I'm trying to send a file from a web page to a php script using FormData, and the file isn't showing up in the $_FILES variable in the PHP page. Not sure if my error is on the JS side or the PHP side, or if I'm misunderstanding something deeper about the process.
Here's my code:
function uploadFile() {
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState === XMLHttpRequest.DONE) {
if (xhr.status === 200) {
console.log('success');
} else {
console.log('error');
}
}
};
xhr.open('POST','php/parsefile.php',true);
xhr.setRequestHeader("Content-Type","multipart/form-data");
var formData = new FormData();
formData.append("myfile", document.querySelector('#fileInput').files[0]);
xhr.send(formData);
}
<input type="file" id="fileInput">
<button onclick="uploadFile();">Upload</button>
Here's parsefile.php:
<?php
echo("Error: " . $_FILES["myfile"]['error'] . "\n");
echo("Name: " . $_FILES['file']['name'] . "\n");
When I upload a simple, small (64 bytes) text file, the console reads success, but the response from the server is just this:
Error:
Name:
What am I missing here? Thanks for any help anyone can provide.
I found two issues in your code:
In JavaScript code, you explicitly defined the "Content-Type" as "multipart/form-data". JS automatically gets the content type when you make the XHR Request.
In the 4th line of your PHP code, the key of the $_FILE is "file". You need to change it to "myfile", in order to make it work.
You can check my edited code below:
JS Code:
function uploadFile() {
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState === XMLHttpRequest.DONE) {
if (xhr.status === 200) {
console.log('success');
} else {
console.log('error');
}
}
};
xhr.open('POST','php/parsefile.php',true);
var formData = new FormData();
formData.append("myfile", document.querySelector('#fileInput').files[0]);
xhr.send(formData);
}
PHP Code:
<?php
echo "Name: ". $_FILES['myfile']['name'];
echo "Error: ".$_FILES['myfile']['error'];
Related
I have a browserside javascript file that's supposed to be asking the serverside php file for a string with an ajax request. The php file seems to have the correct string, but for some reason the ajax request is returning the string 'false'.
This is the php file, named test.php:
<?php
$dir = "site/uploads";
$a = scandir($dir);
$b = json_encode($a);
echo $b;
?>
This is the js file:
function load(){
var xmlhttp = new XMLHttpRequest();
xmlhttp.responseType = "text";
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
console.log('test' + xmlhttp.responseText);
console.log('test' + JSON.parse(xmlhttp.responseText));
}
};
xmlhttp.open("GET", "test.php", 'false');
xmlhttp.send();
var xmlhttp2 = new XMLHttpRequest();
xmlhttp2.responseType = "text";
xmlhttp2.onreadystatechange = function() {
if (xmlhttp2.readyState == 4 && xmlhttp2.status == 200) {
console.log('test2' + xmlhttp2.responseText);
console.log('test2' + JSON.parse(xmlhttp2.responseText));
}
};
xmlhttp2.open("GET", "test2.php", 'false');
xmlhttp2.send();
}
when i open the website in my browser and run load(), the console reads:
testfalse
testfalse
test2false
test2false
and has no errors. What am I doing wrong here? Thanks!
scandir() in the php-file is probably returning false, because of an error.
https://www.php.net/manual/de/function.scandir.php (Check the return values)
There are multiple possiblities for this to happen:
The folder doesn't exist
The path is incorrect (Try using absolute paths)
The folder isn't accessible, because of missing permissions
In my JS code, I take in 3 inputs on a html page and save them to local storage. I then want to send these variables to php in order to save them to my database. No matter how hard I try no tutorial using ajax, jquery etc allows me to successfully post and echo variables from javascript in my php code. I see no reason why my code below doesn't echo the variables, but it doesn't.
Full code: https://codeshare.io/ayvK9e
Exact PHP elements (just trying to send normal variables right now as it still won't work"
PHP:
foreach($_POST as $post_var){
echo($post_var);
}
JS:
const xhr = new XMLHttpRequest();
xhr.onload = function(){
const serverResponse = document.getElementById("serverResponse");
serverResponse.innerHTML = this.responseText
};
xhr.open("POST", "eDBase.php");
xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhr.send("name=dominic&message=bumbaclaat");
If $post not work try using input php
$data = json_decode(file_get_contents('php://input'), true);
When calling my function with the inputs onclick=showFunction; I was passing nothing to the function. In order for my values to be echoed in php I had to pass a parameter to the function onclick=function('text or variable'); IDK how I missed that.
Try using the FormData()
let form = new FormData();
form.append('name', 'dominic');
form.append('message', 'bumbaclaat');
const xhr = new XMLHttpRequest();
xhr.open("POST", "eDBase.php");
xhr.onreadystatechange = function(){
if(xhr.readyState === XMLHttpRequest.DONE && xhr.status === 200) {
const serverResponse = document.getElementById("serverResponse");
serverResponse.innerHTML = this.responseText;
}
else console.log('error')
};
xhr.send(form);
Comment out the setRequestHeader to test it.
And at PHP
if(isset($_POST['name'])){
echo $_POST['name'];
echo $_POST['message'];
}
else{
echo 'There was a problem';
}
I am calling a php file that queries my database and returns a result. I have verified that the php file accurately returns the data as needed, but my calling page is not updated from the JavaScript.
What do I need to alter in my syntax below so that the returned value is returned on page?
<script type="text/javascript">
function boostion()
{
var xhr;
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
} else if (window.ActiveXObject) {
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
xhr.open("GET", "QueryDB.php", true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xhr.onreadystatechange = display_data;
function display_data() {
if (xhr.readyState == 4) {
if (xhr.status == 200) {
document.getElementById("data").innerHTML = xhr.responseText;
} else {
alert('There was a problem with the request.');
}
}
}
}
</script>
EDIT
I have also opened Developer Options in Chrome and checked the Console and there are no errors or issues displayed, everything is a success!
Edit 2
I tried to use the JQuery approach below and used this syntax - but I get the error
Uncaught TypeError: $(...).load is not a function
Syntax:
<script src="https://code.jquery.com/jquery-3.1.1.slim.js"
integrity="sha256-5i/mQ300M779N2OVDrl16lbohwXNUdzL/R2aVUXyXWA="
crossorigin="anonymous" type="text/javascript"></script>
<script type="text/javascript">
$(window).load(function(){
$.get("QueryDB.php", function(data, status){
document.getElementById("data").innerHTML = data;
});
});
</script>
Edit 3
This is my php syntax that runs the sql syntax and echo result that I want to have returned from the javascript
<?php
$option = array();
$option['driver'] = 'mssql';
$option['host'] = 'host';
$option['user'] = 'user';
$option['password'] = 'password';
$option['database'] = 'database';
$option['prefix'] = '';
$db = JDatabase::getInstance( $option );
$result = $db->getQuery(true);
$result->select($db->quoteName(array('trackandfieldresults')));
$result->from($db->quoteName('[TrackData]'));
$db->setQuery($result);
$row = $db->loadRowList();
echo $row['0']
?>
Use xhr.send();
If it is a GET request, you have to apply the query string in in xhr.open and you dont have to set Content-type:application/x-www-form-urlencoded
first, the scripts should be inside the HTML before the ending body tag. then you open another file and write your code in it. JQUERY does not have script tag. Sp you are creating an external javascript file for the script. No script tag needed. Now use this format.
$(window).on('load', function(e){
e.preventDefault();
var dat = //the content you are trying to load
$.get('middleware.php', dat, function(data){
$('#selector').html(data)
});
})
I have a faster approach using JQuery.
$(window).load(function(){
$.get("QueryDB.php", function(data, status){
//Do whatever you want here
});
});
This should do the Job. Your approach is old and kind of complicated to debug
Try this
function boostion(){
var xhr;
if (window.XMLHttpRequest) {
xhr = new XMLHttpRequest();
}
else if (window.ActiveXObject) {
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
xhr.open("GET", "QueryDB.php", true);
xhr.send();
xhr.onreadystatechange = function(){
console.log(xhr);
if (xhr.readyState == 4 && xhr.status==200) {
document.getElementById("data").innerHTML = xhr.responseText;
}
}
}
<div id="data"></div>
<button onclick="boostion();">Load</button>
I want to make image upload from url for example: http://.. ../logo.png
I need to make formData object from image url but it doesn't work:
HTML:
<form id="form-url">
<input type="text" class="image" id="textarea" placeholder="URL" />
<button>UPLOAD</button>
</form>
Javascript:
$("#form-url").submit(function(e) {
if ($(".image").val() != "URL" && $(".image").val() != "") {
//I also tried this:
var data;
var img = new Image();
img.src = $(".image").val();
img.load = function(){
data = getBase64Image($(".image").val());
};
//but it send undefined
//and this:
var data = URL.createObjectURL($(".image").val()); //dont work
//error: TypeError: Argument 1 is not valid for any of the 1-argument overloads of URL.createObjectURL.
//Upload process working on normal input type file uploading but no on URL image
var formData = new FormData(data);
formData.append("fileToUpload", data);
var xhr = new XMLHttpRequest();
xhr.open('POST', "upload_ajax.php", true);
xhr.onload = function () {
if (xhr.status === 200) {
data = xhr.responseText;
datas = data.split("_");
if (datas[0] != "true") {
alert(data);
} else {
alert('YES');
}
} else {
alerter('An error occurred while uploading this file! Try it again.');
}
};
xhr.send(formData);
} else { alerter("Your file must be an image!"); }
return false;
});
My php script for debug:
<?php
if (isset($_POST)) {
var_dump($_POST);
if (empty($_FILES['fileToUpload']['tmp_name'])) {
echo "Your file must be an image!";
} else {
echo $_FILES['fileToUpload']['name'];
echo $_FILES['fileToUpload']['size'];
}
}
?>
Thanks for all help and your time..
and sorry for my bad english (student)
If getBase64Image is from here, or is similar to it.
Then you are using it wrong. You need to pass it the image node itself. Also the image onload event is async, and as such you have to wait for it to be done to get the data and send it.
var xhr = new XMLHttpRequest();
var formData = new FormData();
xhr.open('POST', "upload_ajax.php", true);
...
var img = new Image();
img.onload = function(){
var data = getBase64Image(this);
formData.append("fileToUpload", data);
xhr.send(formData);
};
Also note on the server side you will need to decode it from the base64 encoding, as it is being sent by string, it is going to be in $_POST not $_FILE
var rawContents = base64_decode($_POST['fileToUpload']);
Note you could also just send the url to the php script and just have php get the image data
var rawContents = file_get_contents($_POST['imageurl']);
I need to use the xhr.send(VALUE) to send the data in AJAX. How do I get this data in a PHP file?
JS:
window.onload = function() {
var value = 'hello';
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
alert(xhr.responseText);
} else {
alert("no");
}
}
xhr.open('POST', 'json.php', true);
xhr.send(value);
}
You are just sending a string to the PHP file. You are not sending it as a query string or with a content type, so PHP doesn't populate the $POST array.
You can try to read the raw post data:
$post = file_get_contents('php://input');
echo $post; // hello
Or, if you want PHP to populate $_POST, you need to do some extra steps in your JavaScript.
window.onload = function() {
var value = 'hello';
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if(xhr.readyState == 4 && xhr.status == 200) {
alert(xhr.responseText);
} else {
alert("no");
}
}
xhr.open('POST', 'json.php', true);
// Tell the server you are sending form data
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
// Send it as a query string
xhr.send('value='+value);
}
Then in your PHP, you can access $_POST['value'].
echo $_POST['value']; // hello
If you want to see the $_POST variables on the PHP page you can use this code to display them all so you can visually see their keys and values
echo "<pre>";
print_r($_POST);
echo "</pre>";
From there you will know how to use the data in any file. You can do the same thing with $_GET
Try this, replace your xhr.send with
JS
xhr.send('value='+value);
PHP
echo($_POST['value']);