I have a table with an array column called tokens
I can query it via npm sequelize with no issues, Sometimes this column may have upto 20k elements in the array which i dont always need. I need just 10 elements from it
In SQL this would be
select tokens[:10] from schema.table
How I do this using sequelize ?
This is what I'm doing now
const whereClause = {
where: { active: true },
attributes: {
exclude: ['tokens'],
include: ['tokens[:10]'],
},
};
table.findAll(whereClause);
This gives the following error
original: error: column "tokens[:10]" does not exist
It is looking for a column named "tokens[:10]" instead of taking a subset.
What am I doing wrong ?
You can use literals when you select attributes in sequelize. You can try something like this,
const whereClause = {
where: { active: true },
attributes: [
[Sequelize.literal(`tokens[:${sub-array-length}]`), 'tokens']
]
};
table.findAll(whereClause);
Note the use of colons to denote the sub-array slicing index
Related
Trying to use sequelize findAndCountAll method, to get items.
I've to use distinct, and offset with limit due to my task.
The problem is, that in associated model i've column with array type, and i need to order parent model by that array length.
My query looks like :
const { rows, count } = await this.repo.findAndCountAll({
where: { someField: someValue },
col: 'someCol',
distinct: true,
include: [
{
model: someNestedModel,
as: 'someNestedModelAssociation',
include: [{ model: someInnerNestedModel, as: 'someInnerNestedAssociation' }]
}
],
// eslint-disable-next-line #typescript-eslint/ban-ts-comment
//#ts-ignore
order: this.getOrderByOptions(sortOrder, orderBy),
limit,
offset
});
getOrderByOptions(sortOrder, orderBy) {
switch (orderBy) {
case Sort_By_Array_Length:
return Sequelize.literal('json_array_length(someModelName.someColumnWithArrayName) ASC');
default:
return [[orderBy, sortOrder]];
}
}
The problem is, that my order by query is used both in subQuery and mainQuery.
And using it into subQuery leads to error, cz there is no such field.
If i use subQuery:false flag, it works, but then i got messed with returning results, due to problems with subQuery:false and offset&limits.
So the question is, is there a way, to exclude orderBy field from subQuery?
P.S. Models have many to many association with through table.
I'm trying to count the associated entries using the separate attribute in my includes to improve performance (without it the request it's taking 5s). But I'm receiving the following error:
"message": "missing FROM-clause entry for table "likedPosts""
Sorry for bad english, it's not my first. I hope you understand and can help me.
My code:
#Query((returns) => [Post], {
nullable: true
})
async getAllFeedPostsByUserId(#Arg('user_id') user_id: number): Promise < Post[] > {
const result = await Post.findAll({
attributes: {
include: [
[Sequelize.fn("COUNT", Sequelize.col("likedPosts.feed_post")), "likesAmount"]
]
},
include: [{
model: LikedPosts,
as: 'likedPosts',
attributes: [],
separate: true,
}, ]
});
return result;
}
I think group is must to count entries.
Post.findAll({
attributes: {
include: [[Sequelize.fn('COUNT', Sequelize.col('likedPosts.feed_post')), 'likesAmount']]
},
include: [{
model: LikedPosts,
attributes: []
}],
group: ['likedPosts.feed_post'] // groupBy is necessary else it will generate only 1 record with all rows count
})
I can see seperate
separate desc
To elaborate: by default, to retrieve the related model instance, Sequelize will use a SQL JOIN. By enabling separate, Sequelize will perform a separate query for each of the associated models, and join the resulting documents in code (instead of letting the database perform the join).
// my db structure now
rcv : {
visible: 'all',
ids: [
[0] : userId,
[1] : user2Id ]
}
this is how i query to get the data it works.
//service.ts
getAlbumByUserId(userId) {
return this.afs.collection('albums', ref => ref.where('rcv.visible', '==', 'all').where('rcv.ids', 'array-contains', userId)).valueChanges();
}
//component.ts
this.service.getAlbumByUserId(this.userId);
but i want to set the structure like this but i don't know how to query nested objects in firebase
// database structure
rcv : {
visible: 'all',
ids: {
userId: {
id: userId
}
user2Id: {
id: user2Id
}
}
}
You're looking for the array-contains operator, which can check if a field that is an array contains a certain value.
You're already using the correct array-contains operator, but not with the correct syntax. The array-contains operator checks whether any element of your array is exactly the same as the value you pass in. So you need to pass in the complete value that exists in the array:
ref.where('rcv.visible', '==', 'all').where('rcv.ids', 'array-contains', { id: userId })
As you add more data to the array, it may become unfeasible to reproduce the entire array element for the query. In that case, the common approach is to add an additional field where you keep just the IDs.
So you'd end up with one field (say rcv.users) where you keep all details about the receiving users, and one field (say rcv.ids) where you just keep their IDs, and that you use for querying.
I've got a problem that I've been stuck on, to no avail - seemingly similar in nature to Where condition for joined table in Sequelize ORM, except that I'd like to query on a previous join. Perhaps code will explain my problem. Happy to provide any extra info.
Models:
A.hasMany(B);
B.belongsTo(A);
B.hasMany(C);
C.belongsTo(B);
This is what I'd like to be able to achieve with Sequelize:
SELECT *
FROM `A`AS `A`
LEFT OUTER JOIN `B` AS `B` ON `A`.`id` = `B`.`a_id`
LEFT OUTER JOIN `C` AS `B->C` ON `B`.`id` = `B->C`.`b_id`
AND (`B`.`b_columnName` = `B->C`.`c_columnName`);
This is how I imagine this working: (instead it will create a raw query (2 raw queries, for A-B/C) with AND ( `C`.`columnName` = '$B.columnName$')) on the join (second arg is a string). Have tried sequelize.col, sequelize.where(sequelize.col..., etc..)
A.findOne({
where: { id: myId },
include: [{
model: B,
include: [{
model: C,
where: { $C.c_columnName$: $B.b_columnName$ }
}]
}]
});
Use the Op.col query operator to find columns that match other columns in your query. If you are only joining a single table you can pass an object instead of an array to make it more concise.
const Op = Sequelize.Op;
const result = await A.findOne({
include: {
model: B,
include: {
model: C,
where: {
c_columnName: {
[Op.col]: 'B.b_columnName',
},
}
},
},
});
I have a document structure that looks like this:
type Document = {
_id: string
title: string
variants: VariantType[]
}
type VariantType = {
timestamp: Int
active: Boolean
content: any[]
}
I'm trying to filter a document based on two filter conditions in one query. First I want to match the _id and then find a specific variant based on a timestamp.
My previous version of the query was filtering based on the active key.
const updatedDocument = await allDocuments
.findOneAndUpdate({ _id: mongoId, 'variants.active': false }, .... };
Changing it to
const updatedDocument = await allDocuments
.findOneAndUpdate({ _id: mongoId, 'variants.timestamp': timestamp }, .... };
returns null.
Can mongo even match a document like this. I saw that there is an $eq query selector but I can't seem to get it working either.
Turns out I the problem was with the timestamp I was sending to the server. I was getting it from the wrong place and it wasn't matching any of the variants.