Hey so I need to create a script using googlespreadsheets (javascript) that takes the input of one cell and outputs all the emojis from that cell into the selected one. I want to do this by removing everything from the cell text except the emoji. This is because if I try to just match emojis my output is not correct.
I'm using this regex to locate emojis.
var re = /[\u1F60-\u1F64]|[\u2702-\u27B0]|[\u1F68-\u1F6C]|[\u1F30-\u1F70]|[\u2600-\u26ff]|[\uD83C-\uDBFF\uDC00-\uDFFF]+/gi;
How can I remove everything from the text except items with this regex. Or how can I remove everything but unicode. I have tried all the other suggestions but the output isn't correct or it doesn't work with spreadsheets.
Currently I have:
function SHOW_EMOJIS(s) {
var re = /[\u1F60-\u1F64]|[\u2702-\u27B0]|[\u1F68-\u1F6C]|[\u1F30-\u1F70]|[\u2600-\u26ff]|[\uD83C-\uDBFF\uDC00-\uDFFF]+/gi;
var result = s.match(re).toString();
return result;
}
This returns all the emojis, but instead of seeing: โ ๏ธ๐โ๏ธ๐ฉ๐ปโโ๏ธโ๏ธ๐ฅ I see โ ,๐,โ,๐ฉ๐ป,โ,โ,๐ฅ . The doctor is returned as two separate emoji-characters.
Instead of a custom function, Why not try the inbuilt REGEX?
=REGEXREPLACE(A5,"[[:print:]]","")
Emoji is not printable according to Google Re2๐
To replace all emojis from [A1] please try:
=REGEXREPLACE($A$1,"[๐ป๐ผ๐ฝ๐พ๐ฟยฉยฎโผโโขโนโ-โโฉ-โชโ-โโจโโฉ-โณโธ-โบโโช-โซโถโโป-โพโ-โโโโ-โโโโ โข-โฃโฆโชโฎ-โฏโธ-โบโโโ-โโ-โ โฃโฅ-โฆโจโปโพ-โฟโ-โโโ-โโ -โกโงโช-โซโฐ-โฑโฝ-โพโ-โ
โโ-โโโ-โโฉ-โชโฐ-โตโท-โบโฝโโ
โ-โโโโโโโกโจโณ-โดโโโโโ-โโโฃ-โคโ-โโกโฐโฟโคด-โคตโฌ
-โฌโฌ-โฌโญโญใฐใฝใใ๐๐๐
ฐ-๐
ฑ๐
พ-๐
ฟ๐๐-๐๐-๐๐๐ฏ๐ฒ-๐บ๐-๐๐-๐ก๐ค-๐๐-๐๐-๐๐-๐ฐ๐ณ-๐ต๐ท-๐บ๐-๐ฝ๐ฟ-๐ฝ๐-๐๐-๐ง๐ฏ-๐ฐ๐ณ-๐บ๐๐-๐๐๐-๐๐ค-๐ฅ๐จ๐ฑ-๐ฒ๐ผ๐-๐๐-๐๐-๐๐ก๐ฃ๐จ๐ฏ๐ณ๐บ-๐๐-๐
๐-๐๐-๐๐-๐ฅ๐ฉ๐ซ-๐ฌ๐ฐ๐ณ-๐ผ๐ -๐ซ๐ฐ๐ค-๐คบ๐คผ-๐ฅ
๐ฅ-๐งฟ๐ฉฐ-๐ฉด๐ฉธ-๐ฉผ๐ช-๐ช๐ช-๐ชฌ๐ชฐ-๐ชบ๐ซ-๐ซ
๐ซ-๐ซ๐ซ -๐ซง๐ซฐ-๐ซถ๐ฆ-๐ฟ#๏ธโฃ*๏ธโฃ0๏ธโฃ1๏ธโฃ2๏ธโฃ3๏ธโฃ4๏ธโฃ5๏ธโฃ6๏ธโฃ7๏ธโฃ8๏ธโฃ9๏ธโฃ]","")
Related Answer:
https://stackoverflow.com/a/70125203/5372400
=REGEXREPLACE(A5,"[[:print:]]","") is a nice solution, but have some drawbacks:
it leaves these chars: 0 1 2 3 4 5 6 7 8 9 # * on the place of respective emojis 0๏ธโฃ 1๏ธโฃ 2๏ธโฃ 3๏ธโฃ 4๏ธโฃ 5๏ธโฃ 6๏ธโฃ 7๏ธโฃ 8๏ธโฃ 9๏ธโฃ ๐ #๏ธโฃ *๏ธโฃ
it also replaces other not printable chars.
Test sheet
I have found this today and can't make out why it fails:
Basically if you take some obscure symbol like
"๐"
then "๐".charCodeAt(0) in chrome console - you will get the code 55357, but when you revert the operation with String.fromCharCode(55357) it produces "๏ฟฝ"
Even if I do it like this String.fromCharCode("๐".charCodeAt(0)) it produces "๏ฟฝ" however String.fromCharCode("๐".charCodeAt(0)).charCodeAt(0) is still 55357, so information isn't lost, and it implies that it is Chrome that can't find correct symbol to map to 55357.
Why Chrome cannot represent symbol correctly? Is it because it cannot map it to font correctly? How do I make double conversion to be shown as "๐" again?
If you log
"๐".length
you will get 2, that is, the string actually contains 2 characters, not one. This is because JS only supports 16-bit unicode (BMP) and encodes "astral plane" symbols with "surrogate pairs". Your symbol is \uD83D\uDC49 internally, and when you do .charCodeAt(0) you only get \uD83D, which is invalid unicode.
More on https://mathiasbynens.be/notes/javascript-unicode
Following script will get the 'correct' char code (128073)
(("๐".charCodeAt(0)-0xD800)*0x400) + ("๐".charCodeAt(1)-0xDC00) + 0x10000
one then can convert it to HTML char code like this:
"&#x"+(((("๐".charCodeAt(0)-0xD800)*0x400) + ("๐".charCodeAt(1)-0xDC00) + 0x10000)).toString(16)+";"
And string extension:
String.prototype.charCodeUTF32 = function(){
return ((((this.charCodeAt(0)-0xD800)*0x400) + (this.charCodeAt(1)-0xDC00) + 0x10000));
};
Hope this saves you some time.
TypeScript to convert a text containing emojis:
private emoji2html(text: string): string {
const regexAstralSymbols = /([\uD800-\uDBFF])([\uDC00-\uDFFF])/g;
return text.replace(regexAstralSymbols, (m, first, second) =>
`&#x${(first + second).charCodeUTF32().toString(16)};`);
}
I am trying to retrieve the first one or two letters from the outcode part of a postcode. The outcode can be in the format X1, XX11, XX1X, X1X. What I would like to do is to retrieve the bold part of these outcodes.
I am using a solution thus far which takes the first two characters of the string and then removes the numbers from the result:
PHP:
$str = preg_replace('/[0-9]+/', '', substr($outcode, 0, 2));
JavaScript:
outcode.substr(0, 2).replace(/\d+/g, '')
This works fine, yet I wonder if there is a more efficient way in PHP and JavaScript/jQuery, such as finding the first number in the string and removing it and everything else after it? I have about 3000 outcodes to filter and efficiency is key. Thanks.
EDIT:
Based on some comments, here are some real life examples, with desired results. Remember that the outcode string is only in one of the formats shown above, no other format:
EX13 => EX
EC2M => EC
E1W => E
E2 => E
This works well
"XX01XX".split(/[0-9]/)[0];
"XX".split(/[0-9]/)[0];
Add .slice(0,2) to get the first chars
In Javascript try:
firstDigit = outcode.match(/\d/); will give you the first digit in the string
index = outcode.indexOf(firstDigit);
outcode.substr(0, index);
How do I remove emoji code using JavaScript? I thought I had taken care of it using the code below, but I still have characters like ๐ด.
function removeInvalidChars() {
return this.replace(/[\uE000-\uF8FF]/g, '');
}
For me none of the answers completely removed all emojis so I had to do some work myself and this is what i got :
text.replace(/([\u2700-\u27BF]|[\uE000-\uF8FF]|\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDFFF]|[\u2011-\u26FF]|\uD83E[\uDD10-\uDDFF])/g, '');
Also, it should take into account that if one inserting the string later to the database, replacing with empty string could expose security issue. instead replace with the replacement character U+FFFD, see : http://www.unicode.org/reports/tr36/#Deletion_of_Noncharacters
The range you have selected is the Private Use Area, containing non-standard characters. Carriers used to encode emoji as different, inconsistent values inside this range.
More recently, the emoji have been given standardised 'unified' codepoints. Many of these are outside of the Basic Multilingual Plane, in the block U+1F300โU+1F5FF, including your example ๐ด U+1F534 Large Red Circle.
You could detect these characters with [\U0001F300-\U0001F5FF] in a regex engine that supported non-BMP characters, but JavaScript's RegExp is not such a beast. Unfortunately the JS string model is based on UTF-16 code units, so you'd have to work with the UTF-16 surrogates in a regexp:
return this.replace(/([\uE000-\uF8FF]|\uD83C[\uDF00-\uDFFF]|\uD83D[\uDC00-\uDDFF])/g, '')
However, note that there are other characters in the Basic Multilingual Plane that are used as emoji by phones but which long predate emoji. For example U+2665 is the traditional Heart Suit character โฅ, but it may be rendered as an emoji graphic on some devices. It's up to you whether you treat this as emoji and try to remove it. See this list for more examples.
I solved it by using a regex with Unicode property escapes. I got it from this article, it's for Java but still very helpful - Remove Emojis from a Java String.
'Smile๐'.replace(/[^\p{L}\p{N}\p{P}\p{Z}^$\n]/gu, '');
It removes all symbols except:
\p{L} - all letters from any language
\p{N} - numbers
\p{P} - punctuation
\p{Z} - whitespace separators
^$\n - add any symbols you want to keep
This one should be more correct and it works, but for me it leaves some trash symbols in the string:
'Smile๐'.replace(/\p{Emoji}/gu, '');
Edit: added symbols from comments
I've found many suggestions around but the regex that have solved my problem is:
/(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g
A short example
function removeEmojis (string) {
var regex = /(?:[\u2700-\u27bf]|(?:\ud83c[\udde6-\uddff]){2}|[\ud800-\udbff][\udc00-\udfff]|[\u0023-\u0039]\ufe0f?\u20e3|\u3299|\u3297|\u303d|\u3030|\u24c2|\ud83c[\udd70-\udd71]|\ud83c[\udd7e-\udd7f]|\ud83c\udd8e|\ud83c[\udd91-\udd9a]|\ud83c[\udde6-\uddff]|\ud83c[\ude01-\ude02]|\ud83c\ude1a|\ud83c\ude2f|\ud83c[\ude32-\ude3a]|\ud83c[\ude50-\ude51]|\u203c|\u2049|[\u25aa-\u25ab]|\u25b6|\u25c0|[\u25fb-\u25fe]|\u00a9|\u00ae|\u2122|\u2139|\ud83c\udc04|[\u2600-\u26FF]|\u2b05|\u2b06|\u2b07|\u2b1b|\u2b1c|\u2b50|\u2b55|\u231a|\u231b|\u2328|\u23cf|[\u23e9-\u23f3]|[\u23f8-\u23fa]|\ud83c\udccf|\u2934|\u2935|[\u2190-\u21ff])/g;
return string.replace(regex, '');
}
Hope it can help you
Just an addition to #hababr answer.
If you need to get rid of complicated emojis, you have to remove also additional things like modifiers and etc:
'๐จ๐ฟโ๐ค'.replace(/[\p{Emoji}\p{Emoji_Modifier}\p{Emoji_Component}\p{Emoji_Modifier_Base}\p{Emoji_Presentation}]/gu, '').charCodeAt(0)
update:
*#0-9 - are Emoji characters with a text representation by default, per the Unicode Standard.
so, my current solution is next:
'๐จ๐ฟโ๐ค'.replace(/(?![*#0-9]+)[\p{Emoji}\p{Emoji_Modifier}\p{Emoji_Component}\p{Emoji_Modifier_Base}\p{Emoji_Presentation}]/gu, '').charCodeAt(0)
I know this post is a bit old, but I stumbled across this very problem at work and a colleague came up with an interesting idea. Basically instead of stripping emoji character only allow valid characters in. Consulting this ASCII table:
http://www.asciitable.com/
A function such as this could only keep legal characters (the range itself dependent on what you are after)
function (input) {
var result = '';
if (input.length == 0)
return input;
for (var indexOfInput = 0, lengthOfInput = input.length; indexOfInput < lengthOfInput; indexOfInput++) {
var charAtSpecificIndex = input[indexOfInput].charCodeAt(0);
if ((32 <= charAtSpecificIndex) && (charAtSpecificIndex <= 126)) {
result += input[indexOfInput];
}
}
return result;
};
This should preserve all numbers, letters and special characters of the Alphabet for a situation where you wish to preserve the English alphabet + number + special characters. Hope it helps someone :)
#bobince's solution didn't work for me. Either the Emojis stayed there or they were swapped by a different Emoji.
This solution did the trick for me:
var ranges = [
'\ud83c[\udf00-\udfff]', // U+1F300 to U+1F3FF
'\ud83d[\udc00-\ude4f]', // U+1F400 to U+1F64F
'\ud83d[\ude80-\udeff]' // U+1F680 to U+1F6FF
];
$('#mybtn').on('click', function() {
removeInvalidChars();
})
function removeInvalidChars() {
var str = $('#myinput').val();
str = str.replace(new RegExp(ranges.join('|'), 'g'), '');
$("#myinput").val(str);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="myinput"/>
<input type="submit" id="mybtn" value="clear"/>
Source
After searching and trying lots of unicode regex, I suggest you try this, it can cover all of emojis:
function removeEmoji(str) {
let strCopy = str;
const emojiKeycapRegex = /[\u0023-\u0039]\ufe0f?\u20e3/g;
const emojiRegex = /\p{Extended_Pictographic}/gu;
const emojiComponentRegex = /\p{Emoji_Component}/gu;
if (emojiKeycapRegex.test(strCopy)) {
strCopy = strCopy.replace(emojiKeycapRegex, '');
}
if (emojiRegex.test(strCopy)) {
strCopy = strCopy.replace(emojiRegex, '');
}
if (emojiComponentRegex.test(strCopy)) {
// eslint-disable-next-line no-restricted-syntax
for (const emoji of (strCopy.match(emojiComponentRegex) || [])) {
if (/[\d|*|#]/.test(emoji)) {
continue;
}
strCopy = strCopy.replace(emoji, '');
}
}
return strCopy;
}
let a = "1๏ธโฃaa๐คนโโ๏ธb#๏ธโฃ๐คโ
โ23#!^*bb๐คน๐พ๐คนโโ๏ธ๐ด๐ปccc";
console.log(removeEmoji(a))
Refrence: Unicode Emoij Document
None of the answers here worked for all the unicode characters I tested (specifically characters in the miscellaneous range such as โฝ or โฏ๏ธ).
Here is one that worked for me, (heavily) inspired from this SO PHP answer:
function _removeEmojis(str) {
return str.replace(/([#0-9]\u20E3)|[\xA9\xAE\u203C\u2047-\u2049\u2122\u2139\u3030\u303D\u3297\u3299][\uFE00-\uFEFF]?|[\u2190-\u21FF][\uFE00-\uFEFF]?|[\u2300-\u23FF][\uFE00-\uFEFF]?|[\u2460-\u24FF][\uFE00-\uFEFF]?|[\u25A0-\u25FF][\uFE00-\uFEFF]?|[\u2600-\u27BF][\uFE00-\uFEFF]?|[\u2900-\u297F][\uFE00-\uFEFF]?|[\u2B00-\u2BF0][\uFE00-\uFEFF]?|(?:\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDEFF])[\uFE00-\uFEFF]?/g, '');
}
(My use case is sorting in a data grid where emojis can come first in a string but users want the text ordered by the actual words.)
sandre89's answer is good but not perfect.
I spent some time on the subject and have a working solution.
var ranges = [
'[\u00A0-\u269f]',
'[\u26A0-\u329f]',
// The following characters could not be minified correctly
// if specifed with the ES6 syntax \u{1F400}
'[๐-๐ง]'
//'[\u{1F004}-\u{1F9C0}]'
];
$('#mybtn').on('click', function() {
removeInvalidChars();
});
function removeInvalidChars() {
var str = $('#myinput').val();
str = str.replace(new RegExp(ranges.join('|'), 'ug'), '');
$("#myinput").val(str);
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" id="myinput" />
<input type="submit" id="mybtn" value="clear" />
Here is my CodePen
There are some points to note, though.
Unicode characters from U+1F000 up need a special notation, so you can use sandre89's way, or opt for the \u{1F000} ES6 notation, which may or may not work with your minificator. I succeeded pasting the emojis directly in the UTF-8 encoded script.
Don't forget the u flag in the regex, or your Javascript engine may throw an error.
Beware that things may not be working due to the file encoding, character set, or minificator. In my case nothing worked until I took the script off an .isml file (Demandware) and pasted it into a .js file.
You may gain some insight by referring to Wikipedia Emoji page and How many bytes does one Unicode character take?, and by tinkering with this Online Unicode converter, as I did.
var emoji =/([#0-9]\u20E3)|[\xA9\xAE\u203C\u2047-\u2049\u2122\u2139\u3030\u303D\u3297\u3299][\uFE00-\uFEFF]?|[\u2190-\u21FF][\uFE00-\uFEFF]?|[\u2300-\u23FF][\uFE00-\uFEFF]?|[\u2460-\u24FF][\uFE00-\uFEFF]?|[\u25A0-\u25FF][\uFE00-\uFEFF]?|[\u2600-\u27BF][\uFE00-\uFEFF]?|[\u2900-\u297F][\uFE00-\uFEFF]?|[\u2B00-\u2BF0][\uFE00-\uFEFF]?|(?:\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDEFF])[\uFE00-\uFEFF]?|[\u20E3]|[\u26A0-\u3000]|\uD83E[\udd00-\uddff]|[\u00A0-\u269F]/g;
str.replace(emoji, "");
i add this '\uD83E[\udd00-\uddff]'
these emojis were updated when 2018 june
if u want block emojis after other update then use this
str.replace(/[^0-9a-zA-Zใฑ-ํฃ+รรท=%โคโกโโง)(*&^/~##!-:;,?`_|<>{}ยฅยฃโฌ$โโ โกโโโขยฐโปยคใใยกยฟโฉ\[\]\"\' \\]/g ,"");
u can block all emojis and u can only use eng, num, hangle, and some Characters
thx :)
You can use this function to replace emojis with nothing:
function msgAfterClearEmojis(msg)
{
var new_msg = msg.replace(/([#0-9]\u20E3)|[\xA9\xAE\u203C\u2047-\u2049\u2122\u2139\u3030\u303D\u3297\u3299][\uFE00-\uFEFF]?|[\u2190-\u21FF][\uFE00-\uFEFF]?|[\u2300-\u23FF][\uFE00-\uFEFF]?|[\u2460-\u24FF][\uFE00-\uFEFF]?|[\u25A0-\u25FF][\uFE00-\uFEFF]?|[\u2600-\u27BF][\uFE00-\uFEFF]?|[\u2900-\u297F][\uFE00-\uFEFF]?|[\u2B00-\u2BF0][\uFE00-\uFEFF]?|(?:\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDEFF])[\uFE00-\uFEFF]?|[\u20E3]|[\u26A0-\u3000]|\uD83E[\udd00-\uddff]|[\u00A0-\u269F]/g, '').trim();
return new_msg;
}
You can check here with emoji..
๐ , ๐ , ๐ฝ
function removeEmoji() {
var y = document.getElementById('textbox_id1');
y.value = y.value.replace(/([\u2700-\u27BF]|[\uE000-\uF8FF]|\uD83C[\uDC00-\uDFFF]|\uD83D[\uDC00-\uDFFF]|[\u2011-\u26FF]|\uD83E[\uDD10-\uDDFF])/g, '');
}
input {
padding: 5px;
}
<input type="text" id="textbox_id1" placeholder="Remove emoji..." oninput="removeEmoji()">
You can take more emojis from here: Emoji Keyboard Online
This is the iteration on #hababr's answer.
His answer removes lots of standard chars like $, +, < and so on.
This version keeps all of them (except for the \ backslash - dunno how to properly escape it).
"hey๐ hau๐ ahoy๐ดโโ ๏ธ !##$%^&*()-_=+ยฑยง;:'\|`~/?[]{},.<>".replace(/[^\p{L}\p{N}\p{P}\p{Z}{^$=+ยฑ\\'|`\\~<>}]/gu, "")
// "hey hau ahoy !##$%^&*()-_=+ยฑยง;:'|`~/?[]{},.<>"
I have this regex and it works for all emojis i found on this page
try this regex
<:[^:\s]+:\d+>|<a:[^:\s]+:\d+>|(\u00a9|\u00ae|[\u2000-\u3300]|\ud83c[\ud000-\udfff]|\ud83d[\ud000-\udfff]|\ud83e[\ud000-\udfff]|\ufe0f)
var emojiRegex = /\uD83C\uDFF4(?:\uDB40\uDC67\uDB40\uDC62(?:\uDB40\uDC65\uDB40\uDC6E\uDB40\uDC67|\uDB40\uDC77\uDB40\uDC6C\uDB40\uDC73|\uDB40\uDC73\uDB40\uDC63\uDB40\uDC74)\uDB40\uDC7F|\u200D\u2620\uFE0F)|\uD83D\uDC69\u200D\uD83D\uDC69\u200D(?:\uD83D\uDC66\u200D\uD83D\uDC66|\uD83D\uDC67\u200D(?:\uD83D[\uDC66\uDC67]))|\uD83D\uDC68(?:\u200D(?:\u2764\uFE0F\u200D(?:\uD83D\uDC8B\u200D)?\uD83D\uDC68|(?:\uD83D[\uDC68\uDC69])\u200D(?:\uD83D\uDC66\u200D\uD83D\uDC66|\uD83D\uDC67\u200D(?:\uD83D[\uDC66\uDC67]))|\uD83D\uDC66\u200D\uD83D\uDC66|\uD83D\uDC67\u200D(?:\uD83D[\uDC66\uDC67])|\uD83C[\uDF3E\uDF73\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E[\uDDB0-\uDDB3])|(?:\uD83C[\uDFFB-\uDFFF])\u200D(?:\uD83C[\uDF3E\uDF73\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E[\uDDB0-\uDDB3]))|\uD83D\uDC69\u200D(?:\u2764\uFE0F\u200D(?:\uD83D\uDC8B\u200D(?:\uD83D[\uDC68\uDC69])|\uD83D[\uDC68\uDC69])|\uD83C[\uDF3E\uDF73\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E[\uDDB0-\uDDB3])|\uD83D\uDC69\u200D\uD83D\uDC66\u200D\uD83D\uDC66|(?:\uD83D\uDC41\uFE0F\u200D\uD83D\uDDE8|\uD83D\uDC69(?:\uD83C[\uDFFB-\uDFFF])\u200D[\u2695\u2696\u2708]|\uD83D\uDC68(?:(?:\uD83C[\uDFFB-\uDFFF])\u200D[\u2695\u2696\u2708]|\u200D[\u2695\u2696\u2708])|(?:(?:\u26F9|\uD83C[\uDFCB\uDFCC]|\uD83D\uDD75)\uFE0F|\uD83D\uDC6F|\uD83E[\uDD3C\uDDDE\uDDDF])\u200D[\u2640\u2642]|(?:\u26F9|\uD83C[\uDFCB\uDFCC]|\uD83D\uDD75)(?:\uD83C[\uDFFB-\uDFFF])\u200D[\u2640\u2642]|(?:\uD83C[\uDFC3\uDFC4\uDFCA]|\uD83D[\uDC6E\uDC71\uDC73\uDC77\uDC81\uDC82\uDC86\uDC87\uDE45-\uDE47\uDE4B\uDE4D\uDE4E\uDEA3\uDEB4-\uDEB6]|\uD83E[\uDD26\uDD37-\uDD39\uDD3D\uDD3E\uDDB8\uDDB9\uDDD6-\uDDDD])(?:(?:\uD83C[\uDFFB-\uDFFF])\u200D[\u2640\u2642]|\u200D[\u2640\u2642])|\uD83D\uDC69\u200D[\u2695\u2696\u2708])\uFE0F|\uD83D\uDC69\u200D\uD83D\uDC67\u200D(?:\uD83D[\uDC66\uDC67])|\uD83D\uDC69\u200D\uD83D\uDC69\u200D(?:\uD83D[\uDC66\uDC67])|\uD83D\uDC68(?:\u200D(?:(?:\uD83D[\uDC68\uDC69])\u200D(?:\uD83D[\uDC66\uDC67])|\uD83D[\uDC66\uDC67])|\uD83C[\uDFFB-\uDFFF])|\uD83C\uDFF3\uFE0F\u200D\uD83C\uDF08|\uD83D\uDC69\u200D\uD83D\uDC67|\uD83D\uDC69(?:\uD83C[\uDFFB-\uDFFF])\u200D(?:\uD83C[\uDF3E\uDF73\uDF93\uDFA4\uDFA8\uDFEB\uDFED]|\uD83D[\uDCBB\uDCBC\uDD27\uDD2C\uDE80\uDE92]|\uD83E[\uDDB0-\uDDB3])|\uD83D\uDC69\u200D\uD83D\uDC66|\uD83C\uDDF6\uD83C\uDDE6|\uD83C\uDDFD\uD83C\uDDF0|\uD83C\uDDF4\uD83C\uDDF2|\uD83D\uDC69(?:\uD83C[\uDFFB-\uDFFF])|\uD83C\uDDED(?:\uD83C[\uDDF0\uDDF2\uDDF3\uDDF7\uDDF9\uDDFA])|\uD83C\uDDEC(?:\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEE\uDDF1-\uDDF3\uDDF5-\uDDFA\uDDFC\uDDFE])|\uD83C\uDDEA(?:\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDED\uDDF7-\uDDFA])|\uD83C\uDDE8(?:\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDEE\uDDF0-\uDDF5\uDDF7\uDDFA-\uDDFF])|\uD83C\uDDF2(?:\uD83C[\uDDE6\uDDE8-\uDDED\uDDF0-\uDDFF])|\uD83C\uDDF3(?:\uD83C[\uDDE6\uDDE8\uDDEA-\uDDEC\uDDEE\uDDF1\uDDF4\uDDF5\uDDF7\uDDFA\uDDFF])|\uD83C\uDDFC(?:\uD83C[\uDDEB\uDDF8])|\uD83C\uDDFA(?:\uD83C[\uDDE6\uDDEC\uDDF2\uDDF3\uDDF8\uDDFE\uDDFF])|\uD83C\uDDF0(?:\uD83C[\uDDEA\uDDEC-\uDDEE\uDDF2\uDDF3\uDDF5\uDDF7\uDDFC\uDDFE\uDDFF])|\uD83C\uDDEF(?:\uD83C[\uDDEA\uDDF2\uDDF4\uDDF5])|\uD83C\uDDF8(?:\uD83C[\uDDE6-\uDDEA\uDDEC-\uDDF4\uDDF7-\uDDF9\uDDFB\uDDFD-\uDDFF])|\uD83C\uDDEE(?:\uD83C[\uDDE8-\uDDEA\uDDF1-\uDDF4\uDDF6-\uDDF9])|\uD83C\uDDFF(?:\uD83C[\uDDE6\uDDF2\uDDFC])|\uD83C\uDDEB(?:\uD83C[\uDDEE-\uDDF0\uDDF2\uDDF4\uDDF7])|\uD83C\uDDF5(?:\uD83C[\uDDE6\uDDEA-\uDDED\uDDF0-\uDDF3\uDDF7-\uDDF9\uDDFC\uDDFE])|\uD83C\uDDE9(?:\uD83C[\uDDEA\uDDEC\uDDEF\uDDF0\uDDF2\uDDF4\uDDFF])|\uD83C\uDDF9(?:\uD83C[\uDDE6\uDDE8\uDDE9\uDDEB-\uDDED\uDDEF-\uDDF4\uDDF7\uDDF9\uDDFB\uDDFC\uDDFF])|\uD83C\uDDE7(?:\uD83C[\uDDE6\uDDE7\uDDE9-\uDDEF\uDDF1-\uDDF4\uDDF6-\uDDF9\uDDFB\uDDFC\uDDFE\uDDFF])|[#\*0-9]\uFE0F\u20E3|\uD83C\uDDF1(?:\uD83C[\uDDE6-\uDDE8\uDDEE\uDDF0\uDDF7-\uDDFB\uDDFE])|\uD83C\uDDE6(?:\uD83C[\uDDE8-\uDDEC\uDDEE\uDDF1\uDDF2\uDDF4\uDDF6-\uDDFA\uDDFC\uDDFD\uDDFF])|\uD83C\uDDF7(?:\uD83C[\uDDEA\uDDF4\uDDF8\uDDFA\uDDFC])|\uD83C\uDDFB(?:\uD83C[\uDDE6\uDDE8\uDDEA\uDDEC\uDDEE\uDDF3\uDDFA])|\uD83C\uDDFE(?:\uD83C[\uDDEA\uDDF9])|(?:\uD83C[\uDFC3\uDFC4\uDFCA]|\uD83D[\uDC6E\uDC71\uDC73\uDC77\uDC81\uDC82\uDC86\uDC87\uDE45-\uDE47\uDE4B\uDE4D\uDE4E\uDEA3\uDEB4-\uDEB6]|\uD83E[\uDD26\uDD37-\uDD39\uDD3D\uDD3E\uDDB8\uDDB9\uDDD6-\uDDDD])(?:\uD83C[\uDFFB-\uDFFF])|(?:\u26F9|\uD83C[\uDFCB\uDFCC]|\uD83D\uDD75)(?:\uD83C[\uDFFB-\uDFFF])|(?:[\u261D\u270A-\u270D]|\uD83C[\uDF85\uDFC2\uDFC7]|\uD83D[\uDC42\uDC43\uDC46-\uDC50\uDC66\uDC67\uDC70\uDC72\uDC74-\uDC76\uDC78\uDC7C\uDC83\uDC85\uDCAA\uDD74\uDD7A\uDD90\uDD95\uDD96\uDE4C\uDE4F\uDEC0\uDECC]|\uD83E[\uDD18-\uDD1C\uDD1E\uDD1F\uDD30-\uDD36\uDDB5\uDDB6\uDDD1-\uDDD5])(?:\uD83C[\uDFFB-\uDFFF])|(?:[\u231A\u231B\u23E9-\u23EC\u23F0\u23F3\u25FD\u25FE\u2614\u2615\u2648-\u2653\u267F\u2693\u26A1\u26AA\u26AB\u26BD\u26BE\u26C4\u26C5\u26CE\u26D4\u26EA\u26F2\u26F3\u26F5\u26FA\u26FD\u2705\u270A\u270B\u2728\u274C\u274E\u2753-\u2755\u2757\u2795-\u2797\u27B0\u27BF\u2B1B\u2B1C\u2B50\u2B55]|\uD83C[\uDC04\uDCCF\uDD8E\uDD91-\uDD9A\uDDE6-\uDDFF\uDE01\uDE1A\uDE2F\uDE32-\uDE36\uDE38-\uDE3A\uDE50\uDE51\uDF00-\uDF20\uDF2D-\uDF35\uDF37-\uDF7C\uDF7E-\uDF93\uDFA0-\uDFCA\uDFCF-\uDFD3\uDFE0-\uDFF0\uDFF4\uDFF8-\uDFFF]|\uD83D[\uDC00-\uDC3E\uDC40\uDC42-\uDCFC\uDCFF-\uDD3D\uDD4B-\uDD4E\uDD50-\uDD67\uDD7A\uDD95\uDD96\uDDA4\uDDFB-\uDE4F\uDE80-\uDEC5\uDECC\uDED0-\uDED2\uDEEB\uDEEC\uDEF4-\uDEF9]|\uD83E[\uDD10-\uDD3A\uDD3C-\uDD3E\uDD40-\uDD45\uDD47-\uDD70\uDD73-\uDD76\uDD7A\uDD7C-\uDDA2\uDDB0-\uDDB9\uDDC0-\uDDC2\uDDD0-\uDDFF])|(?:[#\*0-9\xA9\xAE\u203C\u2049\u2122\u2139\u2194-\u2199\u21A9\u21AA\u231A\u231B\u2328\u23CF\u23E9-\u23F3\u23F8-\u23FA\u24C2\u25AA\u25AB\u25B6\u25C0\u25FB-\u25FE\u2600-\u2604\u260E\u2611\u2614\u2615\u2618\u261D\u2620\u2622\u2623\u2626\u262A\u262E\u262F\u2638-\u263A\u2640\u2642\u2648-\u2653\u265F\u2660\u2663\u2665\u2666\u2668\u267B\u267E\u267F\u2692-\u2697\u2699\u269B\u269C\u26A0\u26A1\u26AA\u26AB\u26B0\u26B1\u26BD\u26BE\u26C4\u26C5\u26C8\u26CE\u26CF\u26D1\u26D3\u26D4\u26E9\u26EA\u26F0-\u26F5\u26F7-\u26FA\u26FD\u2702\u2705\u2708-\u270D\u270F\u2712\u2714\u2716\u271D\u2721\u2728\u2733\u2734\u2744\u2747\u274C\u274E\u2753-\u2755\u2757\u2763\u2764\u2795-\u2797\u27A1\u27B0\u27BF\u2934\u2935\u2B05-\u2B07\u2B1B\u2B1C\u2B50\u2B55\u3030\u303D\u3297\u3299]|\uD83C[\uDC04\uDCCF\uDD70\uDD71\uDD7E\uDD7F\uDD8E\uDD91-\uDD9A\uDDE6-\uDDFF\uDE01\uDE02\uDE1A\uDE2F\uDE32-\uDE3A\uDE50\uDE51\uDF00-\uDF21\uDF24-\uDF93\uDF96\uDF97\uDF99-\uDF9B\uDF9E-\uDFF0\uDFF3-\uDFF5\uDFF7-\uDFFF]|\uD83D[\uDC00-\uDCFD\uDCFF-\uDD3D\uDD49-\uDD4E\uDD50-\uDD67\uDD6F\uDD70\uDD73-\uDD7A\uDD87\uDD8A-\uDD8D\uDD90\uDD95\uDD96\uDDA4\uDDA5\uDDA8\uDDB1\uDDB2\uDDBC\uDDC2-\uDDC4\uDDD1-\uDDD3\uDDDC-\uDDDE\uDDE1\uDDE3\uDDE8\uDDEF\uDDF3\uDDFA-\uDE4F\uDE80-\uDEC5\uDECB-\uDED2\uDEE0-\uDEE5\uDEE9\uDEEB\uDEEC\uDEF0\uDEF3-\uDEF9]|\uD83E[\uDD10-\uDD3A\uDD3C-\uDD3E\uDD40-\uDD45\uDD47-\uDD70\uDD73-\uDD76\uDD7A\uDD7C-\uDDA2\uDDB0-\uDDB9\uDDC0-\uDDC2\uDDD0-\uDDFF])\uFE0F|(?:[\u261D\u26F9\u270A-\u270D]|\uD83C[\uDF85\uDFC2-\uDFC4\uDFC7\uDFCA-\uDFCC]|\uD83D[\uDC42\uDC43\uDC46-\uDC50\uDC66-\uDC69\uDC6E\uDC70-\uDC78\uDC7C\uDC81-\uDC83\uDC85-\uDC87\uDCAA\uDD74\uDD75\uDD7A\uDD90\uDD95\uDD96\uDE45-\uDE47\uDE4B-\uDE4F\uDEA3\uDEB4-\uDEB6\uDEC0\uDECC]|\uD83E[\uDD18-\uDD1C\uDD1E\uDD1F\uDD26\uDD30-\uDD39\uDD3D\uDD3E\uDDB5\uDDB6\uDDB8\uDDB9\uDDD1-\uDDDD])/g;
console.log(text.replace(emojiRegex,'');
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script>
function isEmoji(str) {
var ranges = [
'[\uE000-\uF8FF]',
'\uD83C[\uDC00-\uDFFF]',
'\uD83D[\uDC00-\uDFFF]',
'[\u2011-\u26FF]',
'\uD83E[\uDD10-\uDDFF]'
];
if (str.match(ranges.join('|'))) {
return true;
} else {
return false;
}
}
$(document).ready(function(){
$('input').on('input',function(){
var $th = $(this);
console.log("Value of Input"+$th.val());
emojiInput= isEmoji($th.val());
if (emojiInput==true) {
$th.val("");
}
});
});
</script>
</head>
<body>
Enter your name: <input type="text">
</body>
</html>
There is a modern solution using categories
Modern browsers support Unicode property, which allows you to match emojis based on their belonging in the Emoji Unicode category. For example, you can use Unicode property escapes like \p{Emoji} or \P{Emoji} to match/no match emoji characters. Note that 0123456789#* and other characters are interpreted as emojis using the previous Unicode category. Therefore, a better way to do this is to use the {Extended_Pictographic} Unicode category that denotes all the characters typically understood as emojis instead of the {Emoji} category.
const withEmojis = /\p{Extended_Pictographic}/u
withEmojis.test('๐๐');
//true
withEmojis.test('ab');
//false
withEmojis.test('1');
//false
or with negation
const noEmojis = /\P{Extended_Pictographic}/u
noEmojis.test('๐');
//false
noEmojis.test('1212');
//false
You can use mathiasbynens/emoji-regex package to remove or replace emojis.
You can see the latest build's content to grab the regex by visiting following url:
http://unpkg.com/emoji-regex/index.js
In detail, this function first uses TextEncoder to convert content into a byte array with utf-8 encoding, then loops through this array, if it finds a byte whose first five bits are 11110 (i.e. 0xF0), it means this is an emoji start, then it replaces this byte and the next three bytes with 0x30 (i.e. number 0). Finally, it uses TextDecoder to convert the modified byte array back to a string, and uses replaceAll method to remove extra 0s.
function removeEmoji (content) {
let conByte = new TextEncoder("utf-8").encode(content);
for (let i = 0; i < conByte.length; i++) {
if ((conByte[i] & 0xF8) == 0xF0) {
for (let j = 0; j < 4; j++) {
conByte[i+j]=0x30;
}
i += 3;
}
}
content = new TextDecoder("utf-8").decode(conByte);
return content.replaceAll("0000", "");
}