Firebase Function onDelete from database and storage - javascript

I want to be able to delete a folder in firebase storage while onDelete in functions is triggered.
here is my firebase node code, once deleted, it will trigger functions to delete the corresponding folder in firebase storage. I am allowing user to delete their message conversion that includes images. I was able to delete the folder without using the {friendId} but {friendId} is needed in case the user have conversions with two different users.
My Firebase storage is as follow
messages_image_from_friends/
iLJ6nGJodeat2HRi5Q2xdTUmZnw2/
MXGCZv96aVUkSHZeU8kNTZqTQ0n2/
image.png
and Firebase Functions
const functions = require("firebase-functions");
const admin = require("firebase-admin");
const firebase = admin.initializeApp();
exports.deletePhotos = functions.database.ref('/messagesFriends/{userId}/{friendId}')
.onDelete((snap, context) => {
const { userId } = context.params;
<---- const { friendId } = context.params.friendId; ????? ---- >
const bucket = firebase.storage().bucket();
return bucket.deleteFiles({
prefix: `messages_image_from_friends/${userId}/{friendId}`
}, function(err) {
if (err) {
console.log(err);
} else {
console.log(`All the Firebase Storage files in
messages_image_from_friends/${userId}/{friendId} have been deleted`);
}
});
});
Log states that {friendId} is undefined. How do i get {friendId} from exports into prefix.
I have tried "snapshot" and "then()" but do not really know how to implement it as I am new to functions. Please help.
Update!!! 9/12/2020
I was able to get this working by changing onDelete to functions.https.onCall to use hashmap instead.. hope this help others
const functions = require("firebase-functions");
const admin = require("firebase-admin");
const firebase = admin.initializeApp();
exports.deletePhotos = functions.https.onCall((data, context) => {
const userId = data.userId;
const friendId = data.friendId;
console.log(userId, friendId);
const bucket = firebase.storage().bucket();
return bucket.deleteFiles({
prefix: `messages_image_from_friends/`+userId+`/`+friendId+`/`
}, function(err) {
if (err) {
console.log(err);
} else {
console.log(`messages_image_from_friends/`+userId+`/`+friendId);
}
});
// return {response:"This means success"};
});
and the code to call the function from your android app
private FirebaseFunctions mFunctions;
protected void onCreate(Bundle savedInstanceState) {
mFunctions = FirebaseFunctions.getInstance();
////String userId is current firebase user id
////String friendId is from getIntent(), etc
deletePhotos(userId, friendId);
}
private Task<String> deletePhotos(String userId, String friendId) {
// Create the arguments to the callable function.
Map<String, Object> data = new HashMap<>();
data.put("userId", userId);
data.put("friendId", friendId);
return mFunctions
.getHttpsCallable("deletePhotos")
.call(data)
.continueWith(new Continuation<HttpsCallableResult,
String>() {
#Override
public String then(#NonNull Task<HttpsCallableResult>
task) throws Exception {
// This continuation runs on either success or
failure, but if the task
// has failed then getResult() will throw an
Exception which will be
// propagated down.
String result = (String)
task.getResult().getData();
return result;
}
});
}
MAKE SURE YOU MAKE A NEW FIREBASE INIT FOLDER..
I MADE THE MISTAKE OF REDEPLOYING THIS DIRECTLY IN CLOUD FUNCTION CONSOLE WHILE IT WAS CONNECTED AS onDelete and IT WAS UPDATING THE index.js ONLY INSTEAD OF THE WHOLE FUNCTION FOLDER. SO DON'T DO WHAT I DID BECAUSE YOU WILL GET A TypeError: Cannot read property 'origin' of undefined at /srv/node_modules/cors/lib/
HOPE THIS HELPS OTHERS!!!
Update 9/18/20
I was able to make it work with onDelete with this
'use-strict'
const functions = require("firebase-functions");
const admin = require("firebase-admin");
const firebase = admin.initializeApp();
exports.deletePhotos =
functions.database.ref('/messagesFriends/{userId}/{friendId}')
.onDelete((snap, context) => {
const userId = context.params.userId;
const friendId = context.params.friendId;
const bucket = firebase.storage().bucket();
console.log(userId + ' ' + friendId + " found");
return bucket.deleteFiles({
prefix: `messages_image_from_friends/`+userId+`/`+friendId
}, function(err) {
if (err) {
console.log(`messages_image_from_friends/`+userId+`/`+friendId + `
remove error`);
} else {
console.log(`messages_image_from_friends/`+userId+`/`+friendId + `
removed`);
}
});
});

context.params is an object whose properties are populated with each of the wildcards from the trigger path. You're not using it correctly.
const userId = context.params.userId;
const friendId = context.params.friendId;
I suggest reviewing the documentation for database triggers, especially the part on specifying the path:
You can specify a path component as a wildcard by surrounding it with curly brackets; ref('foo/{bar}') matches any child of /foo. The values of these wildcard path components are available within the EventContext.params object of your function. In this example, the value is available as event.params.bar.

Related

how to create a user with firebase without signing in [duplicate]

So I have this issue where every time I add a new user account, it kicks out the current user that is already signed in. I read the firebase api and it said that "If the new account was created, the user is signed in automatically" But they never said anything else about avoiding that.
//ADD EMPLOYEES
addEmployees: function(formData){
firebase.auth().createUserWithEmailAndPassword(formData.email, formData.password).then(function(data){
console.log(data);
});
},
I'm the admin and I'm adding accounts into my site. I would like it if I can add an account without being signed out and signed into the new account. Any way i can avoid this?
Update 20161110 - original answer below
Also, check out this answer for a different approach.
Original answer
This is actually possible.
But not directly, the way to do it is to create a second auth reference and use that to create users:
var config = {apiKey: "apiKey",
authDomain: "projectId.firebaseapp.com",
databaseURL: "https://databaseName.firebaseio.com"};
var secondaryApp = firebase.initializeApp(config, "Secondary");
secondaryApp.auth().createUserWithEmailAndPassword(em, pwd).then(function(firebaseUser) {
console.log("User " + firebaseUser.uid + " created successfully!");
//I don't know if the next statement is necessary
secondaryApp.auth().signOut();
});
If you don't specify which firebase connection you use for an operation it will use the first one by default.
Source for multiple app references.
EDIT
For the actual creation of a new user, it doesn't matter that there is nobody or someone else than the admin, authenticated on the second auth reference because for creating an account all you need is the auth reference itself.
The following hasn't been tested but it is something to think about
The thing you do have to think about is writing data to firebase. Common practice is that users can edit/update their own user info so when you use the second auth reference for writing this should work. But if you have something like roles or permissions for that user make sure you write that with the auth reference that has the right permissions. In this case, the main auth is the admin and the second auth is the newly created user.
Update 20161108 - original answer below
Firebase just released its firebase-admin SDK, which allows server-side code for this and other common administrative use-cases. Read the installation instructions and then dive into the documentation on creating users.
original answer
This is currently not possible. Creating an Email+Password user automatically signs that new user in.
I just created a Firebase Function that triggers when a Firestore document is Created (with rules write-only to admin user). Then use admin.auth().createUser() to create the new user properly.
export const createUser = functions.firestore
.document('newUsers/{userId}')
.onCreate(async (snap, context) => {
const userId = context.params.userId;
const newUser = await admin.auth().createUser({
disabled: false,
displayName: snap.get('displayName'),
email: snap.get('email'),
password: snap.get('password'),
phoneNumber: snap.get('phoneNumber')
});
// You can also store the new user in another collection with extra fields
await admin.firestore().collection('users').doc(newUser.uid).set({
uid: newUser.uid,
email: newUser.email,
name: newUser.displayName,
phoneNumber: newUser.phoneNumber,
otherfield: snap.get('otherfield'),
anotherfield: snap.get('anotherfield')
});
// Delete the temp document
return admin.firestore().collection('newUsers').doc(userId).delete();
});
You can Algo use functions.https.onCall()
exports.createUser= functions.https.onCall((data, context) => {
const uid = context.auth.uid; // Authorize as you want
// ... do the same logic as above
});
calling it.
const createUser = firebase.functions().httpsCallable('createUser');
createUser({userData: data}).then(result => {
// success or error handling
});
Swift 5: Simple Solution
First store the current user in a variable called originalUser
let originalUser = Auth.auth().currentUser
Then, in the completion handler of creating a new user, use the updateCurrentUser method to restore the original user
Auth.auth().updateCurrentUser(originalUser, completion: nil)
Here is a simple solution using web SDKs.
Create a cloud function (https://firebase.google.com/docs/functions)
import admin from 'firebase-admin';
import * as functions from 'firebase-functions';
const createUser = functions.https.onCall((data) => {
return admin.auth().createUser(data)
.catch((error) => {
throw new functions.https.HttpsError('internal', error.message)
});
});
export default createUser;
Call this function from your app
import firebase from 'firebase/app';
const createUser = firebase.functions().httpsCallable('createUser');
createUser({ email, password })
.then(console.log)
.catch(console.error);
Optionally, you can set user document information using the returned uid.
createUser({ email, password })
.then(({ data: user }) => {
return database
.collection('users')
.doc(user.uid)
.set({
firstname,
lastname,
created: new Date(),
});
})
.then(console.log)
.catch(console.error);
I got André's very clever workaround working in Objective-C using the Firebase iOS SDK:
NSString *plistPath = [[NSBundle mainBundle] pathForResource:#"GoogleService-Info" ofType:#"plist"];
FIROptions *secondaryAppOptions = [[FIROptions alloc] initWithContentsOfFile:plistPath];
[FIRApp configureWithName:#"Secondary" options:secondaryAppOptions];
FIRApp *secondaryApp = [FIRApp appNamed:#"Secondary"];
FIRAuth *secondaryAppAuth = [FIRAuth authWithApp:secondaryApp];
[secondaryAppAuth createUserWithEmail:user.email
password:user.password
completion:^(FIRUser * _Nullable user, NSError * _Nullable error) {
[secondaryAppAuth signOut:nil];
}];
Update for Swift 4
I have tried a few different options to create multiple users from a single account, but this is by far the best and easiest solution.
Original answer by Nico
First Configure firebase in your AppDelegate.swift file
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
// Override point for customization after application launch.
FirebaseApp.configure()
FirebaseApp.configure(name: "CreatingUsersApp", options: FirebaseApp.app()!.options)
return true
}
Add the following code to action where you are creating the accounts.
if let secondaryApp = FirebaseApp.app(name: "CreatingUsersApp") {
let secondaryAppAuth = Auth.auth(app: secondaryApp)
// Create user in secondary app.
secondaryAppAuth.createUser(withEmail: email, password: password) { (user, error) in
if error != nil {
print(error!)
} else {
//Print created users email.
print(user!.email!)
//Print current logged in users email.
print(Auth.auth().currentUser?.email ?? "default")
try! secondaryAppAuth.signOut()
}
}
}
}
You can use firebase function for add users.
const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();
const cors = require('cors')({
origin: true,
});
exports.AddUser = functions.https.onRequest(( req, res ) => {
// Grab the text parameter.
cors( req, res, () => {
let email = req.body.email;
let passwd = req.body.passwd;
let role = req.body.role;
const token = req.get('Authorization').split('Bearer ')[1];
admin.auth().verifyIdToken(token)
.then(
(decoded) => {
// return res.status(200).send( decoded )
return creatUser(decoded);
})
.catch((err) => {
return res.status(401).send(err)
});
function creatUser(user){
admin.auth().createUser({
email: email,
emailVerified: false,
password: passwd,
disabled: false
})
.then((result) => {
console.log('result',result);
return res.status(200).send(result);
}).catch((error) => {
console.log(error.message);
return res.status(400).send(error.message);
})
}
});
});
CreateUser(){
//console.log('Create User')
this.submitted = true;
if (this.myGroup.invalid) {
return;
}
let Email = this.myGroup.value.Email;
let Passwd = this.myGroup.value.Passwd;
let Role = 'myrole';
let TechNum = this.myGroup.value.TechNum;
let user = JSON.parse(localStorage.getItem('user'));
let role = user.role;
let AdminUid = user.uid;
let authToken = user.stsTokenManager.accessToken;
let httpHeaders = new HttpHeaders().set('Authorization', 'Bearer ' + authToken);
let options = { headers: httpHeaders };
let params = { email:Email,passwd:Passwd,role:Role };
this.httpClient.post('https://us-central1-myproject.cloudfunctions.net/AddUser', params, options)
.subscribe( val => {
//console.log('Response from cloud function', val );
let createdUser:any = val;
//console.log(createdUser.uid);
const userRef: AngularFirestoreDocument<any> = this.afs.doc(`users/${createdUser.uid}`);
const userUpdate = {
uid: createdUser.uid,
email: createdUser.email,
displayName: null,
photoURL: null,
emailVerified: createdUser.emailVerified,
role: Role,
TechNum:TechNum,
AccountAccess:this.AccountAccess,
UserStatus:'open',
OwnerUid:AdminUid,
OwnerUidRole:role,
RootAccountAccess:this.RootAccountAccess
}
userRef.set(userUpdate, {
merge: false
});
this.toastr.success('Success, user add','Success');
this.myGroup.reset();
this.submitted = false;
},
err => {
console.log('HTTP Error', err.error)
this.toastr.error(err.error,'Error')
},
() => console.log('HTTP request completed.')
);
}
On the web, this is due to unexpected behavior when you call createUserWithEmailAndPassword out of the registration context; e.g. inviting a new user to your app by creating a new user account.
Seems like, createUserWithEmailAndPassword method triggers a new refresh token and user cookies are updated too. (This side-effect is not documented)
Here is a workaround for Web SDK:
After creating the new user;
firebase.auth().updateCurrentUser (loggedInUser.current)
provided that you initiate loggedInUser with the original user beforehand.
Hey i had similar problem ,trying to create users through admin , as it is not possible to signUp user without signIn ,I created a work around ,adding it below with steps
Instead of signup create a node in firebase realtime db with email as key (firebase do not allow email as key so I have created a function to generate key from email and vice versa, I will attach the functions below)
Save a initial password field while saving user (can even hash it with bcrypt or something, if you prefer though it will be used one time only)
Now Once user try to login check if any node with that email (generate key from email) exist in the db and if so then match the password provided.
If the password matched delete the node and do authSignUpWithEmailandPassword with provided credentials.
User is registered successfully
//Sign In
firebaseDB.child("users").once("value", (snapshot) => {
const users = snapshot.val();
const userKey = emailToKey(data.email);
if (Object.keys(users).find((key) => key === userKey)) {
setError("user already exist");
setTimeout(() => {
setError(false);
}, 2000);
setLoading(false);
} else {
firebaseDB
.child(`users`)
.child(userKey)
.set({ email: data.email, initPassword: data.password })
.then(() => setLoading(false))
.catch(() => {
setLoading(false);
setError("Error in creating user please try again");
setTimeout(() => {
setError(false);
}, 2000);
});
}
});
//Sign Up
signUp = (data, setLoading, setError) => {
auth
.createUserWithEmailAndPassword(data.email, data.password)
.then((res) => {
const userDetails = {
email: res.user.email,
id: res.user.uid,
};
const key = emailToKey(data.email);
app
.database()
.ref(`users/${key}`)
.remove()
.then(() => {
firebaseDB.child("users").child(res.user.uid).set(userDetails);
setLoading(false);
})
.catch(() => {
setLoading(false);
setError("error while registering try again");
setTimeout(() => setError(false), 4000);
});
})
.catch((err) => {
setLoading(false);
setError(err.message);
setTimeout(() => setError(false), 4000);
});
};
//Function to create a valid firebase key from email and vice versa
const emailToKey = (email) => {
//firebase do not allow ".", "#", "$", "[", or "]"
let key = email;
key = key.replace(".", ",0,");
key = key.replace("#", ",1,");
key = key.replace("$", ",2,");
key = key.replace("[", ",3,");
key = key.replace("]", ",4,");
return key;
};
const keyToEmail = (key) => {
let email = key;
email = email.replace(",0,", ".");
email = email.replace(",1,", "#");
email = email.replace(",2,", "$");
email = email.replace(",3,", "[");
email = email.replace(",4,", "]");
return email;
};
If you want to do it in your front end create a second auth reference use it to create other users and sign out and delete that reference. If you do it this way you won't be signed out when creating a new user and you won't get the error that the default firebase app already exists.
const createOtherUser =()=>{
var config = {
//your firebase config
};
let secondaryApp = firebase.initializeApp(config, "secondary");
secondaryApp.auth().createUserWithEmailAndPassword(email, password).then((userCredential) => {
console.log(userCredential.user.uid);
}).then(secondaryApp.auth().signOut()
)
.then(secondaryApp.delete()
)
}
Update 19.05.2022 - using #angular/fire (latest available = v.7.3.0)
If you are not using firebase directly in your app, but use e.g. #angular/fire for auth purposes only, you can use the same approach as suggested earlier as follows with the #angular/fire library:
import { Auth, getAuth, createUserWithEmailAndPassword } from '#angular/fire/auth';
import { deleteApp, initializeApp } from '#angular/fire/app';
import { firebaseConfiguration } from '../config/app.config'; // <-- Your project's configuration here.
const tempApp = initializeApp(firebaseConfiguration, "tempApp");
const tempAppAuth = getAuth(tempApp);
await createUserWithEmailAndPassword(tempAppAuth, email, password)
.then(async (newUser) => {
resolve( () ==> {
// Do something, e.g. add user info to database
});
})
.catch(error => reject(error))
.finally( () => {
tempAppAuth.signOut()
.then( () => deleteApp(tempApp));
});
The Swift version:
FIRApp.configure()
// Creating a second app to create user without logging in
FIRApp.configure(withName: "CreatingUsersApp", options: FIRApp.defaultApp()!.options)
if let secondaryApp = FIRApp(named: "CreatingUsersApp") {
let secondaryAppAuth = FIRAuth(app: secondaryApp)
secondaryAppAuth?.createUser(...)
}
Here is a Swift 3 adaptaion of Jcabrera's answer :
let bundle = Bundle.main
let path = bundle.path(forResource: "GoogleService-Info", ofType: "plist")!
let options = FIROptions.init(contentsOfFile: path)
FIRApp.configure(withName: "Secondary", options: options!)
let secondary_app = FIRApp.init(named: "Secondary")
let second_auth = FIRAuth(app : secondary_app!)
second_auth?.createUser(withEmail: self.username.text!, password: self.password.text!)
{
(user,error) in
print(user!.email!)
print(FIRAuth.auth()?.currentUser?.email ?? "default")
}
If you are using Polymer and Firebase (polymerfire) see this answer: https://stackoverflow.com/a/46698801/1821603
Essentially you create a secondary <firebase-app> to handle the new user registration without affecting the current user.
Android solution (Kotlin):
1.You need FirebaseOptions BUILDER(!) for setting api key, db url, etc., and don't forget to call build() at the end
2.Make a secondary auth variable by calling FirebaseApp.initializeApp()
3.Get instance of FirebaseAuth by passing your newly created secondary auth, and do whatever you want (e.g. createUser)
// 1. you can find these in your project settings under general tab
val firebaseOptionsBuilder = FirebaseOptions.Builder()
firebaseOptionsBuilder.setApiKey("YOUR_API_KEY")
firebaseOptionsBuilder.setDatabaseUrl("YOUR_DATABASE_URL")
firebaseOptionsBuilder.setProjectId("YOUR_PROJECT_ID")
firebaseOptionsBuilder.setApplicationId("YOUR_APPLICATION_ID") //not sure if this one is needed
val firebaseOptions = firebaseOptionsBuilder.build()
// indeterminate progress dialog *ANKO*
val progressDialog = indeterminateProgressDialog(resources.getString(R.string.progressDialog_message_registering))
progressDialog.show()
// 2. second auth created by passing the context, firebase options and a string for secondary db name
val newAuth = FirebaseApp.initializeApp(this#ListActivity, firebaseOptions, Constants.secondary_db_auth)
// 3. calling the create method on our newly created auth, passed in getInstance
FirebaseAuth.getInstance(newAuth).createUserWithEmailAndPassword(email!!, password!!)
.addOnCompleteListener { it ->
if (it.isSuccessful) {
// 'it' is a Task<AuthResult>, so we can get our newly created user from result
val newUser = it.result.user
// store wanted values on your user model, e.g. email, name, phonenumber, etc.
val user = User()
user.email = email
user.name = name
user.created = Date().time
user.active = true
user.phone = phone
// set user model on /db_root/users/uid_of_created_user/, or wherever you want depending on your structure
FirebaseDatabase.getInstance().reference.child(Constants.db_users).child(newUser.uid).setValue(user)
// send newly created user email verification link
newUser.sendEmailVerification()
progressDialog.dismiss()
// sign him out
FirebaseAuth.getInstance(newAuth).signOut()
// DELETE SECONDARY AUTH! thanks, Jimmy :D
newAuth.delete()
} else {
progressDialog.dismiss()
try {
throw it.exception!!
// catch exception for already existing user (e-mail)
} catch (e: FirebaseAuthUserCollisionException) {
alert(resources.getString(R.string.exception_FirebaseAuthUserCollision), resources.getString(R.string.alertDialog_title_error)) {
okButton {
isCancelable = false
}
}.show()
}
}
}
For Android, i suggest a simpler way to do it, without having to provide api key, application id...etc by hand by just using the FirebaseOptions of the default instance.
val firebaseDefaultApp = Firebase.auth.app
val signUpAppName = firebaseDefaultApp.name + "_signUp"
val signUpApp = try {
FirebaseApp.initializeApp(
context,
firebaseDefaultApp.options,
signUpAppName
)
} catch (e: IllegalStateException) {
// IllegalStateException is throw if an app with the same name has already been initialized.
FirebaseApp.getInstance(signUpAppName)
}
// Here is the instance you can use to sign up without triggering auth state on the default Firebase.auth
val signUpFirebaseAuth = Firebase.auth(signUpApp)
How to use ?
signUpFirebaseAuth
.createUserWithEmailAndPassword(email, password)
.addOnSuccessListener {
// Optional, you can send verification email here if you need
// As soon as the sign up with sign in is over, we can sign out the current user
firebaseAuthSignUp.signOut()
}
.addOnFailureListener {
// Log
}
My solution to this question is to store the User Name/Email and password in a static class and then add a new user log out the new user and immediately log in as the admin user(id pass you saved). Works like a charm for me :D
This is a version for Kotlin:
fun createUser(mail: String, password: String) {
val opts = FirebaseOptions.fromResource(requireContext())
if (opts == null) return
val app = Firebase.initialize(requireContext(), opts, "Secondary")
FirebaseAuth.getInstance(app)
.createUserWithEmailAndPassword(mail, password)
.addOnSuccessListener {
app.delete()
doWhateverWithAccount(it)
}.addOnFailureListener {
app.delete()
showException(it)
}
}
It uses the configuration from your default Firebase application instance, just under a different name.
It also deletes the newly created instance afterwards, so you can call this multiple times without any exception about already existing Secondary application.

How to fix firebase database initialised multiple times due to React SSR initialised database and cloud function firebase initialised database?

I have updated the question as found the root cause of the issue.
As I have hosted my React SSR app which uses firebase database in the client serving by one of the cloud function named app throwing an error of Error: FIREBASE FATAL ERROR: Database initialized multiple times. Please make sure the format of the database URL matches with each database() call.. When I comment out one by one and deploy, works perfectly. But when I deploy together doesn't work. How do I separate these two keeping both at the same repo?
ORIGINAL Question: Why firebase cloud function throwing an error of 'The default Firebase app does not exist.'?
So I am trying out firebase function for the first time. admin.messaging() throwing me the following error. Help me figure out why?
If I look at the console I get results till console.log('deviceToken', deviceToken);
so whats wrong in const messageDone = await admin.messaging().sendToDevice(deviceToken, payload);?
const functions = require('firebase-functions');
const admin = require('firebase-admin');
exports.updateUnreadCount = functions.database.ref('/chats/{chatId}/{messageId}')
.onCreate(async(snap, context) => {
const appOptions = JSON.parse(process.env.FIREBASE_CONFIG);
appOptions.databaseAuthVariableOverride = context.auth;
const adminApp = admin.initializeApp(appOptions, 'app');
const { message, senderId, receiverUid } = snap.val();
console.log(message, senderId, receiverUid);
console.log('------------------------');
const deleteApp = () => adminApp.delete().catch(() => null);
try {
const db = adminApp.database();
const reciverUserRef = await db.ref(`users/${receiverUid}/contacts/${senderId}/`);
console.log('reciverUserRef', reciverUserRef);
const deviceTokenSnapshot = await reciverUserRef.child('deviceToken').once('value');
const deviceToken = await deviceTokenSnapshot.val();
console.log('deviceToken', deviceToken);
const payload = {
notification: {
title: 'Test Notification Title',
body: message,
sound: 'default',
badge: '1'
}
};
const messageDone = await admin.messaging().sendToDevice(deviceToken, payload);
console.log('Successfully sent message: ', JSON.stringify(messageDone));
return deleteApp().then(() => res);
} catch (err) {
console.log('error', err);
return deleteApp().then(() => Promise.reject(err));
}
});
Update1: According to this https://firebase.google.com/docs/cloud-messaging/send-message#send_to_a_topic, admin.messaging().sendToDevice(deviceToken, payload) APIs are only available in the Admin Node.js SDK?
So switched to
const payload = {
data: {
title: 'Test Notification Title',
body: message,
sound: 'default',
badge: '1'
},
token: deviceToken
};
const messageDone = await admin.messaging().send(payload);
Which is not working either. Getting an error Error: The default Firebase app does not exist. Make sure you call initializeApp() before using any of the Firebase services. Any lead will be helpful.
EDIT: Finally got the function working.
My index.js is exporting to functions, follwoing
exports.app = functions.https.onRequest(app); //React SSR
exports.updateChat = functions.database.ref('/chats/{chatId}/{messageId}').onCreate(updateChat);
exports.app is a react ssr function, which I am using to host my site. This uses database too. and throwing error of multiple database instance.
When I comment out one by one and deploy, works perfectly. But when I deploy together doesn't work. How do I separate these two keeping both at the same repo? Any suggestions, please?
You can initialise db outside export function.
const admin = require('firebase-admin');
const adminApp = admin.initializeApp(appOptions, 'app')
//continue code
Update:
const admin = require('firebase-admin');
const adminApp = admin.initializeApp(options);
async function initialize(options, apps = 'app') {
try {
const defaultApp = adminApp.name
if(defaultApp) {
const adminApp1 = admin.initializeApp(apps);
}else {
const adminApp1 = admin.initializeApp(options, apps);
}
}catch(err) {
console.error(err);
}
}
Modify this snippet as per your need and try it out
It abstracts initialize of app in another function. Just call this function at appropriate place in your code.

Calling a Firebase Cloud Function 'ForEach' child of a Snapshot

I'm trying to deploy a Firebase Cloud Function that sends a text message to its associated recipient for x number of text messages. The function is triggered in my iOS app when an update is made to the 'send' Realtime Database reference, indicating that the user has pressed the 'send' button.
My Firebase structure is
{
"user1uid": {
"send": false
"messagesToSend": {
"messageuid1": {
"messageText": "What's for dinner?",
"recipientNumber": "+18017378888",
}
"messageuid2:
"messageText": "Who won the Cowboys game?",
"recipientNumber": "+18017377787",
}
}
"user2uid": {
"send": false
"messagesToSend": {
"messageuid1": {
"messageText": "What's for dinner?",
"recipientNumber": "+18017378888",
}
"messageuid2:
"messageText": "Who won the Cowboys game?",
"recipientNumber": "+18017377787",
}
}
}
My code currently only sends one message, and I'm not sure how I can properly iterate through the messagesToSend node for each user and send all the messages in it.
I've been trying to follow the tutorial located here. I have looked at the following Stack Overflow responses but am unable to decipher or derive a solution from them:
Firebase cloud function promises
Am I using ForEach correctly?
My index.js code that sends one message is as follows:
const functions = require('firebase-functions');
// The Firebase Admin SDK to access the Firebase Realtime Database.
const admin = require('firebase-admin');
admin.initializeApp();
const twilio = require('twilio')
const accountSid = functions.config().twilio.sid;
const authToken = functions.config().twilio.token;
const client = new twilio(accountSid, authToken);
const twilioNumber = functions.config().twilio.number;
// Start cloud function
exports.sendSecrets = functions.database
.ref('/{uid}/send')
.onUpdate((change,context) => {
const uid = context.params.uid;
return admin.database().ref(uid+'/messagesToSend').once('value').then(snapshot => {
snapshot.forEach(function(childSnapshot) {
var key = childSnapshot.key;
var messageData = childSnapshot.val();
**if (messageData.sanitized) return true;**
var message = messageData.messageText;
var phoneNumber = messageData.recipientNumber;
const textMessage = {
body: `From My App - ${message}`,
from: twilioNumber, // From Twilio number
to: phoneNumber // Text to this number
}
return client.messages.create(textMessage)
})
**return snapshot.ref.toString();**
});
});
Please note that the lines marked with ** at either end indicate that I know I need to return something based on error messages I received indicating that 'Each then() should return a value or throw'.
I make the assumption that you are using the twilio-node library that use promises: https://www.npmjs.com/package/twilio.
Since you want to send several messages in parallel, you have to use Promise.all(), as follows:
const functions = require('firebase-functions');
// The Firebase Admin SDK to access the Firebase Realtime Database.
const admin = require('firebase-admin');
admin.initializeApp();
const twilio = require('twilio')
const accountSid = functions.config().twilio.sid;
const authToken = functions.config().twilio.token;
const client = new twilio(accountSid, authToken);
const twilioNumber = functions.config().twilio.number;
// Start cloud function
exports.sendSecrets = functions.database
.ref('/{uid}/send')
.onUpdate((change,context) => {
const uid = context.params.uid;
return admin.database().ref(uid+'/messagesToSend').once('value')
.then(snapshot => {
const promises = [];
snapshot.forEach(function(childSnapshot) {
var key = childSnapshot.key;
var messageData = childSnapshot.val();
//**if (messageData.sanitized) return true;**
var message = messageData.messageText;
var phoneNumber = messageData.recipientNumber;
const textMessage = {
body: `From My App - ${message}`,
from: twilioNumber, // From Twilio number
to: phoneNumber // Text to this number
}
promises.push(client.messages.create(textMessage));
})
return Promise.all(promises);
})
// Edits made below to parentheses/brackets
.then(results => {
//Do whatever you want !!
// e.g. print the results which will be an array of messages
// (see https://www.twilio.com/docs/libraries/node#testing-your-installation)
})
});
You can also simply return Promise.all() as follows:
....
return Promise.all(promises);
})
});

Error In function After Firebase Deploying

Database Structure
Notification Structure
After successfully deploying my function into fire-base I am having these error in firebase function logs
1: Function execution took 1724 ms, finished with status: 'error'
2:TypeError: Cannot read property 'uid' of undefined
at exports.sendNotification.functions.firestore.document.onWrite.event
(/user_code/index.js:9:30)
at cloudFunctionNewSignature (/user_code/node_modules/firebase-
functions/lib/cloud-functions.js:105:23)
at cloudFunction (/user_code/node_modules/firebase-functions/lib/cloud-
functions.js:135:20)
at /var/tmp/worker/worker.js:733:24
at process._tickDomainCallback (internal/process/next_tick.js:135:7)
3:{"#type":"type.googleapis.com/google.cloud.audit.AuditLog","status":
{"code":3,"message":"The request has errors"},"authenticationInfo":
{"principalEmail":"info.jap.123#gmail.com"},"requestMetadata"{"callerIp":"39.50.37.100",
Index.js
'use-strict'
const functions = require('firebase-functions');
const admin = require('firebase-admin');
//admin.initializeApp(functions.config().firebase);
exports.sendNotification =
functions.firestore.
document("Users/{uid}/Notification/{nid}").onWrite(event=>
{
const user_id = event.params.uid
const notification_id = event.params.nid;
});
Notification Class in this class i am storing the notification id and message into Firebase-Firestore.
private void sendNotification()
{
String number = edTxtDevId.getText().toString();
if (TextUtils.isEmpty(number))
{
edTxtDevId.setError("Please Provide the dev id thank you");
return;
}
Calendar cal = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS");
String time = String.valueOf(cal.getTime());
final String message = "Notification has been sent to this number "+number+" by this number "+user_id+" at time = "+time;
Map<String , Object> notificationMessage = new HashMap<>();
notificationMessage.put("From" , mUserId);
notificationMessage.put("message" , message);
for (int i = 0 ; i < userList.size() ; i++)
{
if (userList.get(i).equals(number))
{
Log.e(TAG, "sendNotification: "+number+" found " +userList.get(i) + " id = "+i);
Toast.makeText(this, message, Toast.LENGTH_SHORT).show();
mFirestore.collection("Users/"+mUserId+"/Notification").add(notificationMessage).addOnSuccessListener(new OnSuccessListener<DocumentReference>() {
#Override
public void onSuccess(DocumentReference documentReference) {
Toast.makeText(MainActivity.this, message, Toast.LENGTH_SHORT).show();
}
});
}
}
}
Please help me if you know how to solve these
Thank you in advance!
Edited:
First of all, just as written here,
You need to pass a function with 2 arguments to onWrite().
Here is an example.
In your case,
document("Users/{uid}/Notification/{nid}").onWrite(event=> should be
document("Users/{uid}/Notification/{nid}").onWrite((change, context) =>
So, your code should look like:
'use strict'
const functions = require('firebase-functions');
// const admin = require('firebase-admin');
// admin.initializeApp(functions.config().firebase);
exports.sendNotification = functions.firestore
.document("Users/{uid}/Notification/{nid}")
.onWrite((change, context) => { // <- changed arguments here
// console.log(uid)
// console.log(nid)
// you can try these, but i think these console.log() will not work.
});
Second, if you want to retrieve uid and nid from the document path, you can use functions.database.DataSnapshot.ref or
functions.EventContext.resource
so your code should look like:
'use strict'
const functions = require('firebase-functions');
// const admin = require('firebase-admin');
// admin.initializeApp(functions.config().firebase);
exports.sendNotification = functions.firestore
.document("Users/{uid}/Notification/{nid}")
.onWrite((change, context) => {
// console.log(change.ref)
// the output will be like: "Users/PfUyNf.../Notification/0Ujdt..."
// or
// console.log(context.resource)
// the output will be like:
// "projects/_/instances/<databaseInstance>/refs/Users/PfUyNf.../Notification/0Ujdt..."
});
then use regexp or something to process the output.
I think there will be better solutions, but hope it helps.

algolia firestore function wont trigger

I've want to sync my Cloud Firestore with Algolia search index. I'm currently only able to deploy the firestore function, but it wont trigger onWrite or onChange.
I'm following this guide: Angular Full Text Search With Algolia Backend
As you can see the JS is deployed but it wont trigger when i add, remove or change a document in the database. The log don't show it either.
Database design:
-|search
-|searchId
-|id: string
-|name: sting
-|ref: string
Database rule:
//Search field
match /search/{searchId}{
allow read;
allow write: if request.auth != null;
}
JS function:
const functions = require('firebase-functions');
const admin = require("firebase-admin");
admin.initializeApp(functions.config().firebase);
const algoliasearch = require('algoliasearch');
const algolia = algoliasearch(functions.config().algolia.appid, functions.config().algolia.adminkey);
exports.updateIndex = functions.database.ref('/search/{searchId}').onWrite(event => {
const index = algolia.initIndex('search');
const searchId = event.params.searchId
const data = event.data.val()
if (!data) {
return index.deleteObject(searchId, (err) => {
if (err) throw err
console.log('Search Removed from Algolia Index', searchId)
})
}
data['objectID'] = searchId
return index.saveObject(data, (err, content) => {
if (err) throw err
console.log('Search Updated in Algolia Index', data.objectID)
})
});
I was facing similar problem. Change those lines:
exports.updateIndex = functions.database.ref('/search/{searchId}')...
to
exports.updateIndex = functions.firestore.document('search/{searchId}')...
and
const data = event.data.val()
to
const data = event.data.exists ? event.data.data() : null;
and it should work. It worked for me but I am facing now
Function returned undefined, expected Promise or value
log error and can't solve it but function works.

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