I'm loading a page using selenium and I want to execute this
<script>
var ep_start = $('#episode_page a.active').attr('ep_start');
var ep_end = $('#episode_page a.active').attr('ep_end');
var id = $("input#movie_id").val();
var default_ep = $("input#default_ep").val();
var alias = $("input#alias_anime").val();
loadListEpisode('#episode_page a.active',ep_start,ep_end,id,default_ep,alias);
</script>
I have no clue how to do it in python, I tried to use the full script
js = '''script'''
browser.execute_script(js)
or just loadListEpisode(...) replacing each one by its equivalent, it's not really working.
The script is present on the page so maybe there's a way to directly call it.
I tried to extract ep_start, ep_end,.. by hand then doing this
source = BeautifulSoup(...)
var1 = source.find(...)
...
browser.execute_script("loadEpisodeList(var1,var2,...)")
It didn't work too, I don't think it's recognizing them as variables
If $ represents jQuery, you would first have to load it into the browser as follows if it has not already been loaded by the current page:
path_to_jquery_js = '/my_scripts/jquery.js' # for example
with open(path_to_jquery_js, 'r') as f:
jquery_js = r.read()
browser.execute_script(jquery_js)
If you do not have jQuery stored locally, then you would have to use something like the requests module from the PyPi repository to fetch it:
import requests
jquery_url = 'https://some_domain/jquery.js' # for example
r = requests.get(jquery_url)
jquery_js = r.text
browser.execute_script(jquery_js
Then you should be able to execute the script as follows:
script = """
var ep_start = $('#episode_page a.active').attr('ep_start');
var ep_end = $('#episode_page a.active').attr('ep_end');
var id = $("input#movie_id").val();
var default_ep = $("input#default_ep").val();
var alias = $("input#alias_anime").val();
loadListEpisode('#episode_page a.active',ep_start,ep_end,id,default_ep,alias);
"""
browser.execute_script(script)
Just make sure loadListEpisode is already defined by other JavaScript that has already been loaded.
This is untested by me for obvious reasons, but give it a shot -- it should work in principle. Let me know how it goes (I am sure you will).
You simply need to pass the script as an argument to execute_script() method as follows:
driver.execute_script("""
var ep_start = $('#episode_page a.active').attr('ep_start');
var ep_end = $('#episode_page a.active').attr('ep_end');
var id = $("input#movie_id").val();
var default_ep = $("input#default_ep").val();
var alias = $("input#alias_anime").val();
loadListEpisode('#episode_page a.active',ep_start,ep_end,id,default_ep,alias);
""")
You can find a relevant discussion in How to extract and print the final numbers using Selenium ChromeDriver and MutationObserver
hello i have a script using Python and Selenium, and I don't understand why this can't retrieve the JS part of the website (the same script works perfectly fine on my other machine):
import chromedriver_binary
from bs4 import BeautifulSoup
chrome_options = webdriver.ChromeOptions()
chrome_options.add_argument("--headless")
chrome_options.add_argument("--disable-gpu")
chrome_options.add_argument("window-size=1024,768")
chrome_options.add_argument("--no-sandbox")
chrome_options.add_argument("--enable-javascript")
url = "https://deliveroo.co.uk/restaurants/london/holborn?geohash=gcpvj6kxet58&collection=pizza"
driver = webdriver.Chrome(chrome_options=chrome_options)
driver.get(url)
soup = BeautifulSoup(driver.page_source, "lxml")
show_data = soup.find_all("script", id="__NEXT_DATA__")
mydata = json.loads( show_data[0].text )
I get the following error, meaning that it couldn't see this part of JSON:
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)
Not too sure why this is working on my other machine and not on my current one.
The .text attribute doesn't work here. To get the right data, it worked for me to use encode_contents(), just changing the definition of mydata like this:
mydata = json.loads( show_data[0].encode_contents())
I am trying to obtain the current NoteBook name when running the IPython notebook. I know I can see it at the top of the notebook. What I am after something like
currentNotebook = IPython.foo.bar.notebookname()
I need to get the name in a variable.
adding to previous answers,
to get the notebook name run the following in a cell:
%%javascript
IPython.notebook.kernel.execute('nb_name = "' + IPython.notebook.notebook_name + '"')
this gets you the file name in nb_name
then to get the full path you may use the following in a separate cell:
import os
nb_full_path = os.path.join(os.getcwd(), nb_name)
I have the following which works with IPython 2.0. I observed that the name of the notebook is stored as the value of the attribute 'data-notebook-name' in the <body> tag of the page. Thus the idea is first to ask Javascript to retrieve the attribute --javascripts can be invoked from a codecell thanks to the %%javascript magic. Then it is possible to access to the Javascript variable through a call to the Python Kernel, with a command which sets a Python variable. Since this last variable is known from the kernel, it can be accessed in other cells as well.
%%javascript
var kernel = IPython.notebook.kernel;
var body = document.body,
attribs = body.attributes;
var command = "theNotebook = " + "'"+attribs['data-notebook-name'].value+"'";
kernel.execute(command);
From a Python code cell
print(theNotebook)
Out[ ]: HowToGetTheNameOfTheNoteBook.ipynb
A defect in this solution is that when one changes the title (name) of a notebook, then this name seems to not be updated immediately (there is probably some kind of cache) and it is necessary to reload the notebook to get access to the new name.
[Edit] On reflection, a more efficient solution is to look for the input field for notebook's name instead of the <body> tag. Looking into the source, it appears that this field has id "notebook_name". It is then possible to catch this value by a document.getElementById() and then follow the same approach as above. The code becomes, still using the javascript magic
%%javascript
var kernel = IPython.notebook.kernel;
var thename = window.document.getElementById("notebook_name").innerHTML;
var command = "theNotebook = " + "'"+thename+"'";
kernel.execute(command);
Then, from a ipython cell,
In [11]: print(theNotebook)
Out [11]: HowToGetTheNameOfTheNoteBookSolBis
Contrary to the first solution, modifications of notebook's name are updated immediately and there is no need to refresh the notebook.
As already mentioned you probably aren't really supposed to be able to do this, but I did find a way. It's a flaming hack though so don't rely on this at all:
import json
import os
import urllib2
import IPython
from IPython.lib import kernel
connection_file_path = kernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
# Updated answer with semi-solutions for both IPython 2.x and IPython < 2.x
if IPython.version_info[0] < 2:
## Not sure if it's even possible to get the port for the
## notebook app; so just using the default...
notebooks = json.load(urllib2.urlopen('http://127.0.0.1:8888/notebooks'))
for nb in notebooks:
if nb['kernel_id'] == kernel_id:
print nb['name']
break
else:
sessions = json.load(urllib2.urlopen('http://127.0.0.1:8888/api/sessions'))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
print sess['notebook']['name']
break
I updated my answer to include a solution that "works" in IPython 2.0 at least with a simple test. It probably isn't guaranteed to give the correct answer if there are multiple notebooks connected to the same kernel, etc.
It seems I cannot comment, so I have to post this as an answer.
The accepted solution by #iguananaut and the update by #mbdevpl appear not to be working with recent versions of the Notebook.
I fixed it as shown below. I checked it on Python v3.6.1 + Notebook v5.0.0 and on Python v3.6.5 and Notebook v5.5.0.
import jupyterlab
if jupyterlab.__version__.split(".")[0] == "3":
from jupyter_server import serverapp as app
key_srv_directory = 'root_dir'
else :
from notebook import notebookapp as app
key_srv_directory = 'notebook_dir'
import urllib
import json
import os
import ipykernel
def notebook_path(key_srv_directory, ):
"""Returns the absolute path of the Notebook or None if it cannot be determined
NOTE: works only when the security is token-based or there is also no password
"""
connection_file = os.path.basename(ipykernel.get_connection_file())
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
for srv in app.list_running_servers():
try:
if srv['token']=='' and not srv['password']: # No token and no password, ahem...
req = urllib.request.urlopen(srv['url']+'api/sessions')
else:
req = urllib.request.urlopen(srv['url']+'api/sessions?token='+srv['token'])
sessions = json.load(req)
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
return os.path.join(srv[key_srv_directory],sess['notebook']['path'])
except:
pass # There may be stale entries in the runtime directory
return None
As stated in the docstring, this works only when either there is no authentication or the authentication is token-based.
Note that, as also reported by others, the Javascript-based method does not seem to work when executing a "Run all cells" (but works when executing cells "manually"), which was a deal-breaker for me.
The ipyparams package can do this pretty easily.
import ipyparams
currentNotebook = ipyparams.notebook_name
On Jupyter 3.0 the following works. Here I'm showing the entire path on the Jupyter server, not just the notebook name:
To store the NOTEBOOK_FULL_PATH on the current notebook front end:
%%javascript
var nb = IPython.notebook;
var kernel = IPython.notebook.kernel;
var command = "NOTEBOOK_FULL_PATH = '" + nb.base_url + nb.notebook_path + "'";
kernel.execute(command);
To then display it:
print("NOTEBOOK_FULL_PATH:\n", NOTEBOOK_FULL_PATH)
Running the first Javascript cell produces no output.
Running the second Python cell produces something like:
NOTEBOOK_FULL_PATH:
/user/zeph/GetNotebookName.ipynb
Yet another hacky solution since my notebook server can change. Basically you print a random string, save it and then search for a file containing that string in the working directory. The while is needed because save_checkpoint is asynchronous.
from time import sleep
from IPython.display import display, Javascript
import subprocess
import os
import uuid
def get_notebook_path_and_save():
magic = str(uuid.uuid1()).replace('-', '')
print(magic)
# saves it (ctrl+S)
display(Javascript('IPython.notebook.save_checkpoint();'))
nb_name = None
while nb_name is None:
try:
sleep(0.1)
nb_name = subprocess.check_output(f'grep -l {magic} *.ipynb', shell=True).decode().strip()
except:
pass
return os.path.join(os.getcwd(), nb_name)
There is no real way yet to do this in Jupyterlab. But there is an official way that's now under active discussion/development as of August 2021:
https://github.com/jupyter/jupyter_client/pull/656
In the meantime, hitting the api/sessions REST endpoint of jupyter_server seems like the best bet. Here's a cleaned-up version of that approach:
from jupyter_server import serverapp
from jupyter_server.utils import url_path_join
from pathlib import Path
import re
import requests
kernelIdRegex = re.compile(r"(?<=kernel-)[\w\d\-]+(?=\.json)")
def getNotebookPath():
kernelId = kernelIdRegex.search(get_ipython().config["IPKernelApp"]["connection_file"])[0]
for jupServ in serverapp.list_running_servers():
for session in requests.get(url_path_join(jupServ["url"], "api/sessions"), params={"token": jupServ["token"]}).json():
if kernelId == session["kernel"]["id"]:
return Path(jupServ["root_dir"]) / session["notebook"]['path']
Tested working with
python==3.9
jupyter_server==1.8.0
jupyterlab==4.0.0a7
Modifying #jfb method, gives the function below which worked fine on ipykernel-5.3.4.
def getNotebookName():
display(Javascript('IPython.notebook.kernel.execute("NotebookName = " + "\'"+window.document.getElementById("notebook_name").innerHTML+"\'");'))
try:
_ = type(NotebookName)
return NotebookName
except:
return None
Note that the display javascript will take some time to reach the browser, and it will take some time to execute the JS and get back to the kernel. I know it may sound stupid, but it's better to run the function in two cells, like this:
nb_name = getNotebookName()
and in the following cell:
for i in range(10):
nb_name = getNotebookName()
if nb_name is not None:
break
However, if you don't need to define a function, the wise method is to run display(Javascript(..)) in one cell, and check the notebook name in another cell. In this way, the browser has enough time to execute the code and return the notebook name.
If you don't mind to use a library, the most robust way is:
import ipynbname
nb_name = ipynbname.name()
If you are using Visual Studio Code:
import IPython ; IPython.extract_module_locals()[1]['__vsc_ipynb_file__']
Assuming you have the Jupyter Notebook server's host, port, and authentication token, this should work for you. It's based off of this answer.
import os
import json
import posixpath
import subprocess
import urllib.request
import psutil
def get_notebook_path(host, port, token):
process_id = os.getpid();
notebooks = get_running_notebooks(host, port, token)
for notebook in notebooks:
if process_id in notebook['process_ids']:
return notebook['path']
def get_running_notebooks(host, port, token):
sessions_url = posixpath.join('http://%s:%d' % (host, port), 'api', 'sessions')
sessions_url += f'?token={token}'
response = urllib.request.urlopen(sessions_url).read()
res = json.loads(response)
notebooks = [{'kernel_id': notebook['kernel']['id'],
'path': notebook['notebook']['path'],
'process_ids': get_process_ids(notebook['kernel']['id'])} for notebook in res]
return notebooks
def get_process_ids(name):
child = subprocess.Popen(['pgrep', '-f', name], stdout=subprocess.PIPE, shell=False)
response = child.communicate()[0]
return [int(pid) for pid in response.split()]
Example usage:
get_notebook_path('127.0.0.1', 17004, '344eb91bee5742a8501cc8ee84043d0af07d42e7135bed90')
To realize why you can't get notebook name using these JS-based solutions, run this code and notice the delay it takes for the message box to appear after python has finished execution of the cell / entire notebook:
%%javascript
function sayHello() {
alert('Hello world!');
}
setTimeout(sayHello, 1000);
More info
Javascript calls are async and hence not guaranteed to complete before python starts running another cell containing the code expecting this notebook name variable to be already created... resulting in NameError when trying to access non-existing variables that should contain notebook name.
I suspect some upvotes on this page became locked before voters could discover that all %%javascript-based solutions ultimately don't work... when the producer and consumer notebook cells are executed together (or in a quick succession).
All Json based solutions fail if we execute more than one cell at a time
because the result will not be ready until after the end of the execution
(its not a matter of using sleep or waiting any time, check it yourself but remember to restart kernel and run all every test)
Based on previous solutions, this avoids using the %% magic in case you need to put it in the middle of some other code:
from IPython.display import display, Javascript
# can have comments here :)
js_cmd = 'IPython.notebook.kernel.execute(\'nb_name = "\' + IPython.notebook.notebook_name + \'"\')'
display(Javascript(js_cmd))
For python 3, the following based on the answer by #Iguananaut and updated for latest python and possibly multiple servers will work:
import os
import json
try:
from urllib2 import urlopen
except:
from urllib.request import urlopen
import ipykernel
connection_file_path = ipykernel.get_connection_file()
connection_file = os.path.basename(connection_file_path)
kernel_id = connection_file.split('-', 1)[1].split('.')[0]
running_servers = !jupyter notebook list
running_servers = [s.split('::')[0].strip() for s in running_servers[1:]]
nb_name = '???'
for serv in running_servers:
uri_parts = serv.split('?')
uri_parts[0] += 'api/sessions'
sessions = json.load(urlopen('?'.join(uri_parts)))
for sess in sessions:
if sess['kernel']['id'] == kernel_id:
nb_name = os.path.basename(sess['notebook']['path'])
break
if nb_name != '???':
break
print (f'[{nb_name}]')
just use ipynbname , which is practical
import ipynbname
nb_fname = ipynbname.name()
nb_path = ipynbname.path()
print(f"{nb_fname=}")
print(f"{nb_path=}")
I found this in https://stackoverflow.com/a/65907473/15497427
My issue is that I can't scrape a website that uses login when it renders the page using Javascript.
I can easily log in using this code:
import requests
from lxml import html
payload ={
"username":"username",
"password":"password"
}
session_requests = requests.session()
result = session_requests.get(login_url)
tree = html.fromstring(result.text)
result = session_requests.post(
login_url,
data = payload,
headers = dict(referer=login_url)
)
Then I can get some values using this code:
result = session_requests.get(agent_url, headers = dict(referer = agent_url ))
tree = html.fromstring(result.content)
needed_info = tree.xpath("//div[#class='col-md-6']/div[#class='table-responsive']/table/tbody/tr[22]/td[2]")[0].text
However, not everything is rendered.
I've also tried to use dryscrape, however, it does not work on Windows.
Selenium is just too heavy for my needs and I'm having issues installing Spynner (probably because it does not support Python 3.6?)
What would you recommend?
I just went and did it using selenium. Everything else was just too much of a hassle for this little project.
I want to provide the app version of my pebble app on its splashscreen. But how can i access it?
Is there a way to access information from the appinfo.json on the watch or in JS? I need at least the version string.
The easiest way to get your app version into the C code is to modify the wscript to generate a header file containing it as part of the build process.
User pedrolane on the Pebble forums has provided his wscript as an example which you can find here: https://code.google.com/p/pebble-for-gopro/source/browse/wscript?spec=svn8634d98109cb03c30c4dab52e665c4ac548cb20a&r=8634d98109cb03c30c4dab52e665c4ac548cb20a
Here's the contents of the file. The generate_appinfo function reads in appinfo.json, grabs the versionLabel and writes it to generated/appinfo.h.
import json
top = '.'
out = 'build'
def options(ctx):
ctx.load('pebble_sdk')
def configure(ctx):
ctx.load('pebble_sdk')
def build(ctx):
ctx.load('pebble_sdk')
def generate_appinfo(task):
src = task.inputs[0].abspath()
tgt = task.outputs[0].abspath()
json_data=open(src)
data = json.load(json_data)
f = open(tgt,'w')
f.write('#ifndef appinfo_h\n')
f.write('#define appinfo_h\n')
f.write('#define VERSION_LABEL "' + data["versionLabel"] + '"\n')
f.write('#endif\n')
f.close()
ctx(
rule = generate_appinfo,
source = 'appinfo.json',
target = 'generated/appinfo.h',
)
ctx.pbl_program(source=ctx.path.ant_glob(['src/**/*.c','generated/**/*.c']),
includes='generated',
target='pebble-app.elf')
ctx.pbl_bundle(elf='pebble-app.elf',
js=ctx.path.ant_glob('src/js/**/*.js'))
To use the value, include appinfo.h and use VERSION_LABEL.
Another hacky solution without code generation, add the following lines in your main.c :
#include "pebble_app_info.h"
extern const PebbleAppInfo __pbl_app_info;
Then you can get the version of your app like this :
__pbl_app_info.app_version.major
__pbl_app_info.app_version.minor