Binary Tree code - Cannot read property 'data' of undefined - javascript

class Node {
constructor(data, left, right) {
this.data = data;
this.left = left;
this.right = right;
}
}
class BST {
constructor() {
this.root = null
}
add(data) {
const node = this.root
if (node === null) {
this.root = new Node(data)
return
} else {
const searchTree = function (node) {
if (data < node.data) {
if (node.left === null) {
node.left = new Node(data)
return
} else if (node.left !== null) {
return searchTree(node.left)
}
} else if (data > node.data) {
if (node.right === null) {
node.right = new Node(data)
return
} else if (node.right !== null) {
return searchTree(node.right)
}
} else {
return null
}
}
return searchTree(node)
}
}
levelOrder() {
const arr = [];
const queue = [];
let node = this.root;
queue.push(node);
while(queue.length) {
node = queue.shift();
arr.push(node);
if(node.left !== null) queue.push(node.left);
if(node.rigth !== null) queue.push(node.right);
}
}
}
const tree = new BST()
tree.add(1)
tree.add(2)
tree.add(3)
tree.add(4)
tree.add(5)
console.log(tree)
Error I keep getting
if (data < node.data) {
^
TypeError: Cannot read property 'data' of undefined
I made sure to double check my code and sometimes it works other times it doesn't....
Can anyone help with this and explain thinks I'm not understanding and what I need to look into.

The issue is that the node.left and node.right are undefined since you're not assigning them any values when creating a new node but you're checking them for strict equality with null like
node.left !== null
You just simply need to change your Node class to this :
class Node {
constructor(data) {
this.data = data;
this.left = null;
this.right = null;
}
}
OR
Use the Logcial NOT to check for a falsy value since undefined and null both are falsy values like
if( !node.left ){
.
.
}
Hope this helps !

making my comments an answer..
The problem is that node.left or node.right are not strictly null but sometimes undefined. So if you alter your comparisons to use weak equality for null which covers both null and undefined it will work.
Ie change ===null to ==null and !==null to !=null. Else make sure you intitialise left and right to null always, but using weak equality is better.
In fact in javascript (and other languages) you can simply use if (node) and if (node.left) and so on.. since either they will null/undefined or a Node instance (and not zero). So even simpler test.

Related

Recursive Add method for BST using Javascript not working

Below is the implementation of a BST with an insertion function for it. currently, the code wouldn't work; It would just spit out Tree { root: null }
When i tried to debug it, it seems that it successfully adds the new Node to the correct spot, but once it returns from the function, all that data is lost and it ends up not inserting anything.
here is the code:
class Node {
constructor(value) {
this.value = value
this.left = null;
this.right = null;
}
}
class Tree {
constructor() {
this.root = null
}
insert(value) {
const insertHelper = (value, node) => {
if (node === null) {
node = new Node(value)
return null
} else if (node.value === node.value) {
console.log("Value exists.")
return null;
} else if (node.value < node.value) {
return this.insertHelper(node, node.right)
} else {
return this.insertHelper(node, node.left)
}
}
return insertHelper(value, this.root)
}
}
var tree = new Tree;
tree.insert(10)
tree.insert(5)
console.log(tree);
Several issues:
this.root is never modified. Function arguments are passed by value, so if you pass this.root as argument, and the function assigns a new value to the corresponding parameter variable node, this will not affect this.root. The solution is to let the helper function return the new value of the node that is passed as argument, so you can assign it back to the root (or other node).
At several places you compare node.value with node.value. That is a mistake. The comparison should involve value.
The recursive calls pass node as first argument, while the function expects the value as first argument.
Here is the corrected code:
class Node {
constructor(value) {
this.value = value;
this.left = null;
this.right = null;
}
}
class Tree {
constructor() {
this.root = null;
}
insert(value) {
const insertHelper = (value, node) => {
if (node === null) {
node = new Node(value);
} else if (node.value === value) {
console.log("Value exists.");
} else if (node.value < value) {
node.right = insertHelper(value, node.right);
} else {
node.left = insertHelper(value, node.left);
}
return node;
}
this.root = insertHelper(value, this.root);
}
}
var tree = new Tree;
tree.insert(10);
tree.insert(5);
console.log(tree);
NB: use semi-colons explicitly. Relying on the automatic semi-colon insertion is asking for trouble. One day it will hit you.

JavaScript; validateBinaryTree function gives value error on node

A coding challenge in which we are to write a function that determines if a binary tree is valid. The tree is simply a collection of BinaryTreeNodes that are manually linked together. The validateBinaryTree function should return false if any values on the left subtree are greater than the root value or false if any values on the right subtree are less, and true otherwise.
Here is the BinaryTreeNode class:
class BinaryTreeNode {
constructor(value) {
this.value = value;
this.left = null;
this.right = null;
}
insertLeft(value) {
this.left = new BinaryTreeNode(value);
return this.left;
}
insertRight(value) {
this.right = new BinaryTreeNode(value);
return this.right;
}
depth_first_print() {
console.log(this.value);
if (this.left) {
this.left.depth_first_print();
}
if (this.right) {
this.right.depth_first_print();
}
}
}
Here is the validateBinaryTree function:
const validateBinaryTree = (rootNode) => {
const rootValue = rootNode.value;
let isValid = true;
const validateLeft = (node) => {
if (node.value > rootValue) isValid = false;
if (node.left) {
validateLeft(node.left);
}
if (node.right) {
validateLeft(node.right);
}
}
const validateRight = (node) => {
if (node.value < rootValue) isValid = false;
if (node.left) {
validateRight(node.left);
}
if (node.right) {
validateRight(node.right);
}
}
validateLeft(rootNode.left);
validateRight(rootNode.right);
return isValid;
}
//Build an invalid binary tree which will look like this:
// 10
// /
// 50
const tree = new BinaryTreeNode(10);
tree.insertLeft(50);
The following function call should print false to the console:
console.log(validateBinaryTree(tree));
But instead I get the following error:
if (node.value < rootValue) isValid = false;
^
TypeError: Cannot read property 'value' of null
Your initial code fails because you try to invoke validateRight on rootNode.right, which is null. That's why it's actually better to place that check (against node === null case) inside validator itself.
Also I'd simplify this code by passing two separate functions inside - one for the left branch, another for the right - closured upon rootNode value. For example:
const validateBinaryTree = (rootNode) => {
const forLeft = val => val < rootNode.value;
const forRight = val => val > rootNode.value;
const validateBranch = (node, branchComparator) => {
return node === null ||
branchComparator(node.value) &&
validateBranch(node.left, branchComparator) &&
validateBranch(node.right, branchComparator);
}
return validateBranch(rootNode.left, forLeft) && validateBranch(rootNode.right, forRight);
}
This version also has a (slight) benefit of immediately stopping the check whenever failing node has been found (because of short-circuit nature of && operator in JS).

Remove operation on binary search tree with only 1 node (the root)

Started writing the removal function for an unbalanced BST structure. Manually running some tests for the first case (node has no children). Decided to run it on a tree of size 1 (just the root), and for some reason it does not seem to be reassigning the root to null the way I'm expecting it to on line 3 of this statement:
return direction ?
parent[direction] :
node = null;
Then when I run inOrderTraversal on the single node tree, which should just console.log each node, and return undefined for a null tree (what I'm expecting) it simply prints the 55 as it does before the removal.
It seems to be working for all other cases where the node to remove has no children.
Here's the fiddle: https://jsfiddle.net/uvdrmwh0/6/
And the code:
"use strict";
function Node(value, left = null, right = null) {
return {
value,
left,
right
};
}
function insert(x, root) {
let currNode = root;
while (currNode) {
if (x < currNode.value) {
if (currNode.left) {
currNode = currNode.left;
} else {
currNode.left = Node(x);
return;
}
} else if (x > currNode.value) {
if (currNode.right) {
currNode = currNode.right;
} else {
currNode.right = Node(x);
return;
}
} else if (x === currNode.value) {
throw new Error("cannot insert node with the same value as an existing node");
} else {
throw new Error("undefined behavior in insert");
}
}
throw new Error("failed to insert");
}
function remove(x, node, parent = null, direction = null) {
if (node === null) return;
if (node.value === x) {
if (!node.left && !node.right) {
return direction ?
parent[direction] = null :
node = null;
} else if (node.left && !node.right) {
//TODO
}
//TODO
}
direction = x < node.value ? "left" : "right";
remove(x, node[direction], node, direction);
}
function inOrderTraversal(node) {
if (node === null) return;
inOrderTraversal(node.left);
console.log(node.value);
inOrderTraversal(node.right);
}
function BinarySearchTree(seed) {
if (!Array.isArray(seed)) {
throw new Error("BinarySearchTree must be seeded with an array");
}
let root = Node(seed[0]);
seed.slice(1).forEach(x => {
insert(x, root);
});
return root;
}
let bst = BinarySearchTree([55]);
inOrderTraversal(bst);
console.log("---------after removal---------");
remove(55, bst);
inOrderTraversal(bst);
Update:
I've noticed things like this work:
let x = { a: 1 };
function changeProperty(obj, key, newValue) {
obj[key] = newValue;
}
changeProperty(x, "a", "hello");
console.log(x.a); //prints hello
But this doesn't:
function reassignObject(obj) {
obj = { a: "some new value" };
}
reassignObject(x);
console.log(x.a); //still prints hello
It seems you can reassign properties of an object (pointers within an object) and it will change the outside reference, but reassigning the reference to the object itself doesn't?
The following change should make it work:
console.log("---------after removal---------");
bst = remove(55, bst); //change here
The changes to node happen locally in remove function. So you should set the bst to whatever is received back from remove function.
The important thing to understand here is how does javascript pass the arguments. I hope this helps.

Convert javascript class instance to plain object preserving methods

I want to convert an instance class to plain object, without losing methods and/or inherited properties. So for example:
class Human {
height: number;
weight: number;
constructor() {
this.height = 180;
this.weight = 180;
}
getWeight() { return this.weight; }
// I want this function to convert the child instance
// accordingly
toJSON() {
// ???
return {};
}
}
class Person extends Human {
public name: string;
constructor() {
super();
this.name = 'Doe';
}
public getName() {
return this.name;
}
}
class PersonWorker extends Person {
constructor() {
super();
}
public report() {
console.log('I am Working');
}
public test() {
console.log('something');
}
}
let p = new PersonWorker;
let jsoned = p.toJSON();
jsoned should look like this:
{
// from Human class
height: 180,
weight: 180,
// when called should return this object's value of weight property
getWeight: function() {return this.weight},
// from Person class
name: 'Doe'
getName(): function() {return this.name},
// and from PersonWorker class
report: function() { console.log('I am Working'); },
test: function() { console.log('something'); }
}
Is this possible to achieve, and if so, how?
In case you're wondering, I need this because I am using a framework that, unfortunately, accepts as input only an object, whereas I am trying to use TypeScript and class inheritance.
Also, I am doing the above conversion once so performance isn't an issue to consider.
The solutions consisting of iterating through object properties will not work if the compiler's target option is set to es6. On es5, the existing implementations by iterating through object properties (using Object.keys(instance)) will work.
So far, I have this implementation:
toJSON(proto?: any) {
// ???
let jsoned: any = {};
let toConvert = <any>proto || this;
Object.getOwnPropertyNames(toConvert).forEach((prop) => {
const val = toConvert[prop];
// don't include those
if (prop === 'toJSON' || prop === 'constructor') {
return;
}
if (typeof val === 'function') {
jsoned[prop] = val.bind(this);
return;
}
jsoned[prop] = val;
const proto = Object.getPrototypeOf(toConvert);
if (proto !== null) {
Object.keys(this.toJSON(proto)).forEach(key => {
if (!!jsoned[key] || key === 'constructor' || key === 'toJSON') return;
if (typeof proto[key] === 'function') {
jsoned[key] = proto[key].bind(this);
return;
}
jsoned[key] = proto[key];
});
}
});
return jsoned;
}
But this is still not working. The resulted object includes only all the properties from all classes but only methods from PersonWorker.
What am I missing here?
Lots of answers already, but this is the simplest yet by using the spread syntax and de-structuring the object:
const {...object} = classInstance
This is what's working for me
const classToObject = theClass => {
const originalClass = theClass || {}
const keys = Object.getOwnPropertyNames(Object.getPrototypeOf(originalClass))
return keys.reduce((classAsObj, key) => {
classAsObj[key] = originalClass[key]
return classAsObj
}, {})
}
Ok, so the implementation in my OP was wrong, and the mistake was simply stupid.
The correct implementation when using es6 is:
toJSON(proto) {
let jsoned = {};
let toConvert = proto || this;
Object.getOwnPropertyNames(toConvert).forEach((prop) => {
const val = toConvert[prop];
// don't include those
if (prop === 'toJSON' || prop === 'constructor') {
return;
}
if (typeof val === 'function') {
jsoned[prop] = val.bind(jsoned);
return;
}
jsoned[prop] = val;
});
const inherited = Object.getPrototypeOf(toConvert);
if (inherited !== null) {
Object.keys(this.toJSON(inherited)).forEach(key => {
if (!!jsoned[key] || key === 'constructor' || key === 'toJSON')
return;
if (typeof inherited[key] === 'function') {
jsoned[key] = inherited[key].bind(jsoned);
return;
}
jsoned[key] = inherited[key];
});
}
return jsoned;
}
Here is the implementation for the toJSON() method. We are copying over the properties & methods from the current instance to a new object and excluding the unwanted methods i.e. toJSON and constructor.
toJSON() {
var jsonedObject = {};
for (var x in this) {
if (x === "toJSON" || x === "constructor") {
continue;
}
jsonedObject[x] = this[x];
}
return jsonedObject;
}
I have tested the object returned by toJSON() in Chrome and I see the object behaving the same way as you are expecting.
I'm riffing on Alex Cory's solution a lot, but this is what I came up with. It expects to be assigned to a class as a Function with a corresponding bind on this.
const toObject = function() {
const original = this || {};
const keys = Object.keys(this);
return keys.reduce((classAsObj, key) => {
if (typeof original[key] === 'object' && original[key].hasOwnProperty('toObject') )
classAsObj[key] = original[key].toObject();
else if (typeof original[key] === 'object' && original[key].hasOwnProperty('length')) {
classAsObj[key] = [];
for (var i = 0; i < original[key].length; i++) {
if (typeof original[key][i] === 'object' && original[key][i].hasOwnProperty('toObject')) {
classAsObj[key].push(original[key][i].toObject());
} else {
classAsObj[key].push(original[key][i]);
}
}
}
else if (typeof original[key] === 'function') { } //do nothing
else
classAsObj[key] = original[key];
return classAsObj;
}, {})
}
then if you're using TypeScript you can put this interface on any class that should be converted to an object:
export interface ToObject {
toObject: Function;
}
and then in your classes, don't forget to bind this
class TestClass implements ToObject {
toObject = toObject.bind(this);
}
This solution will lose methods, but it is a very simple solution to convert a class instance to an object.
obj = JSON.parse(JSON.stringify(classInstance))
using Lodash
This method isn't recursive.
toPlainObject() {
return _.pickBy(this, item => {
return (
!item ||
_.isString(item) ||
_.isArray(item) ||
_.isNumber(item) ||
_.isPlainObject(item)
);
});
}

Is there a javascript serializer for JSON.Net?

I am using Newtonsoft JSON.Net to deserialize an object with PreserveReferencesHandling enabled. jQuery does not support relinking references based on the $ref and $id syntax JSON.Net uses (I don't know if jQuery supports this functionality in any capacity).
I tried using Douglas Crockford's cycle.js but that does not seem to work with my objects, the returned object is identical to the object which got passed in.
I am not incredibly familiar with JSON.Net, but I cannot seem to find any javascript libraries which would serialize (or parse) the JSON their .NET component outputs.
How can I accomplish putting back together object references?
I was looking for a solution to this problem as well, and ended up hacking Douglas Crockford's JSON.retrocycle function. His function does not work for the $ref=some number, but it looks for something like an xpath.
This is my quick and dirty version - don't use this as is - I'm not doing any cleanup, and it probably should be a plugin, but it does the job and is good enough to get going:
function retrocycle(o) {
var self = this;
self.identifiers = [];
self.refs = [];
self.rez = function (value) {
// The rez function walks recursively through the object looking for $ref
// properties. When it finds one that has a value that is a path, then it
// replaces the $ref object with a reference to the value that is found by
// the path.
var i, item, name, path;
if (value && typeof value === 'object') {
if (Object.prototype.toString.apply(value) === '[object Array]') {
for (i = 0; i < value.length; i += 1) {
item = value[i];
if (item && typeof item === 'object') {
path = item.$ref;
if (typeof path === 'string' && path != null) {
//self.refs[parseInt(path)] = {};
value[i] = self.identifiers[parseInt(path)]
} else {
self.identifiers[parseInt(item.$id)] = item;
self.rez(item);
}
}
}
} else {
for (name in value) {
if (typeof value[name] === 'object') {
item = value[name];
if (item) {
path = item.$ref;
if (typeof path === 'string' && path != null) {
//self.refs[parseInt(path)] = {};
value[name] = self.identifiers[parseInt(path)]
} else {
self.identifiers[parseInt(item.$id)] = item;
self.rez(item);
}
}
}
}
}
}
};
self.rez(o);
self.identifiers = [];
}
Use it like this:
$.post("url/function", { ID: params.ID }, function (data) {
retrocycle(data)
// data references should be fixed up now
}, "json");
You would have to write in a double look-up into your js parser. Technically preserving reference handling is to get around circular references, which is to say what would normally cause a stack overflow during parsing.
JSON does not have a native syntax for handling this. Newtonsoft version is a custom implementation, thus parsing the JSON will be a custom implementation.
If you really have to preserve such references, XML may be a better solution. There are some json->xml libraries out there.
Here is one solution for parsing that may be of use, or at least a guide:
https://blogs.oracle.com/sundararajan/entry/a_convention_for_circular_reference
This is my enhanced version of #Dimitri. #Dimitri code sometimes isn't able to rebuild the references. If anyone improves the code, please, tell me.
Regards,
Marco Alves.
if (typeof JSON.retrocycle !== 'function') {
JSON.retrocycle = function retrocycle(o) {
//debugger;
var self = this;
self.identifiers = [];
self.refs = [];
self.buildIdentifiers = function (value) {
//debugger;
if (!value || typeof value !== 'object') {
return;
}
var item;
if (Object.prototype.toString.apply(value) === '[object Array]') {
for (var i = 0; i < value.length; i += 1) {
item = value[i];
if (!item || !item.$id || isNaN(item.$id)) {
if (item) {
self.buildIdentifiers(item);
}
continue;
}
self.identifiers[parseInt(item.$id)] = item;
self.buildIdentifiers(item);
}
return;
}
for (var name in value) {
if (typeof value[name] !== 'object') {
continue;
}
item = value[name];
if (!item || !item.$id || isNaN(item.$id)) {
if (item) {
self.buildIdentifiers(item);
}
continue;
}
self.identifiers[parseInt(item.$id)] = item;
self.buildIdentifiers(item);
}
};
self.rez = function (value) {
// The rez function walks recursively through the object looking for $ref
// properties. When it finds one that has a value that is a path, then it
// replaces the $ref object with a reference to the value that is found by
// the path.
var i, item, name, path;
if (value && typeof value === 'object') {
if (Object.prototype.toString.apply(value) === '[object Array]') {
for (i = 0; i < value.length; i += 1) {
item = value[i];
if (item && typeof item === 'object') {
if (item.$ref)
path = item.$ref;
if (typeof path === 'string' && path != null) {
//self.refs[parseInt(path)] = {};
value[i] = self.identifiers[parseInt(path)];
continue;
}
//self.identifiers[parseInt(item.$id)] = item;
self.rez(item);
}
}
} else {
for (name in value) {
if (typeof value[name] === 'object') {
item = value[name];
if (item) {
path = item.$ref;
if (typeof path === 'string' && path != null) {
//self.refs[parseInt(path)] = {};
value[name] = self.identifiers[parseInt(path)];
continue;
}
//self.identifiers[parseInt(item.$id)] = item;
self.rez(item);
}
}
}
}
}
};
self.buildIdentifiers(o);
self.rez(o);
self.identifiers = []; // Clears the array
};
}

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