I'm converting elapsed ms to HH:mm:ss, but if the elapsed ms are higher of a day, I lost that info:
const elapsedSeconds = 218509
const elapsed = moment.utc(elapsedSeconds * 1000).format('HH:mm:ss');
alert(elapsed); // print 12:41:49
How can I also display days from ms, near the HH:mm:ss?
In this case there are 60hours, so it should print 2(days):12:41:49. Or 60:41:49 at least.
So based on your required ouput you can use moment library to convert date time to specified format.
For that your code looks like :
const elapsedMilliseconds = 218509000;
const duration = moment.duration(elapsedMilliseconds);
const elapsed = duration.days() + "(days):" + duration.hours() + ":" + duration.minutes() + ":" + duration.seconds();
alert(elapsed);
Result :
2(days):12:41:49
If you want to do by javascript to get total HH:mm:ss then :
function padTo2Digits(num) {
return num.toString().padStart(2, '0');
}
function convertMsToHM(milliseconds) {
let seconds = Math.floor(milliseconds / 1000);
let minutes = Math.floor(seconds / 60);
let hours = Math.floor(minutes / 60);
seconds = seconds % 60;
minutes = seconds >= 30 ? minutes + 1 : minutes;
minutes = minutes % 60;
return `${padTo2Digits(hours)}:${padTo2Digits(minutes)}:${padTo2Digits(seconds)}`;
}
console.log(convertMsToHM(218509000));
Result :
"60:42:49"
Related
I have 2 dates in ISO format like so:
startDate: "2018-09-14T00:20:12.200Z"
endDate: "2018-09-16T00:18:00.000Z"
What I'm trying to do is calculate the difference between those 2 days. So with the given dates it would be 1 Day, 21 Hours, 47 Minutes and 40 Seconds (pardon me if the subtraction is not correct).
Tried to do using the following:
const start = new Date(startDate).getTime();
const end = new Date(endDate).getTime();
return Math.abs(end - start).toString();
However this doesn't seem to work.
Any clues?
The following works. Things to note:
getTime() is not needed as the new Date() constructor returns the time in milliseconds.
The date should always be in RFC2822 or ISO formats, else it becomes useless across various browsers, even while using moment.js.
If you can use moment.js, Get time difference using moment.
Refer this to know why only the standardized formats need to be used.
var unitmapping = {"days":24*60*60*1000,
"hours":60*60*1000,
"minutes":60*1000,
"seconds":1000};
function floor(value)
{
return Math.floor(value)
}
function getHumanizedDiff(diff)
{
return floor(diff/unitmapping.days)+" days "+
floor((diff%unitmapping.days)/unitmapping.hours)+" hours "+
floor((diff%unitmapping.hours)/unitmapping.minutes)+" minutes "+
floor((diff%unitmapping.minutes)/unitmapping.seconds)+" seconds "+
floor((diff%unitmapping.seconds))+" milliseconds";
}
console.log(getHumanizedDiff(new Date("2018-09-16T00:18:00.000Z") - new Date("2018-09-14T00:20:12.200Z")));
console.log(getHumanizedDiff(new Date("2018-09-16T00:18:00.000Z") - new Date("2018-09-04T00:20:02.630Z")));
console.log(getHumanizedDiff(new Date("2018-09-17T00:16:04.000Z") - new Date("2018-09-14T00:20:12.240Z")));
var startDate = "2018-09-14T00:20:12.200Z"
var endDate = "2018-09-16T00:18:00.000Z"
const start = new Date(startDate).getTime();
const end = new Date(endDate).getTime();
const milliseconds = Math.abs(end - start).toString()
const seconds = parseInt(milliseconds / 1000);
const minutes = parseInt(seconds / 60);
const hours = parseInt(minutes / 60);
const days = parseInt(hours / 24);
const time = days + ":" + hours % 24 + ":" + minutes % 60 + ":" + seconds % 60;
console.log(time)
yBrodsky's suggestion to use moment.js is probably the best idea, but if you're curious how to do the math here, it would go something like this:
const start = new Date(startDate).getTime();
const end = new Date(endDate).getTime();
let seconds = Math.round(Math.abs(end - start) / 1000); // We'll round away millisecond differences.
const days = Math.floor(seconds / 86400);
seconds -= days * 86400;
const hours = Math.floor(seconds / 3600);
seconds -= hours * 3600;
minutes = Math.floor(seconds / 60);
seconds -= minutes * 60;
This leaves you with hours, minutes, and seconds as numbers that you can format into a string result however you like.
How to parse a given amount of milliseconds (e.g. 125230.41294642858) into a time format like: minutes:seconds?
var ms = 125230.41294642858,
min = 0|(ms/1000/60),
sec = 0|(ms/1000) % 60;
alert(min + ':' + sec);
Try the following
var num = Number(theTextValue);
var seconds = Math.floor(num / 1000);
var minutes = Math.floor(seconds / 60);
var seconds = seconds - (minutes * 60);
var format = minutes + ':' + seconds
Number.prototype.toTime = function(){
var self = this/1000;
var min = (self) << 0;
var sec = (self*60) % 60;
if (sec == 0) sec = '00';
return min + ':' + sec
};
var ms = (new Number('250')).toTime();
console.log(ms);
=> '0:15'
var ms = (new Number('10500')).toTime();
console.log(ms);
=> '10:30'
Even though moment.js does not provide such functionality, if you come here and you are already using moment.js, try this:
function getFormattedMs(ms) {
var duration = moment.duration(ms);
return moment.utc(duration.asMilliseconds()).format("mm:ss");
}
This workaround in moment was introduced in this Issue.
I am using javascript Date object trying to convert millisecond to how many hour, minute and second it is.
I have the currentTime in milliseconds
var currentTime = new Date().getTime()
and I have futureTime in milliseconds
var futureTime = '1432342800000'
I wanted to get difference in millisecond
var timeDiff = futureTime - currentTime
the the timeDiff was
timeDiff = '2568370873'
I want to know how many hours, minutes, seconds it is.
Could anyone help?
const secDiff = timeDiff / 1000; //in s
const minDiff = timeDiff / 60 / 1000; //in minutes
const hDiff = timeDiff / 3600 / 1000; //in hours
updated
function msToHMS( ms ) {
// 1- Convert to seconds:
let seconds = ms / 1000;
// 2- Extract hours:
const hours = parseInt( seconds / 3600 ); // 3,600 seconds in 1 hour
seconds = seconds % 3600; // seconds remaining after extracting hours
// 3- Extract minutes:
const minutes = parseInt( seconds / 60 ); // 60 seconds in 1 minute
// 4- Keep only seconds not extracted to minutes:
seconds = seconds % 60;
alert( hours+":"+minutes+":"+seconds);
}
const timespan = 2568370873;
msToHMS( timespan );
Demo
If you are confident that the period will always be less than a day you could use this one-liner:
new Date(timeDiff).toISOString().slice(11,19) // HH:MM:SS
N.B. This will be wrong if timeDiff is greater than a day.
Convert ms to hh:mm:ss
function millisecondsToHuman(ms) {
const seconds = Math.floor((ms / 1000) % 60);
const minutes = Math.floor((ms / 1000 / 60) % 60);
const hours = Math.floor((ms / 1000 / 3600 ) % 24)
const humanized = [
pad(hours.toString(), 2),
pad(minutes.toString(), 2),
pad(seconds.toString(), 2),
].join(':');
return humanized;
}
=
function msToHMS( duration ) {
var milliseconds = parseInt((duration % 1000) / 100),
seconds = parseInt((duration / 1000) % 60),
minutes = parseInt((duration / (1000 * 60)) % 60),
hours = parseInt((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds ;
}
Converts milliseconds to a string in the format hh:mm:ss. Here's my version:
function HHMMSSFromMilliseconds(ms) {
// 1- Convert to seconds:
var seconds = ms / 1000;
// 2- Extract hours:
var hours = parseInt(seconds / 3600); // 3600 seconds in 1 hour
seconds = parseInt(seconds % 3600); // extract the remaining seconds after extracting hours
// 3- Extract minutes:
var minutes = parseInt(seconds / 60); // 60 seconds in 1 minute
// 4- Keep only seconds not extracted to minutes:
seconds = parseInt(seconds % 60);
// 5 - Format so it shows a leading zero if needed
let hoursStr = ("00" + hours).slice(-2);
let minutesStr = ("00" + minutes).slice(-2);
let secondsStr = ("00" + seconds).slice(-2);
return hoursStr + ":" + minutesStr + ":" + secondsStr
}
let timespan = 23570 * 1000;
let formattedTime = HHMMSSFromMilliseconds(timespan);
console.log(formattedTime);
Convert millis to DD(days):HH:MM:SS
function formatTime(timeMS) {
const [MS_IN_SEC, SEC_IN_DAY, SEC_IN_HOUR, SEC_IN_MIN] = [1000, 86400, 3600, 60];
let seconds = Math.round(Math.abs(timeMS) / MS_IN_SEC);
const days = Math.floor(seconds / SEC_IN_DAY);
seconds = Math.floor(seconds % SEC_IN_DAY);
const hours = Math.floor(seconds / SEC_IN_HOUR);
seconds = Math.floor(seconds % SEC_IN_HOUR);
const minutes = Math.floor(seconds / SEC_IN_MIN);
seconds = Math.floor(seconds % SEC_IN_MIN);
const [dd, hh, mm, ss] = [days, hours, minutes, seconds]
.map(item => item < 10 ? '0' + item : item.toString());
return dd + ':' + hh + ':' + mm + ':' + ss;
}
The difference in time is in milliseconds:
Get time difference between two dates in seconds
to get the difference you have to use math.floor()
http://www.w3schools.com/jsref/jsref_floor.asp
var secDiff = Math.floor(timeDiff / 1000); //in s
var minDiff = Math.floor(timeDiff / 60 / 1000); //in minutes
var hDiff = Math.floor(timeDiff / 3600 / 1000); //in hours
var timediff = futureTime - currentTime
long seconds = (long) (timediff / 1000) % 60 ;
long minutes = (long) ((timediff / (1000*60)) % 60);
long hours = (long) ((timediff / (1000*60*60)) % 24);
if(hours>0)
time = hours+" hrs : "+minutes+" mins";
else if(minutes>0)
time = minutes+" mins";
else if(seconds>0)
time = seconds+" secs";
Here is a simple function
function simplifiedMilliseconds(milliseconds) {
const totalSeconds = parseInt(Math.floor(milliseconds / 1000));
const totalMinutes = parseInt(Math.floor(totalSeconds / 60));
const totalHours = parseInt(Math.floor(totalMinutes / 60));
const days = parseInt(Math.floor(totalHours / 24));
const seconds = parseInt(totalSeconds % 60);
const minutes = parseInt(totalMinutes % 60);
const hours = parseInt(totalHours % 24);
let time = '1s';
if (days > 0) {
time = `${days}d:${hours}h:${minutes}m:${seconds}s`;
} else if (hours > 0) {
time = `${hours}h:${minutes}m:${seconds}s`;
} else if (minutes > 0) {
time = `${minutes}m:${seconds}s`;
} else if (seconds > 0) {
time = `${seconds}s`;
}
return time;
}
I need to get time difference in this format: "HH:MM:SS" using a Javascript.
I have tried this:
var diff = Date.parse( time2) - Date.parse( time1 );
var total_time = (diff / 1000 / 60 / 60) + ":" + (diff / 1000 / 60) + ":" + (diff / 1000);
and this:
var diff = new Date( time2) - new Date( time1 );
var total_time = (diff / 1000 / 60 / 60) + ":" + (diff / 1000 / 60) + ":" + (diff / 1000);
These are the values of time2 and time1:
time1: "2012-11-07 15:20:32.161"
time2: "2012-11-07 17:55:41.451"
And result I am getting in both cases is:
total_time= 0.5250819444444444:31.504916666666666:1890.295
Which you can see is not correct
I think you are getting wrong diff value because of the millisecond part in the date delimited by .. Its not being accepted correctly by the data parser.
Try using the date and time part excluding the milliseconds as below:
var diff = Date.parse(time2.split(".")[0]) - Date.parse( time1.split(".")[0]);
Also while you are getting wrong difference diff, your time computation is also wrong.
It should be:
var second = Math.floor(diff /1000);
//convert the seconds into minutes and remainder is updated seconds value
var minute = Math.floor(second /60);
second = second % 60;
//convert the minutes into hours and remainder is updated minutes value
var hour = Math.floor(minute/60);
minute = minute %60;
var total_time= hour+":" minute+":"+second;
You forgot to remove the number of milliseconds you already calculated from diff. Here is a very verbose example on how you do it in a propper way.
var time1 = "2012-11-07 15:20:32.161",
time2 = "2012-11-07 17:55:41.451",
SECOND = 1000,
MINUTE = SECOND* 60,
HOUR = MINUTE* 60;
var diff = new Date(time2) - new Date(time1);
var hours = Math.floor(diff / HOUR); // Calculate how many times a full hour fits into diff
diff = diff - (hours * HOUR); // Remove hours from difference, we already caluclated those
var minutes = Math.floor(diff / MINUTE); // Calculate how many times a full minute fits into diff
diff = diff - (minutes * MINUTE); // Remove minutes from difference
var seconds = Math.floor(diff / SECOND); // As before
diff = diff - (seconds * SECOND);
var rest = diff;
var total_time = hours + ":" + minutes + ":" + seconds + " " + rest ;
DEMO
For example:
Given time: 08:22 => Rounded to: 08:15
Given time: 08:23 => Rounded to: 08:30
Should be pretty simple. But all I was able to produce is lengthy, not very good code to solve the issue. My mind's just gone blank.
Regards
Given that you have hours and minutes in variables (if you don't you can get them from the Date instance anyway by using Date instance functions):
var m = (parseInt((minutes + 7.5)/15) * 15) % 60;
var h = minutes > 52 ? (hours === 23 ? 0 : ++hours) : hours;
minutes can as well be calculated by using Math.round():
var m = (Math.round(minutes/15) * 15) % 60;
or doing it in a more javascript-sophisticated expression without any functions:
var m = (((minutes + 7.5)/15 | 0) * 15) % 60;
var h = ((((minutes/105) + .5) | 0) + hours) % 24;
You can check the jsPerf test that shows Math.round() is the slowest of the three while mainly the last one being the fastest as it's just an expression without any function calls (no function call overhead i.e. stack manipulation, although native functions may be treated differently in Javascript VM).
//----
This function round the time to the nearest quarter hour.
function roundTimeQuarterHour(time) {
var timeToReturn = new Date(time);
timeToReturn.setMilliseconds(Math.round(timeToReturn.getMilliseconds() / 1000) * 1000);
timeToReturn.setSeconds(Math.round(timeToReturn.getSeconds() / 60) * 60);
timeToReturn.setMinutes(Math.round(timeToReturn.getMinutes() / 15) * 15);
return timeToReturn;
}
With Time String
Here is a method that will round a time string like the one you presented. Eg "08:22"
let roundTime = (time, minutesToRound) => {
let [hours, minutes] = time.split(':');
hours = parseInt(hours);
minutes = parseInt(minutes);
// Convert hours and minutes to time in minutes
time = (hours * 60) + minutes;
let rounded = Math.round(time / minutesToRound) * minutesToRound;
let rHr = ''+Math.floor(rounded / 60)
let rMin = ''+ rounded % 60
return rHr.padStart(2, '0')+':'+rMin.padStart(2, '0')
}
// USAGE //
// Round time to 15 minutes
roundTime('8:07', 15); // "08:00"
roundTime('7:53', 15); // "08:00"
roundTime('7:52', 15); // "07:45"
With Hours and Minutes Already Split Up
You can use this method if you don't need to parse out the hour and minute strings like your example shows
let roundTime = (hours, minutes, minutesToRound) => {
// Convert hours and minutes to minutes
time = (hours * 60) + minutes;
let rounded = Math.round(time / minutesToRound) * minutesToRound;
let roundedHours = Math.floor(rounded / 60)
let roundedMinutes = rounded % 60
return { hours: roundedHours, minutes: roundedMinutes }
}
// USAGE //
// Round time to 15 minutes
roundTime(7, 52, 15); // {hours: 7, minutes: 45}
roundTime(7, 53, 15); // {hours: 8, minutes: 0}
roundTime(1, 10, 15); // {hours: 1, minutes: 15}
With Existing Date Object
Or, if you are looking to round an already existing date object to the nearest x minutes, you can use this method.
If you don't give it any date it will round the current time. In your case, you can round to the nearest 15 minutes.
let getRoundedDate = (minutes, d=new Date()) => {
let ms = 1000 * 60 * minutes; // convert minutes to ms
let roundedDate = new Date(Math.round(d.getTime() / ms) * ms);
return roundedDate
}
// USAGE //
// Round existing date to 5 minutes
getRoundedDate(15, new Date()); // 2018-01-26T00:45:00.000Z
// Get current time rounded to 30 minutes
getRoundedDate(30); // 2018-01-26T00:30:00.000Z
The code here is a little verbose but I'm sure you'll see how you could combine the lines to make this shorter. I've left it this way to clearly show the steps:
var now = new Date();
var mins = now.getMinutes();
var quarterHours = Math.round(mins/15);
if (quarterHours == 4)
{
now.setHours(now.getHours()+1);
}
var rounded = (quarterHours*15)%60;
now.setMinutes(rounded);
document.write(now);
Divide by 9e5 milliseconds (15 * 60 * 1000), round, and multiply back by 9e5 :
const roundToQuarter = date => new Date(Math.round(date / 9e5) * 9e5)
console.log( roundToQuarter(new Date("1999-12-31T23:52:29.999Z")) ) // 1999-12-31T23:45:00
console.log( roundToQuarter(new Date("1999-12-31T23:52:30.000Z")) ) // 2000-01-01T00:00:00
console.log( roundToQuarter(new Date) )
I use these code:
function RoundUp(intervalMilliseconds, datetime){
datetime = datetime || new Date();
var modTicks = datetime.getTime() % intervalMilliseconds;
var delta = modTicks === 0 ? 0 : datetime.getTime() - modTicks;
delta += intervalMilliseconds;
return new Date(delta);
}
function RoundDown(intervalMilliseconds, datetime){
datetime = datetime || new Date();
var modTicks = datetime.getTime() % intervalMilliseconds;
var delta = modTicks === 0 ? 0 : datetime.getTime() - modTicks;
return new Date(delta);
}
function Round(intervalMilliseconds, datetime){
datetime = datetime || new Date();
var modTicks = datetime.getTime() % intervalMilliseconds;
var delta = modTicks === 0 ? 0 : datetime.getTime() - modTicks;
var shouldRoundUp = modTicks > intervalMilliseconds/2;
delta += shouldRoundUp ? intervalMilliseconds : 0;
return new Date(delta);
}
Round to the nearest 5 minutes:
//with current datetime
var result = Round(5 * 60 * 1000);
//with a given datetime
var dt = new Date();
var result = Round(5 * 60 * 1000, dt);
There is an NPM package #qc/date-round that can be used. Given that you have a Date instance to be rounded
import { round } from '#qc/date-round'
const dateIn = ...; // The date to be rounded
const interval = 15 * 60 * 1000; // 15 minutes (aka quarter hour)
const dateOut = round(dateIn, interval)
Then you can use date-fns to format the date
import format from 'date-fns/format';
console.log(format(dateOut, 'HH:mm')) // 24-hr
console.log(format(dateOut, 'hh:mm a')) // 12-hr
Another one with date-fns (not mandatory)
import {getMinutes, setMinutes, setSeconds, setMilliseconds} from 'date-fns'
let date = new Date();
let min = getMinutes(date);
let interval = 3 // in minutes
let new_min = min - min%interval + interval;
let new_date = setMilliseconds(setSeconds(setMinutes(date,new_min),0),0)
console.log('Orignal Date : ' + date);
console.log('Original Minute : ' + min);
console.log('New Minute : ' + new_min);
console.log('New Date : ' + new_date);
Pass the interval in milliseconds get the next cycle in roundUp order
Example if I want next 15 minute cycle from current time then call this method like *calculateNextCycle(15 * 60 * 1000);*
Samething for quarter hour pass the interval
function calculateNextCycle(interval) {
const timeStampCurrentOrOldDate = Date.now();
const timeStampStartOfDay = new Date().setHours(0, 0, 0, 0);
const timeDiff = timeStampCurrentOrOldDate - timeStampStartOfDay;
const mod = Math.ceil(timeDiff / interval);
return new Date(timeStampStartOfDay + (mod * interval));
}
console.log(calculateNextCycle(15 * 60 * 1000));
This method is specifically for Vue.js, it takes a time, and returns to the nearest entered increment, I based this on an above answer, but this is for Vue specifically using echma-6 standards. It will return T:06:00:00, if you fed 06:05 into it. This is used specifically with vuetify's v-calendar to choose a time in weeklyor daily format.
This answer also adds the 0 for like 06 hrs. Which is where this differs from the above answers. If you change the 30 to 15
methods: {
roundTimeAndFormat(datetime, roundTo) {
const hrsMins = datetime.split(':')
let min = ((((hrsMins[1] + 7.5) / roundTo) | 0) * roundTo) % 60
let hr = (((hrsMins[1] / 105 + 0.5) | 0) + hrsMins[0]) % 24
if (Number(hr) < 10) {
hr = ('0' + hr).slice(-2)
}
if (min === 0) {
min = ('0' + min).slice(-2)
}
return 'T' + hr + ':' + min + ':00'
}
}
You would just call:
this.roundTimeAndFormat(dateTime, 15)
And you would get the time to the nearest 15min interval.
If you enter, 11:01, you'd get T11:00:00
Might help others. For any language. Mainly trick with round function.
roundedMinutes = yourRoundFun(Minutes / interval) * interval
E.g. The interval could be 5 minutes, 10 minutes, 15 minutes, 30 minutes.
Then rounded minutes can be reset to the respective date.
yourDateObj.setMinutes(0)
yourDateObj.setMinutes(roundedMinutes)
also if required then
yourDateObj.setSeconds(0)
yourDateObj.setMilliSeconds(0)
Simple?