Develop Reference

How to display time range on iteration?

I am trying to run a for loop that has to loop 8 times. On each iteration I want the loop to increment the value by +1 hour.
The final output should be in this time format:
opening hours:
08:00, 09:00, 10:00,11:00, 12:00, 13:00, 14:00, 15:00,16:00
In this case timediff mentioned in the for...loop holds the value of 8.
var minutesToAdd = 60;
var currentDate = new Date("2022-04-10 08:00:00");
var futureDate = new Date(currentDate.getTime() + minutesToAdd * 120000).toLocaleTimeString();
for (let i = 0; i < timeDiff; i++) {
console.log(futureDate, 'futureeee date');
}

Your code never updates futureDate in the loop. Also, when you expect to print 08:00 in the example, you should print currentDate when no minutes have been added yet.
I would also suggest you use the native function setMinutes and getMinutes to add a number of minutes to a date object.
You say that timeDiff has a value of 8, but then you say you want 9 outputs (8:00 ... 16:00), so you'll need an additional iteration.
Finally, to get the hh:mm output format, there are several solutions. One is to choose a locale that uses a format that is close to what you need, and express you want the short format (without seconds):
let timeDiff = 9; // One more to also output 16:00
let minutesToAdd = 60;
let currentDate = new Date("2022-04-10 08:00:00");
for (let i = 0; i < timeDiff; i++) {
console.log(currentDate.toLocaleTimeString("en-SE", { timeStyle: "short" }));
currentDate.setMinutes(currentDate.getMinutes() + minutesToAdd);
}

You can then use a simple for-loop to iterate from 0 up to and including timeDiff, incrementing each iteration by 1.
for (let hours = 0; hours <= timeDiff; hours += 1) {
// ...
}
Instead of a starting date we'll start with a timestamp Date.parse("2022-04-10 08:00:00"). This allows us to add the time from the loop to the timestamp and create a new date.
const date = new Date(currentTimestamp + hours*HOURS);
To only display the time I've taken the liberty of using the solution provided by the answer of trincot.
const MILLISECOND = 1 , MILLISECONDS = MILLISECOND;
const SECOND = 1000*MILLISECONDS, SECONDS = SECOND ;
const MINUTE = 60*SECONDS , MINUTES = MINUTE ;
const HOUR = 60*MINUTES , HOURS = HOUR ;
const timeDiff = 8;
var currentTimestamp = Date.parse("2022-04-10 08:00:00");
for (let hours = 0; hours <= timeDiff; hours += 1) {
const date = new Date(currentTimestamp + hours*HOURS);
console.log(date.toLocaleString(undefined, { timeStyle: "short" }));
}

Get all days of the week given a day

I'm trying to make a function to get all the days of the week given the current day. I had a function that i thought was working until i noticed that if the day of the week is near the end of the month, like for example February, i get weird data. Anyone know whats going on and how to fix it?
function days(current) {
var week = new Array();
// Starting Monday not Sunday
var first = ((current.getDate() - current.getDay()) + 1);
for (var i = 0; i < 7; i++) {
week.push(
new Date(current.setDate(first++))
);
}
return week;
}
var input = new Date(2017, 1, 27);
console.log('input: %s', input);
var result = days(input);
console.log(result.map(d => d.toString()));
.as-console-wrapper{min-height:100%}

If you don't want to use some kind of other library like Moment.js you can also change your function a little and then it will work. Try this:
function dates(current) {
var week= new Array();
// Starting Monday not Sunday
current.setDate((current.getDate() - current.getDay() +1));
for (var i = 0; i < 7; i++) {
week.push(
new Date(current)
);
current.setDate(current.getDate() +1);
}
return week;
}
console.log(dates(new Date(2017, 1, 27)));

You can use Moment.js library - utility library for dates/time operations
Here's examplary code to get current week's dates starting from monday:
function getThisWeekDates() {
var weekDates= [];
for (var i = 1; i <= 7; i++) {
weekDates.push(moment().day(i));
}
return weekDates;
}
var thisWeekDates = getThisWeekDates();
thisWeekDates.forEach(function(date){ console.log(date.format());});
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.js"></script>
The code above prints following results to the console:
2017-03-20T21:26:27+01:00
2017-03-21T21:26:27+01:00
2017-03-22T21:26:27+01:00
2017-03-23T21:26:27+01:00
2017-03-24T21:26:27+01:00
2017-03-25T21:26:27+01:00
2017-03-26T21:26:27+02:00

I will trace your code using your example of Feb 27, 2017:
first = 27 - 1 + 1 = 27
loop:
Feb.setDate(27) = 27 feb
Feb.setDate(28) = 28 feb
Feb.setDate(29) = Not 29 days in Feb. So it sets current to 29-28 = 1st day of March
March.setDate(30) = March 30
March.setDate(31) = March 31
March.setDate(32) = Not 32 days in March. So it sets current to 31-32 = 1st of April..
April.setDate(33) = Not 33 days in April. So it sets current day 33-30 = 3rd day of May.
Please note that I used the shorthand of Month.setDate() to show the month of the current Date object when it was being called.
So the issue is with your understanding of setDate that is being used on current. It changes the month and if the value you use isn't a day in the month it adjusts the month and day appropriately. I hope this cleared things up for you.
For how to add one to a date, see Add +1 to current date. Adapted to your code, you can set current to the first day of the week then just keep adding 1 day and pushing copies to the array:
function days(current) {
var week = [];
// Starting Monday not Sunday
var first = current.getDate() - current.getDay() + 1;
current.setDate(first);
for (var i = 0; i < 7; i++) {
week.push(new Date(+current));
current.setDate(current.getDate()+1);
}
return week;
}
var input = new Date(2017, 1, 27);
console.log('input: %s', input);
var result = days(input);
console.log(result.map(d => d.toString()));
Note that this changes the date passed in (per the original code), you may want to make current a copy to avoid that.

Suppose monday starts the week, you can calculate monday and go to sunday. getDategives you the day of the week, and Sunday starts at 0. With momnday, we get just offset forward to 6 days to get sunday
mondayThisWeek(date: Date): Date {
const d = new Date(date)
const day = d.getDay()
const diff = d.getDate() - day + (day === 0 ? -6 : 1)
return new Date(d.setDate(diff))
}
const offsetDate = (base: Date, count: number): Date => {
const date = new Date(base)
date.setDate(base.getDate() + count)
return date
}
thisWeek(today: Date): TimeRange {
const monday = mondayThisWeek(today)
return {
startDate: monday,
endDate: offsetDate(monday, 6)
}
}

This can be achieved easly using moment
const getWeekDates = () => {
let weekDates = [];
for (let i = 0; i < 7; i++)
weekDates.push(moment().add(i, 'd'));
return weekDates;
};
console.log(getWeekDates());
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.2/moment.js"></script>

How to check if date is in this week in javascript?

I have this date "2016-04-23T11:45:00Z" and I want to check this date in this week or not ?
Thanks,

Dates are hard, I would always suggest using a library dedicated to date handling as it reduces the chances of errors in your code.
MomentJS is a good one.
var now = moment();
var input = moment("2016-04-17T11:45:00Z");
var isThisWeek = (now.isoWeek() == input.isoWeek())
Edit: Please note as of 2020 moment may not be a good choice for new projects

This seems to be working for me.
function isDateInThisWeek(date) {
const todayObj = new Date();
const todayDate = todayObj.getDate();
const todayDay = todayObj.getDay();
// get first date of week
const firstDayOfWeek = new Date(todayObj.setDate(todayDate - todayDay));
// get last date of week
const lastDayOfWeek = new Date(firstDayOfWeek);
lastDayOfWeek.setDate(lastDayOfWeek.getDate() + 6);
// if date is equal or within the first and last dates of the week
return date >= firstDayOfWeek && date <= lastDayOfWeek;
}
const date = new Date();
const isInWeek = isDateInThisWeek(date);

<div ng-app="myApp">
<div class="container" ng-controller="Ctrl_List">
<h1>{{currentDate}}</h1>
<h1>{{numberCurrentDateWeeks}}</h1>
<h1>{{yourDate}}</h1>
<h1>{{numberYourDateWeeks}}</h1>
</div>
</div>
......
angular.module('myApp', [])
.controller("Ctrl_List", ["$scope", "$filter", function(s, $filter) {
s.yourDate = '2016-04-23T11:45:00Z'
s.currentDate = new Date();
s.numberCurrentDateWeeks = $filter('date')(s.currentDate, "w");
s.numberYourDateWeeks = $filter('date')(s.yourDate, "w");
}]);
then you got the Week numbers just compare or do whatever you like
cheers !

You can do that without any libraries by checking if the date.getTime() (milliseconds since epoch) is between last monday and next monday:
const WEEK_LENGTH = 604800000;
function onCurrentWeek(date) {
var lastMonday = new Date(); // Creating new date object for today
lastMonday.setDate(lastMonday.getDate() - (lastMonday.getDay()-1)); // Setting date to last monday
lastMonday.setHours(0,0,0,0); // Setting Hour to 00:00:00:00
const res = lastMonday.getTime() <= date.getTime() &&
date.getTime() < ( lastMonday.getTime() + WEEK_LENGTH);
return res; // true / false
}
(one week in ms = 24 * 60 * 60 * 1000 * 7 = 604,800,000)

May not be the most optimal solution, but I think it's quite readable:
function isThisWeek (date) {
const now = new Date();
const weekDay = (now.getDay() + 6) % 7; // Make sure Sunday is 6, not 0
const monthDay = now.getDate();
const mondayThisWeek = monthDay - weekDay;
const startOfThisWeek = new Date(+now);
startOfThisWeek.setDate(mondayThisWeek);
startOfThisWeek.setHours(0, 0, 0, 0);
const startOfNextWeek = new Date(+startOfThisWeek);
startOfNextWeek.setDate(mondayThisWeek + 7);
return date >= startOfThisWeek && date < startOfNextWeek;
}

This link explaines, how to do this without using any js libraries. https://gist.github.com/dblock/1081513
Code against link death:
function( d ) {
// Create a copy of this date object
var target = new Date(d.valueOf());
// ISO week date weeks start on monday
// so correct the day number
var dayNr = (d.getDay() + 6) % 7;
// Set the target to the thursday of this week so the
// target date is in the right year
target.setDate(target.getDate() - dayNr + 3);
// ISO 8601 states that week 1 is the week
// with january 4th in it
var jan4 = new Date(target.getFullYear(), 0, 4);
// Number of days between target date and january 4th
var dayDiff = (target - jan4) / 86400000;
// Calculate week number: Week 1 (january 4th) plus the
// number of weeks between target date and january 4th
var weekNr = 1 + Math.ceil(dayDiff / 7);
return weekNr;
}

I managed to do it with this simple trick and without any external library.
Considering monday as the first day of the week, the function takes as parameter a date string and do the validation before checking if the day indeed is in the current week.
function isInThisWeek(livr){
const WEEK = new Date()
// convert delivery date to Date instance
const DATEREF = new Date(livr)
// Check if date instance is in valid format (depends on the function arg)
if(DATEREF instanceof Date && isNaN(DATEREF)){
console.log("invalid date format")
return false}
// Deconstruct to get separated date infos
const [dayR, monthR, yearR] = [DATEREF.getDate(), DATEREF.getMonth(), DATEREF.getFullYear()]
// get Monday date
const monday = (WEEK.getDate() - WEEK.getDay()) + 1
// get Saturday date
const sunday = monday + 6
// Start verification
if (yearR !== WEEK.getFullYear()) { console.log("WRONG YEAR"); return false }
if (monthR !== WEEK.getMonth()) { console.log("WRONG MONTH"); return false }
if(dayR >= monday && dayR <= sunday) { return true }
else {console.log("WRONG DAY"); return false}
}

In the comments I saw that you stated that your week starts on Monday.
In that case, I guess it'd be a good idea to calculate the ISO week number of the 2 dates and see if you get the same week number for both of them.
To calculate the ISO week number, check this answer:
In case anyone else's week starts on Sunday instead, you can use this answer to calculate the week number accordingly.
then you can do something like this:
function isSameWeek(date1, date2) {
return date1.getWeekNumber() === date2.getWeekNumber();
}

const isDateInThisWeek = (date) => {
const today = new Date();
//Get the first day of the current week (Sunday)
const firstDayOfWeek = new Date(
today.setDate(today.getDate() - today.getDay())
);
//Get the last day of the current week (Saturday)
const lastDayOfWeek = new Date(
today.setDate(today.getDate() - today.getDay() + 6)
);
//check if my value is between a minimum date and a maximum date
if (date >= firstDayOfWeek && date <= lastDayOfWeek) {
return true;
} else {
return false;
}
};

How to get the 7 days in a week with a currentDate in javascript?

(first, sorry for my bad english, i'm a beginner)
I have a chart of percent by date. I would like to display every day of the current week in the x-axis.
So, i tried to find how to get the seven days of the week.
that's what i have :
var curr = new Date; // get current date
var first = curr.getDate() - curr.getDay();//to set first day on monday, not on sunday, first+1 :
var firstday = (new Date(curr.setDate(first+1))).toString();
for(var i = 1;i<7;i++){
var next = first + i;
var nextday = (new Date(curr.setDate(next))).toString();
alert(nextday);
}
the alert begins well...until the end of the month. That's what i got :
1 : "Mon 27 Feb 2012 ..."
2 : "Tue 28 Feb 2012 ..."
3 : "Wed 29 Feb 2012 ..."
4 : "Thu 01 Mar 2012 ..."
5 : "Sat 31 Mar 2012 ..."
6 : "Sun 01 Apr 2012 ..."
So, as you can see, it switches the friday and... strangely it switch to the good date...4 weeks later...
So, do you have a better solution for me, or maybe you could just help me and say what is the problem.
Thank you!

I'm afraid you have fallen into one of the numerous traps of object mutation. :)
The problem is that, in the line "var nextday = ...", you are changing the date saved in "curr" on every iteration by calling setDate(). That is no problem as long as next is within the range of the current month; curr.setDate(next) is equivalent to going forward one in this case.
The problems begin when next reaches 30. There is no February 30, so setDate() wraps around to the next month, yielding the 1st of March - so far so good. Unfortunately, the next iteration calls curr.setDate(31), and as curr is the 1st of March (remember that the object referenced by curr is changed in each iteration), we get... March 31! The other strange values can be explained the same way.
A way to fix this is to copy curr on each iteration and then call setDate(), like so:
for (var i = 1; i < 7; i++) {
var next = new Date(curr.getTime());
next.setDate(first + i);
alert(next.toString());
}

Thank you all,
I understood that everytime i change the curr value and that was the problem.
All your solutions are working, but i'll prefer the simplest one, the one from #denisw, which I copy there for anybody else with the same problem :
var curr = new Date; // get current date
var first = curr.getDate() - curr.getDay();
var firstday = (new Date(curr.setDate(first+1))).toString();
for(var i = 1; i < 7; i++) {
var next = new Date(curr.getTime());
next.setDate(first+i);
alert(next.toString());
}
Once again, thank you all, for your quick answers and your help!

You can add date and day. The former goes from 1 to 28..31 and the latter from 0 to 6. What should the Date type do if you set the date to -3?
The solution is to convert all values to milliseconds.
var ONE_DAY_IN_MILLIS = 1000*60*60*24;
var curr = new Date();
// Get offset to first day of week
// Note: Depending on your locale, 0 can be Sunday or Monday.
var offset = curr.getDay() * ONE_DAY_IN_MILLIS;
// Date at the start of week; note that hours, minutes and seconds are != 0
var start = new Date( curr.getTime() - offset );
for( var i=0; i<7; i++ ) {
var nextDay = new Date( start.getTime() + ( i * ONE_DAY_IN_MILLIS ) );
...
}

The problem is that you are modifying your curr date and creating a new date at the same time. There are two ways to do this:
Either never modifiy your curr date object and create new Dates:
var msInDay = 1000 * 60 * 60 * 24;
function addDays(date, days) {
return new Date(date.getTime() + days * msInDay);
}
var curr = new Date();
var first = addDays(curr, -curr.getDay() + 1);
alert(first);
for(var i = 1; i<7; i++) {
var next = addDays(first, i);
alert(next);
}
Or modify your curr date object consistently:
var curr = new Date();
curr.setDate(curr.getDate() - curr.getDay() + 1);
alert(curr);
for(var i = 1; i<7; i++) {
curr.setDate(curr.getDate() + 1);
alert(curr);
}
​

let curr = new Date;
let week = []
for (let i = 1; i <= 7; i++) {
let first = curr.getDate() - curr.getDay() + i
let day = new Date(curr.setDate(first)).toISOString().slice(0, 10)
week.push(day)
}
console.log('week:', week);
jsfidde: https://jsfiddle.net/sinh_nguyen/v9kszn2h/4/

JavaScript - get the first day of the week from current date

I need the fastest way to get the first day of the week. For example: today is the 11th of November, and a Thursday; and I want the first day of this week, which is the 8th of November, and a Monday. I need the fastest method for MongoDB map function, any ideas?

Using the getDay method of Date objects, you can know the number of day of the week (being 0=Sunday, 1=Monday, etc).
You can then subtract that number of days plus one, for example:
function getMonday(d) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
return new Date(d.setDate(diff));
}
getMonday(new Date()); // Mon Nov 08 2010

Not sure how it compares for performance, but this works.
var today = new Date();
var day = today.getDay() || 7; // Get current day number, converting Sun. to 7
if( day !== 1 ) // Only manipulate the date if it isn't Mon.
today.setHours(-24 * (day - 1)); // Set the hours to day number minus 1
// multiplied by negative 24
alert(today); // will be Monday
Or as a function:
# modifies _date_
function setToMonday( date ) {
var day = date.getDay() || 7;
if( day !== 1 )
date.setHours(-24 * (day - 1));
return date;
}
setToMonday(new Date());

CMS's answer is correct but assumes that Monday is the first day of the week.
Chandler Zwolle's answer is correct but fiddles with the Date prototype.
Other answers that add/subtract hours/minutes/seconds/milliseconds are wrong because not all days have 24 hours.
The function below is correct and takes a date as first parameter and the desired first day of the week as second parameter (0 for Sunday, 1 for Monday, etc.). Note: the hour, minutes and seconds are set to 0 to have the beginning of the day.
function firstDayOfWeek(dateObject, firstDayOfWeekIndex) {
const dayOfWeek = dateObject.getDay(),
firstDayOfWeek = new Date(dateObject),
diff = dayOfWeek >= firstDayOfWeekIndex ?
dayOfWeek - firstDayOfWeekIndex :
6 - dayOfWeek
firstDayOfWeek.setDate(dateObject.getDate() - diff)
firstDayOfWeek.setHours(0,0,0,0)
return firstDayOfWeek
}
// August 18th was a Saturday
let lastMonday = firstDayOfWeek(new Date('August 18, 2018 03:24:00'), 1)
// outputs something like "Mon Aug 13 2018 00:00:00 GMT+0200"
// (may vary according to your time zone)
document.write(lastMonday)

First / Last Day of The Week
To get the upcoming first day of the week, you can use something like so:
function getUpcomingSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - currentDay + 7);
return new Date(newDate);
}
console.log(getUpcomingSunday());
Or to get the latest first day:
function getLastSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - (currentDay || 7));
return new Date(newDate);
}
console.log(getLastSunday());
* Depending on your time zone, the beginning of the week doesn't has to start on Sunday, it can start on Friday, Saturday, Monday or any other day your machine is set to. Those methods will account for that.
* You can also format it using toISOString method like so: getLastSunday().toISOString()

Check out Date.js
Date.today().previous().monday()

var dt = new Date(); // current date of week
var currentWeekDay = dt.getDay();
var lessDays = currentWeekDay == 0 ? 6 : currentWeekDay - 1;
var wkStart = new Date(new Date(dt).setDate(dt.getDate() - lessDays));
var wkEnd = new Date(new Date(wkStart).setDate(wkStart.getDate() + 6));
This will work well.

I'm using this
function get_next_week_start() {
var now = new Date();
var next_week_start = new Date(now.getFullYear(), now.getMonth(), now.getDate()+(8 - now.getDay()));
return next_week_start;
}

Returns Monday 00am to Monday 00am.
const now = new Date()
const startOfWeek = new Date(now.getFullYear(), now.getMonth(), now.getDate() - now.getDay() + 1)
const endOfWeek = new Date(now.getFullYear(), now.getMonth(), startOfWeek.getDate() + 7)

This function uses the current millisecond time to subtract the current week, and then subtracts one more week if the current date is on a monday (javascript counts from sunday).
function getMonday(fromDate) {
// length of one day i milliseconds
var dayLength = 24 * 60 * 60 * 1000;
// Get the current date (without time)
var currentDate = new Date(fromDate.getFullYear(), fromDate.getMonth(), fromDate.getDate());
// Get the current date's millisecond for this week
var currentWeekDayMillisecond = ((currentDate.getDay()) * dayLength);
// subtract the current date with the current date's millisecond for this week
var monday = new Date(currentDate.getTime() - currentWeekDayMillisecond + dayLength);
if (monday > currentDate) {
// It is sunday, so we need to go back further
monday = new Date(monday.getTime() - (dayLength * 7));
}
return monday;
}
I have tested it when week spans over from one month to another (and also years), and it seems to work properly.

Good evening,
I prefer to just have a simple extension method:
Date.prototype.startOfWeek = function (pStartOfWeek) {
var mDifference = this.getDay() - pStartOfWeek;
if (mDifference < 0) {
mDifference += 7;
}
return new Date(this.addDays(mDifference * -1));
}
You'll notice this actually utilizes another extension method that I use:
Date.prototype.addDays = function (pDays) {
var mDate = new Date(this.valueOf());
mDate.setDate(mDate.getDate() + pDays);
return mDate;
};
Now, if your weeks start on Sunday, pass in a "0" for the pStartOfWeek parameter, like so:
var mThisSunday = new Date().startOfWeek(0);
Similarly, if your weeks start on Monday, pass in a "1" for the pStartOfWeek parameter:
var mThisMonday = new Date().startOfWeek(1);
Regards,

a more generalized version of this... this will give you any day in the current week based on what day you specify.
//returns the relative day in the week 0 = Sunday, 1 = Monday ... 6 = Saturday
function getRelativeDayInWeek(d,dy) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:dy); // adjust when day is sunday
return new Date(d.setDate(diff));
}
var monday = getRelativeDayInWeek(new Date(),1);
var friday = getRelativeDayInWeek(new Date(),5);
console.log(monday);
console.log(friday);

Simple solution for getting the first day of the week.
With this solution, it is possible to set an arbitrary start of week (e.g. Sunday = 0, Monday = 1, Tuesday = 2, etc.).
function getBeginOfWeek(date = new Date(), startOfWeek = 1) {
const result = new Date(date);
while (result.getDay() !== startOfWeek) {
result.setDate(result.getDate() - 1);
}
return result;
}
The solution correctly wraps on months (due to Date.setDate() being used)
For startOfWeek, the same constant numbers as in Date.getDay() can be used

setDate() has issues with month boundaries that are noted in comments above. A clean workaround is to find the date difference using epoch timestamps rather than the (surprisingly counterintuitive) methods on the Date object. I.e.
function getPreviousMonday(fromDate) {
var dayMillisecs = 24 * 60 * 60 * 1000;
// Get Date object truncated to date.
var d = new Date(new Date(fromDate || Date()).toISOString().slice(0, 10));
// If today is Sunday (day 0) subtract an extra 7 days.
var dayDiff = d.getDay() === 0 ? 7 : 0;
// Get date diff in millisecs to avoid setDate() bugs with month boundaries.
var mondayMillisecs = d.getTime() - (d.getDay() + dayDiff) * dayMillisecs;
// Return date as YYYY-MM-DD string.
return new Date(mondayMillisecs).toISOString().slice(0, 10);
}

Here is my solution:
function getWeekDates(){
var day_milliseconds = 24*60*60*1000;
var dates = [];
var current_date = new Date();
var monday = new Date(current_date.getTime()-(current_date.getDay()-1)*day_milliseconds);
var sunday = new Date(monday.getTime()+6*day_milliseconds);
dates.push(monday);
for(var i = 1; i < 6; i++){
dates.push(new Date(monday.getTime()+i*day_milliseconds));
}
dates.push(sunday);
return dates;
}
Now you can pick date by returned array index.

An example of the mathematically only calculation, without any Date functions.
const date = new Date();
const ts = +date;
const mondayTS = ts - ts % (60 * 60 * 24 * (7-4) * 1000);
const monday = new Date(mondayTS);
console.log(monday.toISOString(), 'Day:', monday.getDay());
const formatTS = v => new Date(v).toISOString();
const adjust = (v, d = 1) => v - v % (d * 1000);
const d = new Date('2020-04-22T21:48:17.468Z');
const ts = +d; // 1587592097468
const test = v => console.log(formatTS(adjust(ts, v)));
test(); // 2020-04-22T21:48:17.000Z
test(60); // 2020-04-22T21:48:00.000Z
test(60 * 60); // 2020-04-22T21:00:00.000Z
test(60 * 60 * 24); // 2020-04-22T00:00:00.000Z
test(60 * 60 * 24 * (7-4)); // 2020-04-20T00:00:00.000Z, monday
// So, what does `(7-4)` mean?
// 7 - days number in the week
// 4 - shifting for the weekday number of the first second of the 1970 year, the first time stamp second.
// new Date(0) ---> 1970-01-01T00:00:00.000Z
// new Date(0).getDay() ---> 4

It is important to discern between local time and UTC. I wanted to find the start of the week in UTC, so I used the following function.
function start_of_week_utc(date, start_day = 1) {
// Returns the start of the week containing a 'date'. Monday 00:00 UTC is
// considered to be the boundary between adjacent weeks, unless 'start_day' is
// specified. A Date object is returned.
date = new Date(date);
const day_of_month = date.getUTCDate();
const day_of_week = date.getUTCDay();
const difference_in_days = (
day_of_week >= start_day
? day_of_week - start_day
: day_of_week - start_day + 7
);
date.setUTCDate(day_of_month - difference_in_days);
date.setUTCHours(0);
date.setUTCMinutes(0);
date.setUTCSeconds(0);
date.setUTCMilliseconds(0);
return date;
}
To find the start of the week in a given timezone, first add the timezone offset to the input date and then subtract it from the output date.
const local_start_of_week = new Date(
start_of_week_utc(
date.getTime() + timezone_offset_ms
).getTime() - timezone_offset_ms
);

I use this:
let current_date = new Date();
let days_to_monday = 1 - current_date.getDay();
monday_date = current_date.addDays(days_to_monday);
// https://stackoverflow.com/a/563442/6533037
Date.prototype.addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
}
It works fine.

Accepted answer won't work for anyone who runs the code in UTC-XX:XX timezone.
Here is code which will work regardless of timezone for date only. This won't work if you provide time too. Only provide date or parse date and provide it as input. I have mentioned different test cases at start of the code.
function getDateForTheMonday(dateString) {
var orignalDate = new Date(dateString)
var modifiedDate = new Date(dateString)
var day = modifiedDate.getDay()
diff = modifiedDate.getDate() - day + (day == 0 ? -6:1);// adjust when day is sunday
modifiedDate.setDate(diff)
var diffInDate = orignalDate.getDate() - modifiedDate.getDate()
if(diffInDate == 6) {
diff = diff + 7
modifiedDate.setDate(diff)
}
console.log("Given Date : " + orignalDate.toUTCString())
console.log("Modified date for Monday : " + modifiedDate)
}
getDateForTheMonday("2022-08-01") // Jul month with 31 Days
getDateForTheMonday("2022-07-01") // June month with 30 days
getDateForTheMonday("2022-03-01") // Non leap year February
getDateForTheMonday("2020-03-01") // Leap year February
getDateForTheMonday("2022-01-01") // First day of the year
getDateForTheMonday("2021-12-31") // Last day of the year

Extending answer from #Christian C. Salvadó and information from #Ayyash (object is mutable) and #Awi and #Louis Ameline (set hours to 00:00:00)
The function can be like this
function getMonday(d) {
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
d.setDate(diff);
d.setHours(0,0,0,0); // set hours to 00:00:00
return d; // object is mutable no need to recreate object
}
getMonday(new Date())

Check out: moment.js
Example:
moment().day(-7); // last Sunday (0 - 7)
moment().day(7); // next Sunday (0 + 7)
moment().day(10); // next Wednesday (3 + 7)
moment().day(24); // 3 Wednesdays from now (3 + 7 + 7 + 7)
Bonus: works with node.js too