I have this in a javascript/jQuery string (This string is grabbed from an html ($('#shortcode')) elements value which could be changed if user clicks some buttons)
[csvtohtml_create include_rows="1-10"
debug_mode="no" source_type="visualizer_plugin" path="map"
source_files="bundeslander_staple.csv" include cols="1,2,4" exclude cols="3"]
In a textbox (named incl_sc) I have the value:
include cols="2,4"
I want to replace include_cols="1,2,4" from the above string with the value from the textbox.
so basically:
How do I replace include_cols values here? (include_cols="2,4" instead of include_cols="1,2,4") I'm great at many things but regex is not one of them. I guess regex is the thing to use here?
I'm trying this:
var s = $('#shortcode').html();
//I want to replace include cols="1,2,4" exclude cols="3"
//with include_cols="1,2" exclude_cols="3" for example
s.replace('/([include="])[^]*?\1/g', incl_sc.val() );
but I don't get any replacement at all (the string s is same string as $("#shortcode").html(). Obviously I'm doing something really dumb. Please help :-)
In short what you will need is
s.replace(/include cols="[^"]+"/g, incl_sc.val());
There were a couple problems with your code,
To use a regex with String.prototype.replace, you must pass a regex as the first argument, but you were actually passing a string.
This is a regex literal /regex/ while this isn't '/actually a string/'
In the text you supplied in your question include_cols is written as include cols (with a space)
And your regex was formed wrong. I recomend testing them in this website, where you can also learn more if you want.
The code above will replace the part include cols="1,2,3" by whatever is in the textarea, regardless of whats between the quotes (as long it doesn't contain another quote).
First of all I think you need to remove the quotes and fix a little bit the regex.
const r = /(include_cols=\")(.*)(\")/g;
s.replace(r, `$1${incl_sc.val()}$3`)
Basically, I group the first and last part in order to include them at the end of the replacement. You can also avoid create the first and last group and put it literally in the last argument of the replace function, like this:
const r = /include_cols=\"(.*)\"/g;
s.replace(r, `include_cols="${incl_sc.val()}"`)
Related
I have a text box with a bunch of comments, all separated by a specific character string as a means of splitting them to display each comment individually.
The string in question is | but I can change this to accommodate whatever will work. My only requirement is that it is not likely to be a string of characters someone will type in an everyday sentence.
I believe I need to use the split method and possibly some regex but all the other questions I've seen only seem to mention splitting by one character or a number of different characters, not a specific set of characters in a row.
Can anyone point me in the right direction?
.split() should work for that purpose:
var comments = "this is a comment|and here is another comment|and yet another one";
var parsedComments = comments.split('|');
This will give you all comments in an array which you can then loop over or do whatever you have to do.
Keep in mind you could also change | to something like <--NEWCOMMENT--> and it will still work fine inside the split('<--NEWCOMMENT-->') method.
Remember that split() removes the character it's splitting on, so your resulting array won't contain any instances of <--NEWCOMMENT-->
There may be a very simple answer to this, probably because of my familiarity (or possibly lack thereof) of the replace method and how it works with regex.
Let's say I have the following string: abcdefHellowxyz
I just want to strip the first six characters and the last four, to return Hello, using regex... Yes, I know there may be other ways, but I'm trying to explore the boundaries of what these methods are capable of doing...
Anyway, I've tinkered on http://regex101.com and got the following Regex worked out:
/^(.{6}).+(.{4})$/
Which seems to pass the string well and shows that abcdef is captured as group 1, and wxyz captured as group 2. But when I try to run the following:
"abcdefHellowxyz".replace(/^(.{6}).+(.{4})$/,"")
to replace those captured groups with "" I receive an empty string as my final output... Am I doing something wrong with this syntax? And if so, how does one correct it, keeping my original stance on wanting to use Regex in this manner...
Thanks so much everyone in advance...
The code below works well as you wish
"abcdefHellowxyz".replace(/^.{6}(.+).{4}$/,"$1")
I think that only use ()to capture the text you want, and in the second parameter of replace(), you can use $1 $2 ... to represent the group1 group2.
Also you can pass a function to the second parameter of replace,and transform the captured text to whatever you want in this function.
For more detail, as #Akxe recommend , you can find document on https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace.
You are replacing any substring that matches /^(.{6}).+(.{4})$/, with this line of code:
"abcdefHellowxyz".replace(/^(.{6}).+(.{4})$/,"")
The regex matches the whole string "abcdefHellowxyz"; thus, the whole string is replaced. Instead, if you are strictly stripping by the lengths of the extraneous substrings, you could simply use substring or substr.
Edit
The answer you're probably looking for is capturing the middle token, instead of the outer ones:
var str = "abcdefHellowxyz";
var matches = str.match(/^.{6}(.+).{4}$/);
str = matches[1]; // index 0 is entire match
console.log(str);
I'm trying to improve my understanding of Regex, but this one has me quite mystified.
I started with some text defined as:
var txt = "{\"columns\":[{\"text\":\"A\",\"value\":80},{\"text\":\"B\",\"renderer\":\"gbpFormat\",\"value\":80},{\"text\":\"C\",\"value\":80}]}";
and do a replace as follows:
txt.replace(/\"renderer\"\:(.*)(?:,)/g,"\"renderer\"\:gbpFormat\,");
which results in:
"{"columns":[{"text":"A","value":80},{"text":"B","renderer":gbpFormat,"value":80}]}"
What I expected was for the renderer attribute value to have it's quotes removed; which has happened, but also the C column is completely missing! I'd really love for someone to explain how my Regex has removed column C?
As an extra bonus, if you could explain how to remove the quotes around any value for renderer (i.e. so I don't have to hard-code the value gbpFormat in the regex) that'd be fantastic.
You are using a greedy operator while you need a lazy one. Change this:
"renderer":(.*)(?:,)
^---- add here the '?' to make it lazy
To
"renderer":(.*?)(?:,)
Working demo
Your code should be:
txt.replace(/\"renderer\"\:(.*?)(?:,)/g,"\"renderer\"\:gbpFormat\,");
If you are learning regex, take a look at this documentation to know more about greedyness. A nice extract to understand this is:
Watch Out for The Greediness!
Suppose you want to use a regex to match an HTML tag. You know that
the input will be a valid HTML file, so the regular expression does
not need to exclude any invalid use of sharp brackets. If it sits
between sharp brackets, it is an HTML tag.
Most people new to regular expressions will attempt to use <.+>. They
will be surprised when they test it on a string like This is a
first test. You might expect the regex to match and when
continuing after that match, .
But it does not. The regex will match first. Obviously not
what we wanted. The reason is that the plus is greedy. That is, the
plus causes the regex engine to repeat the preceding token as often as
possible. Only if that causes the entire regex to fail, will the regex
engine backtrack. That is, it will go back to the plus, make it give
up the last iteration, and proceed with the remainder of the regex.
Like the plus, the star and the repetition using curly braces are
greedy.
Try like this:
txt = txt.replace(/"renderer":"(.*?)"/g,'"renderer":$1');
The issue in the expression you were using was this part:
(.*)(?:,)
By default, the * quantifier is greedy by default, which means that it gobbles up as much as it can, so it will run up to the last comma in your string. The easiest solution would be to turn that in to a non-greedy quantifier, by adding a question mark after the asterisk and change that part of your expression to look like this
(.*?)(?:,)
For the solution I proposed at the top of this answer, I also removed the part matching the comma, because I think it's easier just to match everything between quotes. As for your bonus question, to replace the matched value instead of having to hardcode gbpFormat, I used a backreference ($1), which will insert the first matched group into the replacement string.
Don't manipulate JSON with regexp. It's too likely that you will break it, as you have found, and more importantly there's no need to.
In addition, once you have changed
'{"columns": [..."renderer": "gbpFormat", ...]}'
into
'{"columns": [..."renderer": gbpFormat, ...]}' // remove quotes from gbpFormat
then this is no longer valid JSON. (JSON requires that property values be numbers, quoted strings, objects, or arrays.) So you will not be able to parse it, or send it anywhere and have it interpreted correctly.
Therefore you should parse it to start with, then manipulate the resulting actual JS object:
var object = JSON.parse(txt);
object.columns.forEach(function(column) {
column.renderer = ghpFormat;
});
If you want to replace any quoted value of the renderer property with the value itself, then you could try
column.renderer = window[column.renderer];
Assuming that the value is available in the global namespace.
This question falls into the category of "I need a regexp, or I wrote one and it's not working, and I'm not really sure why it has to be a regexp, but I heard they can do all kinds of things, so that's just what I imagined I must need." People use regexps to try to do far too many complex matching, splitting, scanning, replacement, and validation tasks, including on complex languages such as HTML, or in this case JSON. There is almost always a better way.
The only time I can imagine wanting to manipulate JSON with regexps is if the JSON is broken somehow, perhaps due to a bug in server code, and it needs to be fixed up in order to be parseable.
I've researched stackoverflow and find similar results but it is not really what I wanted.
Given an xml string: "<a b=\"c\"></a>" in javascript context, I want to create a regex that will capture the attribute value including the quotation marks.
NOTE: this is similar if you're using single quotation marks.
Currently I have a regular expression tailored to the XML specification:
[_A-Za-z][\w\.\-]*(?:=\"[^\"]*\")?
[_A-Za-z][\w\.\-]* //This will match the attribute name.
(?:=\"[^\"]*\")? //This will match the attribute value.
\"[^\"]*\" //This part concerns me.
My question now is, what if the xml string looks like this:
<shout statement="Hi! \"Richeve\"."></shout>
I know this is a dumb question to ask but I just want to capture rare cases that this scenario might happen (I know the coder can use single quotes on this scenario) but there are cases that we don't know the current value of the attribute given that the attribute value changes dynamically at runtime.
So to make this clearer, the result of that using the correct regex should be:
"Hi! \"Richeve\"."
I hope my question is clear. Thanks for all the help!
PS: Note that the language context is Javascript and I know it is tempting to use lookbehinds but currently lookbehinds are not supported.
PS: I know it is really hard to parse XML but I have an elegant solution to this :) so I just need this small problem to be solved. So this problem only main focus is capturing quotation marked string tokens containing quotation marks inside the string token.
The standard pattern for content with matching delimiters and embedded escaped delimiters goes like this:
"[^"\\]*(?:\\.[^"\\]*)*"
Ignoring the obvious first and last characters in the pattern, here's how the rest of the pattern works:
[^"\\]*: Consume all characters until a delimiter OR backslash (matching Hi! in your example)
(?:\\.[^"\\]*)* Try to consume a single escaped character \\. followed by a series of non delimiter/backslash characters, repeatedly (matching \"Richeve first and then \". next in your example)
That's it.
You can try to use a more generic delimiter approach using (['"]) and back references, or you can just allow for an alternate pattern with single quotes like so:
("[^"\\]*(?:\\.[^"\\]*)*"|'[^'\\]*(?:\\.[^'\\]*)*')
Here's another description of this technique that might also help (see the section called Strings): http://www.regular-expressions.info/examplesprogrammer.html
Description
I'm pretty really sure embedding double quotes inside a double quoted attribute value is not legal. You could use the unicode equivalent of a double quote \x22 inside the value.
However to answer the question, this expression will:
allow escaped quotes inside attribute values
capture the attribute statement 's value
allow attributes to appear in any order inside the tag
will avoid many of the edge cases which will trip up pattern matching inside html text
doesn't use lookbehinds
<shout\b(?=\s)(?=(?:[^>=]|='(?:[^']|\\')*'|="(?:[^"]|\\")*"|=[^'"][^\s>]*)*?\sstatement=(['"])((?:\\['"]|.)*?)\1(?:\s|\/>|>))(?:[^>=]|='(?:[^']|\\')*'|="(?:[^"]|\\")*"|=[^'"][^\s>]*)*>.*?<\/shout>
Example
Pretty Rubular
Ugly RegexPlanet set to Javascript
Sample Text
Note the difficult edge case in the first attribute :)
<shout onmouseover=' statement="He said \"I am Inside the onMouseOver\" " ; if ( 6 > a ) { funRotate(statement) } ; ' statement="Hi! \"Richeve\"." title="sometitle">SomeString</shout>
Matches
Group 0 gets the entire tag from open to close
Group 1 gets the quote surrounding the statement attribute value, this is used to match the closing quote correctly
Group 2 gets the statement attribute value which may include escaped quotes like \" but not including the surrounding quotes
[0][0] = <shout onmouseover=' statement="He said \"I am Inside the onMouseOver\" " ; if ( 6 > a ) { funRotate(statement) } ; ' statement="Hi! \"Richeve\"." title="sometitle">SomeString</shout>
[0][1] = "
[0][2] = Hi! \"Richeve\".
Quick. I have a string: #user 9#I'm alive! and I want to be about to pull out "user 9".
So far Im doing:
if(variable.match(/\#/g)){
console.log(variable):
}
But the output is still the full line.
Use .split(), in order to pull out your desired item.
var variable = variable.split("#");
console.log(variable[1]);
.split() turns your string into an array, with the first variable as a separator.
Of course, if you just want regex alone, you could do:
console.log(variable.match(/([^#]+)/g));
This will again give you an array of the items, but a smaller one as it doesn't use the empty value before the hash as an item. Further, as stated by #Stephen P, you will need to use a capture group(()) to capture the items you want.
Try something more along these lines...
var thetext="#user 9#I'm alive!";
thetext.match(/\#([^#]+)\#/g);
You want to introduce a capturing group (the part in the parentheses) to collect the text in between the pound signs.
You may want to use .exec() instead of .match() depending on what you're doing.
Also see this answer to the SO question "How do you access the matched groups in a javascript regex?"