How to extract specific words from a string with some patterns?

How to extract specific words from a string with some patterns? - javascript

I am trying to extract some strings from a word with some pattern like -
"38384-1-page1-2222", "1-22-page33-02", "99-222-frontpage-111"
how will I extract all word between - separately, means first word before - and then second word between - and - and so on...
string = "38384-1-page1-2222";
string.substr(0, string.indexof("-")); //return 38384
But how will I extract 1, page1 and 2222 all the words separately?

The javascript function str.split(separator) split the string by the given separator and it returns an array of all the splited string. REF Here
Here is an example following your question :
var string = "38384-1-page1-2222";
var separator = "-";
var separated = string.split(separator);
var firstString = separated[0]; // will be '38384'
var secondString = separated[1]; // will be '1'
var thirdString = separated[2]; // will be 'page1'
/* And So on ... */

Hope this can help
Use String.prototype.split() to get your string into array
var words = ["38384-1-page1-2222", "1-22-page33-02", "99-222-frontpage-111"];
var resultArray = [];
for (let i = 0; i < words.length;i++) {
let temp = words[i];
resultArray = pushArray(temp.split("-"), resultArray)
}
console.log(resultArray)
function pushArray (inputArray, output) {
for (let i = 0; i < inputArray.length;i++) {
output.push(inputArray[i]);
}
return output;
}
Or simply use Array.prototype.reduce()
var words = ["38384-1-page1-2222", "1-22-page33-02", "99-222-frontpage-111"];
var result = words.reduce((previousValue, currentValue) => previousValue.concat(currentValue.split("-")), [])
console.log(result)

You can use regex /[^-]+/g
const words = ["38384-1-page1-2222", "1-22-page33-02", "99-222-frontpage-111"];
console.log(words.map(v=>v.match(/[^-]+/g)).flat())

Related

Finding common strings in javascript

I am trying to find common strings in given two strings.
Example:
string1 = "mega,cloud,two,website,final"
string2 = "window,penguin,literature,network,fun,cloud,final,sausage"
answer = "cloud,final,two"
So far this is what i got:
function commonWords(first, second) {
var words = first.match(/\w+/g);
var result = "";
words.sort();
for(var i = 0; i < words.length; i++){
if(second.includes(words[i])){
result = result.concat(words[i]);
result += ",";
}
}
result = result.substr(0, result.length -1);
return result;
}
But the result that i got is :
answer = cloud,final
Can you help me out please? First time asking question on StackOverFlow, so sorry for the typing.

What I would do is first split on the two strings, then do a reduce and check if the other string includes the current string. If so add them to a new array.
const string1 = "mega,cloud,two,website,final"
const string2 = "window,penguin,literature,network,fun,cloud,final,sausage"
const array1 = string1.split(',')
const array2 = string2.split(',')
const result = array1.reduce((arr, val) => array2.includes(val) ? arr.concat(val) : arr, [])
console.log(result)
// Convert it to a string if desired
console.log(result.toString())

Try the following:
string1 = "mega,cloud,two,website,final"
string2 = "window,penguin,literature,network,fun,cloud,final,sausage";
var arr1= string1.split(",");
var arr2 = string2.split(",");
var result = [];
arr1.forEach(function(str){
arr2.forEach(function(str2){
if(str2.indexOf(str) != -1)
result.push(str);
});
});
var answer = result.join(",");
console.log(answer);

The problem with your function is you also converting the string to into second as an array.
function commonWords(first, second) {
var words = first.match(/\w+/g); // word is a array type
var result = "";
words.sort();
for(var i = 0; i < words.length; i++){
if(second.includes(words[i])){ //second should be string type
result = result.concat(words[i]);
result += ",";
}
}
result = result.substr(0, result.length -1);
return result;
}
Or you can try this
first = "mega,cloud,two,website,final"
second = "window,penguin,literature,network,fun,cloud,final,sausage"
function commonWords(first, second) {
var words = first.match(/\w+/g);
var result = "";
words.sort();
for(var i = 0; i < words.length; i++){
if(second.includes(words[i])){
result = result.concat(words[i]);
result += ",";
}
}
result = result.substr(0, result.length -1);
return result;
}
console.log(commonWords(first, second));

I would convert each string to an array of words with .split(','). Then filter the first array with .filter by checking if each item of the array is in the other one:
string1 = "mega,Cloud,two,website,final"
string2 = "window,penguin,literature,network,fun,cloud,final,sausage"
array1 = string1.toLowerCase().split(',')
array2 = string2.toLowerCase().split(',')
var a = array1.filter(word => -1 !== array2.indexOf(word));
console.log(a)
Before converting the string to an array I have applied .toLowerCase() so that the script can return cloud in the result if it appears in the first one as "Cloud" and in the second as "cloud"

Json from string using regular expression

I have a string like:
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
I want to create JSON from above stringVar:
{
":21:" : "9077f1722efa3632",
":12:" : "700",
":27A:": "2/2",
":21A:": "9077f1722efa3632",
":27:" : "1/2",
":40A:": "IRREVOCABLE"
}
So, I was thinking I could split with regular expression (":(any Of char/digit):")
I would make the first part the key and the second part its value.

The regular expression /(:\w+:)(\S+)/ matches the whole key:value pair. You can add the g modifier, and then use it in a loop to get all the matches and put them into the object.
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
var regexp = /(:\w+:)(\S+)/g;
var obj = {};
var match;
while (match = regexp.exec(stringVar)) {
obj[match[1]] = match[2];
}
console.log(obj);
If you want to create an array of {key: ":20:", value: "9077f1722efa3632"}, you can modify the code to:
const stringVar = ":20:9077f1722efa3632 :12:700 :77E: :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE"
var regexp = /(:\w+:)(\S+)/g;
var array = [];
var match;
while (match = regexp.exec(stringVar)) {
array.push({key: match[1], value: match[2]});
}
console.log(array);
If the values can contain space, change the regexp to:
/(:\w+:)([^:]+)\s/g
This will match anything not containing : as the value, but not include the last space.

You can achieve the same result without using regex.
const stringVar = ":20:9077f1722efa3632 :12:700 :77E:xxx :27A:2/2 :21A:9077f1722efa3632 :27:1/2 :40A:IRREVOCABLE";
const result = stringVar
.split(' ')
.reduce((ret, current) => {
const pos = current.indexOf(':', 1);
ret[current.substring(0, pos + 1)] = current.substring(pos + 1);
return ret;
}, {});
console.log(result);

Remove duplicate in a string - javascript

I have a string in javascript where there are a lot of duplicates. For example I have:
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double"
What can I do to delete duplicates and to get for example x="Int32,Double"?

With Set and Array.from this is pretty easy:
Array.from(new Set(x.split(','))).toString()
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double"
x = Array.from(new Set(x.split(','))).toString();
document.write(x);

If you have to support current browsers, you can split the array and then filter it
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double";
var arr = x.split(',');
x = arr.filter(function(value, index, self) {
return self.indexOf(value) === index;
}).join(',');
document.body.innerHTML = x;

Use new js syntax remove Dupicate from a string.
String.prototype.removeDuplicate = Function() {
const set = new Set(this.split(','))
return [...set].join(',')
}
x.removeDuplicate()

function myFunction(str) {
var result = "";
var freq = {};
for(i=0;i<str.length;i++){
let char = str[i];
if(freq[char]) {
freq[char]++;
} else {
freq[char] =1
result = result+char;
}
}
return result;
}

That is a more readable and better parameterized solution:
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double"
var removeDup = [...new Set(x.split(","))].join(",");
//result "Int32,Double"

Check This out -
removeDuplicates() function takes a string as an argument and then the string split function which is an inbuilt function splits it into an array of single characters. Then the arr2 array which is empty at beginning, a forEach loop checks for every element in the arr2 - if the arr2 has the element it will not push the character in it, otherwise it will push. So the final array returned is with unique elements. Finally we join the array with the join() method to make it a string.
const removeDuplicates = (str) => {
const arr = str.split("");
const arr2 = [];
arr.forEach((el, i) => {
if (!arr2.includes(el)) {
arr2.push(el);
}
});
return arr2.join("").replace(",", "").replace("", " ");
};
console.log(removeDuplicates( "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double"));

Its simple just remove duplicates in string using new Set and join them.
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double";
console.log([...new Set(x)].join(""));

function removeDups(s) {
let charArray = s.split("");
for (let i = 0; i < charArray.length; i++) {
for (let j = i + 1; j < charArray.length; j++)
if (charArray[i] == charArray[j]) {
charArray.splice(j, 1);
j--;
}
}
return charArray.join("");
}
console.log(removeDups("Int32,Int32,Int32,InInt32,Int32,Double,Double,Double"));

You can use Set()
const result = Array.from(new Set(x)).join('')
var x = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double"
const result = Array.from(new Set(x)).join('')
console.log(result)

you can use the replaceAll function:
let str = "/Courses/"
let newStr = str.replaceAll('/', '')
console.log(newStr) // result -> Courses

function removeDuplicate(x)
{
var a = x.split(',');
var x2 = [];
for (var i in a)
if(x2.indexOf(a[i]) == -1) x2.push(a[i])
return x2.join(',');
}

const str = "Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Int32,Double,Double,Double";
const usingSpread = [...str]
const duplicatesRemove = [...new Set(usingSpread)]
const string = duplicatesRemove.join("")
console.log("After removing duplicates: " + string)
STEPS
convert string to character array using spread operator
new Set will implicitly remove duplicate character
convert character array to string using join("") method

Split string into array by several delimiters

Folks,
I have looked at underscore.string and string.js modules and still can't find a good way to do the following:
Suppose I have a query string string:
"!dogs,cats,horses!cows!fish"
I would like to pass it to a function that looks for all words that start with !, and get back an Array:
['dogs','cows','fish']
Similarly, the same function should return an array of words that start with ,:
['cats','horses]
Thanks!!!

You can use RegEx to easily match the split characters.
var string = "!dogs,cats,horses!cows!fish";
var splitString = string.split(/!|,/);
// ["dogs", "cats", "horses", "cows", "fish"]
The only issue with that is that it will possibly add an empty string at the beginning of the array if you start it with !. You could fix that with a function:
splitString.forEach(function(item){
if(item === ""){
splitString.splice(splitString.indexOf(item), 1)
}
});
EDIT:
In response to your clarificaiton, here is a function that does as you ask. It currently returns an object with the values commas and exclaim, each with an array of the corresponding elements.
JSBin showing it working.
function splitString(str){
var exclaimValues = [];
var expandedValues = [];
var commaValues = [];
var needsUnshift = false;
//First split the comma delimited values
var stringFragments = str.split(',');
//Iterate through them and see if they contain !
for(var i = 0; i < stringFragments.length; i++){
var stringValue = stringFragments[i];
// if the value contains an !, its an exclaimValue
if (stringValue.indexOf('!') !== -1){
exclaimValues.push(stringValue);
}
// otherwise, it's a comma value
else {
commaValues.push(stringValue);
}
}
// iterate through each exclaim value
for(var i = 0; i < exclaimValues.length; i++){
var exclaimValue = exclaimValues[i];
var expandedExclaimValues = exclaimValue.split('!');
//we know that if it doesn't start with !, the
// the first value is actually a comma value. So move it
if(exclaimValue.indexOf('!') !== 0) commaValues.unshift(expandedExclaimValues.shift());
for(var j = 0; j < expandedExclaimValues.length; j++){
var expandedExclaimValue = expandedExclaimValues[j];
//If it's not a blank entry, push it to our results list.
if(expandedExclaimValue !== "") expandedValues.push(expandedExclaimValue);
}
}
return {comma: commaValues, exclaim: expandedValues};
}
So if we do:
var str = "!dogs,cats,horses!cows!fish,comma!exclaim,comma2,comma3!exclaim2";
var results = splitString(str)
results would be:
{
comma: ["comma3", "comma", "horses", "cats", "comma2"],
exclaim: ["dogs", "cows", "fish", "exclaim", "exclaim2"]
}

Extract specific substring using javascript?

If I have the following string:
mickey mouse WITH friend:goofy WITH pet:pluto
What is the best way in javascript to take that string and extract out all the "key:value" pairs into some object variable? The colon is the separator. Though I may or may not be able to guarantee the WITH will be there.

var array = str.match(/\w+\:\w+/g);
Then split each item in array using ":", to get the key value pairs.
Here is the code:
function getObject(str) {
var ar = str.match(/\w+\:\w+/g);
var outObj = {};
for (var i=0; i < ar.length; i++) {
var item = ar[i];
var s = item.split(":");
outObj[s[0]] = s[1];
}
return outObj;
}

myString.split(/\s+/).reduce(function(map, str) {
var parts = str.split(":");
if (parts.length > 1)
map[parts.shift()] = parts.join(":");
return map;
}, {});

Maybe something like
"mickey WITH friend:goofy WITH pet:pluto".split(":")
it will return the array, then Looping over the array.

The string pattern has to be consistent in one or the other way atleast.
Use split function of javascript and split by the word that occurs in common(our say space Atleast)
Then you need to split each of those by using : as key, and get the required values into an object.
Hope that's what you were long for.

You can do it this way for example:
var myString = "mickey WITH friend:goofy WITH pet:pluto";
function someName(str, separator) {
var arr = str.split(" "),
arr2 = [],
obj = {};
for(var i = 0, ilen = arr.length; i < ilen; i++) {
if ( arr[i].indexOf(separator) !== -1 ) {
arr2 = arr[i].split(separator);
obj[arr2[0]] = arr2[1];
}
}
return obj;
}
var x = someName(myString, ":");
console.log(x);

Develop Reference

JavaScript is the programming language of the Web.

How to extract specific words from a string with some patterns? - javascript

You can use regex /[^-]+/g const words = ["38384-1-page1-2222", "1-22-page33-02", "99-222-frontpage-111"]; console.log(words.map(v=>v.match(/[^-]+/g)).flat())

Related

Finding common strings in javascript

Json from string using regular expression

Remove duplicate in a string - javascript

Split string into array by several delimiters

Extract specific substring using javascript?

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