I have a line of data like this:
1•#00DDDD•deeppink•1•100•true•25•100•Random\nTopics•1,2,3,0•false
in a text file.
Specifically, for my "problem", I am using Random\nTopics as a piece of text data, and I then search for '\n', and split the message up into two lines based on the placement of '\n'.
It is stored in blockObj.msg, and I search for it using blockObj.msg.split('\n'), but I kept getting an array of 1 (no splits). I thought I was doing something fundamentally wrong and spent over an hour troubleshooting, until on a whim, I tried
blockObj.msg = blockObj.msg.replace(/\\n/g, "\n")
and that seemed to solve the problem. Any ideas as to why this is needed? My solution works, but I am clueless as to why, and would like to understand better so I don't need to spend so long searching for an answer as bizarre as this.
I have a similar error when reading "text" from an input text field. If I type a '\n' in the box, the split will not find it, but using a replace works (the replace seems pointless, but apparently isn't...)
obj.msg = document.getElementById('textTextField').value.replace(/\\n/g, "\n")
Sorry if this is jumbled, long time user of reading for solutions, first time posting a question. Thank you for your time and patience!
P.S. If possible... is there a way to do the opposite? Replace a real "\n" with a fake "\n"? (I would like to have my dynamically generated data file to have a "\n" instead of a new line)
It is stored in blockObj.msg, and I search for it using blockObj.msg.split('\n'),
In a JavaScript string literal, \n is an escape sequence representing a new line, so you are splitting the data on new lines.
The data you have doesn't have new lines in it though. It has slash characters followed by n characters. They are data, not escape sequences.
Your call to replace (blockObj.msg = blockObj.msg.replace(/\\n/g, "\n")) works around this by replacing the slashes and ns with new lines.
That's an overcomplicated approach though. You can match the characters you have directly. blockObj.msg.split('\\n')
in your text file
1•#00DDDD•deeppink•1•100•true•25•100•Random\nTopics•1,2,3,0•false
means that there are characters which are \ and n thats how they are stored, but to insert a new line character by replacement, you are then searching for the \ and the n character pair.
obj.msg = document.getElementById('textTextField').value.replace(/\\n/g, "\n")
when you do the replace(/\\n/g, "\n")
you are searching for \\n this is the escaped version of the string, meaing that the replace must find all strings that are \n but to search for that you need to escape it first into \\n
EDIT
/\\n/g is the regex string..... \n is the value... so /\REGEXSTUFFHERE/g the last / is followed by regex flags, so g in /g would be global search
regex resources
test regex online
Related
I know that backslash is escape character in js. And to display one backslash, I need to write two.
But I am having express server that send request to database and here I need to add only one backslash. SO if filter contains two backslashes, replace it only with one. How to write it?
filter.replace("\\", String.fromCharCode(92)); //do two not one
filter.replace("\\", "\"); //doesn't work, syntax error
example
"aaaa\\aaaa" - > "aaaa\aaaa"
Another ideas?
---UPADTE---
The string that is send to database contains two backslashes but js GUI shows only one (of course).
How to write it?
You said it yourself:
to display one backslash, I need to write two.
So, if you have two in the string to start with, then you need to replace two (type four) with one (type two).
var filter = "This string has a double slash in it: \\\\";
console.log(`The original string: ${filter}`);
filter = filter.replace("\\\\", "\\");
console.log(`The filtered string: ${filter}`);
Quentin answered your question, but another way to think about it is that two backslashes written into a sting will resolve to a single backslash as soon as you do anything with it.
For example:
Console.Log("\");
//Returns Error
Console.Log("\\");
//Returns: \
var i = "this is a backslash \\"
//i now contains only one backslash
Console.Log(i);
//Returns: this is a backslash \
Edit:
Since you clarified that it's after this in the querying that it gets messed up, you could try making sure you've assigned it to a variable and then passed it to the query.
i = "A string containing backslashes \\"
sql.Query(i);
Edit 2:
Oh, I just got it, you're trying to escape colons ':' which is already handled in JS. So if the query isn't parsing your escape characters than just \: should be perfectly valid.
I need a little help replacing a special character in a string using a regular expression that I just can't seem to figure out.
Here is the string that I have, and the special character is a "↵". Essentially I'd like to replace every "↵" with a comma.
var string = "http://espn.com↵http://yellowpages.com↵http://reddit.com↵http://usps.com http://uber.com↵http://cnn.com↵http://w3schools.com↵http://hitch.com↵http://sdsu.com↵http://sf.com↵http://kings.com"
A little background about what I'm doing, perhaps there is an easier way to do this. I'm getting the value of a textarea where each entry (url) is typed out on a new line and trying to format it into an array of urls.
The string above is what I'm getting after getting the value of the textarea.
Thanks for any help.
If regex is not mandatory then try
string = string.split(/\n|\r|↵/).join( "," );
I need some help with Regex.
I have this string: \\lorem\ipsum\dolor,\\sit\amet\conseteteur,\\sadipscing\elitr\sed\diam
and want to get the result: ["dolor", "conseteteur", "diam"]So in words the word between the last backslash and a comma or the end.
I've already figured out a working test, but because of reasons it won't work in neitherChrome (v44.0.2403.130) nor IE (v11.0.9600.17905) console.There i'm getting the result: ["\loremipsumdolor,", "\sitametconseteteur,", "\sadipscingelitrseddiam"]
Can you please tell me, why the online testers aren't working and how i can achieve the right result?
Thanks in advance.
PS: I've tested a few online regex testers with all the same result. (regex101.com, regexpal.com, debuggex.com, scriptular.com)
The string
'\\lorem\ipsum\dolor,\\sit\amet\conseteteur,\\sadipscing\elitr\sed\diam'
is getting escaped, if you try the following in the browser's console you'll see what happens:
var s = '\\lorem\ipsum\dolor,\\sit\amet\conseteteur,\\sadipscing\elitr\sed\diam'
console.log(s);
// prints '\loremipsumdolor,\sitametconseteteur,\sadipscingelitrseddiam'
To use your original string you have to add additional backslashes, otherwise it becomes a different one because it tries to escape anything followed by a single backslash.
The reason why it works in regexp testers is because they probably sanitize the input string to make sure it gets evaluated as-is.
Try this (added an extra \ for each of them):
str = '\\\\lorem\\ipsum\\dolor,\\\\sit\\amet\\conseteteur,\\\\sadipscing\\elitr\\sed\\diam'
re = /\\([^\\]*)(?:,|$)/g
str.match(re)
// should output ["\dolor,", "\conseteteur,", "\diam"]
UPDATE
You can't prevent the interpreter from escaping backslashes in string literals, but this functionality is coming with EcmaScript6 as String.raw
s = String.raw`\\lorem\ipsum\dolor,\\sit\amet\conseteteur,\\sadipscing\elitr\sed\diam`
Remember to use backticks instead of single quotes with String.raw.
It's working in latest Chrome, but I can't say for all other browsers, if they're moderately old, it probably isn't implemented.
Also, if you want to avoid matching the last backslash you need to:
remove the \\ at the start of your regexp
use + instead of * to avoid matching the line end (it will create an extra capture)
use a positive lookahead ?=
like this
s = String.raw`\\lorem\ipsum\dolor,\\sit\amet\conseteteur,\\sadipscing\elitr\sed\diam`;
re = /([^\\]+)(?=,|$)/g;
s.match(re);
// ["dolor", "conseteteur", "diam"]
You may try this,
string.match(/[^\\,]+(?=,|$)/gm);
DEMO
I have googled this ane are really surprised not to find a ready made solution to this as I believe that it is a problem that is faced by anyone who is updating databases from forms.
Problem is the single quote that is used in text fields as an apostrophe and other instances.
So I need to find are replace all occurrences of single quotes within an SQL statement in Javascript / Nodejs before sending it to the database, this of course is not a hard-coded statement and it will be different every time, but the following includes carriage returns in the sql statement as well as spaces before and after an equal sign as well as no spaces to try and catch all occurrences.
The key thing really is the "=" followed by a single speech mark, the text to grab and the closing single speech mark followed by a space, a comma, or the word "WHERE".
I am no expert with regex, but have come up with this, which only correctly extracts a couple of the strings:
/\= *'(.*)' *[, *]/g
Would appreciate help from any of the regex experts out there :-)
update XXX set status = 'Pending's' where xx = 'xxx'
UPDATE XX_XXX
SET
SUBJECT='Test of system's', SERIAL_NUMBER='SN'1'23', SPEC='Verify order's package is complete',
DESCRIPTION='13.3/8'' Buttress Pin's ' WHERE ID='1002-15'
This should be the result:
update XXX set status = 'Pending''s' where xx = 'xxx'
UPDATE XX_XXX
SET
SUBJECT='Test of system''s', SERIAL_NUMBER='SN''1''23', SPEC='Verify order''s package is complete',
DESCRIPTION='13.3/8''' Buttress Pin''s ' WHERE ID='1002-15'
And these are the strings that need to be selected:
Pending's
Test of system's
SN'1'23
Verify order's package is complete
13.3/8'
1002-15
It is very common issue, do not need regex. Just simply replace a single quote in a string to double single quote.
This is example. Just see the comment
--This is double quote I used, because ally's wonderland not work at here.
DECLARE #StringValueWithSingleQuote varchar( 50) = 'Ally''s wonderland'
-- just see the magid, replace double single quote to single quote while displaing
select #StringValueWithSingleQuote
--This is actual you have to do
select REPLACE( #StringValueWithSingleQuote , char(39) , Char(39)+Char(39) )
I am trying to use a RegEx to search through a long string, and I am having trouble coming up with an expression. I am trying to search through some HTML for a set of tags beginning with a tag containing a certain value and ending with a different tag containing another value. The code I am currently using to attempt this is as follows:
matcher = new RegExp(".*(<[^>]+" + startText + "((?!" + endText + ").)*" + endText + ")", 'g');
data.replace(matcher, "$1");
The strangeness around the middle ( ((\\?\\!endText).)* ) is borrowed from another thread, found here, that seems to describe my problem. The issue I am facing is that the expression matches the beginning tag, but it does not find the ending tag and instead includes the remainder of the data. Also, the lookaround in the middle slowed the expression down a lot. Any suggestions as to how I can get this working?
EDIT: I understand that parsing HTML in RegEx isn't the best option (makes me feel dirty), but I'm in a time-crunch and any other alternative I can think of will take too long. It's hard to say what exactly the markup I will be parsing will look like, as I am creating it on the fly. The best I can do is to say that I am looking at a large table of data that is collected for a range of items on a range of dates. Both of these ranges can vary, and I am trying to select a certain range of dates from a single row. The approximate value of startText and endText are \\#\\#ASSET_ID\\#\\#_<YYYY_MM_DD>. The idea is to find the code that corresponds to this range of cells. (This edit could quite possibly have made this even more confusing, but I'm not sure how much more information I could really give without explaining the entire application).
EDIT: Well, this was a stupid question. Apparently, I just forgot to add .* after the last paren. Can't believe I spent so long on this! Thanks to those of you that tried to help!
First of all, why is there a .* Dot Asterisk in the beginning? If you have text like the following:
This is my Text
And you want "my Text" pulled out, you do my\sText. You don't have to do the .*.
That being said, since all you'll be matching now is what you need, you don't need the main Capture Group around "Everything". This: .*(xxx) is a huge no-no, and can almost always be replaced with this: xxx. In other words, your regex could be replaced with:
<[^>]+xxx((?!zzz).)*zzz
From there I examine what it's doing.
You are looking for an HTML opening Delimeter <. You consume it.
You consume at least one character that is NOT a Closing HTML Delimeter, but can consume many. This is important, because if your tag is <table border=2>, then you have, at minimum, so far consumed <t, if not more.
You are now looking for a StartText. If that StartText is table, you'll never find it, because you have consumed the t. So replace that + with a *.
The regex is still success if the following is NOT the closing text, but starts from the VERY END of the document, because the Asterisk is being Greedy. I suggest making it lazy by adding a ?.
When the backtracking fails, it will look for the closing text and gather it successfully.
The result of that logic:
<[^>]*xxx((?!zzz).)*?zzz
If you're going to use a dot anyway, which is okay for new Regex writers, but not suggested for seasoned, I'd go with this:
<[^>]*xxx.*?zzz
So for Javascript, your code would say:
matcher = new RegExp("<[^>]*" + startText + ".*?" + endText, 'gi');
I put the IgnoreCase "i" in there for good measure, but you may or may not want that.