So i need to make this calculator have specific themes 3 to be exact. I read some documentation and found a good way to do it with data atributes. I goes as follows. You define all the variables for a specific theme but only activatie them when a certain data atribute is present in the html tag. If you change the data atribute the variables should now be redefined for that theme. Now ik know this works in CSS but it doesnt seam to work for SCSS. maybe i am doing something wrong syntax related.
these are my SCSS variables.
// Typography
$main-Font: 'Spartan',
sans-serif;
// Theme 1
$background: hsl(222, 26%, 31%);
$keypadColor: hsl(223, 31%, 20%);
$ScreenColor: hsl(224, 36%, 15%);
$tertiaryKeyColor: hsl(225, 21%, 49%);
$tertiaryKeyColorShadow: hsl(224, 28%, 35%);
$secondaryKeyColor: hsl(6, 63%, 50%);
$secondaryKeyColorShadow: hsl(6, 70%, 34%);
$basicKeyColor: hsl(30, 25%, 89%);
$basicKeyColorShadow: hsl(28, 16%, 65%);
$text1: hsl(221, 14%, 31%);
$text2: hsl(0, 0, 100%);
$text3: hsl(0, 0, 100%);
html[data-color-mode="theme-2"] {
// Theme 2
$background: hsl(0, 0%, 90%);
$keypadColor: hsl(0, 5%, 81%);
$ScreenColor: hsl(0, 0%, 93%);
$tertiaryKeyColor: hsl(185, 42%, 37%);
$tertiaryKeyColorShadow: hsl(185, 58%, 25%);
$secondaryKeyColor: hsl(25, 98%, 40%);
$secondaryKeyColorShadow: hsl(25, 99%, 27%);
$basicKeyColor: hsl(45, 7%, 89%);
$basicKeyColorShadow: hsl(35, 11%, 61%);
$text1: hsl(60, 10%, 19%);
$text2: hsl(0, 0, 100%);
$text3: hsl(0, 0, 100%);
}
html[data-color-mode="theme-3"]{
// Theme 3
$background: hsl(268, 75%, 9%);
$keypadColor: hsl(268, 71%, 12%);
$ScreenColor: hsl(268, 71%, 12%);
$tertiaryKeyColor: hsl(281, 89%, 26%);
$tertiaryKeyColorShadow: hsl(285, 91%, 52%);
$ScreenColor: hsl(176, 100%, 44%);
$secondaryKeyColorShadow: hsl(177, 92%, 70%);
$basicKeyColor: hsl(268, 47%, 21%);
$basicKeyColorShadow: hsl(290, 70%, 36%);
$text1: hsl(52, 100%, 62%);
$text2: hsl(0, 0, 100%);
$text3: hsl(198, 20%, 13%);
}
this is the HTML
<!DOCTYPE html>
<html lang="en" data-color-mode="theme-1">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0"> <!-- displays site properly based on user's device -->
<title>Frontend Mentor | Calculator app</title>
<!-- stylesheet link -->
<link rel="stylesheet" href="./css/index.css">
<!-- Js link -->
<script src="./js/app.js" defer></script>
</head>
<body>
<div class="calculator-container">
<header class="flex">
<h2>Calc</h2>
<div class="toggle-button-container">
<h3>theme</h3>
<input type="range" max="2" value="0" name="theme-selector" id="theme-selector-button">
</div>
</header>
<div class="display">
</div>
<main class="keypad grid">
<button>7</button>
<button>8</button>
<button>9</button>
<button class="tertiary-color">DEL</button>
<button>4</button>
<button>5</button>
<button>6</button>
<button>+</button>
<button>1</button>
<button>2</button>
<button>3</button>
<button>-</button>
<button>.</button>
<button>0</button>
<button>/</button>
<button>x</button>
<button class="col-span tertiary-color">RESET</button>
<button class="col-span secondary-color">=</button>
</main>
</div>
</body>
</html>
and this function changes the data atribute. Now this part works because i can see the atribute change in the dev tools
```
const themeSelectorBtn = document.getElementById('theme-selector-button');
let keypadBtns = Array.from(document.querySelectorAll('button'));
const display = document.querySelector('.display');
const app = document.querySelector('html')
themeSelectorBtn.addEventListener('input', () => {
let currentValue = themeSelectorBtn.value;
if(currentValue == 0){
app.dataset.colorMode = 'theme-1';
} else if(currentValue == 1) {
app.dataset.colorMode = 'theme-2';
} else {
app.dataset.colorMode = 'theme-3';
}
})
```
and the documentation i am trying to replicate contains this but in CSS instead of SCSS
```
:root {
/* Theme 1 */
/* Backgrounds */
--main-bg-theme: hsl(222, 26%, 31%);
--toggle-bg-theme: hsl(221, 38%, 25%);
--btn-bg-theme: hsl(221, 35%, 19%);
--screen-bg-theme: hsl(224, 36%, 15%);
--top: white;
/* Button */
--btn-second-bg-theme: hsl(225, 21%, 49%);
--btn-second-shadow-theme: hsl(223, 31%, 24%);
--equals-theme: hsl(6, 63%, 50%);
--btn-primary-bg-theme: hsl(30, 25%, 89%);
--btn-primary-shadow-theme: hsl(28, 16%, 65%);
/* Text */
--text1-theme: hsl(221, 14%, 31%);
--text2-theme: hsl(0, 0, 100%);
--equals: white;
--display: hsl(0, 0, 100%);
--equals-shadow: hsl(6, 70%, 34%);
}
html[data-color-mode="theme2"] {
/* Backgrounds */
--main-bg-theme: hsl(0, 2%, 89%);
--toggle-bg-theme: hsl(0, 12%, 82%);
--btn-bg-theme: hsl(0, 12%, 82%);
--screen-bg-theme: hsl(0, 0%, 100%);
--top: black;
/* Button */
--btn-second-bg-theme: hsl(185, 42%, 37%);
--btn-second-shadow-theme: hsl(185, 50%, 25%);
--equals-theme: hsl(6, 63%, 50%);
--btn-primary-bg-theme: hsl(45, 7%, 89%);
--btn-primary-shadow-theme: hsl(35, 11%, 61%);
/* Text */
--text1-theme: hsl(192, 12%, 8%);
--text2-theme: hsl(0, 0, 100%);
--equals: white;
--display: black;
--equals-shadow: hsl(6, 70%, 34%);
}
html[data-color-mode="theme3"] {
/* Backgrounds */
--main-bg-theme: hsl(268, 75%, 9%);
--toggle-bg-theme: hsl(268, 74%, 20%);
--btn-bg-theme: hsl(268, 74%, 20%);
--screen-bg-theme: hsl(268, 74%, 20%);
--top: hsl(54, 63%, 75%);
/* Button */
--btn-second-bg-theme: hsl(281, 89%, 26%);
--btn-second-shadow-theme: hsl(290, 69%, 43%);
--equals-theme: hsl(177, 92%, 70%);
--btn-primary-bg-theme: hsl(281, 71%, 21%);
--btn-primary-shadow-theme: hsl(290, 70%, 36%);
/* Text */
--text1-theme: hsl(54, 63%, 75%);
--text2-theme: hsl(0, 0, 100%);
--equals: black;
--display: hsl(54, 63%, 75%);
--equals-shadow: hsl(189, 69%, 43%);
}
```
So it turns out i made a silly mistake. I put a - in between colorMode in the HTML file. It works fine now.
Related
Is it possible to have a background gradient that spans an entire table row? I'm only able to apply the background to individual table cells, even when I'm specifically trying to prevent that. Here is a boiled-down sample that targets Webkit on jsfiddle:
http://jsfiddle.net/cGV47/2/
As you can see, I am using border-collapse:collapse and I am specifying background:transparent for the <tr> and <th> child elements, yet the red gradient to the left is repeated for each table cell. I've tried applying the background to the <tr> as well, but with the same result as you see now.
To view the code without going to jsfiddle, here it is:
html
<table>
<thead>
<tr>
<th>One</th>
<th>Two</th>
<th>Three</th>
<th>Four</th>
</tr>
</thead>
<tbody>
<tr>
<td>un</td>
<td>deux</td>
<td>trois</td>
<td>quatre</td>
</tr>
</tbody>
</table>
css
* {margin:0;padding:0;border:0;border-collapse:collapse;}
table { width:100%; }
thead { background: -webkit-linear-gradient(left, rgba(222,22,22,1) 0%, rgba(222,222,222,0) 20%, rgba(222,222,222,0) 80%, rgba(222,222,222,1) 100%); }
thead tr, thead th { background:transparent; }
set background-attachment:fixed; on thead and it will work fine
http://jsfiddle.net/cGV47/64/
I think there is a better solution to these:
Apply the gradient background to the whole table.
Then apply a solid background for thead and tfooter.
table { border:0; border-collapse:collapse;
background: -moz-linear-gradient(left, rgba(255,255,255,1) 0%, rgba(108,211,229,0.2) 40%, rgba(108,211,229,0.2) 60%, rgba(255,255,255,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top, color-stop(0%,rgba(255,255,255,1)), color-stop(40%,rgba(108,211,229,0.2)), color-stop(60%,rgba(108,211,229,0.2)), color-stop(100%,rgba(255,255,255,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left, rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(left, rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(left, rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* IE10+ */
background: linear-gradient(to right, rgba(255,255,255,1) 0%,rgba(108,211,229,0.2) 40%,rgba(108,211,229,0.2) 60%,rgba(255,255,255,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#ffffff',GradientType=1 ); /* IE6-9 */
}
table thead, tfoot {
background: #fff;
}
Take a look:
http://jsfiddle.net/5brPL/
I have found myself testing the brand new repeating-linear-gradient, which apparently works for <tr> elements (I have only tested in Google Chrome though).
The trick is to provide the widest repeating pattern, so that... it does not repeat.
Try this:
tr {
background: repeating-linear-gradient(
45deg,
red 0%,
blue 100%
);
}
http://jsfiddle.net/slyy/2pzwws0d/
Not the prettiest solution, but it does do the trick. You just set up each th to have 25% of the color range. The example below uses a color range from 0 to 255.
http://jsfiddle.net/cGV47/3/
Same HTML that you already have. Here's the CSS:
table { width:100%; }
th {
background: -webkit-linear-gradient(left, rgba(255,255,255,1) 0%,
rgba(191,191,191,1) 100%);
}
th + th {
background: -webkit-linear-gradient(left, rgba(191,191,191,1) 0%,
rgba(128,128,128,1) 100%);
}
th + th + th {
background: -webkit-linear-gradient(left, rgba(128,128,128,1) 0%,
rgba(64,64,64,1) 100%);
}
th + th + th + th {
background: -webkit-linear-gradient(left, rgba(64,64,64,1) 0%,
rgba(0,0,0,1) 100%);
}
I found this issue on Google: http://code.google.com/p/chromium/issues/detail?id=122988 but there is no solution.
Firefox does not have this issue (didn't check any other browsers):
http://jsfiddle.net/cGV47/4/
I have put together a little code that I had hoped would allow the html to scroll to the left whenever a user scrolls down and scroll right when the user scrolls up
I've put together an example of my code here JSFIDDLE
$(document).ready(function() {
$(window).bind('mousewheel', function(e) {
e.preventDefault();
if (e.originalEvent.wheelDelta >= 0) {
$('html, body').scrollRight(1);
}
else {
$('html, body').scrollLeft(1);
}
});
});
I need to prevent the user from scrolling vertically and want the vertical scrolls to cause horizontal scrolling instead.
The scrollRight method is not defined by jQuery so you have to use scrollLeft.
When you call scrollLeft without any arguments you get the current scroll position (starting from the left edge). When you call scrollLeft(value) you set the current scroll position to value (ref. https://api.jquery.com/scrollleft/).
Following snippet works.
$(document).ready(function() {
var body = $('body');
$(window).bind('mousewheel', function(e) {
e.preventDefault();
body.scrollLeft(body.scrollLeft() - e.originalEvent.wheelDelta);
});
});
section {
width: 500vw;
height: 100vh;
/*unimportant */
background: rgba(76,76,76,1);
background: -moz-linear-gradient(45deg, rgba(76,76,76,1) 0%, rgba(89,89,89,1) 12%, rgba(102,102,102,1) 25%, rgba(71,71,71,1) 39%, rgba(44,44,44,1) 50%, rgba(0,0,0,1) 51%, rgba(17,17,17,1) 60%, rgba(43,43,43,1) 76%, rgba(28,28,28,1) 91%, rgba(19,19,19,1) 100%);
background: -webkit-gradient(left bottom, right top, color-stop(0%, rgba(76,76,76,1)), color-stop(12%, rgba(89,89,89,1)), color-stop(25%, rgba(102,102,102,1)), color-stop(39%, rgba(71,71,71,1)), color-stop(50%, rgba(44,44,44,1)), color-stop(51%, rgba(0,0,0,1)), color-stop(60%, rgba(17,17,17,1)), color-stop(76%, rgba(43,43,43,1)), color-stop(91%, rgba(28,28,28,1)), color-stop(100%, rgba(19,19,19,1)));
background: -webkit-linear-gradient(45deg, rgba(76,76,76,1) 0%, rgba(89,89,89,1) 12%, rgba(102,102,102,1) 25%, rgba(71,71,71,1) 39%, rgba(44,44,44,1) 50%, rgba(0,0,0,1) 51%, rgba(17,17,17,1) 60%, rgba(43,43,43,1) 76%, rgba(28,28,28,1) 91%, rgba(19,19,19,1) 100%);
background: -o-linear-gradient(45deg, rgba(76,76,76,1) 0%, rgba(89,89,89,1) 12%, rgba(102,102,102,1) 25%, rgba(71,71,71,1) 39%, rgba(44,44,44,1) 50%, rgba(0,0,0,1) 51%, rgba(17,17,17,1) 60%, rgba(43,43,43,1) 76%, rgba(28,28,28,1) 91%, rgba(19,19,19,1) 100%);
background: -ms-linear-gradient(45deg, rgba(76,76,76,1) 0%, rgba(89,89,89,1) 12%, rgba(102,102,102,1) 25%, rgba(71,71,71,1) 39%, rgba(44,44,44,1) 50%, rgba(0,0,0,1) 51%, rgba(17,17,17,1) 60%, rgba(43,43,43,1) 76%, rgba(28,28,28,1) 91%, rgba(19,19,19,1) 100%);
background: linear-gradient(45deg, rgba(76,76,76,1) 0%, rgba(89,89,89,1) 12%, rgba(102,102,102,1) 25%, rgba(71,71,71,1) 39%, rgba(44,44,44,1) 50%, rgba(0,0,0,1) 51%, rgba(17,17,17,1) 60%, rgba(43,43,43,1) 76%, rgba(28,28,28,1) 91%, rgba(19,19,19,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#4c4c4c', endColorstr='#131313', GradientType=1 );
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section></section>
First of all, you miss te parenthesis at the end of the preventDefault() call. That's why the vertical scrollbar still works.
Second, there is no such jQuery method as scrollRight(). You should use the scrollLeft() method for both direction.
See your updated fiddle!
How to make a fixed gradient background? I have tried a few CSS and HTML code like this:
.mygradienttop {
background-color: #C5C2C2;
background: -webkit-gradient(linear, 0% 0%, 0% 100%, from(#651212), to(#C5C2C2), color-stop(.5,#462020));
background: -moz-linear-gradient(top, #651212 0%, #462020 50%, #C5C2C2 100%);
}
But it's not working. I'm using three.js r63.
I have a div
<div class="test">
Some text
</div>
I would like to have different background color for the same div by percent (Horizontal coloring)
-----------------------------
| 20% | 30% | 50% |
| Red | Yellow | Green |
-----------------------------
Is this possible with CSS?
You can use CSS3 Gradients[1] to achieve such effect
div {
background: linear-gradient(to right, #ff3236 0%,#ff3033 32%,#3e30ff 32%,#3e30ff 63%,#33ff30 63%,#33ff30 100%);
height: 400px;
}
Demo
You can create such gradients over here
You can also use px as a unit, along with % if you are looking for static gradient widths
Demo (Please add browser-prefixes if you are looking for a cross browser solution, I've not added all the rules in this demo)
Demo 2 (Vertical Split, just change to right to to bottom)
1. More on CSS3 Gradients
2. Browser Support
You could achieve this by using a gradient:
Either google it and create an own.
Or use a generator like this:
http://www.colorzilla.com/gradient-editor/
which gives you the following css-code:
background: #ff3019; /* Old browsers */
background: -moz-linear-gradient(left, #ff3019 0%, #d40000 20%, #f2f600 20%, #f2f600 50%, #1e7a00 50%, #1e7a00 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, right top, color-stop(0%,#ff3019), color-stop(20%,#d40000), color-stop(20%,#f2f600), color-stop(50%,#f2f600), color-stop(50%,#1e7a00), color-stop(100%,#1e7a00)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(left, #ff3019 0%,#d40000 20%,#f2f600 20%,#f2f600 50%,#1e7a00 50%,#1e7a00 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(left, #ff3019 0%,#d40000 20%,#f2f600 20%,#f2f600 50%,#1e7a00 50%,#1e7a00 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(left, #ff3019 0%,#d40000 20%,#f2f600 20%,#f2f600 50%,#1e7a00 50%,#1e7a00 100%); /* IE10+ */
background: linear-gradient(to right, #ff3019 0%,#d40000 20%,#f2f600 20%,#f2f600 50%,#1e7a00 50%,#1e7a00 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ff3019', endColorstr='#1e7a00',GradientType=1 ); /* IE6-9 */
You could create three descendant divs within the parent. Absolutely position them, make the parent transparent, then give the three divs a z-index of 0 so they sit underneath the text, not on top.
This method of progressive enhancement works for all browsers that support CSS 2.1 pseudo-elements and their positioning. No CSS3 support required
#div{
position:relative;
z-index:1;
min-width:200px;
min-height:200px;
padding:120px 200px 50px;
background:#d3ff99 url(vines-back.png) -10% 0 repeat-x;
}
#div:before,
#div:after {
position:absolute;
z-index:-1;
top:0;
left:0;
right:0;
bottom:0;
padding-top:100px;
}
DEMO
Is it possible to animate the position of a CSS3-gradient-color using jQuery?
I'd like to animate from this
background: -moz-linear-gradient(top, #FF0000 0%, #FF0000 0%, #FFFFFF 0%,
#FFFFFF 100%); /* firefox */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#FF0000), color-stop(0%,#FF0000),
color-stop(0%,#FFFFFF), color-stop(100%,#FFFFFF)); /* webkit */
to this
background: -moz-linear-gradient(top, #FF0000 0%, #FF0000 50%, #FFFFFF 50%,
#FFFFFF 100%); /* firefox */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#FF0000),
color-stop(50%,#FF0000), color-stop(50%,#FFFFFF), color-stop(100%,#FFFFFF)); /* webkit */
in xx milliseconds
thank you in advance!
Be creative.. This is an example of how I do gradient transitions without extra plugins..
I use 2 identical divs with different gradients layered one on top of the other. Then I use jquery to animate the opacity of the one on top..
Here is it step by step
create a wrapper with a fixed size lets say "width:200px" and "height:100px" (I use a wrapper so that its easier to adjust the position of the divs inside it)
create 2 divs that are the same size as the wrapper give both different background gradients but use the same content for both so visually the only thing that changes is the background gradient.
add "position:relative;" and adjust the position of the div that will be on top, in this case box2 with "bottom:100px;" (notice its the same value as the height of the wrapper and the divs. This makes the div that will be on top to move up 100px positioning itself right over the lower div, relative to the wrapper... this is not possible without using "position:relative;" on the top div)
animate the opacity of the div with your preferred method i use fadeToggle in this example
HTML-----
Click to change gradient<br>
<div align="center" style="width:200px; height:100px;">
<div style="width:200px; height:100px;" class="box1" id="box1">CONTENT BOTTOM DIV</div>
<div style="width:200px; height:100px; position:relative;" class="box2" id="box2">CONTENT TOP DIV</div>
</div>
GRADIENTS IN CSS-----
.box1 {
background: rgb(237,144,23); /* Old browsers */
background: -moz-linear-gradient(top, rgba(237,144,23,1) 0%, rgba(246,230,180,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(237,144,23,1)), color-stop(100%,rgba(246,230,180,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(237,144,23,1) 0%,rgba(246,230,180,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(237,144,23,1) 0%,rgba(246,230,180,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(237,144,23,1) 0%,rgba(246,230,180,1) 100%); /* IE10+ */
background: linear-gradient(top, rgba(237,144,23,1) 0%,rgba(246,230,180,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ed9017', endColorstr='#f6e6b4',GradientType=0 ); /* IE6-9 */
}
.box2 {
background: rgb(246,230,180); /* Old browsers */
background: -moz-linear-gradient(top, rgba(246,230,180,1) 0%, rgba(237,144,23,1) 100%);/* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(246,230,180,1)), color-stop(100%,rgba(237,144,23,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(246,230,180,1) 0%,rgba(237,144,23,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(246,230,180,1) 0%,rgba(237,144,23,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(246,230,180,1) 0%,rgba(237,144,23,1) 100%); /* IE10+ */
background: linear-gradient(top, rgba(246,230,180,1) 0%,rgba(237,144,23,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#f6e6b4', endColorstr='#ed9017',GradientType=0 ); /* IE6-9 */
}
jQuery animation----
$(document).ready(function(){
$("a").click(function(){
$("#box2").fadeToggle(100, "linear");
});
});
you can layer a third div so that you dont need to write the same content twice by adding a second wrapper outside the first one and placing the third div after the inside wrapper closes..
to view this go to the following link..
Link to example
You can make the gradient twice as big (meaning incorporate the first gradient in the first 50%, and the second gradient in the last 50%) as it needs to and use this code:
-webkit-background-size: 200%;
-moz-background-size: 200%;
-o-background-size: 200%;
-ms-background-size: 200%;
background-size: 200%;
on the initial item and.
Not all the prefixes will work, but I do it for compatibility if they add it later
background-position:bottom;
On the hover
CSS gradient transitions haven't been implemented in any of the browsers yet, although it's in the spec. So, you can't do this. You'll need to do this with SVG (if you're brave).
This is a code snippet of one of my project where I use gradient transition using jquery.This may help you:
<div id="gr_anim"> Change Gradient </div>
var p1 = t = 0;
var p2 = 100;
function hello() {
p1 = p1 + 5;
p2 = 100 - p1;
if(p1 <= 100 && p2 >= 0) {
$('#gr_anim').css({
'background-image':'-moz-linear-gradient('+ p1 +'% '+ p2 +'% 45deg, #000, #fff)'
});
} else {
clearTimeout(t);
}
t = setTimeout('hello()',1000);}
$( function() {
hello();});
I think you should try it by using jquery ui's switchClass, you need to add JqueryUI and a link to the dependency effects core
http://jqueryui.com/demos/switchClass/
something like this:
<script type="text/javascript">
$(function() {
$("#button").click(function () {
$(".divPropertyStart").switchClass("divPropertyStart", "divProperty", 1000);
$(".divProperty").switchClass("divProperty", "divPropertyStart", 1000);
return false;
});
});
</script>
<style type="text/css">
.divPropertyStart { background: -moz-linear-gradient(top, #FF0000 0%, #FF0000 0%, #FFFFFF 0%, #FFFFFF 100%); background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#FF0000), color-stop(0%,#FF0000), color-stop(0%,#FFFFFF), color-stop(100%,#FFFFFF)); }
.divProperty { background: -moz-linear-gradient(top, #FF0000 0%, #FF0000 50%, #FFFFFF 50%, #FFFFFF 100%); background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#FF0000), color-stop(50%,#FF0000), color-stop(50%,#FFFFFF), color-stop(100%,#FFFFFF)); }
</style>
<div class="divPropertyStart"></div>
Toggle Effect
This works for me #localhost
Lauw
what about animating the width of the container to which the gradient applies ?
(example for Chrome with JQuery)
html:
<div id='test'>
</div>
<span id='click_me'>
</span>
css:
#test
{
width:400px; height: 400px; float:left;
background: linear-gradient(90deg, #5e5e5e 0%, #000 100%);
}
js:
$('#click_me').on('click',function ()
{
$('#test').animate({'width':'+=400'},400);
}
);
works a treat
EDIT: I've made a mistake here as regards the original question. I am going to leave the answer here though as I think that by using more elements than just one the position of the fade could be moved about with the animate() function within a container div, creating the effect of the fade position sliding