$(document).ready(function () {
$("#livesearch").on("keyup",function(){
var search_term = $(this).val();
$.ajax({
url:"ajax-live-search.php",
type:"POST",
data: {livesearch:search_term},
success: function (data) {
$("#show-search").html(data);
}
});
});
});
My other Js files are not run on jquery ajax function i want to load my MAIN js file to this ajax function how to do it
There is no problem with the code. It is a jQuery code that is used to perform an AJAX call when the keyup event is triggered on an element with the ID of "livesearch". The AJAX call sends the value of the element to the "ajax-live-search.php" file and the response is then displayed in an element with the ID of "show-search".
Related
I have a normal button, which triggers a basic function that prints the value of an element in my HTML to the console.
Now, instead of printing the value of that element i want to send it to my Django view with a POST request.
Here is the function:
$(document).on('click','.btnClick', function() {
var myvalue = $(this).data("myid");
console.log(myvalue);
});
Here, instead of printing that value, i want to send myvalue with a post request using Ajax.
I know how to do a POST request, the only difference is that this time, instead of using a form, i'm using a single button to trigger the request, and i'm not really used to that.
Here is how i would do it with a form:
$(document).ready(function () {
$("#myform").submit(function (event) {
$.ajax({
type: "POST",
url: "/myurl/",
data: {
'myvalue': $('id').val()
},
});
return false;
});
});
So, basically i just need to know how to integrate this piece of code inside the first function, so that the Ajax call is triggered not by the form (as it is in the second code) but from a button.
Just put your jquery ajax function inside into the click event function.
$(document).on('click','.btnClick', function() {
var myvalue = $(this).data("myid");
$.ajax({
type: "POST",
url: "/myurl/",
data: {
'myvalue': myvalue
},
});
});
Hope this will help.
I need to load HTML in a div.
$("#content").load("content.html");
$("#myText").html("Prasath");
After that I need to update some text in a div(id='myText') which is available in "content.html". "content.html" contains huge data, so it takes some time to load. Before that this line is executed:
$("#myText").html("Prasath");
How to load HTML content synchronously from JavaScript/jQuery ?
I don't want to do this from call back option in load.
You can't load it synchronously but you can quite easily do the next task in the load() callback. For example:
$("#content").load("content.html", function() {
$("#myText").html("Prasath");
});
$("#content").load("content.html", function(data){
// this will execute after load is fired.
});
Use a callback.
EDIT: If you really want to make synchronous request, you can use the following code. However, you'll get a warning in console as I mentioned in the comment earlier:
var data = $.ajax({
type: "GET",
url: "content.html",
async: false
}).responseText;
// this code waits for the above ajax request.
Please have a look on the JQuery documentation about load().
You can pass callback function to load()
For example:
$("#content").load("content.html", function(){
$("#myText").html("Prasath");
});
EDIT: There is no way to make load() to load content synchronously. A workaround solution is that you can define a Jquery function that use ajax() to send synchronous request to target url and then set the response content to destinate div.
$(function(){
$.fn.extend({
syncLoad: function (url) {
var result = $.ajax({
url: url,
async: false,
type: "GET"
}).responseText;
$(this).html(result);
}
});
$("#content").syncLoad("/echo/js/?js=hello%20world!");
});
JS Fiddle: https://jsfiddle.net/1v8fmb8b/
I have a page with has a heading say :
<div class="something"><? some php code ?></div>
In that page I also have an ajax doing a job like:
<script>
$(document).ready(function () {
$(document).ajaxStart(function () {
$("#loader").show();
}).ajaxStop(function () {
$("#loader").hide();
});
});
$('#link').on('click', function(e) {
e.preventDefault;
var href = this.getAttribute('href');
$.ajax({
url: href,
success: function(text) {
alert("Added Succesfully");
}
});
return false;
});
</script>
Now in the success in ajax i also want to refresh the div i mentioned. Only refresh as it is attached to PHP which will fetch data from an external API. Is this possible ?
You could put your php code in an external file and reload your div by calling JQuery load method:
$("#something").load("mycode.php");
I hope it helps you.
link
$.ajax({
dataType: "json",
url: "http://www.omdbapi.com/?i=tt0111161",
success: function (data) {
console.log(data);
$("#movie-data").append(JSON.stringify(data));
With the append function you can insert the data from the ajax call into a div. explanation and example
The append() method inserts specified content at the end of the selected elements.
Tip: To insert content at the beginning of the selected elements, use the prepend() method.
Or maybe this answer can fix your issue
or you can take a look at the jquery load function
Load data from the server and place the returned HTML into the matched element.
This method is the simplest way to fetch data from the server. It is roughly equivalent to $.get(url, data, success) except that it is a method rather than global function and it has an implicit callback function. When a successful response is detected (i.e. when textStatus is "success" or "notmodified"), .load() sets the HTML contents of the matched element to the returned data.
Here's a question which has proved very difficult to find an answer online for.
Let's say a user runs an ajax function onclick to fill the contents of a div.
But, what if the ajax output is php, and for that onclick, i want other divs on the page to change in a manner that is dependent on the contents of div1?
This means I need to wait for div1 to actually change so i can use the ajax output of the php calculations to adjust div2 accordingly.
After some testing i've found out that i cant add a call to a second ajax function at the end of the first because it seems to run before the div content from the first ajax call actually changes.
So how can i trigger an ajax call onchange of the contents of a div?
All ajax calls take a callback to run when the call completes, put your logic in there.
You could use Jquery
$('#div1').change(function(){
doAjax( $(this).html() );
});
Or in the callback of the ajax
$.ajax({
url: 'http://yoururl.com',
type: 'post',
data: { key: value },
success: function( data ){
doAjax( data );
}
});
If you are aware of jquery, this is what you should try:
$.ajax({
traditional: true,
type: "post",
url: '<your_url>',
beforeSend: function () {
//your logic to perform operation before ajax request
},
data: {
//data to send
},
success: function(response) {
//your logic to perform operation after ajax request
//here make another ajax request
}
});
I have a jQuery ajax call that returns html of a table. Now I need to let user to do some javascript action on the table.
Can the return ajax response contain the javascript code or do I have to load the javascript code in the page on the first load of the page?
The user has the option of triggering the 'new' javascript. It doesn't have to triggered on ajax call.
To answer the actual question, the return response can contain the script. Simplest is to place it after the html, as the ready event has already fired in page it is being loaded into
You can use the success (or other event) callbacks provided with jQuery .ajax() to perform this JS action. Something like this:
$.ajax({
success: function(){
// Perform JS action
}
}
The jQuery API lists all such event callbacks available for AJAX calls. Check this for more info.
The returned ajax response can contain javascript code as a string. Then you can eval(response).
If you want to request a script with ajax that will be run when retrieved, then you can use jQuery's getScript() method to retrieve it and then execute it.
Per the jQuery doc, getScript() is a shorthand for:
$.ajax({
url: url,
dataType: "script",
success: success
});
Which shows that jQuery's ajax command will handle a returned script for you automatically if you set the data type appropriately.
You can make your request a variable and extend upon it after the set up.
// Make the request to the server
var dataID = $("#WhatINeedForAParameter").val();
var request = $.ajax({
url: "PageOrControllerOrWebApi/MethodName",
type: "POST",
data: { id : dataID },
dataType: "json"
});
// When the request is done process
// what you need done
request.done(function(msg) {
alert('You got this ' + msg);
});
// If the request failed you can
// see what the problem was and
// handle the situation accordingly
request.fail(function(jqXHR, textStatus) {
alert( "Your request failed: " + textStatus );
});
you can do it using success callback i think this can be a way please try
$.ajax({
.....,
.....,
success:
var script = document.createElement( 'script' );
script.type = 'text/javascript';
script.src = url;
$("#tableID").append( script );
});
i hope it should help.