I have the following sentence as a test:
This is a test with #shouldshow and to see if there #show
#yes this#shouldnotshow what is going on here
I have figured out most of the Reg Exp I need. Here's what I have so far: /((?<=#)([A-Z]*))/gi
This matches every tag but also matches the shouldnotshow portion. I want to not match words that are prefixed by anything but # (excluding whitespace & \n).
So the only matched words I should get are: shouldshow show yes.
Note: after #show is a newline
You just need to see if the hash is prefixed with whitespace or starts the string
https://regex101.com/r/JDuGvr/1
/(\s|^)#(\w+)/gm
with positive lookbehind as OP used
https://regex101.com/r/06X3ZX/1
/(?<=(\s|^)#)(\w+)/gm;
use [a-zA-Z0-9] if you do not want an underscore
const re1 = /(\s|^)#(\w+)/gm;
const re2 = /(?<=(\s|^)#)(\w+)/gm;
const str = `This is a test with #shouldshow and to see if there #show
#yes this#shouldnotshow what is going on here`;
const res1 = [...str.matchAll(re1)].map(match => match[2]); // here the match is the third item
console.log(res1)
const res2 = [...str.matchAll(re2)].map(match => match[0]); // match is the first item
console.log(res2)
Another option could be using your pattern asserting a # on the left that does not have a non whitespace char before it using (?<!\S)# and get the match only without capture groups.
Match at least 1+ times a char A-Z to prevent matching an empty string.
(?<=(?<!\S)#)[A-Z]+
Regex demo
const regex = /(?<=(?<!\S)#)[A-Z]+/gi;
const str = `This is a test with #shouldshow and to see if there #show
#yes this#shouldnotshow what is going on her`;
console.log(str.match(regex));
Related
I want this string {Rotation:[45f,90f],lvl:10s} to turn into {Rotation:[45,90],lvl:10}.
I've tried this:
const bar = `{Rotation:[45f,90f],lvl:10s}`
const regex = /(\d)\w+/g
console.log(bar.replace(regex, '$&'.substring(0, -1)))
I've also tried to just select the letter at the end using $ but I can't seem to get it right.
You can use
bar.replace(/(\d+)[a-z]\b/gi, '$1')
See the regex demo.
Here,
(\d+) - captures one or more digits into Group 1
[a-z] - matches any letter
\b - at the word boundary, ie. at the end of the word
gi - all occurrences, case insensitive
The replacement is Group 1 value, $1.
See the JavaScript demo:
const bar = `{Rotation:[45f,90f],lvl:10s}`
const regex = /(\d+)[a-z]\b/gi
console.log(bar.replace(regex, '$1'))
Check this out :
const str = `{Rotation:[45f,90f],lvl:10s}`.split('');
const x = str.splice(str.length - 2, 1)
console.log(str.join(''));
You can use positive lookahead to match the closing brace, but not capture it. Then the single character can be replaced with a blank string.
const bar= '{Rotation:[45f,90f],lvl:10s}'
const regex = /.(?=})/g
console.log(bar.replace(regex, ''))
{Rotation:[45f,90f],lvl:10}
The following regex will match each group of one or more digits followed by f or s.
$1 represents the contents captured by the capture group (\d).
const bar = `{Rotation:[45f,90f],lvl:10s}`
const regex = /(\d+)[fs]/g
console.log(bar.replace(regex, '$1'))
I trying to have a regular expression which is finding between two words but those words are not certain one.
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303
This is my text. I'm trying to find the word between Soyadı and Sınıfı, in this case ERTANĞA, but the word Sınıfı also can be no, numara or any number. This is what I did.
soyad[ıi](.*)S[ıi]n[ıi]f[ıi]|no|numara|[0-9]
[ıi] is for Turkish character issue, don't mind that.
You can use something like below :
/.*Soyad(ı|i)|S(ı|i)n(ı|i)f(ı|i).*|no.*|numera.*|[0-9]/gmi
Here is the link I worked on : https://regex101.com/r/QXLjLF/1
In JS code:
const regex = /.*Soyad(ı|i)|S(ı|i)n(ı|i)f(ı|i).*|no.*|numera.*|[0-9]/gmi;
var str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303`;
var newStr = str.replace(regex, '');
console.log(newStr);
You can use a single capture group to get the word ERTANĞA, keep the character class [ıi] instead of using an alternation for (ı|i) and group the alternatives at the end of the pattern using a non capture group (?:
soyad[ıi](.+?)(?:S[ıi]n[ıi]f[ıi]|n(?:o|umara)|[0-9])
soyad[ıi] Match soyadı or soyadi
(.+?) Capture group 1, match 1 or more chars as least as possible
(?: Non capture group
S[ıi]n[ıi]f[ıi] Match S and then ı or i etc..
| Or
n(?:o|umara) Match either no or numara
| Or
[0-9] Match a digit 0-9
) Close non capture group
Note that you don't need the /m flag as there are no anchors in the pattern.
Regex demo
const regex = /soyad[ıi](.+?)(?:S[ıi]n[ıi]f[ıi]|n(?:o|umara)|[0-9])/gi;
const str = "2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303\n";
console.log(Array.from(str.matchAll(regex), m => m[1]));
This might do it
const str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnumaraE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnoE10/ENo303`
const re = /(?:Soyad(ı|i))(.*?)(?:S(ı|i)n(ı|i)f(ı|i)|no|numara)/gmi
console.log([...str.matchAll(re)].map(x => x[2]))
ES5
const str = `2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞASınıfıE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnumaraE10/ENo303
2015ÖĞLEYEMEKKARTI(2016-20.AdıMEVLÜTSoyadıERTANĞAnoE10/ENo303`
const re = /(?:Soyad(ı|i))(.*?)(?:S(ı|i)n(ı|i)f(ı|i)|no|numara)/gmi
const res = []
let match;
while ((match = re.exec(str)) !== null) res.push(match[2])
console.log(res)
I have this regex that looks for a digit and a character in a word with a minimum length of 4 :
^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{4,}$
it works for :
ABCD1
but if i have multiple words like :
ABCD1 ABCD2
it stop working because the whitespace break the regex :/
How can i improve my regex to allow to capture all the words separated by spaces ?
Demo : https://regex101.com/r/S3APfJ/1
You could use match() on the input to find all matches:
var input = "1234 ABCD1 ABCD2 ABCDE";
var matches = input.match(/\b(?=\S*\d)(?=\S*[a-zA-Z])[a-zA-Z0-9]{4,}\b/g);
console.log(matches);
You can use
text.split(/\s+/).filter(x => /YOUR_VALIDATION_REGEX/.test(x))
NOTE:
.split(/\s+/) - splits the string with whitespace
.filter(x => /^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{4,}$/.test(x) - fetches the item if it matches your initial regex.
See a JavaScript demo:
const text = "this is a phrase with ABC1 and ABCD2 but no ABC1!";
const rx = /^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{4,}$/;
console.log(text.split(/\s+/).filter(x => rx.test(x)));
The /^(?=.*\d)(?=.*[a-zA-Z])[a-zA-Z0-9]{4,}$/ performance can be improved if you use
/^(?=\D*\d)(?=[^a-zA-Z]*[a-zA-Z])[a-zA-Z0-9]{4,}$/
I have the following string:
[TITLE|prefix=a] [STORENAME|prefix=b|suffix=c] [DYNAMIC|limit=10|random=0|reverse=0]
And I would like to get the value of the prefix of TITLE, which is a.
I have tried it with (?<=TITLE|)(?<=prefix=).*?(?=]|\|) and that seems to work but that gives me also the prefix of STORENAME (b). So if [TITLE|prefix=a] will be missing in the string, I'll have the wrong value.
So I need to set the end of the match with ] that belongs to [TITLE. Please notice that this string is dynamic. So it could be [TITLE|suffix=x|prefix=y] as well.
const regex = "[TITLE|prefix=a] [STORENAME|prefix=b|suffix=c] [DYNAMIC|limit=10|random=0|reverse=0]".match(/(?<=TITLE|)(?<=prefix=).*?(?=]|\|)/);
console.log(regex);
You can use
(?<=TITLE(?:\|suffix=[^\]|]+)?\|prefix=)[^\]|]+
See the regex demo. Details:
(?<=TITLE(?:\|suffix=[^\]|]+)?\|prefix=) - a location in string immediately preceded with TITLE|prefix| or TITLE|suffix=...|prefix|
[^\]|]+ - one or more chars other than ] and |.
See JavaScript demo:
const texts = ['[TITLE|prefix=a] [STORENAME|prefix=b|suffix=c] [DYNAMIC|limit=10|random=0|reverse=0]', '[TITLE|suffix=s|prefix=a]'];
for (let s of texts) {
console.log(s, '=>', s.match(/(?<=TITLE(?:\|suffix=[^\]|]+)?\|prefix=)[^\]|]+/)[0]);
}
You could also use a capturing group
\[TITLE\|(?:[^|=\]]*=[^|=\]]*\|)*prefix=([^|=\]]*)[^\]]*]
Explanation
\[TITLE\| Match [TITLE|
(?:\w+=\w+\|)* Repeat 0+ occurrences wordchars = wordchars and |
prefix= Match literally
(\w+) Capture group 1, match 1+ word chars
[^\]]* Match any char except ]
] Match the closing ]
Regex demo
const regex = /\[TITLE\|(?:\w+=\w+\|)*prefix=(\w+)[^\]]*\]/g;
const str = `[TITLE|prefix=a] [STORENAME|prefix=b|suffix=c] [DYNAMIC|limit=10|random=0|reverse=0]
[TITLE|suffix=x|prefix=y]`;
let m;
while ((m = regex.exec(str)) !== null) {
console.log(m[1]);
}
Or with a negated character class instead of \w
\[TITLE\|(?:[^|=\]]*=[^|=\]]*\|)*prefix=([^|=\]]*)[^\]]*]
Regex demo
Actually i have the following RegExp expression:
/^(?:(?:\,([A-Za-z]{5}))?)+$/g
So the accepted input should be something like ,IGORA but even ,IGORA,GIANC,LOLLI is valid and i would be able to slice the string to 3 group in this case, in other the group number should be equals to the user input that pass the RegExp test.
i was trying to do something like this in JavaScript but it return only the last value
var str = ',GIANC,IGORA';
var arr = str.match(/^(?:(?:\,([A-Za-z]{5}))?)+$/).slice(1);
alert(arr);
So the output is 'IGORA' while i would it to be 'GIANC' 'IGORA'
Here is another example
/^([A-Z]{5})(?:(?:\,([A-Za-z]{2}))?)+$/g
test of regexp may have at least 5 chart string but it also can have other 5 chart string separated with a comma so from input
IGORA,CIAOA,POPOP
I would have an array of ["IGORA","CIAOA","POPOP"]
You can capture the words in a capturing surrounded by an optional preceding comma or an optional trailing comma.
You can test the regex here: ,?([A-Za-z]+),?
const pattern = /,?([A-Za-z]+),?/gm;
const str = `,IGORA,GIANC,LOLLI`;
let matches = [];
let match;
// Iterate until no match found
while ((m = pattern.exec(str))) {
// The first captured group is the match
matches.push(m[1]);
}
console.log(matches);
There are other ways to do this, but I found that one of the simple ways is by using the replace method, as it can replace all instances that match that regex.
For example:
var regex = /^(?:(?:\,([A-Za-z]{5}))?)+$/g;
var str = ',GIANC,IGORA';
var arr = [];
str.replace(regex, function(match) {
arr[arr.length] = match;
return match;
});
console.log(arr);
Also, in my code snippet you can see that there is an extra coma in each string, you can solve that by changing line 5 to arr[arr.length] = match.replace(/^,/, '').
Is this what you're looking for?
Explanation:
\b word boundary (starting or ending a word)
\w a word ([A-z])
{5} 5 characters of previous
So it matches all 5-character words but not NANANANA
var str = 'IGORA,CIAOA,POPOP,NANANANA';
var arr = str.match(/\b\w{5}\b/g);
console.log(arr); //['IGORA', 'CIAOA', 'POPOP']
If you only wish to select words separated by commas and nothing else, you can test for them like so:
(?<=,\s*|^) preceded by , with any number of trailing space, OR is the first word in list.
(?=,\s*|$) followed by , and any number of trailing spaces OR is last word in list.
In the following code, POPOP and MOMMA are rejected because they are not separated by a comma, and NANANANA fails because it is not 5 character.
var str = 'IGORA, CIAOA, POPOP MOMMA, NANANANA, MEOWI';
var arr = str.match(/(?<=,\s*|^)\b\w{5}\b(?=,\s*|$)/g);
console.log(arr); //['IGORA', 'CIAOA', 'MEOWI']
If you can't have any trailing spaces after the comma, just leave out the \s* from both (?<=,\s*|^) and (?=,\s*|$).