I have a string in which I need to get the value between either "[ValueToBeFetched]" or "{ValueToBeFetched}".
var test = "I am \"{now}\" doing \"[well]\"";
test.match(/"\[.*?]\"/g)
the above regex serves the purpose and gets the value between square brackets and I can use the same for curly brackets also.
test.match(/"\{.*?}\"/g)
Is there a way to keep only one regex and do this, something like an or {|[ operator in regex.
I tried some scenarios but they don't seem to work.
Thanks in advance.
You could try following regex:
(?:{|\[).*?(?:}|\])
Details:
(?:{|\[): Non-capturing group, gets character { or [
.*?: gets as few as possible
(?:}|\]): Non-capturing group, gets character } or ]
Demo
Code in JavaScript:
var test = "I am \"{now}\" doing \"[well]\"";
var result = test.match(/"(?:{|\[).*?(?:}|\])"/g);
console.log(result);
Result:
["{now}", "[well]"]
As you said, there is an or operator which is |:
[Edited as suggested] Let's catch all sentences that begins with an "a" or a "b" :
/^((a|b).*)/gm
In this example, if the line parsed begins with a or b, the entire sentence will be catched in the first result group.
You may test your regex with an online regex tester
For your special case, try something like that, and use the online regex tester i mentionned before to understand how it works:
((\[|\{)\w*(\]|\}))
Related
I'm completely mess with Regular Expressions right now(lack of practice).
I'm writing a node script, which goes through a bunch of js files, each file calls a function, with one of the arguments being a json. The aim is to get all those json arguments and place them in one file. The problem I'm facing at the moment is the extraction of the argument part of the code, here is the function call part of that string:
$translateProvider.translations('de', {
WASTE_MANAGEMENT: 'Abfallmanagement',
WASTE_TYPE_LIST: 'Abfallarten',
WASTE_ENTRY_LIST: 'Abfalleinträge',
WASTE_TYPE: 'Abfallart',
TREATMENT_TYPE: 'Behandlungsart',
TREATMENT_TYPE_STATUS: 'Status Behandlungsart',
DUPLICATED_TREATMENT_TYPE: 'Doppelte Behandlungsart',
TREATMENT_TYPE_LIST: 'Behandlungsarten',
TREATMENT_TARGET_LIST: 'Ziele Behandlungsarten',
TREATMENT_TARGET_ADD: 'Ziel Behandlungsart hinzufügen',
SITE_TARGET: 'Gebäudeziel',
WASTE_TREATMENT_TYPES: 'Abfallbehandlungsarten',
WASTE_TREATMENT_TARGETS: '{{Abfallbehandlungsziele}}',
WASTE_TREATMENT_TYPES_LIST: '{{Abfallbehandlungsarten}}',
WASTE_TYPE_ADD: 'Abfallart hinzufügen',
UNIT_ADD: 'Einheit hinzufügen'
})
So I'm trying to write a regular expression which matches the segment of the js code, which starts with "'de', {" and ends with "})", while it can have any characters between(single/double curly brackets included).
I tried something like this \'de'\s*,\s*{([^}]*)})\ , but that doesn't work. The furthest I got was with this \'de'\s*,\s*{([^})]*)}\ , but this ends at the first closing curly bracket within the json, which is not what I want.
It seems, that even the concepts of regular exressions I understood before, now I completely forgot.
Any is help is much appreciated.
You did not state the desired output. Here is a solution that parses the text, and creates an array of arrays. You can easily transform that to a desired output.
const input = `$translateProvider.translations('de', {
WASTE_MANAGEMENT: 'Abfallmanagement',
WASTE_TYPE_LIST: 'Abfallarten',
WASTE_ENTRY_LIST: 'Abfalleinträge',
WASTE_TYPE: 'Abfallart',
TREATMENT_TYPE: 'Behandlungsart',
TREATMENT_TYPE_STATUS: 'Status Behandlungsart',
DUPLICATED_TREATMENT_TYPE: 'Doppelte Behandlungsart',
TREATMENT_TYPE_LIST: 'Behandlungsarten',
TREATMENT_TARGET_LIST: 'Ziele Behandlungsarten',
TREATMENT_TARGET_ADD: 'Ziel Behandlungsart hinzufügen',
SITE_TARGET: 'Gebäudeziel',
WASTE_TREATMENT_TYPES: 'Abfallbehandlungsarten',
WASTE_TREATMENT_TARGETS: '{{Abfallbehandlungsziele}}',
WASTE_TREATMENT_TYPES_LIST: '{{Abfallbehandlungsarten}}',
WASTE_TYPE_ADD: 'Abfallart hinzufügen',
UNIT_ADD: 'Einheit hinzufügen'
})`;
const regex1 = /\.translations\([^{]*\{\s+(.*?)\s*\}\)/s;
const regex2 = /',[\r\n]+\s*/;
const regex3 = /: +'/;
let result = [];
let m = input.match(regex1);
if(m) {
result = m[1].split(regex2).map(line => line.split(regex3));
}
console.log(result);
Explanation of regex1:
\.translations\( -- literal .translations(
[^{]* -- anything not {
\{\s+ -- { and all whitespace
(.*?) -- capture group 1 with non-greedy scan up to:
\s*\}\) -- whitespace, followed by })
s flag to make . match newlines
Explanation of regex2:
',[\r\n]+\s* -- ',, followed by newlines and space (to split lines)
Explanation of regex3:
: +' -- literal : ' (to split key/value)
Learn more about regex: https://twiki.org/cgi-bin/view/Codev/TWikiPresentation2018x10x14Regex
This can be done with lookahead, lookbehind, and boundary-type assertions:
/(?<=^\$translateProvider\.translations\('de', {)[\s\S]*(?=}\)$)/
(?<=^\$translateProvider\.translations\('de', {) is a lookbehind assertion that checks for '$translateProvider.translations('de', {' at the beginning of the string.
(?=}\)$) is a lookahead assertion that checks for '})' at the end of the string.
[\s\S]* is a character class that matches any sequence of space and non-space characters between the two assertions.
Here is the regex101 link for you to test
Hope this helps.
Hi I am having problem while trying to remove these square brackets.
I figured out how to find square brackets but I need to find square brackets only if it starts with # like this,
by the way I am using .replace to remove them in javascript, Not sure if it is going to help to find the answer.
#[john_doe]
The result must be #john_doe.
I dont want to remove other brackets which is like that,
[something written here]
Here is the link of the regex
You need a regular expression replace solution like
text = text.replace(/#\[([^\][]*)]/g, "#$1")
See the regex demo.
Pattern details
#\[ - a #[ text
([^\][]*) - Group 1 ($1): any zero or more chars other than [ and ] (the ] is special inside character classes (in ECMAScript regex standard, even at the start position) and need escaping)
] - a ] char.
See the JavaScript demo:
let text = '#[john_doe] and [something written here]';
text = text.replace(/#\[([^\][]*)]/g, "#$1");
console.log(text);
You can use Regular expression /#\[/g:
const texts = ['#[john_doe]', '[something written here]']
texts.forEach(t => {
// Match the # character followed by an opening square bracket [
const result = t.replace(/#\[/g, '#')
console.log(result)
})
let name = "#[something_here]"
name.replace(/(\[|\])/, "")
I am passing a URL to a block of code in which I need to insert a new element into the regex. Pretty sure the regex is valid and the code seems right but no matter what I can't seem to execute the match for regex!
//** Incoming url's
//** url e.g. api/223344
//** api/11aa/page/2017
//** Need to match to the following
//** dir/api/12ab/page/1999
//** Hence the need to add dir at the front
var url = req.url;
//** pass in: /^\/api\/([a-zA-Z0-9-_~ %]+)(?:\/page\/([a-zA-Z0-9-_~ %]+))?$/
var re = myregex.toString();
//** Insert dir into regex: /^dir\/api\/([a-zA-Z0-9-_~ %]+)(?:\/page\/([a-zA-Z0-9-_~ %]+))?$/
var regVar = re.substr(0, 2) + 'dir' + re.substr(2);
var matchedData = url.match(regVar);
matchedData === null ? console.log('NO') : console.log('Yay');
I hope I am just missing the obvious but can anyone see why I can't match and always returns NO?
Thanks
Let's break down your regex
^\/api\/ this matches the beginning of a string, and it looks to match exactly the string "/api"
([a-zA-Z0-9-_~ %]+) this is a capturing group: this one specifically will capture anything inside those brackets, with the + indicating to capture 1 or more, so for example, this section will match abAB25-_ %
(?:\/page\/([a-zA-Z0-9-_~ %]+)) this groups multiple tokens together as well, but does not create a capturing group like above (the ?: makes it non-captuing). You are first matching a string exactly like "/page/" followed by a group exactly like mentioned in the paragraph above (that matches a-z, A-Z, 0-9, etc.
?$ is at the end, and the ? means capture 0 or more of the precending group, and the $ matches the end of the string
This regex will match this string, for example: /api/abAB25-_ %/page/abAB25-_ %
You may be able to take advantage of capturing groups, however, and use something like this instead to get similar results: ^\/api\/([a-zA-Z0-9-_~ %]+)\/page\/\1?$. Here, we are using \1 to reference that first capturing group and match exactly the same tokens it is matching. EDIT: actually, this probably won't work, since the text after /api/ and the text after /page/ will most likely be different, carrying on...
Afterwards, you are are adding "dir" to the beginning of your search, so you can now match someting like this: dir/api/abAB25-_ %/page/abAB25-_ %
You have also now converted the regex to a string, so like Crayon Violent pointed out in their comment, this will break your expected funtionality. You can fix this by using .source on your regex: var matchedData = url.match(regVar.source); https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/source
Now you can properly match a string like this: dir/api/11aa/page/2017 see this example: https://repl.it/Mj8h
As mentioned by Crayon Violent in the comments, it seems you're passing a String rather than a regular expression in the .match() function. maybe try the following:
url.match(new RegExp(regVar, "i"));
to convert the string to a regular expression. The "i" is for ignore case; don't know that's what you want. Learn more here:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp
I was given a task to do which requires a long time to do.
The image say it all :
This is what I have : (x100 times):
And I need to extract this value only
How can I capture the value ?
I have made it with this regex :
DbCommand.*?\("(.*?)"\);
As you can see it does work :
And after the replace function (replace to $1) I do get the pure value :
but the problem is that I need only the pure values and not the rest of the unmatched group :
Question : In other words :
How can I get the purified result like :
Eservices_Claims_Get_Pending_Claims_List
Eservices_Claims_Get_Pending_Claims_Step1
Here is my code at Online regexer
Is there any way of replacing "all besides the matched group" ?
p.s. I know there are other ways of doing it but I prefer a regex solution ( which will also help me to understand regex better)
Unfortunately, JavaScript doesn't understand lookbehind. If it did, you could change your regular expression to match .*? preceded (lookbehind) by DbCommand.*?\(" and followed (lookahead) by "\);.
With that solution denied, i believe the cleanest solution is to perform two matches:
// you probably want to build the regexps dynamically
var regexG = /DbCommand.*?\("(.*?)"\);/g;
var regex = /DbCommand.*?\("(.*?)"\);/;
var matches = str.match(regexG).map(function(item){ return item.match(regex)[1] });
console.log(matches);
// ["Eservices_Claims_Get_Pending_Claims_List", "Eservices_Claims_Get_Pending_Claims_Step1"]
DEMO: http://jsbin.com/aqaBobOP/2/edit
You should be able to do a global replace of:
public static DataTable.*?{.*?DbCommand.*?\("(.*?)"\);.*?}
All I've done is changed it to match the whole block including the function definition using a bunch of .*?s.
Note: Make sure your regex settings are such that the dot (.) matches all characters, including newlines.
In fact if you want to close up all whitespace, you can slap a \s* on the front and replace with $1\n:
\s*public static DataTable.*?{.*?DbCommand.*?\("(.*?)"\);.*?}
Using your test case: http://regexr.com?37ibi
You can use this (without the ignore case and multiline option, with a global search):
pattern: (?:[^D]+|\BD|D(?!bCommand ))+|DbCommand [^"]+"([^"]+)
replace: $1\n
Try simply replacing the whole document replacing using this expression:
^(?: |\t)*(?:(?!DbCommand).)*$
You will then only be left with the lines that begin with the string DbCommand
You can then remove the spaces in between by replacing:
\r?\n\s* with \n globally.
Here is an example of this working: http://regexr.com?37ic4
Given this string:
var str = 'A1=B2;C3,D0*E9+F6-';
I would like to retrieve the substring that goes from the beginning of the string up to 'D0*' (excluding), in this case:
'A1=B2;C3,'
I know how to achieve this using the combination of the substr and indexOf methods:
str.substr(0, str.indexOf('D0*'))
Live demo: http://jsfiddle.net/simevidas/XSu22/
However, this is obviously not the best solution since it contains a redundancy (the str name has to be written twice). This redundancy can be avoided by using the match method together with a regular expression that captures the substring:
str.match(/???/)[1]
Which regular expression literal do we have to pass into match to ensure that the correct substring is returned?
My guess is this: /(.*)D0\*/ (and that works), but my experience with regular expressions is rather limited, so I'm going to need a confirmation...
Try this:
/(.*?)D0\*/.exec(str)[1]
Or:
str.match(/(.*?)D0\*/)[1]
DEMO HERE
? directly following a quantifier makes the quantifier non-greedy (makes it match minimum instead of maximum of the interval defined).
Here's where that's from
/^(.+?)D0\*/
Try it here: http://rubular.com/r/TNTizJLSn9
/^.*(?=D0\*)/
more text to hit character limit...
You can do a number-group, like your example.
/^(.*?)foo/
It mean somethink like:
Store all in group, from start (the 0)
Stop, but don't store on found foo (the indexOf)
After that, you need match and get
'hello foo bar foo bar'.match(/^(.*?)foo/)[1]; // will return "hello "
It mean that will work on str variable and get the first (and unique) number-group existent. The [0] instead [1] mean that will get all matched code.
Bye :)