Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
I want to push an item into an array that in that have objects in them, like this:
var testarray = [
{
first: "See this?",
second: "Oh my!"
},
{
first: "Nice!",
second: "Amazing!"
}
]
You can see that I for this variable/array, I can't just use this testarray.push("Wonderful!"). Please show me how I can push things into these sort of arrays.
The "multiple things" are objects. Push another object in the same format.
testarray.push({first: "Wow!", second: "Wonderful!"});
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed last month.
Improve this question
I have a following data, and I want to convert to list of array without key.
How do I do it?
Data
[{
"time": "01/13 15:50",
"price": 3000,
"changeRate": -0.27
},
{
"time": "01/13 15:40",
"price": 4000,
"changeRate": -0.27
}]
Desired output
[
[01/13 15:50, 3000],
[01/13 15:40, 4000]
]
Thank you in advance!
You can use the map method for that. It's used to transform (or "map") one array into a new one. The new array has the same length as the original, and its items are derived from the items in the original array.
data.map(item => [item.time, item.price]);
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 1 year ago.
Improve this question
I'm trying to add a new item (a placeholder) to an array -- to each node
My array looks as follow:
And I wanna add the following key/value under value Year: "2010"
I have tried *json1.push("Year", "2010")* but that just creates a new entry
If you want to add it to the first object on the array, use
json1[0]["year"] = "2010"
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 2 years ago.
Improve this question
I'M TRYING TO HANDLE THIS DATA IN JAVASCRIPT SO HOW CAN I REMOVE DATA ACCORDING TO THE ID NUMBER THE FIRST NUMBER
600030/01/2018/163904
600010/01/2014/3789
600030/01/2020/47104
600030/01/2012/39104
600010/01/2011/93817
how can i remove all 600030 data so i get
600010/01/2014/3789
600010/01/2011/93817
If all data shaped in Array and element is instance of String.
I would recommend Array.prototype.filter and String.prototype.startsWith();
let data = [
'600030/01/2018/163904',
'600010/01/2014/3789',
'600030/01/2020/47104',
'600030/01/2012/39104',
'600010/01/2011/93817',
];
let filteredData = data.filter((d)=>!d.startsWith('600030'));
console.log( filteredData );
Result is
[
'600010/01/2014/3789',
'600010/01/2011/93817'
]
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 2 years ago.
Improve this question
What I'm doing I'm trying to remove the quotation in array in Java
this is the code
Array [ "johan|39012|manager|2010", "" ]
What I wanna or what I aspect
"johan|39012|manager|2010"
Try this and you will have an array with of good string:
const arr = [ "johan|39012|manager|2010", "" ];
const newArr = arr.filter(item => item.length > 0);
console.log(newArr);
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I need for an Plugin an Object structure like this:
{
"Beer":145.53,
"Apple (red)":7.33,
"Apple (green)":0.03
}
Don't know how to write it that this shine.
I got the all values already so how to set it up like this?
Use this notation to make objects with those properties:
var obj = {};
obj["Beer"] = 145;
obj["Apple (red)"] = 7.5;
....