Develop Reference

How to find similarities between a text string and an array?

I have a string array, which I want to compare with a text string, if it finds similarities I want to be able to mark in black the similarity found within the string
example:
context.body: 'G-22-6-04136 - PatientName1'
newBody: ['G-22-6-04136 - PatientName1' , 'G-22-6-04137 - PatientName2']
When finding the similarity between the two the result would be something like this
newBody: [**'G-22-6-04136 - PatientName1'** , 'G-22-6-04137 - PatientName2']
How could I do it? Is this possible to do? In advance thank you very much for the help
const totalSize: number = this.getSizeFromAttachments(attachments);
const chunkSplit = Math.floor(isNaN(totalSize) ? 1 : totalSize / this.LIMIT_ATTACHMENTS) + 1;
const attachmentsChunk: any[][] = _.chunk(attachments, chunkSplit);
if ((totalSize > this.LIMIT_ATTACHMENTS) && attachmentsChunk?.length >= 1) {
const result = attachment.map(element => this.getCantidad.find(y => element.content === y.content))
const aux = this.namePatient
const ans = []
result.forEach(ele => {
const expected_key = ele["correlative_soli"];
if (aux[expected_key]) {
const newItem = { ...ele };
newItem["name_Patient"] = aux[expected_key]
newItem["fileName"] = `${expected_key}${aux[expected_key] ? ' - ' + aux[expected_key] : null}\n`.replace(/\n/g, '<br />')
ans.push(newItem)
}
});
let newBody: any;
const resultFilter = attachment.map(element => element.content);
const newArr = [];
ans.filter(element => {
if (resultFilter.includes(element.content)) {
newArr.push({
fileNameC: element.fileName
})
}
})
newBody = `• ${newArr.map(element => element.fileNameC)}`;
const date = this.cleanDateSolic;
const amoung= attachmentsChunk?.length;
const getCurrent = `(${index}/${attachmentsChunk?.length})`
const header = `${this.cleanDateSolic} pront ${attachmentsChunk?.length} mail. This is the (${index}/${attachmentsChunk?.length})`;
console.log('body', context.body);
// context.body is the body I receive of frontend like a string
const newContext = {
newDate: date,
amoung: amoung,
getCurrent: getCurrent,
newBody: newBody,
...context
}
return this.prepareEmail({
to: to,
subject: ` ${subject} (Correo ${index}/${attachmentsChunk?.length})`,
template: template,
context: newContext,
}, attachment);
}

I have a string array, which I want to compare with a text string, if it finds similarities I want to be able to mark in black the similarity found within the string
First of all the text will be in black by default, I think you are talking about to make that bold if matched. But again it depends - If you want to render that in HTML then instead of ** you can use <strong>.
Live Demo :
const textString = 'G-22-6-04136 - PatientName1';
let arr = ['G-22-6-04136 - PatientName1', 'G-22-6-04137 - PatientName2'];
const res = arr.map(str => str === textString ? `<strong>${str}<strong>` : str);
document.getElementById('result').innerHTML = res[0];
<div id="result">
</div>

Based on your example, it looks like the string needs to be an exact match, is that correct?
Also, "mark it in bold" is going to depend on what you're using to render this, but if you just want to wrap the string in ** or <b> or whatever, you could do something like this:
newBody.map(str => str === context.body ? `**${str}**` : str);

You can just see if string exists in the array by doing
if arr.includes(desiredStr) //make text bold

MySQL conditional filters handling

I am using node.js and trying to query based on multiple filters if only they are true
select * from orders ${isFilter ? 'where' : ''}
${orderId !== undefined && orderId ? `order_id = '${orderId}' or ` : '' }
${receiptId !== undefined && receiptId? `receipt_id = '${receiptId}' or `: '' }
${driver !== undefined && driver ? `driver_id = '${Number(driver)}'` : '' }
this works fine where there is no filter or when all the filters are true but the OR causes an issue when one filter or more are missing. what would be the best way to handle this ?

This is a pseudo code to dynamically compose the query
var clause = 'where';
var query = 'select * from orders';
if (isFilter) { // this statement could be removed
if (orderId !== undefined && orderId) {
query += clause + ' order_id = `${orderId}`';
clause = 'or';
}
if (receiptId !== undefined && receiptId) {
query += clause + ' receiptId = `${receiptId}`';
clause = 'or';
}
if (driver !== undefined && driver) {
query += clause + ' driver = `${driver}`';
clause = 'or'; // this is not really needed, but it could be useful for further filters in future
}
}

let whereClause = [];
if(orderId) whereClause.push(`order_id = '${orderId}'`);
if(receiptId) whereClause.push(`receipt_id = '${receiptId}'`);
if(driver) whereClause.push(`driver_id = ${parseInt(driver)}`);
let whereQuery = whereClause.join(' OR ');
let sql = `select * from orders where true ${whereClause.length ? whereQuery : ''}`;
try using join. so that you can add many properties even not in order. Also if you're expecting it to be undefined, then you may remove that as it resulted false on condition statement.

I think it would be reasonable if you can log the query. we can be sure about the query that's being sent.
This would be the first step to troubleshoot and may be we can use the way you are trying using ternary operator with few changes.

The code you used above to build the query string is not possible to cover all possible cases.
Example:
What if isFilter==false and one of the 3 variables orderId, receiptId and driver has the value !== undefined? => your query will be wrong because the WHERE statement is missing.
Another case, if one of the variables orderId or receiptId satisfied the condition and the variable driver is not valid. => Your query will be wrong because of the extra of 'OR' at the end.
Those are the 2 cases that are most likely to cause problems for the above code. Here is my suggestion to solve your problem:
queryString="select * from orders"
if(isFilter){
queryString+=' where'
if(orderId){
queryString+=' ..... or'
}
if(receiptId){
queryString+=' ..... or'
}
if(driver){
queryString+=' .....'
}
}
queryString=queryString.trim()
if(queryString.endsWith('or')){
queryString=queryString.substring(0,queryString.length-2)
}
if(queryString.endsWith('where')){
queryString=queryString.substring(0,queryString.length-5)
}

select * from orders ${isFilter ? 'where 1=0' : ''}
${orderId !== undefined && orderId ? `OR order_id = '${orderId}' ` : '' }
${receiptId !== undefined && receiptId? `OR receipt_id = '${receiptId}' `: '' }
${driver !== undefined && driver ? `OR driver_id = '${Number(driver)}'` : '' }
Instead if its AND you can do 1=1 instead of 1=0.

How to render conditional jsx using ternary operator in react?

i want to use ternary operator for conditional rendering of jsx using react and javascript.
below is my code,
const Parent = () => {
return (
<Child
isChecked={true}
isMany={true}
/>
);
};
const Child = (props) => {
const name=defaultTo(props.optionName, 'name');
return (
{props.isMany
? `${props.getValue().length} ${name}${
props.getValue().length > 1 ? 's' : ''
} selected`
: props.getValue()[0].label
}
);
}
the above code works and it returns output like "2 names selected" or "1 name selected" based on getValue length. here Child component is reusable and isChecked prop is optional. it may or maynot be passed as prop to this Child component.
Now if the isChecked prop is true, i want to display output like "2 selected" or "1 selected" which depends on getValue length.
how can i modify the above code to do so.
could someone help me with this. thanks.
EDIT:
below is what i have tried.
const Child = (props) => {
const name= props.isChecked ?
defaultTo(props.optionName, '')
: defaultTo(props.optionName, 'name');
return (
{props.isMany
? `${props.getValue().length} ${name}${
(props.getValue().length > 1 && !isChecked) ? 's' : ''
} selected`
: props.getValue()[0].label
}
);
}
this kind of works but still displays that 's' if more than one count so the output is like below
1 selected
2 s selected
3 s selected
....

I'd do much of the work before the return, something along these lines:
const Child = (props) => {
const {isChecked, isMany, optionName} = props;
const value = props.getValue();
const {length} = value;
const nameDisplay = isMany && `${defaultTo(optionName, "name")}${length === 1 ? "" : "s"}`;
return (
isMany
? isChecked
? `${length} selected`
: `${length} ${nameDisplay}`
: value[0].label;
);
};
I should note that just adding an s works for name, but doesn't work for many other nouns in English (bus for instance, or mouse). Making plurals in English is, sadly, fairly complicated in practice. Rather than accepting just optionName, you might consider accepting something that includes both the singular and the plural.
Side note: ? : is a ternary operator (an operator accepting three operands, like a binary operator accepts two operands and a unary operator accepts one), and it's JavaScript's only ternary operator at the moment, but that could change. Its proper name is the conditional operator.

You can make another ternary operator.
const Child = (props) => {
const name=defaultTo(props.optionName, 'name');
return (
{props.isChecked ?
props.getValue().length + " selected" :
(props.isMany
? `${props.getValue().length} ${name}${
props.getValue().length > 1 ? 's' : ''
} selected`
: props.getValue()[0].label)
}
);
}

Javascript Return Conditionals

searchList(array, filters) {
var currentUserId = 125;
var list = array;
// array example [{aisle: A9, userid: 125},{aisle: B2, userid: null},{aisle: C#, userid: 125}]
// filters example {assignedButtonActive: true, unassignedButtonActive: false, aisle: A9}
result = Object.keys(list)
.map((key) => {
return { ...list[key] };
})
.filter((data) => {
// If assigned or unassigned buttons are not active, this filter doesnt apply and aisle should be the only thing filtering
let assigned = filters.assignedButtonActive
let unassigned = filters.unassignedButtonActive
let aisleSelection = filter.aisle;
let aisle = data.aisle;
let userid = data.userid;
return aisle.indexOf(aisleSelection) > -1 // Need a conditional to also filter out assigned/unassigned if the buttons are active, otherwise not needed.
});
return result;
}
I am trying to filter a list with the combination of an input search and button/flags. I have no problem with the input search function filtering and returning the list. The problem Im having is using boolean flags along with the search input to be even more exact on what i want to filter, but I am having an issue on how to return the result using conditionals/booleans in this case. I cant seem to mix the two conditions for a return with both filters applied. I've tried something like this return aisle.indexOf(aisleSelection) > -1 && (assigned) ? assignedTo == currentUserId : (unassigned) ? assignedTo == null : [] but seems I'm way off. For example if either assigned/unassigned flags are active, it will add one of these two filters assignedTo === currentUserId or assignedTo == null to filter along with aisle filter as well, pretty much so they can work together as well, not one or the other
Not looking for the solution written out for me, more on how I can handle this filtering beyond just an input, with the possibility to off more filters being used
Any help/tips would be greatly appreciated

Finish out the function before returning, then have different return statements for each condition
rather than
return aisle.indexOf(aisleSelection) > -1
try
if (aisle.indexOf(aisleSelection) > -1) {
return true}
else if (other possibility){
return true}
else (case to filter out){
return false}
filter gets called on each element in the array, and decides to keep the element if the callback function returns true

Based on what I have understood, follow through this code especially the part I have commented then let me know if this what you wanted. If there's you don't get, let me know.
function searchList(array, filters) {
var currentUserId = 125;
var list = array;
result = Object.keys(list)
.map((key) => ({ ...list[key] }))
.filter((data) => {
let assignedSelection = filters.assignedButtonActive;
let unassignedSelection = filters.unassignedButtonActive;
let aisleSelection = filters.aisle;
let aisle = data.aisle;
let userid = data.userid;
return Boolean(Boolean(assignedSelection) || Boolean(unassignedSelection)) && aisle.includes(aisleSelection)?assignedTo = currentUserId:assignedTo = null;
/**
Explanation:
I am not sure of what you wanted to achieve with this, but follow through and see If this is what you wanted.
1. Boolean(Boolean(assignedSelection) || Boolean(unassignedSelection))
This part will return true if either assignedSelection or unassignedSelection is true.
This part will return false if both assignedSelection and unassignedSelection are false.
2. aisle.includes(aisleSelection)
This part will return true if aisleSelection matches aisle
This part will return false if aisleSelection does not match aisle
3. Boolean(Boolean(assignedSelection) || Boolean(unassignedSelection)) && aisle.includes(aisleSelection)
This part will return true if both part_(1) and part_(2) return true
Thus part will return false if either part_(1) or part_(2) returns false
4. return Boolean(Boolean(assignedSelection) || Boolean(unassignedSelection)) && aisle.includes(aisleSelection)? assignedTo = currentUserId : assignedTo = null;
This part will return null if part_(3) returns false
This part will give the variable assignedTo the value currentUserId if part_(3) returns true
*/
});
return result;
}
//Execute the example
var arrayExample = [
{ aisle: "A9", userid: 125 },
{ aisle: "B2", userid: null },
{ aisle: "C#", userid: 126 },
];
var filtersExample = {
assignedButtonActive: true,
unassignedButtonActive: false,
aisle: "A9",
};
searchList(arrayExample, filtersExample);

in such cases, I use the usual brackets to show the individual parts of the inequality. example
return aisle.indexOf(aisleSelection) > -1 && (assigned) ? assignedTo == currentUserId : ((unassigned) ? assignedTo == null : [])
but maybe
return assignedTo = (aisle.indexOf(aisleSelection) > -1 && (assigned) ? currentUserId : ((unassigned) ? null : []))
I may have misunderstood the necessary conditions. if you describe the conditions in more detail, the answer will be more correct.

Node js filter array with reactive form values

I've got probelm with filtering array from form values.
I using angular 7 and express js
export function getItems(req: Request, res: Response) {
const itemCriteria: ItemCriteria = req.body.itemCriteria;
const name = (itemCriteria.name) ? itemCriteria.name : '';
const description= (itemCriteria.description) ?
itemCriteria.description: '';
const category= itemCriteria.category;
const filterItems: Item[] = items
.filter(item=> item.category.id === category &&
item.name .includes(name ) &&
item.description.includes(description)
);
res.status(200).json(filterItems);
}
When I fill all fields filterItems is correct, but when I fill only one or two fields I've got error 'Cannot read property of undefinied'. This fields is from reactive form but only one is required else is optional. So my question is how can I filter this array correct?

When one of Criteria is empty, you don't have to include it in the filter function.
So you can change it by following.
const filterItems: Item[] = items
.filter(item=> (!category || (item.category && item.category.id === category)) &&
(!name || (item.name && item.name.includes(name))) &&
(!description || (item.description && item.description.includes(description))
);

You are trying to read a property of an undefined variable. It's hard to know which one it is, but you can protect your code from these types of errors by making sure a variable is defined like this:
const myProperty = someVariable && someVariable.someProperty
This shortcircuits if someVariable is falsy.
In your case this might look like:
const filterItems: Item[] = items
.filter(item=> item && item.category && item.category.id === category &&
item.name && item.name.includes(firstName) &&
item.description && item.description.includes(lastName)
);
(also it's not clear where firstName, lastName, and items come from, but I don't think that's the cause of the error you're asking about)