Develop Reference

How to get url parameters with same name from URL in js?

For example I have this url
https://www.test.com/test.html?categoryid=4&test1=12&test2=65&brand[0]=val1&brand[1]=val2&test3=15
Now how do I get value of brand[0]=val1&brand[1]=val2 but it can be any number of there in the url maybe brand[2],brand[3] etc... or none url can be without this parameter
I need to get if brand parameter is in url and if yes then I need to get all which are availabe in the url
Any help would be great!

So you don't really know if there would be parameters or not so that's why I can propose this solution right here it will parse all your parameters anyways and stack them in the config JSON in case there is no parameters config would be empty then on your DOMloaded event you can handle the cases as you want
const config = {};
const loadConfig = () => {
const urlQuery = new URLSearchParams(window.location.search);
urlQuery.forEach((e, k) => {
config[k] = e;
});
};
const onLoadEvent = () => {
console.log(config) // should contain all the query string params.
}

How to get nested query string parameter

The use case is to land on a page with a URL looking like this -
http://localhost:3000/track?url=https://somewebsite.com/?968061242&lang=EN&sign=daff4be265096eb31aca5c986ac51c6c&source=api_wrapper
I tried the following to get the query params,
let search = window.location.search;
let params = new URLSearchParams(search);
let resp = params.get('url');
console.log("resp => ", resp);
but the output I get is only up to https://somewebsite.com/?968061242
How I can also get the nested params as part of the same get method call?

Use urlencoding api of JS
Example:
const url = `http://localhost:3000/track?url=${encodeURIComponent('https://somewebsite.com/?968061242&lang=EN&sign=daff4be265096eb31aca5c986ac51c6c&source=api_wrapper')}`
let search = new URL(url).search;
let params = new URLSearchParams(search);
let resp = params.get('url');

Best way to add query param to all navigations

I am looking for a solution to add query param on each URL after navigation using WebDriverIO.
For example:
Base URL: https://www.google.com/?block=true
When I click a button on the page loaded from the above URL, new URL that loads is https://www.google.com/search-page.
I would like to append ?block=true to all the navigations.
For the base URL, I can use the method browser.url("https://www.google.com/?block=true"). Not sure how I can add to other pages that are navigated using click actions.

You can use URLSearchParams to generate complex search params. Check out the below example.
const baseUrl = "https://www.google.com/?block=true"; // window.location.href
const searchUrl = "https://www.google.com/search?test=testparam";
function getRedirectUrl(baseUrl, newUrl) {
let oldParms = new URL(baseUrl).searchParams;
const newUrlParams = new URL(newUrl).searchParams;
for(let [value, key] of oldParms.entries()){
newUrlParams.append(key, value);
}
const newSearch = new URL(newUrl).search;
return `${newUrl.slice(0, -1 * newSearch.length)}?${newUrlParams.toString()}`;
}
console.log(getRedirectUrl(baseUrl, searchUrl));

Trying to split following url

I'm trying to split following URL:
http://www.store.com/products.aspx/Books/The-happy-donkey
in order to get only store.
How can this be done?

To do something as generic as possible I'd do something like:
const url = new URL('http://www.store.com/products.aspx/Books/The-happy-donkey');
const { hostname } = url;
const domain = hostname.match(/^www\.(\w+)\.com/);
console.log(domain[1]);

Use below code
//window.location.href
let str = "http://www.store.com/products.aspx/Books/The-happy-donkey";
const words = str.split('.');
console.log(words[1]);

Removing query parameter using node.js not working

I am having this code to remove a query parameter from a url, but it is not working. Can you have a look please?
const url = require('url')
const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
delete obj.query.query2
const link = url.format(obj)
console.log(link) // I was expecting the removal of query2 but it didn't happen
It logged the same url as was passed above, why query2 is not removed? Thanks

You need to remove search node from object
const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
delete obj.query.query2
delete obj.search
const link = url.format(obj)
console.log(link)
This will return you url http://www.example.com/path?query1=val1

If you look at through the source for url module (https://github.com/defunctzombie/node-url/blob/master/url.js). You can see that
it will look at the search node first (line 413). Remove this as well, so that the query object is evaluated.
delete obj.search;

Even though you delete query2 from query object, query2 is still present in search field.
const url = require('url');
const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
console.log(obj);
delete obj.query.query2
delete obj.search
console.log(obj);
const link = url.format(obj)
console.log(link)

const url = require("url")
const urlObj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
delete urlObj.query.query2
delete urlObj.search
const newUrl = url.format(urlObj)
console.log(newUrl) // print >> http://www.example.com/path?query1=val1