This is my array:
const
array1 = [
{
"value": "0",
"name": "5",
"waste": "remove",
"city": "NY"
},
{
"value": "0",
"name": "51",
"waste": "remove",
}
]
So now, i wanted to remove certain and form a new array with objects: For example, i need to remove "Waste & value" and keep rest of the things, so i used this code:
var keys_to_keep = ['name', 'city']
const result = array2.map(e => {
const obj = {};
keys_to_keep.forEach(k => obj[k] = e[k])
return obj;
});
console.log(result)
And it gives a output as
[ { name: '5', city: 'NY' }, { name: '51', city: undefined } ]
Now as you can see city with undefined value, how to remove that ? i mean filter this and just show keys with value,
So my question is how to filter undefined and also is there any other better solution for removing unwanted object keys and showing new array with wanted keys ? or the method am using is performant enough ?
You can check if the value is undefined in your forEach:
const result = array2.map(e => {
const obj = {};
keys_to_keep.forEach(k => {
if (undefined !== e[k]) {
obj[k] = e[k]
}
)
return obj;
});
You can check if e[k] is defined before you add it to obj by checking whether the e object has the property k using .hasOwnProperty():
const array = [{ "value": "0", "name": "5", "waste": "remove", "city": "NY" }, { "value": "0", "name": "51", "waste": "remove", } ];
const keys_to_keep = ['name', 'city'];
const result = array.map(e => {
const obj = {};
keys_to_keep.forEach(k => {
if (e.hasOwnProperty(k))
obj[k] = e[k]
});
return obj;
});
console.log(result)
If the keys you want to remove aren't dynamic, you can also use destructuring assignment to pull out the properties you want to discard, and use the rest syntax to obtain an object without those properties:
const array = [{ "value": "0", "name": "5", "waste": "remove", "city": "NY" }, { "value": "0", "name": "51", "waste": "remove", } ];
const result = array.map(({value, waste, ...r}) => r);
console.log(result)
I am going to answer both the parts. So here are the steps to do that.
Use map() on the main array.
Get entries of each object using Object.entries().
Apply filter() on entires array are remove those entires for which key is not present in keys_to_keep
Now for the second part.
Using keys_to_keep create an object which contain undefined values for each key.
Use map() again on prev result and use Spread operator. First spread the object created above and then spread the original values. This way if any key is not found it will be set to undefined
const
array1 = [
{
"value": "0",
"name": "5",
"waste": "remove",
"city": "NY"
},
{
"value": "0",
"name": "51",
"waste": "remove",
}
]
var keys_to_keep = ['name', 'city']
let obj = Object.fromEntries(keys_to_keep.map(x => [x, undefined]));
const res = array1.map(obj =>
Object.fromEntries(
Object.entries(obj).filter(([k, v]) => keys_to_keep.includes(k))))
.map(x => ({...obj, ...x}))
console.log(res)
You can use .map to iterate over the objects, Object.entries to get the key-value pairs of each item, Object.fromEntries to group them into the resulting objects, and .filter to get only the entries with a key in keys_to_keep and a value that is not undefined:
const array1 = [
{ "value": "0", "name": "5", "waste": "remove", "city": "NY" },
{ "value": "0", "name": "51", "waste": "remove" }
];
var keys_to_keep = ['name', 'city'];
const result = array1.map(item =>
Object.fromEntries(
Object.entries(item).filter(([key, value]) =>
keys_to_keep.includes(key) && value !== undefined
)
)
);
console.log(result)
Related
I have an array like this:
var values = Array ( );
values [0] = Array ("", "Guest1", "Guest2", "Guest3")
values [1] = Array ("Name", "Hans", "Carl", "Peter")
values [2] = Array ("City", "Berlin", "Tokio", "Washington")
values [3] = Array ("Phone", "123", "234", "345")
I would like to create an object like this:
var data= {
Guest1: { "Name" : "Hans", "City" : "Berlin", "Phone" : "123" },
Guest2: { "Name" : "Carl", "City" : "Tokio", "Phone" : "234" },
Guest3: { "Name" : "Peter", "City" : "Washington", "Phone" : "345" },
};
I got the first key using:
const data = Object.fromEntries(values[0].map(key => [key, 0]));
delete data[""];
However, I am struggling to create the rest of the object.
I would highly recommend finding a way to query your data in a more meaningful shape, but it can be wrangled.
const values = [
["", "Guest1", "Guest2", "Guest3"],
["Name", "Hans", "Carl", "Peter"],
["City", "Berlin", "Tokio", "Washington"],
["Phone", "123", "234", "345"],
]
const [header, ...rows] = values;
const data = {};
for (const [key, ...row] of rows) {
for (const [i, value] of row.entries()) {
(data[header[i + 1]] ??= {})[key] = value;
}
}
console.log(data);
Reference:
for...of
destructuring assignment and ...rest property
nullish coalescing assignment (??=)
I am fetching a data from Laravel API this way
$inventory = Gifts::with('allocation')->get();
$response = [
'data' => $inventory->toArray(),
]
The output for the above looks like the image below in the console
This is what is inside the 0: {…}
{
"id": 1,
"name": "Bar 1",
"allocation": [
{
"id": 1,
"location_id": "1",
"qty": "2",
},
{
"id": 2,
"location_id": "4",
"qty": "32",
},
{
"id": 3,
"location_id": "7",
"qty": "12",
}
]
}
I'm trying to get an output like this
{
"isEditable": false,
"id": 1,
"name": "Bar 1",
"location1": "2"
"location4": "32"
"location7": "12"
}
It's an array that consists of 100+ entries like this and the allocation can be more or less or maybe empty as well
What I have done so far
const array = result.data(gift => ({ isEditable: false, ...gift }));
This adds "isEditable" field to the array.
You could use Array.prototype.map() to map the result array into a new one that only includes id, name, and the locationNN properties.
In the Array.prototype.map()'s callback:
Use the spread operator to separate the allocation property from the other properties of each array item (call it otherProps e.g.):
Spread the otherProps into a new object, inserting the isEditable property.
Map the allocation items into a key-value pair array, where the key is location_id appended to "location"; and the value is the qty property.
Use Object.fromEntries() on the key-value pair array to create an object, and spread that object into the outer object to be returned.
const output = result.map(r => {
const { allocation, ...otherProps } = r 1️⃣
return {
...otherProps, 2️⃣
isEditable: false,
...Object.fromEntries( 4️⃣
allocation.map(a => [`location${a.location_id}`, a.qty]) 3️⃣
)
}
})
demo
This solution uses reduce
const { allocation, ...rest } = gift
const processed = allocation.reduce((acc, loc, idx) => {
acc[`location${loc.location_id}`] = loc.qty
return acc
}, {})
const result = { ...rest, ...processed }
console.log(result)
I have below array. First object is the original data. Inside array is the changed value. I am trying to create a final data by matching with the Name field with inside array. which should look like
var a =
[
{"Id":"1","Test":"Name1","Name":"hunt9988ggggggggggggdfsf1111"},
{"Id":"2","Test":"Name2","Name":"hunt9988ggggggggggggdfsf"},
[
**{"Name":"hunt9988ggggggggggggdfsf1118","Id":"1"}, // Changed value
{"Name":"hunt9988ggggggggggggdfsf1118","Id":"2"}**
]
]
Final Data
var a =
[
{"Id":"1","Test":"Name1","Name":"hunt9988ggggggggggggdfsf1118"},
{"Id":"2","Test":"Name2","Name":"hunt9988ggggggggggggdfsf1118"}
]
I am trying with below code
var result = a.map(item => ({ value: item.Id, text: item.Name}));
console.log(result)
Like this?
Note I modify the original array
let a = [{
"Id": "1",
"Test": "Name1",
"Name": "hunt9988ggggggggggggdfsf1111"
},
{
"Id": "2",
"Test": "Name2",
"Name": "hunt9988ggggggggggggdfsf"
},
[{
"Name": "hunt9988ggggggggggggdfsf1118",
"Id": "1"
}, // Changed value
{
"Name": "hunt9988ggggggggggggdfsf1118",
"Id": "2"
}
]
]
const replaceArray = a.find(item => Array.isArray(item))
replaceArray.forEach(item => a.find(aItem => aItem.Id === item.Id).Name=item.Name)
a = a.filter(item => item.Id)
console.log(a)
I have one javascript array and one object . Need help to sort javascript object keys based on the order number in another array
In subgroup array , I have name , order number. Need to sort Offerings keys based on that order number
const subgroup = [
{
"code": "6748",
"name": "test123",
"orderNumber": "0"
},
{
"code": "1234",
"name": "customdata",
"orderNumber": "1"
}
]
const offerings = {
"customdata" : [
{
"code": "Audi",
"color": "black"
}
],
"test123" : [
{
"brand": "Audi",
"color": "black"
}
]
}
I believe this should work for you. I've added some comments in the code that should hopefully do an okay job of explaining what is happening.
var subgroup = [{
"code": "6748",
"name": "test123",
"orderNumber": "0"
}, {
"code": "1234",
"name": "customdata",
"orderNumber": "1"
}];
var offerings = {
"customdata": [{
"code": "Audi",
"color": "black"
}],
"test123": [{
"brand": "Audi",
"color": "black"
}]
}
function sortObjectFromArray(refArray, sortObject, orderKey = 'order', linkKey = 'key') {
// Get copy of refArray
let reference = refArray.slice();
// Sort sortObject [ into an array at this point ]
let sorted = [];
for (let key in sortObject) {
// Searches the refArray for the linkKey, and returns the intended index
let index = reference.find((item) => item[linkKey] === key)[orderKey];
// Places the sortObject's value in the correct index of the 'sorted' Array
sorted[parseInt(index)] = [key, sortObject[key]];
};
// Return an object, created from previous 'sorted' Array
return sorted.reduce((obj, [key, value]) => {
obj[key] = value;
return obj;
}, {});
};
offerings = sortObjectFromArray(subgroup, offerings, 'orderNumber', 'name');
console.log(offerings);
I am having an object of the following kind:
var sourceObj = {
"feature1": [
{"id":"1","name":"abc","enabled":false,"type":"type1"},
{"id":"2","name":"xyz","enabled":false,"type":"type1"}
]
,
"feature2": [
{"id":"3","name":"lmn","enabled":true,"type":"type2"},
{"id":"4","name":"pqr","enabled":false,"type":"type2"}
]
}
Need to get converted to an array of objects of the following type:
var destArr = [
{ "feature_name":"feature1",
"feature_details":[
{"id":"1","name":"abc","enabled":false,"type":"type1"},
{"id":"2","name":"xyz","enabled":true,"type":"type1"}
]
},
{ "feature_name":"feature2",
"feature_details":[
{"id":"3","name":"lmn","enabled":true,"type":"type2"}
{"id":"4","name":"pqr","enabled":false,"type":"type2"}
]
}
]
I have tried the following approaches for conversion of source object to resultant array of objects and resultant array of objects back to the source object
//Converting source object to array of objects
let arr = Object.keys(sourceObj).map(key => {
return sourceObj[key];
})
converting array of objects back to source objetc
let obj = Object.assign({}, ...destArr.map(item => ({ [item.name]: item.value })));
You could use Object.entries to map everything in a single shot.
To go back to the original structure, you could use reduce against the generated array (see backToOriginalArray below)
var sourceObj = {
"feature1": [{
"id": "1",
"name": "abc",
"enabled": false,
"type": "type1"
},
{
"id": "2",
"name": "xyz",
"enabled": false,
"type": "type1"
}
],
"feature2": [{
"id": "3",
"name": "lmn",
"enabled": true,
"type": "type2"
},
{
"id": "4",
"name": "pqr",
"enabled": false,
"type": "type2"
}
]
};
// Step 1: use object.entries against the original object to build an array of objects.
var destArray = Object.entries(sourceObj).map(([key, value]) => ({
"feature_name": key,
"feature_details": value
}));
console.log(destArray);
// Step 2: use reduce against the generated array to get an object with the same structure of the original one.
var backToOriginalArray = destArray.reduce((acc, {feature_name, feature_details}) => (acc[feature_name] = feature_details, acc), {});
console.log(backToOriginalArray);
Map the Object.entries of your initial object:
var sourceObj = {
"feature1": [
{"id":"1","name":"abc","enabled":false,"type":"type1"},
{"id":"2","name":"xyz","enabled":false,"type":"type1"}
],
"feature2": [
{"id":"3","name":"lmn","enabled":true,"type":"type2"},
{"id":"4","name":"pqr","enabled":false,"type":"type2"}
]
};
const destArr = Object.entries(sourceObj).map(
([feature_name, feature_details]) => ({ feature_name, feature_details })
);
console.log(destArr);
To go the other way around, use Object.fromEntries:
const arr=[{feature_name:"feature1",feature_details:[{id:"1",name:"abc",enabled:!1,type:"type1"},{id:"2",name:"xyz",enabled:!1,type:"type1"}]},{feature_name:"feature2",feature_details:[{id:"3",name:"lmn",enabled:!0,type:"type2"},{id:"4",name:"pqr",enabled:!1,type:"type2"}]}];
const obj = Object.fromEntries(arr.map(
({ feature_name, feature_details }) => [feature_name, feature_details]
));
console.log(obj);