'For loop' within a function - javascript

I hope everyone is having an amazing day so far.
I am asking for help on an exercise that I am stuck on. I have gone through and researched all over but still am not getting it right.
The task is:
Create a for loop in which an iterator starting from 0 up to the iteratorMax value (not included) (the second parameter to your function) is incremented by 1. Add the iterator to num(the first parameter to your function) for each incrementation. you must return the number at the end of your function.
I was given this code to start with:
function IncrementNumber(num, iteratorMax){
//Add For loop here
//return value here
}
I have tried coding it a number of different ways but still not correct.
for example:
function IncrementNumber(num, iteratorMax){
for (let i = 0; i < iteratorMax; i++) {
return(i);
}
}
I have tried to declare "i" but that seems to be incorrect also.
I really appreciate any help or hints to what I am missing or doing wrong in my code.
Thank you!

For the IncrementNumber(value, N) method, when value is 0, this algorithm returns the result of the equation:
Total = N x (N-1) / 2
function IncrementNumber(num, iteratorMax){
for(let i = 0 ; i < iteratorMax ; ++i){
num += i;
console.log(`i: ${i}\tnumber: ${num}`);
}
return num;
}
console.log(`Result: ${IncrementNumber(0, 10)}`);

If you call return within the loop, the loop will only be executed once.
You need to move the return statement outside of the loop.
Whenever calling return, this will cause the current function to exit.
function IncrementNumber(num, iteratorMax){
for (let i = 0; i < iteratorMax; i++) {
num += i;
}
return num;
}

Related

Explanation How Rectangle Recursion JavaScript works

I am a beginner in code world. I have troubles understanding recursion in JavaScript especially when it needs two or more looping. Like I want to print rectangle using recursion. I don't know completely how to make a base case, condition when it still executed. For examples, these codes below I use to print rectangle or holey rectangle.
function box(num) {
for (let i = 0; i < num; i++) {
let str = ''
for (let j = 0; j < num; j++) {
str += '*'
}
console.log(str)
}
}
box(5)
function holeBox (num) {
for(let i = 0; i < num; i++){
let str = ''
for(let j = 0; j < num; j++){
if(i == 0 || i == num -1 || j == 0 || j == num - 1) {
str += '*'
} else {
str += ' '
}
}
console.log(str)
}
}
holeBox (5)
Please help me to understand recursion, an explanation would be great. My goals are not only to solve those codes but also to understand how recursion works. I've searched there's no good source to learn recursion, or I just too dumb to understand. Thanks in advance
To understand how recursion works, just think of how you can split up what you want to accomplish into smaller tasks, and how the function can complete one of those tasks, and then call itself to do the next- and so on until it is finished. I personally don't think printing boxes is the best way to learn recursion, so imagine you wanted to search an array for a specific value; ignore JavaScript's indexOf()/find() functions or similar for now.
To do this using loops, its easy, just iterate over the array, and check every value:
//Returns the index of the first occurrence of a value in an array, or -1 if nothing is found
function search(needle, haystack) {
for (let i = 0; i < haystack.length; i++) {
if (haystack[i] == needle) return i;
}
return -1;
}
Doing this using recursion is easy as well:
function recursiveSearch(needle, haystack, i) {
if (i > (haystack.length - 1)) return -1; //check if we are at the end of the array
if (haystack[i] == needle) return i; //check if we've found what we're looking for
//if we haven't found the value yet and we're not at the end of the array, call this function to look at the next element
return recursiveSearch(needle, haystack, i + 1);
}
These functions do the same thing, just differently. In the recursive function, the two if statements are the base cases. The function:
Tests if the current element is out of bounds of the array (meaning we've already searched every element), and if so, returns -1
Tests if the current element is what we're looking for, and if so, returns the index
If neither of the statements above apply, we call this function recursively to check the next element
Repeat this until one of the base cases kicks in.
Note that recursive functions are usually called from other helper functions so that you don't have to pass the initial parameters to call the function. For example, the recursiveSearch() function above would be private, and it would be called by another function like this:
function search(needle, haystack) {
return recursiveSearch(needle, haystack, 0);
}
so that we don't have to include the third parameter when we call it, thus decreasing confusion.
Yes, even your box code can be turn into recursion but I don't think it will help you understand the concept of recursion.
If you really have to:
function getBox(arr, size) {
let length = arr.length;
if (length == size)
return arr; // recursion stop rule - if the size reached
for (let i = 0; i < length; i++)
arr[i].push("*"); // fill new size for all row
arr.push(new Array(length + 1).fill("*")); // add new row
return getBox(arr, size); // recursive call with arr bigger in 1 row
}
However, I believe #Gumbo answer explain the concept better then this...

JavaScript: setInterval and for loop explanation

i searched around for a couple of questions related to the use of the for loop and the setInterval function in JavaScript but i couldn´t find a concrete answer on why this snippet doesn´t work. Could someone explain please what´s happening under the hood and why this code doesn´t print anything at all?
for (let i = 0; i++; i < 10) {
window.setInterval(function () {
console.log('Test');
} , 100)
}
Your for loop is not correct. The condition needs to be the second statement in the for loop.
Following code should work.
for (let i = 0; i < 10 ; i++; ) {
window.setInterval(function () {
console.log('Test');
} , 100)
}
Expected Syntax for loop. You can read more here
for ([initialization]; [condition]; [final-expression])
statement
EDIT 1:
Though all answers (including mine) mentioned that condition needs to be second statement in the for loop which is correct. There is one more additional important behavior.
The for loop for (let i = 0; i++; i < 10) is actually correct in terms of grammar and even the javascript runtime executes this code.
But, as in your case, if the condition is evaluating to falsy value then it would exit the loop.
Breaking your for loop for (let i = 0; i++; i < 10) into each seperate construct
Initialization: let i = 0; This statement initializes the value of variable i to 0.
Condition: i++; Javascript evaluates the statement to check if the statement is true or not. In case of i++ the runtime firstly checks for the current value of i which is 0 . Since 0 is considered a falsy value the condition evaluates to false and hence the statement is not executed. Also, i++ statement is a post increment which basically increments i and then result the original value of i.
So, if you would have written loop like below, using the intiliaztion of i=1, then it would have worked, though it would be running infinitely untill the browser/Server crashes as the condition i++ would always evaluate to true. I hope that makes sense.
for (let i = 1; i++; i < 10) {
// Statements would run
}
Or
for (let i = 0; ++i; i < 10) { **// Pre increment**
// Statements would run
}
Or
for (let i = 0; i=i+1; i < 10) { **// increment i by assigment
// Statements would run
}
Douglas Crockford in his book Good Parts mention about the usage of ++ & -- and how it can confuse readers.
your for loop syntax is wrong, should be
for (let i = 0; i < 10; i++)
your setInterval code will run every 100 milliseconds for each iteration of the loop (so 10 times every 100 milliseconds)
Nothing to do with setInterval, you simply malformed your for loop:
This:
for (let i = 0; i++; i < 10)
Should be this:
for (let i = 0; i < 10; i++)
First declare the initial state of the loop, then the terminating state of the loop, then the incremental change of the loop.
Observe.

For loop homework

I have homework and these are my instructions:
create javascript 06.js with a general function: addThemUp()
There is NO HTML page. There is NO EVENT HANDLER.
The function receives two parameters. They go between (..).
Use any names you want for the parameters but you could use descriptive names
Add all integers from the first parameter to the second.
All you need to do is use a for() loop and return the total.
Return the total of the integers. Use return because this is a general function.
Here is my code
function addThemUp(earlier,later) {
var total = 0;
for (i = 0; i <= earlier; i ++) {
total = total + 0;
};
return total;
};
For some reason this one is messing up bad. We were able to do this exact same thing with Count but adding up and array seems to be different. When I run it through the grader I'm only receiving 25% grade.
You need to make use of both earlier and later in your loop:
function addThemUp(earlier,later) {
var total = 0;
for (i = earlier; i <= later; i ++) {
total = total + i;
};
return total;
};
Shouldn't it be using
i <= later
As it would stop on the first value otherwise?
I'll point out two things that could help you on your way.
First: this line
total = total + 0;
Think about what it's doing for a bit.
total (which starts as 0) is adding... 0... to itself. ;)
Next, this line:
for (i = 0; i <= earlier; i ++) {
IIRC, earlier is the first of the two numbers you're concerned about.
That part of the for loop says "stop when this condition is met." ;)

Strange behaviour of for loop in Heap's algorithm in JavaScript

I'm trying to implement Heap's algorithm to find different permutations of a string and found a strange behaviour with a for loop, here's the code
function permAlone(str) {
var strArr = str.split(''),
permutations = [];
function swap(strArr, x, y) {
var tmp = strArr[x];
strArr[x] = strArr[y];
strArr[y] = tmp;
}
function generate(n) {
if (n === 1) {
permutations.push(strArr.join());
} else {
for (var i = 0; i != n; i++) {
generate(n - 1);
swap(n % 2 ? 0 : i, n - 1);
}
}
}
generate(strArr.length);
return permutations;
}
console.log(permAlone('aab'));
In the for loop within the generate function, if I put i = 0 the output of the script is ['a,a,b', 'a,a,b'] but if I put var i = 0 the output is ['a,a,b', 'a,a,b', 'a,a,b', 'a,a,b', 'a,a,b', 'a,a,b'].
I understand that var i would create a local variable for the loop, but don't understand in this case why it would change how the loop functions as there is no i variable declared anywhere else in the script.
Thanks any help appreciated.
The reason the behaviour changes if you have a global i variable is that you have multiple recursive calls to generate() all trying to control their own partially complete for loops with the same variable, and all setting i back to 0 when they start.
Picture what happens on the second iteration of the for loop: i is 1 because it has just been incremented, but then immediately a recursive call to generate() starts its own loop and sets i back to 0 again.
If you create a local variable with var then each for loop in each recursive call is independent of all the others.
Try stepping through the code with the debugger, or try adding the following as the first line inside the for loop and watch what happens to the variables when the code runs:
console.log('n:' + n + '; i: '+i);

Trouble pushing to an array in JS

Below is just a section of my code but I know it's problematic because I can't get it to return any value except 'undefined'. I have been over this for hours and cannot figure it out.
I want to be able to input a number and have its factors pushed to an array. I have tested it by alerting the first item in the array and I get nothing. I'm sure this is a pretty easy but I just can't figure it out. Here is the code:
var numberInQuestion = prompt("Of what number are you wanting to find the largest prime factor?");
//determine factors and push to array for later use
var factorsArray = [];
function factors(numberInQuestion){
for(var i = 2; i < numberInQuestion-1; i++){
if(numberInQuestion % i === 0){
return factorsArray.push[i];
} else {
continue;
}
}
};
factors(numberInQuestion);
alert(factorsArray[0]);
Thanks for any help!
you can only return one value
you must use (), not [] for calling push
factorsArray should be local to factors (put the definition inside the function)
the else { continue; } is useless
Here is the fully corrected code:
var numberInQuestion = prompt("Of what number are you wanting to find the factors of?");
//determine factors
function factors(numberInQuestion){
var factorsArray = []; // make it local
for (var i = 2; i < numberInQuestion-1; i++){
if(numberInQuestion % i === 0){
factorsArray.push(i); // use (), and don't return here
} // no need for else { continue; } because it's a loop anyway
}
return factorsArray; // return at the end
};
var result = factors(numberInQuestion); // assign the result to a variable
alert(result);
Here's a JSFiddle.
You have an error in your pushing syntax. Correct syntax for pushing is -
factorsArray.push(i);
Also returning immediately from the function after finding the first divisor will not give you the full list. You probably want to return after you've found out all the divisors.
Taking all of the above into consideration, you should rewrite your function as follow -
function factors(numberInQuestion){
for(var i = 2; i < numberInQuestion - 1; i++){
if(numberInQuestion % i === 0) {
factorsArray.push(i);
}
}
}
and you will be OK.
You've coded this so that when you find the first factor your function returns immediately. Just get rid of the return keyword in that statement. (What "return" means in JavaScript and other similar languages is to immediately exit the function and resume from where the function was called.)
Oh, also, you call functions (like .push()) with parentheses, not square brackets.
The function should not return when pushing to the array. Return the array after executing the loop. The else clause is also unnecessary.
var numberInQuestion = prompt("Of what number are you wanting to find the largest prime factor?");
function factors(numberInQuestion){
var factorsArray = [];
for(var i = 2; i < numberInQuestion-1; i++){
if(numberInQuestion % i === 0 && isPrime(i)){
factorsArray.push(i);
}
}
return factorsArray;
};
var factors = factors(numberInQuestion);
alert(factors[factors.length-1]);
//From: http://stackoverflow.com/questions/11966520/how-to-find-prime-numbers
function isPrime (n)
{
if (n < 2) return false;
var q = Math.sqrt (n);
for (var i = 2; i <= q; i++)
{
if (n % i == 0)
{
return false;
}
}
return true;
}
Given the purpose of the example two items must be considered
The code does not determine if the number is actually prime. The code will return the smallest factor possible since the loop starts at two and increments, then returns the first element in the array. The largest factor would actually be the last element in the array. I have corrected the example to find the greatest prime factor. You can test it via this fiddle: http://jsfiddle.net/whKGB/1/

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