As I mentioned I have MUI Theme Provider with Layout which includes Dashboard, Order screens ...
When user hits '/' endpoint it should return Login Screen but Layout keeps showing itself.
-App.js
<ThemeProvider theme={theme}>
<Router>
<Layout>
<Switch>
<Route exact path="/">
<Login />
</Route>
<Route path="/dashboard">
<Dashboard />
</Route>
<Route path="/orders">
<Orders />
</Route>
<Route path="/users">
<Users />
</Route>
<Route path="/employees">
<Employee />
</Route>
</Switch>
</Layout>
</Router>
</ThemeProvider>
);
-Layout.js
...AppBar,Sidebar etc
<div style={{width:'100%'}}>
<div className={classes.toolbar}></div>
{children}
</div>
As-is, the code is unconditionally rendering a Layout component outside the Switch, so it's rendered regardless of the currently matched route.
If you want the Layout component to only render on certain routes, conditionally render it with those routes.
Example, render the Login component on exactly the "/" path, everything else into a route rendering the Layout and another Switch.
<ThemeProvider theme={theme}>
<Router>
<Switch>
<Route exact path="/">
<Login />
</Route>
<Route path="/">
<Layout>
<Switch>
<Route path="/dashboard">
<Dashboard />
</Route>
<Route path="/orders">
<Orders />
</Route>
<Route path="/users">
<Users />
</Route>
<Route path="/employees">
<Employee />
</Route>
</Switch>
</Layout>
</Route>
</Switch>
</Router>
</ThemeProvider>
Related
I am having three layouts and they are Admin, App, CompanySetup. I need to restrict routes of app layout in admin layout and vice-versa. I shared my Code below.
Routes.js
<Route path='/'>
<Route path='app'>
<Route index element={<Home />}></Route>
<Route
path='search/category/:category'
element={<SearchPage />}
></Route>
<Route
path='search/category/:category/name/:name'
element={<SearchPage />}
></Route>
</Route>
<Route path='admin'>
<Route element={<AdminRouteProvider></AdminRouteProvider>}>
<Route
path='dashboard'
element={<AdminDashboard />}
></Route>
</Route>
</Route>
</Route>
AppLayout.js
<Layout className='min-vh-100 bg-white'>
<Content className='p-4'>
<Outlet />
</Content>
</Layout>
AdminLayout.js
<Layout className='min-vh-100 bg-white'>
<Sider width={240} className='bg-white border-end'>
<Sidebar />
</Sider>
<Layout>
<Header className='bg-body border-bottom'>
<HeaderNav></HeaderNav>
</Header>
<Content className='p-5 bg-body'>
<AdminRouteProvider>
<Outlet></Outlet>
</AdminRouteProvider>
</Content>
</Layout>
</Layout>
Here I am having separate layouts for '/app' and '/admin'. My issue is in admin layout '/app' is allowed. How to restrict that?
you can use useEffect/useEffectLayout to prevent from access the route or path of '/app'.
for example-
useEffect(()=>{
if(!JSON.parse(localStorage.getItem('admin')){
window.location.href="/app"
}
},[])
this is just an example may this code also change according to your need. If you still facing issue just lemme know.
From what I can tell you are not rendering any actual layout routes for either "/app" or "/admin". Import AppLayout and AdminLayout1 and render the appropriate layout routes.
import AppLayout from '../path/to/AppLayout';
import AdminLayout from '../path/to/AdminLayout';
...
<Route path="/">
<Route path="app" element={<AppLayout />}>
<Route index element={<Home />} />
<Route path="search/category/:category">
<Route index element={<SearchPage />} />
<Route path="name/:name" element={<SearchPage />} />
</Route>
</Route>
<Route path="admin" element={<AdminLayout />}>
<Route path="dashboard" element={<AdminDashboard />} />
<Route path="*" element={<Navigate to="dashboard" replace />} />
</Route>
</Route>
I am using react-router#6, and want to add a route for 404 pages, and render the page outside the main layout. This is what I have so far:
<BrowserRouter>
<Routes>
<Route path='/' element={<Layout />}>
<Route
path='/'
element={<HomePage />}
/>
<Route
path='login'
element={<LoginPage />}
/>
</Route>
<Route
path='*'
element={<PageNotFound />}
/>
</Routes>
</BrowserRouter>
The "*" route works fine, PageNotFound component is rendering outside the layout, as it should. Problem is that the any of the other routes does not show up, only the layout.
What am I missing?
From what you describe it sounds like the Layout component is missing rendering an Outlet component for the nested routes to render their content into.
Example:
import { Outlet } from 'react-router-dom';
const Layout = () => {
...
return (
<>
... common layout UI ...
<Outlet /> // <-- nested routes render out here
</>
);
};
<BrowserRouter>
<Routes>
<Route element={<Layout />}>
<Route path='/' element={<HomePage />} />
<Route path='login' element={<LoginPage />} />
</Route>
<Route path='*' element={<PageNotFound />} />
</Routes>
</BrowserRouter>
For more details you can see the following:
Layout Routes
Outlets
I'm having a problem regarding using of error page in my react app. The 404 page always shows at the bottom of every page that I render. I'm new to react. I hope someone can help me.
This is my App.js
import {BrowserRouter as Router,Switch,Route} from 'react-router-dom';
import Login from './components/auth/Login';
import Register from './components/auth/Register';
import ErrorPage from './components/ErrorPage';
import Order from './components/Order';
import Navbar from './components/partials/Navbar';
import Footer from './components/partials/Footer';
import Shop from './components/Shop';
import ItemDetails from './components/ItemDetails';
import Cart from './components/Cart';
import Customize from './components/Customize';
const App = () => {
return (
<>
<Router>
<Switch>
<Route exact path='/login'>
<Login />
</Route>
<Route exact path='/register'>
<Register />
</Route>
<div>
<Navbar />
<Route exact path='/'>
<Shop />
</Route>
<Route exact path='/order'>
<Order />
</Route>
<Route exact path='/item/details'>
<ItemDetails />
</Route>
<Route exact path='/cart'>
<Cart />
</Route>
<Route exact path='/customize'>
<Customize />
</Route>
<Route component={ErrorPage} />
</div>
</Switch>
</Router>
<Footer />
</>
);
}
export default App;
I searched about handling error page in react and I see that the order of routes is important but I don't get why I'm still getting the error page even it's in the bottom. Thank you guys.
That's because the switch component returns the first child at the root that meets the path condition. If the path condition doesn't exist it's evaluated as true. In your case you have 3 child Login, Register and the div which will always be evaluated to true. So just move all routes to the root of your switch:
<Router>
<Switch>
<Route exact path='/login'>
<Login />
</Route>
<Route exact path='/register'>
<Register />
</Route>
<div>
<Navbar />
<Switch>
<Route exact path='/'>
<Shop />
</Route>
<Route exact path='/order'>
<Order />
</Route>
<Route exact path='/item/details'>
<ItemDetails />
</Route>
<Route exact path='/cart'>
<Cart />
</Route>
<Route exact path='/customize'>
<Customize />
</Route>
<Route component={ErrorPage} />
</Switch>
</div>
</Switch>
</Router>
In my code, I want Header & Footer components to be rendered in all routes except '/login'so how to do that? How to hide component on a specific route?
const AppRouter = () => {
return (
<BrowserRouter>
<div>
<Header />
<Switch>
<Route path="/login" component={Login} /> {/* I wanna render this route without Header & Footer */}
<Route path="/" component={Home} exact />
<Route path="/product" component={ProductOverview} />
<Route path="/profile" component={Profile} />
<Route component={NotFound} />
</Switch>
<Footer />
</div>
</BrowserRouter>
);
};
I have an application with a Login page followed by a Dashboard page. The routes that I've defined in the index.js are like this:
<Router>
<div>
<Route exact path="/" component={Login}/>
<Route path="/dashboard" component={Dashboard} />
</div>
</Router>
Dashboard.js:
return (
<div>
<Header/>
<Footer/>
<Switch>
<Route path="/dashboard/content1" component={content1} />
<Route path="/dashboard/content2" component={content2} />
</Switch>
</div>
);
The Dashboard component is rendering 3 of its child components. Header, Footer and Content1. I want the Dashboard component to render Content1 by default (i.e. when the url is /dashboard) and also when the url is /dashboard/content1, and should render content2 when the url is /dashboard/content2. Header & Footer components should remain. Please suggest the configuration for the Dashboard component to achieve the same.
In React-router v4 you provide Routes within the component, so you can write your Routes as follows
<Router>
<div>
<Route exact path="/" component={Login}/>
<Route path="/dashboard" component={Dashboard} />
</div>
</Router>
and then in the Dashboard Component render method
render() {
return (
<div>
{/* other content */}
<Switch>
<Route exact path="/dashboard" component={content1} />
<Route path="/dashboard/content1" component={content1} />
<Route path="/dashboard/content2" component={content2} />
</Switch>
</div>
)
}
As a variant of an answer to your post before you have edited it, you can do it (nesting) like this:
<Router>
<Header/>
<Content1/>
<Footer/>
<Switch>
<Route exact path="/" component={Login}/>
<Route exact path="/dashboard" component={Dashboard} />
<Route exact path="/dashboard/content1" component={content1} />
<Route exact path="/dashboard/content2" component={content2} />
</Switch>
</Router>
React-Router's Switch component renders the first thing that matches,
so if you put a route without a path last, it will render that if no other routes match, essentially treating it as a default. Like so:
return (
<div>
<Header/>
<Footer/>
<Switch>
<Route path="/dashboard/content2" exact component={Content2} />
<Route component={Content1} />
</Switch>
</div>
);
I have found that rendering a component instead of a Route also works, although I dont know if it's officially supported.
return (
<div>
<Header/>
<Footer/>
<Switch>
<Route path="/dashboard/content2" exact component={Content2} />
<Content1 />
</Switch>
</div>
);