I have a object like this
const obj = {'id_1': 'data_1', 'id_2': 'data_2'....}
And I have an aggregate query like this:
models.dummy.aggregate(
[
{ $match: findQuery },
{
$project: {
id: 1,
tId: 1,
quantity: 1,
status: 1,
notes:
}
}
]);
Now here for notes field in $project, I want to save the result obj['tId'] for it. I'm not able to figure how do I access the object obj in the aggregate query and utilise the tId to associate the notes field with the value.
Expected output for notes
notes: obj[tId]
// O/P:
[
{
notes: 'data_1';
...
},
{
notes: 'data_2';
...
}
...
]
Related
For example, I have something in my database like in customers collection.
{
Max: {
shoping_list: {
food: { Pizza: 2, Ramen: 1, Sushi: 5 }
}
},
John: {
shoping_list: {
food: { Pizza: 2, Ramen: 1, Burger: 1 }
}
}
}
In my backend, I want to get the sum of food
const request = await customers.aggregate([
{
$group: {
_id: null,
Pizza: {
$sum: '$shoping_list.food.Pizza',
},
Is there a way how to update or get the sum automatically without manually writing every food from the shopping_list?
The design of the document may lead the query looks complex but still achievable.
$replaceRoot - Replace the input document with a new document.
1.1. $reduce - Iterate the array and transform it into a new form (array).
1.2. input - Transform key-value pair of current document $$ROOT to an array of objects such as: [{ k: "", v: "" }]
1.3. initialValue - Initialize the value with an empty array. And this will result in the output in the array.
1.4. in
1.4.1. $concatArrays - Combine aggregate array result ($$value) with 1.4.2.
1.4.2. With the $cond operator to filter out the document with { k: "_id" }, and we transform the current iterate object's v shoping_list.food to the array via $objectToArray.
$unwind - Deconstruct the foods array into multiple documents.
$group - Group by foods.k and perform sum for foods.v.
db.collection.aggregate([
{
$replaceRoot: {
newRoot: {
foods: {
$reduce: {
input: {
$objectToArray: "$$ROOT"
},
initialValue: [],
in: {
$concatArrays: [
"$$value",
{
$cond: {
if: {
$ne: [
"$$this.k",
"_id"
]
},
then: {
$objectToArray: "$$this.v.shoping_list.food"
},
else: []
}
}
]
}
}
}
}
}
},
{
$unwind: "$foods"
},
{
$group: {
_id: "$foods.k",
sum: {
$sum: "$foods.v"
}
}
}
])
Demo # Mongo Playground
So I tried several ways, but I can't, I can modify several objects with the same key but I can't modify any with different keys, if anyone can help me is quite a complex problem
{
id: 123,
"infos": [
{ name: 'Joe', value: 'Disabled', id: 0 },
{ name: 'Adam', value: 'Enabled', id: 0 }
]
};
In my database I have a collection with an array and several objects inside which gives this.
I want to modify these objects, filter by their name and modify the value.
To give you a better example, my site returns me an object with the new data, and I want to modify the database object with the new object, without clearing the array, the name key never changes.
const object = [
{ name: 'Joe', value: 'Hey', id: 1 },
{ name: 'Adam', value: 'None', id: 1 }
];
for(const obj in object) {
Schema.findOneAndUpdate({ id: 123 }, {
$set: {
[`infos.${obj}.value`]: "Test"
}
})
}
This code works but it is not optimized, it makes several requests, I would like to do everything in one request, and also it doesn't update the id, only the value.
If anyone can help me that would be great, I've looked everywhere and can't find anything
My schema structure
new Schema({
id: { "type": String, "required": true, "unique": true },
infos: []
})
I use the $addToSet method to insert objects into the infos array
Try This :
db.collection.update({
id: 123,
},
{
$set: {
"infos.$[x].value": "Value",
"infos.$[x].name": "User"
}
},
{
arrayFilters: [
{
"x.id": {
$in: [
1
]
}
},
],
multi: true
})
The all positional $[] operator acts as a placeholder for all elements in the array field.
In $in you can use dynamic array of id.
Ex :
const ids = [1,2,..n]
db.collection.update(
//Same code as it is...
{
arrayFilters: [
{
"x.id": {
$in: ids
}
},
],
multi: true
})
MongoPlayGround Link : https://mongoplayground.net/p/Tuz831lkPqk
Maybe you look for something like this:
db.collection.update({},
{
$set: {
"infos.$[x].value": "test1",
"infos.$[x].id": 10,
"infos.$[y].value": "test2",
"infos.$[y].id": 20
}
},
{
arrayFilters: [
{
"x.name": "Adam"
},
{
"y.name": "Joe"
}
],
multi: true
})
Explained:
You define arrayFilters for all names in objects you have and update the values & id in all documents ...
playground
I have this one schema
{
_id: "123456",
id: "123",
inventory: [
{
id: "foo",
count: 0
},
{
id: "bar",
count: 3
}
]
}
I wanted every "count" keys in the inventory array to be "price" which will look like this at the end:
{
_id: "123456",
id: "123",
inventory: [
{
id: "foo",
price: 0
},
{
id: "bar",
price: 3
}
]
}
And I've tried this
Model.updateOne({ id: "123" }, { $unset: { inventory: [{ count: 1 }] } } )
But it seems to be deleting the "inventory" field itself
The first thing here is to try to use $rename but how the docs explain:
$rename does not work if these fields are in array elements.
So is necessary to look for another method. So you can use this update with aggregation query:
This query uses mainly $map, $arrayToObject and $objectToArray. The trick here is:
Create a new field called inventory (overwrite existing one)
Iterate over every value of the array with $map, and then for each object in the array use $objectToArray to create an array and also iterate over that second array using again $map.
Into this second iteration create fields k and v. Field v will be the same (you don't want to change the value, only the key). And for field k you have to change only the one whose match with your condition, i.e. only change from count to price. If this condition is not matched then the key remain.
db.collection.update({},
[
{
$set: {
inventory: {
$map: {
input: "$inventory",
in: {
$arrayToObject: {
$map: {
input: {$objectToArray: "$$this"},
in: {
k: {
$cond: [
{
$eq: ["$$this.k","count"]
},
"price",
"$$this.k"
]
},
v: "$$this.v"
}
}
}
}
}
}
}
}
])
Example here
Suppose I have the following document:
{
_id: "609bcd3160653e022a6d0fd8",
companies:{
apple: [
{
product_id: "609bcd3160653e022a6d0fd7"
},
{
product_id: "609bcd3160653e022a6d0fd6"
}
],
microsoft: [
{
product_id: "609bcd3160653e022a6d0fd5"
},
{
product_id: "609bcd3160653e022a6d0fd4"
}
]
}
}
How can I find and delete the object with the product_id: "609bcd3160653e022a6d0fd4".
P.S: I use MongoDB native driver for Nodejs.
Thanks a lot!
If I don't know the name of the array? I want to find the object by product_id
It is not possible with regular update query, you can try update with aggregation pipeline starting from MongoDB 4.2,
$objectToArray convert companies object to array in key-value format
$map to iterate loop of above converted array
$filter to filter dynamic array's by product_id
$arrayToObject convert key-value array to regular object format
let product_id = "609bcd3160653e022a6d0fd4";
YourSchema.findOneAndUpdate(
{ _id: "609bcd3160653e022a6d0fd8" }, // put your query
[{
$set: {
companies: {
$arrayToObject: {
$map: {
input: { $objectToArray: "$companies" },
in: {
k: "$$this.k",
v: {
$filter: {
input: "$$this.v",
cond: { $ne: ["$$this.product_id", product_id] }
}
}
}
}
}
}
}
}],
{
new: true // return updated document
}
);
Playground
I need your help in aggregate functions in Mongo.
I have such aggregation:
const likes = await this.aggregate([
{
$match: { post: postId },
},
{
$group: {
_id: '$likeType',
count: { $sum: 1 },
},
},
]);
It collects all likes/dislikes for a post and returns this:
[ { _id: 'pos', count: 40 }, { _id: 'neg', count: 3 } ]
I faced a problem: if there is only one type of likes (for example only 'pos'), it returns this:
[ { _id: 'pos', count: 40 } ]
But I need this array to show zero value too:
[ { _id: 'pos', count: 40 }, { _id: 'neg', count: 0 } ]
Is there any way to set default values for all types of _ids?
I understand that it can't find any 'neg's and it can't return them. So I want to set defaults to let the system know, that there are only two types: 'pos' and 'neg'.
Are there any solutions for such cases?
Thanks!
My suggestion is:
Get distinct Ids: https://docs.mongodb.com/manual/reference/method/db.collection.distinct/
Do your search with your query param.
Filter distinct Ids which is not your query param. Append default values to result.