I have question if is it even possible.
I have contact.php home.php and porfolio.php .
In every single site I have exacly same header (include "header.php") and only what I need is change one h1. I mean on every site have different title of h1. Is there any possible way, to change on every site html code differently ?
Like every site have same header.php but every time different h1..
Or should I make like "one half of code.php" .. CHANGEABLE CONTENT .. "second half of code.php.
Or should I do it in javascript ? like onload function and if site is contact.php then change h1.innerHTML on "".. ?
<body>
<?php include "./components/header.php"; ?>
</body>
I'm pretty sure someone on stackoverflow have answered a similar question but you can do something like
<body>
<?php
$h1Content = "put your desired h1 content here";
include "./components/header.php";
?>
</body>
Then in your header.php, do
<h1><?php echo $h1Content ?></h1>
You can also use an isset to check or set a default value
<h1><?php echo isset($h1Content)? $h1Content : 'Default Value' ?></h1>
you can achieve this easily. All you have to do is to assign header value to an variable and then use that variable in your header file.
//header.php file
<h1><?php echo $mainHeader; ?></h1>
and then before you inject the header you have to init that value on each site
<?php $mainHeader = 'Hello world'; ?>
<body>
<?php include "./components/header.php"; ?>
</body>
Related
What is the easiest way to run Javascript code inside PHP, preferably without using external libraries? Specifically, I need the innerHTML of a div to change depending on some calculations performed using the user's form inputs that were captured earlier with $_POST in a separate form. How can I get the following JS code to run inside the following PHP code? (My most basic attempt was using echo command, but it's throwing up errors)
HTML:
<div id="output">
</div><!--#output -->
PHP (desired JS included):
if (count($valid_locations)<$num_of_locations){
echo '<script>const output = document.querySelector("#output");</script>;';
echo '<script>output.innerHTML = "<div class="alert-danger"> Trip unable to be created. Please adjust the budget/number of travelers/duration etc.</div>;";</script>';
}else{
createTrip($trips);
}
Right now, the IF condition is True and the code does run, but it echos ";" for some reason. I have verified that the condition is met and it runs by adding in a simple echo "this runs";, which did appear upon refresh. I just don't understand why it's outputting to the default echo space and the script isnt running to change the innerHTML of the output div. Is this even possible to do with PHP? If so, what's the best way? (doesn't need to be secure, won't be used publicly). I've heard of a few things such as ajax but it seems so complicated. Any explanations on stuff like that specific to this scenario would be greatly appreciated.
Following up on the comments, you don't need JS to achieve what you want. You could just use PHP
<?php
$output = null;
if (!empty($_POST)) {
//...
//... do stuff
//...
if (count($valid_locations)<$num_of_locations){
$output = 'Error occured - bla bla bla';
}
}
?>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php if (isset($output)) {?>
<div id="output"><?= $output; ?></div>
<?php } ?>
</body>
</html>
I created a website in WordPress (Website: Link) using this theme.
I would like to know, how can I add a [timeline-express] widget after the image slider?
(I tried to modify idyllic-functions.php, using:
...
</div> <!-- end .main-slider -->';
echo $idyllic_category_sliders_display;
echo add_filter( 'widget_text', 'timeline-express');
...
,but the site crashes.)
Open this file: idyllic/inc/front-page/front-page-features.php and add this following line on line 34:
<?php echo do_shortcode('[timeline-express]'); ?>
Just above this line:
<div class="our-feature-box <?php echo esc_attr($feature_box_class); ?>">
So, your updated code will be also follows:
<?php echo do_shortcode('[timeline-express]'); ?>
<div class="our-feature-box <?php echo esc_attr($feature_box_class); ?>">
Note that, it's always a good practice to create a child theme, copy file/template to the child theme directory, and then modify your codes. Otherwise, you will lose your modified codes once the theme is updated.
PS: please try to follow what #tacoshy mentioned in his comment while asking questions in stackoverflow.
So my main page loads other php pages into it with click of a button so it can be a single page website without having to load all the content at once.
index.php
<?php
session_start();
?>
<head>
$('#btnPetShop').one( "click", function(){
$( "#page_shop" ).load( "shop.php" );
});
</head>
<body>
<?php
echo session_status();/----Always returns 1, no matter if logged in or not----/
if(isset($_SESSION['admin']))
{
if($_SESSION['admin']==1)
{
/----this part works, I am logged in as admin----/
}
}
?>
<div id="page_shop"></div>
</body>
shop.php
<?php
if(isset($_SESSION['admin']))
{
if($_SESSION['admin']==1)
{
}
else{}
}
else{} <----I end up here as if $_SESSION['admin'] is not set----/
/----code entered here loads fine----/
?>
The idea is to make a delete and edit button (if you are logged in as admin) on every article in shop.php.
Problem is that $_SESSION['admin'] is recognized on index.php, but not inside shop.php
I tried typing the content of shop.php directly into and it works, the problem is that i want it to load with a click of a button.
Where ever ( in any PHP page) if you want to use any Session variable then you have to first declare session_start(); so, in your case if you have $_SESSION['admin']="User1234" on index.php and if you want to use value of $_SESSION['admin'] in shop.php then you have to again declare session_satart(); and then use it. For example, If let consider that index.php has session variable $_SESSION['admin']="User1234" and now you want to print "Welcome User1234" on shop.php then you can do it as shown below.
index.php
<?php
session_start();
$_SESSION['admin'] = "User1234";
?>
Shop.php
<?php
session_start();
echo "Welcome, ". $_SESSION['admin']
?>
Output:
Welcome, User1234
You need to add session_start(); in each page that needs access to the session data.
See: http://php.net/manual/en/function.session-start.php
EDIT
Since the solution mentioned in my original answer does not work for you and session_status() returns 1 in your code, it means sessions are enabled on your server. There is only one thing left which could explain that your sessions are lost:
You are loading shop.php with an AJAX request, is the URL exactly in the same domain as index.php? Try to add the full path before shop.php to see if this solves the issue.
Just to be clear, if your index.php runs on http://localhost/test/index.php, your new code will be:
$( "#page_shop" ).load( "http://localhost/test/shop.php" );
Well okay, I feel dumb... I found the solution.
I had this as a script
$('#btn_logout').click(function(){
<?php session_destroy();?>
});
This is a big no no and if you do this you should be ashamed
I am trying to add an horizontal ad in between the content. An example article of my website is: http://articlefirm.com/biography/penny-taylor-age-net-worth-biography-twitter.html. I would like the ad to come somewhere inside the content.
The website is on YII framework. Here's the content code:
<?php echo $page->detail; ?>
Please let me know how could I add script inside the above given code.
you can change your main.php layout and add the code for show the ads as you like this way
if you need pass some php vars to the main.php layout
a simple way is add property to your controller
class YourController extends CController {
public $myParam;
then assign in your action the values you need for params
eg:
$this->myParam ='my_adv';
and then in your layout you can simple
<?php echo $this->myParam; ?>
otherwise if you don't need pass params form controller/action
you can simply change you views/layouts/main.php
adding the conde you need
<?php
echo 'here i cand add the adv i need before the view content';
?>
<?php echo $content; ?>
I have a giant image/button in my header on every page that leads my users to a form they fill out, I want to remove that image/button on the form page itself, hoping to use css. I'm using wordpress, but this form is not a wordpress page, its located in a different directory and its called index.php. How do I go about hiding the image?
Within index.php, the first few lines there is a call to get_header() which loads the header so i thought to put this bit of code right after it:
<?php if ( is_page('mysite.org/the-index-page/') ) { ?>
<style type = "text/css">.order-btn { display: none; }</style>
<?php } ?>
however nothing happens. Am I doing this right or is there a better way to do it?
A better solution is probably to remove the button from that specific page. It sounds as if the button markup is inside your header.php file. You could try this:
<?php if ( !is_page( 'the-index-page' ) ) : ?>
// Button markup here
<?php endif; ?>
And if it's not working, this should:
$url = $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
<?php if ( !( $url == 'mysite.org/the-index-page/' ) ) : ?>
// Button markup here
<?php endif; ?>