I have three divs I want to show based on a radio selection. I've written the below script, but the problem I've run into is the div doesn't hide after a different radio button is selected. I'm using ucalc so I can't change the class names or ids of the divs or the radio buttons so have to work with that.
Note, the radio button is automatically selected when the form loads so the first div needs to be showing initially.
Code below:
$(document).ready(function(){
// First Div/Radio Button
$('#input_radio-30-0-des').on('change', function(){
var a = $(this).prop('checked');
if(a) {
$("#grid-40-42").show();
} else {
$("#grid-40-42").hide();
}
});
// Second Div/Radio Button
$("#grid-44-46").hide();
$('#input_radio-30-1-des').on('change', function(){
var a = $(this).prop('checked');
if(a) {
$("#grid-44-46").show();
} else {
$("#grid-44-46").hide();
}
});
// Third Div/Radio Button
$("#grid-46-48").hide();
$('#input_radio-30-2-des').on('change', function(){
var a = $(this).prop('checked');
if(a) {
$("#grid-46-48").show();
} else {
$("#grid-46-48").hide();
}
});
});
I'm not very familiar with writing javascript (you can probably tell!) so an explanation for 'dummies' would be appreciated!
Thank you for your help!
You need to hide 2nd & 3rd div by CSS and when user change other button then find ID so according to ID show that div and rest div will hide as below snippet.
$(document).ready(function(){
$('#input_radio-30-0-des, #input_radio-30-1-des, #input_radio-30-2-des').on('change', function(){
var getid = $(this).attr('id');
if (getid=='input_radio-30-0-des') {
$('#grid-44-46, #grid-46-48').hide()//2nd and 3rd div hide
$("#grid-40-42").show();
}
if (getid=='input_radio-30-1-des') {
$('#grid-40-42, #grid-46-48').hide()//1st and 3rd div hide
$("#grid-44-46").show();
}
if (getid=='input_radio-30-2-des') {
$('#grid-40-42, #grid-44-46').hide()//1st and 2rd div hide
$("#grid-46-48").show();
}
})
});
#grid-44-46, #grid-46-48{display: none;}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<label><input type="radio" name="div-show-hide" id="input_radio-30-0-des" checked> Button One</label>
<label><input type="radio" name="div-show-hide" id="input_radio-30-1-des"> Button Two</label>
<label><input type="radio" name="div-show-hide" id="input_radio-30-2-des"> Button Three</label>
<div id="grid-40-42"><h2>Show - Div One</h2></div>
<div id="grid-44-46"><h2>Show - Div Two</h2></div>
<div id="grid-46-48"><h2>Show - Div Three</h2></div>
Use wild card to hide all <div> which id start with grid- on radio change.
$("[id^=grid-]").hide();
$('#input_radio-30-0-des').on('change', function() {
$("[id^=grid-]").hide();
var a = $(this).prop('checked');
if (a) {
$("#grid-40-42").show();
} else {
$("#grid-40-42").hide();
}
});
$('#input_radio-30-1-des').on('change', function() {
$("[id^=grid-]").hide();
var a = $(this).prop('checked');
if (a) {
$("#grid-44-46").show();
} else {
$("#grid-44-46").hide();
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type='radio' id='input_radio-30-0-des' name="group1" />
<div id='grid-40-42'>grid-40-42</div>
<input type='radio' id='input_radio-30-1-des' name="group1" />
<div id='grid-44-46'>grid-40-46</div>
Note
No need multi-pal $(document).ready(function(){ .
Id must be unique.
I'm using a Javascript object to match each Radio button with it's targeted div.
I assume they are hidden by default. Just having fun and giving an alternative to multiple checks! A cleaner code also where you could easily setup all those confusing names...
$( document ).ready(function() {
let matches = {
"input_radio-30-0-des": 'grid-40-42',
"input_radio-30-1-des": 'grid-44-46',
"input_radio-30-2-des": 'grid-46-48'
};
$(":input[name='FM']").on("change", function () {
var target= matches[$(this).attr('id')];
$('#' +target).toggle($(this).checked);
$("[id^=grid-]").not('#' +target).hide();
})
});
div[id*='grid-'] { display: none; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<input type="radio" name="FM" id="input_radio-30-0-des" value="0"/>
<label for="input_radio-30-0-des">0</label>
<input type="radio" name="FM" id="input_radio-30-1-des" value="1"/>
<label for="input_radio-30-1-des">1</label>
<input type="radio" name="FM" id="input_radio-30-2-des" value="2"/>
<label for="input_radio-30-2-des">2</label>
<div id="grid-40-42">40-42</div>
<div id="grid-44-46">44-46</div>
<div id="grid-46-48">46-48</div>
I have 3 radio inputs, that are wrapped in div so that they look like buttons instead of the default radio circle input, on click I am replacing the button text for checked icon. Now on validation if it fails I am returning the old value, and would like to again replace the text of the button for icon checked if the radio input was checked.
This is the script for the click action:
$('.Image-input__input-wrapper').click(function() {
$( '.plan-text-icon-toggle' ).replaceWith( '<span class="plan-text-icon-toggle">This is what I need</span>' )
$(this).find( '.plan-text-icon-toggle' ).replaceWith( '<span class="plan-text-icon-toggle"><i class="ion-checkmark-round"></i></span>' );
});
This is the html:
<div class="Image-input__input-wrapper">
<span class="plan-text-icon-toggle">This is what I need</span>
<input class="Image-input__input" type="radio" name="plan" value="player" {{ old('plan')=="player" ? 'checked='.'"'.'checked'.'"' : '' }}>
</div>
Now I would like to to do same for on page load if the button was checked already, but not sure how to do it?
Update
I have tried with adapting the suggestion in the answers:
function checkinput(elem) {
var parent = elem.parent(),
checked = elem.is(':checked');
$('.radio').removeClass('active').html('This is what I need');
if (checked) {
parent.addClass('active').html('Checked');
}
}
// apply style on change
$('[type=radio]').on('change', function () {
var elem = $(this);
checkinput(elem);
});
// apply style on load
var elem = $('[type=radio]:checked');
checkinput(elem);
Here is the full example. But it is not working.
You can always use input radio and just change the style with CSS. Look the example bellow:
function checkinput(elem) {
var parent = elem.parent(),
checked = elem.is(':checked');
$('.radio').removeClass('active');
if (checked) {
parent.addClass('active');
}
}
// apply style on change
$('[type=radio]').on('change', function () {
var elem = $(this);
checkinput(elem);
});
// apply style on load
var elem = $('[type=radio]:checked');
checkinput(elem);
.radio .on {
display: none;
}
.radio.active .off {
display: none;
}
.radio.active .on {
display: inline;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<label class="radio">
<span class="on">Message when checked</span>
<span class="off">Message when unchecked</span>
<input type="radio" name="my-radio" value="1">
</label>
</div>
<div>
<label class="radio">
<span class="on">Message when checked</span>
<span class="off">Message when unchecked</span>
<input type="radio" name="my-radio" value="2">
</label>
</div>
<div>
<label class="radio">
<span class="on">Message when checked</span>
<span class="off">Message when unchecked</span>
<input type="radio" name="my-radio" value="3" checked>
</label>
</div>
I am having a radio element that I want to get the text:
<div class="fleft multiplecolumns">
<div class="rdbUniteWrapper" style="line-height:20px">
<span class="EasilyRadioWrapper EasilyControlWrapper">
<span class="EasilyRadio EasilyChecked"></span>
<input id="rdbUnite_106" name="rdbUnite" type="radio" value="106" class="formElementHidden" checked="checked" style="opacity: 0;">
</span>
<label for="rdbUnite_106" style="font-weight: bold">kg (kilogramme)</label>
</div>
I tried $('input:radio[name=radio]:checked').next().text(); but it' s not the solution...
What am I doing wrong ?
Cheers
input:radio is not the sibling of label element, its parent span is. thus you need to traverse to parent span, then to next sibling element:
$('input:radio[name=radio]:checked').parent().next().text();
I find out the solution
var labelUnite = $('label[for="' + $("input[name='rdbUnite']:checked").attr("id") + '"]').text();
thanks for your helps
try below code
$('input:radio[name=radio]:checked').parent().next().text();
I am having a radio element that I want to get the text
Since the two are nicely related by id = for, you can use an attribute value selector:
// Assuming `this` is a reference to the radio button element
var label = $('label[for="' + this.id + '"]');
Then if you want the text, use .text():
var test = label.text();
Live example:
$("input[type=radio]").on("click", function() {
alert($('label[for="' + this.id + '"]').text());
});
Click a radio button to see its label text:
<div>
<label for="r1">This is for r1</label>
<input type="radio" id="r1">
</div>
<div>
<label for="r2">This is for r2</label>
<input type="radio" id="r2">
</div>
<div>
<label for="r3">This is for r3</label>
<input type="radio" id="r3">
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
More generally, a radio button element and its label are related in one of two ways:
Via id = for, as in your example
Via containment, where the label contains the input[type=radio]
If you want to handle the general case, you can do something like this:
// Assuming `this` is the radio button element
var text;
var label = null;
if (this.id) {
label = $('label[for="' + this.id + '"]');
}
if (!label || !label[0]) {
label = $(this).closest('label');
}
text = label && label.text();
Use This :-
var label = $("label[for='"+$('input:radio[name=radio]:checked').attr('id')+"']")
I currently have this form, and I am trying to get the value of the radio buttons when it is checked but I continually keep on having an error, what may be the problem with the code below?
html
<form name="radioset2" id="radioset2" action="survey.html">
<fieldset>
<span class = "question"> question1 </span>
<div id = "radio1">
<label for="r_q1_id">Yes</label>
<input id="r_q1_id" type="radio" name="r_q1_name" value="yes" />
</div>
<div id = "radio2">
<label for="r_q2_id">No</label>
<input id="r_q2_id" type="radio" name="r_q1_name" value="no" />
</div>
</fieldset>
</form>
javascript
function validRadio() {
var radio_buttons = document.getElementsByName.elements['r_q1_name'];
for(var x=0; x<radio_buttons.length; x++) {
if(radio_buttons[x].checked) {
alert(radio_buttons[x].value + " button is checked");
} else {
alert(radio_buttons[x].value + " button is not checked");
}
}
return false;
}
If you are targetting modern browsers, you can simply use the :checked CSS selector with the querySelector function to get the value of the checked input. That would remove the need of looping over the inputs.
http://jsfiddle.net/4uy2V/
var val = document.querySelector('[name=r_q1_name]:checked').value;
I have two radio buttons and want to post the value of the selected one.
How can I get the value with jQuery?
I can get all of them like this:
$("form :radio")
How do I know which one is selected?
To get the value of the selected radioName item of a form with id myForm:
$('input[name=radioName]:checked', '#myForm').val()
Here's an example:
$('#myForm input').on('change', function() {
alert($('input[name=radioName]:checked', '#myForm').val());
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<fieldset>
<legend>Choose radioName</legend>
<label><input type="radio" name="radioName" value="1" /> 1</label> <br />
<label><input type="radio" name="radioName" value="2" /> 2</label> <br />
<label><input type="radio" name="radioName" value="3" /> 3</label> <br />
</fieldset>
</form>
Use this..
$("#myform input[type='radio']:checked").val();
If you already have a reference to a radio button group, for example:
var myRadio = $("input[name=myRadio]");
Use the filter() function, not find(). (find() is for locating child/descendant elements, whereas filter() searches top-level elements in your selection.)
var checkedValue = myRadio.filter(":checked").val();
Notes: This answer was originally correcting another answer that recommended using find(), which seems to have since been changed. find() could still be useful for the situation where you already had a reference to a container element, but not to the radio buttons, e.g.:
var form = $("#mainForm");
...
var checkedValue = form.find("input[name=myRadio]:checked").val();
This should work:
$("input[name='radioName']:checked").val()
Note the "" usaged around the input:checked and not '' like the Peter J's solution
You can use the :checked selector along with the radio selector.
$("form:radio:checked").val();
If you want just the boolean value, i.e. if it's checked or not try this:
$("#Myradio").is(":checked")
Get all radios:
var radios = jQuery("input[type='radio']");
Filter to get the one thats checked
radios.filter(":checked")
Another option is:
$('input[name=radioName]:checked').val()
$("input:radio:checked").val();
In my case I have two radio buttons in one form and I wanted to know the status of each button.
This below worked for me:
// get radio buttons value
console.log( "radio1: " + $('input[id=radio1]:checked', '#toggle-form').val() );
console.log( "radio2: " + $('input[id=radio2]:checked', '#toggle-form').val() );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="toggle-form">
<div id="radio">
<input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">Plot single</label>
<input type="radio" id="radio2" name="radio"/><label for="radio2">Plot all</label>
</div>
</form>
Here's how I would write the form and handle the getting of the checked radio.
Using a form called myForm:
<form id='myForm'>
<input type='radio' name='radio1' class='radio1' value='val1' />
<input type='radio' name='radio1' class='radio1' value='val2' />
...
</form>
Get the value from the form:
$('#myForm .radio1:checked').val();
If you're not posting the form, I would simplify it further by using:
<input type='radio' class='radio1' value='val1' />
<input type='radio' class='radio1' value='val2' />
Then getting the checked value becomes:
$('.radio1:checked').val();
Having a class name on the input allows me to easily style the inputs...
try this one.
it worked for me
$('input[type="radio"][name="name"]:checked').val();
In a JSF generated radio button (using <h:selectOneRadio> tag), you can do this:
radiobuttonvalue = jQuery("input[name='form_id\:radiobutton_id']:checked").val();
where selectOneRadio ID is radiobutton_id and form ID is form_id.
Be sure to use name instead id, as indicated, because jQuery uses this attribute (name is generated automatically by JSF resembling control ID).
Also, check if the user does not select anything.
var radioanswer = 'none';
if ($('input[name=myRadio]:checked').val() != null) {
radioanswer = $('input[name=myRadio]:checked').val();
}
If you have Multiple radio buttons in single form then
var myRadio1 = $('input[name=radioButtonName1]');
var value1 = myRadio1.filter(':checked').val();
var myRadio2 = $('input[name=radioButtonName2]');
var value2 = myRadio2.filter(':checked').val();
This is working for me.
I wrote a jQuery plugin for setting and getting radio-button values. It also respects the "change" event on them.
(function ($) {
function changeRadioButton(element, value) {
var name = $(element).attr("name");
$("[type=radio][name=" + name + "]:checked").removeAttr("checked");
$("[type=radio][name=" + name + "][value=" + value + "]").attr("checked", "checked");
$("[type=radio][name=" + name + "]:checked").change();
}
function getRadioButton(element) {
var name = $(element).attr("name");
return $("[type=radio][name=" + name + "]:checked").attr("value");
}
var originalVal = $.fn.val;
$.fn.val = function(value) {
//is it a radio button? treat it differently.
if($(this).is("[type=radio]")) {
if (typeof value != 'undefined') {
//setter
changeRadioButton(this, value);
return $(this);
} else {
//getter
return getRadioButton(this);
}
} else {
//it wasn't a radio button - let's call the default val function.
if (typeof value != 'undefined') {
return originalVal.call(this, value);
} else {
return originalVal.call(this);
}
}
};
})(jQuery);
Put the code anywhere to enable the addin. Then enjoy! It just overrides the default val function without breaking anything.
You can visit this jsFiddle to try it in action, and see how it works.
Fiddle
$(".Stat").click(function () {
var rdbVal1 = $("input[name$=S]:checked").val();
}
This works fine
$('input[type="radio"][class="className"]:checked').val()
Working Demo
The :checked selector works for checkboxes, radio buttons, and select elements. For select elements only, use the :selected selector.
API for :checked Selector
To get the value of the selected radio that uses a class:
$('.class:checked').val()
I use this simple script
$('input[name="myRadio"]').on('change', function() {
var radioValue = $('input[name="myRadio"]:checked').val();
alert(radioValue);
});
Use this:
value = $('input[name=button-name]:checked').val();
DEMO : https://jsfiddle.net/ipsjolly/xygr065w/
$(function(){
$("#submit").click(function(){
alert($('input:radio:checked').val());
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr>
<td>Sales Promotion</td>
<td><input type="radio" name="q12_3" value="1">1</td>
<td><input type="radio" name="q12_3" value="2">2</td>
<td><input type="radio" name="q12_3" value="3">3</td>
<td><input type="radio" name="q12_3" value="4">4</td>
<td><input type="radio" name="q12_3" value="5">5</td>
</tr>
</table>
<button id="submit">submit</button>
If you only have 1 set of radio buttons on 1 form, the jQuery code is as simple as this:
$( "input:checked" ).val()
I've released a library to help with this. Pulls all possible input values, actually, but also includes which radio button was checked. You can check it out at https://github.com/mazondo/formalizedata
It'll give you a js object of the answers, so a form like:
<form>
<input type="radio" name"favorite-color" value="blue" checked> Blue
<input type="radio" name="favorite-color" value="red"> Red
</form>
will give you:
$("form").formalizeData()
{
"favorite-color" : "blue"
}
JQuery to get all the radio buttons in the form and the checked value.
$.each($("input[type='radio']").filter(":checked"), function () {
console.log("Name:" + this.name);
console.log("Value:" + $(this).val());
});
To retrieve all radio buttons values in JavaScript array use following jQuery code :
var values = jQuery('input:checkbox:checked.group1').map(function () {
return this.value;
}).get();
try it-
var radioVal = $("#myform").find("input[type='radio']:checked").val();
console.log(radioVal);
Another way to get it:
$("#myForm input[type=radio]").on("change",function(){
if(this.checked) {
alert(this.value);
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<span><input type="radio" name="q12_3" value="1">1</span><br>
<span><input type="radio" name="q12_3" value="2">2</span>
</form>
From this question, I came up with an alternate way to access the currently selected input when you're within a click event for its respective label. The reason why is because the newly selected input isn't updated until after its label's click event.
TL;DR
$('label').click(function() {
var selected = $('#' + $(this).attr('for')).val();
...
});
$(function() {
// this outright does not work properly as explained above
$('#reported label').click(function() {
var query = $('input[name="filter"]:checked').val();
var time = (new Date()).toString();
$('.query[data-method="click event"]').html(query + ' at ' + time);
});
// this works, but fails to update when same label is clicked consecutively
$('#reported input[name="filter"]').on('change', function() {
var query = $('input[name="filter"]:checked').val();
var time = (new Date()).toString();
$('.query[data-method="change event"]').html(query + ' at ' + time);
});
// here is the solution I came up with
$('#reported label').click(function() {
var query = $('#' + $(this).attr('for')).val();
var time = (new Date()).toString();
$('.query[data-method="click event with this"]').html(query + ' at ' + time);
});
});
input[name="filter"] {
display: none;
}
#reported label {
background-color: #ccc;
padding: 5px;
margin: 5px;
border-radius: 5px;
cursor: pointer;
}
.query {
padding: 5px;
margin: 5px;
}
.query:before {
content: "on " attr(data-method)": ";
}
[data-method="click event"] {
color: red;
}
[data-method="change event"] {
color: #cc0;
}
[data-method="click event with this"] {
color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="reported">
<input type="radio" name="filter" id="question" value="questions" checked="checked">
<label for="question">Questions</label>
<input type="radio" name="filter" id="answer" value="answers">
<label for="answer">Answers</label>
<input type="radio" name="filter" id="comment" value="comments">
<label for="comment">Comments</label>
<input type="radio" name="filter" id="user" value="users">
<label for="user">Users</label>
<input type="radio" name="filter" id="company" value="companies">
<label for="company">Companies</label>
<div class="query" data-method="click event"></div>
<div class="query" data-method="change event"></div>
<div class="query" data-method="click event with this"></div>
</form>
$(function () {
// Someone has clicked one of the radio buttons
var myform= 'form.myform';
$(myform).click(function () {
var radValue= "";
$(this).find('input[type=radio]:checked').each(function () {
radValue= $(this).val();
});
})
});