I am trying to group the people by their age and as you can see, my code works with the reduce method. I managed to get this working but now I want to do the same with forEach method. Here's my code:
{name:'Kyle', age:42},
{name:'Suk', age:34},
{name:'Lol', age:35},
{name:'Pol', age:23},
{name:'Kol', age:23}
]
people.reduce((groupedPeople, person)=>{
const age = person.age
if(groupedPeople[age] == null) {groupedPeople[age]=[]
}
groupedPeople[age].push(person)
return groupedPeople
})
Reduce accepts initial value that you update each iteration and return. So if you wish to use forEach, just move initial value before the forEach:
const people = [{
name: 'Kyle',
age: 42
},
{
name: 'Suk',
age: 34
},
{
name: 'Lol',
age: 35
},
{
name: 'Pol',
age: 23
},
{
name: 'Kol',
age: 23
}
]
const groupedPeople = {}
people.forEach((person) => {
const age = person.age
if (groupedPeople[age] == null) {
groupedPeople[age] = []
}
groupedPeople[age].push(person)
})
console.log(groupedPeople)
However, I am not sure why you wish to do that. Code with reduce is much cleaner.
Why forEach is just reduce with an accumulative value. Might as well be "global".
var people = [
{name:'Kyle', age:42},
{name:'Suk', age:34},
{name:'Lol', age:35},
{name:'Pol', age:23},
{name:'Kol', age:23}
];
var result = people.reduce((groupedPeople, person) => {
const age = person.age
if (groupedPeople[age] == null) {
groupedPeople[age] = []
}
groupedPeople[age].push(person)
return groupedPeople
}, {}) // <---- you forgot this {}
console.log(result)
var result = {};
people.forEach(function(person) {
if (result[person.age] == null) {
result[person.age] = []
}
result[person.age].push(person)
})
console.log(result)
.as-console-wrapper {
max-height: 100%!important;
top: 0;
}
Related
I am new to react, I have an object and an array, I want to get details of unmatched items from the object when compared with array values. I tried but shows all the data when consol.log. here is my code
var content:[
0:{id:20, name:'Jack Daniel'}
1:{id:21, name:'Sophie McDonald'}
2:{id:22, name:'Jason Thomas'}
3:{id:23, name:'Chris Williams'}
]
var filter:[Sophie McDonald, Chris Williams]
filterValues = content.filter(item=> {
for(var i = 0;i<filter.length;i++) {
if (item.name === filtered[i])
{
return item
}
}
});
console.log(filteredValues)
// returns 0:{id:21, name:'Sophie McDonald'}
// 1:{id:23, name:'Chris Williams'}
But I need unmatched results,
filterValues = content.filter(item=> {
for(var i = 0;i<filter.length;i++) {
if (item.name !== filtered[i])
{
return item
}
}
});
console.log(filteredValues)
// returns 0:{id:20, name:'Jack Daniel'}
// 1:{id:21, name:'Sophie McDonald'}
// 2:{id:22, name:'Jason Thomas'}
// 3:{id:23, name:'Chris Williams'}
Result must be
0:{id:20, name:'Jack Daniel'}
1:{id:22, name:'Jason Thomas'}
Try using filter, checking if the values of the array are present in your object values:
const content = [{
id: 20,
name: 'Jack Daniel'
},
{
id: 21,
name: 'Sophie McDonald'
},
{
id: 22,
name: 'Jason Thomas'
},
{
id: 23,
name: 'Chris Williams'
}
];
const values = ['Sophie McDonald', 'Chris Williams'];
const filteredValues = content.filter(({
name
}) => !values.includes(name));
console.log(filteredValues);
Seems to work with a few edits to the format:
let content = [
{id:20, name:'Jack Daniel'},
{id:21, name:'Sophie McDonald'},
{id:22, name:'Jason Thomas'},
{id:23, name:'Chris Williams'}
]
let filter = ["Sophie McDonald", "Chris Williams"]
let filterValues = content.filter(item=> {
for(var i = 0;i<filter.length;i++) {
if (item.name !== filter[i]){
return item
}
}
});
console.log(filterValues)
I'm given the following JavaScript object:
{
name: [
{
"firstName":"First ",
"lastName":"Last"
}
],
age: 21
}
The name property (or other similar complex props) are always provided as an object within an array, even though there can only ever be a single value.
I need to save the information as an object that looks like this (without the array around the value of the name property):
{
name: {
firstName: 'First ',
lastName: 'Last'
},
age: 21
}
I need a generic function that doesn't reference a particular property name because that changes depending on the query. Here's my solution:
const object = {
name: [{"firstName":"First ","lastName":"Last"}],
age: 21
}
const data = {}
for (const property in object) {
const value = object[property]
if (Array.isArray(value)) {
data[property] = value[0]
} else {
data[property] = value
}
}
Which returns the properly formatted object.
My question is whether this is the most performant and/or most obvious way to get the result I'm looking for?
If you want abstraction over the entire object you could do something like this:
const object1 = {
name: [{"firstName":"First ","lastName":"Last"}],
age: 21
}
const rebuildObject = (object) => Object.keys(object).reduce((result, key) => {
const value = object[key];
result[key] = Array.isArray(value) ? object[key][0] : value;
return result;
}, {});
const newObject = rebuildObject(object1);
console.log(newObject);
If the name array is guaranteed to only ever have 1 object inside of it and is always an array, you can do:
const data = {
name: [
{
"firstName":"First ",
"lastName":"Last"
}
],
age: 21
};
if(data.name.length === 0) {
const newObj = {
name: data.name[0],
age: data.age
};
};
console.log(newObj); // { firstName: 'First ', lastName: 'Last', age: 21 }
Edit
When name is actually any arbitray key name, you can do:
const data = {
name: [
{
"firstName":"First ",
"lastName":"Last"
}
],
age: 21
};
const objKeys = Object.keys(data);
console.log(objKeys) // > Array ["name", "age"]
let arbKey = objKeys.filter(objKey => objKey !== "age")[0];
console.log(arbKey); // > "name"
const newObj = {
arbKey: data[arbKey][0],
age: data.age
};
console.log(newObj); // > Object { arbKey: Object { firstName: "First ", lastName: "Last" }, age: 21 };
Note: This only works based on the object schema you have provided. If your actual code is different, you will need to tweak it.
this is a generic function that can serve what you need, call the function with the object and property name you want to transform.
function arrayToObject(object, property) {
if(object[property] && Array.isArray(object[property])) {
object[property] = object[property][0];
}
return object;
}
// let data = {
// name: [
// {
// "firstName":"First ",
// "lastName":"Last"
// }
// ],
// age: 21
// }
// console.log(arrayToObject(data, 'name'));
// { name: { firstName: 'First ', lastName: 'Last' }, age: 21 }
update:
in case we don't know the property name,
we can use this version.
function arrayToObject(object) {
for(let key in object){
if(Array.isArray(object[key])) {
object[key] = object[key][0];
}
}
return object;
}
let a = {
name: [
{
"firstName":"First ",
"lastName":"Last"
}
],
age: 21
}
a.name = a.name[0];
I have some code that should loop through an array of objects and if the name value is repeated anywhere in array, the code should display "repeatedName". If not "not repeatedName".
export default function App() {
const arr = [
{
name: "John",
age: 22
},
{
name: "Julia",
age: 28
},
{
name: "John",
age: 22
},
{
name: "Bill",
age: 22
}
];
return (
<div className="App">
{arr.map((i, k) => (
<p>
{arr[k + 1] !== undefined && i.name === arr[k + 1].name
? "repeatedName"
: "not repeatedName"}
</p>
))}
</div>
);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>
Now i get this:
not repeatedName
not repeatedName
not repeatedName
not repeatedName
But the expected result is:
not repeatedName
not repeatedName
repeatedName
not repeatedName
demo: https://codesandbox.io/s/unruffled-shaw-0mdxi?file=/src/App.js:450-462
How to change my code to get the described result?
In order to get the duplicates, you will need to store the unique names in another array, then reference that array within the loop of the object.
The following will loop through the object and add the name of the person to the array. Then when it continues through the loop, the name is checked with names we already know about.
const uniqueNames = []
const people = [
{
name: "John",
age: 22
},
{
name: "Julia",
age: 28
},
{
name: "John",
age: 22
},
{
name: "Bill",
age: 22
}
]
people.forEach((person) => {
if (uniqueNames.indexOf(person.name) > -1) {
console.log('Repeated')
return
}
uniqueNames.push(person.name)
console.log('Not repeated')
})
Here's another take on the task (just for the heck of it):
(Carl's solution is a more elegant one)
const arr = [
{
name: "John",
age: 22
},
{
name: "Julia",
age: 28
},
{
name: "John",
age: 22
},
{
name: "Bill",
age: 22
}
];
return (
<div className="App">
{arr.map((i,k)=>{
const isFound = k-1 > 0 && arr.slice(0, k-1).some( el => {
return el.name === i.name;
})
return isFound ? <p>repeatedName</p> : <p>not repeatedName</p>
})}
</div>
);
}
Assuming you want to check if the name previously appeared anywhere in the array, you can do this with map - but it's going to look fairly clumsy and inelegant:
{arr.map((i, k) => (
<p>
{arr[k - 1] !== undefined && arr.slice(0, k).some(obj => obj.name === arr[k].name)
? "repeatedName"
: "not repeatedName"}
</p>
))}
Although I am in general a fan of the "functional style" using map and so on, here I think it's more appropriate to use a more imperative style with a loop and some internal state:
const getRepeatedStates = arr => {
const names = [];
const result = [];
for (let i = 0; i < arr.length; i++) {
const currentName = arr[i].name;
result.push(names.includes(currentName) ? "repeatedName" : "not repeatedName";
names.push(currentName);
}
return result;
}
And then in your returned JSX, use
{getRepeatedStates(arr).map(text => (<p>{text}</p>)}
There is a handy JavaScript object that makes it very easy to identify duplicates like these.
It's called Set. Use Set.prototype.add() to add to the set, and Set.prototype.has() to determine if a value is in the set. A value can exist only once in a Set.
const arr = [
{ name: "John", age: 22 },
{ name: "Julia", age: 28 },
{ name: "John", age: 22 },
{ name: "Bill", age: 22 }
];
const nameSet = new Set();
let nameStats = arr.map(el => {
let status = nameSet.has(el.name) ?
"repeatedName" : "not repeatedName";
nameSet.add(el.name);
return status;
});
console.log('nameStats:', nameStats);
hi I am trying to create a object map from array of objects using reduce method but did n't find a way to add 2 properties as key . Let say I have array of objects like -
const students = [
{
name: "sam",
age: 26,
},
{
name: 'john",
age: 30,
}
]
i am trying to create a map like
{
sam_26:{
name: "sam",
age: 26,
}
}
my code for reduce function :
students.reduce((obj, student) => {
`${obj[student.name]}_${obj[student.age]}` = student;
return obj;
}, {});
this didn't work . any pointers will be helpful ..thanks!
Create the key with the values taken from the student object. Assign the current student to the obj (the accumulator) using the key:
const students = [{
name: "sam",
age: 26,
},
{
name: "john",
age: 30,
}
];
const result = students.reduce((obj, student) => {
const key = `${student.name}_${student.age}`;
obj[key] = student;
return obj;
}, {});
console.log(result);
A generic approach that uses a callback to create the key:
const keyBy = (arr, cb) =>
arr.reduce((r, o) => {
const key = cb(o);
r[key] = o;
return r;
}, {});
const students = [{"name":"sam","age":26},{"name":"john","age":30}];
const result = keyBy(students, (o) => `${o.name}_${o.age}`);
console.log(result);
You can't assign to the left side with a template literal like that. Try defining the property first, and then assigning it to the object:
const students = [ { name: "sam", age: 26, }, { name: 'john', age: 30, } ];
const finalObj = students.reduce((obj, student) => {
const prop = `${student.name}_${student.age}`;
obj[prop] = student;
return obj;
}, {});
console.log(finalObj);
Hopefully this snippet will be useful
const students = [{
name: "sam",
age: 26,
},
{
name: "john",
age: 30,
}
]
//Using reduce function to add value to the accumalator
var x = students.reduce(function(acc, curr, index) {
// Here acc is the object which is passed as argument,
//In this object checking if it has a key like sam_26 & so on
if (!acc.hasOwnProperty([curr['name'] + '_' + curr['age']])) {
//if not then add the key and add relevant vakues to it
acc[curr.name + '_' + curr.age] = {
name: curr.name,
age: curr.age
}
}
return acc;
}, {});
console.log(x)
I tried this script and it worked. Simply create variable name based on student name and age then assign back to the object
students.reduce((obj, student) => {
var name = student.name + '-' + student.age;
obj[name] = student;
return obj;
}, {});
I'm learning JS. Supposing I have the below array of objects:
var family = [
{
name: "Mike",
age: 10
},
{
name: "Matt"
age: 13
},
{
name: "Nancy",
age: 15
},
{
name: "Adam",
age: 22
},
{
name: "Jenny",
age: 85
},
{
name: "Nancy",
age: 2
},
{
name: "Carl",
age: 40
}
];
Notice that Nancy is showing up twice (changing only the age). Supposing I want to output only unique names. How do I output the above array of objects, without duplicates? ES6 answers more than welcome.
Related (couldn't find a good way for usage on objects):
Remove Duplicates from JavaScript Array
Easiest way to find duplicate values in a JavaScript array
EDIT Here's what I tried. It works well with strings but I can't figure how to make it work with objects:
family.reduce((a, b) => {
if (a.indexOf(b) < 0 ) {
a.push(b);
}
return a;
},[]);
You could use a Set in combination with Array#map and a spread operator ... in a single line.
Map returns an array with all names, which are going into the set initializer and then all values of the set are returned in an array.
var family = [{ name: "Mike", age: 10 }, { name: "Matt", age: 13 }, { name: "Nancy", age: 15 }, { name: "Adam", age: 22 }, { name: "Jenny", age: 85 }, { name: "Nancy", age: 2 }, { name: "Carl", age: 40 }],
unique = [...new Set(family.map(a => a.name))];
console.log(unique);
For filtering and return only unique names, you can use Array#filter with Set.
var family = [{ name: "Mike", age: 10 }, { name: "Matt", age: 13 }, { name: "Nancy", age: 15 }, { name: "Adam", age: 22 }, { name: "Jenny", age: 85 }, { name: "Nancy", age: 2 }, { name: "Carl", age: 40 }],
unique = family.filter((set => f => !set.has(f.name) && set.add(f.name))(new Set));
console.log(unique);
The Solution
Store occurrences of name external to the loop in an object, and filter if there's been a previous occurrence.
https://jsfiddle.net/nputptbb/2/
var occurrences = {}
var filteredFamily = family.filter(function(x) {
if (occurrences[x.name]) {
return false;
}
occurrences[x.name] = true;
return true;
})
you can also generalize this solution to a function
function filterByProperty(array, propertyName) {
var occurrences = {}
return array.filter(function(x) {
var property = x[propertyName]
if (occurrences[property]) {
return false;
}
occurrences[property]] = true;
return true;
})
}
and use it like
var filteredFamily = filterByProperty(family, 'name')
Explanation
Don't compare objects using indexOf, which only uses the === operator between objects. The reason why your current answer doesn't work is because === in JS does not compare the objects deeply, but instead compares the references. What I mean by that you can see in the following code:
var a = { x: 1 }
var b = { x: 1 }
console.log(a === b) // false
console.log(a === a) // true
Equality will tell you if you found the same exact object, but not if you found an object with the same contents.
In this case, you can compare your object on name since it should be a unique key. So obj.name === obj.name instead of obj === obj. Moreover another problem with your code that affects its runtime and not its function is that you use an indexOf inside of your reduce. indexOf is O(n), which makes the complexity of your algorithm O(n^2). Thus, it's better to use an object, which has O(1) lookup.
This will work fine.
const result = [1, 2, 2, 3, 3, 3, 3].reduce((x, y) => x.includes(y) ? x : [...x, y], []);
console.log(result);
With the code you mentioned, you can try:
family.filter((item, index, array) => {
return array.map((mapItem) => mapItem['name']).indexOf(item['name']) === index
})
Or you can have a generic function to make it work for other array of objects as well:
function printUniqueResults (arrayOfObj, key) {
return arrayOfObj.filter((item, index, array) => {
return array.map((mapItem) => mapItem[key]).indexOf(item[key]) === index
})
}
and then just use printUniqueResults(family, 'name')
(FIDDLE)
I just thought of 2 simple ways for Lodash users
Given this array:
let family = [
{
name: "Mike",
age: 10
},
{
name: "Matt",
age: 13
},
{
name: "Nancy",
age: 15
},
{
name: "Adam",
age: 22
},
{
name: "Jenny",
age: 85
},
{
name: "Nancy",
age: 2
},
{
name: "Carl",
age: 40
}
]
1. Find duplicates:
let duplicatesArr = _.difference(family, _.uniqBy(family, 'name'), 'name')
// duplicatesArr:
// [{
// name: "Nancy",
// age: 2
// }]
2 Find if there are duplicates, for validation purpose:
let uniqArr = _.uniqBy(family, 'name')
if (uniqArr.length === family.length) {
// No duplicates
}
if (uniqArr.length !== family.length) {
// Has duplicates
}
Since most of the answers won't have a good performance, i thought i share my take on this:
const arrayWithDuplicateData = [{ id: 5, name: 'Facebook'}, { id: 3, name: 'Twitter' }, { id: 5, name: 'Facebook' }];
const uniqueObj = {};
arrayWithDuplicateData.forEach(i => {
uniqueObj[i.id] = i;
});
const arrayWithoutDuplicates = Object.values(uniqueObj);
We're leveraging the fact that keys are unique within objects. That means the last duplication item inside the first array, will win over its predecessors. If we'd want to change that, we could flip the array before iterating over it.
Also we're not bound to use only one property of our object for identifying duplications.
const arrayWithDuplicateData = [{ id: 5, name: 'Facebook'}, { id: 3, name: 'Twitter' }, { id: 5, name: 'Facebook' }];
const uniqueObj = {};
arrayWithDuplicateData.forEach(item => {
uniqueObj[`${item.id}_${item.name}`] = item;
});
const arrayWithoutDuplicates = Object.values(uniqueObj);
Or we could simply add a check, if the uniqueObj already holds a key and if yes, not overwrite it.
Overall this way is not very costly in terms of performance and served me well so far.
I would probably set up some kind of object. Since you've said ECMAScript 6, you have access to Set, but since you want to compare values on your objects, it will take a little more work than that.
An example might look something like this (removed namespace pattern for clarity):
var setOfValues = new Set();
var items = [];
function add(item, valueGetter) {
var value = valueGetter(item);
if (setOfValues.has(value))
return;
setOfValues.add(value);
items.push(item);
}
function addMany(items, valueGetter) {
items.forEach(item => add(item, valueGetter));
}
Use it like this:
var family = [
...
];
addMany(family, item => item.name);
// items will now contain the unique items
Explanation: you need to pull a value from each object as it's added and decide if it has already been added yet, based on the value you get. It requires a value getter, which is a function that given an item, returns a value (item => item.name). Then, you only add items whose values haven't already been seen.
A class implementation:
// Prevents duplicate objects from being added
class ObjectSet {
constructor(key) {
this.key = key;
this.items = [];
this.set = new Set();
}
add(item) {
if (this.set.has(item[this.key])) return;
this.set.add(item[this.key]);
this.items.push(item);
}
addMany(items) {
items.forEach(item => this.add(item));
}
}
var mySet = new ObjectSet('name');
mySet.addMany(family);
console.log(mySet.items);