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I don't know how to do this question
Given an array of numbers, it is necessary to cyclically shift the elements of the array to the right
Example 1:
Input: [1,2,3,4,5,6,7], k = 3
Output: [5,6,7,1,2,3,4]
Explanation:
Shift 1 step to the right: [7,1,2,3,4,5,6]
Shift 2 steps to the right: [6,7,1,2,3,4,5]
Shift 3 steps to the right: [5,6,7,1,2,3,4]
Example 2:
Input: [-1, -100,3,99], k = 2
Output: [3.99, -1, -100]
Explanation:
Shift 1 step to the right: [99, -1, -100.3]
Shift 2 steps to the right: [3.99, -1, -100]
I must write for this function
function rotate(nums, k){
}
Use pop() and unshift() methods
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Assume if I am adding multiple filters and giving user to make the conditions between applied filters
If I added 2 filters
Then input box must validate 1 AND 2
There is always And between 1 & 2.
If there are multiple filters
Then it will be like
1 and 2 and 3 and 4 so on...
1 and 2 and (3 or 4 or 5 so on....)
1 and 2 and (3 or 4) and 5 so on.....
`
Var regex = /^((0-9){1,}(AND|OR)\s)a*/gi;
Var regex2 = /^\d+(( (and|or) )?\d+|((\d+|(( and| or) )\d+)))( (and|or) \d+|((\d+|(( and| or) )\d+)))*$/;
Var regex3 = /^(\d+(and\d+)+)$|^(\d+(or\d+)+)$|and(and\dor)/gi;
`
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I have a need to split a string in javascript to individual components. Let me go through the example of the requirement I'm having.
This is the string I'm having:
"[InsertDelta, position: 63, lines: [return {]]"
I need to split the above string into three components as below:
InsertDela
position: 63
lines: [return {]
Is there any way to separate the strings like this in javascript?
You can use split to split the string at "," and then use for each to iterate through the items.
let y = "[InsertDelta, position: 63, lines: [return {]]";
let x = y.split(",");
x.forEach(item => console.log(item.replace(/\[?\]?/g, "")));
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I need an easy solution, in javascript, to remove thousands from an integer
for example:
29492 => 20492
1024 => 24
12345 => 10345
How could i do this easily ? the shorter/clearer the better
Even if I agree with Get Off My Lawn, you could have a solution that wok for both, with simple use of modulo.
x = x - (x%10000) + (x%1000)
//29492 => 29492 - 9492 + 492
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i have a number limit i.e. 000 now i want to increment it by 1 so the next limit will be '001' but when i try to add it gives me '1',
also if somehow i figure out to maintain it '001', the second problem is after '009' there should be '010'. Advance Thanks for you efforts.
Thats padding.
function pad(num, size) {
var s = "000" + num;
return s.substr(s.length-size);
}
Assuming you'll never need more than 3 digits
[Edit] - For those who like early technology i.e ES7
There is a new method called padStart()
padStart - The padStart() method pads the current string with another string (multiple times, if needed) until the resulting string reaches the given length. The padding is applied from the start (left) of the current string.
Example 1
const digits = 3
digits.toString().padStart(3, '0') // prints 003
Example 2
const digits = 76
digits.toString().padStart(3, '0') // prints 076
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Say I have a String
Thi__(1)__s i__(2)__s a test__(5)__ mess__(4)__age __(6)__
I want to replace the numbers in between the pattern __()__ by that number-1, that is, 2 with 1, 3 with 2 and so on. And there is a condition, that number should be greater than 3.
So my final string will look like
Thi__(1)__s i__(2)__s a test__(4)__ mess__(3)__age __(5)__
I know how to make a logic for that but as I am new to Javascript/Jquery I am looking for a better way.
Any help would be appreciated.
var str = "Thi__(1)__s i__(2)__s a test__(5)__ mess__(4)__age __(6)__";
var replaced = str.replace(/(__\()(\d+)(\)__)/g, function(_, left, val, right){ //replace all (digits)
val = +val; //convert to number
return left + (val > 3 ? --val: val) + right; //use whatever convert logic you need
});