I am trying to stop the browser from validating the form on submit. I have overridden the onsubmit event to use my own function. Unfortunately, when I submit the form, it is still validated, and my function does not run. The following is the code:
function submitFunction() {
alert("Name is required.");
event.preventDefault();
}
<form onsubmit="submitFunction()">
<input type="text" placeholder="Name" required>
<input type="submit" value="submit">
</form>
How can I fix this? Thanks for any help!
If you add to your form the attribute called novalidate then it will call your function:
function submitFunction() {
alert("Name is required.");
}
<form onsubmit="submitFunction()" novalidate>
<input type="text" placeholder="Name" required>
<input type="submit" value="submit">
</form>
From the documentation of <form>:
This Boolean attribute indicates that the form shouldn't be validated when submitted. If this attribute is not set (and therefore the form is validated), it can be overridden by a formnovalidate attribute on a <button>, <input type="submit">, or <input type="image"> element belonging to the form.
Related
I have a form like below:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" onclick="document.getElementsByTagName('form')[0].submit()" value="Submit">
</form>
Though I clicked the button and indeed it submitted the form, but the alert box wasn't shown. That is, the submit() method submitted the form but without triggering the onsubmit event. What happened? And how should I use submit() method to trigger the onsubmit event?
Well, the documentation for the submit method is pretty clear that it doesn't trigger onsubmit.
Since any of the following form elements cause a form submit:
<input type='submit'>
<input type='button'>
<button>
You likely don't need an onclick handler on that button at all
it seems that you can't, please check this post - https://stackoverflow.com/a/19847255/8449863
however, please try workaround with hidden submit button:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" value="Submit" onclick="document.getElementById('submit').click();" >
<input id="submit" type="submit" style="display: none;" />
</form>
I have a form like below:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" onclick="document.getElementsByTagName('form')[0].submit()" value="Submit">
</form>
Though I clicked the button and indeed it submitted the form, but the alert box wasn't shown. That is, the submit() method submitted the form but without triggering the onsubmit event. What happened? And how should I use submit() method to trigger the onsubmit event?
Well, the documentation for the submit method is pretty clear that it doesn't trigger onsubmit.
Since any of the following form elements cause a form submit:
<input type='submit'>
<input type='button'>
<button>
You likely don't need an onclick handler on that button at all
it seems that you can't, please check this post - https://stackoverflow.com/a/19847255/8449863
however, please try workaround with hidden submit button:
<form action="/action_page.php" onsubmit="alert('The form was submitted');" >
Enter name: <input type="text" name="fname">
<input type="button" value="Submit" onclick="document.getElementById('submit').click();" >
<input id="submit" type="submit" style="display: none;" />
</form>
i have one form with some input text with the name = "user_name" , "mob" , "email" and inside this form i have a link for example Plans and end with submit button. Now if user click the link then i want to have all the values of the input text of the same form send to another page to pks.php and if the user click on the submit button then it will work on action confirm.php. For example Check this code
<form action="confirm.php" method ="post">
<input type ="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
PLANS
<input type="submit">
</form>
Can you help me out?? How can i achieve this. Thanks in advance
The simplest way is to change the link to a second submit button. You can then use the formaction attribute to change the URL the form submits to when you use this button.
<form action="confirm.php" method ="post">
<input type ="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
<input type="submit" formaction="pks.php" value="PLANS">
<input type="submit">
</form>
If you can't do that, you need to run Javascript when they click on the link. You can have this code change the action of the form, and then submit it.
document.getElementById('plans').addEventListener('click', function(e) {
e.preventDefault();
var form = document.getElementById('myform');
form.action = this.href;
form.submit();
});
<form id="myform" action="confirm.php" method="post">
<input type="text" name="user_name">
<input type="number" name="mob">
<input type="text" name="email">
<a id="plans" href="pks.php">PLANS</a>
<input type="submit">
</form>
You will probably want to use JavaScript to control the form if you want the action attribute to change. By default, submitting the form will cause it to post to confirm.php.
Using JQuery you can do this:
$('form').on('submit', function(e) {
// Stop the form from submitting
e.preventDefault();
// Do logic to determine what action you should do
var myAction = 'pks.php';
// assign the action to the form
$(this).attr('action', myAction);
// submit the form
$(this).submit();
});
I haven't run this script so it may not work out of the box but you should be able to adapt and fix it without too much difficulty.
My code looks something like this -
<form name="myForm" ng-submit="!myForm.phone.$isEmpty(this.$viewValue)" action="/my/url" method="get">
<input name="phone">
<button type="submit">submit</button>
</form>
Now I can't submit the form even if I fill the phone number field.
But if I code like this :
<form name="myForm" ng-submit="!myForm.phone.$isEmpty(myForm.phone.$viewValue)" action="/my/url" method="get">
<input name="phone">
<button type="submit">submit</button>
</form>
Its perfectly working now.
So the difficulty is with 'this'. I cant even check the context of this, it should be the the context of $scope.myForm.phone, but somehow it isn't. Can someone please explain.
That's not what ng-submit is for. ng-submit is a function or expression called when the form is submitted. It's nothing to do with validation. If you want to ensure the text field is not empty before it's submitted you just need to add required and then if it is empty myForm.$invalid will be true.
Is this what you are trying to do:
html
<form name="myForm" ng-submit="submit(phone)">
<input name="phone" type="text" ng-model="phone.value" required>
<button type="submit" ng-disabled="myForm.$invalid" >submit</button>
</form>
controller
$scope.submit = function(phone){
console.log('phone', phone);
}
$scope.phone = {
value: ''
};
update
The this that you passed into the ng-submit is a reference to your controller. Since you have the name attribute set to myForm you can access the form model via this.myForm and the phone model via this.myForm.phone. So if you wanted to use $isEmpty to verify if the field is empty you would have to use:
this.myForm.phone.$isEmpty(this.myForm.phone.$viewValue)
ng-submit is used to provide a handler for the moment when the form IS submitted.
What you're looking for is disabling submit button with ng-disabled
<form name="myForm" ng-submit="functionInController()" action="/my/url" method="get">
<input name="phone" required>
<button type="submit" ng-disabled="myForm.$invalid">submit</button>
</form>
Pay attention to required directive added to the input. Which makes sure this field is not empty for submit
i want to only validate the form and don't want to submit it, so that i can use the form values in modifying other part of the same html page by calling a function "myfunction()" after form validation. for this i want to use a button suggest me required code.my code is following :-
<form name="form1">
<input type="text" name="name1" required></input>
<button onclick="myfunction()" ></button> // i want to validation of form by this button
</form>
You can try this by setting onsubmit event of form to return false; as follows:
<form name="form1" onsubmit="return false;">
<input type="text" name="name1" required></input>
<button onclick="myfunction();" ></button>
</form>
This will not submit the form on clicking the button but will execute myfunction() instead.
If you know jQuery, then you can do this as follows:
$('form[name="form1"]').submit(function (event) {
// This will prevent form being submitted.
event.preventDefault();
// Call your function.
myfunction();
});
For maintainability consider adding an event listener to the button by selection instead of inline. When the button is clicked an event object is passed to the callback. Event objects have a number of properties and methods. In this case you're looking for the method "preventDefault" which prevents the default action of the event which in this case is a form submit. An example:
<form name="form1">
<input type="text" name="name1" required />
<button id="my-button"></button>
</form>
document.getElementById('my-button').addEventListener('click', function(e){
e.preventDefault();
var form = document.forms['form1']; //or this.parentNode
//do stuff
}, false);
i have achived this goal by modifying code as follow:-
<form name="form1" onsubmit="myfunction();return false;">
<input type="text" name="name1" required></input>
<button >check form and call function</button>
</form>
by this i am able to check form and call my function and form is also not submitted in this case.
now i want to reset the form without clicking any button. suggest javascript code for this.
HTML form validation by input type button, not by submit.
Try this
<form name="form1" onsubmit="myfunction(); return false;">
<input type="text" name="name1" required></input>
<button type="submit">Submit</button>
</form>