Clamping an arrow with a circle shape for mini map - javascript

I'm currently working on a mini map for a game in which keeps track of different items of importance on and off the screen. When I first created the mini map through a secondary camera rendered onto a texture and displayed on screen in a miniature display, it was rectangle shape. I was able to ensure when the item of importance left the view of the map, an arrow pointing to the target showed up and remained on the edge of the map. It was basically clamping the x & y positions of the arrow to half the camera view's width and length (with some suitable margin space).
Anyway. Now I am trying to make the mini map circular and while I have the proper render mask on to guarantee that shape of the mini map, I am having difficulties in clamping the arrows to the shape of the new mini-map. In the rectangular mini map, the arrows stayed in the corners while clamped, but obviously, circles don't have corners.
I am thinking clamping the arrow's x & y positions have to do with the radius of the circle (half of the height of the screen/minimap), but because I'm a little weak on the math side, I am kindly requesting some help. How would I clamp the arrows to the edge of a new circle shape?
The code I have now is as follows:
let {width: canvasWidth, height: canvasHeight} = cc.Canvas.instance.node, // 960, 640
targetScreenPoint = cc.Camera.main.getWorldToScreenPoint(this.targetNode.position)
// other code for rotation of arrow, etc...
// FIXME: clamp the the edge of the minimap mask which is circular
// This is the old clamping code for a rectangle shape.
let arrowPoint = targetScreenPoint;
arrowPoint.x = utils.clamp(arrowPoint.x, (-canvasWidth / 2) + this.arrowMargin,
(canvasWidth / 2) - this.arrowMargin);
arrowPoint.y = utils.clamp(arrowPoint.y, (-canvasHeight / 2) + this.arrowMargin,
(canvasHeight /2) - this.arrowMargin);
this.node.position = cc.v2(arrowPoint.x, arrowPoint.y);
I should probably also note that all mini-map symbols and arrows technically are on screen but only are displayed in on the secondary camera through a culling mask... you know, just in case it helps.

Just for anyone else looking to do the same, I basically normalized the direction from the target node that the arrow points at and multiplied it by the radius of the image mask (with appropriate margin space).
Since the player node and the centre of the mask is at origin, I just got the difference from the player. The (640/2) is the diameter, which of course, shouldn't be hardcoded, but meh for now. Thanks to those who commented and got me thinking in the right direction.
let direction = this.targetNode.position.sub(this.playerNode.position).normalize();
let arrowPos = direction.mul((640/2) - this.arrowMargin);
this.node.position = arrowPos;

Related

How are the bounds calculated in the Leaflet CRS.Simple tutorial?

In the example in Leaflet (for non geographic image), they set "bounds". I am trying to understand how they computed the values
var bounds = [[-26.5,-25], [1021.5,1023]];
The origin is bottom-left and y increases upwards / x towards the right. How did negative numbers turn up here? Also, after experimentation, I see that the actual pixel coordinates change if you specify different coordinates for bounds. I have a custom png map which I would like to use but I am unable to proceed due to this.
Oh, you mean this image:
If you open the full file (available at https://github.com/Leaflet/Leaflet/blob/v1.4.0/docs/examples/crs-simple/uqm_map_full.png ) with an image editor, you'll see that it measures 2315x2315 pixels. Now, the pixel that represents the (0,0) coordinate is not at a corner of the image, but rather 56 pixels away from the lower-left corner of the image:
Similarly, the (1000, 1000) coordinate is about 48 pixels from the top-right corner of the image:
Therefore, if we measure pixel coordinates of the grid corners:
Game coordinate (0, 0) → Pixel coordinate (59, 56)
Game coordinate (1000, 1000) → Pixel coordinate (2264, 2267)
The problem here is finding the bounds (measured in game coordinates) of the image. Or, in other words:
Pixel coordinate (0, 0) → Game coordinate (?, ?)
Pixel coordinate (2315, 2315) → Game coordinate (?, ?)
We know that the pixel-to-game-coordinate ratio is constant, we know the image size and the distance to the coordinates grid, so we can infer stuff:
1000 horizontal game units = image width - left margin - right margin
or
1000 horizontal game units = 2315px - 56px - 48px = 2213px
therefore the pixel/game unit ratio is
2213px / 1000 game units = 2.213 px/unit
therefore the left margin is...
~59px = ~59px / (2.213px/unit) ~= 26.66 game units
...therefore the left edge of the image is at ~ -26.66 game units. Idem for the right margin...
~51px = ~51px / (2.213px/unit) = ~23.04 game units
...therefore the right edge of the image is at ~1023.04 game units
Repeating that for the top and bottom margins we can fill up all the numbers:
Pixel coordinate (0, 0) → Game coordinate (-26.66, -25)
Pixel coordinate (2315, 2315) → Game coordinate (1023.04, 1025)
Why don't these numbers match the ones in the example exactly? Because I might have used a different pixel for measurement when I wrote that Leaflet tutorial. Still, the error is negligible.
Let me remark a sentence from that tutorial:
One common mistake when using CRS.Simple is assuming that the map units equal image pixels. In this case, the map covers 1000x1000 units, but the image is 2315x2315 pixels big. Different cases will call for one pixel = one map unit, or 64 pixels = one map unit, or anything. Think in map units in a grid, and then add your layers (L.ImageOverlays, L.Markers and so on) accordingly.
If you have your own game map (or anything else), you should ask yourself: Where is the (0,0) coordinate? What are the coordinates of the image edges in the units I'm gonna use?

Scaling and repositioning with SVG.js difficulties

I’m using svg.js to manipulate SVGs within the browser. Most of what I’m doing is relatively simple, but I’m having some difficulties with scaling/positioning a few objects.
I have an SVG that contains a “Pin” icon. You can click on the SVG to zoom it (which just resizes it to fill the browser viewport), in turn resizing all of its children, including the Pin. I need to scale this icon back down to its original size of 36px x 36px and reposition it so the bottom center of the Pin sits where it originally sat. I’ve got the resizing down, but the repositioning piece escapes me.
Some example states:
Scaled at 100% with Pin at base size of 36px x 36px.
Scaled up by 9.77241379 with pin scaled down to its base size of 36px x 36px. Using svg.js the scale() method scales at the center point of the pin, leaving it floating in space.
What I’m using to scale the Pin when the parent container is scaled up:
scaleHotspot(hotspot) {
const child = hotspot.first();
const bbox = child.bbox();
const rbox = child.rbox();
const scale = bbox.w / rbox.w;
hotspot.scale(scale);
}
Because the Pin is scaled using its center point it’s now sitting up higher than it’s supposed to be. I need to determine how much to move the Pin down to have the point of the Pin sitting in its original position.
I originally thought this worked but testing in various places yielded strange results.
const newY = -(bbox.height / 2 - (bbox.height - (1 / scale)));
Suggestions around getting the Pin positioned so that its bottom center point sits where the unscaled version was?
With .transform(), you can define a center around which to scale. Use .bbox() to find that point in current user space. Since these coordinates already include pre-existing transformations, set the relative flag to add the scaling on top:
scaleHotspot(hotspot) {
const bbox = hotspot.bbox();
const rbox = hotspot.rbox();
const scale = bbox.w / rbox.w;
const center = bbox.x + bbox.w / 2;
const bottom = bbox.y + bbox.h;
hotspot.transform({scale: scale, cx: center, cy: bottom}, true);
}

Snap SVG rotate & scale

I'm trying to scale and then rotate a triangle and then translate it to a given point in Snap SVG.
I want to rotate the triangle around the top of it not the center, so i can build something like a pie.
So I thought I scale first, then rotate and later translate.
var t = new Snap.Matrix();
t.scale(0.5);
t.rotate(45, bbox.cx, (bbox.cy-(bbox.h/2)));
But the scale and rotation somehow are allways a bit off.
I reused a jsfiddle I found and updated it, so you can see what I try:
http://jsfiddle.net/AGq9X/477/
Somehow the bbox.cx and bbox.cy are not in the center of the triangle.
On my local setup they are.
The strange thing is, just rotation without scaleing works fine,
but scaling and then roation always seems to be a bit off on the y axis, the triangle doesn't stays at the rotation point.
Any ideas how i can fix that?
EDIT:
Ok I found the Solution,thanks to lan, you were right, the center of scaleing is important, and
I thought it was useing the center of the object, but it was the upper left corner. I adjusted it
and now it works greate:
var bbox = obj.getBBox(); //get coords etc. of triangle object
var t = new Snap.Matrix();
var offset = (bbox.cy+(bbox.h)) - centerY; //translate Y to center,
//depends on scaleing factor (0.5 = bbox.h, 0.25 = bbox.h*2)
t.scale(0.5, 0.5, bbox.cx, (bbox.cy+(bbox.h/2))); //scale object
t.translate(0,-offset); //translate to center
t.rotate(45, bbox.cx, (bbox.cy+(bbox.h/2))); //rotate object
obj.transform(t); //apply transformation to object
EDIT2:
I wanted to know how to save transformation, so you don't need to apply them every time you use a new transformation. Ian recommended to use element.transform() like so to get the old transformations:
element.transform( element.transform() + 's2,2' )
This is slightly more complicated than one would expect, but you would be animating a matrix, which does some odd things sometimes.
Personally I would use Snaps alternate animate method Snap.animate() and not using a matrix. Set the scale first and then build your animation string.
Something like..
var triangle2 = p.select("#myShape2").transform('s0.5');
...
Snap.animate(0,90,function( val ) {
triangle2.transform('r'+ val + ',' + bbox.cx+','+(bbox.cy-(bbox.h/2))+'s0.5')
}, 2000)
jsfiddle

How to rotate image - canvas pixel manipulation?

I use getImageData and putImageData to draw on canvas from a buffer canvas. I use these methods because I have a large number of particles and these proved to provide the best performance.
Now I'd like to add rotation of particles but I'm having problems with that.
Here is a jsfiddle which uses transformation matrix for rotation. As you can see in the picture (or fiddle) there are holes in the resulting image which I kinda expected from using this matrix.
nx = ~~ (xx * Math.cos(angle) + yy * Math.sin(angle) + cx);
ny = ~~ (xx * Math.sin(angle) - yy * Math.cos(angle) + cy);
But I don't know how to make this better, especially when I'm looking performance effecient solution?
jsfiddle demo
Image - square after rotation (square is used as a simple body):
Currently my backup is procedurally generated sprite animation which is prepared in advance with standard canvas states: save -> translate -> rotate -> restore.
Thank you very much for any directions you can give me.
The problem is that you are trying to map a single pixel to a single pixel. When you rotate an image, each pixel in the original can influence any of the surrounding pixels in the new image. You are effectively mapping the top left corner of each pixel to it's location in the new image, but you need map the center of each pixel to it's location in the new image and then check the overlap of this rotated pixel with that location, and the 8 surrounding pixels in the new image.
Here you can see the effect. The yellow dots are the centers of the pixel which find the "home" location for the pixel (i.e. where the majority of the influence will be placed). You then need to figure out the percentage of that pixel (the underlying blue/white grid) cell is covered by the original pixel (black box surrounding the yellow dot). Once you figure out the home location influence, you need to repeat that process for the 8 surrounding pixel with respect to current pixel in the original image. In your current code, you are using the top left corner of each pixel to find the home pixel for the new image. You should use the center of the pixel.
Since multiple iterations might affect the same pixel, you'll need to calculate the transformation in a buffer before drawing it to the final image. For pixels in the transformation that are not fully covered by pixels in the original image, figure out the percentage of the pixel that is covered and use that to influence the alpha channel. You'll have to take care when applying the pixels to the final image that you account for the alpha portion and blend with what's already there.

Isometric Screen to Map

I'm trying to figure out how I can get the correct "active" tile under the mouse when I have "ramp" and +1 height tiles (see picture below).
When my world is flat, everything works no problem. Once I add a tile with a height of say +1, along with a ramp going back to +0, my screen -> map routine is still looking as if everything is "flat".
In the picture above, the green "ramp" is the real tile I want to render and calculate mouse -> map, however the blue tile you see "below" it is the area which gets calculated. So if you move your mouse into any of the dark green areas, it thinks you're on another tile.
Here is my map render (very simple)
canvas.width = canvas.width; // cheap clear in firefox 3.6, does not work in other browsers
for(i=0;i<map_y;i++){
for(j=0;j<map_x;j++){
var xpos = (i-j)*tile_h + current_x;
var ypos = (i+j)*tile_h/2+ current_y;
context.beginPath();
context.moveTo(xpos, ypos+(tile_h/2));
context.lineTo(xpos+(tile_w/2), ypos);
context.lineTo(xpos+(tile_w), ypos+(tile_h/2));
context.lineTo(xpos+(tile_w/2), ypos+(tile_h));
context.fill();
}
}
And here is my mouse -> map routine:
ymouse=( (2*(ev.pageY-canvas.offsetTop-current_y)-ev.pageX+canvas.offsetLeft+current_x)/2 );
xmouse=( ev.pageX+ymouse-current_x-(tile_w/2)-canvas.offsetLeft );
ymouse=Math.round(ymouse/tile_h);
xmouse=Math.round(xmouse/(tile_w/2));
current_tile=[xmouse,ymouse];
I have a feeling I'll have to start over and implement a world based map system rather than a simple screen -> map routine.
Thanks.
Your assumption is correct. In order to "pick" against world geometry, your routine needs to be aware of the world (and not just the base-level tile configuration). That is, without any concept of the height of the tiles near the one that is currently picked (by your current algorithm), there's no way to determine whether a neighboring tile (or one even further away, depending on the permitted height) should be intercepted by picking ray.
You've got the final possible point of your picking ray, already. What remains is to define the remainder of the ray, in world-space, and to check that ray for intersections with world geometry.
If, like the picture, your view angle is always 45 degrees and always from the same direction, your mouse -> map routine could use an algorithm something like:
calculate i,j of tile as you're doing currently (your final value of xmouse, ymouse)
look up height and angle of tile at i,j
given the height and angle, does this tile intersect the picking ray? If so, set lasti, lastj = i, j
increment/decrement i,j one step diagonally toward viewer
have we fallen off the edge of the map? If so, return lasti, lastj. Otherwise go back to 2.
Depending on the maximum height of a tile, you might have to check only 2 tiles, rather than going all the way to the edge of the map.
3 is the tricky part, and depends on your world geometry. Draw some triangles and you should be able to figure it out. Or you might try looking at the function intersect_quadrilateral_ray() here.

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