I'm not super great a javascript yet and I'm mostly a front end person. I am trying to have people's submissions be randomized across the screen but not entirely sure how to (it's okay if it wipes away everything with the refresh of the page). I have this so far:
<script>
function myFunction() {
var x = document.getElementById("myText").value;
document.getElementById("demo").innerHTML = x;
}
</script>
Which gives me an option where someone submits something and it appears on the bottom but I'm trying to have each response randomize somewhere on the screen.
I have the input displayed beneath the textbox but can't figure out how to have multiple answers show and then randomize across the screen.
Create multiple elements where you display the responses, then select one of them randomly when you're displaying.
function myFunction() {
var x = document.getElementById("myText").value;
let divs = document.querySelectorAll(".demo");
let chosen = divs[Math.floor(Math.random() * divs.length)];
chosen.innerText = x;
}
.demo {
height: 20px;
}
<input id="myText"> <button onclick="myFunction()">Enter</button>
<div class="demo"></div>
<div class="demo"></div>
<div class="demo"></div>
<div class="demo"></div>
<div class="demo"></div>
<div class="demo"></div>
<div class="demo"></div>
Related
i want my popup (when a button is clicked) to show a random image out of my folder each time i click the button. I used html, css and javascript for my website.
The problem: it is the same random image each time. Only if i restart the page a different random image is showed.
What works right now: when i click the start-button a popup with a random image from that folder shows up (just how i want it) but if i click the close-button on my random picture and press the start-button again the same picture pops up again. Only if i restart my page then a new random picture will show when i press the start-button. But that picture stays the same, when i close the popup and want to start it again.
I want a random image everytime when i press the start-button without having to restart the page.
Do i use a boolean in javascript? Can i restart the function on its own? I have seen similar questions all the time but none of the solutions have worked for me kinda.
(the start-button is also a picture but it is a button) Sorry if the code is weirdly formatted, i am new to code <3
Thank you!!
My code:
HTML:
<div class="popup" id="popup-1">
<div class="overlay"> </div>
<div class="content">
<img class="imagelook"/> <!-- image is start-button -->
<div
class="close-btn"
onclick="togglePopup()"
onclick="generateRandomPicture(array)">× <!-- random image from folder -->
</div>
</div>
</div>
<body>
<button type="button" onclick="togglePopup()" class="imglook"></button> <!-- the start-button -->
</body>
Javascript:
function togglePopup(){
document.getElementById("popup-1").classList.toggle("active");
}
const imageArray =[
"zettel/9.png",
"zettel/8.png",
"zettel/10.png",
"zettel/11.png",
"zettel/12.png",
"zettel/13.png"
];
const image = document.querySelector("img");
window.onload = () => generateRandomPicture(imageArray);
function generateRandomPicture(array){
let randomNum = Math.floor(Math.random() * imageArray.length);
image.setAttribute("src", imageArray[randomNum]);
}
Perhaps the following might help - coded to allow for multiple popup elements in conjunction with multiple button elements to trigger the display of different images in the respective popup div
const images = [
"zettel/9.png",
"zettel/8.png",
"zettel/10.png",
"zettel/11.png",
"zettel/12.png",
"zettel/13.png"
];
const _CN='active';
const bttnclickhandler=function(e){
// generate random image based upon array
let imgsrc=images[mt_rand(0,images.length-1)];
// assign image the new src
this.previousElementSibling.querySelector('img').src=imgsrc;
this.previousElementSibling.classList.add(_CN);
console.info(imgsrc)
};
const closeclickhandler=function(e){
e.target.closest('.popup').classList.remove(_CN);
this.previousElementSibling.src='';
console.clear();
};
// generate a random number between a & b
const mt_rand=(a,b)=>Math.floor( Math.random() * ( b - a + 1 ) + a );
// assign listeners to all pertinent elements
document.querySelectorAll('button.imglook').forEach(n=>n.addEventListener('click',bttnclickhandler));
document.querySelectorAll('div.close-btn').forEach(n=>n.addEventListener('click',closeclickhandler));
document.querySelectorAll('div.popup').forEach(n=>{
n.querySelector('img').src=images[mt_rand(0,images.length-1)]
})
.active{background:pink}
.popup{margin:1rem;}
.imglook{padding:1rem}
<div class="popup">
<div class="overlay"></div>
<div class="content">
<img class="imagelook" />
<div class="close-btn">×</div>
</div>
</div>
<button type="button" class="imglook"></button>
<div class="popup">
<div class="overlay"></div>
<div class="content">
<img class="imagelook" />
<div class="close-btn">×</div>
</div>
</div>
<button type="button" class="imglook"></button>
I don't really know how to name this problem.
I made a simple code where clicking a button results in displaying a random number on screen. But I've run into an issue that every time you display the number then the button "locks" itself and you need to reload the page to click it again.
My problem is I don't want to reload everytime I click the button.
<div class="box" id="box">
<p id="p1">Generate a number</p>
<p id="p2"> <script src="main.js"></script></p>
<div class="container">
<button id="genbutton" class="button" onclick="generator()">Generate</button>
</div>
</div>
function generator() {
document.getElementById("p2").innerHTML = x;
document.write.innerHTML(x);
}
codepen demo
This is because you're only generating x (the random number) once. In your codepen example, move the generation of x into the event handler:
function generator() {
var x = Math.floor(Math.random() * 1001);
document.getElementById("p2").innerHTML = x;
}
I want to create a basic page in html that displays a single image.
I also added two buttons Previous and Next. These buttons should allow the user to move forward or backward. Have 6 images in total. When the user reaches the end (or beginning when clicking on the back button) of the slide show, the slide show should not wrap around to the beginning (or end).
button onclick function for both the cases is not working. Its only getting displayed the first image as what mentioned in the img src attribute.
This is what I have done so far. I put all the images into an array and try to travel the array forward and backward side based on the button click.
<body>
<img src="img1.jpg" id="demo" style="width:400px;height:600px"/img>
<br/>
<input type="button" onclick="preImage()" value="Previous
">
<input type="button" onclick = "nextImage()" value="Next
">
<script>
var slider_content = document.getElementById("demo");
var image = ['img1','img2','img3','img4','img5','img6'];
var i = image.length;
function nextImage(){
if(i<image.length){
i=i+1;
}else{
i=1;
}
slider_content.innerHTML="<img src="+image[i-1]+".jpg>";
}
function preImage(){
if(i<image.length+1 && i>1){
i=i-1;
}else{
i=image.length;
}
slide_content.innerHTML = "<img src="+image[i-1]+".jpg">
}
</script>
</body>
Create a wrapper div to your image and change the innerHTML of the div.
<div id="demo" style="width:400px;height:600px">
<img src="img1.jpg">
</div>
An error needs to be corrected in the preImage function:
slide_content.innerHTML = "<img src="+image[i-1]+".jpg">
to
slider_content.innerHTML = "<img src="+image[i-1]+".jpg>";
and also what Daniel said.
I'm trying to hide a part of every user email, registered in a website.
So lets say I have get zero#example.com and I want to hide everything after the "#". And only show it if someone clicks on whats left of the email.
Any help would be appreciated.
This just hides everything.
<p>
<button onclick=".hide('#email')">Hide</button>
<button onclick=".show('#email')">Show</button>
</p>
<div id="email">
<h2>zero#example.com<h2>
</div>
Try following:
<script type="text/javascript">
function show(){
document.getElementById('trail').style.display = 'inline';
}
function hide(){
document.getElementById('trail').style.display = 'none';
}
</script>
<p>
<button onclick="hide()">Hide</button>
<button onclick="show()">Show</button>
</p>
<div id="email">
<h2>zero<span id="trail">#something.com</span></h2>
</div>
You can use split ( => https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split ) if you know what character to expect. In this case:
var full; // let's say, it already has a value (f.e. zero#something.com)
var visiblePart = full.split("#")[0];
and eventually you can do something like this on click:
function show(){
document.getElementById("emailH2").innerHTML = full;
}
function hide(){
document.getElementById("emailH2").innerHTML = visiblePart;
}
and
<h2 id = "emailH2">zero#something.com<h2>
I've got 3 images in the screen. Each image should display a different form in the SAME POSITION in the screen and hide the other 2 forms.
Image1: When clicked show form1 and hide form2 and form 3
Image2: When clicked show form2 and hide form1 and form 3
Image3: When clicked show form3 and hide form1 and form 2
Forms should be shown at the same position. I just see a solution calling the whole page by sending a parameter in the URL stating which form to show on the screen. I would really like to show the right form depending on what image is clicked at the moment without that.
I'm using HTML5, Bootstrap 4 and JavaScript - any suggestion using any of these languages would be perfect.
There are a lot of answers to things like this, try looking around before asking a question.
Here is one of the simplest approaches you will ever see using only JS and HTML
JavaScript
const imageOne = document.getElementById('imageOne');
const imageTwo = document.getElementById('imageTwo');
const imageThree = document.getElementById('imageThree');
const formOne = document.getElementById('formOne');
const formTwo = document.getElementById('formTwo');
const formThree = document.getElementById('formThree');
imageOne.addEventListener("click", function() {
formOne.style.display = "block";
formTwo.style.display = "none";
formThree.style.display = "none";
});
imageTwo.addEventListener("click", function() {
formOne.style.display = "none";
formTwo.style.display = "block";
formThree.style.display = "none";
});
imageThree.addEventListener("click", function() {
formOne.style.display = "none";
formTwo.style.display = "none";
formThree.style.display = "block;
});
HTML
<img id="imageOne" src="http://foo.bar">
<img id="imageTwo" src="http://bar.foo">
<img id="imageThree" src="http://last.image">
<div id="formOne" style="display: none">
<form>
....
</form>
</div>
<div id="formTwo" style="display: none">
<form>
....
</form>
</div>
<div id="formThree" style="display: none">
<form>
....
</form>
</div>
Ok, you need:
the 3 images
the 3 forms, with position absolute or fixed (so that they stay in the same position)
a JS function attached to the click event of every image that changes the correspondet form style to display:block and the others to display:none.
Something like:
var form1 = document.getElementById('form1')
document.getElementById('form1').onclick = function() {
form1.style.display = 'block'
form2.style.display = 'none'
form3.style.display = 'none'
}
For each one of your forms.
Here is a working pen I made to show how to do it.
https://codepen.io/jaimelopez18/pen/zWOEMw
This is all made with pure js (vanilla). You should try to learn this first and after you get a good grasp of it, I recommend taking a look at VueJS.
I just made a simple skeleton in jsFiddle as per your requirements, have a look at the code.
HTML:
<html>
<head>
<script type='text/javascript' src="jquery.min.js"></script>
</head>
<body>
<div class="jsImgWrp">
<img src="http://via.placeholder.com/350x150" class="jsImg" data-formid="form1" />
<img src="http://via.placeholder.com/350x150" class="jsImg" data-formid="form2"/>
<img src="http://via.placeholder.com/350x150" class="jsImg" data-formid="form3" />
</div>
<div class="jsFormWrp form-wrapper">
<div class="jsFrm form1 active">
form 1
</div>
<div class="jsFrm form2">
form 2
</div>
<div class="jsFrm form3">
form 3
</div>
</div>
</body>
</html>
CSS:
.form-wrapper .jsFrm {
display:none;
padding:10px;
border:solid 2px #eee;
width:200px;
height:100px;
}
.form-wrapper .jsFrm.active {
display:block;
}
.jsImgWrp img {
width:100px;
display:inline-block;
}
Javascript:
$(document).ready(function(){
var imgWrapper = $('.jsImgWrp');
var formWrapper = $('.jsFormWrp');
$('.jsImg', imgWrapper).on('click', function(){
var formId = $(this).data('formid');
$('.jsFrm').removeClass('active');
$('.' + formId).addClass('active');
})
});
Hope this may help you.