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This question's answers are a community effort. Edit existing answers to improve this post. It is not currently accepting new answers or interactions.
How do I append an object (such as a string or number) to an array in JavaScript?
Use the Array.prototype.push method to append values to the end of an array:
// initialize array
var arr = [
"Hi",
"Hello",
"Bonjour"
];
// append new value to the array
arr.push("Hola");
console.log(arr);
You can use the push() function to append more than one value to an array in a single call:
// initialize array
var arr = ["Hi", "Hello", "Bonjour", "Hola"];
// append multiple values to the array
arr.push("Salut", "Hey");
// display all values
for (var i = 0; i < arr.length; i++) {
console.log(arr[i]);
}
Update
If you want to add the items of one array to another array, you can use firstArray.concat(secondArray):
var arr = [
"apple",
"banana",
"cherry"
];
// Do not forget to assign the result as, unlike push, concat does not change the existing array
arr = arr.concat([
"dragonfruit",
"elderberry",
"fig"
]);
console.log(arr);
Update
Just an addition to this answer if you want to prepend any value to the start of an array (i.e. first index) then you can use Array.prototype.unshift for this purpose.
var arr = [1, 2, 3];
arr.unshift(0);
console.log(arr);
It also supports appending multiple values at once just like push.
Update
Another way with ES6 syntax is to return a new array with the spread syntax. This leaves the original array unchanged, but returns a new array with new items appended, compliant with the spirit of functional programming.
const arr = [
"Hi",
"Hello",
"Bonjour",
];
const newArr = [
...arr,
"Salut",
];
console.log(newArr);
If you're only appending a single variable, then push() works just fine. If you need to append another array, use concat():
var ar1 = [1, 2, 3];
var ar2 = [4, 5, 6];
var ar3 = ar1.concat(ar2);
alert(ar1);
alert(ar2);
alert(ar3);
The concat does not affect ar1 and ar2 unless reassigned, for example:
var ar1 = [1, 2, 3];
var ar2 = [4, 5, 6];
ar1 = ar1.concat(ar2);
alert(ar1);
There is a lot of great information on JavaScript Reference.
Some quick benchmarking (each test = 500k appended elements and the results are averages of multiple runs) showed the following:
Firefox 3.6 (Mac):
Small arrays: arr[arr.length] = b is faster (300ms vs. 800ms)
Large arrays: arr.push(b) is faster (500ms vs. 900ms)
Safari 5.0 (Mac):
Small arrays: arr[arr.length] = b is faster (90ms vs. 115ms)
Large arrays: arr[arr.length] = b is faster (160ms vs. 185ms)
Google Chrome 6.0 (Mac):
Small arrays: No significant difference (and Chrome is FAST! Only ~38ms !!)
Large arrays: No significant difference (160ms)
I like the arr.push() syntax better, but I think I'd be better off with the arr[arr.length] Version, at least in raw speed. I'd love to see the results of an IE run though.
My benchmarking loops:
function arrpush_small() {
var arr1 = [];
for (a = 0; a < 100; a++)
{
arr1 = [];
for (i = 0; i < 5000; i++)
{
arr1.push('elem' + i);
}
}
}
function arrlen_small() {
var arr2 = [];
for (b = 0; b < 100; b++)
{
arr2 = [];
for (j = 0; j < 5000; j++)
{
arr2[arr2.length] = 'elem' + j;
}
}
}
function arrpush_large() {
var arr1 = [];
for (i = 0; i < 500000; i++)
{
arr1.push('elem' + i);
}
}
function arrlen_large() {
var arr2 = [];
for (j = 0; j < 500000; j++)
{
arr2[arr2.length] = 'elem' + j;
}
}
I think it's worth mentioning that push can be called with multiple arguments, which will be appended to the array in order. For example:
var arr = ['first'];
arr.push('second', 'third');
console.log(arr);
As a result of this you can use push.apply to append an array to another array like so:
var arr = ['first'];
arr.push('second', 'third');
arr.push.apply(arr, ['forth', 'fifth']);
console.log(arr);
Annotated ES5 has more info on exactly what push and apply do.
2016 update: with spread, you don't need that apply anymore, like:
var arr = ['first'];
arr.push('second', 'third');
arr.push(...['fourth', 'fifth']);
console.log(arr) ;
You can use the push and apply functions to append two arrays.
var array1 = [11, 32, 75];
var array2 = [99, 67, 34];
Array.prototype.push.apply(array1, array2);
console.log(array1);
It will append array2 to array1. Now array1 contains [11, 32, 75, 99, 67, 34].
This code is much simpler than writing for loops to copy each and every items in the array.
With the new ES6 spread operator, joining two arrays using push becomes even easier:
var arr = [1, 2, 3, 4, 5];
var arr2 = [6, 7, 8, 9, 10];
arr.push(...arr2);
console.log(arr);
This adds the contents of arr2 onto the end of arr.
Babel REPL Example
If arr is an array, and val is the value you wish to add use:
arr.push(val);
E.g.
var arr = ['a', 'b', 'c'];
arr.push('d');
console.log(arr);
Use concat:
a = [1, 2, 3];
b = [3, 4, 5];
a = a.concat(b);
console.log(a);
JavaScript with the ECMAScript 5 (ES5) standard which is supported by most browsers now, you can use apply() to append array1 to array2.
var array1 = [3, 4, 5];
var array2 = [1, 2];
Array.prototype.push.apply(array2, array1);
console.log(array2); // [1, 2, 3, 4, 5]
JavaScript with ECMAScript 6 (ES6) standard which is supported by Chrome, Firefox, Internet Explorer, and Edge, you can use the spread operator:
"use strict";
let array1 = [3, 4, 5];
let array2 = [1, 2];
array2.push(...array1);
console.log(array2); // [1, 2, 3, 4, 5]
The spread operator will replace array2.push(...array1); with array2.push(3, 4, 5); when the browser is thinking the logic.
Bonus point
If you'd like to create another variable to store all the items from both arrays, you can do this:
ES5 var combinedArray = array1.concat(array2);
ES6 const combinedArray = [...array1, ...array2]
The spread operator (...) is to spread out all items from a collection.
If you want to append two arrays -
var a = ['a', 'b'];
var b = ['c', 'd'];
then you could use:
var c = a.concat(b);
And if you want to add record g to array (var a=[]) then you could use:
a.push('g');
There are a couple of ways to append an array in JavaScript:
1) The push() method adds one or more elements to the end of an array and returns the new length of the array.
var a = [1, 2, 3];
a.push(4, 5);
console.log(a);
Output:
[1, 2, 3, 4, 5]
2) The unshift() method adds one or more elements to the beginning of an array and returns the new length of the array:
var a = [1, 2, 3];
a.unshift(4, 5);
console.log(a);
Output:
[4, 5, 1, 2, 3]
3) The concat() method is used to merge two or more arrays. This method does not change the existing arrays, but instead returns a new array.
var arr1 = ["a", "b", "c"];
var arr2 = ["d", "e", "f"];
var arr3 = arr1.concat(arr2);
console.log(arr3);
Output:
[ "a", "b", "c", "d", "e", "f" ]
4) You can use the array's .length property to add an element to the end of the array:
var ar = ['one', 'two', 'three'];
ar[ar.length] = 'four';
console.log( ar );
Output:
["one", "two", "three", "four"]
5) The splice() method changes the content of an array by removing existing elements and/or adding new elements:
var myFish = ["angel", "clown", "mandarin", "surgeon"];
myFish.splice(4, 0, "nemo");
//array.splice(start, deleteCount, item1, item2, ...)
console.log(myFish);
Output:
["angel", "clown", "mandarin", "surgeon","nemo"]
6) You can also add a new element to an array simply by specifying a new index and assigning a value:
var ar = ['one', 'two', 'three'];
ar[3] = 'four'; // add new element to ar
console.log(ar);
Output:
["one", "two","three","four"]
The push() method adds new items to the end of an array, and returns the new length. Example:
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.push("Kiwi");
// The result of fruits will be:
Banana, Orange, Apple, Mango, Kiwi
The exact answer to your question is already answered, but let's look at some other ways to add items to an array.
The unshift() method adds new items to the beginning of an array, and returns the new length. Example:
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.unshift("Lemon", "Pineapple");
// The result of fruits will be:
Lemon, Pineapple, Banana, Orange, Apple, Mango
And lastly, the concat() method is used to join two or more arrays. Example:
var fruits = ["Banana", "Orange"];
var moreFruits = ["Apple", "Mango", "Lemon"];
var allFruits = fruits.concat(moreFruits);
// The values of the children array will be:
Banana, Orange, Apple, Mango, Lemon
Now, you can take advantage of ES6 syntax and just do
let array = [1, 2];
console.log([...array, 3]);
keeping the original array immutable.
Append a single element
// Append to the end
arrName.push('newName1');
// Prepend to the start
arrName.unshift('newName1');
// Insert at index 1
arrName.splice(1, 0,'newName1');
// 1: index number, 0: number of element to remove, newName1: new element
// Replace index 3 (of exists), add new element otherwise.
arrName[3] = 'newName1';
Append multiple elements
// Insert from index number 1
arrName.splice(1, 0,'newElemenet1', 'newElemenet2', 'newElemenet3');
// 1: index number from where insert starts,
// 0: number of element to remove,
//newElemenet1,2,3: new elements
Append an array
// Join two or more arrays
arrName.concat(newAry1, newAry2);
//newAry1,newAry2: Two different arrays which are to be combined (concatenated) to an existing array
If you know the highest index (such as stored in a variable "i") then you can do
myArray[i + 1] = someValue;
However, if you don't know then you can either use
myArray.push(someValue);
as other answers suggested, or you can use
myArray[myArray.length] = someValue;
Note that the array is zero based so .length returns the highest index plus one.
Also note that you don't have to add in order and you can actually skip values, as in
myArray[myArray.length + 1000] = someValue;
In which case the values in between will have a value of undefined.
It is therefore a good practice when looping through a JavaScript to verify that a value actually exists at that point.
This can be done by something like the following:
if(myArray[i] === "undefined"){ continue; }
If you are certain that you don't have any zeros in the array then you can just do:
if(!myArray[i]){ continue; }
Of course, make sure in this case that you don't use as the condition myArray[i] (as some people over the Internet suggest based on the end that as soon as i is greater than the highest index, it will return undefined which evaluates to false).
You can do it using JavaScript Spread Operator Syntax:
// Initialize the array
var arr = [
"Hi",
"Hello",
"Bangladesh"
];
// Append a new value to the array
arr = [...arr, "Feni"];
// Or you can add a variable value
var testValue = "Cool";
arr = [...arr, testValue ];
console.log(arr);
// Final output [ 'Hi', 'Hello', 'Bangladesh', 'Feni', 'Cool' ]
If you are using ES6 you can use spread operator to do it.
var arr = [
"apple",
"banana",
"cherry"
];
var arr2 = [
"dragonfruit",
"elderberry",
"fig"
];
arr.push(...arr2);
concat(), of course, can be used with two-dimensional arrays as well. No looping required.
var a = [
[1, 2],
[3, 4] ];
var b = [
["a", "b"],
["c", "d"] ];
b = b.concat(a);
alert(b[2][1]); // Result: 2
Just want to add a snippet for non-destructive addition of an element.
var newArr = oldArr.concat([newEl]);
Let the array length property do the work:
myarray[myarray.length] = 'new element value added to the end of the array';
myarray.length returns the number of strings in the array.
JavaScript is zero-based, so the next element key of the array will be the current length of the array.
Example:
var myarray = [0, 1, 2, 3],
myarrayLength = myarray.length; // myarrayLength is set to 4
Append a value to an array
Since Array.prototype.push adds one or more elements to the end of an array and returns the new length of the array, sometimes we want just to get the new up-to-date array so we can do something like so:
const arr = [1, 2, 3];
const val = 4;
arr.concat([val]); // [1, 2, 3, 4]
Or just:
[...arr, val] // [1, 2, 3, 4]
Append a single item
To append a single item to an array, use the push() method provided by the Array object:
const fruits = ['banana', 'pear', 'apple']
fruits.push('mango')
console.log(fruits)
push() mutates the original array.
To create a new array instead, use the concat() Array method:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango')
console.log(allfruits)
Notice that concat() does not actually add an item to the array, but creates a new array, which you can assign to another variable, or reassign to the original array (declaring it as let, as you cannot reassign a const):
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango')
console.log(allfruits)
let fruits = ['banana', 'pear', 'apple']
fruits = fruits.concat('mango')
Append multiple items
To append a multiple item to an array, you can use push() by calling it with multiple arguments:
const fruits = ['banana', 'pear', 'apple']
fruits.push('mango', 'melon', 'avocado')
console.log(fruits)
You can also use the concat() method you saw before, passing a list of items separated by a comma:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango', 'melon', 'avocado')
console.log(allfruits)
or an array:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat(['mango', 'melon', 'avocado'])
console.log(allfruits)
Remember that as described previously this method does not mutate the original array, but it returns a new array.
Originally posted at
If you want to combine two arrays without the duplicate you may try the code below:
array_merge = function (arr1, arr2) {
return arr1.concat(arr2.filter(function(item){
return arr1.indexOf(item) < 0;
}))
}
Usage:
array1 = ['1', '2', '3']
array2 = ['2', '3', '4', '5']
combined_array = array_merge(array1, array2)
Output:
[1,2,3,4,5]
You .push() that value in.
Example: array.push(value);
If you want to append a single value into an array, simply use the push method. It will add a new element at the end of the array.
But if you intend to add multiple elements then store the elements in a new array and concat the second array with the first array...either way you wish.
arr=['a','b','c'];
arr.push('d');
//now print the array in console.log and it will contain 'a','b','c','d' as elements.
console.log(array);
We don't have an append function for Array in JavaScript, but we have push and unshift. Imagine you have the array below:
var arr = [1, 2, 3, 4, 5];
And we like to append a value to this array. We can do arr.push(6), and it will add 6 to the end of the array:
arr.push(6); // Returns [1, 2, 3, 4, 5, 6];
Also we can use unshift, look at how we can apply this:
arr.unshift(0); // Returns [0, 1, 2, 3, 4, 5];
They are main functions to add or append new values to the arrays.
You can use the push() if you want to add values,
e.g. arr.push("Test1", "Test2");.
If you have array you can use concat(), e.g. Array1.concat(Array2).
If you have just one element to add, you can also try the length method, e.g. array[aray.length] = 'test';.
Appending items on an array
let fruits = ["orange", "banana", "apple", "lemon"]; /* Array declaration */
fruits.push("avacado"); /* Adding an element to the array */
/* Displaying elements of the array */
for(var i=0; i < fruits.length; i++){
console.log(fruits[i]);
}
You can use the push method.
Array.prototype.append = function(destArray){
destArray = destArray || [];
this.push.call(this, ...destArray);
return this;
}
var arr = [1,2,5,67];
var arr1 = [7,4,7,8];
console.log(arr.append(arr1)); // [7, 4, 7, 8, 1, 4, 5, 67, 7]
console.log(arr.append("Hola")) // [1, 2, 5, 67, 7, 4, 7, 8, "H", "o", "l", "a"]
push() adds a new element to the end of an array.
pop() removes an element from the end of an array.
To append an object (such as a string or number) to an array, use:
array.push(toAppend);
This question's answers are a community effort. Edit existing answers to improve this post. It is not currently accepting new answers or interactions.
How do I append an object (such as a string or number) to an array in JavaScript?
Use the Array.prototype.push method to append values to the end of an array:
// initialize array
var arr = [
"Hi",
"Hello",
"Bonjour"
];
// append new value to the array
arr.push("Hola");
console.log(arr);
You can use the push() function to append more than one value to an array in a single call:
// initialize array
var arr = ["Hi", "Hello", "Bonjour", "Hola"];
// append multiple values to the array
arr.push("Salut", "Hey");
// display all values
for (var i = 0; i < arr.length; i++) {
console.log(arr[i]);
}
Update
If you want to add the items of one array to another array, you can use firstArray.concat(secondArray):
var arr = [
"apple",
"banana",
"cherry"
];
// Do not forget to assign the result as, unlike push, concat does not change the existing array
arr = arr.concat([
"dragonfruit",
"elderberry",
"fig"
]);
console.log(arr);
Update
Just an addition to this answer if you want to prepend any value to the start of an array (i.e. first index) then you can use Array.prototype.unshift for this purpose.
var arr = [1, 2, 3];
arr.unshift(0);
console.log(arr);
It also supports appending multiple values at once just like push.
Update
Another way with ES6 syntax is to return a new array with the spread syntax. This leaves the original array unchanged, but returns a new array with new items appended, compliant with the spirit of functional programming.
const arr = [
"Hi",
"Hello",
"Bonjour",
];
const newArr = [
...arr,
"Salut",
];
console.log(newArr);
If you're only appending a single variable, then push() works just fine. If you need to append another array, use concat():
var ar1 = [1, 2, 3];
var ar2 = [4, 5, 6];
var ar3 = ar1.concat(ar2);
alert(ar1);
alert(ar2);
alert(ar3);
The concat does not affect ar1 and ar2 unless reassigned, for example:
var ar1 = [1, 2, 3];
var ar2 = [4, 5, 6];
ar1 = ar1.concat(ar2);
alert(ar1);
There is a lot of great information on JavaScript Reference.
Some quick benchmarking (each test = 500k appended elements and the results are averages of multiple runs) showed the following:
Firefox 3.6 (Mac):
Small arrays: arr[arr.length] = b is faster (300ms vs. 800ms)
Large arrays: arr.push(b) is faster (500ms vs. 900ms)
Safari 5.0 (Mac):
Small arrays: arr[arr.length] = b is faster (90ms vs. 115ms)
Large arrays: arr[arr.length] = b is faster (160ms vs. 185ms)
Google Chrome 6.0 (Mac):
Small arrays: No significant difference (and Chrome is FAST! Only ~38ms !!)
Large arrays: No significant difference (160ms)
I like the arr.push() syntax better, but I think I'd be better off with the arr[arr.length] Version, at least in raw speed. I'd love to see the results of an IE run though.
My benchmarking loops:
function arrpush_small() {
var arr1 = [];
for (a = 0; a < 100; a++)
{
arr1 = [];
for (i = 0; i < 5000; i++)
{
arr1.push('elem' + i);
}
}
}
function arrlen_small() {
var arr2 = [];
for (b = 0; b < 100; b++)
{
arr2 = [];
for (j = 0; j < 5000; j++)
{
arr2[arr2.length] = 'elem' + j;
}
}
}
function arrpush_large() {
var arr1 = [];
for (i = 0; i < 500000; i++)
{
arr1.push('elem' + i);
}
}
function arrlen_large() {
var arr2 = [];
for (j = 0; j < 500000; j++)
{
arr2[arr2.length] = 'elem' + j;
}
}
I think it's worth mentioning that push can be called with multiple arguments, which will be appended to the array in order. For example:
var arr = ['first'];
arr.push('second', 'third');
console.log(arr);
As a result of this you can use push.apply to append an array to another array like so:
var arr = ['first'];
arr.push('second', 'third');
arr.push.apply(arr, ['forth', 'fifth']);
console.log(arr);
Annotated ES5 has more info on exactly what push and apply do.
2016 update: with spread, you don't need that apply anymore, like:
var arr = ['first'];
arr.push('second', 'third');
arr.push(...['fourth', 'fifth']);
console.log(arr) ;
You can use the push and apply functions to append two arrays.
var array1 = [11, 32, 75];
var array2 = [99, 67, 34];
Array.prototype.push.apply(array1, array2);
console.log(array1);
It will append array2 to array1. Now array1 contains [11, 32, 75, 99, 67, 34].
This code is much simpler than writing for loops to copy each and every items in the array.
With the new ES6 spread operator, joining two arrays using push becomes even easier:
var arr = [1, 2, 3, 4, 5];
var arr2 = [6, 7, 8, 9, 10];
arr.push(...arr2);
console.log(arr);
This adds the contents of arr2 onto the end of arr.
Babel REPL Example
If arr is an array, and val is the value you wish to add use:
arr.push(val);
E.g.
var arr = ['a', 'b', 'c'];
arr.push('d');
console.log(arr);
Use concat:
a = [1, 2, 3];
b = [3, 4, 5];
a = a.concat(b);
console.log(a);
JavaScript with the ECMAScript 5 (ES5) standard which is supported by most browsers now, you can use apply() to append array1 to array2.
var array1 = [3, 4, 5];
var array2 = [1, 2];
Array.prototype.push.apply(array2, array1);
console.log(array2); // [1, 2, 3, 4, 5]
JavaScript with ECMAScript 6 (ES6) standard which is supported by Chrome, Firefox, Internet Explorer, and Edge, you can use the spread operator:
"use strict";
let array1 = [3, 4, 5];
let array2 = [1, 2];
array2.push(...array1);
console.log(array2); // [1, 2, 3, 4, 5]
The spread operator will replace array2.push(...array1); with array2.push(3, 4, 5); when the browser is thinking the logic.
Bonus point
If you'd like to create another variable to store all the items from both arrays, you can do this:
ES5 var combinedArray = array1.concat(array2);
ES6 const combinedArray = [...array1, ...array2]
The spread operator (...) is to spread out all items from a collection.
If you want to append two arrays -
var a = ['a', 'b'];
var b = ['c', 'd'];
then you could use:
var c = a.concat(b);
And if you want to add record g to array (var a=[]) then you could use:
a.push('g');
There are a couple of ways to append an array in JavaScript:
1) The push() method adds one or more elements to the end of an array and returns the new length of the array.
var a = [1, 2, 3];
a.push(4, 5);
console.log(a);
Output:
[1, 2, 3, 4, 5]
2) The unshift() method adds one or more elements to the beginning of an array and returns the new length of the array:
var a = [1, 2, 3];
a.unshift(4, 5);
console.log(a);
Output:
[4, 5, 1, 2, 3]
3) The concat() method is used to merge two or more arrays. This method does not change the existing arrays, but instead returns a new array.
var arr1 = ["a", "b", "c"];
var arr2 = ["d", "e", "f"];
var arr3 = arr1.concat(arr2);
console.log(arr3);
Output:
[ "a", "b", "c", "d", "e", "f" ]
4) You can use the array's .length property to add an element to the end of the array:
var ar = ['one', 'two', 'three'];
ar[ar.length] = 'four';
console.log( ar );
Output:
["one", "two", "three", "four"]
5) The splice() method changes the content of an array by removing existing elements and/or adding new elements:
var myFish = ["angel", "clown", "mandarin", "surgeon"];
myFish.splice(4, 0, "nemo");
//array.splice(start, deleteCount, item1, item2, ...)
console.log(myFish);
Output:
["angel", "clown", "mandarin", "surgeon","nemo"]
6) You can also add a new element to an array simply by specifying a new index and assigning a value:
var ar = ['one', 'two', 'three'];
ar[3] = 'four'; // add new element to ar
console.log(ar);
Output:
["one", "two","three","four"]
The push() method adds new items to the end of an array, and returns the new length. Example:
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.push("Kiwi");
// The result of fruits will be:
Banana, Orange, Apple, Mango, Kiwi
The exact answer to your question is already answered, but let's look at some other ways to add items to an array.
The unshift() method adds new items to the beginning of an array, and returns the new length. Example:
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.unshift("Lemon", "Pineapple");
// The result of fruits will be:
Lemon, Pineapple, Banana, Orange, Apple, Mango
And lastly, the concat() method is used to join two or more arrays. Example:
var fruits = ["Banana", "Orange"];
var moreFruits = ["Apple", "Mango", "Lemon"];
var allFruits = fruits.concat(moreFruits);
// The values of the children array will be:
Banana, Orange, Apple, Mango, Lemon
Now, you can take advantage of ES6 syntax and just do
let array = [1, 2];
console.log([...array, 3]);
keeping the original array immutable.
Append a single element
// Append to the end
arrName.push('newName1');
// Prepend to the start
arrName.unshift('newName1');
// Insert at index 1
arrName.splice(1, 0,'newName1');
// 1: index number, 0: number of element to remove, newName1: new element
// Replace index 3 (of exists), add new element otherwise.
arrName[3] = 'newName1';
Append multiple elements
// Insert from index number 1
arrName.splice(1, 0,'newElemenet1', 'newElemenet2', 'newElemenet3');
// 1: index number from where insert starts,
// 0: number of element to remove,
//newElemenet1,2,3: new elements
Append an array
// Join two or more arrays
arrName.concat(newAry1, newAry2);
//newAry1,newAry2: Two different arrays which are to be combined (concatenated) to an existing array
If you know the highest index (such as stored in a variable "i") then you can do
myArray[i + 1] = someValue;
However, if you don't know then you can either use
myArray.push(someValue);
as other answers suggested, or you can use
myArray[myArray.length] = someValue;
Note that the array is zero based so .length returns the highest index plus one.
Also note that you don't have to add in order and you can actually skip values, as in
myArray[myArray.length + 1000] = someValue;
In which case the values in between will have a value of undefined.
It is therefore a good practice when looping through a JavaScript to verify that a value actually exists at that point.
This can be done by something like the following:
if(myArray[i] === "undefined"){ continue; }
If you are certain that you don't have any zeros in the array then you can just do:
if(!myArray[i]){ continue; }
Of course, make sure in this case that you don't use as the condition myArray[i] (as some people over the Internet suggest based on the end that as soon as i is greater than the highest index, it will return undefined which evaluates to false).
You can do it using JavaScript Spread Operator Syntax:
// Initialize the array
var arr = [
"Hi",
"Hello",
"Bangladesh"
];
// Append a new value to the array
arr = [...arr, "Feni"];
// Or you can add a variable value
var testValue = "Cool";
arr = [...arr, testValue ];
console.log(arr);
// Final output [ 'Hi', 'Hello', 'Bangladesh', 'Feni', 'Cool' ]
If you are using ES6 you can use spread operator to do it.
var arr = [
"apple",
"banana",
"cherry"
];
var arr2 = [
"dragonfruit",
"elderberry",
"fig"
];
arr.push(...arr2);
concat(), of course, can be used with two-dimensional arrays as well. No looping required.
var a = [
[1, 2],
[3, 4] ];
var b = [
["a", "b"],
["c", "d"] ];
b = b.concat(a);
alert(b[2][1]); // Result: 2
Just want to add a snippet for non-destructive addition of an element.
var newArr = oldArr.concat([newEl]);
Let the array length property do the work:
myarray[myarray.length] = 'new element value added to the end of the array';
myarray.length returns the number of strings in the array.
JavaScript is zero-based, so the next element key of the array will be the current length of the array.
Example:
var myarray = [0, 1, 2, 3],
myarrayLength = myarray.length; // myarrayLength is set to 4
Append a value to an array
Since Array.prototype.push adds one or more elements to the end of an array and returns the new length of the array, sometimes we want just to get the new up-to-date array so we can do something like so:
const arr = [1, 2, 3];
const val = 4;
arr.concat([val]); // [1, 2, 3, 4]
Or just:
[...arr, val] // [1, 2, 3, 4]
Append a single item
To append a single item to an array, use the push() method provided by the Array object:
const fruits = ['banana', 'pear', 'apple']
fruits.push('mango')
console.log(fruits)
push() mutates the original array.
To create a new array instead, use the concat() Array method:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango')
console.log(allfruits)
Notice that concat() does not actually add an item to the array, but creates a new array, which you can assign to another variable, or reassign to the original array (declaring it as let, as you cannot reassign a const):
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango')
console.log(allfruits)
let fruits = ['banana', 'pear', 'apple']
fruits = fruits.concat('mango')
Append multiple items
To append a multiple item to an array, you can use push() by calling it with multiple arguments:
const fruits = ['banana', 'pear', 'apple']
fruits.push('mango', 'melon', 'avocado')
console.log(fruits)
You can also use the concat() method you saw before, passing a list of items separated by a comma:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat('mango', 'melon', 'avocado')
console.log(allfruits)
or an array:
const fruits = ['banana', 'pear', 'apple']
const allfruits = fruits.concat(['mango', 'melon', 'avocado'])
console.log(allfruits)
Remember that as described previously this method does not mutate the original array, but it returns a new array.
Originally posted at
If you want to combine two arrays without the duplicate you may try the code below:
array_merge = function (arr1, arr2) {
return arr1.concat(arr2.filter(function(item){
return arr1.indexOf(item) < 0;
}))
}
Usage:
array1 = ['1', '2', '3']
array2 = ['2', '3', '4', '5']
combined_array = array_merge(array1, array2)
Output:
[1,2,3,4,5]
You .push() that value in.
Example: array.push(value);
If you want to append a single value into an array, simply use the push method. It will add a new element at the end of the array.
But if you intend to add multiple elements then store the elements in a new array and concat the second array with the first array...either way you wish.
arr=['a','b','c'];
arr.push('d');
//now print the array in console.log and it will contain 'a','b','c','d' as elements.
console.log(array);
We don't have an append function for Array in JavaScript, but we have push and unshift. Imagine you have the array below:
var arr = [1, 2, 3, 4, 5];
And we like to append a value to this array. We can do arr.push(6), and it will add 6 to the end of the array:
arr.push(6); // Returns [1, 2, 3, 4, 5, 6];
Also we can use unshift, look at how we can apply this:
arr.unshift(0); // Returns [0, 1, 2, 3, 4, 5];
They are main functions to add or append new values to the arrays.
You can use the push() if you want to add values,
e.g. arr.push("Test1", "Test2");.
If you have array you can use concat(), e.g. Array1.concat(Array2).
If you have just one element to add, you can also try the length method, e.g. array[aray.length] = 'test';.
Appending items on an array
let fruits = ["orange", "banana", "apple", "lemon"]; /* Array declaration */
fruits.push("avacado"); /* Adding an element to the array */
/* Displaying elements of the array */
for(var i=0; i < fruits.length; i++){
console.log(fruits[i]);
}
You can use the push method.
Array.prototype.append = function(destArray){
destArray = destArray || [];
this.push.call(this, ...destArray);
return this;
}
var arr = [1,2,5,67];
var arr1 = [7,4,7,8];
console.log(arr.append(arr1)); // [7, 4, 7, 8, 1, 4, 5, 67, 7]
console.log(arr.append("Hola")) // [1, 2, 5, 67, 7, 4, 7, 8, "H", "o", "l", "a"]
push() adds a new element to the end of an array.
pop() removes an element from the end of an array.
To append an object (such as a string or number) to an array, use:
array.push(toAppend);
I have two arrays, arr1 = [1,2,7,9,10] and arr2 = [40,50,70,80,30]. From these two arrays, I have a zero-filled array of length 15 that I want to populate using arr1 as the indexes and arr2 as the values: [0,40,50,0,0,0,0,70,0,80,30,0,0,0,0]
What is the code to do this?
Here is the solution:
var arr1 = [1,2,7,9,10]; // Add 0 to your array if you want first element of array3 to be replaced with arr2 element
// If you want first element like in example this would be correct
// var arr1 = [0,1,6,8,9];
var arr2 = [40,50,70,80,30];
var arr3 = []; //[40,50,0,0,0,0,70,0,80,30,0,0,0,0,0]
var arr3Length = 15;
var arr2Counter = 0;
for ( var i = 0; i < arr3Length; i ++ ) {
if ( arr1.includes(i) ) {
arr3.push(arr2[arr2Counter]);
arr2Counter ++;
} else {
arr3.push(0);
}
}
console.log(arr3);
JavaScript array starts with 0 element, not 1, so your first value is 0, not 40...
Here is a succinct way to do it without any for loop or if/else. You first create an array withs 0s and the appropriate length, and then you fill the slots.
const indices = [1, 2, 7, 9, 10]; // criteria 1
const values = [40, 50, 70, 80, 30]; // criteria 2
const length = 15; // criteria 3
const array = new Array(length).fill(0);
indices.forEach((idx, i) => array[idx] = values[i]);
console.log(array)
You could also calculate a default value for criteria 3 (length) if the length given is smaller than the last element of your index array.
lengthSafe = length < indices[indices.length-1] ? indices[indices.length-1] : length;
You should also make sure that your values array is not smaller than your indices array.
Aslo, beware, JavaScript array indexing starts at 0, not 1!
If you consider 1 to be your first index, do this instead:
indices.forEach((idx, i) => array[idx - 1] = values[i]);
I'm not looking to push the values from one array into another, or concatenate them but simply sum the item values from each - either into a new array, or alternatively amending either arrayOne or arrayTwo with the values from the other e.g.
var arrayOne = [1,2,3,4,5]
var arrayTwo = [2,4,6,8,10]
// loop / function..
var newArray = [3,6,9,12,15]
OR arrayOne = [3,6,9,12,15]
I thought this would be straightforward but this requires 2 loops running at the same time?
Thanks for your help!
var arrayOne = [1,2,3,4,5];
var arrayTwo = [2,4,6,8,10];
var newArray = [];
newArray = arr1.map((item,index)=>{
return item + arr2[index]
});
You could collect all wanted array for adding values at the same index in an array and reduce the arrays.
This works with an arbitrary count of arrays.
var array1 = [1, 2, 3, 4, 5],
array2 = [2, 4, 6, 8, 10],
result = [array1, array2].reduce(
(a, b) => (b.forEach((v, i) => a[i] = (a[i] || 0) + v), a)
);
console.log(result);
You can use Array's map():
var arrayOne = [1,2,3,4,5];
var arrayTwo = [2,4,6,8,10];
var newArray = arrayOne.map( (item, i) => item += arrayTwo[i] );
console.log(newArray);
I want to compare an array with an array set.
For example,
array 1 = [[1,2,3],[1,4,5]];
array 2 = [1,3,6,5,4];
Since the elements 1,4,5 in array 2 match with a set in array 1 it should return true.
use loop and loop. get all child array in array1, and check each child array include in array2.
function check(){
var array1 = [[1,2,3],[1,4,5]];
var array2 = [1,3,6,5,4];
for(let arr of array1){
let flag=true;
for(let child of arr){
if(array2.indexOf(child) < 0){
flag = false;
break; // if one element not in array2, enter next loop.
}
}
if(flag) return flag; // if got one child array elements all in array2, stop loop.
}
}
Iterate over your array and check if the value exists in the other array.
var sets = [
[1, 2, 3],
[1, 4, 5]
],
valid = [1, 3, 6, 5, 4];
var processed = sets.map(set => set.every(val => valid.includes(val)));
console.log( processed);
There are ways to make this more efficient, but try this for starters.
Here's an example how you can check if any are true:
// Check if any are true
var any = processed.some(v=>v);
console.log( any );
You can iterate over array1 and use every() on each number group and as a condition for it use includes() with the second array for a relatively short syntax:
var array1 = [
[1, 2, 3],
[1, 4, 5]
];
var array2 = [1, 3, 6, 5, 4];
var results = [];
array1.forEach(function(item, index, array) {
if (item.every(x => array2.includes(x))) {
results.push(item)
}
});
console.log(results)
Edited : I'm pushing the results that return true to an empty array ...
Flatten the first array (unpack the nested arrays). Then do an intersection of the flattened array and the second array. Map through the first array, and for each each array do an intersection against the second array. Then filter out all arrays that are empty. If the resulting array contains something, then something matched.
const hasMatch = Boolean(array1.map(a => intersect(a, array2)).filter(i => i.length).length)
var array1 = [
[1, 2, 3],
[1, 4, 5]
];
var array2 = [1, 3, 6, 5, 4];
var isMatch = doesNestedArrayMatchArray(array1, array2);
function doesNestedArrayMatchArray(nestedArray, bigArray) {
var atLeastOneMatch = false;
for (var i = 0; i < nestedArray.length; i++) {
var innerMatch = true;
//go through each array of array1
for (var j = 0; j < nestedArray[i].length; j++) {
if (bigArray.indexOf(nestedArray[i][j]) == -1){
innerMatch = false;
break;
}
}
if (innerMatch) atLeastOneMatch = true;
}
return atLeastOneMatch;
}
console.log(isMatch)