Trouble batch setting a document field by docId in Firestore - javascript

I have been using firebase (firestore) for a while but I'm a little stuck and was wondering if anyone can think of a solution.
On the firestore DB I have a single collection of users, each user has an email address and several other fields. In this instance I am checking if a user email exists and if it does, I want to create a list field for that particular user with a listUid. I am referencing the users by email, grabbing the docId for those users and then trying to set a list field for each of them.
I am not getting any error's from firestore, it's simply not updating in the DB for some reason and I can't figure out where I am going wrong. Thanks in advance
export const addListUidToExistingUserList = (
{ firestore },
emailArray,
listUid
) => {
return async () => {
let docIds = [];
emailArray.forEach((emailAddress) => {
//find users by email (works)
const query = db
.collection("users")
.where("email", "==", emailAddress);
//get docId's for user with matching email (works)
query.get().then((querySnapshot) => {
querySnapshot.forEach((doc) => {
docIds.push(doc.id);
});
});
//add a new list with corresponding listUid (does not work)
docIds.forEach((id) => {
let userRef = db.collection("users").doc(id);
batch.set(userRef, { lists: [{ listUid }] });
});
});
return await batch.commit();
};
};

You are running into this issue because your docIds array is always empty at the time you call docIds.forEach.
That's because query.get().then runs asynchronously, and so docIds.forEach is not waiting for it to complete.
You could either:
await query.get().then; or
Add the docIds.forEach function INSIDE the then callback of query.get.
Here are your possible fixes:
await query.get().then
//get docId's for user with matching email (works)
await query.get().then((querySnapshot) => {
querySnapshot.forEach((doc) => {
docIds.push(doc.id);
});
});
OR:
docIds.forEach inside then
//get docId's for user with matching email (works)
query.get().then((querySnapshot) => {
querySnapshot.forEach((doc) => {
docIds.push(doc.id);
});
docIds.forEach((id) => {
let userRef = db.collection("users").doc(id);
batch.set(userRef, { lists: [{ listUid }] });
});
});
Note: Of course, you could also add batch.set directly into your first iteration of querySnapshot.docs.forEach to prevent an unnecessary iteration.

Related

How to get data from 2 collection in firebase at a time?(similar to aggregate lookup in MongoDB) [duplicate]

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

how to remove an array item from firestore using JavaScript?

I'm trying to add a delete button to my page. the event listener callback is working properly except for the updateDoc function.
const deleteBook = document.getElementsByClassName('deleteBook');
for (let i = 0; i < deleteBook.length; i++) {
deleteBook[i].addEventListener('click', async () => {
//book to delete
const bookToDelete = deleteBook[i].parentElement.firstElementChild.textContent
// collection title to delete the book from
const bookCol = deleteBook[i].parentElement.parentElement.parentElement.firstElementChild.textContent
// get a snap of the database
const docRef = doc(dataBase, 'users', `${auth.currentUser.uid}`)
const docSnap = (await getDoc(docRef)).data();
// loop over the collections and get a match with the bookCol
for (const col in docSnap) {
if (docSnap[col].title === bookCol) {
console.log('col to delete from found')
console.log(`book to delete ${bookToDelete}`)
await updateDoc(doc(dataBase, 'users', `${auth.currentUser.uid}`), {
[`${col}.books`]: arrayRemove(`${bookToDelete}`)
}).then(()=>{
// fullfiled
console.log('book deleted')
}, ()=>{
// rejected
console.log('promis rejected')
})
}
}
})
}
Col is the object that contains the books array. In the console it always prints book deleted, but in the firestore console, nothing changes. this is a screenshot of the database.
I would really appreciate any help and thank you.
I have replicated the behavior that you're experiencing. I tried changing the content of ${bookToDelete} to any word or even ID. It always returns book deleted even if its deleted or not. The line of code below should be changed in order to get the correct output.
.then(()=>{
// fullfiled
console.log('book deleted')
}, ()=>{
// rejected
console.log('promis rejected')
})
I have created a workaround for your use-case with this kind of issue. See snippet below:
const db = getFirestore();
const colName = "users";
const arrayName = "books";
const usersCol = collection(db, colName);
const userRef = doc(db, colName, `${auth.currentUser.uid}`);
const arrayRef = `${col}.${arrayName}`;
const q = query(usersCol, where(arrayRef, "array-contains", `${bookToDelete}`));
const querySnapshot = await getDocs(q)
.then((querySnapshot) => {
// Removal of object will not proceed if the querySnapshot is empty.
if ((querySnapshot.empty)) {
console.log("No object found!");
}
else {
// Proceeds to removal of object.
updateDoc(userRef, {
[arrayRef]: arrayRemove(`${bookToDelete}`)
})
.then(() => {
// Check again if the object was deleted successfully.
const querySnapshot = getDocs(q)
.then((querySnapshot) => {
if ((querySnapshot.empty)) {
console.log("Book Deleted!");
}
else {
console.log("Failed!");
}
})
});
}
})
// Catch if there are any Firebase errors.
.catch(error => console.log('Failed!', error));
The workaround that I created will query the object in the array then remove the object in the array if it exist. After removing, it will query again to check if the object has been deleted and logs Book Deleted!. Vise versa for checking if the object doesn't exist on the 1st query, it will not proceed on removing them and logs No object found!.
The workaround itself can still be improved. You can add any logic you want for your use-case.
I'd also recommend to create a Feature Request if you want to have this kind of feature together with the arrayRemove Method.

What is going wrong with my express call? I need an array of ID's but its returning an empty array

Im guessing this problem is because I don't know how to use async await effectively. I still dont get it and I've been trying to understand for ages. sigh.
Anyway, heres my function:
app.post("/declineTrades", async (request, response) => {
//---------------------------------------------
const batch = db.batch();
const listingID = request.body.listingID;
const tradeOfferQuery = db
//---------------------------------------------
//Get trade offers that contain the item that just sold
//(therefore it cannot be traded anymore, I need to cancel all existing trade offers that contain the item because this item isn't available anymore)
//---------------------------------------------
.collection("tradeOffers")
.where("status", "==", "pending")
.where("itemIds", "array-contains", listingID);
//---------------------------------------------
//Function that gets all trade offers that contain the ID of the item.
async function getIdsToDecline() {
let tempArray = [];
tradeOfferQuery.get().then((querySnapshot) => {
querySnapshot.forEach((doc) => {
//For each trade offer found
let offerRef = db.collection("tradeOffers").doc(doc.id);
//Change the status to declined
batch.update(offerRef, { status: "declined" });
//Get the data from the trade offer because I want to send an email
//to the who just got their trade offer declined.
const offerGet = offerRef.get().then((offer) => {
const offerData = offer.data();
//Check the items that the receiving person had in this trade offer
const receiverItemIds = Array.from(
offerData.receiversItems
.reduce((set, { itemID }) => set.add(itemID), new Set())
.values()
);
//if the receiver item id's array includes this item that just sold, I know that
//I can get the sender ID (users can be sender or receiver, so i need to check which person is which)
if (receiverItemIds.includes(listingID)) {
tempArray.push(offerData.senderID);
}
});
});
});
//With the ID's now pushed, return the tempArray
return tempArray;
}
//---------------------------------------------
//Call the above function to get the ID's of people that got declined
//due to the item no longer being available
const peopleToDeclineArray = await getIdsToDecline();
//Update the trade offer objects to declined
const result = await batch.commit();
//END
response.status(201).send({
success: true,
result: result,
idArray: peopleToDeclineArray,
});
});
Im guessing that my return tempArray is in the wrong place? But I have tried putting it in other places and it still returns an empty array. Is my logic correct here? I need to run the forEach loop and add to the array before the batch.commit happens and before the response is sent.
TIA Guys!
As #jabaa pointed out in their comment, there are problems with an incorrectly chained Promise in your getIdsToDecline function.
Currently the function initializes an array called tempArray, starts executing the trade offer query and then returns the array (which is currently still empty) because the query hasn't finished yet.
While you could throw in await before tradeOfferQuery.get(), this won't solve your problem as it will only wait for the tradeOfferQuery to execute and the batch to be filled with entries, while still not waiting for any of the offerRef.get() calls to be completed to fill the tempArray.
To fix this, we need to make sure that all of the offerRef.get() calls finish first. To get all of these documents, you would use the following code to fetch each document, wait for all of them to complete and then pull out the snapshots:
const itemsToFetch = [ /* ... */ ];
const getAllItemsPromise = Promise.all(
itemsToFetch.map(item => item.get())
);
const fetchedItemSnapshots = await getAllItemsPromise;
For documents based on a query, you'd tweak this to be:
const querySnapshot = /* ... */;
const getSenderDocPromises = [];
querySnapshot.forEach((doc) => {
const senderID = doc.get("senderID");
const senderRef = db.collection("users").doc(senderID);
getSenderDocPromises.push(senderRef.get());
}
const getAllSenderDocPromise = Promise.all(getSenderDocPromises);
const fetchedSenderDataSnapshots = await getAllSenderDocPromise;
However neither of these approaches are necessary, as the document you are requesting using these offerRef.get() calls are already returned in your query so we don't even need to use get() here!
(doc) => {
let offerRef = db.collection("tradeOffers").doc(doc.id);
//Change the status to declined
batch.update(offerRef, { status: "declined" });
//Get the data from the trade offer because I want to send an email
//to the who just got their trade offer declined.
const offerGet = offerRef.get().then((offer) => {
const offerData = offer.data();
//Check the items that the receiving person had in this trade offer
const receiverItemIds = Array.from(
offerData.receiversItems
.reduce((set, { itemID }) => set.add(itemID), new Set())
.values()
);
//if the receiver item id's array includes this item that just sold, I know that
//I can get the sender ID (users can be sender or receiver, so i need to check which person is which)
if (receiverItemIds.includes(listingID)) {
tempArray.push(offerData.senderID);
}
});
}
could be replaced with just
(doc) => {
// Change the status to declined
batch.update(doc.ref, { status: "declined" });
// Fetch the IDs of items that the receiving person had in this trade offer
const receiverItemIds = Array.from(
doc.get("receiversItems") // <-- this is the efficient form of doc.data().receiversItems
.reduce((set, { itemID }) => set.add(itemID), new Set())
.values()
);
// If the received item IDs includes the listed item, add the
// sender's ID to the array
if (receiverItemIds.includes(listingID)) {
tempArray.push(doc.get("senderID"));
}
}
which could be simplified to just
(doc) => {
//Change the status to declined
batch.update(doc.ref, { status: "declined" });
// Check if any items that the receiving person had in this trade offer
// include the listing ID.
const receiversItemsHasListingID = doc.get("receiversItems")
.some(item => item.itemID === listingID);
// If the listing ID was found, add the sender's ID to the array
if (receiversItemsHasListingID) {
tempArray.push(doc.get("senderID"));
}
}
Based on this, getIdsToDecline actually queues declining the invalid trades and returns the IDs of those senders affected. Instead of using the batch and tradeOfferQuery objects that are outside of the function that make this even more unclear, you should roll them into the function and pull it out of the express handler. I'll also rename it to declineInvalidTradesAndReturnAffectedSenders.
async function declineInvalidTradesAndReturnAffectedSenders(listingID) {
const tradeOfferQuery = db
.collection("tradeOffers")
.where("status", "==", "pending")
.where("itemIds", "array-contains", listingID);
const batch = db.batch();
const affectedSenderIDs = [];
const querySnapshot = await tradeOfferQuery.get();
querySnapshot.forEach((offerDoc) => {
batch.update(offerDoc.ref, { status: "declined" });
const receiversItemsHasListingID = offerDoc.get("receiversItems")
.some(item => item.itemID === listingID);
if (receiversItemsHasListingID) {
affectedSenderIDs.push(offerDoc.get("senderID"));
}
}
await batch.commit(); // generally, the return value of this isn't useful
return affectedSenderIDs;
}
This then would change your route handler to:
app.post("/declineTrades", async (request, response) => {
const listingID = request.body.listingID;
const peopleToDeclineArray = await declineInvalidTradesAndReturnAffectedSenders(listingID);
response.status(201).send({
success: true,
result: result,
idArray: peopleToDeclineArray,
});
});
Then adding the appropriate error handling, swapping out the incorrect use of HTTP 201 Created for HTTP 200 OK, and using json() instead of send(); you now get:
app.post("/declineTrades", async (request, response) => {
try {
const listingID = request.body.listingID;
const affectedSenderIDs = await declineInvalidTradesAndReturnAffectedSenders(listingID);
response.status(200).json({
success: true,
idArray: affectedSenderIDs, // consider renaming to affectedSenderIDs
});
} catch (error) {
console.error(`Failed to decline invalid trades for listing ${listingID}`, error);
if (!response.headersSent) {
response.status(500).json({
success: false,
errorCode: error.code || "unknown"
});
} else {
response.end(); // forcefully end corrupt response
}
}
});
Note: Even after all these changes, you are still missing any form of authentication. Consider swapping the HTTPS Event Function out for a Callable Function where this is handled for you but requires using a Firebase Client SDK.

Cloud Firestore: Query two collection [duplicate]

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

How to join multiple documents in a Cloud Firestore query?

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

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