I am trying to parse a markdown content with the use of regex. To grab bold and italic items from the input, I'm currently using a regex:
/(\*\*)(?<bold>[^**]+)(\*\*)|(?<normal>[^`*[~]+)|\*(?<italic>[^*]+)\*/g
Regex101 Link: https://regex101.com/r/2zOMid/1
The problem with this regex are:
if there is a single * in between a bold text content, the match is breaked
if there are long texts like ******* anywhere in between the match is broken
#####: tried with:
I tried removing the [^**] part in the bold group but that messed up the bold match with finding the last ** occurrence and including all `**`` chars within
What I want to have:
accurate bold
* allowed inside bold
accurate italics
Language: Javascript
Assumptions:
Bold text wrapped inside **
Italic text wrapped inside *
There was some discussion in the chat going on. Just to have it mentioned, there is no requirement yet on how to deal with escaped characters like \* so I didn't take attention of it.
Depending on the desired outcome I'd pick a two step solution and keep the patterns simple:
str = str.replace(/\*\*(.+?)\*\*(?!\*)/g,'<b>$1</b>').replace(/\*([^*><]+)\*/g,'<i>$1</i>');
Step 1: Replace bold parts
Replace \*\*(.+?)\*\*(?!\*) with <b>$1</b> -> Regex101
demo
It captures (.+?) one or more characters between ** lazily to $1
and uses a lookahead for matching the outher most * at the end.
Step 2: Now as the amount of remaining * is reduced, italic parts
Replace remaining \*([^*><]+)\* to <i>$1</i> -> Regex101
demo
[^*><]+ matches one or more characters that are not *, > or <.
Here is the JS-demo at tio.run
Myself I don't think it's a good idea to rely on the amount of the same character for distinguishing between kinds of replacement. The way how it works finally gets a matter of taste.
[^**] will not avoid two consecutive *. It is a character class that is no different from [^*]. The repeated asterisk has no effect.
The pattern for italic should better come in front of the normal part, which should capture anything that remains. This could even be a sole asterisk (for example) -- the pattern for normal text should allow this.
It will be easier to use split and use the bold/italic pattern for matching the "delimiter" of the split, while still capturing it. All the rest will then be "normal". The downside of split is that you cannot benefit from named capture groups, but they will just be represented by separate entries in the returned array.
I will ignore the other syntax that markdown can have (like you seem to hint at with [ and ~ in your regex). On the other hand, it is important to deal well with backslash, as it is used to escape an asterisk.
Here is the regular expression (link):
(\*\*?)(?![\s\*])((?:[\s*]*(?:\\[\\*]|[^\\\s*]))+?)\1
Here is a snippet with two functions:
a function that first splits the input into tokens, where each token is a pair, like ["normal", " this is normal text "] and ["i", "text in italics"]
another function that uses these tokens to generate HTML
The snippet is interactive. Just type the input, and the output will be rendered in HTML using the above sequence.
function tokeniseMarkdown(s) {
const regex = /(\*\*?)(?![\s\*])((?:[\s*]*(?:\\[\\*]|[^\\\s*]))+?)\1/gs;
const styles = ["i", "b"];
// Matches follow this cyclic order:
// normal text, mark (= "*" or "**"), formatted text, normal text, ...
const types = ["normal", "mark", ""];
return s.split(regex).map((match, i, matches) =>
types[i%3] !== "mark" && match &&
[types[i%3] || styles[matches[i-1].length-1],
match.replace(/\\([\\*])/g, "$1")]
).filter(Boolean); // Exclude empty matches and marks
}
function tokensToHtml(tokens) {
const container = document.createElement("span");
for (const [style, text] of tokens) {
let node = style === "normal" ? document.createTextNode(text)
: document.createElement(style);
node.textContent = text;
container.appendChild(node);
}
return container.innerHTML;
}
// I/O management
document.addEventListener("input", refresh);
function refresh() {
const s = document.querySelector("textarea").value;
const tokens = tokeniseMarkdown(s);
document.querySelector("div").innerHTML = tokensToHtml(tokens);
}
refresh();
textarea { width: 100%; height: 6em }
div { font: 22px "Times New Roman" }
<textarea>**fi*rst b** some normal text here **second b** *first i* normal *second i* normal again</textarea><br>
<div></div>
Looking some more about the negative lookaheads, I came up with this regex:
/\*\*(?<bold>(?:(?!\*\*).)+)\*\*|`(?<code>[^`]+)`|~~(?<strike>(?:(?!~~).)+)~~|\[(?<linkTitle>[^]]+)]\((?<linkHref>.*)\)|(?<normal>[^`[*~]+)|\*(?<italic>[^*]+)\*|(?<tara>[*~]{3,})|(?<sitara>[`[]+)/g
Regex101
this pretty much works for me as per my input scenarios. If someone has a more optimized regex, please comment.
italic: ((?<!\s)\*(?!\s)(?:(?:[^\*\*]*(?:(?:\*\*[^\*\*]*){2})+?)+?|[^\*\*]+?)(?<!\s)\*)
(?<!\s)\*(?!\s) means matching the start * with no space around,
(?:(?:[^\*\*]*(?:(?:\*\*[^\*\*]*){2})+?)+? means match ** with even appearance, by which negalates meaningless ** inside intalic.
|[^\*\*]+? means if there's no match for one or more ** pair, match anything except a single **.(this "or" order is important)
(?<!\s)*) means matching the end * with no space ahead
And ?: is non-capturing group in js, you can delete it if not needing
bold:
((?<!\s)\*\*(?!\s)(?:[^\*]+?|(?:[^\*]*(?:(?:\*[^\*]*){2})+?)+?)(?<!\s)\*\*)
Similar to italic, except the order of * pair and other character.
Together you can get:
((?<!\s)\*(?!\s)(?:(?:[^\*\*]*(?:(?:\*\*[^\*\*]*){2})+?)+?|[^\*\*]+?)(?<!\s)\*)|((?<!\s)\*\*(?!\s)(?:[^\*]+?|(?:[^\*]*(?:(?:\*[^\*]*){2})+?)+?)(?<!\s)\*\*)
See the result here: https://regex101.com/r/9gTBpj/1
You can choose the tags depending on the number of asterisks. (1 โ italic, 2 โ bold, 3 โ bold+italic)
function simpleMarkdownTransform(markdown) {
return markdown
.replace(/</g, '<') // disallow tags
.replace(/>/g, '>')
.replace(
/(\*{1,3})(.+?)\1(?!\*)/g,
(match, { length: length }, text) => {
if (length !== 2) text = text.italics()
return length === 1 ? text : text.bold()
}
)
.replace(/\n/g, '<br>') // new line
}
Example:
simpleMarkdownTransform('abcd **bold** efgh *italic* ijkl ***bold-italic*** mnop')
// "abcd <b>bold</b> efgh <i>italic</i> ijkl <b><i>bold-italic</i></b> mnop"
Related
I need help for how to detect if an input contains a Japanese emoji/emoticon.
Currently my character set is charset=utf-8. On inputting text, the user can enter Japanese characters/alpanumerics/symbols but if they insert an emoji, onsubmit JavaScript will check if there is an emoji, error message will display.
I can't get this to work because I have no idea on how to detect an emoji in JavaScript?
The answers might work but are terrible because they rely on unicode ranges that are unreadable and somewhat "magic" because it's not always clear where do they come from and why they work, not to mention they're not resilient to new emojis being added to the spec.
Major browsers now support unicode property escape which allows for matching emojis based on their belonging in the Emoji unicode category: \p{Emoji} matches an emoji, \P{Emoji} matches a non-emoji.
Note that officially, 0123456789#* and other characters are emojis too, so the property escape you might want to use is not Emoji but rather Extended_Pictographic which denotes all the characters typically understood as emojis!
Make sure to include the u flag at the end.
console.log(
/\p{Emoji}/u.test('flowers'), // false :)
/\p{Emoji}/u.test('flowers ๐ผ๐บ๐ธ'), // true :)
/\p{Emoji}/u.test('flowers 123'), // true :(
)
console.log(
/\p{Extended_Pictographic}/u.test('flowers'), // false :)
/\p{Extended_Pictographic}/u.test('flowers ๐ผ๐บ๐ธ'), // true :)
/\p{Extended_Pictographic}/u.test('flowers 123'), // false :)
)
This works fine for detecting emojis, but if you want to use the same regex to extract them, you might be surprised with its behavior, since some emojis that appear as one character are actually several characters. They're what we call emoji sequences, more about them in this question
const regex = /\p{Extended_Pictographic}/ug
const family = '๐จโ๐ฉโ๐ง' // "family
console.log(family.length) // not 1, but 8!
console.log(regex.test(family)) // true, as expected
console.log(family.match(regex)) // not [family], but [man, woman, girl]
You can use the following regex:
/(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g
If you just want to remove it from the string, you can do something like this.
function removeEmojis (string) {
var regex = /(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g;
return string.replace(regex, '');
}
A simple function that returns true if your string contains one or more emojis.
function isEmoji(str) {
var ranges = [
'(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|[\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|[\ud83c[\ude32-\ude3a]|[\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])' // U+1F680 to U+1F6FF
];
if (str.match(ranges.join('|'))) {
return true;
} else {
return false;
}
}
First of all, you cannot rely on ECMAScript 2018+ compliant \p{Emoji} (at least at the time of writing). It really matches some 0123456789#* non-emoji chars (see Nino Filiu's answer). See Why do Unicode emoji property escapes match numbers? for more details.
To test if there are any emoji chars in a string in JavaScript, you can use the following ECMAScript 2018+ compliant solution (mind the u flag):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]/u;
console.log( regex_emoji.test('flowers 123') ); // => false
console.log( regex_emoji.test('flowers ๐ผ๐บ๐ธ') ); // => true
You can even extract one or more emoji char sequences using this pattern (note the added g flag to find all occurrences and + to match one or more consecutive occurrences of the character class pattern):
const regex_emoji = /[\p{Extended_Pictographic}\u{1F3FB}-\u{1F3FF}\u{1F9B0}-\u{1F9B3}]+/gu;
console.log( 'flowers 123'.match(regex_emoji) ); // => null
console.log( 'flowers ๐ผ๐บ๐ธ'.match(regex_emoji) ); // => [ "๐ผ๐บ๐ธ" ]
In a nutshell, the Extended_Pictographic Unicode category class matches most emoji chars except for some Emoji_Components, that is, light skin to dark skin mode chars (\u{1F3FB}-\u{1F3FF}) and red-haired to white-haired chars (\u{1F9B0}-\u{1F9B3}).
To count, or extract emojis as an array of single chars or consecutive sequences (like in the second code snippet from above) from longer texts and perform other actions on emojis, you can use a custom regex (like in Scott Weaver's answer). It is safer to use the longer, escaped version. However, there are 4702 emoji characters defined in the Emoji Keyboard/Display Test Data for UTR #51 (Version: 14.0) file. Thus, the (ES5 compliant, works even in IE) regex to match a single emoji char is
var EmojiPattern = /[#*0-9]\uFE0F?\u20E3|\u00A9\uFE0F?|[\u00AE\u203C\u2049\u2122\u2139\u2194-\u2199\u21A9\u21AA]\uFE0F?|[\u231A\u231B]|[\u2328\u23CF]\uFE0F?|[\u23E9-\u23EC]|[\u23ED-\u23EF]\uFE0F?|\u23F0|[\u23F1\u23F2]\uFE0F?|\u23F3|[\u23F8-\u23FA\u24C2\u25AA\u25AB\u25B6\u25C0\u25FB\u25FC]\uFE0F?|[\u25FD\u25FE]|[\u2600-\u2604\u260E\u2611]\uFE0F?|[\u2614\u2615]|\u2618\uFE0F?|\u261D(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\u2620\u2622\u2623\u2626\u262A\u262E\u262F\u2638-\u263A\u2640\u2642]\uFE0F?|[\u2648-\u2653]|[\u265F\u2660\u2663\u2665\u2666\u2668\u267B\u267E]\uFE0F?|\u267F|\u2692\uFE0F?|\u2693|[\u2694-\u2697\u2699\u269B\u269C\u26A0]\uFE0F?|\u26A1|\u26A7\uFE0F?|[\u26AA\u26AB]|[\u26B0\u26B1]\uFE0F?|[\u26BD\u26BE\u26C4\u26C5]|\u26C8\uFE0F?|\u26CE|[\u26CF\u26D1\u26D3]\uFE0F?|\u26D4|\u26E9\uFE0F?|\u26EA|[\u26F0\u26F1]\uFE0F?|[\u26F2\u26F3]|\u26F4\uFE0F?|\u26F5|[\u26F7\u26F8]\uFE0F?|\u26F9(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\u26FA\u26FD]|\u2702\uFE0F?|\u2705|[\u2708\u2709]\uFE0F?|[\u270A\u270B](?:\uD83C[\uDFFB-\uDFFF])?|[\u270C\u270D](?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\u270F\uFE0F?|[\u2712\u2714\u2716\u271D\u2721]\uFE0F?|\u2728|[\u2733\u2734\u2744\u2747]\uFE0F?|[\u274C\u274E\u2753-\u2755\u2757]|\u2763\uFE0F?|\u2764(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79)|\uFE0F(?:\u200D(?:\uD83D\uDD25|\uD83E\uDE79))?)?|[\u2795-\u2797]|\u27A1\uFE0F?|[\u27B0\u27BF]|[\u2934\u2935\u2B05-\u2B07]\uFE0F?|[\u2B1B\u2B1C\u2B50\u2B55]|[\u3030\u303D\u3297\u3299]\uFE0F?|\uD83C(?:[\uDC04\uDCCF]|[\uDD70\uDD71\uDD7E\uDD7F]\uFE0F?|[\uDD8E\uDD91-\uDD9A]|\uDDE6\uD83C[\uDDE8-\uDDEC\uDDEE\uDDF1\uDDF2\uDDF4\uDDF6-\uDDFA\uDDFC\uDDFD\uDDFF]|\uDDE7\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEF\uDDF1-\uDDF4\uDDF6-\uDDF9\uDDFB\uDDFC\uDDFE\uDDFF]|\uDDE8\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDEE\uDDF0-\uDDF5\uDDF7\uDDFA-\uDDFF]|\uDDE9\uD83C[\uDDEA\uDDEC\uDDEF\uDDF0\uDDF2\uDDF4\uDDFF]|\uDDEA\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDED\uDDF7-\uDDFA]|\uDDEB\uD83C[\uDDEE-\uDDF0\uDDF2\uDDF4\uDDF7]|\uDDEC\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEE\uDDF1-\uDDF3\uDDF5-\uDDFA\uDDFC\uDDFE]|\uDDED\uD83C[\uDDF0\uDDF2\uDDF3\uDDF7\uDDF9\uDDFA]|\uDDEE\uD83C[\uDDE8-\uDDEA\uDDF1-\uDDF4\uDDF6-\uDDF9]|\uDDEF\uD83C[\uDDEA\uDDF2\uDDF4\uDDF5]|\uDDF0\uD83C[\uDDEA\uDDEC-\uDDEE\uDDF2\uDDF3\uDDF5\uDDF7\uDDFC\uDDFE\uDDFF]|\uDDF1\uD83C[\uDDE6-\uDDE8\uDDEE\uDDF0\uDDF7-\uDDFB\uDDFE]|\uDDF2\uD83C[\uDDE6\uDDE8-\uDDED\uDDF0-\uDDFF]|\uDDF3\uD83C[\uDDE6\uDDE8\uDDEA-\uDDEC\uDDEE\uDDF1\uDDF4\uDDF5\uDDF7\uDDFA\uDDFF]|\uDDF4\uD83C\uDDF2|\uDDF5\uD83C[\uDDE6\uDDEA-\uDDED\uDDF0-\uDDF3\uDDF7-\uDDF9\uDDFC\uDDFE]|\uDDF6\uD83C\uDDE6|\uDDF7\uD83C[\uDDEA\uDDF4\uDDF8\uDDFA\uDDFC]|\uDDF8\uD83C[\uDDE6-\uDDEA\uDDEC-\uDDF4\uDDF7-\uDDF9\uDDFB\uDDFD-\uDDFF]|\uDDF9\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDED\uDDEF-\uDDF4\uDDF7\uDDF9\uDDFB\uDDFC\uDDFF]|\uDDFA\uD83C[\uDDE6\uDDEC\uDDF2\uDDF3\uDDF8\uDDFE\uDDFF]|\uDDFB\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDEE\uDDF3\uDDFA]|\uDDFC\uD83C[\uDDEB\uDDF8]|\uDDFD\uD83C\uDDF0|\uDDFE\uD83C[\uDDEA\uDDF9]|\uDDFF\uD83C[\uDDE6\uDDF2\uDDFC]|\uDE01|\uDE02\uFE0F?|[\uDE1A\uDE2F\uDE32-\uDE36]|\uDE37\uFE0F?|[\uDE38-\uDE3A\uDE50\uDE51\uDF00-\uDF20]|[\uDF21\uDF24-\uDF2C]\uFE0F?|[\uDF2D-\uDF35]|\uDF36\uFE0F?|[\uDF37-\uDF7C]|\uDF7D\uFE0F?|[\uDF7E-\uDF84]|\uDF85(?:\uD83C[\uDFFB-\uDFFF])?|[\uDF86-\uDF93]|[\uDF96\uDF97\uDF99-\uDF9B\uDF9E\uDF9F]\uFE0F?|[\uDFA0-\uDFC1]|\uDFC2(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC3\uDFC4](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFC5\uDFC6]|\uDFC7(?:\uD83C[\uDFFB-\uDFFF])?|[\uDFC8\uDFC9]|\uDFCA(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCB\uDFCC](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDFCD\uDFCE]\uFE0F?|[\uDFCF-\uDFD3]|[\uDFD4-\uDFDF]\uFE0F?|[\uDFE0-\uDFF0]|\uDFF3(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08)|\uFE0F(?:\u200D(?:\u26A7\uFE0F?|\uD83C\uDF08))?)?|\uDFF4(?:\u200D\u2620\uFE0F?|\uDB40\uDC67\uDB40\uDC62\uDB40(?:\uDC65\uDB40\uDC6E\uDB40\uDC67|\uDC73\uDB40\uDC63\uDB40\uDC74|\uDC77\uDB40\uDC6C\uDB40\uDC73)\uDB40\uDC7F)?|[\uDFF5\uDFF7]\uFE0F?|[\uDFF8-\uDFFF])|\uD83D(?:[\uDC00-\uDC07]|\uDC08(?:\u200D\u2B1B)?|[\uDC09-\uDC14]|\uDC15(?:\u200D\uD83E\uDDBA)?|[\uDC16-\uDC3A]|\uDC3B(?:\u200D\u2744\uFE0F?)?|[\uDC3C-\uDC3E]|\uDC3F\uFE0F?|\uDC40|\uDC41(?:\u200D\uD83D\uDDE8\uFE0F?|\uFE0F(?:\u200D\uD83D\uDDE8\uFE0F?)?)?|[\uDC42\uDC43](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC44\uDC45]|[\uDC46-\uDC50](?:\uD83C[\uDFFB-\uDFFF])?|[\uDC51-\uDC65]|[\uDC66\uDC67](?:\uD83C[\uDFFB-\uDFFF])?|\uDC68(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|[\uDC68\uDC69]\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92])|\uD83E[\uDDAF-\uDDB3\uDDBC\uDDBD])|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFC-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFD-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFD\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?\uDC68\uD83C[\uDFFB-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D\uDC68\uD83C[\uDFFB-\uDFFE]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|\uDC69(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:\uDC8B\u200D\uD83D)?[\uDC68\uDC69]|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?|\uDC69\u200D\uD83D(?:\uDC66(?:\u200D\uD83D\uDC66)?|\uDC67(?:\u200D\uD83D[\uDC66\uDC67])?)|[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92])|\uD83E[\uDDAF-\uDDB3\uDDBC\uDDBD])|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFC-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB\uDFFD-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFD\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D\uD83D(?:[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF]|\uDC8B\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFF])|\uD83C[\uDF3E\uDF73\uDF7C\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83D[\uDC68\uDC69]\uD83C[\uDFFB-\uDFFE]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|\uDC6A|[\uDC6B-\uDC6D](?:\uD83C[\uDFFB-\uDFFF])?|\uDC6E(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC6F(?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDC70\uDC71](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC72(?:\uD83C[\uDFFB-\uDFFF])?|\uDC73(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDC74-\uDC76](?:\uD83C[\uDFFB-\uDFFF])?|\uDC77(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC78(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC79-\uDC7B]|\uDC7C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC7D-\uDC80]|[\uDC81\uDC82](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDC83(?:\uD83C[\uDFFB-\uDFFF])?|\uDC84|\uDC85(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC86\uDC87](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDC88-\uDC8E]|\uDC8F(?:\uD83C[\uDFFB-\uDFFF])?|\uDC90|\uDC91(?:\uD83C[\uDFFB-\uDFFF])?|[\uDC92-\uDCA9]|\uDCAA(?:\uD83C[\uDFFB-\uDFFF])?|[\uDCAB-\uDCFC]|\uDCFD\uFE0F?|[\uDCFF-\uDD3D]|[\uDD49\uDD4A]\uFE0F?|[\uDD4B-\uDD4E\uDD50-\uDD67]|[\uDD6F\uDD70\uDD73]\uFE0F?|\uDD74(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|\uDD75(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?|\uFE0F(?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD76-\uDD79]\uFE0F?|\uDD7A(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD87\uDD8A-\uDD8D]\uFE0F?|\uDD90(?:\uD83C[\uDFFB-\uDFFF]|\uFE0F)?|[\uDD95\uDD96](?:\uD83C[\uDFFB-\uDFFF])?|\uDDA4|[\uDDA5\uDDA8\uDDB1\uDDB2\uDDBC\uDDC2-\uDDC4\uDDD1-\uDDD3\uDDDC-\uDDDE\uDDE1\uDDE3\uDDE8\uDDEF\uDDF3\uDDFA]\uFE0F?|[\uDDFB-\uDE2D]|\uDE2E(?:\u200D\uD83D\uDCA8)?|[\uDE2F-\uDE34]|\uDE35(?:\u200D\uD83D\uDCAB)?|\uDE36(?:\u200D\uD83C\uDF2B\uFE0F?)?|[\uDE37-\uDE44]|[\uDE45-\uDE47](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDE48-\uDE4A]|\uDE4B(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE4D\uDE4E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDE4F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDE80-\uDEA2]|\uDEA3(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEA4-\uDEB3]|[\uDEB4-\uDEB6](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDEB7-\uDEBF]|\uDEC0(?:\uD83C[\uDFFB-\uDFFF])?|[\uDEC1-\uDEC5]|\uDECB\uFE0F?|\uDECC(?:\uD83C[\uDFFB-\uDFFF])?|[\uDECD-\uDECF]\uFE0F?|[\uDED0-\uDED2\uDED5-\uDED7\uDEDD-\uDEDF]|[\uDEE0-\uDEE5\uDEE9]\uFE0F?|[\uDEEB\uDEEC]|[\uDEF0\uDEF3]\uFE0F?|[\uDEF4-\uDEFC\uDFE0-\uDFEB\uDFF0])|\uD83E(?:\uDD0C(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD0D\uDD0E]|\uDD0F(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD10-\uDD17]|[\uDD18-\uDD1F](?:\uD83C[\uDFFB-\uDFFF])?|[\uDD20-\uDD25]|\uDD26(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD27-\uDD2F]|[\uDD30-\uDD34](?:\uD83C[\uDFFB-\uDFFF])?|\uDD35(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD36(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD37-\uDD39](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDD3A|\uDD3C(?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDD3D\uDD3E](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDD3F-\uDD45\uDD47-\uDD76]|\uDD77(?:\uD83C[\uDFFB-\uDFFF])?|[\uDD78-\uDDB4]|[\uDDB5\uDDB6](?:\uD83C[\uDFFB-\uDFFF])?|\uDDB7|[\uDDB8\uDDB9](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDBA|\uDDBB(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDBC-\uDDCC]|[\uDDCD-\uDDCF](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD0|\uDDD1(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1|[\uDDAF-\uDDB3\uDDBC\uDDBD]))|\uD83C(?:\uDFFB(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFC-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFC(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFD-\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFD(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFE(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFD\uDFFF]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?|\uDFFF(?:\u200D(?:[\u2695\u2696\u2708]\uFE0F?|\u2764\uFE0F?\u200D(?:\uD83D\uDC8B\u200D)?\uD83E\uDDD1\uD83C[\uDFFB-\uDFFE]|\uD83C[\uDF3E\uDF73\uDF7C\uDF84\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E(?:\uDD1D\u200D\uD83E\uDDD1\uD83C[\uDFFB-\uDFFF]|[\uDDAF-\uDDB3\uDDBC\uDDBD])))?))?|[\uDDD2\uDDD3](?:\uD83C[\uDFFB-\uDFFF])?|\uDDD4(?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|\uDDD5(?:\uD83C[\uDFFB-\uDFFF])?|[\uDDD6-\uDDDD](?:\u200D[\u2640\u2642]\uFE0F?|\uD83C[\uDFFB-\uDFFF](?:\u200D[\u2640\u2642]\uFE0F?)?)?|[\uDDDE\uDDDF](?:\u200D[\u2640\u2642]\uFE0F?)?|[\uDDE0-\uDDFF\uDE70-\uDE74\uDE78-\uDE7C\uDE80-\uDE86\uDE90-\uDEAC\uDEB0-\uDEBA\uDEC0-\uDEC2]|[\uDEC3-\uDEC5](?:\uD83C[\uDFFB-\uDFFF])?|[\uDED0-\uDED9\uDEE0-\uDEE7]|\uDEF0(?:\uD83C[\uDFFB-\uDFFF])?|\uDEF1(?:\uD83C(?:\uDFFB(?:\u200D\uD83E\uDEF2\uD83C[\uDFFC-\uDFFF])?|\uDFFC(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFD-\uDFFF])?|\uDFFD(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB\uDFFC\uDFFE\uDFFF])?|\uDFFE(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFD\uDFFF])?|\uDFFF(?:\u200D\uD83E\uDEF2\uD83C[\uDFFB-\uDFFE])?))?|[\uDEF2-\uDEF6](?:\uD83C[\uDFFB-\uDFFF])?)/g;
See the regex demo. The g flag at the end means this regex can match all occurrences in the input string.
The pattern is created dynamically from the list of emojis and contracted using a regex trie.
See this JavaScript demo:
var text = 'flowers ๐ผ๐บ๐ธ';
// Detecting if there is at least one emoji
console.log( emoji_detection_regex.test(text) ); // => true
// Counting emojis
console.log( (text.match(emoji_count_regex) || []).length ); // => 3
// Extracting one by one, single emoji array
console.log( text.match(emoji_count_regex) ); // => ["๐ผ","๐บ","๐ธ"]
// Extracting emoji sequences
console.log( text.match(emoji_extract_or_remove_regex) ); // => ["๐ผ๐บ๐ธ"]
// Removing emojis
console.log( text.replace(emoji_extract_or_remove_regex, '') ); // => 'flowers '
<script src="https://gitcdn.link/repo/stribizhev/Emojis/main/ws_emoji_regex.js"></script>
The emoji regex declarations are available in the https://github.com/stribizhev/Emojis/blob/main/ws_emoji_regex.js file.
We can detect all list of surrogate pairs or the Emoji characters in a specific range.
If the issue related with storing the input string to database like MySQL version before 5.5 we need to detect and remove all the surrogate pairs using the below regex
/([\uD800-\uDBFF][\uDC00-\uDFFF])/g.
Update for 2020: Many of these patterns don't match compound emojis or Modifier Sequences correctly, or are simply outdated and do not match the newer emojis.
Consider this kissing couple: ๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ. It's actually 6 (maybe more) other emojis glued together with the ZWJ zero-width joiner. To match this correctly, you have to actually match that sequence.
Thus, by matching the longer sequences first, this brute-force pattern (too long too paste, but it's a simple alternation and runs fast) correctly parses all 3521 combined emojis as of May 2021:
GitHub link: https://github.com/sweaver2112/Regex-combined-emojis
Edit 5/10/2021: If the size of the Unicode escape version of this regex is off-putting to you, you could actually skip the Unicode escape sequences and just use literal emojis, thereby saving tons of space...well, almost. This character, "*๏ธโฃ", which starts with an asterisk, will throw a "nothing to quantify" error. Getting rid of just this guy yields a much shorter, still working, copy/pastable regex that matches 3,520/3,521 Emojis at the present date:
Regex 101 Demo (compact, unsafe literal emoji version)
Regex 101 Demo (long, safe unicode escape version)
The demos' input string includes all characters from
https://unicode.org/emoji/charts/full-emoji-list.html (13.1)
https://unicode.org/emoji/charts-13.1/full-emoji-modifiers.html
Working example using the compact version:
/*the pattern*/
var emojiPattern = String.raw`(?:๐ง๐ปโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ปโโค๏ธโ๐โ๐ง๐พ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ป|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ผโโค๏ธโ๐โ๐ง๐พ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐พ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐พโโค๏ธโ๐โ๐ง๐ป|๐ง๐พโโค๏ธโ๐โ๐ง๐ผ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ป|๐จ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ปโโค๏ธโ๐โ๐จ๐พ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ป|๐จ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ผโโค๏ธโ๐โ๐จ๐พ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐พโโค๏ธโ๐โ๐จ๐ป|๐จ๐พโโค๏ธโ๐โ๐จ๐ผ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐พโโค๏ธโ๐โ๐จ๐พ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฟ|๐ด๓ ง๓ ข๓ ฅ๓ ฎ๓ ง๓ ฟ|๐ด๓ ง๓ ข๓ ณ๓ ฃ๓ ด๓ ฟ|๐ด๓ ง๓ ข๓ ท๓ ฌ๓ ณ๓ 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๐ฝโโ๏ธ|๐
๐พโโ๏ธ|๐
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โ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ถโ๐ซ๏ธ|๐ต๏ธโโ๏ธ|๐ต๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐ณ๏ธโ๐|๐ณ๏ธโโง๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|๐ฎโ๐จ|๐ตโ๐ซ|โค๏ธโ๐ฅ|โค๏ธโ๐ฉน|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆฐ|๐จโ๐ฆฑ|๐จโ๐ฆณ|๐จโ๐ฆฒ|๐ฉโ๐ฆฐ|๐งโ๐ฆฐ|๐ฉโ๐ฆฑ|๐งโ๐ฆฑ|๐ฉโ๐ฆณ|๐งโ๐ฆณ|๐ฉโ๐ฆฒ|๐งโ๐ฆฒ|๐ฑโโ๏ธ|๐ฑโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐
โโ๏ธ|๐
โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐คฆโโ๏ธ|๐คฆโโ๏ธ|๐คทโโ๏ธ|๐คทโโ๏ธ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐ซ|๐จโ๐ซ|๐ฉโ๐ซ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐พ|๐จโ๐พ|๐ฉโ๐พ|๐งโ๐ณ|๐จโ๐ณ|๐ฉโ๐ณ|๐งโ๐ง|๐จโ๐ง|๐ฉโ๐ง|๐งโ๐ญ|๐จโ๐ญ|๐ฉโ๐ญ|๐งโ๐ผ|๐จโ๐ผ|๐ฉโ๐ผ|๐งโ๐ฌ|๐จโ๐ฌ|๐ฉโ๐ฌ|๐งโ๐ป|๐จโ๐ป|๐ฉโ๐ป|๐งโ๐ค|๐จโ๐ค|๐ฉโ๐ค|๐งโ๐จ|๐จโ๐จ|๐ฉโ๐จ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐|๐จโ๐|๐ฉโ๐|๐ฎโโ๏ธ|๐ฎโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ทโโ๏ธ|๐ทโโ๏ธ|๐ณโโ๏ธ|๐ณโโ๏ธ|๐คตโโ๏ธ|๐คตโโ๏ธ|๐ฐโโ๏ธ|๐ฐโโ๏ธ|๐ฉโ๐ผ|๐จโ๐ผ|๐งโ๐ผ|๐งโ๐|๐ฆธโโ๏ธ|๐ฆธโโ๏ธ|๐ฆนโโ๏ธ|๐ฆนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ถโโ๏ธ|๐ถโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโ๐ฆฏ|๐จโ๐ฆฏ|๐ฉโ๐ฆฏ|๐งโ๐ฆผ|๐จโ๐ฆผ|๐ฉโ๐ฆผ|๐งโ๐ฆฝ|๐จโ๐ฆฝ|๐ฉโ๐ฆฝ|๐โโ๏ธ|๐โโ๏ธ|๐ฏโโ๏ธ|๐ฏโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ฃโโ๏ธ|๐ฃโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|โน๏ธโโ๏ธ|โน๏ธโโ๏ธ|๐ดโโ๏ธ|๐ดโโ๏ธ|๐ตโโ๏ธ|๐ตโโ๏ธ|๐คธโโ๏ธ|๐คธโโ๏ธ|๐คผโโ๏ธ|๐คผโโ๏ธ|๐คฝโโ๏ธ|๐คฝโโ๏ธ|๐คพโโ๏ธ|๐คพโโ๏ธ|๐คนโโ๏ธ|๐คนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆ|๐จโ๐ง|๐ฉโ๐ฆ|๐ฉโ๐ง|๐โ๐ฆบ|๐ปโโ๏ธ|๐ดโโ ๏ธ|๐โโฌ|๐ฆ๐จ|๐ฆ๐ฉ|๐ฆ๐ช|๐ฆ๐ซ|๐ฆ๐ฌ|๐ฆ๐ฎ|๐ฆ๐ฑ|๐ฆ๐ฒ|๐ฆ๐ด|๐ฆ๐ถ|๐ฆ๐ท|๐ฆ๐ธ|๐ฆ๐น|๐ฆ๐บ|๐ฆ๐ผ|๐ฆ๐ฝ|๐ฆ๐ฟ|๐ง๐ฆ|๐ง๐ง|๐ง๐ฉ|๐ง๐ช|๐ง๐ซ|๐ง๐ฌ|๐ง๐ญ|๐ง๐ฎ|๐ง๐ฏ|๐ง๐ฑ|๐ง๐ฒ|๐ง๐ณ|๐ง๐ด|๐ง๐ถ|๐ง๐ท|๐ง๐ธ|๐ง๐น|๐ง๐ป|๐ง๐ผ|๐ง๐พ|๐ง๐ฟ|๐จ๐ฆ|๐จ๐จ|๐จ๐ฉ|๐จ๐ซ|๐จ๐ฌ|๐จ๐ญ|๐จ๐ฎ|๐จ๐ฐ|๐จ๐ฑ|๐จ๐ฒ|๐จ๐ณ|๐จ๐ด|๐จ๐ต|๐จ๐ท|๐จ๐บ|๐จ๐ป|๐จ๐ผ|๐จ๐ฝ|๐จ๐พ|๐จ๐ฟ|๐ฉ๐ช|๐ฉ๐ฌ|๐ฉ๐ฏ|๐ฉ๐ฐ|๐ฉ๐ฒ|๐ฉ๐ด|๐ฉ๐ฟ|๐ช๐ฆ|๐ช๐จ|๐ช๐ช|๐ช๐ฌ|๐ช๐ญ|๐ช๐ท|๐ช๐ธ|๐ช๐น|๐ช๐บ|๐ซ๐ฎ|๐ซ๐ฏ|๐ซ๐ฐ|๐ซ๐ฒ|๐ซ๐ด|๐ซ๐ท|๐ฌ๐ฆ|๐ฌ๐ง|๐ฌ๐ฉ|๐ฌ๐ช|๐ฌ๐ซ|๐ฌ๐ฌ|๐ฌ๐ญ|๐ฌ๐ฎ|๐ฌ๐ฑ|๐ฌ๐ฒ|๐ฌ๐ณ|๐ฌ๐ต|๐ฌ๐ถ|๐ฌ๐ท|๐ฌ๐ธ|๐ฌ๐น|๐ฌ๐บ|๐ฌ๐ผ|๐ฌ๐พ|๐ญ๐ฐ|๐ญ๐ฒ|๐ญ๐ณ|๐ญ๐ท|๐ญ๐น|๐ญ๐บ|๐ฎ๐จ|๐ฎ๐ฉ|๐ฎ๐ช|๐ฎ๐ฑ|๐ฎ๐ฒ|๐ฎ๐ณ|๐ฎ๐ด|๐ฎ๐ถ|๐ฎ๐ท|๐ฎ๐ธ|๐ฎ๐น|๐ฏ๐ช|๐ฏ๐ฒ|๐ฏ๐ด|๐ฏ๐ต|๐ฐ๐ช|๐ฐ๐ฌ|๐ฐ๐ญ|๐ฐ๐ฎ|๐ฐ๐ฒ|๐ฐ๐ณ|๐ฐ๐ต|๐ฐ๐ท|๐ฐ๐ผ|๐ฐ๐พ|๐ฐ๐ฟ|๐ฑ๐ฆ|๐ฑ๐ง|๐ฑ๐จ|๐ฑ๐ฎ|๐ฑ๐ฐ|๐ฑ๐ท|๐ฑ๐ธ|๐ฑ๐น|๐ฑ๐บ|๐ฑ๐ป|๐ฑ๐พ|๐ฒ๐ฆ|๐ฒ๐จ|๐ฒ๐ฉ|๐ฒ๐ช|๐ฒ๐ซ|๐ฒ๐ฌ|๐ฒ๐ญ|๐ฒ๐ฐ|๐ฒ๐ฑ|๐ฒ๐ฒ|๐ฒ๐ณ|๐ฒ๐ด|๐ฒ๐ต|๐ฒ๐ถ|๐ฒ๐ท|๐ฒ๐ธ|๐ฒ๐น|๐ฒ๐บ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ณ๐ฆ|๐ณ๐จ|๐ณ๐ช|๐ณ๐ซ|๐ณ๐ฌ|๐ณ๐ฎ|๐ณ๐ฑ|๐ณ๐ด|๐ณ๐ต|๐ณ๐ท|๐ณ๐บ|๐ณ๐ฟ|๐ด๐ฒ|๐ต๐ฆ|๐ต๐ช|๐ต๐ซ|๐ต๐ฌ|๐ต๐ญ|๐ต๐ฐ|๐ต๐ฑ|๐ต๐ฒ|๐ต๐ณ|๐ต๐ท|๐ต๐ธ|๐ต๐น|๐ต๐ผ|๐ต๐พ|๐ถ๐ฆ|๐ท๐ช|๐ท๐ด|๐ท๐ธ|๐ท๐บ|๐ท๐ผ|๐ธ๐ฆ|๐ธ๐ง|๐ธ๐จ|๐ธ๐ฉ|๐ธ๐ช|๐ธ๐ฌ|๐ธ๐ญ|๐ธ๐ฎ|๐ธ๐ฏ|๐ธ๐ฐ|๐ธ๐ฑ|๐ธ๐ฒ|๐ธ๐ณ|๐ธ๐ด|๐ธ๐ท|๐ธ๐ธ|๐ธ๐น|๐ธ๐ป|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐น๐ฆ|๐น๐จ|๐น๐ฉ|๐น๐ซ|๐น๐ฌ|๐น๐ญ|๐น๐ฏ|๐น๐ฐ|๐น๐ฑ|๐น๐ฒ|๐น๐ณ|๐น๐ด|๐น๐ท|๐น๐น|๐น๐ป|๐น๐ผ|๐น๐ฟ|๐บ๐ฆ|๐บ๐ฌ|๐บ๐ฒ|๐บ๐ณ|๐บ๐ธ|๐บ๐พ|๐บ๐ฟ|๐ป๐ฆ|๐ป๐จ|๐ป๐ช|๐ป๐ฌ|๐ป๐ฎ|๐ป๐ณ|๐ป๐บ|๐ผ๐ซ|๐ผ๐ธ|๐ฝ๐ฐ|๐พ๐ช|๐พ๐น|๐ฟ๐ฆ|๐ฟ๐ฒ|๐ฟ๐ผ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฒ๐ป|๐คฒ๐ผ|๐คฒ๐ฝ|๐คฒ๐พ|๐คฒ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
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๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฆ๐ป|๐คฆ๐ผ|๐คฆ๐ฝ|๐คฆ๐พ|๐คฆ๐ฟ|๐คท๐ป|๐คท๐ผ|๐คท๐ฝ|๐คท๐พ|๐คท๐ฟ|๐ฎ๐ป|๐ฎ๐ผ|๐ฎ๐ฝ|๐ฎ๐พ|๐ฎ๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฅท๐ป|๐ฅท๐ผ|๐ฅท๐ฝ|๐ฅท๐พ|๐ฅท๐ฟ|๐ท๐ป|๐ท๐ผ|๐ท๐ฝ|๐ท๐พ|๐ท๐ฟ|๐คด๐ป|๐คด๐ผ|๐คด๐ฝ|๐คด๐พ|๐คด๐ฟ|๐ธ๐ป|๐ธ๐ผ|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐ณ๐ป|๐ณ๐ผ|๐ณ๐ฝ|๐ณ๐พ|๐ณ๐ฟ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐คต๐ป|๐คต๐ผ|๐คต๐ฝ|๐คต๐พ|๐คต๐ฟ|๐ฐ๐ป|๐ฐ๐ผ|๐ฐ๐ฝ|๐ฐ๐พ|๐ฐ๐ฟ|๐คฐ๐ป|๐คฐ๐ผ|๐คฐ๐ฝ|๐คฐ๐พ|๐คฐ๐ฟ|๐คฑ๐ป|๐คฑ๐ผ|๐คฑ๐ฝ|๐คฑ๐พ|๐คฑ๐ฟ|๐ผ๐ป|๐ผ๐ผ|๐ผ๐ฝ|๐ผ๐พ|๐ผ๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐คถ๐ป|๐คถ๐ผ|๐คถ๐ฝ|๐คถ๐พ|๐คถ๐ฟ|๐ฆธ๐ป|๐ฆธ๐ผ|๐ฆธ๐ฝ|๐ฆธ๐พ|๐ฆธ๐ฟ|๐ฆน๐ป|๐ฆน๐ผ|๐ฆน๐ฝ|๐ฆน๐พ|๐ฆน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ถ๐ป|๐ถ๐ผ|๐ถ๐ฝ|๐ถ๐พ|๐ถ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐บ๐ป|๐บ๐ผ|๐บ๐ฝ|๐บ๐พ|๐บ๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฃ๐ป|๐ฃ๐ผ|๐ฃ๐ฝ|๐ฃ๐พ|๐ฃ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐คธ๐ป|๐คธ๐ผ|๐คธ๐ฝ|๐คธ๐พ|๐คธ๐ฟ|๐คฝ๐ป|๐คฝ๐ผ|๐คฝ๐ฝ|๐คฝ๐พ|๐คฝ๐ฟ|๐คพ๐ป|๐คพ๐ผ|๐คพ๐ฝ|๐คพ๐พ|๐คพ๐ฟ|๐คน๐ป|๐คน๐ผ|๐คน๐ฝ|๐คน๐พ|๐คน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ญ๐ป|๐ญ๐ผ|๐ญ๐ฝ|๐ญ๐พ|๐ญ๐ฟ|๐ซ๐ป|๐ซ๐ผ|๐ซ๐ฝ|๐ซ๐พ|๐ซ๐ฟ|๐ฌ๐ป|๐ฌ๐ผ|๐ฌ๐ฝ|๐ฌ๐พ|๐ฌ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|#๏ธโฃ|0๏ธโฃ|1๏ธโฃ|2๏ธโฃ|3๏ธโฃ|4๏ธโฃ|5๏ธโฃ|6๏ธโฃ|7๏ธโฃ|8๏ธโฃ|9๏ธโฃ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โน๐ป|โน๐ผ|โน๐ฝ|โน๐พ|โน๐ฟ|๐|๐|๐|๐|๐|๐
|๐คฃ|๐|๐|๐|๐|๐|๐|๐ฅฐ|๐|๐คฉ|๐|๐|๐|๐|๐ฅฒ|๐|๐|๐|๐คช|๐|๐ค|๐ค|๐คญ|๐คซ|๐ค|๐ค|๐คจ|๐|๐|๐ถ|๐|๐|๐|๐ฌ|๐คฅ|๐|๐|๐ช|๐คค|๐ด|๐ท|๐ค|๐ค|๐คข|๐คฎ|๐คง|๐ฅต|๐ฅถ|๐ฅด|๐ต|๐คฏ|๐ค |๐ฅณ|๐ฅธ|๐|๐ค|๐ง|๐|๐|๐|๐ฎ|๐ฏ|๐ฒ|๐ณ|๐ฅบ|๐ฆ|๐ง|๐จ|๐ฐ|๐ฅ|๐ข|๐ญ|๐ฑ|๐|๐ฃ|๐|๐|๐ฉ|๐ซ|๐ฅฑ|๐ค|๐ก|๐ |๐คฌ|๐|๐ฟ|๐|๐ฉ|๐คก|๐น|๐บ|๐ป|๐ฝ|๐พ|๐ค|๐บ|๐ธ|๐น|๐ป|๐ผ|๐ฝ|๐|๐ฟ|๐พ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งก|๐|๐|๐|๐|๐ค|๐ค|๐ค|๐ฏ|๐ข|๐ฅ|๐ซ|๐ฆ|๐จ|๐ณ|๐ฃ|๐ฌ|๐จ|๐ฏ|๐ญ|๐ค|๐|๐ค|๐|๐|๐|๐ค|๐ค|๐ค|๐ค|๐ค|๐ค|๐|๐|๐|๐|๐|๐|๐|๐|๐ค|๐ค|๐|๐|๐|๐คฒ|๐ค|๐|๐
|๐คณ|๐ช|๐ฆพ|๐ฆฟ|๐ฆต|๐ฆถ|๐|๐ฆป|๐|๐ง |๐ซ|๐ซ|๐ฆท|๐ฆด|๐|๐|๐
|๐|๐ถ|๐ง|๐ฆ|๐ง|๐ง|๐ฑ|๐จ|๐ง|๐ฉ|๐ง|๐ด|๐ต|๐|๐|๐
|๐|๐|๐|๐ง|๐|๐คฆ|๐คท|๐ฎ|๐ต|๐|๐ฅท|๐ท|๐คด|๐ธ|๐ณ|๐ฒ|๐ง|๐คต|๐ฐ|๐คฐ|๐คฑ|๐ผ|๐
|๐คถ|๐ฆธ|๐ฆน|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐|๐|๐ถ|๐ง|๐ง|๐|๐|๐บ|๐ด|๐ฏ|๐ง|๐ง|๐คบ|๐|๐|๐|๐|๐ฃ|๐|๐|๐ด|๐ต|๐คธ|๐คผ|๐คฝ|๐คพ|๐คน|๐ง|๐|๐|๐ญ|๐ซ|๐ฌ|๐|๐|๐ช|๐ฃ|๐ค|๐ฅ|๐ซ|๐ฃ|๐ฆฐ|๐ฆฑ|๐ฆณ|๐ฆฒ|๐ต|๐|๐ฆ|๐ฆง|๐ถ|๐|๐ฆฎ|๐ฉ|๐บ|๐ฆ|๐ฆ|๐ฑ|๐|๐ฆ|๐ฏ|๐
|๐|๐ด|๐|๐ฆ|๐ฆ|๐ฆ|๐ฆฌ|๐ฎ|๐|๐|๐|๐ท|๐|๐|๐ฝ|๐|๐|๐|๐ช|๐ซ|๐ฆ|๐ฆ|๐|๐ฆฃ|๐ฆ|๐ฆ|๐ญ|๐|๐|๐น|๐ฐ|๐|๐ฟ|๐ฆซ|๐ฆ|๐ฆ|๐ป|๐จ|๐ผ|๐ฆฅ|๐ฆฆ|๐ฆจ|๐ฆ|๐ฆก|๐พ|๐ฆ|๐|๐|๐ฃ|๐ค|๐ฅ|๐ฆ|๐ง|๐|๐ฆ
|๐ฆ|๐ฆข|๐ฆ|๐ฆค|๐ชถ|๐ฆฉ|๐ฆ|๐ฆ|๐ธ|๐|๐ข|๐ฆ|๐|๐ฒ|๐|๐ฆ|๐ฆ|๐ณ|๐|๐ฌ|๐ฆญ|๐|๐ |๐ก|๐ฆ|๐|๐|๐|๐ฆ|๐|๐|๐|๐ชฒ|๐|๐ฆ|๐ชณ|๐ท|๐ธ|๐ฆ|๐ฆ|๐ชฐ|๐ชฑ|๐ฆ |๐|๐ธ|๐ฎ|๐ต|๐น|๐ฅ|๐บ|๐ป|๐ผ|๐ท|๐ฑ|๐ชด|๐ฒ|๐ณ|๐ด|๐ต|๐พ|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฅญ|๐|๐|๐|๐|๐|๐|๐ซ|๐ฅ|๐
|๐ซ|๐ฅฅ|๐ฅ|๐|๐ฅ|๐ฅ|๐ฝ|๐ถ|๐ซ|๐ฅ|๐ฅฌ|๐ฅฆ|๐ง|๐ง
|๐|๐ฅ|๐ฐ|๐|๐ฅ|๐ฅ|๐ซ|๐ฅจ|๐ฅฏ|๐ฅ|๐ง|๐ง|๐|๐|๐ฅฉ|๐ฅ|๐|๐|๐|๐ญ|๐ฅช|๐ฎ|๐ฏ|๐ซ|๐ฅ|๐ง|๐ฅ|๐ณ|๐ฅ|๐ฒ|๐ซ|๐ฅฃ|๐ฅ|๐ฟ|๐ง|๐ง|๐ฅซ|๐ฑ|๐|๐|๐|๐|๐|๐|๐ |๐ข|๐ฃ|๐ค|๐ฅ|๐ฅฎ|๐ก|๐ฅ|๐ฅ |๐ฅก|๐ฆ|๐ฆ|๐ฆ|๐ฆ|๐ฆช|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐|๐ฐ|๐ง|๐ฅง|๐ซ|๐ฌ|๐ญ|๐ฎ|๐ฏ|๐ผ|๐ฅ|๐ซ|๐ต|๐ถ|๐พ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ฅ|๐ฅ|๐ฅค|๐ง|๐ง|๐ง|๐ง|๐ฅข|๐ฝ|๐ด|๐ฅ|๐ช|๐บ|๐|๐|๐|๐|๐บ|๐พ|๐งญ|๐|๐|๐ป|๐|๐|๐|๐|๐|๐|๐|๐|๐งฑ|๐ชจ|๐ชต|๐|๐|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐ฅ|๐ฆ|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐ญ|๐ฏ|๐ฐ|๐|๐ผ|๐ฝ|๐|๐|๐|๐|๐|๐|๐|๐|๐
|๐|๐|๐|๐ |๐ก|๐ข|๐|๐ช|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ป|๐|๐|๐|๐|๐|๐ต|๐ฆฝ|๐ฆผ|๐บ|๐ฒ|๐ด|๐น|๐ผ|๐|๐ฃ|๐ค|๐ข|๐จ|๐ฅ|๐ฆ|๐|๐ง|๐ถ|๐ค|๐ณ|๐ฅ|๐ข|๐ฉ|๐ซ|๐ฌ|๐ช|๐บ|๐|๐|๐ |๐ก|๐ฐ|๐|๐ธ|๐|๐งณ|๐ฐ|๐|๐ง|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ |๐|๐ก|๐|๐ข|๐|๐ฃ|๐|๐ค|๐|๐ฅ|๐|๐ฆ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ก|๐|๐|๐ช|๐|๐ |๐|๐ค|๐ฅ|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐|๐|๐|๐ฅ|๐ง|๐|๐|๐|๐|๐|๐งจ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งง|๐|๐|๐|๐|๐ซ|๐|๐|๐
|๐ฅ|๐ฅ|๐ฅ|๐ฅ|๐|๐|๐|๐|๐พ|๐ฅ|๐ณ|๐|๐|๐|๐ฅ|๐|๐ธ|๐ฅ|๐ฅ|๐ฅ
|๐ฃ|๐คฟ|๐ฝ|๐ฟ|๐ท|๐ฅ|๐ฏ|๐ช|๐ช|๐ฑ|๐ฎ|๐ช|๐งฟ|๐ฎ|๐น|๐ฐ|๐ฒ|๐งฉ|๐งธ|๐ช
|๐ช|๐|๐|๐ด|๐ญ|๐ผ|๐จ|๐งต|๐ชก|๐งถ|๐ชข|๐|๐ถ|๐ฅฝ|๐ฅผ|๐ฆบ|๐|๐|๐|๐งฃ|๐งค|๐งฅ|๐งฆ|๐|๐|๐ฅป|๐ฉฑ|๐ฉฒ|๐ฉณ|๐|๐|๐|๐|๐|๐|๐|๐ฉด|๐|๐|๐ฅพ|๐ฅฟ|๐ |๐ก|๐ฉฐ|๐ข|๐|๐|๐ฉ|๐|๐งข|๐ช|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐ข|๐ฃ|๐ฏ|๐|๐|๐ผ|๐ต|๐ถ|๐|๐|๐|๐ค|๐ง|๐ป|๐ท|๐ช|๐ธ|๐น|๐บ|๐ป|๐ช|๐ฅ|๐ช|๐ฑ|๐ฒ|๐|๐|๐ |๐|๐|๐ป|๐ฅ|๐จ|๐ฑ|๐ฒ|๐ฝ|๐พ|๐ฟ|๐|๐งฎ|๐ฅ|๐|๐ฝ|๐ฌ|๐บ|๐ท|๐ธ|๐น|๐ผ|๐|๐|๐ฏ|๐ก|๐ฆ|๐ฎ|๐ช|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฐ|๐|๐|๐|๐ท|๐ฐ|๐ช|๐ด|๐ต|๐ถ|๐ท|๐ธ|๐ณ|๐งพ|๐น|๐ง|๐จ|๐ฉ|๐ค|๐ฅ|๐ฆ|๐ซ|๐ช|๐ฌ|๐ญ|๐ฎ|๐ณ|๐|๐|๐|๐|๐|๐ผ|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐จ|๐ช|๐ |๐ก|๐ซ|๐ช|๐น|๐ก|๐ช|๐ง|๐ช|๐ฉ|๐|๐ฆฏ|๐|๐ช|๐งฐ|๐งฒ|๐ช|๐งช|๐งซ|๐งฌ|๐ฌ|๐ญ|๐ก|๐|๐ฉธ|๐|๐ฉน|๐ฉบ|๐ช|๐|๐ช|๐ช|๐|๐|๐ช|๐ฝ|๐ช |๐ฟ|๐|๐ชค|๐ช|๐งด|๐งท|๐งน|๐งบ|๐งป|๐ชฃ|๐งผ|๐ชฅ|๐งฝ|๐งฏ|๐|๐ฌ|๐ชฆ|๐ฟ|๐ชง|๐ง|๐ฎ|๐ฐ|๐น|๐บ|๐ป|๐ผ|๐พ|๐|๐|๐|๐
|๐ธ|๐ซ|๐ณ|๐ญ|๐ฏ|๐ฑ|๐ท|๐ต|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฏ|๐|๐|๐|๐ผ|๐ฝ|๐ฆ|๐
|๐|๐ถ|๐ณ|๐ด|๐ฑ|๐ฒ|๐ฑ|๐|๐ฐ|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐
ฐ|๐|๐
ฑ|๐|๐|๐|๐|๐|๐|๐
พ|๐|๐
ฟ|๐|๐|๐|๐|๐|๐ท|๐ถ|๐ฏ|๐|๐น|๐|๐ฒ|๐|๐ธ|๐ด|๐ณ|๐บ|๐ต|๐ด|๐ |๐ก|๐ข|๐ต|๐ฃ|๐ค|๐ฅ|๐ง|๐จ|๐ฉ|๐ฆ|๐ช|๐ซ|๐ถ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ |๐|๐ณ|๐ฒ|๐|๐ฉ|๐|๐ด|๐ณ|๐ป|๐ผ|๐ฝ|๐พ|๐ฟ|โบ|โน|โ |โฃ|โค|โ|โ|โ|โ|โ|โท|โน|โ|โ|โฐ|โช|โฉ|โฒ|โบ|โจ|โฝ|โ|โต|โด|โ|โ|โณ|โ|โฐ|โฑ|โฒ|โ|โญ|โ|โ
|โ|โ|โ|โฑ|โก|โ|โ|โ|โ|โจ|โฝ|โพ|โณ|โธ|โ |โฅ|โฆ|โฃ|โ|โ|โ|โจ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โฐ|โฑ|โฟ|โ |โ|โข|โฃ|โฌ|โ|โก|โ|โฌ|โ|โฌ
|โ|โ|โ|โฉ|โช|โคด|โคต|โ|โก|โธ|โฏ|โ|โฆ|โช|โฎ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โถ|โฉ|โญ|โฏ|โ|โช|โฎ|โซ|โฌ|โธ|โน|โบ|โ|โ|โ|โง|โ|โ|โ|โ|โพ|โผ|โ|โ|โ|โ|โ|ใฐ|โ|โป|โ|โญ|โ
|โ|โ|โ|โ|โฐ|โฟ|ใฝ|โณ|โด|โ|ยฉ|ยฎ|โข|โน|โ|ใ|ใ|โซ|โช|โฌ|โฌ|โผ|โป|โพ|โฝ|โช|โซ)`
/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g")
/*extracting the emojis*/
let emojis = [..."This ๐๐ฉโโ๏ธis the ๐งโโ๏ธtext๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ.".matchAll(emoRegex)];
console.log(emojis)
/*count of emojis*/
let emoCount = [..."This ๐๐ฉโโ๏ธis the ๐งโโ๏ธtext๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ.".matchAll(emoRegex)].length
console.log(emoCount)
/*strip emojis from text*/
let stripped = "This ๐๐ฉโโ๏ธis the ๐งโโ๏ธtext๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ.".replaceAll(emoRegex, "")
console.log(stripped)
/*use the pattern string to build a custom regex*/
let customRegex = new RegExp(".*"+emojiPattern+"{3}$") //match a string ending in 3 emojis
console.log(customRegex.test("yep three here ๐๐ฉโโ๏ธ๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ")) //true
console.log(customRegex.test("nope ๐ฅฃ๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ")) //false
You can use regular expression to detect it in input text:
/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g
I wrote the following function: containsEmojis(input, includeBasic=true), which checks an input string for emojis according to the list of emojis defined in the Unicode specification version 13 (see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt), and allows to ignore "basic" emojis that can be represented with only 3 bytes.
The snippet below defines the function and runs a few test cases:
/**
* iterates over the code points of an input string and returns true if an emoji is found.
*
* an emoji is found if the hex code for the character is 5 characters starting with "1F",
* or if #includeBasic is true, the character is 4 and starts with one of the prefixes of
* a basic emoji as defined in the Unicode specification version 13
* see https://unicode.org/Public/emoji/13.0/emoji-sequences.txt
*
* #input the string to check
* #includeBasic include also the basic emojis that only take 3 characters
*/
function containsEmojis(input, includeBasic) {
if (typeof includeBasic == "undefined")
includeBasic = true;
for (var c of input) {
var cHex = ("" + c).codePointAt(0).toString(16);
var lHex = cHex.length;
if (lHex > 3) {
var prefix = cHex.substring(0, 2);
if (lHex == 5 && prefix == "1f") {
return true;
}
if (includeBasic && lHex == 4) {
if (["20", "21", "23", "24", "25", "26", "27", "2B", "29", "30", "32"].indexOf(prefix) > -1)
return true;
}
}
}
return false;
}
// can be tested as follows:
var input;
input = "Hello World!";
console.log(input, containsEmojis(input));
input = "Hello ๐!";
console.log(input, containsEmojis(input));
console.log(input, containsEmojis(input, false));
// now try a basic emoji
input = "It sparkles โจ yay!";
console.log(input, containsEmojis(input));
// pass false for includeBasic
console.log(input, containsEmojis(input, false));
another solution I found that worked for me:
const example = '๐ฉโ๐ฉโ๐งโ๐ฆ๐ชฒ';
const regexpEmojiPresentation = /\p{Emoji_Presentation}/gu;
console.log(example.match(regexpEmojiPresentation));
check the emoji like bellow ways
function getEmojiChars(text) {
console.log(text.match(/\ud83c[\udf00-\udfff]|\ud83d[\udc00-\ude4f]|\ud83d[\ude80-\udeff]/g)) ;
}
you will get the array of emoji in the text
Given the following data
green-pineapple-bird
red-apple-dog
blue-apple-cat
green-apple-orange-horse
green-apple-mouse
I am trying to figure out how to get (Javascript) RegExp.test() to match for any entry that contains the word "apple" (anywhere) but not match any entry that contains the word "orange" (anywhere). The resulting list would be:
red-apple-dog
blue-apple-cat
green-apple-mouse
I have included the dashes in the data just to make it easier to read. The actual data may, or may not, include dashes.
If I try this:
/^(?!orange).*(apple).*/gm
using https://regex101.com/ it matches all lines.
Using JavaScript RegEx excluding certain word/phrase? for inspiration I tried:
/^(?!.*apple\.(?:orange|butter)).*apple\.\w+.*/gm
If it makes a difference I am using Mozilla Rhino 1.7R4.
For each character not in apple (before or after), you need to repeat the negative lookahead for orange. Because you don't want pineapple to match, you should also put word boundaries around the apple:
const re = /^((?!orange).)*\bapple\b((?!orange).)*$/;
`green-pineapple-bird
red-apple-dog
blue-apple-cat
green-apple-orange-horse
green-apple-mouse`
.split('\n')
.forEach(str => {
console.log(re.test(str) + ' ' + str)
});
I am writing a message formatting parser that has the capability (among others) to parse links. This specific case requires parsing a link in the from of <url|linkname> and replacing that text with just the linkname. The issue here is that both url or linkname may or may not contain \1 or \2 characters anywhere in any order (at most one of each though). I want to match the pattern but keep the "invalid" characters. This problem solves itself for linkname as that part of the pattern is just ([^\n+]), but the url fragment is matched by a much more complicated pattern, more specifically the URL validation pattern from is.js. It would not be trivial to modify the whole pattern manually to tolerate [\1\2] everywhere, and I need the pattern to preserve those characters as they are used for tracking purposes (so I can't simply just .replace(/\1|\2/g, "") before matching).
If this kind of matching is not possible, is there some automated way to reliably modify the RegExp to add [\1\2]{0,2} between every character match, add \1\2 to all [chars] matches, etc.
This is the url pattern taken from is.js:
/(?:(?:https?|ftp):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?/i
This pattern was adapted for my purposes and for the <url|linkname> format as follows:
let namedUrlRegex = /<((?:(?:https?|ftp):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?)\|([^\n]+)>/ig;
The code where this is used is here: JSFiddle
Examples for clarification (... represents the namedUrlRegex variable from above, and $2 is the capture group that captures linkname):
Current behavior:
"<googl\1e.com|Google>".replace(..., "$2") // "<googl\1e.com|Google>" WRONG
"<google.com|Goo\1gle>".replace(..., "$2") // "Goo\1gle" CORRECT
"<not_\1a_url|Google>".replace(..., "$2") // "<not_\1a_url|Google>" CORRECT
Expected behavior:
"<googl\1e.com|Google>".replace(..., "$2") // "Google" (note there is no \1)
"<google.com|Goo\1gle>".replace(..., "$2") // "Goo\1gle"
"<not_\1a_url|Google>".replace(..., "$2") // "<not_\1a_url|Google>"
Note the same rules for \1 apply to \2, \1\2, \1...\2, \2...\1 etc
Context: This is used to normalize a string from a WYSIWYG editor to the length/content that it will display as, preserving the location of the current selection (denoted by \1 and \2 so it can be restored after parsing). If the "caret" is removed completely (e.g. if the cursor was in the URL of a link), it will select the whole string instead. Everything works as expected, except for when the selection starts or ends in the url fragment.
Edit for clarification: I only want to change a segment in a string if it follows the format of <url|linkname> where url matches the URL pattern (tolerating \1, \2) and linkname consists of non-\n characters. If this condition is not met within a <...|...> string, it should be left unaltered as per the not_a_url example above.
I ended up making a RegEx that matches all "symbols" in the expression. One quirk of this is that it expects :, =, ! characters to be escaped, even outside of a (?:...), (?=...), (?!...) expression. This is addressed by escaping them before processing.
Fiddle
let r = /(\\.|\[.+?\]|\w|[^\\\/\[\]\^\$\(\)\?\*\+\{\}\|\+\:\=\!]|(\{.+?\}))(?:((?:\{.+?\}|\+|\*)\??)|\??)/g;
let url = /((?:(?:https?|ftp):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?)/
function tolerate(regex, insert) {
let first = true;
// convert to string
return regex.toString().replace(/\/(.+)\//, "$1").
// escape :=!
replace(/((?:^|[^\\])\\(?:\\)*\(\?|[^?])([:=!]+)/g, (m, g1, g2) => g1 + (g2.split("").join("\\"))).
// substitute string
replace(r, function(m, g1, g2, g3, g4) {
// g2 = {...} multiplier (to prevent matching digits as symbols)
if (g2) return m;
// g3 = multiplier after symbol (must wrap in parenthesis to preserve behavior)
if (g3) return "(?:" + insert + g1 + ")" + g3;
// prevent matching tolerated characters at beginning, remove to change this behavior
if (first) {
first = false;
return m;
}
// insert the insert
return insert + m;
}
);
}
alert(tolerate(url, "\1?\2?"));
I was pointed out to this post, which does not seem to follow the criteria I have:
Replace a Regex capture group with uppercase in Javascript
I am trying to make a regex that will:
format a string by adding uppercase for the first letter of each word and lower case for the rest of the characters
ignore HTML markup
Accept swedish characters (รฅรครถร
รร)
Say I've got this string:
<b>app</b>le store รถstersund
Then I want it to be (changes marked by uppercase characters)
<b>App</b>le Store รstersund
I've been playing around with it and the closest I've got is the following:
(?!([^<])*?>)[รฅรครถร
รร]|\s\b\w
Resulted in
<b>app</b>le Store รstersund
Or this
/(?!([^<])*?>)[รฅรครถร
รร]|\S\b\w/g
Resulted in
<B>App</B>Le store รstersund
Here's a fiddle:
http://refiddle.com/refiddles/598aabef75622d4a531b0000
Any help or advice is much appreciated.
It is not possible to do this with regexp alone, since regexp doesn't understand HTML structure. [*] Instead, we need to process each text node, and carry through our logic for what is the beginning of the word in case a word continues across different text nodes. A character is at start of the word if it is preceded by a whitespace, or if it is at the start of the string and it is either the first text node, or the previous text node ended in whitespace.
function htmlToTitlecase(html, letters) {
let div = document.createElement('div');
let re = new RegExp("(^|\\s)([" + letters + "])", "gi");
div.innerHTML = html;
let treeWalker = document.createTreeWalker(div, NodeFilter.SHOW_TEXT);
let startOfWord = true;
while (treeWalker.nextNode()) {
let node = treeWalker.currentNode;
node.data = node.data.replace(re, function(match, space, letter) {
if (space || startOfWord) {
return space + letter.toUpperCase();
} else {
return match;
}
});
startOfWord = node.data.match(/\s$/);
}
return div.innerHTML;
}
console.log(htmlToTitlecase("<b>app</b>le store รถstersund", "a-zรฅรครถ"));
// <b>App</b>le Store รstersund
[*] Maybe possible, but even if so, it would be horribly ugly, since it would need to cover an awful amount of corner cases. Also might need a stronger RegExp engine than JavaScript's, like Ruby's or Perl's.
EDIT:
Even if just specifying really simple html tags? The only ones I am actually in need of covering is <b> and </b> at the moment.
This was not specified in the question. The solution is general enough to work for any markup (including simple tags). But...
function simpleHtmlToTitlecaseSwedish(html) {
return html.replace(/(^|\s)(<\/?b>|)([a-zรฅรครถ])/gi, function(match, space, tag, letter) {
return space + tag + letter.toUpperCase();
});
}
console.log(simpleHtmlToTitlecaseSwedish("<b>app</b>le store รถstersund", "a-zรฅรครถ"));
I have a solution which use almost only regex. It may be not the most intuitive way to do it, but it should be effective and I find it funny :)
You have to append at the end of your string every lowercase character followed by their uppercase counterpart, like this (it must also be preceded by a space for my regex) :
aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZรฅร
รครรถร
(I don't know which letters are missing, I know nothing about swedish alphabet, sorry... I'm counting on you to correct that !)
Then you can use the following regex :
(?![^<]*>)(\s<[^/]*?>|\s|^)([\wรฅรครถ])(?=.*\2(.)\S*$)|[\wรฅร
รครรถร]+$
Replace by :
$1$3
Test it here
Here is a working javascript code :
// Initialization
var regex = /(?![^<]*>)(\s<[^/]*?>|\s|^)([\wรฅรครถ])(?=.*\2(.)\S*$)|[\wรฅร
รครรถร]+$/g;
var string = "test <b when=\"2>1\">ap<i>p</i></b>le store รถstersund";
// Processing
result = string + " aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZรฅร
รครรถร";
result = result.replace(regex, "$1$3");
// Display result
console.log(result);
Edit : I forgot to handle first word of the string, it's corrected :)
Just trying to figure this one out as regex is nowhere near my strong point :(
Basically I'm trying to get the value between bbcode tags: That could look like either of the following:
[center]text[/center]
[left][center]text[/center][/left]
[right][left][center]text[/center][/left][/right]
And currently have this hideous if else block of code to prevent it getting large like the third option above.
if (/\[left\]|\[\/left\]/.test(text[2])) {
// set the value in the [left][/left] tags
text[2] = text[2].match(/\[left\](.*?)\[\/left\]/)[1];
} else if (/\[right\]|\[\/right\]/.test(text[2])) {
// set value in the [right][/right] tags
text[2] = text[2].match(/\[right\](.*?)\[\/right\]/)[1];
} else if (/\[center\]|\[\/center\]/.test(text[2])) {
// set value in the [right][/right] tags
text[2] = text[2].match(/\[center\](.*?)\[\/center\]/)[1];
}
What I'd like to do is shorten it down to a single regex expression to grab that value text from the above examples, I've gotten down to an expression like this:
/\[(?:center|left|right)\](.*?)\[\/(?:center|left|right)\]/
But as you can see in this RegExr demo, it doesn't match what I need it to.
How can I achieve this?
Note
It should only match left|right|center as the selected text could also have various other bbcode tags.
If the string looks like this:
[center][left][img]/link/to/img.png[/img][/left][/center]
I want to get what is between the left|center|right tags which in this case would be:
[img]/link/to/img.png[/img]
More examples:
[center][url=lintosomething.com]LINK TEXT[/url][/center]
Should only get: [url=lintosomething.com]LINK TEXT[/url]
Or
[center]egibibskdfbgfdkfbg sd fgkgb fkgbgk fhwo3g regbiurb geir so go to [url=lintosomething.com]LINK TEXT[/url] and ibgri gbenkenbieurgnerougnerogrnreog erngo[/center]
Wanting:
egibibskdfbgfdkfbg sd fgkgb fkgbgk fhwo3g regbiurb geir so go to [url=lintosomething.com]LINK TEXT[/url] and ibgri gbenkenbieurgnerougnerogrnreog erngo
Edit: Ok, I think this fits your needs.
My regex:
/[^\]\[]*\[(\w+)[=\.\"\w]*\][^\]]+\[\/\1\][^\]\[]*/g
Explanation:
Match 0 or more characters that arent [ or ]
Match a single [
Match 1 or more of alpha characters, we'll use this later as a backreference
Match 0 or more of = . " or alpha characters
Match a single ]
Match 1 or more non [ characters
Match a single [
Match a single /
Match the same characters as step 3. (Our back reference)
Match a single ]
Match 0 or more characters that arent [ or ]
See it in action
However I would like to state that if you're going to be parsing bbcodes you're almost certainly better off just using a bbparser.
Why not just replace all those tags with empty string
var rawString; // your input string
var cleanedString = rawString.replace(~\[/?(left|right|center)\]~, '');
You could use a capturing group like this:
(?:\[\w+\])*(\w+)(?:\[\/\w+\])*
Or with a capture group named "value" like this:
(?:\[\w+\])*(?<value>\w+)(?:\[\/\w+\])*
The first and last groups are non-capturing... (?: ...)
And the middle group is capturing (\w+)
And the middle group if named like this (?<value>\w+)
Note: For simplicity, I replaced your center|left|right values with \w+ but you could swap them back in with no impact.
I use an app called RegExRX. Here's a screenshot with the RegEx and captured values.
Lots of ways you could tweak it. Good luck!