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I have an array of objects.
I need to get an array with unique website name with newest date.
Sample data
"data" : [
{
"position" : 2,
"website" : "abc.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 3,
"website" : "qwe.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 1,
"website" : "qwe.com",
"owned" : false,
"date" : "2020-04-06",
"dateTime" : ISODate("2020-04-06T00:00:00.000Z")
},
{
"position" : 6,
"website" : "xyz.agency",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 4,
"website" : "opq.com",
"owned" : true,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 2,
"website" : "opq.com",
"owned" : true,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 4,
"website" : "opq.com",
"owned" : true,
"date" : "2020-04-01",
"dateTime" : ISODate("2020-04-01T00:00:00.000Z")
}
]
Based on datetTime, position and website. Need a mongoDB query or Javascript code. (Earlier its with dateTime and website)
(Extracting the object from which have highest date and unique website name with top position)
Expected response
"data" : [
{
"position" : 2,
"website" : "abc.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 3,
"website" : "qwe.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 6,
"website" : "xyz.agency",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
},
{
"position" : 2,
"website" : "opq.com",
"owned" : true,
"date" : "2020-05-06",
"dateTime" : ISODate("2020-05-06T00:00:00.000Z")
}
],
use forEach and build an object to handle dulicates and maintain only new date item.
Get Object.values from above object.
const uniq = (arr) => {
const res = {};
arr.forEach((item) => {
if (
!res[item.website] ||
new Date(item.dateTime) > new Date(res[item.website].dateTime)
) {
res[item.website] = { ...item };
}
});
return Object.values(res);
};
// Update uniq2
const uniq2 = (arr) => {
const res = {};
arr.forEach((item) => {
if (!res[item.website]) {
res[item.website] = { ...item };
} else {
if (new Date(item.dateTime) > new Date(res[item.website].dateTime)) {
res[item.website].dateTime = item.dateTime;
}
if (item.position > res[item.website].position) {
res[item.website].position = item.position;
}
}
});
return Object.values(res);
};
const data2 = [
{
position: 2,
website: "abc.com",
owned: false,
date: "2020-05-06",
dateTime: "2020-05-06T00:00:00.000Z",
},
{
position: 3,
website: "qwe.com",
owned: false,
date: "2020-05-06",
dateTime: "2020-05-06T00:00:00.000Z",
},
{
position: 1,
website: "qwe.com",
owned: false,
date: "2020-04-06",
dateTime: "2020-04-06T00:00:00.000Z",
},
{
position: 6,
website: "xyz.agency",
owned: false,
date: "2020-05-06",
dateTime: "2020-05-06T00:00:00.000Z",
},
{
position: 1,
website: "opq.com",
owned: true,
date: "2020-05-06",
dateTime: "2020-05-06T00:00:00.000Z",
},
{
position: 2,
website: "opq.com",
owned: true,
date: "2020-05-06",
dateTime: "2020-05-06T00:00:00.000Z",
},
{
position: 3,
website: "opq.com",
owned: true,
date: "2020-04-01",
dateTime: "2020-04-01T00:00:00.000Z",
},
];
console.log(uniq2(data2));
In javascript you can reduce it:
var data = [ { "position" : 0, "website" : "abc.com", "owned" : false, "date" : "2020-05-06", "dateTime" : 'ISODate("2020-05-06T00:00:00.000Z")' }, { "position" : 0, "website" : "qwe.com", "owned" : false, "date" : "2020-05-06", "dateTime" : 'ISODate("2020-05-06T00:00:00.000Z")' }, { "position" : 0, "website" : "qwe.com", "owned" : false, "date" : "2020-04-06", "dateTime" : 'ISODate("2020-04-06T00:00:00.000Z")' }, { "position" : 0, "website" : "xyz.agency", "owned" : false, "date" : "2020-05-06", "dateTime" : 'ISODate("2020-05-06T00:00:00.000Z")' }, { "position" : 1, "website" : "opq.com", "owned" : true, "date" : "2020-05-06", "dateTime" : 'ISODate("2020-05-06T00:00:00.000Z")' }, { "position" : 1, "website" : "opq.com", "owned" : true, "date" : "2020-04-01", "dateTime" : 'ISODate("2020-04-01T00:00:00.000Z")' }];
var result = data.reduce((acc, elem)=>{
isPresent = acc.findIndex(k=>k.website==elem.website);
if(isPresent==-1){
acc.push(elem);
} else {
if(new Date(acc[isPresent].date) < new Date(elem.date)) acc[isPresent] = elem;
}
return acc;
},[]);
console.log(result);
Try this- It also takes into consideration when the object is duplicate and dateTime are same/equal :
var d = { "data" : [
{
"position" : 0,
"website" : "abc.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : "2020-05-06T00:00:00.000Z"
},
{
"position" : 0,
"website" : "qwe.com",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : "2020-05-06T00:00:00.000Z"
},
{
"position" : 0,
"website" : "xyz.agency",
"owned" : false,
"date" : "2020-05-06",
"dateTime" : "2020-05-06T00:00:00.000Z"
},
{
"position" : 1,
"website" : "opq.com",
"owned" : true,
"date" : "2020-05-06",
"dateTime" : "2020-05-06T00:00:00.000Z"
}
]
}
var filtered = d.data.filter((el,idx)=> {
let found = d.data.findIndex((e,i)=> e.website === el.website && idx !== i);
return found === -1 ? el:Date.parse(el.dateTime) ===
Date.parse((d.data[found]).dateTime) && (found < idx) ? el:
Date.parse(el.dateTime) <
Date.parse((d.data[found]).dateTime) ? el: false
});
console.log(filtered);
Need to remove duplication in array of objects and merge array with union USING JS.
trying to filter array
Just wanted to merge array["INTERFACE"] on the basis of APP_ID. and remove duplicate records.
unfiltered unmerged array!
var data = [
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC",
"URL" : "/SummaryCopc",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "05",
"NAME" : "SUMMARY",
"URL" : "/Summary",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC 2",
"URL" : "/SummaryCopc2",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD 2",
"URL" : "/Dashboard 2",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
}
];
wanted result
[
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "05",
"NAME" : "SUMMARY",
"URL" : "/Summary",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC",
"URL" : "/SummaryCopc",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
}, {
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD 2",
"URL" : "/Dashboard2",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC 2",
"URL" : "/SummaryCopc2",
"STATUS" : "A"
}
]
}
]
trying to filter array
Just wanted to merge array["INTERFACE"] on the basis of APP_ID. and remove duplicate records.
Here is a slightly elastic solution relying on function generators that allows dynamic aggregation.
The logic followed by the below example is that in your data input, the unique key of the main objects is APP_ID. Next, the aggregation rule of each APP_ID is that it should follow another aggregation rule for INTERFACE. Each interface, in fact, has a unique NAME, explaining why you have multiple "07" and "06" in your result sample.
The code explanation is documented in the code itself.
var data = [
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC",
"URL" : "/SummaryCopc",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "05",
"NAME" : "SUMMARY",
"URL" : "/Summary",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC 2",
"URL" : "/SummaryCopc2",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD 2",
"URL" : "/Dashboard 2",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
}
];
// Aggregate duplicates with a common uniqueKey, invoking the aggregateExpression callback for each pair.
function* aggregateDuplicates(arr, uniqueKey, aggregateExpression) {
const aggregateGroups = arr.reduce((acc,next) => {
acc[next[uniqueKey]] = acc[next[uniqueKey]] || [];
return acc[next[uniqueKey]].push(next), acc;
}, {});
// loop items.
for (var [_, entries] of Object.entries(aggregateGroups)) {
// Aggregate results following the aggregateExpression.
yield Object.assign({}, entries.reduce((acc, next) => aggregateExpression(acc, next)));
}
}
// Aggregate duplicates of data, whose unique key is APP_ID.
const res = [...aggregateDuplicates(data, 'APP_ID', (a,b) => {
// In order to properly aggregate the INTERFACE property, acquire the set of entires interfaces of two items with the same APP_ID.
var interfacesSet = [...a.INTERFACE, ...b.INTERFACE];
// Finally, spread common values between them, then aggregate the INTERFACE property by its unique NAME key.
return Object.assign(a, b, {
INTERFACE: [...aggregateDuplicates(interfacesSet, 'NAME', (c,d) => {
// For that NAME property, just assign the values of both objects, nothing more nothing less.
return Object.assign(c,d)
})]
});
})];
console.log(res);
SIDE NOTE: The sorting to the INTERFACE property is not applied, this is a plus, but I don't think it's mandatory as long as the output data is effectively correct.
// Create the array of APP_ID
let idArr = data.map(val => val.APP_ID)
// Remove duplicate APP_ID
idArr = [...new Set(idArr)];
// Filter data according to unique APP_IDs
let newArr = idArr.map(val => {
return data.filter(value => value.APP_ID == val)[0]
})
console.log(newArr);
Solution
Here is a quick solution that I was able to come up with,
Note that this solution takes care of union of INTERFACES within the same APP_ID
const data = [
{
APP_ID: '1001',
INTERFACE: [
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'A',
},
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD',
URL: '/Dashboard',
STATUS: 'A',
},
{
INTERFACE_ID: '06',
NAME: 'SUMMARY COPC',
URL: '/SummaryCopc',
STATUS: 'A',
},
],
},
{
APP_ID: '1002',
INTERFACE: [
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD',
URL: '/Dashboard',
STATUS: 'A',
},
{
INTERFACE_ID: '08',
NAME: 'BIOMETRIC',
URL: '/Biometric',
STATUS: 'A',
},
],
},
{
APP_ID: '1001',
INTERFACE: [
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'A',
},
{
INTERFACE_ID: '05',
NAME: 'SUMMARY',
URL: '/Summary',
STATUS: 'A',
},
{
INTERFACE_ID: '06',
NAME: 'SUMMARY COPC 2',
URL: '/SummaryCopc2',
STATUS: 'A',
},
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD 2',
URL: '/Dashboard 2',
STATUS: 'A',
},
],
},
{
APP_ID: '1002',
INTERFACE: [
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD',
URL: '/Dashboard',
STATUS: 'A',
},
{
INTERFACE_ID: '08',
NAME: 'BIOMETRIC',
URL: '/Biometric',
STATUS: 'A',
},
],
},
];
const result = {};
data.forEach(elem => {
if (!result[elem.APP_ID]) {
result[elem.APP_ID] = {};
result[elem.APP_ID].APP_ID = elem.APP_ID;
result[elem.APP_ID].INTERFACE = elem.INTERFACE;
} else {
const interfaces = result[elem.APP_ID].INTERFACE;
for (const elemInterface of elem.INTERFACE) {
if (
!interfaces.some(inter => {
return elemInterface.INTERFACE_ID === inter.INTERFACE_ID;
})
) {
interfaces.push(elemInterface);
}
}
}
});
console.log('TCL: results', Object.values(result));
Assumptions:
Since you stated that you wanted union of the interfaces within the same APP_ID I assume that there should be no duplicate interfaces
Example: If there is an interface array A1,
[
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'A',
},
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD',
URL: '/Dashboard',
STATUS: 'A',
},
{
INTERFACE_ID: '06',
NAME: 'SUMMARY COPC',
URL: '/SummaryCopc',
STATUS: 'A',
},
]
and another interface array A2,
[
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'A',
},
{
INTERFACE_ID: '05',
NAME: 'SUMMARY',
URL: '/Summary',
STATUS: 'A',
},
{
INTERFACE_ID: '06',
NAME: 'SUMMARY COPC 2',
URL: '/SummaryCopc2',
STATUS: 'A',
},
{
INTERFACE_ID: '07',
NAME: 'DASHBOARD 2',
URL: '/Dashboard 2',
STATUS: 'A',
},
]
Then A1 union A2 would be,
[
{
"INTERFACE_ID": "01",
"NAME": "CIF OPENNING",
"URL": "/CusIdInfo",
"STATUS": "A"
},
{
"INTERFACE_ID": "07",
"NAME": "DASHBOARD",
"URL": "/Dashboard",
"STATUS": "A"
},
{
"INTERFACE_ID": "06",
"NAME": "SUMMARY COPC",
"URL": "/SummaryCopc",
"STATUS": "A"
},
{
"INTERFACE_ID": "05",
"NAME": "SUMMARY",
"URL": "/Summary",
"STATUS": "A"
}
]
Note that there are no duplicates.
My second assumption is that when you check for duplicity in interfaces you use the INTERFACE_ID and not the whole interface object.
Example: Assume an interface object I1,
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'A',
}
and another interface object I2 with the only difference being that it has a different status value which is 'B',
{
INTERFACE_ID: '01',
NAME: 'CIF OPENNING',
URL: '/CusIdInfo',
STATUS: 'B',
}
I am still considering I1 and I2 to be duplicates based on their INTERFACE_ID.
Suppose you want to compare entire object for duplicity then update your question and I shall change the answer to factor it in
Came up with this solution. Hope this works for you.
NOTE : In the expected result array you have 2 interface objects with same ID so i am assuming that two interface are duplicate only if all their properties match.
var data = [
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC",
"URL" : "/SummaryCopc",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1001",
"INTERFACE" : [
{
"INTERFACE_ID" : "01",
"NAME" : "CIF OPENNING",
"URL" : "/CusIdInfo",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "05",
"NAME" : "SUMMARY",
"URL" : "/Summary",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "06",
"NAME" : "SUMMARY COPC 2",
"URL" : "/SummaryCopc2",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD 2",
"URL" : "/Dashboard 2",
"STATUS" : "A"
}
]
},
{
"APP_ID" : "1002",
"INTERFACE" : [
{
"INTERFACE_ID" : "07",
"NAME" : "DASHBOARD",
"URL" : "/Dashboard",
"STATUS" : "A"
},
{
"INTERFACE_ID" : "08",
"NAME" : "BIOMETRIC",
"URL" : "/Biometric",
"STATUS" : "A"
}
]
}
];
isInterfaceDuplicate = function(interface, app_id) {
var keys = Object.keys(interface);
var isDuplicate = false;
app_map[app_id].forEach(app_obj => {
var matched = true;
keys.forEach(key => {
if (interface[key] !== app_obj[key]) {
matched = false;
return;
}
});
if (matched) {
isDuplicate = true;
return;
}
});
return isDuplicate;
};
/* Create a mapping for APP_ID and INTERFACE */
var app_map = {};
data.forEach(app_obj => {
// If APP_ID is not present in map, then add in map directly.
if (!app_map[app_obj.APP_ID]) {
app_map[app_obj.APP_ID] = [...app_obj.INTERFACE];
return;
}
// If APP_ID is present in map, only add non duplicate interfaces in APP_ID key.
app_obj.INTERFACE.forEach(interface => {
var isDuplicate = isInterfaceDuplicate(interface, app_obj.APP_ID);
if (!isDuplicate) {
app_map[app_obj.APP_ID].push({...interface});
}
});
});
/* Create result array from the map */
var result = [];
Object.keys(app_map).forEach(app_id => {
result.push({
"APP_ID": app_id,
"INTERFACE": app_map[app_id]
});
});
console.log(result);
I have the following firebase database. I would like to filter and list the orders which's deliveryDuration value is "45"
"orders" : [ null, {
"comment" : "",
"date" : "2018-07-09 10:07:18",
"deliveryDuration" : "45",
"delivery_address" : "",
"item" : [ {
"available" : true,
"category" : "Dessert",
"details" : "(Hausgemacht)",
"name" : "Warmer Topfenstrudel",
"price" : 3.9,
"quantity" : 1
} ],
"orderVerified" : false,
"telefon" : "",
"userID" : "xyc#gmail.com",
"userName" : ""
}, {
"comment" : "",
"date" : "2018-07-10 10:07:33",
"deliveryDuration" : "30",
"delivery_address" : "",
"item" : [ {
"available" : true,
"category" : "Dessert",
"details" : "(Hausgemacht)",
"name" : "Warmer Topfenstrudel",
"price" : 3.9,
"quantity" : 1
} ],
"orderVerified" : false,
"telefon" : "",
"userID" : "xyc#gmail.com",
"userName" : ""
}, {
"comment" : "",
"date" : "2018-07-10 10:13:13",
"deliveryDuration" : "10",
"delivery_address" : "",
"item" : [ {
"available" : true,
"category" : "Spezialitäten",
"details" : "Schweinschnitzel mit Parmesan gebacken auf Spaghetti Napoli",
"name" : "Piccata Milanese",
"price" : 12.9,
"quantity" : 1
} ],
"orderVerified" : false,
"telefon" : "",
"userID" : "xyc#gmail.com",
"userName" : ""
}
}
I tried writing the following function:
getNewItems: function (order) {
if (db.ref('orders').child(order).child('deliveryDuration').equalTo(45)){
return db.ref('orders').child(order).child('deliveryDuration')
}}
How could I get the filtered objects? I was thinking that that i write an if-else statement and the function returns the values what i was looking for.
I think you're looking for this:
getNewItems: function (order) {
return db.ref('orders').orderByChild('deliveryDuration').equalTo(45));
}}
This Firebase query takes each child node of the location you query, orders it by the deliveryDuration property, and then filters to only get the ones who are equal to 45.
In my angular , i am having one $scope variable as below.
$scope.roleList2 = [
{ "roleName" : "User", "roleId" : "role1", "children" : [
{ "roleName" : "subUser1", "roleId" : "role11", "collapsed" : true, "children" : [] },
{ "roleName" : "subUser2", "roleId" : "role12", "collapsed" : true, "children" : [
{ "roleName" : "subUser2-1", "roleId" : "role121", "children" : [
{ "roleName" : "subUser2-1-1", "roleId" : "role1211", "children" : [] },
{ "roleName" : "subUser2-1-2", "roleId" : "role1212", "children" : [] }
]}
]}
]},
{ "roleName" : "Admin", "roleId" : "role2", "children" : [
{ "roleName" : "subAdmin1", "roleId" : "role11", "collapsed" : true, "children" : [] },
{ "roleName" : "subAdmin2", "roleId" : "role12", "children" : [
{ "roleName" : "subAdmin2-1", "roleId" : "role121", "children" : [
{ "roleName" : "subAdmin2-1-1", "roleId" : "role1211", "children" : [] },
{ "roleName" : "subAdmin2-1-2", "roleId" : "role1212", "children" : [] }
]}
]}
]},
{ "roleName" : "Guest", "roleId" : "role3", "children" : [
{ "roleName" : "subGuest1", "roleId" : "role11", "children" : [] },
{ "roleName" : "subGuest2", "roleId" : "role12", "collapsed" : true, "children" : [
{ "roleName" : "Banned Area", "roleId" : "role121", "children" : [
{ "roleName" : "subGuest2-1-1", "roleId" : "role1211", "Parent":"Banned Area" ,"children" : [] },
{ "roleName" : "subGuest2-1-2", "roleId" : "role1212", "Parent":"Banned Area", "children" : [] }
]}
]}
]}
];
I want to first find array for given path
Admin>subAdmin2-1
and insert
{ "roleName" : "subAdmin2-1-3", "roleId" : "role1213", "children" : [] }
Please guide, how can achieve this.
This is quick and dirty but will work:
for (var i=0; i<$scope.roleList2.length; i++) {
if ($scope.roleList2[i].roleName == "Admin") {
var subRoles = $scope.roleList2[i].children;
for (var k=0; k<subRoles.length; k++) {
if (subRoles[k].roleName == "subAdmin2") {
var subSubRoles = subRoles[k].children;
for (var j=0; j<subSubRoles.length; j++) {
if (subSubRoles[j].roleName == "subAdmin2-1") {
subSubRoles[j].children.push({ "roleName" : "subAdmin2-1-3", "roleId" : "role1213", "children" : [] });
console.log(subSubRoles[j]);
}
}
}
}
}
}
You can try improving with a recursion. And you probably want this to be in a function, so you can call
var role = "{ "roleName" : "subAdmin2-1-3", "roleId" : "role1213", "children" : [] }";
$scope.addSubRole(role, "Admin", "subAdmin2-1")
This is my 1st time using underscore...I've this simple json...
"categories" : [
{
"tag" : "cat1",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 1",
"pt" : "Categoria 1"
},
"children" : [
{
"tag" : "cat11",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 1.1",
"pt" : "Categoria 1.1"
}
},
{
"tag" : "cat12",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 1.2",
"pt" : "Categoria 1.2"
}
}
]
},
{
"tag" : "cat2",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 2",
"pt" : "Categoria 2"
},
"children" : [
{
"tag" : "cat21",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 2.1",
"pt" : "Categoria 2.1"
}
},
{
"tag" : "cat22",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 2.2",
"pt" : "Categoria 2.2"
}
}
]
},
{
"tag" : "cat3",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 3",
"pt" : "Categoria 3"
},
"children" : [
{
"tag" : "cat31",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 3.1",
"pt" : "Categoria 3.1"
}
},
{
"tag" : "cat32",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 3.2",
"pt" : "Categoria 3.2"
}
}
]
},
{
"tag" : "cat4",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 4",
"pt" : "Categoria 4"
},
"children" : [
{
"tag" : "cat41",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 4.1",
"pt" : "Categoria 4.1"
}
},
{
"tag" : "cat42",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 4.2",
"pt" : "Categoria 4.2"
}
}
]
}
]
you can see I've the TAG key in several places. I need to get the entire tree based in a criteria for tag. I was using, find, filter, where and findWhere and all the time I got the same results:
var find = _.find($rootScope.webshop.categories, {tag: 'cat1'});
this works !
but if I try...
var find = _.find($rootScope.webshop.categories, {tag: 'cat11'});
No results :( Even using _.where or ._filter or ._findWhere. - The results always will be the same.
Can someone help a beginner in Underscore with something that's probably simple ?!
ty !
_.find does not recurse, you will have to build your own solution. Something like this:
_.findIn = function() {
var args = Array.prototype.slice.call(arguments, 0);
var childrenProp = args[0];
var result = _.find.apply(_, args.slice(1));
if (result !== void(8)) return result;
var arr = args[1];
for (var i = 0, l = arr.length; i < l; i++) {
args[1] = arr[i][childrenProp];
var result = _.findIn.apply(_, args);
if (result !== void(8)) return result;
}
return void(8);
}
_.findIn('children', categories, {tag: 'cat11'})
categories = [
{
"tag" : "cat1",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 1",
"pt" : "Categoria 1"
},
"children" : [
{
"tag" : "cat11",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 1.1",
"pt" : "Categoria 1.1"
}
},
{
"tag" : "cat12",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 1.2",
"pt" : "Categoria 1.2"
}
}
]
},
{
"tag" : "cat2",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 2",
"pt" : "Categoria 2"
},
"children" : [
{
"tag" : "cat21",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 2.1",
"pt" : "Categoria 2.1"
}
},
{
"tag" : "cat22",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 2.2",
"pt" : "Categoria 2.2"
}
}
]
},
{
"tag" : "cat3",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 3",
"pt" : "Categoria 3"
},
"children" : [
{
"tag" : "cat31",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 3.1",
"pt" : "Categoria 3.1"
}
},
{
"tag" : "cat32",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 3.2",
"pt" : "Categoria 3.2"
}
}
]
},
{
"tag" : "cat4",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 4",
"pt" : "Categoria 4"
},
"children" : [
{
"tag" : "cat41",
"active" : true,
"order" : 10,
"title" : {
"en" : "Category 4.1",
"pt" : "Categoria 4.1"
}
},
{
"tag" : "cat42",
"active" : true,
"order" : 20,
"title" : {
"en" : "Category 4.2",
"pt" : "Categoria 4.2"
}
}
]
}
]
_.findIn = function() {
var args = Array.prototype.slice.call(arguments, 0);
var childrenProp = args[0];
var result = _.find.apply(_, args.slice(1));
if (result !== void(8)) return result;
var arr = args[1];
for (var i = 0, l = arr.length; i < l; i++) {
args[1] = arr[i][childrenProp];
var result = _.findIn.apply(_, args);
if (result !== void(8)) return result;
}
return void(8);
}
document.write(JSON.stringify(_.findIn('children', categories, {tag: 'cat11'})));
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