CRUD in React with Firestore for data in an array - javascript

It's my first time using Firebase as my backend and I can successfully access and fetch the data in my React App, but I have problem with CRUD operations.
Example of my collection:
- closets (collection)
- unique ID (specific user)
- name (string)
- shorts (array of objects - map)
- 0 (first object in array)
- name (string)
- image (string)
.........
.........
I can read all the files, but I can't update or delete them. I need to access all data in arrays (e.g shorts array based on example above) and be able to change name or remove the whole object.
Using custom hook to map the data:
export const useGetData = () => {
const [documents, setDocuments] = React.useState([]);
const db = firebase.firestore();
React.useEffect(() => {
db.collection("closets")
.get()
.then((querySnapshot) => {
let arr = [];
querySnapshot.docs.map((doc) =>
arr.push({ id: doc.id, name: doc.data() })
);
setDocuments(arr);
});
}, [db]);
return [documents];
};
Here I am trying to update name in dress array
const [nameValue, setNameValue] = React.useState("");
const db = firebase.firestore();
const getNameValue = (event) => {
setNameValue(event.target.value);
};
const updateValue = () => {
db.collection("closets")
.doc(doc)
.update({
"dress.name": nameValue
})
.then(function () {
console.log("Document successfully updated!");
})
.catch(function (error) {
console.error("Error updating document: ", error);
});
};
return (
<>
<input onBlur={getNameValue} type="text" />
<button onClick={updateValue}>Update</button>
</>
Getting error s.indexOf is not a function
I am not really sure how achieve updating this specific string in object, which is part of array.
Here is created example in codesandbox, for better understanding:
https://codesandbox.io/s/second-leeway-test-forked-ii0p6

You can update the array using:
firebase.firestore.FieldValue.arrayUnion(elem)
firebase.firestore.FieldValue.arrayRemove(elem)
See: https://firebase.google.com/docs/firestore/manage-data/add-data#update_elements_in_an_array
To update an element you must first remove it from the array and then add the modified one.
However, I suggest you model the database through subcollections, so as to simplify their management, like this:
- closets (collection)
- unique ID (doc)
- name (string)
- shorts (collection)
- short (doc)
- name (string)
- image (string)
See: https://firebase.google.com/docs/firestore/data-model#subcollections

Related

How to get data from 2 collection in firebase at a time?(similar to aggregate lookup in MongoDB) [duplicate]

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

Cloud Firestore: Query two collection [duplicate]

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

How to get the unique id (key) of a document in Firebase database collection?

I am trying to fetch the documents of a collection in my React-Native app but I dont know how to fetch them by ID (key).
P.S: I dont have any field called unique id or id inside the document but as I have understood, the unique id is the auto-generated key when I create a document which stands as the name of that document (20 characters id).
This is how I fetch all the fields inside a document:
var ref = firebase.firestore().collection('discounts')
.orderBy('rest_id')
EDIT:
getDiscounts = () => {
try {
this.setState({
loading: true
})
var ref = firebase.firestore().collection('discounts')
.orderBy('rest_id')
.limit(this.state.limit)
ref.onSnapshot((querySnapshot => {
var discounts = querySnapshot.docs.map(document => document.data());
var lastVisibleDiscount = discounts[discounts.length - 1].rest_id;
this.setState({
discounts: discounts,
lastVisibleDiscount: lastVisibleDiscount,
loading: false,
});
}));
}
catch (error) {
console.log(error);
}
}
To print the keys of the documents in the collection in the order of the value of their rest_id field, you can do something like this:
firebase.firestore().collection("discounts").orderBy('rest_id').get().then(function(querySnapshot) {
querySnapshot.forEach(function(doc) {
console.log(doc.id);
});
});
This is an almost literal copy of the code in the documentation on getting all documents from a collection, so I recommend spending some time there.
You can use (using await/async)
const ref = await ref.get()
It will have an array called docs that you can map over to get the id and data of the document:
const data = ref.docs.map(doc => {return {id: doc.id, data: doc.data()} })

How can I query a fire store sub-collection with angular?

I am trying to query a Firestore sub collection in an ionic 4 app/angular app. My database looks as follows people(id) ----> tasks(id)
{ description : this is a description about a cat,<br>
title: this is a cat <br>
category: cat }
I am using a Firestore function to query all of the data in the collection. This is what the Firestore function looks like:
import * as functions from 'firebase-functions';
import * as admin from 'firebase-admin'
admin.initializeApp()
export const getFeed = functions.https.onCall(async (req,res) =>{
const docs = await
admin.firestore().collection('people').limit(5).get()
return docs.docs.map(doc => {
return {
postID: doc.id,
...doc.data()
}
})
})
the typescript home.ts file looks like this :
const getFeed = this.aff.httpsCallable('getFeed')
this.posts = getFeed({}).subscribe(data=> {
console.log(data)
// this.posts = data
})
}
I've tried to use the array-contains option to query, but it doesn't
work. The array shows up empty on the console.
export const getFeed = functions.https.onCall(async (req,res) =>{
const docs = await
admin.firestore().collection('people').where("category",
"array-
contains", "cat").limit(5).get()
return docs.docs.map(doc => {
return {
postID: doc.id,
...doc.data()
}
})
})
It's not very clear from your question, but it looks like the category field of your database isn't actually a list type field. array-contains only works if the value is a list, not if it's just a single string value. If it's just a string, then use a == filter on it.
I have found workaround by adopting array field type instead of subcollection.
Here is an example of my code:
var coll = this.firestore.collection('credentials', ref => ref.where('tags', 'array-contains-any', ['agile']).orderBy('shortName')); // selects part of collection where roomId = roomStripped, sorted by name
return coll.snapshotChanges();
I have main collection called credentials, and a list of tags in each document.

How to join multiple documents in a Cloud Firestore query?

I have a Cloud Firestore DB with the following structure:
users
[uid]
name: "Test User"
posts
[id]
content: "Just some test post."
timestamp: (Dec. 22, 2017)
uid: [uid]
There is more data present in the actual DB, the above just illustrates the collection/document/field structure.
I have a view in my web app where I'm displaying posts and would like to display the name of the user who posted. I'm using the below query to fetch the posts:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
const postDocs = docSnaps.docs;
for (let i in postDocs) {
loadedPosts[postDocs[i].id] = postDocs[i].data();
}
});
// Render loadedPosts later
What I want to do is query the user object by the uid stored in the post's uid field, and add the user's name field into the corresponding loadedPosts object. If I was only loading one post at a time this would be no problem, just wait for the query to come back with an object and in the .then() function make another query to the user document, and so on.
However because I'm getting multiple post documents at once, I'm having a hard time figuring out how to map the correct user to the correct post after calling .get() on each post's user/[uid] document due to the asynchronous way they return.
Can anyone think of an elegant solution to this issue?
It seems fairly simple to me:
let loadedPosts = {};
posts = db.collection('posts')
.orderBy('timestamp', 'desc')
.limit(3);
posts.get()
.then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
db.collection('users').child(doc.data().uid).get().then((userDoc) => {
loadedPosts[doc.id].userName = userDoc.data().name;
});
})
});
If you want to prevent loading a user multiple times, you can cache the user data client side. In that case I'd recommend factoring the user-loading code into a helper function. But it'll be a variation of the above.
I would do 1 user doc call and the needed posts call.
let users = {} ;
let loadedPosts = {};
db.collection('users').get().then((results) => {
results.forEach((doc) => {
users[doc.id] = doc.data();
});
posts = db.collection('posts').orderBy('timestamp', 'desc').limit(3);
posts.get().then((docSnaps) => {
docSnaps.forEach((doc) => {
loadedPosts[doc.id] = doc.data();
loadedPosts[doc.id].userName = users[doc.data().uid].name;
});
});
After trying multiple solution I get it done with RXJS combineLatest, take operator. Using map function we can combine result.
Might not be an optimum solution but here its solve your problem.
combineLatest(
this.firestore.collection('Collection1').snapshotChanges(),
this.firestore.collection('Collection2').snapshotChanges(),
//In collection 2 we have document with reference id of collection 1
)
.pipe(
take(1),
).subscribe(
([dataFromCollection1, dataFromCollection2]) => {
this.dataofCollection1 = dataFromCollection1.map((data) => {
return {
id: data.payload.doc.id,
...data.payload.doc.data() as {},
}
as IdataFromCollection1;
});
this.dataofCollection2 = dataFromCollection2.map((data2) => {
return {
id: data2.payload.doc.id,
...data2.payload.doc.data() as {},
}
as IdataFromCollection2;
});
console.log(this.dataofCollection2, 'all feeess');
const mergeDataFromCollection =
this.dataofCollection1.map(itm => ({
payment: [this.dataofCollection2.find((item) => (item.RefId === itm.id))],
...itm
}))
console.log(mergeDataFromCollection, 'all data');
},
my solution as below.
Concept: You know user id you want to get information, in your posts list, you can request user document and save it as promise in your post item. after promise resolve then you get user information.
Note: i do not test below code, but it is simplify version of my code.
let posts: Observable<{}[]>; // you can display in HTML directly with | async tag
this.posts = this.listenPosts()
.map( posts => {
posts.forEach( post => {
post.promise = this.getUserDoc( post.uid )
.then( (doc: DocumentSnapshot) => {
post.userName = doc.data().name;
});
}); // end forEach
return posts;
});
// normally, i keep in provider
listenPosts(): Observable<any> {
let fsPath = 'posts';
return this.afDb.collection( fsPath ).valueChanges();
}
// to get the document according the user uid
getUserDoc( uid: string ): Promise<any> {
let fsPath = 'users/' + uid;
return this.afDb.doc( fsPath ).ref.get();
}
Note: afDb: AngularFirestore it is initialize in constructor (by angularFire lib)
If you want to join observables instead of promises, use combineLatest. Here is an example joining a user document to a post document:
getPosts(): Observable<Post[]> {
let data: any;
return this.afs.collection<Post>('posts').valueChanges().pipe(
switchMap((r: any[]) => {
data = r;
const docs = r.map(
(d: any) => this.afs.doc<any>(`users/${d.user}`).valueChanges()
);
return combineLatest(docs).pipe(
map((arr: any) => arr.reduce((acc: any, cur: any) => [acc].concat(cur)))
);
}),
map((d: any) => {
let i = 0;
return d.map(
(doc: any) => {
const t = { ...data[i], user: doc };
++i;
return t;
}
);
})
);
}
This example joins each document in a collection, but you could simplify this if you wanted to just join one single document to another.
This assumes your post document has a user variable with the userId of the document.
J

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