Develop Reference

Is it possible to call to APIs inside a react-router loader function

I'd like to know if it's possible to make 2 API calls inside a loader function if I am using react-router 6. My ideas was to create an object based on these 2 calls and destruct the object in the rendering component like this:
function MainComponent (){
const {data , reservation} = useRouteLoaderData('room-details');
..
..
}
export default MainComponent;
export async function loader({request, params}) {
const id = params.roomId;
const response = await fetch ('http://localhost:8080/rooms/' + id);
const response2 = await fetch('http://localhost:8080/rooms/reservation/' + id)
const megaResponse = {
data: response, //i tried data:{respose} It ain't work
reservation: response2,
};
if (!response.ok) {
throw json({message: 'Something Wrong'}, {status: 500});
}
else {
return megaResponse;
}
}
But i have no success output.
I'd really want to make these 2 call in one place, otherwise I will have to use useEffect in a child component. Not a good Idea I think.
Thanks

I suspect you are not returning the unpacked response, i.e. JSON. I suggest surrounding the asynchronous code in a try/catch and simply try to process the requests/responses. Unpack the JSON value from the response objects. Since it doesn't appear the requests are dependent on one another I recommend loading them into an array of Promises that can be run concurrently and awaited as a whole. If during any part of the processing a Promise is rejected or an exception thrown, the catch block will return the JSON error response to the UI, otherwise, the { data, reservation } object is returned.
const loader = async ({ request, params }) => {
const { roomId } = params;
try {
const [data, reservation] = await Promise.all([
fetch("http://localhost:8080/rooms/" + roomId),
fetch("http://localhost:8080/rooms/reservaton/" + roomId)
]).then((responses) => responses.map((response) => response.json()));
return { data, reservation };
} catch {
throw json({ message: "Something Wrong" }, { status: 500 });
}
};

I found the solution, I tried it and it worked. It is as follow:
function MainComponent (){
const [data , reservation] = useRouteLoaderData('room-details');
..
..
}
export default MainComponent;
export async function loader({request, params}) {
const id = params.roomId;
return Promise.all([
fetch ('http://localhost:8080/rooms/' + id),
fetch('http://localhost:8080/rooms/reservation/' + id)
])
.then(
([data, reservation]) =>
Promise.all([data.json(), reservation.json()]),
error => {throw json({message: 'Something Wrong'}, {status: 500});}
)
.then(([data, reservation]) => {
return [data, reservation];
});
}
Thanks

Firebase Firestore return QuerySnapshot

I just started to play with the firebase cloud function and firestore but when I'm using firestore inside the firebase cloud function (as below code) it's return and QuerySnapshot instead of return data. If anyone has got this issue before and solved it already then tell me. It would help me to resolve this issue too.
Thanks.
export async function allRestaurants(req: Request, res: Response) {
try {
// const { id } = req.params
const restaurantsRef = admin.firestore().collection('restaurants');
const snapshot = await restaurantsRef.get();
console.log(">>>>>>>>>", snapshot);
return res.status(200).send({ data: { restaurants: snapshot } })
} catch (err) {
return handleError(res, err)
}
}

It is normal that you get a QuerySnapshot, since the get() method returns a Promise that resolves with a QuerySnapshot.
It's up to you to generate the content you want to send back to the Cloud Function consumer.
For example, you can use the forEach() method to loop over the QuerySnapshot, or, as shown below, use the docs array.
export async function allRestaurants(req: Request, res: Response) {
try {
// const { id } = req.params
const restaurantsRef = admin.firestore().collection('restaurants');
const snapshot = await restaurantsRef.get();
const responseContent = snapshot.docs.map(doc => doc.data());
return res.status(200).send({ data: { restaurants: responseContent } })
} catch (err) {
return handleError(res, err)
}
}

Javascript Async/Await not returning, more like Await_Forever

I started started a node environment based off express, my issue is more with Promise.
I've written a module that has an http call (axios) and i'm using async/await in order to receive the response and handle it, everything is working great in the module in terms of flow and i'm able to execute console.log()s, yet my returned value isn't coming back to index.js.
index.js
works great and my readFile() function works great.
const getDistance = require('./actions/getDistance');
app.post('/find-closest', async (req, res) =>{
try{
let address = req.body.address;
let data = await readFile('src/agents.json');
return res.json(getDistance(JSON.parse(data),address));
} catch (e) {
console.log('Error');
console.log(e);
return res.json(e);
}
});
getDistance.js
module.exports = function (agents, origins) {
let destinations = '&destinations=' + agents.map(agent => agent.address).join('|');
const getDistances = async () => {
try {
return await axios.get(url + origins + destinations + apiKey)
} catch (error) {
console.error(error)
}
};
const setDistancesResponse = async () => {
const distances = await getDistances()
console.log('test',distances.data); //<=this returns
return 'baboom'; //this is not returned through
};
setDistancesResponse();
};
I am expecting my endpoint to return a JSON response of the string "baboom".
What am I doing wrong here?
Thanks, Bud

Your exported getDistance function doesn't return anything. You are probably looking for
module.exports = async function(agents, origins) {
const destinations = '&destinations=' + agents.map(agent => agent.address).join('|');
const distances = await axios.get(url + origins + destinations + apiKey)
console.log('test',distances.data); // this logs something
return 'baboom';
};
and given that this now returns a promise, you will have to wait for the result value:
app.post('/find-closest', async (req, res) =>{
try{
let address = req.body.address;
let data = await readFile('src/agents.json');
return res.json(await getDistance(JSON.parse(data), address));
// ^^^^^
} catch (e) {
console.error('Error', e);
return res.json(e);
}
});

I think you misses return value. Try this:
return setDistancesResponse();

Get data using await async without try catch

I am trying to use await-async without try-catch for this:
const getUsers = async (reject, time) => (
new Promise((resolve, reject) => {
setTimeout(() => {
if (reject) {
reject(....)
}
resolve(.....);
}, time);
})
);
module.exports = {
getUsers ,
};
With try-catch block it looks like this:
const { getUsers } = require('./users');
const users = async () => {
try {
const value = await getUsers(1000, false);
.....
} catch (error) {
.....
}
}
users();
How can I write the same code without using the try-catch block?

Using the promise functions then-catch to make the process simpler I use this utils :
// utils.js
const utils = promise => (
promise
.then(data => ({ data, error: null }))
.catch(error => ({ error, data: null }))
);
module.exports = utils;
And then
const { getUsers } = require('./api');
const utils = require('./utils');
const users = async () => {
const { error, data } = await utils(getUsers(2000, false));
if (!error) {
console.info(data);
return;
}
console.error(error);
}
users();
Without using the try-catch block I got the same output, this way makes it better to understand the code.

In Extension to L Y E S - C H I O U K H's Answer:
The Utils Function is actually correct but, make sure to add the return keyword before the promise as shown down below:
// utils.js
const utils = promise => (
return promise
.then(data => { [data, null]; })
.catch(error => { [null, error]; });
);
module.exports = utils;
When Calling in Main Code:
let resonse, error; // any variable name is fine make sure there is one for error and the response
[response, error] = await utils(any_function()); // Make sure that inside the tuple, response is first and error is last like: [response, error].
if (error) console.log(error);
// -- Do Whatever with the Response -- //
Using My Method Would Give you Benefits like:
Your Own Variable Names.
Not Running into Type Safety issues when using Typescript.
Good Reason to Strong Type your code.
Personally, I have been using this in my code lately, and has reduced some many headaches, my code is cleaner, I don't have to stick with the same variable names, especially when working on a large codebase.
Happy Coding :)
See Ya!

If you have a valid default for the error case you can use the catch method on the getUsers promise and then await a promise whose error will be handled
const users = async () => {
const value = await getUsers(1000, false).catch(e => null);
}
While this approach should work it should be noted that this may mask the case when getUsers returns null vs when it raises an error, and you will still need to check for the null or get a null access error. All in all I would stick with the try { .. } catch (e) { ... } for most casses

A package I found called await-to-js can also help it.
import to from 'await-to-js';
const [err, users] = await to(getUsers());
if(err) doSomething();
The idea is like Lyes CHIOUKH's method, just a wrapper. Copied the source code here.
/**
* #param { Promise } promise
* #param { Object= } errorExt - Additional Information you can pass to the err object
* #return { Promise }
*/
export function to<T, U = Error> (
promise: Promise<T>,
errorExt?: object
): Promise<[U | null, T | undefined]> {
return promise
.then<[null, T]>((data: T) => [null, data])
.catch<[U, undefined]>((err: U) => {
if (errorExt) {
Object.assign(err, errorExt);
}
return [err, undefined];
});
}
export default to;

If you have such above single line async/await function, then this would have been clean code for you:
const getUsers = async (time, shouldReject=false) => {
return new Promise((resolve, reject) => {
setTimeout(() => {
if (shouldReject) {
reject(Error('Rejected...'));
} else {
resolve(["User1", "User2"]);
}
}, time);
});
}
const userOperation = users => {
console.log("Operating user", users);
}
// Example 1, pass
getUsers(100)
.then(users => userOperation(users))
.catch(e => console.log(e.message));
// Example 2, rejected
getUsers(100, true)
.then(users => userOperation(users))
.catch(e => console.log(e.message));
And for multiple await in a single async function, it would good to have try/catch block as below:
const users = async () => {
try {
const value = await getUsers(1000, false);
const value1 = await getUsers2(1000, false);
...
} catch (error) {
...
}
}

Save Async/Await response on a variable

I am trying to understand async calls using async/await and try/catch.
In the example below, how can I save my successful response to a variable that can be utilized throughout the rest of the code?
const axios = require('axios');
const users = 'http://localhost:3000/users';
const asyncExample = async () =>{
try {
const data = await axios(users);
console.log(data); //200
}
catch (err) {
console.log(err);
}
};
//Save response on a variable
const globalData = asyncExample();
console.log(globalData) //Promise { <pending> }

1) Return something from your asyncExample function
const asyncExample = async () => {
const result = await axios(users)
return result
}
2) Call that function and handle its returned Promise:
;(async () => {
const users = await asyncExample()
console.log(users)
})()
Here's why should you handle it like this:
You can't do top-level await (there's a proposal for it though);
await must exist within an async function.
However I must point out that your original example doesn't need async/await
at all; Since axios already returns a Promise you can simply do:
const asyncExample = () => {
return axios(users)
}
const users = await asyncExample()

try..catch creates a new block scope. Use let to define data before try..catch instead of const, return data from asyncExample function call
(async() => {
const users = 123;
const asyncExample = async() => {
let data;
try {
data = await Promise.resolve(users);
} catch (err) {
console.log(err);
}
return data;
};
//Save response on a variable
const globalData = await asyncExample();
console.log(globalData);
// return globalData;
})();

I had same issue with you and found this post. After 2 days of trying I finally found a simple solution.
According to the document of JS, an async function will only return a Promise object instead of value. To access the response of Promise, you have to use .then()method or await which can return the resulting object of Promise is instead of Promise itself.
To change variables from await, you have access and change the variable you want to assign within the async function instead of return from it.
//Save response on a variable
var globalData;
const asyncExample = async () =>{
try {
const data = await axios(users);
globalData = data; // this will change globalData
console.log(data); //200
}
catch (err) {
console.log(err);
}
};
asyncExample();
But if you do this, you may get an undefined output.
asyncExample();
console.log(globalData) //undefined
Since asyncExample() is an async function, when console.log is called, asyncExample() has not finished yet, so globalData is still not assigned. The following code will call console.log after asyncExample() was done.
const show = async () => {
await asyncExample();
console.log(globalData);
}
show();

Because the events are happening asynchronously you need to tie in a callback/promise. I'm going to assume it returns a promise.
const axios = require('axios');
const users = 'http://localhost:3000/users';
const asyncExample = async () =>{
try {
const data = await axios(users);
console.log(data); //200
}
catch (err) {
console.log(err);
}
};
//Save response on a variable
const globalData = asyncExample().then( (success, err) => {
if (err) { console.error(err); }
console.log(success)
}

Just use a callback/promise (cascading programming):
axios(users).then(function(response) {
const globalData = response;
console.log(globalData)
});