I have an error in my school javascript project - javascript
I have multiple errors in my code. When I run the code, it gives an error saying that there is an unexpected identifier. Here is the full error, "SyntaxError: Unexpected identifier at /script.js:46:16". However, when I check through lines 46 through 16, I cant find any unclosed functions or methods. When I comment the if statement on line 46, it just gives an error on the other if statement. Can someone help me?
Heres the code:
function print(str){
console.log(str)
}
function farhToKelvin(far){
const cel = Math.floor(far / (9/5) - 32)
const kel = cel + 273
return kel
}
function farhToCelsius(far){
const cel = Math.floor(far / (9/5) - 32)
return cel
}
function convertToFarh(type, val){
type.toLowerCase()
val.toLowerCase()
if (type == "kelvin"){
return Math.floor(far / (9/5) - 32 - 273)
}
else if(type == "celsius"){
return Math.floor(far / (9/5) - 32)
}
}
while (farh != "exit"){
var farh = prompt("enter a farhanhite tempature: ")
var type = prompt("convert it to celsius, or kelvin")
type.toLowerCase()
if (type == "celsius"){
const c = farhToCelsius(farh)
var val = convertToFarh(c)
if (val > 50 or val == 50){
print("it is cold, you should wear a coat")
}
if (val > 50 or val == 50){
print("it is hot, you should wear a tank top")
}
}
else if(type == "kelvin"){
const k = farhToKelvin(farh)
var val = convertToFarh(k)
if (val > 50 or val == 50){
print("it is cold, you should wear a coat")
}
if (val > 50 or val == 50){
print("it is hot, you should wear a tank top")
}
}
}
if (val > 50 or val == 50){
In Javascript, instead of or, we use ||. If you have a similar problem again, you might want to take a look at What does this symbol mean in JavaScript?
change
if (val > 50 or val == 50)
to this
if (val > 50 || val == 50)
or better to this
if (val >= 50)
there are similar problems on line 50 and 60 and 64
you need to update them all.
logically line 46 and 50 are the same. based on you print message the line 50 should be
if (val > 50 ) but line 45 should be if ( val <= 50)
so you have both syntax and semantic problems in your code to address
Here's a complete list of the issues you have in your code:
Using or instead of || (as others have stated)
Using incorrect variable name in the convertToFarh function
Omitting type parameter when calling convertToFarh
Attempting to call String.toLowerCase() on a number variable
Misspelling fahrenheit
Using or instead of || (Logical OR)
In your code, I believe you are intending to indicate if (val > 50 || val == 50) { instead of using or as used in other programming languages.
Before:
if (val > 50 or val == 50){
print("it is cold, you should wear a coat")
}
if (val > 50 or val == 50){
print("it is hot, you should wear a tank top")
}
After:
if (val > 50 || val == 50){
print("it is cold, you should wear a coat")
}
if (val > 50 || val == 50){
print("it is hot, you should wear a tank top")
}
This logic also doesn't make sense. Perhaps you mean value < 50 in the first one and val >= 50 in the second?
You also repeat yourself whether you're converting to/from Kelvin or Celsius, so that code could be extracted out into its own function or just reduce the if..else blocks down to only affect the necessary variables and perform the comparison after these blocks.
Using incorrect variable name in convertToFarh function
In the convertToFarh function, you reference a variable named far, but there's no variable by that name. So you either mean to reference the val argument or you are trying to reference the fahr variable declared outside the function. In my code, I assume the former is the case val and rename it as follows:
function convertToFarh(type, val){
type.toLowerCase()
val.toLowerCase()
if (type == "kelvin"){
return Math.floor(val / (9/5) - 32 - 273)
}
else if(type == "celsius"){
return Math.floor(val / (9/5) - 32)
}
}
Omitting type parameter when calling convertToFarh
In both function calls to convertToFarh, you use the c or k variable as the value of the val parameter, but you don't indicate the type. I have fixed this to indicate the type for each part:
var val = convertToFarh("celsius", c);
var val = convertToFarh("kelvin", k);
Attempting to call String.toLowerCase() on a number variable
In the convertToFarh function, you are attempting to call the String.toLowerCase() method on a number type (val) which gives an error. In my code, I simply commented this out and confirmed it can safely be removed.
Misspelling fahrenheit
It might not seem like a big deal, but making sure variables have proper spelling helps when others are reviewing your code (whether bug-fixing or general code review). I have fixed function names, variable names, and any references to fahrenheit in your code to be the proper spelling. This includes:
"enter a fahrenheit temperature: "
function fahrToKelvin and function calls
function fahrToCelsius and function calls
function convertToFahr and function calls
The variable named farh to fahr
Function parameters named far were changed to val to avoid variable name collision
Full code
function print(str) {
console.log(str);
}
function fahrToKelvin(val) {
const cel = (val - 32) / (9 / 5);
return Math.floor(cel + 273.15);
}
function fahrToCelsius(val) {
const cel = Math.floor((val - 32) * 5 / 9);
return cel;
}
function convertToFahr(type, val) {
if (type == "kelvin") {
return Math.floor(val / (5 / 9) - 459.67);
} else if (type == "celsius") {
return Math.floor(val / (9 / 5) + 32);
}
}
var fahr = prompt("enter a fahrenheit tempature: ");
var type = prompt("convert it to celsius, or kelvin");
type = type.toLowerCase();
if (type == "celsius") {
const c = fahrToCelsius(fahr);
var val = convertToFahr("celsius", c);
if (val < 50) {
print("it is cold, you should wear a coat");
}
if (val >= 50) {
print("it is hot, you should wear a tank top");
}
} else if (type == "kelvin") {
const k = fahrToKelvin(fahr);
var val = convertToFahr("kelvin", k);
if (val < 50) {
print("it is cold, you should wear a coat");
}
if (val >= 50) {
print("it is hot, you should wear a tank top");
}
}
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I am trying to make a dice game point counter where you are awarded points based on how close your guess of what you thought the number was going to be to what the number rolled is. My current code looks like this function continueL(e){ if (e.keyCode == Keyboard.letter('L')){ add(copter); var evorod = readInt("What number do you think it's going to be? You are guessing "); println("Please click the die to roll a number"); mouseClickMethod(contin); } } function contin(e){ var num = Randomizer.nextInt(1,12); println("The number rolled is.... " + num); var numText = new Text("The number rolled is...." + num, "20pt Arial"); numText.setPosition(50, 200); numText.setColor(Color.red); add(numText); if (num == evorod){ println("Congrats! You Win! Here is 100 points"); } else { if(num == evorod - 1 || num == evorod + 1){ println("So close! Here is 80 points!"); } else { if(num == evorod - 2 || num == evorod + 2){ println("Almost got it. Take 60 points!"); } else { if(num == evorod - 3 || num == evorod + 3){ println("Nice try. Take 40 points!"); } else { if(num == evorod - 4 || num == evorod + 4){ println("Whoops... maybe next time? Take 20 points"); } else { println("Better luck next time."); } } } } } remove(copter); } But it only displays the final else no matter what your guess was vs the number rolled. edit: evorod is a global variable
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I was trying to work on this hackerrank problem. Every student receives a grade in the inclusive range from 0-100 to . Any less than 38 is a failing grade. Sam is a professor at the university and likes to round each student's according to these rules: If the difference between grade the and the next multiple of 5 is less than 3, round up to the next multiple of 5. If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade. Given the initial value of for each of Sam's students, write code to automate the rounding process. My code is: function gradingStudents(grades) { const roundup = y => y + 1; { if ( grades < 38 || grades % 5 === 0) return grades; else if ( grades % 5 < 4 && grades % 5 !== 0) return roundup(grades); } { if (roundup % 5 === 0) return roundup; else { gradingStudents(roundup + 1) } } } gradingStudents(38) // -> 39 I tried to use Math.ceil(grades) inside the variable roundup but output didnt change. So, when you invoke the function with a number that is not before a multiple of 5 (e.g. 43) it returns the proceeding number. However, if it is the number before a multiple of 5 it gives a range error. "maximum call stack size reached." As far as I got, the code doesnt proceed to the second part. Even if it did, I am not sure if it would fetch the current value of the function roundup when dealing with if statements in the second block. What do I dont get in here? Also, this is actually meant for an array output but since I am a beginner I am pretty much okay with this one for the start as well :D .
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Try this: function gradingStudents(grades) { //input: 43 var finalGrade; if(grade < 38) return grades; else{ var gradeDif = grades % 5; //3 if(gradeDif > 3){ return grades; } else { return grades + (5 - gradeDif); //Output: 45 } } }
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my solution: function gradingStudents(grades) { return grades.map(function(grade) { return (grade >= 38 && grade % 5 >= 3) ? grade + 5 - (grade % 5) : grade; }); }
How NOT to break a function/loop on returning a value (Js)
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You need to use continue instead of return in the last else of your main if/else block on line 15
javascript value coming up empty not sure how to handle it
function updategeneral() { //tmp = "fine_" + tmp + "_"; var actual = doc.findItem("1speed").value; var posted = doc.findItem("2speed").value; amt = ""; if (1speed != "" && 2speed != "") { var a = 1 * 1speed; var b = 1 * 2speed; if (a - b <= 9) { alert(amt); amt = doc.getDefault("general_spb_1_to_15"); } else if (a - b <= 15) { amt = doc.getDefault("general_spb_16_to_25"); } else if (a - b <= 25) { amt = doc.getDefault("general_spb_15_to_19"); } else if (a - b <= 29) { amt = doc.getDefault("general_spb_26+"); } doc.findItem("mcare_amount").value = amt; alert(doc.findItem("mcare_amount").value = amt); } } Default values are: general_spb_1_to_15=30.00 || general_spb_16_to_25=40.00 || general_spb_26+=50.00 My problem is when amt is empty or 0 it is always going to general_spb_1_to_15=30.00. I am not sure how to fix this- can someone please help? The values that I am using are 1speed = 20 and 2speed = 25 which is negative or empty.
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Math calculation issue with Javascript
I am having a bit of trouble with a few math calculation in javascript. The goal of this calculation is to generate a value when the user clicks on a text field. For example: 1 Kilogram costs 32 cents to ship to America and the user wants to find out what 10KG will cost him which is $3.20. For this I have the following piece of javascript code: function calculate(num) { var weight = document.getElementById('weight'+num); var price = document.getElementById('price'+num); if(num == undefined || num == '' || num.length <= 0 || isNaN(weight.value) || isNaN(price.value)) return false; if(num == 1) multiplyBy = 0.32; if(num == 2) multiplyBy = 0.14; if(num == 3) multiplyBy = 0.24; if(num == 4) multiplyBy = 0.53; var sum = parseInt(document.getElementById('weight'+num).value) * multiplyBy; if(isNaN(sum)) return false; price.value = sum; } The above code works perfectly fine, however when I reverse the process (someone has $3.20 and wants to find out how much KG he/she can ship with that (which is 10KG) the script returns: 9.375KG The following code is used for this calculation: function reverse(num) { var weight = document.getElementById('weight'+num); var price = document.getElementById('price'+num); if(num == undefined || num == '' || num.length <= 0 || isNaN(weight.value) || isNaN(price.value)) return false; if(num == 1) divideBy = 0.32; if(num == 2) divideBy = 0.14; if(num == 3) divideBy = 0.24; if(num == 4) divideBy = 0.53; var sum = parseInt(document.getElementById('price'+num).value) / divideBy; if(isNaN(sum)) return false; weight.value = sum; } I honestly don't grasp why it is failing, It would be much appreciated if someone could help me out with this.
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