I made an API on Node.js, If I send some params I get the response, it's the same person but different language info, I would like to present it like in the second example I haven't been able to figure it out.
How I'm getting the data
[
{
"Id": 1,
"ced": "123",
"Name": "Andres",
"NativeLanguage": 1,
"Level": 100,
"NameLang": "spanish",
},
{
"Id": 1,
"ced": "123",
"Name": "Andres",
"NativeLanguage": 1,
"Level": 100,
"NameLang": "english",
}
]
how I want to see it
[
{
"Id": 1,
"ced": "123",
"Name": "Andres",
}
"Idiomas":
[
{
"NativeLanguage": 1,
"Level": 100,
"NameLang": "spanish",
},
{
"NativeLanguage": 1,
"Level": 100,
"NameLang": "spanish",
}
]
]
export default {
el: "myFormPerson",
data() {
return {
results:[],
ced:'',
}
},
methods: {
submitForm() {
axios.get('http://localhost:8080/person/' + this.ced)
.then((response) => {
this.results = response.data;
//console.log(this.results);
})
.catch(function (error) {
console.log(error);
})
.finally(function () {
});
//console.log(this.ced);
},
}
}
How I see it right now [1]: https://i.stack.imgur.com/ezHgH.png
Rather than pointlessly trying to get the format you want in the MySQL result (not possible) - work with the JSON to convert it to what you want
this.results=Object.values(response.data.reduce((acc,{Id,ced,Name,...rest})=>(acc[Id]||={Id,ced,Name,Idiomas:[]},acc[Id].Idiomas.push({...rest}),acc),{}));
working example
const have = [{
"Id": 1,
"ced": "123",
"Name": "Andres",
"NativeLanguage": 1,
"Level": 100,
"NameLang": "spanish",
},
{
"Id": 1,
"ced": "123",
"Name": "Andres",
"NativeLanguage": 1,
"Level": 100,
"NameLang": "english",
}
];
const want = Object.values(have.reduce((acc,{Id,ced,Name,...rest}) => (acc[Id]||={Id,ced,Name,Idiomas:[]},acc[Id].Idiomas.push({...rest}),acc),{}));
console.log(want);
Related
I want to return only matches results.
My array:
products: [
{
"id": 1,
"name": "Product 1",
"concepts": [
{
"id": 10,
"name": "Blabla"
},
{
"id": 15,
"name": "Zlazla"
}
]
},
{
"id": 2,
"name": "Product 2",
"concepts": [
{
"id": 14,
"name": "Gulagula"
},
{
"id": 15,
"name": "Zlazla"
}
]
}
]
I want to filter products which only have one of the concepts below.
concepts array:
['14', '15']
Couldn't solve this in an easy way.
You can try this way:
var products= [
{
"id": 1,
"name": "Product 1",
"concepts": [
{
"id": 10,
"name": "Blabla"
},
{
"id": 15,
"name": "Zlazla"
}
]
},
{
"id": 2,
"name": "Product 2",
"concepts": [
{
"id": 14,
"name": "Gulagula"
},
{
"id": 15,
"name": "Zlazla"
}
]
}
]
var products = products.filter((product) => product.concepts = product.concepts.filter( (x) => x.id == 14 || x.id == 15));
console.log(products);
How can i make the cart_items like my expetation.. just it no more.. my problem just it :D
i just wanna make my cart_items like this.. hope you are can help me thanks. did I make the wrong method? and one more thing, i wanna make the qty inside the cart_items
this is my expectation
"cart": [
{
"id": 1,
"date": "12/10/2020",
"store": {
"id": 1,
"name": "Dirumah Aja",
"promo": 1
},
"cart_items": [
{
"id": 1,
"product": {
"id": 1,
"name": "Bakso Urat",
"price": 10000,
"promo": {
"nama": "promo"
}
},
"qty": 5
}
]
}
]
and this is what I got
"cart": [
{
"cart_items": {
"name": "Steak Sapi Impor",
"price": "38000",
"stock": "4",
"image": "https://firebasestorage.googleapis.com/v0/b/francise-fb70a.appspot.com/o/steak.jpg?alt=media&token=46e0d769-96d3-440f-8edb-5fce2481ace0",
"promo": 3,
"id": 8,
"qty": 1
},
"store": {
"name": "Amanda Foods Store",
"email": "amanda#food.com",
"store_image": "https://firebasestorage.googleapis.com/v0/b/francise-fb70a.appspot.com/o/full_hd_retina.jpeg?alt=media&token=3e602e86-661b-48ee-9e9c-af9f94a170d1",
"product": [
5,
7,
8,
2
],
"store_promo": 1,
"location": {
"street_name": "Jl. Kebon Gedang II B",
"province": "Jawa Barat",
"city": "Bandung",
"post_code": "40285"
},
"id": 1
},
"date_order": "Nov 03 2020 08:48:03",
"id": 2
}
]
This is my data
data() {
return {
promo_id: [],
promo_partner: [],
products: {},
qty: 1,
cart_items: [
{}
]
};
and this is my method
addToCart() {
const date = (new Date()).toString().split(' ').splice(1,4).join(' ')
this.products.cart_items = this.product;
this.products.cart_items.qty = this.qty;
this.products.store = this.partner;
this.products.date_order = date;
console.log(this.cart_items)
axios
.post("http://localhost:3000/cart/", this.products)
.then(() => {
swal("Belanja Berhasil!", {
icon: "success",
});
})
.catch((error) => console.log(error));
}
}
You need to use .push() to add items to an array. You're replacing the array with this.product.
if (!this.products.cart_items) { // initialize cart_items if necessary
this.products.cart_items = [];
}
this.products.cart_items.push({id: this.product.id, product: this.product, qty: this.qty});
For example: I have an array of objects like this:
let arrayOfObjects: [
{ "id": 0, "name": "Available" },
{ "id": 1, "name": "Ready" },
{ "id": 2, "name": "Started" }
];
Now I want to replace or overwrite the array above with the same array, but including different values (same keys, different values):
let arrayOfObjects: [
{ "id": 0, "name": "Not Available" },
{ "id": 1, "name": "Not Ready" },
{ "id": 2, "name": "Not Started" }
];
How can this be done in TypeScript?
Try this JS
let oneArray = [
{ "id": 0, "name": "Available" },
{ "id": 1, "name": "Ready" },
{ "id": 2, "name": "Started" }
];
let twoArray = [
{ "id": 0, "name": "Not Available" },
{ "id": 1, "name": "Not Ready" },
{ "id": 2, "name": "Not Started" }
];
let newArray = Object.assign([], oneArray, twoArray);
console.log(newArray);
In TS
interface Data {
oneArray: array;
twoArray: array;
}
function merge(data: Data) {
return Object.assign([], data.oneArray, data.twoArray);
}
let user = {
oneArray: [
{ "id": 0, "name": "Available" },
{ "id": 1, "name": "Ready" },
{ "id": 2, "name": "Started" }
],
twoArray: [
{ "id": 0, "name": "Not Available" },
{ "id": 1, "name": "Not Ready" },
{ "id": 2, "name": "Not Started" }
]
};
console.log(merge(user));
Sure :)
let arrayOfObjects = [
{ "id": 0, "name": "Available" },
{ "id": 1, "name": "Ready" },
{ "id": 2, "name": "Started" }
];
const newValues = ['Not Available', 'Not Ready', 'Not Started'];
newValues.forEach((value, i) => {
arrayOfObjects.find(o => o.id === i).name = value;
});
console.log(arrayOfObjects);
I wouldn't recommend this though: functional programming is awesome.
let arrayOfObjects = [
{ "id": 0, "name": "Available" },
{ "id": 1, "name": "Ready" },
{ "id": 2, "name": "Started" }
];
let names = ['Not Available', 'Not Ready', 'Not Started']
let result = arrayOfObjects.map((user, index) => ({ ...user, name: names[index] }))
console.log(result)
I want to group By sub-work in array
Here is my array I want to group By sub-work
result = [
{
"date": "10-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
{
"date": "12-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
]
Here is what I try
result = _(result)
.map(function(items, data) {
_.groupBy(items.data, function({ sub_work }) {
return sub_work;
});
})
.value();
first I map result into data then I try to groupby but It's return null
Update
I want my output look like this
[
{
"date": "10-07-2019",
sub-work: [{
sub-work : "sub_work1",
sub-data[
{
"id": 7,
"title": 'subdata-1',
}
]
}]
}
]
...........................
It would be better if you could provide your expected result.
Here's what I could infer:
_(result)
.map(function(obj) { // Convert into a 2D array.
return obj.data.map(e => Object.assign(e, {date: obj.date}));
})
.flatten() // We have an array of objects now.
.groupBy('sub-work') // We can call groupBy().
.value();
Here's what you get:
{
"sub_work1": [{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "10-07-2019"
}, {
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "12-07-2019"
}]
}
I have 2 arrays of objects: itemsList and itemsFetched. All of the objects inside each array have the same structure (nr of key/values). One of those keys has the same 'meaning' but a different name (item_id on itemsList, id on itemsFetched ). Their values are the same.
I need to filter the itemsList array and leave only the objects that have the item_id value equal to the id value on itemsFetched. Then copy(add) the key/value count from each object on the itemsFetched array (which matches the item_id=id) to the filtered array.
I've a working code but I'm sure it isnt the best way to solve this problem. I've already asked something similar before (regarding the 'filter' part) which solved my problem, but since I had to add the 'count' part after the filtering, I ended up refactoring the whole thing.
itemsList (sample)
[
{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
},
{
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
},
{
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
},
{
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
]
itemsFetched (sample)
[
{
"item_id": 1,
"count": 50,
"unseen": true
},
{
"item_id": 401,
"count": 2,
"unseen": true
},
{
"item_id": 901,
"count": 1,
"unseen": true
}
]
resultArray (what I want in the end)
[
{
"id": 1,
"name": "Pokeball",
"count": 50,
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png",
},
{
"id": 401,
"name": "Incense",
"count": 2,
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"count": 1,
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
]
my current code (working)
let arr = [];
itemsFetched.forEach((item) => {
itemsList.forEach((item2) => {
if (item.item_id === item2.id) {
arr.push({
"id": item.item_id,
"name": item2.name,
"count": item.count,
"img": item2.img
});
}
});
});
PS: I'm able to use ES6/7 syntax/features.
You can use hash map to reduce Time complexitly, your algorithm is O(m*n), The follow is O(m+n+r)
const itemsMap = itemsList.reduce((map, item) => {
map[item.id] = item
return map
}, {})
const results = itemsFetched
.filter((item) => itemsMap.hasOwnProperty(item.item_id))
.map((item) => ({
id: item.item_id,
name: itemsMap[item.item_id].name,
count: item.count,
img: itemsMap[item.item_id].img,
}))
Use a for ... of loop (an ES6 feature) in conjunction with Array#map.
This makes it much easier to return the merged object the first time you find a match, which is a logically optimization because neither list should contain more than one entry with a given id.
const result = itemsFetched.map(data => {
for (let item of itemsList) {
if (data.item_id === item.id) {
return {
id: item.id,
name: item.name,
count: data.count,
img: item.img
}
}
}
})
Snippet:
const itemsList = [{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
}, {
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
}, {
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
}, {
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
}, {
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}]
const itemsFetched = [{
"item_id": 1,
"count": 50,
"unseen": true
}, {
"item_id": 401,
"count": 2,
"unseen": true
}, {
"item_id": 901,
"count": 1,
"unseen": true
}]
const result = itemsFetched.map(data => {
for (let item of itemsList) {
if (data.item_id === item.id) {
return {
id: item.id,
name: item.name,
count: data.count,
img: item.img
}
}
}
})
console.log(result)
One way to improve is to use for..of statement instead of forEach for the inner loop. This helps break from the loop once the id matches. There is no direct way to break from forEach method.
let arr = [];
itemsFetched.forEach((item) => {
for (let item2 of itemsList) {
if (itemsFetched.item_id === itemsList.id) {
arr.push({
"id": itemsFetched.item_id,
"name": itemsList.name,
"count": itemsFetched.count,
"img": itemsList.img
});
break;
}
}
});
Like this?
var itemsList = [
{
"id": 0,
"name": "Egg",
"img": "http://www.serebii.net/pokemongo/items/egg.png"
},
{
"id": 1,
"name": "Pokeball",
"img": "http://www.serebii.net/pokemongo/items/20pokeballs.png"
},
{
"id": 2,
"name": "Greatball",
"img": "http://www.serebii.net/pokemongo/items/greatball.png"
},
{
"id": 401,
"name": "Incense",
"img": "http://www.serebii.net/pokemongo/items/incense.png"
},
{
"id": 901,
"name": "Incubator (Unlimited)",
"img": "http://www.serebii.net/pokemongo/items/eggincubator.png"
}
];
var itemsFetched = [
{
"item_id": 1,
"count": 50,
"unseen": true
},
{
"item_id": 401,
"count": 2,
"unseen": true
},
{
"item_id": 901,
"count": 1,
"unseen": true
}
]
let arr = [];
itemsFetched.forEach((item) => {
itemsList.forEach((item2) => {
if (item.item_id == item2.id) {
arr.push({
"id": item.item_id,
"name": item2.name,
"count": item.count,
"img": item2.img
});
}
});
});
console.log(arr);