I use the npm package use-dark-mode as the name implies, it makes it possible to change the theme to light or dark, The problem is that I want to change the background-color of some blocks when changing the theme to dark, and vice versa, return the old color when I switch to light mode, for example, my block background is orange, I switch to dark mode, it turns red and when I switch to light mode, it returns old orange
App.js
import React from 'react';
import './App.css'
import Content from "./components/Content/Content";
import Dark_Mode from "./components/Dark Mode/Dark_Mode";
const App = () => {
return(
<div>
<Dark_Mode />
<Content />
</div>
);
};
export default App;
Content.jsx
import React from 'react';
import './style.css'
const Content = () => {
return (
<>
<div className={"content_container"}>
<h3>Hello from React.JS</h3>
</div>
</>
);
};
export default Content;
Dark_Mode.jsx
import React from 'react';
import useDarkMode from 'use-dark-mode';
const DarkModeToggle = () => {
const darkMode = useDarkMode(false);
return (
<div>
<button type="button" onClick={darkMode.disable}>
☀
</button>
<button type="button" onClick={darkMode.enable}>
☾
</button>
</div>
);
};
export default DarkModeToggle;
style.css
#import '../../App.css';
.content_container {
margin: auto;
width: 500px;
max-width: 100%;
background: orange;
}
.content_container h3 {
text-align: center;
}
App.css
body.light-mode {
background-color: #fff;
color: #333;
transition: background-color 0.3s ease;
}
body.dark-mode {
background-color: #1a1919;
color: #999;
}
:root {
--color-orange: orange;
}
As you can see, I have App.css when the theme changes, it changes the background of the <body>, I still have Content.jsx when switching theme I want to change the background of the block with the className content_container which is connected to style.css, In addition, you may have noticed that I tried to use global styles, but I failed. Finally, I would like to show a screenshot on the site for a clear understanding of everything.
You could give the root element a class on theme change and use css variables in root, but be class specific:
Dark_mode.jsx:
function setTheme(themeName) {
document.documentElement.classList.remove('light-theme', 'dark-theme');
document.documentElement.classList.add(themeName);
}
const DarkModeToggle = () => {
const activateDarkTheme = () => setTheme('dark-theme');
const activateLightTheme = () => setTheme('light-theme');
return (
<div>
<button type="button" onClick={activateDarkTheme}>
☀
</button>
<button type="button" onClick={activateLightTheme}>
☾
</button>
</div>
);
};
Styles:
:root, // this is used for the default theme, will be overwritten by other styles with classes because of specifity
:root.dark-theme {
--color-bg: #000;
}
:root.light-theme {
--color-bg: #fff;
}
I found a more convenient solution! although it is my fault, I was a little inattentive and did not study the documentation of this package that I use in my project, here is a simple solution
Content.jsx
import './Content.css'
import useDarkMode from 'use-dark-mode';
export default function Content () {
const { value } = useDarkMode(false);
return <div>
<div className={value ? 'Dark_Mode' : 'Light_Mode'}>
<h3>Hello from React.JS</h3>
</div>
</div>
}
Content.css
.Dark_Mode {
margin: auto;
max-width: 100%;
width: 400px;
height: 275px;
background-color: orange;
}
.Light_Mode {
margin: auto;
max-width: 100%;
width: 400px;
height: 275px;
background-color: rgb(24, 106, 199);
}
Related
Having the following components:
<CheckboxGroupLabel htmlFor={option.label}>
<FormCheckbox
onClick={() => onChange}
key={option.label}
defaultChecked={defaultChecked}
{...rest}
/>
{option.value}
</CheckboxGroupLabel>
Their styled components are:
import styled from 'styled-components';
import * as Checkbox from '#radix-ui/react-checkbox';
export const CheckboxGroupLabel = styled.label`
background-color: red;
display: flex;
width: 100%;
margin: 18px;
line-height: 20px;
cursor: pointer;
width: 100px;
`;
export const StyledCheckboxRoot = styled(Checkbox.Root)`
button {
all: unset;
}
`;
So the checkbox is inside label but only checkbox is clickable, I would like to make the whole label clickable.
Is there a way to do that?
Have you tried just moving onClick into CheckboxGroupLabel?
https://codesandbox.io/s/label-onclick-3ebkbi
import "./styles.css";
import * as Checkbox from "#radix-ui/react-checkbox";
import { CheckIcon } from "#radix-ui/react-icons";
export default function MyComponent() {
const onLabelClick = () => {
console.log("clicked label");
};
return (
<div>
<label onClick={onLabelClick} htmlFor="mycheckbox">
<Checkbox.Root className="checkbox" defaultChecked id="mycheckbox">
<Checkbox.Indicator className="indicator">
<CheckIcon />
</Checkbox.Indicator>
My checkbox label
</Checkbox.Root>
</label>
</div>
);
}
Whenever I try to style Antd Design component ( Layout, Sider and so on ) but it doesn't seems to be working. Therefore there won't be any changes on them. But it works fine on other HTML elements like div, h1, p tags.
Here's my code:
.sidbar{
flex: 1;
background-color: red;
border-right: 0.5px solid rgb(218, 217, 217);
min-height: 100vh;
background-color: white;
}
import styles from "../styles/Sidebar.module.scss";
import React from "react";
import { Layout, Menu } from "antd";
const { Header, Content, Footer, Sider } = Layout;
import {
HomeOutlined,
DashboardOutlined,
TeamOutlined,
} from "#ant-design/icons";
import Link from "next/link";
const Sidebar = () => {
return (
<div>
<Layout className={styles.sidebar}>
<Header>header</Header>
<Layout>
<Sider>left sidebar</Sider>
<Content>main content</Content>
<Sider>right sidebar</Sider>
</Layout>
<Footer>footer</Footer>
</Layout>
</div>
);
};
export default Sidebar;
I would like to specify style(background and text color) of the button that will be disabled later in code.
button needs to look like this on render and like this after click
My code is
import React, { useState, useEffect } from "react";
import "./styles.css";
export default function App() {
const [loading, setLoading] = useState(false);
const handleClick = (e) => {
e.preventDefault();
setLoading(true);
};
return (
<div className="App">
<button disabled={loading} onClick={handleClick} className="btn">
{" "}
Click me
</button>
</div>
);
}
and Css
.btn {
width: 200px;
height: 50px;
background-color: blue;
/* color: white; */
}
.btn:hover {
cursor: pointer;
}
link to codesandbox
When I specify color of the text(white) disabled doesn't change color to grey( button doesn't look disabled), when text color is not defined, it's black and after click it's grey. Is there any way to define text color as white before click, and when button is clicked change color to grey? Because I need to make the button with blue background and white text on render. Thank you anyone who will help me.
Most of this can be done with CSS, though you'll need to add one more thing to your React component.
JS:
import React, { useState, useEffect } from "react";
import "./styles.css";
export default function App() {
const [loading, setLoading] = useState(false);
const handleClick = (e) => {
e.preventDefault();
setLoading(true);
};
return (
<div className="App">
<button disabled={loading} onClick={handleClick} className={`btn${loading ? ' disabled' : ''}`}>
{" "}
Click me
</button>
</div>
);
}
CSS
.btn {
width: 200px;
height: 50px;
background-color: blue;
/* color: white; */
}
.btn.disabled {
opacity: .65;
pointer-events: none;
}
.btn:hover {
cursor: pointer;
}
.btn:active {
color: green; // Or whatever style you want
}
EDIT: You can also use the :enabled and :disabled pseudo-selectors like the comment above said.
I would like to add some transition styling to my side navigation on my app. I am able to do this using normal classes however in this tutorial they use css modules and i am unsure how to do this using css modules.
I would like my nav to glide in and out, at the moment it jumps statically when the onClick function fires - toggleSideDrawer.
I have used this logic but I am not sure if it is doing anything:
className={props.toggleSideDrawer ? classes.SideDrawerOpen : classes.SideDrawer
Essentially i want that when the user clicks the toggle, the transform property switches from translateX(-100%) to translateX(0) but this is not happening.
Side nav code:
import React from "react";
import Logo from "../../Logo/Logo";
import NavigationItems from "../NavigationItems/NavigationItems";
import Backdrop from "../../UI/Backdrop/Backdrop";
import Aux from "../../../hoc/Aux";
import classes from "./SideDrawer.css";
const SideDrawer = props => {
return (
<Aux classname={classes.SideDrawer}>
<Backdrop
showBackdrop={props.showSideDrawer}
clicked={props.toggleSideDrawer}
/>
{props.showSideDrawer && (
<div
onClick={props.toggleSideDrawer}
className={
props.toggleSideDrawer ? classes.SideDrawerOpen : classes.SideDrawer
}
>
<div className={classes.Logo}>
<Logo />
</div>
<nav>
<NavigationItems />
</nav>
</div>
)}
</Aux>
);
};
export default SideDrawer;
Where the code is used in my Layout component:
import React, { useState } from "react";
import Aux from "../Aux";
import classes from "./Layout.css";
import Toolbar from "../../components/Navigation/Toolbar/Toolbar";
import SideDrawer from "../../components/Navigation/SideDrawer/SideDrawer";
const layout = props => {
const [showSideDrawer, setShowSideDrawer] = useState(false);
return (
<Aux>
<SideDrawer
showSideDrawer={showSideDrawer}
toggleSideDrawer={() => {
setShowSideDrawer(!showSideDrawer);
}}
/>
<Toolbar
onMenuClick={() => {
setShowSideDrawer(!showSideDrawer);
}}
/>
<main className={classes.mainContent}> {props.children} </main>
</Aux>
);
};
export default layout;
CSS:
.SideDrawer {
position: fixed;
width: 280px;
max-width: 70%;
height: 100%;
left: 0;
top: 0;
z-index: 200;
background-color: white;
padding: 32px 16px;
box-sizing: border-box;
transform: translateX(-100%);
}
#media (min-width: 500px) {
.SideDrawer {
display: none;
}
}
.Logo {
height: 11%;
text-align: center;
}
.SideDrawerOpen {
position: fixed;
width: 280px;
max-width: 70%;
height: 100%;
left: 0;
top: 0;
z-index: 200;
padding: 32px 16px;
box-sizing: border-box;
background-color: red;
transform: translateX(0);
transition: transform 0.3s ease-out;
}
The thing is that you need the element will has the transition rule all the time.
My suggestion is to set a static class which which will hold all the styles and addd another one only for overriding transform to make it move.
Something like that (it uses scss but it's easy to do it with css)
.SideDrawer {
position: fixed;
width: 280px;
max-width: 70%;
height: 100%;
left: 0;
top: 0;
z-index: 200;
background-color: white;
padding: 32px 16px;
box-sizing: border-box;
transition: transform .3s ease;
transform: translateX(-100%);
&.show {
transform: translateX(0);
}
}
export const App = () => {
const [showSideDrawer, setShowSideDrawer] = useState(false);
const sidebarClasses = classname([
styles.SideDrawer,
{
[styles.show]: showSideDrawer
}
]);
const ToggleSidebar = () => {
return (
<button onClick={() => setShowSideDrawer(!showSideDrawer)}>
Toggle Sidebar
</button>
);
};
return (
<Fragment>
<h1>App</h1>
<div className={sidebarClasses}>
<div>Sidebar content</div>
<ToggleSidebar />
</div>
<ToggleSidebar />
</Fragment>
);
};
https://codesandbox.io/s/xenodochial-framework-04sbe?file=/src/App.jsx
#MoshFeu helped me fix this.
The problem is that you render the drawer only when showSideDrawer so before it becomes true, the sidebar is not in the DOM yet so the transition is not affecting it.
The solution is to keep it in the DOM all the time but toggle . Open class to change the style.
There are libraries that knows to make the transition works even for elements that are not in the DOM but it's a bit more complicated.
code fix for SideDrawer.js without the conditional within the return
class SideDrawer extends Component {
render() {
let sideDrawerClass = [classes.SideDrawer];
// SideDrawer will now be an array with the side drawer classes and the open class
if (this.props.showSideDrawer) {
sideDrawerClass.push(classes.Open);
}
return (
<Aux classname={classes.SideDrawer}>
<Backdrop
showBackdrop={this.props.showSideDrawer}
clicked={this.props.toggleSideDrawer}
/>
<div
className={sideDrawerClass.join(" ")}
onClick={this.props.toggleSideDrawer}
>
<div className={classes.Logo}>
<Logo />
</div>
<nav>
<NavigationItems />
</nav>
</div>
</Aux>
);
}
}
export default SideDrawer;
How can I add CSS for react semantic UI ? I am using create react app. I have installed semantic-ui-react and CSS CDN: https://react.semantic-ui.com/usage/?fbclid=IwAR3ZBaJfpxHGiNcAvophLp7IAPO-gHZfDvSOLs8h-n0-_29ncPoOdjwCX7o#content-delivery-network-cdn
loginForm.js:
import React from "react";
import { Button, Form, Header } from "semantic-ui-react";
import styles from './loginForm.css';
const LoginForm = () => (
<Form className={styles.formStyle}>
<Button className={styles.buttonStyle}>Login</Button>
</Form>
);
export default LoginForm;
loginForm.css:
.formStyle {
margin-left: 500px;
margin-top: 100px;
width: 550px;
}
.buttonStyle {
border-radius: 18px;
width: 200px;
background-color:#3865FE;
}
Above CSS code is not working for loginForm.js why so ? I also tried following :
<Form style={styles.formStyle}>
<Button style={styles.buttonStyle}>Login</Button>
</Form>
Above code is also not working.
Actually you're setting the value of className incorrectly.
Here is the modified version of your code.
import React from "react";
import { Button, Form, Header } from "semantic-ui-react";
import from './loginForm.css';
const LoginForm = () => (
<Form className='formStyle'>
<Button className='buttonStyle'>Login</Button>
</Form>
);
export default LoginForm;
and for loginForm.css
.ui.form.formStyle {
margin-left: 300px ;
margin-top: 100px ;
width: 550px ;
height: 400px;
}
.ui.button.buttonStyle {
border-radius: 18px;
width: 200px;
background-color:#3865FE;
}
thanks #funJoker for suggesting me how to edit semantic-ui style.