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How can I convert seconds to an HH-MM-SS string using JavaScript?
You can manage to do this without any external JavaScript library with the help of JavaScript Date method like following:
const date = new Date(null);
date.setSeconds(SECONDS); // specify value for SECONDS here
const result = date.toISOString().slice(11, 19);
Or, as per #Frank's comment; a one liner:
new Date(SECONDS * 1000).toISOString().slice(11, 19);
Updated (2020):
Please use #Frank's one line solution:
new Date(SECONDS * 1000).toISOString().substring(11, 16)
If SECONDS<3600 and if you want to show only MM:SS then use below code:
new Date(SECONDS * 1000).toISOString().substring(14, 19)
It is by far the best solution.
Old answer:
Use the Moment.js library.
I don't think any built-in feature of the standard Date object will do this for you in a way that's more convenient than just doing the math yourself.
hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;
Example:
let totalSeconds = 28565;
let hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
let minutes = Math.floor(totalSeconds / 60);
let seconds = totalSeconds % 60;
console.log("hours: " + hours);
console.log("minutes: " + minutes);
console.log("seconds: " + seconds);
// If you want strings with leading zeroes:
minutes = String(minutes).padStart(2, "0");
hours = String(hours).padStart(2, "0");
seconds = String(seconds).padStart(2, "0");
console.log(hours + ":" + minutes + ":" + seconds);
I know this is kinda old, but...
ES2015:
var toHHMMSS = (secs) => {
var sec_num = parseInt(secs, 10)
var hours = Math.floor(sec_num / 3600)
var minutes = Math.floor(sec_num / 60) % 60
var seconds = sec_num % 60
return [hours,minutes,seconds]
.map(v => v < 10 ? "0" + v : v)
.filter((v,i) => v !== "00" || i > 0)
.join(":")
}
It will output:
toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18
As Cleiton pointed out in his answer, moment.js can be used for this:
moment().startOf('day')
.seconds(15457)
.format('H:mm:ss');
Here's a simple function for converting times that might help
function formatSeconds(seconds) {
var date = new Date(1970,0,1);
date.setSeconds(seconds);
return date.toTimeString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}
This does the trick:
function secondstotime(secs)
{
var t = new Date(1970,0,1);
t.setSeconds(secs);
var s = t.toTimeString().substr(0,8);
if(secs > 86399)
s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
return s;
}
(Sourced from here)
var timeInSec = "661"; //even it can be string
String.prototype.toHHMMSS = function () {
/* extend the String by using prototypical inheritance */
var seconds = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(seconds / 3600);
var minutes = Math.floor((seconds - (hours * 3600)) / 60);
seconds = seconds - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
alert("5678".toHHMMSS()); // "01:34:38"
console.log(timeInSec.toHHMMSS()); //"00:11:01"
we can make this function lot shorter and crisp but that decreases the readability, so we will write it as simple as possible and as stable as possible.
or you can check this working here:
Try this:
function toTimeString(seconds) {
return (new Date(seconds * 1000)).toUTCString().match(/(\d\d:\d\d:\d\d)/)[0];
}
I think the most general (and cryptic) solution could be this
function hms(seconds) {
return [3600, 60]
.reduceRight(
(pipeline, breakpoint) => remainder =>
[Math.floor(remainder / breakpoint)].concat(pipeline(remainder % breakpoint)),
r => [r]
)(seconds)
.map(amount => amount.toString().padStart(2, '0'))
.join('-');
}
Or to copy & paste the shortest version
function hms(seconds) {
return [3600, 60]
.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(seconds)
.map(a => a.toString().padStart(2, '0'))
.join('-');
}
Some example outputs:
> hms(0)
< "00-00-00"
> hms(5)
< "00-00-05"
> hms(60)
< "00-01-00"
> hms(3785)
< "01-03-05"
> hms(37850)
< "10-30-50"
> hms(378500)
< "105-08-20"
How it works
Algorithm
To get hours you divide total seconds by 3600 and floor it.
To get minutes you divide remainder by 60 and floor it.
To get seconds you just use the remainder.
It would also be nice to keep individual amounts in an array for easier formatting.
For example given the input of 3785s the output should be [1, 3, 5], that is 1 hour, 3 minutes and 5 seconds.
Creating pipeline
Naming the 3600 and 60 constants "breakpoints" you can write this algorithm into function as this
function divideAndAppend(remainder, breakpoint, callback) {
return [Math.floor(remainder / breakpoint)].concat(callback(remainder % breakpoint));
}
It returns an array where first item is the amount for given breakpoint and the rest of the array is given by the callback.
Reusing the divideAndAppend in callback function will give you a pipeline of composed divideAndAppend functions. Each one of these
computes amount per given breakpoint and append it to the array making your desired output.
Then you also need the "final" callback that ends this pipeline. In another words you used all breakpoints and now you have only the remainder.
Since you have already the answer at 3) you should use some sort of identity function, in this case remainder => [remainder].
You can now write the pipeline like this
let pipeline = r3 => divideAndAppend(
r3,
3600,
r2 => divideAndAppend(
r2,
60,
r1 => [r1]));
> pipeline(3785)
< [1, 3, 5]
Cool right?
Generalizing using for-loop
Now you can generalize with a variable amount of breakpoints and create a for-loop that will compose individial divideAndAppend functions into
the pipeline.
You start with the identity function r1 => [r1], then use the 60 breakpoint and finally use the 3600 breakpoint.
let breakpoints = [60, 3600];
let pipeline = r => [r];
for (const b of breakpoints) {
const previousPipeline = pipeline;
pipeline = r => divideAndAppend(r, b, previousPipeline);
}
> pipeline(3785)
< [1, 3, 5]
Using Array.prototype.reduce()
Now you can rewrite this for-loop into reducer for shorter and more functional code. In other words rewrite function composition into the reducer.
let pipeline = [60, 3600].reduce(
(ppln, b) => r => divideAndAppend(r, b, ppln),
r => [r]
);
> pipeline(3785)
< [1, 3, 5]
The accumulator ppln is the pipeline and you are composing it using the previous version of it. The initial pipeline is r => [r].
You can now inline the function divideAndAppend and use Array.prototype.reduceRight which is the same as [].reverse().reduce(...) to make the breakpoints
definitions more natural.
let pipeline = [3600, 60]
.reduceRight(
(ppln, b) => r => [Math.floor(r / b)].concat(ppln(r % b)),
r => [r]
);
Which is the final form. Then you just appy mapping to string with padded 0's on left and join the strings with : separator;
More generalizations
Wrapping the reducer into function
function decompose(total, breakpoints) {
return breakpoints.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(total);
}
> decompose(3785, [3600, 60])
< [1, 3, 5]
you now have very general algorithm you can work with. For example:
Convert easily (the weird) us length standards
Given the standards
Unit
Divisions
1 foot
12 inches
1 yard
3 feet
1 mile
1760 yards
> decompose(123_456, [1760 * 3 * 12, 3 * 12, 12])
< [1, 1669, 1, 0]
123456 in = 1 mi, 1669 yd, 1 feet and 0 in
Or you can somewhat convert to decimal or binary representations
> decompose(123_456, [100_000, 10_000, 1000, 100, 10])
< [1, 2, 3, 4, 5, 6]
> decompose(127, [128, 64, 32, 16, 8, 4, 2])
< [0, 1, 1, 1, 1, 1, 1, 1]
Works also with floating point breakpoints
Since Javascript supports mod operator with floating point numbers, you can also do
> decompose(26.5, [20, 2.5])
< [1, 2, 1.5]
The edge case of no breakpoints is also naturally covered
> decompose(123, [])
< [123]
Here is an extension to Number class. toHHMMSS() converts seconds to an hh:mm:ss string.
Number.prototype.toHHMMSS = function() {
var hours = Math.floor(this / 3600) < 10 ? ("00" + Math.floor(this / 3600)).slice(-2) : Math.floor(this / 3600);
var minutes = ("00" + Math.floor((this % 3600) / 60)).slice(-2);
var seconds = ("00" + (this % 3600) % 60).slice(-2);
return hours + ":" + minutes + ":" + seconds;
}
// Usage: [number variable].toHHMMSS();
// Here is a simple test
var totalseconds = 1234;
document.getElementById("timespan").innerHTML = totalseconds.toHHMMSS();
// HTML of the test
<div id="timespan"></div>
Easy to follow version for noobies:
var totalNumberOfSeconds = YOURNUMBEROFSECONDS;
var hours = parseInt( totalNumberOfSeconds / 3600 );
var minutes = parseInt( (totalNumberOfSeconds - (hours * 3600)) / 60 );
var seconds = Math.floor((totalNumberOfSeconds - ((hours * 3600) + (minutes * 60))));
var result = (hours < 10 ? "0" + hours : hours) + ":" + (minutes < 10 ? "0" + minutes : minutes) + ":" + (seconds < 10 ? "0" + seconds : seconds);
console.log(result);
This function should do it :
var convertTime = function (input, separator) {
var pad = function(input) {return input < 10 ? "0" + input : input;};
return [
pad(Math.floor(input / 3600)),
pad(Math.floor(input % 3600 / 60)),
pad(Math.floor(input % 60)),
].join(typeof separator !== 'undefined' ? separator : ':' );
}
Without passing a separator, it uses : as the (default) separator :
time = convertTime(13551.9941351); // --> OUTPUT = 03:45:51
If you want to use - as a separator, just pass it as the second parameter:
time = convertTime(1126.5135155, '-'); // --> OUTPUT = 00-18-46
See also this Fiddle.
Chiming in on this old thread -- the OP stated HH:MM:SS, and many of the solutions work, until you realize you need more than 24 hours listed. And maybe you don't want more than a single line of code. Here you go:
d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}
It returns H+:MM:SS. To use it, simply use:
d(91260); // returns "25:21:00"
d(960); // returns "0:16:00"
...I tried to get it to use the least amount of code possible, for a nice one-liner approach.
For the special case of HH:MM:SS.MS (eq: "00:04:33.637") as used by FFMPEG to specify milliseconds.
[-][HH:]MM:SS[.m...]
HH expresses the number of hours, MM the number of minutes for a
maximum of 2 digits, and SS the number of seconds for a maximum of 2
digits. The m at the end expresses decimal value for SS.
/* HH:MM:SS.MS to (FLOAT)seconds ---------------*/
function timerToSec(timer){
let vtimer = timer.split(":")
let vhours = +vtimer[0]
let vminutes = +vtimer[1]
let vseconds = parseFloat(vtimer[2])
return vhours * 3600 + vminutes * 60 + vseconds
}
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
/* Example: 7hours, 4 minutes, 33 seconds and 637 milliseconds */
const t = "07:04:33.637"
console.log(
t + " => " +
timerToSec(t) +
"s"
)
/* Test: 25473 seconds and 637 milliseconds */
const s = 25473.637 // "25473.637"
console.log(
s + "s => " +
secToTimer(s)
)
Example usage, a milliseconds transport timer:
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
let job, origin = new Date().getTime()
const timer = () => {
job = requestAnimationFrame(timer)
OUT.textContent = secToTimer((new Date().getTime() - origin) / 1000)
}
requestAnimationFrame(timer)
span {font-size:4rem}
<span id="OUT"></span>
<br>
<button onclick="origin = new Date().getTime()">RESET</button>
<button onclick="requestAnimationFrame(timer)">RESTART</button>
<button onclick="cancelAnimationFrame(job)">STOP</button>
Example usage, binded to a media element
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
VIDEO.addEventListener("timeupdate", function(e){
OUT.textContent = secToTimer(e.target.currentTime)
}, false)
span {font-size:4rem}
<span id="OUT"></span><br>
<video id="VIDEO" width="400" controls autoplay>
<source src="https://www.w3schools.com/html/mov_bbb.mp4" type="video/mp4">
</video>
Outside the question, those functions written in php:
<?php
/* HH:MM:SS to (FLOAT)seconds ------------------*/
function timerToSec($timer){
$vtimer = explode(":",$timer);
$vhours = (int)$vtimer[0];
$vminutes = (int)$vtimer[1];
$vseconds = (float)$vtimer[2];
return $vhours * 3600 + $vminutes * 60 + $vseconds;
}
/* Seconds to (STRING)HH:MM:SS -----------------*/
function secToTimer($sec){
return explode(" ", date("H:i:s", $sec))[0];
}
After looking at all the answers and not being happy with most of them, this is what I came up with. I know I am very late to the conversation, but here it is anyway.
function secsToTime(secs){
var time = new Date();
// create Date object and set to today's date and time
time.setHours(parseInt(secs/3600) % 24);
time.setMinutes(parseInt(secs/60) % 60);
time.setSeconds(parseInt(secs%60));
time = time.toTimeString().split(" ")[0];
// time.toString() = "HH:mm:ss GMT-0800 (PST)"
// time.toString().split(" ") = ["HH:mm:ss", "GMT-0800", "(PST)"]
// time.toTimeString().split(" ")[0]; = "HH:mm:ss"
return time;
}
I create a new Date object, change the time to my parameters, convert the Date Object to a time string, and removed the additional stuff by splitting the string and returning only the part that need.
I thought I would share this approach, since it removes the need for regex, logic and math acrobatics to get the results in "HH:mm:ss" format, and instead it relies on built in methods.
You may want to take a look at the documentation here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
below is the given code which will convert seconds into hh-mm-ss format:
var measuredTime = new Date(null);
measuredTime.setSeconds(4995); // specify value of SECONDS
var MHSTime = measuredTime.toISOString().substr(11, 8);
Get alternative method from Convert seconds to HH-MM-SS format in JavaScript
var time1 = date1.getTime();
var time2 = date2.getTime();
var totalMilisec = time2 - time1;
alert(DateFormat('hh:mm:ss',new Date(totalMilisec)))
/* ----------------------------------------------------------
* Field | Full Form | Short Form
* -------------|--------------------|-----------------------
* Year | yyyy (4 digits) | yy (2 digits)
* Month | MMM (abbr.) | MM (2 digits)
| NNN (name) |
* Day of Month | dd (2 digits) |
* Day of Week | EE (name) | E (abbr)
* Hour (1-12) | hh (2 digits) |
* Minute | mm (2 digits) |
* Second | ss (2 digits) |
* ----------------------------------------------------------
*/
function DateFormat(formatString,date){
if (typeof date=='undefined'){
var DateToFormat=new Date();
}
else{
var DateToFormat=date;
}
var DAY = DateToFormat.getDate();
var DAYidx = DateToFormat.getDay();
var MONTH = DateToFormat.getMonth()+1;
var MONTHidx = DateToFormat.getMonth();
var YEAR = DateToFormat.getYear();
var FULL_YEAR = DateToFormat.getFullYear();
var HOUR = DateToFormat.getHours();
var MINUTES = DateToFormat.getMinutes();
var SECONDS = DateToFormat.getSeconds();
var arrMonths = new Array("January","February","March","April","May","June","July","August","September","October","November","December");
var arrDay=new Array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
var strMONTH;
var strDAY;
var strHOUR;
var strMINUTES;
var strSECONDS;
var Separator;
if(parseInt(MONTH)< 10 && MONTH.toString().length < 2)
strMONTH = "0" + MONTH;
else
strMONTH=MONTH;
if(parseInt(DAY)< 10 && DAY.toString().length < 2)
strDAY = "0" + DAY;
else
strDAY=DAY;
if(parseInt(HOUR)< 10 && HOUR.toString().length < 2)
strHOUR = "0" + HOUR;
else
strHOUR=HOUR;
if(parseInt(MINUTES)< 10 && MINUTES.toString().length < 2)
strMINUTES = "0" + MINUTES;
else
strMINUTES=MINUTES;
if(parseInt(SECONDS)< 10 && SECONDS.toString().length < 2)
strSECONDS = "0" + SECONDS;
else
strSECONDS=SECONDS;
switch (formatString){
case "hh:mm:ss":
return strHOUR + ':' + strMINUTES + ':' + strSECONDS;
break;
//More cases to meet your requirements.
}
}
I just wanted to give a little explanation to the nice answer above:
var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;
var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds < 10 ? "0" + seconds : seconds);
On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.
When you see something like this:
25 % 24
Think of it like this:
25 mod 24 or what is the remainder when we divide 25 by 24
None of the answers here satisfies my requirements as I want to be able to handle
Large numbers of seconds (days), and
Negative numbers
Although those are not required by the OP, it's good practice to cover edge cases, especially when it takes little effort.
It's pretty obvious is that the OP means a NUMBER of seconds when he says seconds. Why would peg your function on String?
function secondsToTimeSpan(seconds) {
const value = Math.abs(seconds);
const days = Math.floor(value / 1440);
const hours = Math.floor((value - (days * 1440)) / 3600);
const min = Math.floor((value - (days * 1440) - (hours * 3600)) / 60);
const sec = value - (days * 1440) - (hours * 3600) - (min * 60);
return `${seconds < 0 ? '-':''}${days > 0 ? days + '.':''}${hours < 10 ? '0' + hours:hours}:${min < 10 ? '0' + min:min}:${sec < 10 ? '0' + sec:sec}`
}
secondsToTimeSpan(0); // => 00:00:00
secondsToTimeSpan(1); // => 00:00:01
secondsToTimeSpan(1440); // => 1.00:00:00
secondsToTimeSpan(-1440); // => -1.00:00:00
secondsToTimeSpan(-1); // => -00:00:01
Simple function to convert seconds into in hh:mm:ss format :
function getHHMMSSFromSeconds(totalSeconds) {
if (!totalSeconds) {
return '00:00:00';
}
const hours = Math.floor(totalSeconds / 3600);
const minutes = Math.floor(totalSeconds % 3600 / 60);
const seconds = totalSeconds % 60;
const hhmmss = padTo2(hours) + ':' + padTo2(minutes) + ':' + padTo2(seconds);
return hhmmss;
}
// function to convert single digit to double digit
function padTo2(value) {
if (!value) {
return '00';
}
return value < 10 ? String(value).padStart(2, '0') : value;
}
Here is a function to convert seconds to hh-mm-ss format based on powtac's answer here
jsfiddle
/**
* Convert seconds to hh-mm-ss format.
* #param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
var hours = Math.floor(totalSeconds / 3600);
var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
var seconds = totalSeconds - (hours * 3600) - (minutes * 60);
// round seconds
seconds = Math.round(seconds * 100) / 100
var result = (hours < 10 ? "0" + hours : hours);
result += "-" + (minutes < 10 ? "0" + minutes : minutes);
result += "-" + (seconds < 10 ? "0" + seconds : seconds);
return result;
}
Example use
var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10
There are lots of options of solve this problem, and obvious there are good option suggested about, But I wants to add one more optimized code here
function formatSeconds(sec) {
return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
.map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
.filter((i, j) => i !== "00" || j > 0)
.join(":");
}
if you don't wants formatted zero with less then 10 number, you can use
function formatSeconds(sec) {
return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);
}
Sample Code http://fiddly.org/1c476/1
In one line, using T.J. Crowder's solution :
secToHHMMSS = seconds => `${Math.floor(seconds / 3600)}:${Math.floor((seconds % 3600) / 60)}:${Math.floor((seconds % 3600) % 60)}`
In one line, another solution that also count days :
secToDHHMMSS = seconds => `${parseInt(seconds / 86400)}d ${new Date(seconds * 1000).toISOString().substr(11, 8)}`
Source : https://gist.github.com/martinbean/2bf88c446be8048814cf02b2641ba276
var sec_to_hms = function(sec){
var min, hours;
sec = sec - (min = Math.floor(sec/60))*60;
min = min - (hours = Math.floor(min/60))*60;
return (hours?hours+':':'') + ((min+'').padStart(2, '0')) + ':'+ ((sec+'').padStart(2, '0'));
}
alert(sec_to_hms(2442542));
Have you tried adding seconds to a Date object?
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
};
var dt = new Date();
dt.addSeconds(1234);
A sample:
https://jsfiddle.net/j5g2p0dc/5/
Updated:
Sample link was missing so I created a new one.
You can also use below code:
int ss = nDur%60;
nDur = nDur/60;
int mm = nDur%60;
int hh = nDur/60;
For anyone using AngularJS, a simple solution is to filter the value with the date API, which converts milliseconds to a string based on the requested format. Example:
<div>Offer ends in {{ timeRemaining | date: 'HH:mm:ss' }}</div>
Note that this expects milliseconds, so you may want to multiply timeRemaining by 1000 if you are converting from seconds (as the original question was formulated).
I ran into the case some have mentioned where the number of seconds is more than a day. Here's an adapted version of #Harish Anchu's top-rated answer that accounts for longer periods of time:
function secondsToTime(seconds) {
const arr = new Date(seconds * 1000).toISOString().substr(11, 8).split(':');
const days = Math.floor(seconds / 86400);
arr[0] = parseInt(arr[0], 10) + days * 24;
return arr.join(':');
}
Example:
secondsToTime(101596) // outputs '28:13:16' as opposed to '04:13:16'
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
Usage Example
alert("186".toHHMMSS());
I have a function inside my app that takes a value and puts it out in a special way. It is there to calculate a value to be the same value but split in "hours : minutes".
I need the function to also work for negative values - something like an if check inside the function to check if the entered time is negative and then to change the calculation/output.
Here is the function its pretty straight forward:
const calcSingle = time => {
// insert a if check somewhere here to check for time and if its negative
let hour = Math.floor(time / 60);
let minutes = time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return hour + ":" + minutes;
};
If I call this on for example:
calcSingle(200) I get back "03:20" which is the correct value.
However if I try calcSingle(-200) I get: "0-4:0-20" which obviously is wrong because it should be the same value but with a minus so this => "-03:20".
const calcSingle = time => {
// insert a if check somewhere here to check for time and if its negative
let hour = Math.floor(time / 60);
let minutes = time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return hour + ":" + minutes;
};
console.log(
calcSingle(200)
)
console.log(
calcSingle(-200)
)
Edit: Thanks for all the responses from all of you guys I will use math.abs it solves my problem! Great help guys - have a good day!
You can add check at beginning and call same function changing sign.
if (time < 0) {
return `-${calcSingle(Math.abs(time))}`;
}
Like this
const calcSingle = time => {
if (time < 0) {
return `-${calcSingle(Math.abs(time))}`;
}
// insert a if check somewhere here to check for time and if its negative
let hour = Math.floor(time / 60);
let minutes = time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return hour + ":" + minutes;
};
console.log(calcSingle(200));
console.log(calcSingle(-200));
I think a Math.abs() will solve your problem:
const calcSingle = time => {
let isNegative = time < 0;
let _time = Math.abs(time);
// insert a if check somewhere here to check for time and if its negative
let hour = Math.floor(_time / 60);
let minutes = _time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return (isNegative ? '-':'') + hour + ":" + minutes;
};
console.log(
calcSingle(200)
)
console.log(
calcSingle(-200)
)
Simplest version
const pad = num => ("0" + num).slice(-2);
const calcSingle = time => {
let _time = Math.abs(time);
let hour = pad(Math.floor(_time / 60));
let minutes = pad(_time % 60);
return (time < 0 ? '-' : '') + hour + ":" + minutes;
};
console.log(
calcSingle(200)
)
console.log(
calcSingle(-200)
)
Math.abs can be used.
Math.abs()
const calcSingle = time => {
// insert a if check somewhere here to check for time and if its negative
let _time = Math.abs(time);
let hour = Math.floor(_time / 60);
let minutes = _time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return (time < 0 ? '-' : '') + hour + ":" + minutes;
};
console.log(calcSingle(200), calcSingle(-200));
You could use Math.abs() to get the absolute value of time. You can then check in your return statement whether your initial time is less than 0 (therefore a negative number) and use that to return either a positive or negative time.
You could use the following code:
const calcSingle = time => {
const absTime = Math.abs(time);
let hour = Math.floor(absTime / 60);
let minutes = absTime % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return `${time < 0 ? "-" : ""}${hour}:${minutes}`;
};
Use a boolean to store the value and append the minus at the end of result
calcSingle = time => {
var bIsNegative = false;
if (time < 0) {
bIsNegative = true;
}
time = Math.abs(time);
// insert a if check somewhere here to check for time and if its negative
let hour = Math.floor(time / 60);
let minutes = time % 60;
hour = hour < 10 ? "0" + hour : hour;
minutes = minutes < 10 ? "0" + minutes : minutes;
return bIsNegative ? "-" + (hour + ":" + minutes) : hour + ":" + minutes;
};
console.log(
calcSingle(200)
)
console.log(
calcSingle(-200)
)
I have an Electron app where an Excel-Sheet with a couple of columns containing time values needs to be imported. In my app those values are converted in a loop to momentjs object for further manipulation:
x['Time'] = moment(x['Time'], ['HH:mm','HH:mm:ss']).format('HH:mm:ss');
This works fine as long the Excel contains time values formatted as text. But if the Excel is set up the way it's meant to be, then the value of the Cell is a Number between 0 and 1 (Excel counts time internally as floating point - so e.g. 0,5 translates to 12:00:00).
Does anyone know how I can translate that back to a readable Timevalue for momentjs?
export const parseDateExcel = (excelTimestamp) => {
const secondsInDay = 24 * 60 * 60;
const excelEpoch = new Date(1899, 11, 31);
const excelEpochAsUnixTimestamp = excelEpoch.getTime();
const missingLeapYearDay = secondsInDay * 1000;
const delta = excelEpochAsUnixTimestamp - missingLeapYearDay;
const excelTimestampAsUnixTimestamp = excelTimestamp * secondsInDay * 1000;
const parsed = excelTimestampAsUnixTimestamp + delta;
return isNaN(parsed) ? null : parsed;
};
Usage:
new Date(parseDateExcel(36902.49097)) //=> Thu Jan 11 2001 11:46:59 GMT+0000 (Greenwich Mean Time)
Source
This is as far as I have work with the Excel time decimal values.
So according to Excel the time text is represented by a decimal number ranging from 0 to 1.
function excelDateToJSDate(excel_date, time = false) {
let day_time = excel_date % 1
let meridiem = "AMPM"
let hour = Math.floor(day_time * 24)
let minute = Math.floor(Math.abs(day_time * 24 * 60) % 60)
let second = Math.floor(Math.abs(day_time * 24 * 60 * 60) % 60)
hour >= 12 ? meridiem = meridiem.slice(2, 4) : meridiem = meridiem.slice(0, 2)
hour > 12 ? hour = hour - 12 : hour = hour
hour = hour < 10 ? "0" + hour : hour
minute = minute < 10 ? "0" + minute : minute
second = second < 10 ? "0" + second : second
let daytime = "" + hour + ":" + minute + ":" + second + " " + meridiem
return time ? daytime : (new Date(0, 0, excel_date, 0, -new Date(0).getTimezoneOffset(), 0)).toLocaleDateString(navigator.language, {}) + " " + daytime
};
First we define the midday, then handle the hours, minutes and seconds, then verify if the given hour is either AM or PM, as a formatting fashion preference we change the 24 hours to 12 hour convention and add padding zeros to any value less than 10 and lastly return the time or date as a string.
Example
function excelDateToJSDate(excel_date, time = false) {
let day_time = excel_date % 1
let meridiem = "AMPM"
let hour = Math.floor(day_time * 24)
let minute = Math.floor(Math.abs(day_time * 24 * 60) % 60)
let second = Math.floor(Math.abs(day_time * 24 * 60 * 60) % 60)
hour >= 12 ? meridiem = meridiem.slice(2, 4) : meridiem = meridiem.slice(0, 2)
hour > 12 ? hour = hour - 12 : hour = hour
hour = hour < 10 ? "0" + hour : hour
minute = minute < 10 ? "0" + minute : minute
second = second < 10 ? "0" + second : second
let daytime = "" + hour + ":" + minute + ":" + second + " " + meridiem
return time ? daytime : (new Date(0, 0, excel_date, 0, -new Date(0).getTimezoneOffset(), 0)).toLocaleDateString(navigator.language, {}) + " " + daytime
};
console.log(excelDateToJSDate(0.125, true));
console.log(excelDateToJSDate(43556));
Due to the fact I could not find a real answer, here is one that worked for me:
let fromExcel = 0,709722222222222; //translates to 17:02:00
let basenumber = (fromExcel*24)
let hour = Math.floor(basenumber).toString();
if (hour.length < 2) {
hour = '0'+hour;
}
var minute = Math.round((basenumber % 1)*60).toString();
if (minute.length < 2) {
minute = '0'+minute;
}
let Timestring = (hour+':'+minute+':00');
So I have a String momentjscan translate. The reason I do not mark this as answer is that there sure are nicer ways of conversion and I could not find a solution to calculate the seconds (which in my special case does not matter, as I do not use them).
How can I convert seconds to an HH-MM-SS string using JavaScript?
You can manage to do this without any external JavaScript library with the help of JavaScript Date method like following:
const date = new Date(null);
date.setSeconds(SECONDS); // specify value for SECONDS here
const result = date.toISOString().slice(11, 19);
Or, as per #Frank's comment; a one liner:
new Date(SECONDS * 1000).toISOString().slice(11, 19);
Updated (2020):
Please use #Frank's one line solution:
new Date(SECONDS * 1000).toISOString().substring(11, 16)
If SECONDS<3600 and if you want to show only MM:SS then use below code:
new Date(SECONDS * 1000).toISOString().substring(14, 19)
It is by far the best solution.
Old answer:
Use the Moment.js library.
I don't think any built-in feature of the standard Date object will do this for you in a way that's more convenient than just doing the math yourself.
hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;
Example:
let totalSeconds = 28565;
let hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
let minutes = Math.floor(totalSeconds / 60);
let seconds = totalSeconds % 60;
console.log("hours: " + hours);
console.log("minutes: " + minutes);
console.log("seconds: " + seconds);
// If you want strings with leading zeroes:
minutes = String(minutes).padStart(2, "0");
hours = String(hours).padStart(2, "0");
seconds = String(seconds).padStart(2, "0");
console.log(hours + ":" + minutes + ":" + seconds);
I know this is kinda old, but...
ES2015:
var toHHMMSS = (secs) => {
var sec_num = parseInt(secs, 10)
var hours = Math.floor(sec_num / 3600)
var minutes = Math.floor(sec_num / 60) % 60
var seconds = sec_num % 60
return [hours,minutes,seconds]
.map(v => v < 10 ? "0" + v : v)
.filter((v,i) => v !== "00" || i > 0)
.join(":")
}
It will output:
toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18
As Cleiton pointed out in his answer, moment.js can be used for this:
moment().startOf('day')
.seconds(15457)
.format('H:mm:ss');
Here's a simple function for converting times that might help
function formatSeconds(seconds) {
var date = new Date(1970,0,1);
date.setSeconds(seconds);
return date.toTimeString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}
This does the trick:
function secondstotime(secs)
{
var t = new Date(1970,0,1);
t.setSeconds(secs);
var s = t.toTimeString().substr(0,8);
if(secs > 86399)
s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
return s;
}
(Sourced from here)
var timeInSec = "661"; //even it can be string
String.prototype.toHHMMSS = function () {
/* extend the String by using prototypical inheritance */
var seconds = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(seconds / 3600);
var minutes = Math.floor((seconds - (hours * 3600)) / 60);
seconds = seconds - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
alert("5678".toHHMMSS()); // "01:34:38"
console.log(timeInSec.toHHMMSS()); //"00:11:01"
we can make this function lot shorter and crisp but that decreases the readability, so we will write it as simple as possible and as stable as possible.
or you can check this working here:
I think the most general (and cryptic) solution could be this
function hms(seconds) {
return [3600, 60]
.reduceRight(
(pipeline, breakpoint) => remainder =>
[Math.floor(remainder / breakpoint)].concat(pipeline(remainder % breakpoint)),
r => [r]
)(seconds)
.map(amount => amount.toString().padStart(2, '0'))
.join('-');
}
Or to copy & paste the shortest version
function hms(seconds) {
return [3600, 60]
.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(seconds)
.map(a => a.toString().padStart(2, '0'))
.join('-');
}
Some example outputs:
> hms(0)
< "00-00-00"
> hms(5)
< "00-00-05"
> hms(60)
< "00-01-00"
> hms(3785)
< "01-03-05"
> hms(37850)
< "10-30-50"
> hms(378500)
< "105-08-20"
How it works
Algorithm
To get hours you divide total seconds by 3600 and floor it.
To get minutes you divide remainder by 60 and floor it.
To get seconds you just use the remainder.
It would also be nice to keep individual amounts in an array for easier formatting.
For example given the input of 3785s the output should be [1, 3, 5], that is 1 hour, 3 minutes and 5 seconds.
Creating pipeline
Naming the 3600 and 60 constants "breakpoints" you can write this algorithm into function as this
function divideAndAppend(remainder, breakpoint, callback) {
return [Math.floor(remainder / breakpoint)].concat(callback(remainder % breakpoint));
}
It returns an array where first item is the amount for given breakpoint and the rest of the array is given by the callback.
Reusing the divideAndAppend in callback function will give you a pipeline of composed divideAndAppend functions. Each one of these
computes amount per given breakpoint and append it to the array making your desired output.
Then you also need the "final" callback that ends this pipeline. In another words you used all breakpoints and now you have only the remainder.
Since you have already the answer at 3) you should use some sort of identity function, in this case remainder => [remainder].
You can now write the pipeline like this
let pipeline = r3 => divideAndAppend(
r3,
3600,
r2 => divideAndAppend(
r2,
60,
r1 => [r1]));
> pipeline(3785)
< [1, 3, 5]
Cool right?
Generalizing using for-loop
Now you can generalize with a variable amount of breakpoints and create a for-loop that will compose individial divideAndAppend functions into
the pipeline.
You start with the identity function r1 => [r1], then use the 60 breakpoint and finally use the 3600 breakpoint.
let breakpoints = [60, 3600];
let pipeline = r => [r];
for (const b of breakpoints) {
const previousPipeline = pipeline;
pipeline = r => divideAndAppend(r, b, previousPipeline);
}
> pipeline(3785)
< [1, 3, 5]
Using Array.prototype.reduce()
Now you can rewrite this for-loop into reducer for shorter and more functional code. In other words rewrite function composition into the reducer.
let pipeline = [60, 3600].reduce(
(ppln, b) => r => divideAndAppend(r, b, ppln),
r => [r]
);
> pipeline(3785)
< [1, 3, 5]
The accumulator ppln is the pipeline and you are composing it using the previous version of it. The initial pipeline is r => [r].
You can now inline the function divideAndAppend and use Array.prototype.reduceRight which is the same as [].reverse().reduce(...) to make the breakpoints
definitions more natural.
let pipeline = [3600, 60]
.reduceRight(
(ppln, b) => r => [Math.floor(r / b)].concat(ppln(r % b)),
r => [r]
);
Which is the final form. Then you just appy mapping to string with padded 0's on left and join the strings with : separator;
More generalizations
Wrapping the reducer into function
function decompose(total, breakpoints) {
return breakpoints.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(total);
}
> decompose(3785, [3600, 60])
< [1, 3, 5]
you now have very general algorithm you can work with. For example:
Convert easily (the weird) us length standards
Given the standards
Unit
Divisions
1 foot
12 inches
1 yard
3 feet
1 mile
1760 yards
> decompose(123_456, [1760 * 3 * 12, 3 * 12, 12])
< [1, 1669, 1, 0]
123456 in = 1 mi, 1669 yd, 1 feet and 0 in
Or you can somewhat convert to decimal or binary representations
> decompose(123_456, [100_000, 10_000, 1000, 100, 10])
< [1, 2, 3, 4, 5, 6]
> decompose(127, [128, 64, 32, 16, 8, 4, 2])
< [0, 1, 1, 1, 1, 1, 1, 1]
Works also with floating point breakpoints
Since Javascript supports mod operator with floating point numbers, you can also do
> decompose(26.5, [20, 2.5])
< [1, 2, 1.5]
The edge case of no breakpoints is also naturally covered
> decompose(123, [])
< [123]
Try this:
function toTimeString(seconds) {
return (new Date(seconds * 1000)).toUTCString().match(/(\d\d:\d\d:\d\d)/)[0];
}
Here is an extension to Number class. toHHMMSS() converts seconds to an hh:mm:ss string.
Number.prototype.toHHMMSS = function() {
var hours = Math.floor(this / 3600) < 10 ? ("00" + Math.floor(this / 3600)).slice(-2) : Math.floor(this / 3600);
var minutes = ("00" + Math.floor((this % 3600) / 60)).slice(-2);
var seconds = ("00" + (this % 3600) % 60).slice(-2);
return hours + ":" + minutes + ":" + seconds;
}
// Usage: [number variable].toHHMMSS();
// Here is a simple test
var totalseconds = 1234;
document.getElementById("timespan").innerHTML = totalseconds.toHHMMSS();
// HTML of the test
<div id="timespan"></div>
Easy to follow version for noobies:
var totalNumberOfSeconds = YOURNUMBEROFSECONDS;
var hours = parseInt( totalNumberOfSeconds / 3600 );
var minutes = parseInt( (totalNumberOfSeconds - (hours * 3600)) / 60 );
var seconds = Math.floor((totalNumberOfSeconds - ((hours * 3600) + (minutes * 60))));
var result = (hours < 10 ? "0" + hours : hours) + ":" + (minutes < 10 ? "0" + minutes : minutes) + ":" + (seconds < 10 ? "0" + seconds : seconds);
console.log(result);
This function should do it :
var convertTime = function (input, separator) {
var pad = function(input) {return input < 10 ? "0" + input : input;};
return [
pad(Math.floor(input / 3600)),
pad(Math.floor(input % 3600 / 60)),
pad(Math.floor(input % 60)),
].join(typeof separator !== 'undefined' ? separator : ':' );
}
Without passing a separator, it uses : as the (default) separator :
time = convertTime(13551.9941351); // --> OUTPUT = 03:45:51
If you want to use - as a separator, just pass it as the second parameter:
time = convertTime(1126.5135155, '-'); // --> OUTPUT = 00-18-46
See also this Fiddle.
Chiming in on this old thread -- the OP stated HH:MM:SS, and many of the solutions work, until you realize you need more than 24 hours listed. And maybe you don't want more than a single line of code. Here you go:
d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}
It returns H+:MM:SS. To use it, simply use:
d(91260); // returns "25:21:00"
d(960); // returns "0:16:00"
...I tried to get it to use the least amount of code possible, for a nice one-liner approach.
For the special case of HH:MM:SS.MS (eq: "00:04:33.637") as used by FFMPEG to specify milliseconds.
[-][HH:]MM:SS[.m...]
HH expresses the number of hours, MM the number of minutes for a
maximum of 2 digits, and SS the number of seconds for a maximum of 2
digits. The m at the end expresses decimal value for SS.
/* HH:MM:SS.MS to (FLOAT)seconds ---------------*/
function timerToSec(timer){
let vtimer = timer.split(":")
let vhours = +vtimer[0]
let vminutes = +vtimer[1]
let vseconds = parseFloat(vtimer[2])
return vhours * 3600 + vminutes * 60 + vseconds
}
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
/* Example: 7hours, 4 minutes, 33 seconds and 637 milliseconds */
const t = "07:04:33.637"
console.log(
t + " => " +
timerToSec(t) +
"s"
)
/* Test: 25473 seconds and 637 milliseconds */
const s = 25473.637 // "25473.637"
console.log(
s + "s => " +
secToTimer(s)
)
Example usage, a milliseconds transport timer:
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
let job, origin = new Date().getTime()
const timer = () => {
job = requestAnimationFrame(timer)
OUT.textContent = secToTimer((new Date().getTime() - origin) / 1000)
}
requestAnimationFrame(timer)
span {font-size:4rem}
<span id="OUT"></span>
<br>
<button onclick="origin = new Date().getTime()">RESET</button>
<button onclick="requestAnimationFrame(timer)">RESTART</button>
<button onclick="cancelAnimationFrame(job)">STOP</button>
Example usage, binded to a media element
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
VIDEO.addEventListener("timeupdate", function(e){
OUT.textContent = secToTimer(e.target.currentTime)
}, false)
span {font-size:4rem}
<span id="OUT"></span><br>
<video id="VIDEO" width="400" controls autoplay>
<source src="https://www.w3schools.com/html/mov_bbb.mp4" type="video/mp4">
</video>
Outside the question, those functions written in php:
<?php
/* HH:MM:SS to (FLOAT)seconds ------------------*/
function timerToSec($timer){
$vtimer = explode(":",$timer);
$vhours = (int)$vtimer[0];
$vminutes = (int)$vtimer[1];
$vseconds = (float)$vtimer[2];
return $vhours * 3600 + $vminutes * 60 + $vseconds;
}
/* Seconds to (STRING)HH:MM:SS -----------------*/
function secToTimer($sec){
return explode(" ", date("H:i:s", $sec))[0];
}
After looking at all the answers and not being happy with most of them, this is what I came up with. I know I am very late to the conversation, but here it is anyway.
function secsToTime(secs){
var time = new Date();
// create Date object and set to today's date and time
time.setHours(parseInt(secs/3600) % 24);
time.setMinutes(parseInt(secs/60) % 60);
time.setSeconds(parseInt(secs%60));
time = time.toTimeString().split(" ")[0];
// time.toString() = "HH:mm:ss GMT-0800 (PST)"
// time.toString().split(" ") = ["HH:mm:ss", "GMT-0800", "(PST)"]
// time.toTimeString().split(" ")[0]; = "HH:mm:ss"
return time;
}
I create a new Date object, change the time to my parameters, convert the Date Object to a time string, and removed the additional stuff by splitting the string and returning only the part that need.
I thought I would share this approach, since it removes the need for regex, logic and math acrobatics to get the results in "HH:mm:ss" format, and instead it relies on built in methods.
You may want to take a look at the documentation here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
below is the given code which will convert seconds into hh-mm-ss format:
var measuredTime = new Date(null);
measuredTime.setSeconds(4995); // specify value of SECONDS
var MHSTime = measuredTime.toISOString().substr(11, 8);
Get alternative method from Convert seconds to HH-MM-SS format in JavaScript
var time1 = date1.getTime();
var time2 = date2.getTime();
var totalMilisec = time2 - time1;
alert(DateFormat('hh:mm:ss',new Date(totalMilisec)))
/* ----------------------------------------------------------
* Field | Full Form | Short Form
* -------------|--------------------|-----------------------
* Year | yyyy (4 digits) | yy (2 digits)
* Month | MMM (abbr.) | MM (2 digits)
| NNN (name) |
* Day of Month | dd (2 digits) |
* Day of Week | EE (name) | E (abbr)
* Hour (1-12) | hh (2 digits) |
* Minute | mm (2 digits) |
* Second | ss (2 digits) |
* ----------------------------------------------------------
*/
function DateFormat(formatString,date){
if (typeof date=='undefined'){
var DateToFormat=new Date();
}
else{
var DateToFormat=date;
}
var DAY = DateToFormat.getDate();
var DAYidx = DateToFormat.getDay();
var MONTH = DateToFormat.getMonth()+1;
var MONTHidx = DateToFormat.getMonth();
var YEAR = DateToFormat.getYear();
var FULL_YEAR = DateToFormat.getFullYear();
var HOUR = DateToFormat.getHours();
var MINUTES = DateToFormat.getMinutes();
var SECONDS = DateToFormat.getSeconds();
var arrMonths = new Array("January","February","March","April","May","June","July","August","September","October","November","December");
var arrDay=new Array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
var strMONTH;
var strDAY;
var strHOUR;
var strMINUTES;
var strSECONDS;
var Separator;
if(parseInt(MONTH)< 10 && MONTH.toString().length < 2)
strMONTH = "0" + MONTH;
else
strMONTH=MONTH;
if(parseInt(DAY)< 10 && DAY.toString().length < 2)
strDAY = "0" + DAY;
else
strDAY=DAY;
if(parseInt(HOUR)< 10 && HOUR.toString().length < 2)
strHOUR = "0" + HOUR;
else
strHOUR=HOUR;
if(parseInt(MINUTES)< 10 && MINUTES.toString().length < 2)
strMINUTES = "0" + MINUTES;
else
strMINUTES=MINUTES;
if(parseInt(SECONDS)< 10 && SECONDS.toString().length < 2)
strSECONDS = "0" + SECONDS;
else
strSECONDS=SECONDS;
switch (formatString){
case "hh:mm:ss":
return strHOUR + ':' + strMINUTES + ':' + strSECONDS;
break;
//More cases to meet your requirements.
}
}
I just wanted to give a little explanation to the nice answer above:
var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;
var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds < 10 ? "0" + seconds : seconds);
On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.
When you see something like this:
25 % 24
Think of it like this:
25 mod 24 or what is the remainder when we divide 25 by 24
None of the answers here satisfies my requirements as I want to be able to handle
Large numbers of seconds (days), and
Negative numbers
Although those are not required by the OP, it's good practice to cover edge cases, especially when it takes little effort.
It's pretty obvious is that the OP means a NUMBER of seconds when he says seconds. Why would peg your function on String?
function secondsToTimeSpan(seconds) {
const value = Math.abs(seconds);
const days = Math.floor(value / 1440);
const hours = Math.floor((value - (days * 1440)) / 3600);
const min = Math.floor((value - (days * 1440) - (hours * 3600)) / 60);
const sec = value - (days * 1440) - (hours * 3600) - (min * 60);
return `${seconds < 0 ? '-':''}${days > 0 ? days + '.':''}${hours < 10 ? '0' + hours:hours}:${min < 10 ? '0' + min:min}:${sec < 10 ? '0' + sec:sec}`
}
secondsToTimeSpan(0); // => 00:00:00
secondsToTimeSpan(1); // => 00:00:01
secondsToTimeSpan(1440); // => 1.00:00:00
secondsToTimeSpan(-1440); // => -1.00:00:00
secondsToTimeSpan(-1); // => -00:00:01
Simple function to convert seconds into in hh:mm:ss format :
function getHHMMSSFromSeconds(totalSeconds) {
if (!totalSeconds) {
return '00:00:00';
}
const hours = Math.floor(totalSeconds / 3600);
const minutes = Math.floor(totalSeconds % 3600 / 60);
const seconds = totalSeconds % 60;
const hhmmss = padTo2(hours) + ':' + padTo2(minutes) + ':' + padTo2(seconds);
return hhmmss;
}
// function to convert single digit to double digit
function padTo2(value) {
if (!value) {
return '00';
}
return value < 10 ? String(value).padStart(2, '0') : value;
}
Here is a function to convert seconds to hh-mm-ss format based on powtac's answer here
jsfiddle
/**
* Convert seconds to hh-mm-ss format.
* #param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
var hours = Math.floor(totalSeconds / 3600);
var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
var seconds = totalSeconds - (hours * 3600) - (minutes * 60);
// round seconds
seconds = Math.round(seconds * 100) / 100
var result = (hours < 10 ? "0" + hours : hours);
result += "-" + (minutes < 10 ? "0" + minutes : minutes);
result += "-" + (seconds < 10 ? "0" + seconds : seconds);
return result;
}
Example use
var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10
There are lots of options of solve this problem, and obvious there are good option suggested about, But I wants to add one more optimized code here
function formatSeconds(sec) {
return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
.map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
.filter((i, j) => i !== "00" || j > 0)
.join(":");
}
if you don't wants formatted zero with less then 10 number, you can use
function formatSeconds(sec) {
return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);
}
Sample Code http://fiddly.org/1c476/1
In one line, using T.J. Crowder's solution :
secToHHMMSS = seconds => `${Math.floor(seconds / 3600)}:${Math.floor((seconds % 3600) / 60)}:${Math.floor((seconds % 3600) % 60)}`
In one line, another solution that also count days :
secToDHHMMSS = seconds => `${parseInt(seconds / 86400)}d ${new Date(seconds * 1000).toISOString().substr(11, 8)}`
Source : https://gist.github.com/martinbean/2bf88c446be8048814cf02b2641ba276
var sec_to_hms = function(sec){
var min, hours;
sec = sec - (min = Math.floor(sec/60))*60;
min = min - (hours = Math.floor(min/60))*60;
return (hours?hours+':':'') + ((min+'').padStart(2, '0')) + ':'+ ((sec+'').padStart(2, '0'));
}
alert(sec_to_hms(2442542));
Have you tried adding seconds to a Date object?
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
};
var dt = new Date();
dt.addSeconds(1234);
A sample:
https://jsfiddle.net/j5g2p0dc/5/
Updated:
Sample link was missing so I created a new one.
You can also use below code:
int ss = nDur%60;
nDur = nDur/60;
int mm = nDur%60;
int hh = nDur/60;
For anyone using AngularJS, a simple solution is to filter the value with the date API, which converts milliseconds to a string based on the requested format. Example:
<div>Offer ends in {{ timeRemaining | date: 'HH:mm:ss' }}</div>
Note that this expects milliseconds, so you may want to multiply timeRemaining by 1000 if you are converting from seconds (as the original question was formulated).
I ran into the case some have mentioned where the number of seconds is more than a day. Here's an adapted version of #Harish Anchu's top-rated answer that accounts for longer periods of time:
function secondsToTime(seconds) {
const arr = new Date(seconds * 1000).toISOString().substr(11, 8).split(':');
const days = Math.floor(seconds / 86400);
arr[0] = parseInt(arr[0], 10) + days * 24;
return arr.join(':');
}
Example:
secondsToTime(101596) // outputs '28:13:16' as opposed to '04:13:16'
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
Usage Example
alert("186".toHHMMSS());
How can I convert seconds to an HH-MM-SS string using JavaScript?
You can manage to do this without any external JavaScript library with the help of JavaScript Date method like following:
const date = new Date(null);
date.setSeconds(SECONDS); // specify value for SECONDS here
const result = date.toISOString().slice(11, 19);
Or, as per #Frank's comment; a one liner:
new Date(SECONDS * 1000).toISOString().slice(11, 19);
Updated (2020):
Please use #Frank's one line solution:
new Date(SECONDS * 1000).toISOString().substring(11, 16)
If SECONDS<3600 and if you want to show only MM:SS then use below code:
new Date(SECONDS * 1000).toISOString().substring(14, 19)
It is by far the best solution.
Old answer:
Use the Moment.js library.
I don't think any built-in feature of the standard Date object will do this for you in a way that's more convenient than just doing the math yourself.
hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;
Example:
let totalSeconds = 28565;
let hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
let minutes = Math.floor(totalSeconds / 60);
let seconds = totalSeconds % 60;
console.log("hours: " + hours);
console.log("minutes: " + minutes);
console.log("seconds: " + seconds);
// If you want strings with leading zeroes:
minutes = String(minutes).padStart(2, "0");
hours = String(hours).padStart(2, "0");
seconds = String(seconds).padStart(2, "0");
console.log(hours + ":" + minutes + ":" + seconds);
I know this is kinda old, but...
ES2015:
var toHHMMSS = (secs) => {
var sec_num = parseInt(secs, 10)
var hours = Math.floor(sec_num / 3600)
var minutes = Math.floor(sec_num / 60) % 60
var seconds = sec_num % 60
return [hours,minutes,seconds]
.map(v => v < 10 ? "0" + v : v)
.filter((v,i) => v !== "00" || i > 0)
.join(":")
}
It will output:
toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18
As Cleiton pointed out in his answer, moment.js can be used for this:
moment().startOf('day')
.seconds(15457)
.format('H:mm:ss');
Here's a simple function for converting times that might help
function formatSeconds(seconds) {
var date = new Date(1970,0,1);
date.setSeconds(seconds);
return date.toTimeString().replace(/.*(\d{2}:\d{2}:\d{2}).*/, "$1");
}
This does the trick:
function secondstotime(secs)
{
var t = new Date(1970,0,1);
t.setSeconds(secs);
var s = t.toTimeString().substr(0,8);
if(secs > 86399)
s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
return s;
}
(Sourced from here)
var timeInSec = "661"; //even it can be string
String.prototype.toHHMMSS = function () {
/* extend the String by using prototypical inheritance */
var seconds = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(seconds / 3600);
var minutes = Math.floor((seconds - (hours * 3600)) / 60);
seconds = seconds - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
var time = hours+':'+minutes+':'+seconds;
return time;
}
alert("5678".toHHMMSS()); // "01:34:38"
console.log(timeInSec.toHHMMSS()); //"00:11:01"
we can make this function lot shorter and crisp but that decreases the readability, so we will write it as simple as possible and as stable as possible.
or you can check this working here:
I think the most general (and cryptic) solution could be this
function hms(seconds) {
return [3600, 60]
.reduceRight(
(pipeline, breakpoint) => remainder =>
[Math.floor(remainder / breakpoint)].concat(pipeline(remainder % breakpoint)),
r => [r]
)(seconds)
.map(amount => amount.toString().padStart(2, '0'))
.join('-');
}
Or to copy & paste the shortest version
function hms(seconds) {
return [3600, 60]
.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(seconds)
.map(a => a.toString().padStart(2, '0'))
.join('-');
}
Some example outputs:
> hms(0)
< "00-00-00"
> hms(5)
< "00-00-05"
> hms(60)
< "00-01-00"
> hms(3785)
< "01-03-05"
> hms(37850)
< "10-30-50"
> hms(378500)
< "105-08-20"
How it works
Algorithm
To get hours you divide total seconds by 3600 and floor it.
To get minutes you divide remainder by 60 and floor it.
To get seconds you just use the remainder.
It would also be nice to keep individual amounts in an array for easier formatting.
For example given the input of 3785s the output should be [1, 3, 5], that is 1 hour, 3 minutes and 5 seconds.
Creating pipeline
Naming the 3600 and 60 constants "breakpoints" you can write this algorithm into function as this
function divideAndAppend(remainder, breakpoint, callback) {
return [Math.floor(remainder / breakpoint)].concat(callback(remainder % breakpoint));
}
It returns an array where first item is the amount for given breakpoint and the rest of the array is given by the callback.
Reusing the divideAndAppend in callback function will give you a pipeline of composed divideAndAppend functions. Each one of these
computes amount per given breakpoint and append it to the array making your desired output.
Then you also need the "final" callback that ends this pipeline. In another words you used all breakpoints and now you have only the remainder.
Since you have already the answer at 3) you should use some sort of identity function, in this case remainder => [remainder].
You can now write the pipeline like this
let pipeline = r3 => divideAndAppend(
r3,
3600,
r2 => divideAndAppend(
r2,
60,
r1 => [r1]));
> pipeline(3785)
< [1, 3, 5]
Cool right?
Generalizing using for-loop
Now you can generalize with a variable amount of breakpoints and create a for-loop that will compose individial divideAndAppend functions into
the pipeline.
You start with the identity function r1 => [r1], then use the 60 breakpoint and finally use the 3600 breakpoint.
let breakpoints = [60, 3600];
let pipeline = r => [r];
for (const b of breakpoints) {
const previousPipeline = pipeline;
pipeline = r => divideAndAppend(r, b, previousPipeline);
}
> pipeline(3785)
< [1, 3, 5]
Using Array.prototype.reduce()
Now you can rewrite this for-loop into reducer for shorter and more functional code. In other words rewrite function composition into the reducer.
let pipeline = [60, 3600].reduce(
(ppln, b) => r => divideAndAppend(r, b, ppln),
r => [r]
);
> pipeline(3785)
< [1, 3, 5]
The accumulator ppln is the pipeline and you are composing it using the previous version of it. The initial pipeline is r => [r].
You can now inline the function divideAndAppend and use Array.prototype.reduceRight which is the same as [].reverse().reduce(...) to make the breakpoints
definitions more natural.
let pipeline = [3600, 60]
.reduceRight(
(ppln, b) => r => [Math.floor(r / b)].concat(ppln(r % b)),
r => [r]
);
Which is the final form. Then you just appy mapping to string with padded 0's on left and join the strings with : separator;
More generalizations
Wrapping the reducer into function
function decompose(total, breakpoints) {
return breakpoints.reduceRight(
(p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
r => [r]
)(total);
}
> decompose(3785, [3600, 60])
< [1, 3, 5]
you now have very general algorithm you can work with. For example:
Convert easily (the weird) us length standards
Given the standards
Unit
Divisions
1 foot
12 inches
1 yard
3 feet
1 mile
1760 yards
> decompose(123_456, [1760 * 3 * 12, 3 * 12, 12])
< [1, 1669, 1, 0]
123456 in = 1 mi, 1669 yd, 1 feet and 0 in
Or you can somewhat convert to decimal or binary representations
> decompose(123_456, [100_000, 10_000, 1000, 100, 10])
< [1, 2, 3, 4, 5, 6]
> decompose(127, [128, 64, 32, 16, 8, 4, 2])
< [0, 1, 1, 1, 1, 1, 1, 1]
Works also with floating point breakpoints
Since Javascript supports mod operator with floating point numbers, you can also do
> decompose(26.5, [20, 2.5])
< [1, 2, 1.5]
The edge case of no breakpoints is also naturally covered
> decompose(123, [])
< [123]
Try this:
function toTimeString(seconds) {
return (new Date(seconds * 1000)).toUTCString().match(/(\d\d:\d\d:\d\d)/)[0];
}
Here is an extension to Number class. toHHMMSS() converts seconds to an hh:mm:ss string.
Number.prototype.toHHMMSS = function() {
var hours = Math.floor(this / 3600) < 10 ? ("00" + Math.floor(this / 3600)).slice(-2) : Math.floor(this / 3600);
var minutes = ("00" + Math.floor((this % 3600) / 60)).slice(-2);
var seconds = ("00" + (this % 3600) % 60).slice(-2);
return hours + ":" + minutes + ":" + seconds;
}
// Usage: [number variable].toHHMMSS();
// Here is a simple test
var totalseconds = 1234;
document.getElementById("timespan").innerHTML = totalseconds.toHHMMSS();
// HTML of the test
<div id="timespan"></div>
Easy to follow version for noobies:
var totalNumberOfSeconds = YOURNUMBEROFSECONDS;
var hours = parseInt( totalNumberOfSeconds / 3600 );
var minutes = parseInt( (totalNumberOfSeconds - (hours * 3600)) / 60 );
var seconds = Math.floor((totalNumberOfSeconds - ((hours * 3600) + (minutes * 60))));
var result = (hours < 10 ? "0" + hours : hours) + ":" + (minutes < 10 ? "0" + minutes : minutes) + ":" + (seconds < 10 ? "0" + seconds : seconds);
console.log(result);
This function should do it :
var convertTime = function (input, separator) {
var pad = function(input) {return input < 10 ? "0" + input : input;};
return [
pad(Math.floor(input / 3600)),
pad(Math.floor(input % 3600 / 60)),
pad(Math.floor(input % 60)),
].join(typeof separator !== 'undefined' ? separator : ':' );
}
Without passing a separator, it uses : as the (default) separator :
time = convertTime(13551.9941351); // --> OUTPUT = 03:45:51
If you want to use - as a separator, just pass it as the second parameter:
time = convertTime(1126.5135155, '-'); // --> OUTPUT = 00-18-46
See also this Fiddle.
Chiming in on this old thread -- the OP stated HH:MM:SS, and many of the solutions work, until you realize you need more than 24 hours listed. And maybe you don't want more than a single line of code. Here you go:
d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}
It returns H+:MM:SS. To use it, simply use:
d(91260); // returns "25:21:00"
d(960); // returns "0:16:00"
...I tried to get it to use the least amount of code possible, for a nice one-liner approach.
For the special case of HH:MM:SS.MS (eq: "00:04:33.637") as used by FFMPEG to specify milliseconds.
[-][HH:]MM:SS[.m...]
HH expresses the number of hours, MM the number of minutes for a
maximum of 2 digits, and SS the number of seconds for a maximum of 2
digits. The m at the end expresses decimal value for SS.
/* HH:MM:SS.MS to (FLOAT)seconds ---------------*/
function timerToSec(timer){
let vtimer = timer.split(":")
let vhours = +vtimer[0]
let vminutes = +vtimer[1]
let vseconds = parseFloat(vtimer[2])
return vhours * 3600 + vminutes * 60 + vseconds
}
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
/* Example: 7hours, 4 minutes, 33 seconds and 637 milliseconds */
const t = "07:04:33.637"
console.log(
t + " => " +
timerToSec(t) +
"s"
)
/* Test: 25473 seconds and 637 milliseconds */
const s = 25473.637 // "25473.637"
console.log(
s + "s => " +
secToTimer(s)
)
Example usage, a milliseconds transport timer:
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
let job, origin = new Date().getTime()
const timer = () => {
job = requestAnimationFrame(timer)
OUT.textContent = secToTimer((new Date().getTime() - origin) / 1000)
}
requestAnimationFrame(timer)
span {font-size:4rem}
<span id="OUT"></span>
<br>
<button onclick="origin = new Date().getTime()">RESET</button>
<button onclick="requestAnimationFrame(timer)">RESTART</button>
<button onclick="cancelAnimationFrame(job)">STOP</button>
Example usage, binded to a media element
/* Seconds to (STRING)HH:MM:SS.MS --------------*/
function secToTimer(sec){
let o = new Date(0)
let p = new Date(sec*1000)
return new Date(p.getTime()-o.getTime())
.toISOString()
.split("T")[1]
.split("Z")[0]
}
VIDEO.addEventListener("timeupdate", function(e){
OUT.textContent = secToTimer(e.target.currentTime)
}, false)
span {font-size:4rem}
<span id="OUT"></span><br>
<video id="VIDEO" width="400" controls autoplay>
<source src="https://www.w3schools.com/html/mov_bbb.mp4" type="video/mp4">
</video>
Outside the question, those functions written in php:
<?php
/* HH:MM:SS to (FLOAT)seconds ------------------*/
function timerToSec($timer){
$vtimer = explode(":",$timer);
$vhours = (int)$vtimer[0];
$vminutes = (int)$vtimer[1];
$vseconds = (float)$vtimer[2];
return $vhours * 3600 + $vminutes * 60 + $vseconds;
}
/* Seconds to (STRING)HH:MM:SS -----------------*/
function secToTimer($sec){
return explode(" ", date("H:i:s", $sec))[0];
}
After looking at all the answers and not being happy with most of them, this is what I came up with. I know I am very late to the conversation, but here it is anyway.
function secsToTime(secs){
var time = new Date();
// create Date object and set to today's date and time
time.setHours(parseInt(secs/3600) % 24);
time.setMinutes(parseInt(secs/60) % 60);
time.setSeconds(parseInt(secs%60));
time = time.toTimeString().split(" ")[0];
// time.toString() = "HH:mm:ss GMT-0800 (PST)"
// time.toString().split(" ") = ["HH:mm:ss", "GMT-0800", "(PST)"]
// time.toTimeString().split(" ")[0]; = "HH:mm:ss"
return time;
}
I create a new Date object, change the time to my parameters, convert the Date Object to a time string, and removed the additional stuff by splitting the string and returning only the part that need.
I thought I would share this approach, since it removes the need for regex, logic and math acrobatics to get the results in "HH:mm:ss" format, and instead it relies on built in methods.
You may want to take a look at the documentation here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date
below is the given code which will convert seconds into hh-mm-ss format:
var measuredTime = new Date(null);
measuredTime.setSeconds(4995); // specify value of SECONDS
var MHSTime = measuredTime.toISOString().substr(11, 8);
Get alternative method from Convert seconds to HH-MM-SS format in JavaScript
var time1 = date1.getTime();
var time2 = date2.getTime();
var totalMilisec = time2 - time1;
alert(DateFormat('hh:mm:ss',new Date(totalMilisec)))
/* ----------------------------------------------------------
* Field | Full Form | Short Form
* -------------|--------------------|-----------------------
* Year | yyyy (4 digits) | yy (2 digits)
* Month | MMM (abbr.) | MM (2 digits)
| NNN (name) |
* Day of Month | dd (2 digits) |
* Day of Week | EE (name) | E (abbr)
* Hour (1-12) | hh (2 digits) |
* Minute | mm (2 digits) |
* Second | ss (2 digits) |
* ----------------------------------------------------------
*/
function DateFormat(formatString,date){
if (typeof date=='undefined'){
var DateToFormat=new Date();
}
else{
var DateToFormat=date;
}
var DAY = DateToFormat.getDate();
var DAYidx = DateToFormat.getDay();
var MONTH = DateToFormat.getMonth()+1;
var MONTHidx = DateToFormat.getMonth();
var YEAR = DateToFormat.getYear();
var FULL_YEAR = DateToFormat.getFullYear();
var HOUR = DateToFormat.getHours();
var MINUTES = DateToFormat.getMinutes();
var SECONDS = DateToFormat.getSeconds();
var arrMonths = new Array("January","February","March","April","May","June","July","August","September","October","November","December");
var arrDay=new Array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
var strMONTH;
var strDAY;
var strHOUR;
var strMINUTES;
var strSECONDS;
var Separator;
if(parseInt(MONTH)< 10 && MONTH.toString().length < 2)
strMONTH = "0" + MONTH;
else
strMONTH=MONTH;
if(parseInt(DAY)< 10 && DAY.toString().length < 2)
strDAY = "0" + DAY;
else
strDAY=DAY;
if(parseInt(HOUR)< 10 && HOUR.toString().length < 2)
strHOUR = "0" + HOUR;
else
strHOUR=HOUR;
if(parseInt(MINUTES)< 10 && MINUTES.toString().length < 2)
strMINUTES = "0" + MINUTES;
else
strMINUTES=MINUTES;
if(parseInt(SECONDS)< 10 && SECONDS.toString().length < 2)
strSECONDS = "0" + SECONDS;
else
strSECONDS=SECONDS;
switch (formatString){
case "hh:mm:ss":
return strHOUR + ':' + strMINUTES + ':' + strSECONDS;
break;
//More cases to meet your requirements.
}
}
I just wanted to give a little explanation to the nice answer above:
var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;
var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds < 10 ? "0" + seconds : seconds);
On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.
When you see something like this:
25 % 24
Think of it like this:
25 mod 24 or what is the remainder when we divide 25 by 24
None of the answers here satisfies my requirements as I want to be able to handle
Large numbers of seconds (days), and
Negative numbers
Although those are not required by the OP, it's good practice to cover edge cases, especially when it takes little effort.
It's pretty obvious is that the OP means a NUMBER of seconds when he says seconds. Why would peg your function on String?
function secondsToTimeSpan(seconds) {
const value = Math.abs(seconds);
const days = Math.floor(value / 1440);
const hours = Math.floor((value - (days * 1440)) / 3600);
const min = Math.floor((value - (days * 1440) - (hours * 3600)) / 60);
const sec = value - (days * 1440) - (hours * 3600) - (min * 60);
return `${seconds < 0 ? '-':''}${days > 0 ? days + '.':''}${hours < 10 ? '0' + hours:hours}:${min < 10 ? '0' + min:min}:${sec < 10 ? '0' + sec:sec}`
}
secondsToTimeSpan(0); // => 00:00:00
secondsToTimeSpan(1); // => 00:00:01
secondsToTimeSpan(1440); // => 1.00:00:00
secondsToTimeSpan(-1440); // => -1.00:00:00
secondsToTimeSpan(-1); // => -00:00:01
Simple function to convert seconds into in hh:mm:ss format :
function getHHMMSSFromSeconds(totalSeconds) {
if (!totalSeconds) {
return '00:00:00';
}
const hours = Math.floor(totalSeconds / 3600);
const minutes = Math.floor(totalSeconds % 3600 / 60);
const seconds = totalSeconds % 60;
const hhmmss = padTo2(hours) + ':' + padTo2(minutes) + ':' + padTo2(seconds);
return hhmmss;
}
// function to convert single digit to double digit
function padTo2(value) {
if (!value) {
return '00';
}
return value < 10 ? String(value).padStart(2, '0') : value;
}
Here is a function to convert seconds to hh-mm-ss format based on powtac's answer here
jsfiddle
/**
* Convert seconds to hh-mm-ss format.
* #param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
var hours = Math.floor(totalSeconds / 3600);
var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
var seconds = totalSeconds - (hours * 3600) - (minutes * 60);
// round seconds
seconds = Math.round(seconds * 100) / 100
var result = (hours < 10 ? "0" + hours : hours);
result += "-" + (minutes < 10 ? "0" + minutes : minutes);
result += "-" + (seconds < 10 ? "0" + seconds : seconds);
return result;
}
Example use
var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10
There are lots of options of solve this problem, and obvious there are good option suggested about, But I wants to add one more optimized code here
function formatSeconds(sec) {
return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
.map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
.filter((i, j) => i !== "00" || j > 0)
.join(":");
}
if you don't wants formatted zero with less then 10 number, you can use
function formatSeconds(sec) {
return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);
}
Sample Code http://fiddly.org/1c476/1
In one line, using T.J. Crowder's solution :
secToHHMMSS = seconds => `${Math.floor(seconds / 3600)}:${Math.floor((seconds % 3600) / 60)}:${Math.floor((seconds % 3600) % 60)}`
In one line, another solution that also count days :
secToDHHMMSS = seconds => `${parseInt(seconds / 86400)}d ${new Date(seconds * 1000).toISOString().substr(11, 8)}`
Source : https://gist.github.com/martinbean/2bf88c446be8048814cf02b2641ba276
var sec_to_hms = function(sec){
var min, hours;
sec = sec - (min = Math.floor(sec/60))*60;
min = min - (hours = Math.floor(min/60))*60;
return (hours?hours+':':'') + ((min+'').padStart(2, '0')) + ':'+ ((sec+'').padStart(2, '0'));
}
alert(sec_to_hms(2442542));
Have you tried adding seconds to a Date object?
Date.prototype.addSeconds = function(seconds) {
this.setSeconds(this.getSeconds() + seconds);
};
var dt = new Date();
dt.addSeconds(1234);
A sample:
https://jsfiddle.net/j5g2p0dc/5/
Updated:
Sample link was missing so I created a new one.
You can also use below code:
int ss = nDur%60;
nDur = nDur/60;
int mm = nDur%60;
int hh = nDur/60;
For anyone using AngularJS, a simple solution is to filter the value with the date API, which converts milliseconds to a string based on the requested format. Example:
<div>Offer ends in {{ timeRemaining | date: 'HH:mm:ss' }}</div>
Note that this expects milliseconds, so you may want to multiply timeRemaining by 1000 if you are converting from seconds (as the original question was formulated).
I ran into the case some have mentioned where the number of seconds is more than a day. Here's an adapted version of #Harish Anchu's top-rated answer that accounts for longer periods of time:
function secondsToTime(seconds) {
const arr = new Date(seconds * 1000).toISOString().substr(11, 8).split(':');
const days = Math.floor(seconds / 86400);
arr[0] = parseInt(arr[0], 10) + days * 24;
return arr.join(':');
}
Example:
secondsToTime(101596) // outputs '28:13:16' as opposed to '04:13:16'
String.prototype.toHHMMSS = function () {
var sec_num = parseInt(this, 10); // don't forget the second param
var hours = Math.floor(sec_num / 3600);
var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
var seconds = sec_num - (hours * 3600) - (minutes * 60);
if (hours < 10) {hours = "0"+hours;}
if (minutes < 10) {minutes = "0"+minutes;}
if (seconds < 10) {seconds = "0"+seconds;}
return hours+':'+minutes+':'+seconds;
}
Usage Example
alert("186".toHHMMSS());