Develop Reference

SubString in JavaScript [duplicate]

This question already has answers here:
How to get the nth occurrence in a string?
(14 answers)
Closed 2 years ago.
For example, I have a string like following
var string = "test1;test2;test3;test4;test5";
I want the following substring from the above string, I don't know the startIndex, the only thing I can tell substring should start after the second semicolon to till the end.
var substring = "test3;test4;test5";
Now I want to have substring like following
var substring2 = "test4;test5"
How to achieve this in JavaScript

You mean this?
const string = "test1;test2;test3;test4;test5";
const arr = string.split(";")
console.log(arr.slice(2).join(";")); // from item #2
console.log(arr.slice(-2).join(";")) // last 2 items
If the string is very long, you may want to use one of these versions
How to get the nth occurrence in a string?
As a function
const string = "test1;test2;test3;test4;test5";
const restOfString = (string,pos) => {
const arr = string.split(";")
return arr.slice(pos).join(";"); // from item #pos
};
console.log(restOfString(string,2))
console.log(restOfString(string,3))

Try to use a combination of string split and join to achieve this.
var s = "test1;test2;test3;test4;test5";
var a = s.split(";")
console.log(a.slice(3).join(";"))

How to convert object array to comma separated string? [duplicate]

This question already has answers here:
Transform Javascript Array into delimited String
(7 answers)
Closed 4 years ago.
Im trying to convert at object array with jQuery or javascript to a comma separated string, and no matter what I try I can´t get it right.
I have this from a select value.
ort = $('#ort').val();
ort=JSON.stringify(ort)
ort=["Varberg","Halmstad","Falkenberg"]
How can I convert it to a string looking like this?
ort=Varberg,Halmstad,Falkenberg
Any input appreciated, thanks.

You can use join
let arr = ["Varberg","Halmstad","Falkenberg"]
console.log(arr.join(','))

Use Array.prototype.join to to convert it into a comma separated string.
let str = ort=["Varberg","Halmstad","Falkenberg"].join(","); //"," not needed in join
console.log(str);
A simple toString also works in this case.
let str = ort=["Varberg","Halmstad","Falkenberg"].toString();
console.log(str);

Another way to achieve this is by using Array.prototype.reduce:
console.log(["Varberg", "Halmstad", "Falkenberg"].reduce((s, el, idx, arr) => {
s += el
if (idx < arr.length - 1) {
s += ','
}
return s;
}, ''));

Split URL string to get each parameter value in javascript [duplicate]

This question already has answers here:
How to convert URL parameters to a JavaScript object? [duplicate]
(34 answers)
Closed 8 years ago.
var url = "journey?reference=123line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC"
How can I split the string above so that I get each parameter's value??

You could use the split function to extract the parameter pairs. First trim the stuff before and including the ?, then split the & and after that loop though that and split the =.
var url = "journey?reference=123line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC";
var queryparams = url.split('?')[1];
var params = queryparams.split('&');
var pair = null,
data = [];
params.forEach(function(d) {
pair = d.split('=');
data.push({key: pair[0], value: pair[1]});
});
See jsfiddle

Try this:
var myurl = "journey?reference=123&line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC";
var keyval = myurl.split('?')[1].split('&');
for(var x=0,y=keyval.length; x<y; x+=1)
console.log(keyval[x], keyval[x].split('=')[0], keyval[x].split('=')[1]);

to split line in JS u should use:
var location = location.href.split('&');

Return only a part of the match [duplicate]

This question already has an answer here:
Get part of the string using regexp [closed]
(1 answer)
Closed 9 years ago.
Here's an example http://jsbin.com/USONirAn/1
var string = "some text username#Jake# some text username#John# some text some text username#Johny# userphoto#1.jpg#";
var type = "username";
var regexp = new RegExp(type + "#(.*?)#");
var matches = string.match(regexp);
Current regexp returns into matches an array with 3 items - [username#Jake#, username#John#, username#Johny#].
How do I make it return only a strings that I used to search for - (.*?)? In this example is should be an array [Jake, John, Johny]. Is it possible to get this only by changing a regexp function?
Update:
I've also tried to use exec function, but it returns both [username#Jake#, Jake] http://jsbin.com/USONirAn/6

Search-and-don't-replace
var matches = []
string.replace(regexp, function () {
matches.push(arguments[1]);
});
http://jsbin.com/USONirAn/4

Return hello world to olleh dlrow in javascript [duplicate]

This question already has answers here:
JavaScript reverse the order of letters for each word in a string
(5 answers)
How do you reverse a string in-place in JavaScript?
(57 answers)
Closed 9 years ago.
Was wondering if you can reverse a string and still maintain the order.
Below is a function that returns "dlroW olleH" and I want to return "olleH dlroW"
var myFunction = function() {
var userdata = document.getElementById('data').value,
uRev = userdata.split("").reverse().join("");
document.getElementById('results').innerHTML = uRev;
};
Thanks!

Reverse the words and then the characters:
var myFunction = function() {
var userdata = document.getElementById('data').value,
uRev = userdata.split(" ").reverse().join(" ").split("").reverse().join("");
document.getElementById('results').innerHTML = uRev;
};
Example JSFiddle

function reverseString(s){
return s.split("").reverse().join("");
}
function reverseEachWord(s) {
return s.split(" ").map(reverseString).join(" ");

alert(userdata.split(" ").reverse().join(" ").split("").reverse().join(""));

first split your string in an array of words using split(" "), then split each array segment using the method above.

Try this,
var myFunction = function() {
var resArr=[];
var userdata = document.getElementById('data').value,
uRev = userdata.split("");
for (var i=0;i<uRev.length;i++){
resArr.push(uRev[i].reverse());
}
document.getElementById('results').innerHTML = resArr.join('');
};

var test = 'Hello World';
alert(
test.replace(
/\w+/g ,
function(a){return a.split('').reverse().join('');}
)
);