I created multiple nested map function of an object array and I ended up in the kind of output.
let tags = product.map(item => item.outSourceItem.map(outsourceitem => outsourceitem.tags));
tags = [
[
[
{
"_id": 11,
"name": "eleven"
}
]
],
[
[
{
"_id": 12,
"name": "twelve"
}
]
],
[
[
{
"_id": 13,
"name": "thirteen"
}
]
],
[
[
{
"_id": 11,
"name": "eleven"
}
]
]
]
I just want it to be like this.
[
{
"_id": 11,
"name": "eleven"
},
{
"_id": 12,
"name": "twelve"
},
{
"_id": 13,
"name": "thirteen"
},
{
"_id": 11,
"name": "eleven"
}
]
any one liner function for this? I use .flat() but it doesn't work either.
Try Array#flat with depth of infinity:
const tags = [
[
[
{
"_id": 11,
"name": "eleven"
}
]
],
[
[
{
"_id": 12,
"name": "twelve"
}
]
],
[
[
{
"_id": 13,
"name": "thirteen"
}
]
],
[
[
{
"_id": 11,
"name": "eleven"
}
]
]
];
const result = tags.flat(Infinity);
console.log(result);
Related
I want to return only matches results.
My array:
products: [
{
"id": 1,
"name": "Product 1",
"concepts": [
{
"id": 10,
"name": "Blabla"
},
{
"id": 15,
"name": "Zlazla"
}
]
},
{
"id": 2,
"name": "Product 2",
"concepts": [
{
"id": 14,
"name": "Gulagula"
},
{
"id": 15,
"name": "Zlazla"
}
]
}
]
I want to filter products which only have one of the concepts below.
concepts array:
['14', '15']
Couldn't solve this in an easy way.
You can try this way:
var products= [
{
"id": 1,
"name": "Product 1",
"concepts": [
{
"id": 10,
"name": "Blabla"
},
{
"id": 15,
"name": "Zlazla"
}
]
},
{
"id": 2,
"name": "Product 2",
"concepts": [
{
"id": 14,
"name": "Gulagula"
},
{
"id": 15,
"name": "Zlazla"
}
]
}
]
var products = products.filter((product) => product.concepts = product.concepts.filter( (x) => x.id == 14 || x.id == 15));
console.log(products);
This question already has answers here:
How to sort an array based on the length of each element?
(12 answers)
Closed 1 year ago.
I have an array like below, and I need to sort the array by the string length of name field.
for an example,
[
{
"_id": 10,
"name": "AAAAAA"
},
{
"_id": 11,
"name": "AA"
},
{
"_id": 12,
"name": "AAAA"
},
{
"_id": 13,
"name": "A"
},
{
"_id": 14,
"name": "AAAAAAAA"
}
]
I need the array like this,
[
{
"_id": 13,
"name": "A"
},
{
"_id": 11,
"name": "AA"
},
{
"_id": 12,
"name": "AAAA"
},
{
"_id": 10,
"name": "AAAAAA"
},
{
"_id": 14,
"name": "AAAAAAAA"
}
]
can any one help me out with this. Thanks.
This can be accomplished with the _.orderBy method:
_.orderBy(data, [({ name }) => name.length, 'name'], ['desc']);
Here is a break-down:
I threw some "B"s into the mix to show the secondary sorting (after length is compared). Sorting the length alone is not unique enough.
const data = [
{ "_id": 1, "name": "AAAAAA" },
{ "_id": 2, "name": "AA" },
{ "_id": 3, "name": "AAAA" },
{ "_id": 4, "name": "A" },
{ "_id": 5, "name": "AAAAAAAA" },
{ "_id": 6, "name": "BBBBBB" },
{ "_id": 7, "name": "BB" },
{ "_id": 8, "name": "BBBB" },
{ "_id": 9, "name": "B" },
{ "_id": 10, "name": "BBBBBBBB" }
];
const sorted = _.orderBy(
data, // Data to be sorted
[
({ name: { length } }) => length, // First, sort by length
'name' // Them sort lexicographically
], [
'desc', // Length (descending)
'asc' // This is implied, and could be removed
]
);
console.log(sorted);
.as-console-wrapper { top: 0; max-height: 100% !important; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js"></script>
I have an array like this
{
"activities": [
{
"activityId": "60f672b20f38640008a6c29b",
"_id": "610cb887b149cb00095e1eb6",
"trackingProgress": [
{
"_id": "610cb8ee541fea0009189c36",
"dateRecorded": "2021-07-16T00:00:00.000Z",
"items": [
{
"_id": "610cb8ee541fea0009189c37",
"feelingType": "Satisfied",
"times": 2
}
]
},
{
"_id": "611358300fea490008d56ea7",
"dateRecorded": "2021-08-10T00:00:00.000Z",
"items": [
{
"_id": "6113583b0fea490008d56eae",
"feelingType": "Neutral",
"times": 1
}
]
},
{
"_id": "611b6068fed9100009a4f689",
"dateRecorded": "2021-08-17T00:00:00.000Z",
"items": [
{
"_id": "611b6068fed9100009a4f68a",
"feelingType": "Satisfied",
"times": 4
}
]
}
],
"title": "Losing & Managing Weight",
"description": "Losing weight",
"order": null,
"daysOfWeek": [
"tuesday"
],
"reminderTimeAt": "09:00 am",
"type": "Custom",
"progressOverview": {
"notSatisfied": 0,
"neutral": 1,
"satisfied": 6
}
}
]
}
I use JSONPATH to get _id in items
$.activities.[*].trackingProgress.[*].items[*].[_id]
it return an array like this
[
"610cb8ee541fea0009189c37",
"6113583b0fea490008d56eae",
"611b6068fed9100009a4f68a"
]
But, i want to keep the "_id", something like :
[
"_id":"610cb8ee541fea0009189c37",
"_id":"6113583b0fea490008d56eae",
"_id":"611b6068fed9100009a4f68a"
]
How can i do that?? Thank you a lots, i search internet but i found nothing
If you use map, you can get an array of items that each have an _id and value.
let result = [
"610cb8ee541fea0009189c37",
"6113583b0fea490008d56eae",
"611b6068fed9100009a4f68a"
].map(i => ({"_id": i}))
Results in:
[{ _id: "610cb8ee541fea0009189c37" },
{ _id: "6113583b0fea490008d56eae" },
{ _id: "611b6068fed9100009a4f68a" }]
I want to group By sub-work in array
Here is my array I want to group By sub-work
result = [
{
"date": "10-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
{
"date": "12-07-2019",
"data": [
{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [
{
"id": 7,
"title": 'subdata-1',
}
]
}
]
},
]
Here is what I try
result = _(result)
.map(function(items, data) {
_.groupBy(items.data, function({ sub_work }) {
return sub_work;
});
})
.value();
first I map result into data then I try to groupby but It's return null
Update
I want my output look like this
[
{
"date": "10-07-2019",
sub-work: [{
sub-work : "sub_work1",
sub-data[
{
"id": 7,
"title": 'subdata-1',
}
]
}]
}
]
...........................
It would be better if you could provide your expected result.
Here's what I could infer:
_(result)
.map(function(obj) { // Convert into a 2D array.
return obj.data.map(e => Object.assign(e, {date: obj.date}));
})
.flatten() // We have an array of objects now.
.groupBy('sub-work') // We can call groupBy().
.value();
Here's what you get:
{
"sub_work1": [{
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "10-07-2019"
}, {
"data_id": "20",
"work": "work_1",
"sub-work": "sub_work1",
"sub-data": [{
"id": 7,
"title": "subdata-1"
}],
"date": "12-07-2019"
}]
}
I have three arrays.
1. Existing viewers array - existingViewers
New viewers array - newViewers
Permitted Viewers array - permittedViewers
permittedViewers is used for rendering the drop-down. And I wish to filter the newViewers and existingViewers entries from the permittedViewers.
I am doing this as three steps. And I am afraid this is not the optimized way. Can someone suggest the ideal way of doing this?
The expected result is
[
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let existingViewers = [{
"viewerId": 1,
"name": "name1"
},
{
"viewerId": 2,
"name": "name2"
}
],
newViewers = [
{
"viewerId": 3,
"name": "name3"
}
],
permittedViewers = [{
"id": 1,
"name": "name1"
},
{
"id": 2,
"name": "name2"
},
{
"id": 3,
"name": "name3"
},
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let grouped = [...existingViewers, ...newViewers]
let viewerFilter = grouped.map(viewer => { return viewer.viewerId; });
let filteredPermittedViewers = permittedViewers.filter(viewer => !viewerFilter.includes(viewer.id));
console.log(filteredPermittedViewers)
I'd make a Set of the ids of the first two arrays, and then filter the third by whether the set includes the id. (Sets have O(1) lookup time)
let existingViewers=[{"viewerId":1,"name":"name1"},{"viewerId":2,"name":"name2"}],newViewers=[{"viewerId":3,"name":"name3"}],permittedViewers=[{"id":1,"name":"name1"},{"id":2,"name":"name2"},{"id":3,"name":"name3"},{"id":4,"name":"name4"},{"id":5,"name":"name5"},{"id":6,"name":"name6"}];
const ids = new Set([...existingViewers, ...newViewers].map(({ viewerId }) => viewerId));
const output = permittedViewers.filter(({ id }) => !ids.has(id));
console.log(output);
You can compress all three statements into a single statement -- just replace the variable name with the statement that creates it:
let existingViewers = [{
"viewerId": 1,
"name": "name1"
},
{
"viewerId": 2,
"name": "name2"
}
],
newViewers = [
{
"viewerId": 3,
"name": "name3"
}
],
permittedViewers = [{
"id": 1,
"name": "name1"
},
{
"id": 2,
"name": "name2"
},
{
"id": 3,
"name": "name3"
},
{
"id": 4,
"name": "name4"
},
{
"id": 5,
"name": "name5"
},
{
"id": 6,
"name": "name6"
}
]
let filteredPermittedViewers = permittedViewers.filter(viewer => ! [...existingViewers, ...newViewers].map(viewer => viewer.viewerId).includes(viewer.id));
console.log(filteredPermittedViewers)