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What if we do not wait for an asynchronous javascript function?

What if we do not wait for an asynchronous javascript function?
As far as I know some languages like C # should not run an asynchronous function unmanaged!
I wanted to know if this is also true for the JavaScript language?
var asynchronousFunction = async function() {
//...
}
function main() {
var result = true;
//...
asynchronousFunction(); // The result of this function has no effect on our output (result)
//...
return result;
}

It's run just the same. (In fact, you never await a function, you await for the the Promise it returns.)
The asynchronous function is run synchronously until the first await or return within it, at which point a Promise is returned to the caller and the rest of the function is arranged to run later.
It's up to the caller to do something (or nothing) to the Promise. After all, you might wish to store the promise in an array and await for the lot of them (Promise.all) or do something more esoteric about it, so JavaScript itself doesn't care.
Some smart enough IDEs and linters are able to raise a warning about unhandled promises, though, especially if you have enough type information to do so (e.g. by using TypeScript).

It's true for javascript as well.
You don't want to just create a promise and leave it totally hanging, if there are errors then they become unhandled errors and if it exits unexpectedly then you have no way of knowing that.
What I recommend is using the Promise.race at the top level and then it will run all of your async functions in parallel but will exit if any one of them exits unexpectedly.
async function worker() {
while (true) {
// do background work in a loop
}
}
async function server() {
await init()
await listen()
}
function main() {
const p0 = worker()
const p1 = server()
try {
await Promise.race([p0, p1])
console.log('done')
return true
} catch (err) {
console.log('The server had an error unexpectedly', err)
return false
}
}
If you expect the promises to eventually exit gracefully then use Promise.all instead, which will wait until all promises exit successfully before resolving.

Why is try {} .. catch() not working with async/await function?

const errorTest = async() => {
const result = await $.get("http://dataa.fixer.io/api/latest?access_key=9790286e305d82fbde77cc1948cf847c&format=1");
return result;
}
try {
errorTest()
}
catch(err) {
console.log("OUTSIDE ERROR!" + err)
}
The URL is intentionally incorrect to throw an error, but the outside catch() it not capturing it. Why?
If I use then() and catch() instead, it works.
errorTest()
.then(val=> console.log(val))
.catch(err=> console.error("ERROR OCCURRED"))
This works, but the try {..} catch() doesn't. Why?
I keep getting the Uncaught (in promise) error.

async function errorTest() { /* ... */ }
try {
errorTest()
}
catch(err) {
console.log("OUTSIDE ERROR!" + err)
}
Because errorTest is async, it will always return a promise and it is never guaranteed to finish execution before the next statement begins: it is asynchronous. errorTest returns, and you exit the try block, very likely before errorTest is fully run. Therefore, your catch block will never fire, because nothing in errorTest would synchronously throw an exception.
Promise rejection and exceptions are two different channels of failure: promise rejection is asynchronous, and exceptions are synchronous. async will kindly convert synchronous exceptions (throw) to asynchronous exceptions (promise rejection), but otherwise these are two entirely different systems.
(I'd previously written that async functions do not begin to run immediately, which was my mistake: As on MDN, async functions do start to run immediately but pause at the first await point, but their thrown errors are converted to promise rejections even if they do happen immediately.)
function errorTest() {
return new Promise(/* ... */); // nothing throws!
}
function errorTestSynchronous() {
throw new Error(/* ... */); // always throws synchronously
}
function errorTestMixed() {
// throws synchronously 50% of the time, rejects 50% of the time,
// and annoys developers 100% of the time
if (Math.random() < 0.5) throw new Error();
return new Promise((resolve, reject) => { reject(); });
}
Here you can see various forms of throwing. The first, errorTest, is exactly equivalent to yours: an async function works as though you've refactored your code into a new Promise. The second, errorTestSynchronous, throws synchronously: it would trigger your catch block, but because it's synchronous, you've lost your chance to react to other asynchronous actions like your $.get call. Finally, errorTestMixed can fail both ways: It can throw, or it can reject the promise.
Since all synchronous errors can be made asynchronous, and all asynchronous code should have .catch() promise chaining for errors anyway, it's rare to need both types of error in the same function and it is usually better style to always use asynchronous errors for async or Promise-returning functions—even if those come via a throw statement in an async function.
As in Ayotunde Ajayi's answer, you can solve this by using await to convert your asynchronous error to appear synchronously, since await will unwrap a Promise failure back into a thrown exception:
// within an async function
try {
await errorTest()
}
catch(err) {
console.log("OUTSIDE ERROR!" + err)
}
But behind the scenes, it will appear exactly as you suggested in your question:
errorTest()
.then(val=> console.log(val))
.catch(err=> console.error("ERROR OCCURRED"))

You need to await errorTest
const callFunction=async()=>{
try{
const result = await errorTest()
}catch(err){
console.log(err)
}
}
callFunction ()
Note that the await errorTest() function has to also be in an async function. That's why I put it inside callFunction ()
Another Option
const errorTest = async() => {
try{
const result = await $.get("http://dataa.fixer.io/api/latest?access_key=9790286e305d82fbde77cc1948cf847c&format=1");
console.log(result)
}catch(err){
console.log(err)
}
}

I think the fundamental misunderstanding here is how the event loop works. Because javascript is single threaded and non-blocking, any asynchronous code is taken out of the normal flow of execution. So your code will call errorTest, and because the call to $.get performs a blocking operation (trying to make a network request) the runtime will skip errorTest (unless you await it, as the other answers have mentioned) and continue executing.
That means the runtime will immediately jump back up to your try/catch, consider no exceptions to have been thrown, and then continue executing statements which come after your try/catch (if any).
Once all your user code has ran and the call stack is empty, the event loop will check if there are any callbacks that need to be ran in the event queue (see diagram below). Chaining .then on your async code is equivalent to defining a callback. If the blocking operation to $.get completed successfully, it would have put your callback in the event queue with the result of errorTest() to be executed.
If, however, it didn't run successfully (it threw an exception), that exception would bubble up, as all exceptions do until they're caught. If you have defined a .catch, that would be a callback to handle the exception and that'll get placed on the event queue to run. If you did not, the exception bubbles up to the event loop itself and results in the error you saw (Uncaught (in promise) error) -- because the exception was never caught.
Remember, your try/catch has long since finished executing and that function doesn't exist anymore as far as the runtime is concerned, so it can't help you handle that exception.
Now if you add an await before errorTest() the runtime doesn't execute any of your other code until $.get completes. In that case your function is still around to catch the exception, which is why it works. But you can only call await in functions themselves that are prefixed with async, which is what the other commenters are indicating.
Diagram is from https://www.educative.io/answers/what-is-an-event-loop-in-javascript. Recommend you check it out as well as https://www.digitalocean.com/community/tutorials/understanding-the-event-loop-callbacks-promises-and-async-await-in-javascript to improve your understanding of these concepts.

Is it safe to omit await to let a method run in parallel? [duplicate]

I would like to run this code with babel:
redisClientAsync.delAsync('key');
return await someOtherAsyncFunction();
inside an async function without await the first line. is this OK?
how else can I run something that I don't care?
Can I just fire the non-promisified function del('key',null) without a callback?

Yes, you can do that, and it will run the two asynchronous functions in parallel. You've just created a promise and thrown it away.
However, this means that when the promise is rejected you won't notice. You'll just get an unhandledRejection eventually which will crash your process if not handled.
Is this OK? How can I run something that I don't care?
Probably it's not OK. If you truly wouldn't care, you hadn't run it in the first place. So you should be clear and explicit what you care about (and what not):
do you want to wait? (for side effects)
do you need the result?
do you want to catch exceptions?
If you only want to wait and don't care for the result value, you can easily throw away the result:
void (await someAsyncFunction()); // or omit the void keyword,
// doesn't make a difference in an expression statement
If you don't care about exceptions, you can ignore them using
… someAsyncFunction().catch(function ignore() {}) …
You can throw that away, await it, do anything with it.
If you want the result, you have to await it. If you care about exceptions, but don't really want to wait, you may want to execute it in parallel with the following functions:
var [_, res] = await Promise.all([
someAsyncFunction(), // result is ignored, exceptions aren't
someOtherAsyncFunction()
]);
return res;

inside an async function without await the first line. is this OK?
Yes, there are cases where you'd want to do this which are perfectly reasonable. Especially where you don't care about the result - one example is an analytics tracking operation that should not interfere with business critical code.
how else can I run something that I don't care?
In many ways, however simply calling the promise function works. Your del without a callback would probably work in this case but some functions don't guard against not passing callbacks, so you can pass an empty function instead (.del('key', () => {})).
You do want to however make sure that you know about it failing, even if you don't want to disrupt the operation of code - so please consider adding a process.on("unhandledRejection', event handler to explicitly ignore these particular exceptions or suppress them via:
redisClient.delAsync('key').catch(()=>{});
Or preferably, something like:
redisClient.delAsync('key').catch(logErr);

From all the research I've made so far, I think it's fine to do it, as long as you guarantee that the function you are not awaiting for guarantees a way to handle its own errors in case that happens. For example, a try-catch wrapping the whole function body, like you see in the following snippet for the asyncFunction.
It doesn't matter if the function throws synchronously or asynchronously. It guarantees the your mainFunction will complete no matter what. That's the key point here.
If you don't guarantee that, you have to risks:
If it throws synchronously, your main function will not complete.
If it throws asynchronously, you'll get an unhandled excepction
// THIS IS SOME API CALL YOU DON'T WANT TO WAIT FOR
const mockAPI = () => {
console.log("From mockAPI");
return new Promise((resolve,reject) => {
setTimeout(() => reject("LATE THROW: API ERROR"), 500);
});
};
// THIS IS THE SOME ASYNC FUNCTION YOU CALL BUT NOT AWAIT FOR
const asyncFunction = async (syncThrow) => {
try {
console.log("Async function START");
if (syncThrow) throw new Error("EARLY THROW");
await mockAPI();
console.log("Async function DONE");
}
catch(err) {
console.log("From async function catch");
console.log(err.message || err);
return;
}
};
// THIS IS YOUR MAIN FUNCTION
const mainFunction = async (syncThrow) => {
try {
console.clear();
console.log("Main function START");
asyncFunction(syncThrow);
console.log("Main function DONE <<< THAT'S THE IMPORTANT PART");
}
catch(err) {
console.log("THIS WILL NEVER HAPPEN");
console.log(err);
}
};
<div>
<button onClick="mainFunction(true)">Sync throw</button>
<button onClick="mainFunction(false)">Async throw</button>
</div>

Not in Node.js.
Node does not wait for ever-pending Promises. If other tasks are already completed and there is nothing left in the event loop, the Node process will be terminated even though there exists pending promise.
For the following script, if someOtherAsyncFunction() get resolved in 5 seconds, but redisClientAsync.delAsync('key') takes 10 seconds to execute, the Node process will be terminated after 5 seconds in theory, before the first line is resolved.
async function doSomething() {
redisClientAsync.delAsync('key');
return await someOtherAsyncFunction();
}
await doSomething();

Firing Vuex actions asynchronously and sequentially - what am I not understanding?

I have a Vuex store and I am trying to fetch data from the Firebase Realtime Database. I am initially fetching the user information, however afterwards I would like to fetch some other information that relies upon the initial data fetched.
As you can see from the code, I am trying to do this using async / await, however whenever firing the two actions in my created() hook, the user's information isn't initialised, and therefore the second action fails.
My user store
async fetchCreds({ commit }) {
try {
firebase.auth().onAuthStateChanged(async function(user) {
const { uid } = user
const userDoc = await users.doc(uid).get()
return commit('SET_USER', userDoc.data())
})
} catch (error) {
console.log(error)
commit('SET_USER', {})
}
}
My club action which relies upon the above call
async fetchClubInformation({ commit, rootState }) {
try {
const clubIDForLoggedInUser = rootState.user.clubId
const clubDoc = await clubs.doc(clubIDForLoggedInUser).get()
return commit('SET_CLUB_INFO', clubDoc.data())
} catch (error) {
console.log(error)
}
}
}
The methods being called within my component's created() method.
created: async function() {
await this.fetchCreds();
await this.fetchClubInformation();
this.loading = false;
}
I have a feeling I'm fundamentally misunderstanding async / await, but I can't understand what in the code is incorrect - any help or advice would be greatly appreciated.

I'm not particularly familiar with Firebase but after a bit of digging through the source code I think I can shed a little light on your problems.
Firstly, consider the following example:
async function myFn (obj) {
obj.method(function () {
console.log('here 1')
})
console.log('here 2')
}
await myFn(x)
console.log('here 3')
Question: What order will you see the log messages?
Well here 2 will definitely come before here 3 but it's impossible to tell from the code above when here 1 will show up. It depends on what obj.method does with the function it's been passed. It might never call it at all. It might call it synchronously (e.g. Array's forEach method), in which case here 1 will appear before the other messages. If it's asynchronous (e.g. timers, server calls) then here 1 may not show up for some time, long after here 3.
The async modifier will implicitly return a Promise from the function if it doesn't return a Promise itself. The resolved value of that Promise will be the value returned from the function and the Promise will resolve at the point the function returns. For a function without a return at the end that's equivalent to it finishing with return undefined.
So, to stress the key point, the Promise returned by an async function will only wait until that function returns.
The method onAuthStateChanged calls its callback asynchronously, so the code in that callback won't run until after the surrounding function has completed. There's nothing to tell the implicitly returned Promise to wait for that callback to be invoked. The await inside the callback is irrelevant as that function hasn't even been called yet.
Firebase makes extensive use of Promises, so typically the solution would just be to return or await the relevant Promise:
// Note: This WON'T work, explanation follows
return firebase.auth().onAuthStateChanged(async function(user) {
// Note: This WON'T work, explanation follows
await firebase.auth().onAuthStateChanged(async function(user) {
This won't work here because onAuthStateChanged doesn't actually return a Promise, it returns an unsubscribe function.
You could, of course, create a new Promise yourself and 'fix' it that way. However, creating new Promises using new Promise is generally considered a code smell. Typically it's only necessary when wrapping code that doesn't support Promises properly. If we're working with a library that has proper Promise support (as we are here) then we shouldn't need to create any Promises.
So why doesn't onAuthStateChanged return a Promise?
Because it's a way of watching all sign-in/sign-out events. Every time the user signs in or signs out it'll call the callback. It isn't intended as a way to watch a particular sign-in. A Promise can only be resolved once, to a single value. So while a single sign-in event could be modelled with a Promise it's meaningless when watching all sign-in/sign-out events.
So fetchCreds is registering to be notified about all sign-in/sign-out events. It doesn't do anything with the returned unsubscribe function, so presumably it'll be listening to all such events until the page is reloaded. If you call fetchCreds multiple times it'll keep adding more and more listeners.
If you're waiting for a user to finish signing in then I suggest waiting for that directly instead. firebase.auth() has various methods starting with the prefix signIn, e.g. signInWithEmailAndPassword, and these do return a Promise that resolves when the user has finished signing in. The resolved value provides access to various information, including the user. I don't know which method you're using but the idea is much the same for all of them.
However, it might be that you're really just interested in grabbing the details of the current user. If that's all you want then you don't need to use onAuthStateChanged at all. You should just be able to grab a copy using the currentUser property. Something like this:
async fetchCreds({ commit }) {
try {
const { uid } = firebase.auth().currentUser
const userDoc = await users.doc(uid).get()
commit('SET_USER', userDoc.data())
} catch (error) {
console.log(error)
commit('SET_USER', {})
}
}
As I've already mentioned, this relies on the assumption that the user is already signed in. If that isn't a safe assumption then you might want to consider waiting until after sign in has completed before creating components that need user credentials.
Update:
Questions from the comments:
If the obj.method() call was asynchronous and we did await the callback function within it, would that ensure that the outer async function (myFn) never resolves before the inner one has finished?
I'm not entirely sure what you're asking here.
Just to be clear, I'm being very careful with my use of the words async and asynchronous. A function such as setTimeout would be considered asynchronous but it is not async.
async/await is just a lot of syntactic sugar around Promises. You don't really wait for a function, you wait for a Promise. When we talk about awaiting an async function we're really talking about waiting for the Promise it returns to resolve.
So when you say await the callback function it's not really clear what that means. Which Promise are you trying to await?
Putting the async modifier on a function doesn't make it magically wait for things. It will only wait when it encounters await. You can still have other asynchronous calls within an async function and, just like with a normal function, these calls will be performed after the function has returned. The only way to 'pause' is to await a Promise.
Putting an await inside another function, even a nested function, won't make any difference to whether the outer function waits unless the outer function is already waiting for the inner function. Behind the scenes this is all just Promises chaining then calls. Whenever you write await you're just adding another then call to a Promise. However, that won't have the desired effect unless that Promise is in the same chain as the Promise returned by the outer async function. It only needs one link to be missing for the chain to fail.
So modifying my earlier example:
async function myFn (obj) {
await obj.method(async function () {
await somePromise
// ...
})
// ...
}
await myFn(x)
Note that there are 3 functions here: myFn, method and the callback passed to method. The question is, will await myFn(x) wait for somePromise?
From the code above we can't actually tell. It would depend on what method does internally. For example, if method looked like this then it still wouldn't work:
function method (callback) {
setTimeout(callback, 1000)
}
Putting async on method won't help, that'll just make it return a Promise but the Promise still won't be waiting for the timer to fire.
Our Promise chain has a broken link. myFn and the callback are both creating their parts of the chain but unless method links those Promises together it won't work.
On the other hand, if method is written to return a suitable Promise that waits for the callback to complete then we will get our target behaviour:
function method (callback) {
return someServerCallThatReturnsAPromise().then(callback)
}
We could have used async/await here instead but there was no need as we can just return the Promise directly.
Also, if in the async myFn function you're not returning anything, does that mean it'll resolve immediately and as undefined?
The term immediately is not well-defined here.
If a function isn't returning anything at the end then it's equivalent to having return undefined at the end.
The Promise returned by an async function will resolve at the point the function returns.
The resolved value for the Promise will be the value returned.
So if you aren't returning anything it will resolve to undefined. Resolving won't happen until the end of the function is reached. If the function doesn't contain any await calls then this will happen 'immediately' in the same sense as a synchronous function returning 'immediately'.
However, await is just syntactic sugar around a then call, and then calls are always asynchronous. So while the Promise might resolve 'immediately' the await still has to wait. It's a very short wait, but it isn't synchronous and other code may get the opportunity to run in the meantime.
Consider the following:
const myFn = async function () {
console.log('here 3')
}
console.log('here 1')
Promise.resolve('hi').then(() => {
console.log('here 4')
})
console.log('here 2')
await myFn()
console.log('here 5')
The log messages will appear in the order they're numbered. So even though myFn resolves 'immediately' you'll still get here 4 jumping in between here 3 and here 5.

To make it short
fetchCreds({ commit }) {
return new Promise((resolve, reject) => {
try {
firebase.auth().onAuthStateChanged(async function(user) {
const { uid } = user
const userDoc = await users.doc(uid).get()
commit('SET_USER', userDoc.data())
resolve()
})
} catch (error) {
console.log(error)
commit('SET_USER', {})
resolve()
}}
}
async () => undefined // returns Promise<undefined> -> undefined resolves immediatly
asnyc () => func(cb) // returns Promise<any> resolves before callback got called
() => new Promise(resolve => func(() => resolve())) // resolves after callback got called

How make promise execute synchronously?

I use dom-to-image.js for converting dom to png image. As dom-to-image.js uses promise, the code executes asynchronously. I want to execute .then function synchronously.
I have the following code:
domtoimage.toPng(document.getElementById("main")).then(function(dataUrl) {
console.log(dataUrl);
}).catch(function(error) {
console.error('oops, something went wrong!', error);
});
console.log("this console should be executed after console.log(dataUrl)")
I want to execute .then function first, before executing console.log("this console should be executed after console.log(dataUrl)").
Please tell me some way to achieve this.

There are of course legit reasons to force synchronous execution of a promise in js. The most obvious is when require'ing a file that needs to initialize using some asynchronous stuff, and optimization is not an overriding concern.
Seems like the package synchronized-promise seems like it ought to do the trick. In your case (warning - untested..):
const dti = () => docstoimage.toPng(document.getElementById("main"))
.then(dataUrl => console.log('url: ', dataUrl))
.catch(err => console.error('oops: ', err))
const sp = require('synchronized-promise')
const syncDti = sp(dti)
syncDti() // performs the 'synchronized version'
console.log("this console should be executed afterwards")

You didn't mention if it's done in browser or in NodeJs. For NodeJs that's possible by using execSync or spawnSync from child_process:
import { spawnSync } from "child_process";
function doSyncStuff(domObj){
const output = spawnSync(...);
console.log("this logs in server");
return output;

bit of a necro, but I'm the author of https://www.npmjs.com/package/synchronous-promise - which was around before this question was raised and does what you want (:

Async functions are a promise.
You have to use the promise syntax with them or use await (async-await syntax) on them in another async function.
An example of the regular promise syntax would be: myPromise.then(() => {})
For what you are looking for, you can use the promise syntax on them to wait for them as if they aren't a promise. Do take care though, as the code in myPromise.then(() => {}) is synchronous and can't use async-await features. I've wrapped things in a main function but you don't need to for extra code but you don't need to.
You can then run the main function through the promise method.
For e.g:
async function myFunction() {
// Do stuff
}
async function main() {
// Do stuff
await myFunction()
}
async function mySecondaryFunction() {
// Do stuff
}
function mySynchronousFunction() {
console.log("hello")
}
main().then(() => {
mySynchronousFunction()
mySecondaryFunction().then(() => {
console.log("idk")
}
})
See, we can use both types of functions!
Do know, though that this doesn't actually make promises synchronous.
It just acts like they're synchronous.
EDIT: Uhhh, I just realized you could put the console.log you want to execute after in both the try and catch functions.

For those stumbling upon this now:
If you're not concerned with IE support, you could use async and await to execute the promise as though it were synchronous. The await syntax will pause execution of the function until the promise resolves, letting you write the code as if there wasn't a promise. To catch an error, you wrap it in a try/catch block.
The only catch is that using the await syntax requires you to wrap it inside a function declared with async.
async function toPng() {
try {
let dataUrl = await domtoimage.toPng(document.getElementById("main"));
console.log(dataUrl);
}
catch (error ) {
console.error('oops, something went wrong!', error);
}
console.log("this console should be executed after console.log(dataUrl)")
}