AJAX does not send POST - javascript

First of all, I have already read through many other posts and tried different things, but no solution approach has worked so far.
My problem: ajax does not send the POST data.
fillTable.js
function fillTableWithData(htmlID, tableSQL, colsSQL, orderSQL){
var jsondata = new FormData();
jsondata.append("action", htmlID);
jsondata.append("table", tableSQL);
jsondata.append("cols", colsSQL);
jsondata.append("order", orderSQL);
$.ajax({
url:"table.php",
method: "POST",
dataType: 'json',
contentType:false,
processData:false,
data: jsondata,
success:function(result){
// $(htmlID).html(result);
alert("test");
}
});
}
table.php
<?php
require('db.php');
echo (count($_POST)); // result is 0
if(isset($_POST['action'])){ // not set
if($_POST['action'] == "getDataAsRows"){
getDataAsRows($_POST['table'], $_POST['cols'], $_POST['order']);
}
}
function getDataAsRows($table, $cols, $order) {
...
}
?>
Both files are inside the same folder:
/scripts/fillTable.js
/scripts/table.php
The url should not be a problem, since the php code prints out the length of $_POST.

Related

how to use data sent with Ajax POST in PHP

I have a strange behaviour, I sent data to a PHP page using Post request, my problem is when I try to manipulate this data (echo for exemple) in PHP page I get nothing, but when I make condition on the value I sent the condition is ok.
My JS code
$.ajax({
type: "POST",
url: 'admin/page.php',
data: {
type: 'search',
date1:'2021/04/15',
date2:'2021/04/13'
},
success: function(data){
alert(data);
}
});
My PHP code
$uname = $_POST["type"];
$date1 = $_POST["date1"];
$date2 = $_POST["date2"];
if ($uname=='search') // condition OK
{
echo $date1;
echo $date2;
}

Sending AJAX post request to PHP

So here is my AJAX code using JQuery:
$('#button-upload').on('click', function(){
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
}
});
}
});
The request isn't registered in the network.
Secondly, I'm not sure how can I collect this data with PHP using $_POST.
You seem to be a php newbie. Here is a snippet of code you can use to retrive the ajax data.
Here is the link to the documentation about the global variable $_POST I suggest you to read it.
Another useful link about the predefined variables in php
JS code:
$('#button-upload').on('click', function(event){
event.preventDefault();
if( sendSMSArr.length > 0 ){
$.ajax({
url: 'manager/smsendr4.php',
type: 'POST',
dataType: 'json',
data: {'distribution': sendSMSArr},
success: function(response){
console.log(response);
}
});
}
});
PHP:
<?php
if(isset($_POST['distribution'])){
# I've added a sanitization filter, but you can omit it if you don't need to pass the data to a database.
$dist = filter_var($_POST['distribution'], FILTER_SANITIZE_STRING);
# put your logics here after you got the distribution $_POST variable value.
}
?>

Jquery and AJAX post to php data attribute?

Hello I have the following AJAX code:
var formData = new FormData($('form')[0]);
$.ajax({
url: 'saveImage.php', //Server script to process data
type: 'POST',
data: formData,
processData: false,
success: function(data){
console.log(data);
}
});
It works great and it loads up the PHP page it the background like it should:
<?php
include_once "mysql_connect.php";
$imageName = mysql_real_escape_string($_FILES["Image1"]["name"]);
$imageData = '';
$imageext = '';
if($imageName != null){
$imageData = mysql_real_escape_string(file_get_contents($_FILES["Image1"]["tmp_name"]));
$imageType = mysql_real_escape_string($_FILES["Image1"]["type"]);
$imageSize = getimagesize($_FILES["Image1"]["tmp_name"]);
$imageType = mysql_real_escape_string($_FILES["Image1"]["type"]);
$FileSize = FileSize($_FILES["Image1"]["tmp_name"]);
$imageext = mysql_real_escape_string($imageSize['mime']);
}
$query=mysql_query("INSERT INTO pictures (`id`, `imagedata`, `imageext`) VALUES ('', '$imageData', '$imageext');");
echo $imageext;
?>
The only problem is that the PHP page cant find the variable Image1 which is the name of the input in the form. Have I done something wrong. I was thinking that maybe in the data parameter in the Ajax it would be something like this but correct:
data: "Image1"=formData,
Is that a thing, if not why cant my PHP see that input field?
You forgot cache and contentType properties in your Ajax function. Try that it should work :
var formData = new FormData($('form')[0]);
$.ajax({
type: "POST",
url: "saveImage.php",
processData: false,
contentType: false,
cache:false,
data: formData,
success: function(data){
console.log(data);
}
});

codeigniter or PHP - how to go to a URL after a specific AJAX POST submission

I am successfully inserting data into my database in codeigniter via a an ajax post from javascript:
//JAVASCRIPT:
$.ajax({
type: "POST",
url: submissionURL,
data: submissionString,
failure: function(errMsg) {
console.error("error:",errMsg);
},
success: function(data){
$('body').append(data); //MH - want to avoid this
}
});
//PHP:
public function respond(){
$this->load->model('scenarios_model');
$responseID = $this->scenarios_model->insert_response();
//redirect('/pages/view/name/$responseID') //MH - not working, so I have to do this
$redirectURL = base_url() . 'pages/view/name/' . $responseID;
echo "<script>window.location = '$redirectURL'</script>";
}
But the problem is that I can't get codeigniter's redirect function to work, nor can I get PHP's header location method to work, as mentioned here:
Redirect to specified URL on PHP script completion?
either - I'm guessing this is because the headers are already sent? So as you can see, in order to get this to work, I have to echo out a script tag and dynamically insert it into the DOM, which seems janky. How do I do this properly?
Maybe you can 'return' the url in respond function and use it in js
PHP :
public function respond(){
// code
$redirectURL = base_url() . 'pages/view/name/' . $responseID;
return json_encode(['url' => $redirectURL]);
}
JS :
$.ajax({
type: "POST",
url: submissionURL,
data: submissionString,
dataType: 'JSON',
failure: function(errMsg) {
console.error("error:",errMsg);
},
success: function(data){
window.location = data.url
}
});
you have to concatenate the variable. That's all.
redirect('controller_name/function_name/parameter/'.$redirectURL);

AJAX not coming up a success even though its updating the database

My php is updating the table but not refreshing in javascript have tried several different ways of doing this and nothing is working.
PHP
$sql = "UPDATE INTOXDM.ASTP_FORM SET SUPERVISOR_EID = '".$newSuper."' WHERE FORMID = '".$formId."'";
$row = $xdm->fetch($sql);
$return["color"] = $row['APPRENTICE_SIGNATURE'];
$return["json"] = json_encode($return);
echo json_encode($return);
?>
Javascipt
var data = {
"formId": formID,
"newSuper": newSuper
};
data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
success: function() {
location.reload();
}
});
I'd start by modifing the code like this:
var data = {
"formId": formID,
"newSuper": newSuper
};
// No need for serialization here,
// the 'data' parameter of jQuery.ajax accepts JS object
// data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
// As suggested by Rocket Hazmat, try to add an error callback here
error: function(jQueryXHR, textStatus, errorMessage) {
console.log("Something went wrong " + errorMessage);
},
success: function(jsonResponse) {
// Try to reference the location object from document/window
// wd = document or window as seen here http://stackoverflow.com/questions/2624111/preferred-method-to-reload-page-with-javascript
// Also watch out, usually browsers require a user confirmation before reloading if the page contains POST data
// One of these should be fine
wd.location.assign(wd.location.href) : go to the URL
wd.location.replace(wd.location.href) : go to the URL and replace previous page in history
wd.location.reload(<true/false/blank>) : reload page from server/cache/cache
}
});
Also, this might be a shot in the dark but the parameter dataType gave me problems sometime in the past, so if you are sure about the json returned by your php script, you could use the eval function to jsonify the response
$.ajax({
...
// Remove data type
// dataType: "json",
...
success: function(plainTextResponse) {
// Eval response, NOT SAFE! But working
var jsonResponse = eval('('+ plainTextResponse +')');
...
}
});
Your ajax is expecting json data and your php is sending malformed json string. Send a correct json string and your script will work fine.
Your php json_encode should be like this:
$data = json_encode($return);
echo $data;

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