
<?php
//delete_account.php
session_start();
if (isset($_SESSION['login_user'])) {
include("dbconn.php");
if (isset($_POST['delete']) && $_POST['mark_delete'] > 0) {
$mark_delete = $_POST['mark_delete'];
foreach ($mark_delete as $x) {
$sql = "UPDATE account SET status = 0 WHERE id_number = '$x'"; //status change to 0 as inactive instead of deleting the row data
mysqli_query($conn, $sql);
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Delete Account</title>
</head>
<body>
<h1>Restaurant Management Information System</h1>
<h3>Mark the accounts that you want to delete and press the delete button...</h3>
<div>
<button>Menu</button>
<button>Add New Item</button>
<button>View Activity Log</button>
<button>Logout</button>
</div>
<div>
<form action="delete_account.php" method="post">
<?php
$sql = "SELECT * FROM account ORDER BY last_name, first_name";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
echo "<ol>";
while ($row = mysqli_fetch_assoc($result)) {
if ($row['status'] == 1) { //display account with status value of 1 as active
echo "<li>";
echo "<input type='checkbox' name='mark_delete[]' value='" . $row['id_number'] . "' />";
echo $row['last_name'] . ", " . $row['first_name'] . "</li>";
}
}
echo "</ol>";
}
else
echo "No account existed...";
?>
<input type="submit" name="delete" value="Delete" />
</form>
</div>
</body>
</html>
<?php
}
else {
header("Location: home.php");
exit();
}
mysqli_close($conn);
?>
Sample code 2 (using while / mysqli_fetch_assoc()): *You may skip this code
<?php
//items.php
session_start();
if (isset($_SESSION['login_user'])) {
include("dbconn.php");
if (isset($_POST['add_stocks'])) {
$amount_add = $_POST['amount_add'];
$sql = "SELECT item_id, stock FROM items";
$result = mysqli_query($conn, $sql);
if (!empty($amount_add)) {
$x = 0;
while ($row = mysqli_fetch_assoc($result)) {
if (is_int((int)$amount_add[$x])) {
$stock = $row['stock'] + $amount_add[$x];
$sql = "UPDATE items SET stock = '$stock' WHERE item_id = '$row[item_id]'";
mysqli_query($conn, $sql);
}
$x++;
}
}
}
else if (isset($_POST['add_new'])) {
$stock = $_POST['stock'];
if (empty($stock))
$stock = 0;
if (is_int((int)$stock)) {
$sql = "INSERT INTO items (item_name, prize, stock) VALUES ('$_POST[item_name]', '$_POST[prize]', '$stock')";
mysqli_query($conn, $sql);
}
}
else if (isset($_POST['item_delete'])) {
$item_delete = $_POST['item_delete'];
$x = 0;
while (!isset($item_delete[$x]))
$x++;
$sql = "DELETE FROM items WHERE item_id = '$item_delete[$x]'";
mysqli_query($conn, $sql);
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Add Items</title>
</head>
<body>
<h1>Restaurant Management Information System</h1>
<h3>Restock some items or add a new one...</h3>
<div>
<button>Menu</button>
<button>View Activity Log</button>
<button>Logout</button>
<button>Delete an Account</button>
</div>
<div>
<form action="items.php" method="post">
<div>
<input type="submit" name="add_stocks" value="Add Stocks" onclick="return confirm('Add new stock. Apply?')" />
</div>
<table border="1">
<?php
$sql = "SELECT * FROM items";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
?>
<tr>
<th>ID</th>
<th>Name</th>
<th>Prize</th>
<th>Stock</th>
<th>Add Stocks</th>
<th>Action</th>
</tr>
<?php
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $row['item_id'] . "</td>";
echo "<td>" . $row['item_name'] . "</td>";
echo "<td>" . $row['prize'] . "</td>";
echo "<td>" . $row['stock'] . "</td>";
echo "<td><input type='text' name='amount_add[]' /></td>";
echo "<td><button type='submit' name='item_delete[]' value='" . $row['item_id'] . "' onclick='return confirm(\"You are about to delete < " . $row['item_name'] . " >. Are you sure?\")' />Delete</button></td>";
echo "</tr>";
}
}
else {
echo "<tr>";
echo "<td>No item existed...</td>";
echo "</tr>";
}
?>
</table>
</form>
<form action="items.php" method="post" id="item_table">
<label>Item Name:</label>
<input type="text" name="item_name" placeholder="Name" required="required" />
<label>Item Prize</label>
<input type="text" name="prize" placeholder="Prize" required="required" />
<label>Stock</label>
<input type="text" name="stock" />
<input type="submit" name="add_new" value="Add New Item" onclick="return confirm('Add new item. Apply?')" />
</form>
</div>
</body>
</html>
<?php
}
else {
header("Location: home.php");
exit();
}
mysqli_close($conn);
?>
The 2 codes above works in PHP posting the < tagname name=" name[ ] >
Now the real code: Image (the Total Prize didn't display, why? Sorry, I'm not really good at javascript)
<?php
session_start();
if (isset($_SESSION['login_user'])) {
include("dbconn.php");
/*{
code here
}*/
?>
<!DOCTYPE html>
<html>
<head>
<title>Order</title>
</head>
<body>
<h1>Restaurant Management Information System</h1>
<h3>Choose an amount of items to stock for order...</h3>
<div>
<button>Add New Item</button>
<button>View Activity Log</button>
<button>Logout</button>
<button>Delete an Account</button>
</div>
<div>
<form action="order.php" method="post">
<table border="1">
<div>
<input type="submit" name="order_items" value="Order" onclick="return confirm('Confirm order?')" />
</div>
<?php
$sql = "SELECT * FROM items";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
?>
<tr>
<th>ID</th>
<th>Name</th>
<th>Prize</th>
<th>Stock</th>
<th>Order Qty</th>
<th>Total Prize</th>
</tr>
<?php
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $row['item_id'] . "</td>";
echo "<td>" . $row['item_name'] . "</td>";
echo "<td>" . $row['prize'] . "<input type='hidden' name='prize[]' value='" . $row['prize'] . "' /></td>";
echo "<td>" . $row['stock'] . "</td>";
echo "<td><input type='text' name='quantity[]' onchange='total_prize()' value='0' /></td>"; //not working!
echo "<td><input type='text' name='total[]' readonly /></td>";
echo "</tr>";
}
}
else
echo "No item to display...";
?>
</table>
</form>
<script>
int x = 0; //initialize var only once
function total_prize() { //this function will be call many times
document.getElementByName("total")[x].value = document.getElementByName("prize")[x].value * document.getElementByName("quantity")[x].value;
x++;
}
</script>
</div>
</body>
</html>
<?php
}
else {
header("Location: home.php");
exit();
}
mysqli_close($conn);
?>
Just focus on:
while ($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $row['item_id'] . "</td>";
echo "<td>" . $row['item_name'] . "</td>";
echo "<td>" . $row['prize'] . "<input type='hidden' name='prize[]' value='" . $row['prize'] . "' /></td>";
echo "<td>" . $row['stock'] . "</td>";
echo "<td><input type='text' name='quantity[]' onchange='total_prize()' value='0' /></td>"; //not working!
echo "<td><input type='text' name='total[]' readonly /></td>";
echo "</tr>";
...
<script>
int x = 0; //initialize var only once
function total_prize() { //this function will be call many times
document.getElementByName("total")[x].value = document.getElementByName("prize")[x].value * document.getElementByName("quantity")[x].value;
x++;
}
</script>
Thank you!

In your code, whenever a quantity[] is changed, it'll update only 1 item, means when you change the value on 4th quantity[](which is quantity[3]), it still get prize[0] and quantity[0]'s value, and then put the compute result to total[0], and if you now want to change that, you will end up change the value to total[1] and so on...
The problem is that you only want to change nth elements that you're currently playing with, but a static number x can't help you with that, as it only able to ref to 1 index, and it changes when function calls, it won't have a desired behavior.
Solution:
Give some index information to your total_prize function, like give it the current index.
function total_prize(index) {
var prize = document.getElementsByName('prize[]').item(index);
var quanity = document.getElementsByName('quanity[]').item(index);
var total = document.getElementsByName('total[]').item(index);
// If any of the dom element not exist, do nothing.
if (prize === null || quanity === null || total === null) {
return;
}
total.value = strToNumber(prize.value) * strToNumber(quanity.value);
}
function strToNumber(str) {
var num = parseInt(str, 10);
return isNaN(num) ? 0 : num;
}
<input type="hidden" name="prize[]" value="1"/>
<input type="hidden" name="prize[]" value="2"/>
<input type="hidden" name="prize[]" value="3"/>
<input type="hidden" name="prize[]" value="4"/>
Q1<input type="text" name="quanity[]" onchange="total_prize(0)"/><br/>
Q2<input type="text" name="quanity[]" onchange="total_prize(1)"/><br/>
Q3<input type="text" name="quanity[]" onchange="total_prize(2)"/><br/>
Q4<input type="text" name="quanity[]" onchange="total_prize(3)"/><br/>
T1<input type="text" name="total[]" /><br/>
T2<input type="text" name="total[]" /><br/>
T3<input type="text" name="total[]" /><br/>
T4<input type="text" name="total[]" /><br/>
Or use the same function without any given info, but loop through all elements and update all of their value each time the function is called.
function total_prize() {
var prizes = document.getElementsByName('prize[]');
var quanities = document.getElementsByName('quanity[]');
var totals = document.getElementsByName('total[]');
// Use the length that is shortest.
var length = Math.min(prizes.length, quanities.length, totals.length);
var index, price, quanity;
for (index = 0; index < length; index += 1) {
if (quanities[index].value.length === 0) {
totals[index].value = '';
} else {
price = strToNumber(prizes[index].value);
quanity = strToNumber(quanities[index].value);
totals[index].value = price * quanity;
}
}
}
function strToNumber(str) {
var num = parseInt(str, 10);
return isNaN(num) ? 0 : num;
}
<input type="hidden" name="prize[]" value="1"/>
<input type="hidden" name="prize[]" value="2"/>
<input type="hidden" name="prize[]" value="3"/>
<input type="hidden" name="prize[]" value="4"/>
Q1<input type="text" name="quanity[]" onchange="total_prize()"/><br/>
Q2<input type="text" name="quanity[]" onchange="total_prize()"/><br/>
Q3<input type="text" name="quanity[]" onchange="total_prize()"/><br/>
Q4<input type="text" name="quanity[]" onchange="total_prize()"/><br/>
T1<input type="text" name="total[]" /><br/>
T2<input type="text" name="total[]" /><br/>
T3<input type="text" name="total[]" /><br/>
T4<input type="text" name="total[]" /><br/>

Related

Trying to use JavaScript to calculate total booking price for selected seats using php pdo?

I am trying to use JavaScript to calculate total price for the tickets which are selected by using the checkbox. The result is should be shown in a alert window by clicking on the check button which invokes the JavaScript function. But when I click the button nothing happens. I don't even get any error message. I am a beginner so please if anyone can help me, I will be extremely thankful.
<?php foreach ($res as $row): ?>
<form action="book.php" method="get">
<tr><td><?php echo $row['RowNumber']; ?></td><td><?php echo $row['Price']; ?></td>
<td><input type="checkbox" type="hidden" name="myForm[<?php echo $row['RowNumber']; ?>][row]" id="row" value="<?php echo $row['RowNumber']; ?>"></input></td></tr>
<input type="hidden" name="myForm[<?php echo $row['RowNumber']; ?>][price]" id="price" value="<?php echo $row['Price']; ?>"></input>
</form>
<?php endforeach; ?>
</table>
<form action='book.php' method='get'>
Enter Email:<input type='text' name='name'></form>
<script>
function summary() {
var total = 0.0;
var seats = document.getElementById("row").value;
for(i = 1; i <= document.getElementById("row").value; i++) {
if(document.getElementId("row").checked) {
total = total + parseFloat(document.getElementById("price").innerHTML);
}
}
return total;
alert("Price of seats =" + total);
}
</script>
<input type="button" onclick="summary()" value="check">
<?php
You're returning before calling the alert, which means you never get to the alert itself. Remove the return total line.
This is a very common problem.All we have face atleast once.you should use Chrome istead of firefox or internet explorer.close your webpage and restart again.
return total should be after alertbox.
thankx.
You can try this sample
<form action="book.php" method="get">
<table>
<?php foreach ($res as $row): ?>
<tr data-rownumber="<?php echo $row['RowNumber']; ?>">
<td><?php echo $row['RowNumber']; ?></td>
<td><?php echo $row['Price']; ?></td>
<td>
<input type="checkbox" name="myForm[<?php echo $row['RowNumber']; ?>][row]" id="row-<?php echo $row['RowNumber']; ?>" value="<?php echo $row['RowNumber']; ?>" onclick="summary()" />
<input type="hidden" name="myForm[<?php echo $row['RowNumber']; ?>][price]" id="price-<?php echo $row['RowNumber']; ?>" value="<?php echo $row['Price']; ?>" />
</td>
</tr>
<?php endforeach; ?>
</table>
</form>
<form action='book.php' method='get'>
Enter Email:<input type='text' name='name'>
</form>
<script>
function summary() {
var total = 0.0;
var table = document.getElementById('items-table');
var rows = table.getElementsByTagName('tr');
for (var i = 0; i < rows.length; i++) {
var row = rows[i];
var rowNumber = row.getAttribute('data-rownumber');
var isChecked = document.getElementById('row-' + rowNumber).checked;
if (isChecked) {
var price = parseFloat(document.getElementById('price-' + rowNumber).value);
total += price;
}
}
alert("Price of seats = " + total);
return total;
}
</script>
<input type="button" onclick="summary()" value="check">

keep checkbox checked after submit using foreach loop?

My Code is:
<form method="POST" action="" style="margin-top: 30px;">
<div class="form-group" style="display: inline-block;">
<label for="Name" class="label-control" >Device Price</label>
<input type="text" name="price" class="form-control">
</div>
<div class="row" style="margin-bottom: 20px;">
<div class="col-md-3">
<?php
$r = 0;
$sql = "SELECT * FROM Subscribes ";
$result = $db->query($sql);
while ($row = $result->fetch_assoc()) {
if ($r == 5) {
echo "</div><div class='col-md-3'>";
$r = 0;
}
$r++;
$p = $row['price'];
echo "<label style='font-size: 16px; margin: 20px;'>";
echo "<input name='checkbox[]' type='checkbox' ";
echo "value=" . $p . " >" . $row['sub_name'];
if ($p == 0) {
echo "<label style='color:#f00'> Free </label>";
}
echo "</label>";
}
?>
</div>
</div>
<div class="row">
<div class="col-md-12">
<div class="form-group" style="margin-left: 35%;">
<button class="btn btn-info" name="sum" style="font-size: 24px;">TOTAL</button>
<label style="margin-left: 6%; font-size: 24px;">
<?php
if (isset($_POST['sum'])) {
$price = $_POST['price'];
$price = $price + $price * .52;
$total = $price;
if (!empty($_POST['checkbox'])) {
foreach ($_POST['checkbox'] as $value) {
$total = $total + $value;
}
}
echo $total;
}
?></label>
</div>
</div>
</div>
You can put a checked property to a checkbox:<input type="checkbox" checked>"
In your case, you have to check the POST data in the first block aswell and add the checked property to checkboxes that have been submitted.
echo "<input name='checkbox[]' type='checkbox' ";
echo "value=" . $p;
//if value is in the array of submitted checkboxes, add the checked property
if(array_search($p ,$_POST["checkbox"]) >= 0) echo "checked";
echo ">" . $row['sub_name'];
You can almost just check posted value to see if checked[$r] is on, but in the case where the user leaves some of the boxes unchecked, those don't get posted.
So, you need a way to identify each checkbox. You could do this by naming them like this when you echo them:
$id = $row['id']; // or whatever your id is
echo "<input name='checkbox[$id][]' type='checkbox' value=$p >"
Now, when the user submits the form, you know exactly which checkboxes should be checked. So you can simply add the checked attributed when you render them:
echo "<input name='checkbox[$id][]' type='checkbox' value=$p $checked>"
So altogether:
<?php
$r = 0;
$sql = "SELECT * FROM Subscribes ";
$result = $db->query($sql);
while ($row = $result->fetch_assoc()) {
if ($r == 5) {
echo "</div><div class='col-md-3'>";
$r = 0;
}
$r++;
$p = $row['price'];
$id = $row['id'];
$checked = null;
if(array_key_exists('checkbox', $_POST) && array_key_exists($id, $_POST['checkbox']){
$checked = "checked";
}
echo "<label style='font-size: 16px; margin: 20px;'>";
echo "<input name='checkbox[$id][]' type='checkbox' value=$p $checked>" . $row['sub_name'];
if ($p == 0) {
echo "<label style='color:#f00'> Free </label>";
}
echo "</label>";
}
?>

How to post the information using javascript for a preview table

Hey I need to know how to post the information to another php page using javascript to provide a preview table.
Here's my HTML that has a onchange tag that sends the productID to the function.
<form action="Home.php" method="Post">
<div>
<p>
<span class="text">Please Select a product:</span>
<select id="Select_Product" name="Select_Product" onchange="productInfo(this.value)" class="select">
<?php
//setting the select statement and running it
$search = "SELECT * FROM Library.Products order by Name";
$return = mysql_query($search);
//echo "<select id=Select_Product name=Select_Product onchange=productInfo(this.value) class=select>";
while ($row = mysql_fetch_array($return)) {
echo "<option value='" . $row['ProductID'] . "' selected='selected'>".$row['Name'] . "</option>";
}
?>
</select>
</p>
<table>
<tr>
<td>
<input name="action" type="submit"class="button" id="button_Add" value="Add"/>
</td>
<td>
<input name="action" type="submit" class="button" id="button_Remove" value="Remove"/>
</td>
<td>
<input name="action" type="submit" class="button" id="button_empty" value="Empty"/>
</td>
</tr>
</table>
</div>
From there I want it to send it to catalogue.php.
<script>
function productInfo(key) {
//Send key to catalogue.php
}
</script>
If I can get the other page to get that variable I can run a MYSQL command to get the information. Here is what catalogue.php looks like at the moment.
<?php
$sql = "SELECT Name, Price FROM Library.Products WHERE ProductID = " . $product_id;
echo "<table border=\"1\" padding=\"3\" width=\"650px\"><tr><th>Name</th><th>Description</th><th>Price</th><th width=\"80px\">Image</th></tr>";
echo "<tr>";
echo "<td>" .$product_id . "</td>";
echo "<td> Hi</td>";
echo "<td></td>";
echo "<td align=\"center\"><img alt=\"\" src=\"productImages/".$product_id.".jpg\ width=\"120\" height=\"120\"/></td>";
echo "</tr>";
echo "</table><br>";
document.
?>
So in a sense I want to turn the key in productInfo(key) to be assigned to the variable $product_id in catalogue.php. Thanks for helping.
You can add an invisible form :
<script>
function productInfo(key) {
//Send key to catalogue.php
document.getElementById( "key" ).value = key;
document.getElementById( "frm" ).submit(); // SUBMIT FORM.
}
</script>
<form action="catalogue.php" method="post" id="frm"
style="display:none" target="_blank">
<input type="text" id="key" name="key"/>
</form>
catalogue.php needs one little change :
<?php
$product_id = $_POST[ "key" ]; //<================== VALUE FROM THE INVISIBLE FORM.
$sql = "SELECT Name, Price FROM Library.Products WHERE ProductID = " . $product_id;
echo "<table border=\"1\" padding=\"3\" width=\"650px\"><tr><th>Name</th><th>Description</th><th>Price</th><th width=\"80px\">Image</th></tr>";
echo "<tr>";
echo "<td>" .$product_id . "</td>";
echo "<td> Hi</td>";
echo "<td></td>";
echo "<td align=\"center\"><img alt=\"\" src=\"productImages/".$product_id.".jpg\ width=\"120\" height=\"120\"/></td>";
echo "</tr>";
echo "</table><br>";
document.
?>
Or you can use Ajax :
html file
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type = "text/javascript">
function myAjax ( key ) {
$.ajax( { type : 'POST',
data : { 'param' : key },
url : 'catalogue.php',
success: function ( data ) {
document.getElementById( "my_div" ).innerHTML = data;
},
error: function ( data ) {
alert( "error" );
}
});
}
function productInfo( key ) {
//Send key to catalogue.php
myAjax( key );
}
</script>
</head>
<body>
<button onclick="productInfo('123')">Click here to get the data</button>
<div id="my_div">
- data will show here -
</div>
</body>
</html>
catalogue.php
<?php
$key = $_POST[ "param" ];
echo "<table border='1'>" .
" <tr>" .
" <td>$key</td>" .
" <td>ABC</td>" .
" </tr>" .
"</table>";
?>

Remove particular row by clicking remove link present in the same row

I have form 1st page(test.php) as follows
<form method="post" action="newtest.php">
<input name="product[]" type="checkbox" value="1" <?php if(in_array("1", $session_products)) echo "checked='checked'"; ?> alt="1607.00" />
<input name="product[]" type="checkbox" value="2" <?php if(in_array("2", $session_products)) echo "checked='checked'"; ?> alt="1848.00" />
<input name="product[]" type="checkbox" value="3" <?php if(in_array("3", $session_products)) echo "checked='checked'"; ?> alt="180.00" />
<input name="product[]" type="checkbox" value="4" <?php if(in_array("4", $session_products)) echo "checked='checked'"; ?> alt="650.00" />
<input name="product[]" type="checkbox" value="5" <?php if(in_array("5", $session_products)) echo "checked='checked'"; ?> alt="495.00" />
<div class="ph-float">
<input type="submit" name="button" value="Checkout >>" class="ph-button ph-btn-green fm-submit" disabled="true" >
</div>
</form>
Based on checkbox selection am displaying Book name,Amount and total in a table as follows(newtest.php)
(Remember am not using data base, these values are not comming from data base instad am taking these values from
product array as specified below)
<?php
$product = array();
$product[1] = array('name' => "Text Book of Human Anatomy by B.D.Chaurasiavol 6th edition Vol -I Vol-II Vol-III.", 'price' => 1607);
$product[2] = array('name' => "Nettars Atlas of Anatomy", 'price' => 1848);
$product[3] = array('name' => "Genera Anatomy by B.D.Chaurasia", 'price' => 180);
$product[4] = array('name' => "Inderbir Singh Embryology 10th edition ", 'price' => 650);
$product[5] = array('name' => "Inderbir Singh Histology ", 'price' => 495);
if(isset($_POST['button']))
{
$first = array();
$second = array();
foreach ($_POST['product'] as $pId)
{
$first[] = $product[$pId]['name'];
$second[] = $product[$pId]['price'];
}
$bookauthor = count($first);
$bookprice = count($second);
$max = ($bookauthor > $bookprice ? $bookauthor : $bookprice);
echo '<br />';
echo '<i style="font-color:#000000;font-weight:bold;text-decoration:underline;font-size:21px; padding-left:110px;margin-top:10px"> List of books you have selected:</i>';
echo '<table>';
echo '<tr>';
echo '<th style="text-align: center">SL No.</th>';
echo "<th>Book Name</th>";
echo "<th>Amount in INR</th>";
echo "<th>Action</th>";
echo '</tr>';
$count = 0;
for ($i = 0; $i < $max; $i++)
{
$count++;
echo '<tr>';
echo "<td style='text-align: center'>{$count}</td>";
echo "<td>{$first[$i]}</td>";
echo "<td>{$second[$i]}</td>";
echo "<td><a href='#'><i style='color:#F5F5F5;background:#D52020'>REMOVE</i> </a></td>";
echo '</tr>';
}
$total = array_sum($second);
echo '<tr>';
echo "<td colspan='2' style='font-weight:bold;font-size:14px'>Total Amount</td>";
echo "<td style='font-weight:bold;font-size:14px;'>{$total}</td>";
echo "</tr>";
echo '</table>';
}
?>
I want to remove particular row from table when i click on REMOVE link displaying in a same row, how to achive this?
link is ok or should i have to use button.If any one write some code may helpfull as am new webie...
Thanks in advance.
$('i').click(function(){
$(this).parent('a').parent('td').parent('tr').remove();
});
The row is deleted but as clicking makes you follow the link, it's immediately restored when the page is refreshed.
Add return false; or event.preventDefault(); at the end of the callback to prevent the default behavior :
$(document).ready(function() {
$("#favoriteFoodTable .deleteLink").on("click",function() {
var tr = $(this).closest('tr');
tr.css("background-color","#FF3700");
tr.fadeOut(400, function(){
tr.remove();
});
return false;
});
});

PHP not getting variables from jscript

I have trying to create a php cart and I have a table with a couple of products, when I click on the submit button some javascript is called and then the form is submitted.
When I execute the page and press the button I get a page "productcart.php?productid=1&command=add" and chrome says that there is an internal server error. I believe that there is a jscript or PHP error that is not letting the variables be pulled into the php code block. Can anyone see if there is something else I am doing wrong?
also what does the "?productid=1&command=add" mean? why does the browser return that?
<script type="text/javascript">
function addtocart(prod_id)
{
document.productform.productid.value = prod_id;
document.productform.command.value = 'add';
document.productform.submit();
}
</script>
<?php
include("local-connect.php");
include("productfunctions.php");
if($_REQUEST['command'] == 'add' && $_REQUEST['productid'] > 0)
{
$product_id = $_REQUEST['productid'];
add_to_cart($product_id, 1);
echo 'it worked';
//header("Location:cart.php");
exit();
}
?>
<form name="productform" action="">
<input type="hidden" name="productid" />
<input type="hidden" name="command" />
<table id="product_table">
<?php
$query = "SELECT * FROM products";
$result = mysqli_query($dbc,$query) or die ("Error querying database");
while($row = mysqli_fetch_array($result))
{
echo '<tr>
<td><img id="shopping_img" src="' .$row['image'] . '"/></td>
<td><p><strong>' . $row['name'] . '</strong></p>
<p>' . $row['descri'] . '</p>
<p>Price:<strong>$' . $row['price'] . '</strong></p></td>
<td><input type="button" value="Add to Cart" onclick="addtocart(' . $row['id'] . ')" /></td>
</tr>';
}
?>
</table>
</form>
This will fix the "?productid=1&command=add" in the URL and protect from code injection.
I added method="post" and used $_POST I also used intval() to insure an integer is sent to your function.
<script type="text/javascript">
function addtocart(prod_id)
{
document.productform.productid.value = prod_id;
document.productform.command.value = 'add';
document.productform.submit();
}
</script>
<?php
include("local-connect.php");
include("productfunctions.php");
if($_POST['command'] == 'add' && $_POST['productid'] > 0)
{
$product_id = intval($_POST['productid']);
add_to_cart($product_id, 1);
echo 'it worked';
//header("Location:cart.php");
exit();
}
?>
<form name="productform" action="" method="post">
<input type="hidden" name="productid" />
<input type="hidden" name="command" />
<table id="product_table">
<?php
$query = "SELECT * FROM products";
$result = mysqli_query($dbc,$query) or die ("Error querying database");
while($row = mysqli_fetch_array($result))
{
echo '<tr>
<td><img id="shopping_img" src="' .$row['image'] . '"/></td>
<td><p><strong>' . $row['name'] . '</strong></p>
<p>' . $row['descri'] . '</p>
<p>Price:<strong>$' . $row['price'] . '</strong></p></td>
<td><input type="button" value="Add to Cart" onclick="addtocart(' . $row['id'] . ')" /></td>
</tr>';
}
?>
</table>
</form>

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