I have an excel sheet that updates daily, and I need to extract the last element of specific columns. I am using the XLSX node module, but cant find any way to read specific columns in my sheet.
This is what I had in mind:
var wb = XLSX.readFile("test.xlsx", { cellDates: true });
var ws = wb.Sheets["Sheet1"];
const colArray = ws["B"]; //To get column B as an array
Anyone with a solution to this? Preferably with the XLSX module.
Thanks in advance.
You can do it like this
//Create an array with the object keys and filter "B" columns. Assign it to the variable "columnB"
let columnB = Object.keys(ws).filter(key => key[0] === "B");
//Get the last key name in your columnB variable.Assign it to the "lastElementKey" variable.
let lastElementKey = columnB[columnB.length -1];
//And lastly, this is your last element in column "B"
ws[lastElementKey]
Related
I'm trying to leave a blank column in between data of an appended row, so that I can add a VLOOKUP function, functionally I don't need to do this (I could just add the VLOOKUP to the end of the row), but aesthetically it would be better if I could. Is there a way to just skip a column when appending data into a row?
Explanation:
You can use two separate setValues statements to achieve your goal and paste the data right after the last row with content with getLastRow().
I have fully described each block of lines in the following script so I think it is straightforward to work with it.
I tried to create a generic code where you can select:
the column you want to separate the data: sep_col
the starting column you want to paste the data: start_col
the number of columns you want to have between the two different datasets: space_col
Code snippet:
function myFunction() {
// get spreadsheet details
const ss = SpreadsheetApp.getActive();
const sh = ss.getSheetByName('Sheet1'); // change that to the name of your sheet
// provide some data
const sep_col = 3; // column you want to separate the data
const data = ["d1","d2","d3","d5","d6"];
const data1 = data.slice(0,sep_col);
const data2 = data.slice(sep_col,data.length);
// get current last row of document
const Lrow = sh.getLastRow();
// paste the data to separate ranges
const start_col = 1;
const space_col = 1;
sh.getRange(Lrow+1,start_col, 1, data1.length).setValues([data1]);
sh.getRange(Lrow+1,start_col+data1.length + space_col, 1, data2.length).setValues([data2]);
}
JavaScript References:
Array.prototype.slice()
Sheet used for the code snippet:
I do SEO, and therefore I have a lot of keywords flowing around in different spreadsheets. I'd like a way to filter these into seperate sheets based on specific filters, but I can't for the life of me, figure out how to do this in Google Apps Script.
Criteria I set myself for this to work out:
A list of strings and their corresponding volumes are entered in column 1+2.
A list of filter-words are written in column 3.
The script has to create a new sheet for each of the filter words and move the strings + volumes into these different sheets if the string contains a filter word.
Example:
Filter words: Apple, Banana, Pineapple
String: "The Apple Was Big", Volume: "100"
The script would move the string and volume into the sheet called "Apple" on row 1
(Beware, I'm in no means experienced in coding)
I believe you can use the following structure:
for(let i = 0; i <= column3RowAmount; i++){ //Run as long as there are more filter words
create(column3Row[i]); //create a new sheet with the name of the filter word
for(let j = 0; j <= column1RowAmount; j++){ //Run as long as there are more keywords
if(column1Row[j].indexOf(column3Row[i]) >= 0){ //If the Row in column 1 contains the filter word
column1Row[j].moveToSheet(column3Row[i]); // Make sure not to move Column 3, but only 1+2
}
}
}
Example sheet: https://docs.google.com/spreadsheets/d/15YIMyGmmfZdy094gwuJNxFmTd8h7NOLnA8KevZrGtdU/edit?usp=sharing
Explanation:
Your goal is to create a sheet for every filter-word in column C. Then copy the data in columns A, B but only the rows that include the filter-word to the corresponding sheet.
For starters, you need to get the filter-word list. You can get the full range of column C and filter out the empty cells:
const sh_names = sh.getRange('C1:C').getValues().flat().filter(r=>r!='');
Similarly, you need to get the data in columns A and B:
const data = sh.getRange('A1:B'+sh.getLastRow()).getValues();
The next step is to iterate over sh_names and for every element / filter-word, check if a sheet with that name exists. If it does not exist, then create a sheet with that name, if it exists then skip the creation part:
if(!ss.getSheetByName(s)){
ss.insertSheet().setName(s);}
The next step is to filter data on the rows that include the filter-word:
let f_data = data.filter(r=>r[0].includes(s));
Finally, check if the length of the data is bigger than 0, otherwise there is not data to use and set the values of data to the corresponding sheet:
sheet.getRange(sheet.getLastRow()+1,1,f_data.length,f_data[0].length).setValues(f_data)
Solution
function myFunction() {
const ss = SpreadsheetApp.getActive();
const sh = ss.getSheetByName('Ark1');
const filter_sh = ss.getSheetByName('Filter');
const data = sh.getRange('A1:B'+sh.getLastRow()).getValues();
const sh_names = filter_sh.getRange('A1:A'+filter_sh.getLastRow()).getValues().flat();
sh_names.forEach(s=>{
if(!ss.getSheetByName(s)){
ss.insertSheet().setName(s);}
let sheet = ss.getSheetByName(s);
let f_data = data.filter(r=>r[0].includes(s));
if(f_data.length>0){
sheet.getRange(sheet.getLastRow()+1,1,f_data.length,f_data[0].length).setValues(f_data);}
});
}
This function will place all of your results into column 4 next to the appropriate word rather than creating a page for each word. So it runs much faster.
function stringswords() {
const ss=SpreadsheetApp.getActive();
const sh=ss.getSheetByName('Sheet1');
const sr=2;
const rgd=sh.getRange(sr,1,sh.getLastRow()-sr+1,2);
const data=rgd.getDisplayValues();
const rgw=sh.getRange(sr,3,sh.getLastRow()-sr+1,1);
const words=rgw.getDisplayValues().flat();
const wiObj={};
words.forEach(function(w,i){wiObj[w]=i});
const rgr=sh.getRange(sr,4,sh.getLastRow()-sr+1,1);
rgr.clearContent();
var results=rgr.getValues();
words.forEach(function(w,i,A){
data.forEach(function(r,j,D) {
if(data[j][0] && data[j][0].indexOf(w)!=-1) {
results[wiObj[w]][0]+=Utilities.formatString('String:%s Vol:%s\n',data[j][0],data[j][1]);
}
});
});
rgr.setValues(results);
}
Image of Data and output:
I want to compare two sheets (based on header values in row 1) and delete any column with a unique value (without a match). For example, Assuming Sheet1, Row 1 data and Sheet 2, Row 1 are uniform, if a user adds/deletes a column within any sheet, I want to always match the number of columns in both sheets with their values
Screenshots of sheets headings.
IF both sheets looks like this
And a user adds a new Column N
Or delete column N
How can I ensure that both sheet matches by deleting the odd/distinct column in Sheet 1?
I have tried modifying this code below but I can't just get the unique one out. This code only look for headers with a defined value.
function deleteAloneColumns(){
var sheet = SpreadsheetApp.getActiveSheet();
var lastColumnPos = sheet.getLastColumn();
var headers = sheet.getRange( 1 ,1, 1, lastColumnPos ).getValues()[0];
for( var i = lastColumnPos ; i < 1; i--){
if( headers[i] === "alone" ) sheet.deleteColumn(i);
}
SpreadsheetApp.getUi().alert( 'Job done!' );
}
Any help to compare and delete the column with the unique value will be appreciated.
Problem
Balancing sheets based on header row values mismatch.
Solution
If I understood you correctly, you have a source sheet against which validation is run and two primary use cases: user adds a new column named differently than any other column (if you want to check that the column strictly matches the one in sheet1, it is easy to modify) in source sheet or deletes one that should be there.
const balanceSheets = (sourceShName = 'Sheet1',targetShName = 'Sheet2') => {
const ss = SpreadsheetApp.getActiveSpreadsheet();
const s1 = ss.getSheetByName(sourceShName);
const s2 = ss.getSheetByName(targetShName);
const s2lcol = s2.getLastColumn();
//keep all vals from source to reduce I/O
const s1DataVals = s1.getDataRange().getValues();
const s2Vals = s2.getRange(1, 1, 1, s2lcol).getValues();
const h1Vals = s1DataVals[0];
const h2Vals = s2Vals[0];
//assume s1 is source (validation) sheet
//assume s2 is target sheet that a user can edit
//case 1: target has value not present in source -> delete column in target
let colIdx = 0;
h2Vals.forEach(value => {
const isOK = h1Vals.some(val => val===value);
isOK ? colIdx++ : s2.deleteColumn(colIdx+1);
});
//case 2: target does not have values present in source -> append column from source
h1Vals.forEach((value,index) => {
const isOK = h2Vals.some(val => val===value);
!isOK && s2.insertColumnAfter(index);
const valuesToInsert = s1DataVals.map(row => [row[index]]);
const numRowsToInsert = valuesToInsert.length;
s2.getRange(1,index+1, numRowsToInsert,1).setValues(valuesToInsert);
});
};
Showcase
Here is a small demo of how it works as a macros:
Notes
Solving your problem with two forEach is suboptimal, but I kept number of I/O low (it can be lowered further by, for example, moving deleteColum out of the loop while only keeping track of column indices).
The script uses ES6 capabilities provided by V8, so please, be careful (although I would recommend migrating as soon as possible - even if you encounter bugs / inconsistencies , it is worth more than it costs.
UPD made script more flexible by moving sheet names to parameter list.
UPD2 after discussing the issue with deleteColumn() behaviour, the answer is updated to keep column pointer in bounds (for those curious about it - forEach kept incrementing the index, while deleteColumn reduced bounds for any given index).
Reference
insertColumnAfter() method reference
I am currently using NodeJS and the library SheetsJS to read an XLSX workbook.
My task is to take data from multiple sheets and append them to a new worksheet. The structure of the sheet has the Categories in Column A and Category Values in Column B.
*Things I've Tried *
I have tried 2 things that have presented 2 different issues:
1.) I've tried using the builtin function sheet_to_json to format my xlsx data into JSON but it makes the header the key for every object. I've used the option skipHeader: true to negate this but if A1 is the header, A2 is the next value that gets repeated as the object.
Below is a code snippet:
let readFiletoJSON = filename => {
//wb = workbook
let wb = xlsx.readFile(filename, {cellDates: true});
let ws = wb.Sheets["1-Header"]
let currentRange = { s: { c: 0, r: 1 }, e: { c: 1, r: 10 } }
let encodedRange = xlsx.utils.encode_range(currentRange)
let sheetData = []
sheetData.push(
xlsx.utils.sheet_to_json(ws, {range: encodedRange}, {skipHeader: true})
)
console.log(sheetData)
2.) I have also tried creating my own array of objects with Column A as the key and Column B as the value however, I have trouble figuring out how to read the object into the new worksheet. How can I read the values into the new sheet?
I hope this is clear enough. Thank you in advance.
Is there a way to retrieve a column dynamically by it's column name (header)?
Instead of:
var values = sheet.getRange("A:A").getValues();
Something like: (Just for simplicity)
var values = sheet.getRange(sheet.column.getHeader("name").getValues();
Please keep in mind that Google Apps Script is roughly ES3.
You can write one ;)
function getColValuesByName(sheet, name) {
var index = sheet.getRange(1,1,1,sheet.getLastColumn()).getValues()[0].indexOf(name);
index++;
return sheet.getRange(1,index,sheet.getLastRow(),1).getValues();
}
Here's a very simple one-line function you can copy. It returns the column number (A = 1, B = 2, etc.) for use in getRange, for example.
function getColByHeader(name) {
return SpreadsheetApp.getActiveSheet().getRange('1:1').getValues()[0].indexOf(name) + 1;
}
Although there is no direct way, there are plenty of ways to get what you want with a little set up:
Get all data and filter it(no set up):
var values = sheet.getDataRange().getValues();
var headers = values.splice(0,1);
headerIdx = headers[0].indexOf("name");
values = values.map(function(row){return [row[headerIdx]];})
Named ranges set up:
If you have named ranges associated with that column,
spreadsheet.getRangeByName('Sheet Name!name').getValues();//where 'name' is a named range
Developer metadata set up:
If you have developer metadata associated with that column,
SpreadsheetApp.getActive()
.createDeveloperMetadataFinder()
.withKey(/*METADATA_KEY_ASSOCIATED_WITH_COLUMN*/)
.find()[0]
.getLocation()
.getColumn()
.getValues();