Develop Reference

Post AJAX API Javascript SAPUI5 failed

I want to use POST method with AJAX in SAPUI5 javascript but I found an error.
var url = "https://xxxx*xxxx.co.id:8877/TaspenSAP/SimpanDosirPunah";
$.ajax({
type: "POST",
url: url,
data: JSON.stringify({
nomorDosir: "01001961288",
kodeCabang: "A02"
}),
dataType: "json",
async: false,
contentType: 'application/json; charset=utf-8',
success: function(data, textStatus, xhr){
console.log("sukses: " + data + " " + JSON.stringify(xhr));
},
error: function (e,xhr,textStatus,err,data) {
console.log(e);
console.log(xhr);
console.log(textStatus);
console.log(err);
}
});
error:
I already did change code with dataType=text, or data: {nomorDosir: "01001961288", kodeCabang: "A02"} (without stringify), but I not yet find the solution. How to fix this problem?
Thanks.
Bobby

Not sure what your use case is but if you are trying to post to an oData service, it might be much easier to use SAPs createEntry method where the URL is the path to the model you want to post to and your JSON are the properties:
var oModel = new sap.ui.model.odata.v2.ODataModel("https://services.odata.org/V2/OData/OData.svc/");
//oModel should use your service uri
var url = "https://xxxx*xxxx.co.id:8877/TaspenSAP/SimpanDosirPunah";
oModel.createEntry(url, {
properties: {
nomorDosir: "01001961288",
kodeCabang: "A02"
}
}, {
method: "POST",
success: function(response) {
alert(JSON.stringify(response));
//do something
},
error: function(error) {
alert(JSON.stringify(error));
}
});
oModel.submitChanges();

What you have is wrong json format, you have:
data: JSON.stringify({nomorDosir: "01001961288", kodeCabang: "A02"}),
Which actually should be:
data: {"nomorDosir": "01001961288", "kodeCabang": "A02"},
Which then you don't need to do a json.stringify on, because it already IS a json format. Hope this will help you out.
Which you could also try is setting a variable outside like this:
var url = "https://xxxx*xxxx.co.id:8877/TaspenSAP/SimpanDosirPunah";
var json = {"nomorDosir": "01001961288", "kodeCabang": "A02"};
$.ajax({
type: "POST",
url: url,
data: json,
dataType: "json",
async: false,
contentType: 'application/json; charset=utf-8',
success: function(data, textStatus, xhr){
console.log("sukses: "+data+" "+JSON.stringify(xhr));
},
error: function (e,xhr,textStatus,err,data) {
console.log(e);
console.log(xhr);
console.log(textStatus);
console.log(err);
}
});

Post request is succeeding according to database but failing according to Ajax block

I am posting to my database (for context using GAE, and Objectify as a DAO) and it posts correctly (and the backend returns a response of 202), however, under the Ajax it is not calling the "success" block (i.e. in the method below even when it post's correctly, it calls alert("error1")). The source code for Ajax says a Post is supposed to call the success block when the status is between 200 and 300. Any ideas why it isn't working? Any help would be great!
function userExist() {
var rootUrl = "http://localhost:8888/api/";
function loginToJSON() {
return JSON.stringify({
"username": $('#username').val(),
"password": $('#password').val()
});
}
//System.out.println(loginToJSON());
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootUrl + 'userLogin',
dataType: "json",
data: loginToJSON(),
success: function(data, status, jqXHR) {
alert("success");
},
error: function(jqXHR, status, errorThrown){
alert("error1");
}
});
}
The relevant java backend is
#POST
public Response login(Login l) {
if (loginService.checkCred(l)) {
return Response.status(202).build();
} else {
return Response.status(403).build();
}
}

Pass array from ajax to python (Tornado)

I have the following AJAX post.
I'm using the framework Tornado and I don't know how to send the information of the bidimensional array 'point' to the server in order to make some operations with the elements of the array, and then send the result back to the client.
$.ajax(
{
type: "POST",
url: "application/json",
data: {point:point},
cache: false,
contentType: false,
processData: false,
success: function (data, textStatus, response)
{
alert(data);
},
statusCode: {
401: function (response, textStatus, errorThrown)
{
alert("Error");
}
}
});
Thank you

In your get handler in tornado you can do either:
data = json.loads(urllib.unquote_plus(self.request.body))
or you can do this:
data = tornado.escape.json_decode(self.request.body)
Both of these will json decode the body of request in tornado

asp.net ashx handler: can't receive response

Hello everyone and thanks for your time.
Here is my javascript:
$('.sender').click(function (e) {
$.ajax({
type: "POST",
url: "fHandler.ashx",
data: { firstName: 'stack', lastName: 'overflow' },
// DO NOT SET CONTENT TYPE to json
// contentType: "application/json; charset=utf-8",
// DataType needs to stay, otherwise the response object
// will be treated as a single string
dataType: "json",
success: function (response) {
alert('success');
},
error: function (response) {
alert('error: ' + response);
console.log('err: '+response);
}
});
});
And here is the code in my .ashx handler:
public void ProcessRequest(HttpContext context)
{
context.Response.AppendHeader("Access-Control-Allow-Origin", "*");//to fix the allow origin problem
context.Response.ContentType = "text/plain";
string json = new StreamReader(context.Request.InputStream).ReadToEnd();
context.Response.Write(json);
}
public bool IsReusable
{
get
{
return false;
}
}
While the click event is working, my Ajaxrequest doesn't seem to get any response as the alert at success doesn't popup. I've debugged using the browser's network console and it return the expected response but it doesn't seem to reach the success function in the JavaScript code. Any insights or suggestions are welcome. Thanks.

In case you are still interested in the answer, try this before doing the request
var data = { firstName: 'stack', lastName: 'overflow' };
var jsonData = JSON.stringify(data);
and change your AJAX request to
$.ajax({
type: "POST",
url: "fHandler.ashx",
data: jsonData,
dataType: 'json',
contentType: 'application/json; charset-utf-8'
})
.done(function (response) {
// do something nice
})
.fail(function (jqXHR, textStatus, errorThrown) {
console.log("request error");
console.log(textStatus);
console.log(errorThrown);
});
Explanation
You are trying to send the plain data object. You must transform it into a Json string using JSON.stringify(object).
Changing the dataType isn't really a solution but a workaround.
Additional Notes
Also, I think you should use .done() and .fail(). See here for further details.

Jquery jsonp response error - Callback was not called

I'm trying to get some information from a different domain, the domain allows only jsonp call - others get rejected. How can I get the content instead of execution? Because I get an error in response. I don't need to execute it, I just need it in my script. In any format (the response is json but js doesn't understand it).
I can't affect on that domain so it's impossible to change something on that side.
Here's my code:
$.ajax({
url: url + '?callback=?',
crossDomain: true,
type: "POST",
data: {key: key},
contentType: "application/json; charset=utf-8;",
async: false,
dataType: 'jsonp',
jsonp: 'callback',
jsonpCallback: 'jsonpCallback',
error: function(xhr, status, error) {
console.log(status + '; ' + error);
}
});
window.jsonpCallback = function(response) {
console.log('callback success');
};

There are a few issues with your $.ajax call.
$.ajax({
url: url + '?callback=?',
// this is not needed for JSONP. What this does, is force a local
// AJAX call to accessed as if it were cross domain
crossDomain: true,
// JSONP can only be GET
type: "POST",
data: {key: key},
// contentType is for the request body, it is incorrect here
contentType: "application/json; charset=utf-8;",
// This does not work with JSONP, nor should you be using it anyway.
// It will lock up the browser
async: false,
dataType: 'jsonp',
// This changes the parameter that jQuery will add to the URL
jsonp: 'callback',
// This overrides the callback value that jQuery will add to the URL
// useful to help with caching
// or if the URL has a hard-coded callback (you need to set jsonp: false)
jsonpCallback: 'jsonpCallback',
error: function(xhr, status, error) {
console.log(status + '; ' + error);
}
});
You should be calling your url like this:
$.ajax({
url: url,
data: {key: key},
dataType: 'jsonp',
success: function(response) {
console.log('callback success');
},
error: function(xhr, status, error) {
console.log(status + '; ' + error);
}
});
JSONP is not JSON. JSONP is actually just adding a script tag to your <head>. The response needs to be a JavaScript file containing a function call with the JSON data as a parameter.
JSONP is something the server needs to support. If the server doesn't respond correctly, you can't use JSONP.
Please read the docs: http://api.jquery.com/jquery.ajax/

var url = "https://status.github.com/api/status.json?callback=apiStatus";
$.ajax({
url: url,
dataType: 'jsonp',
jsonpCallback: 'apiStatus',
success: function (response) {
console.log('callback success: ', response);
},
error: function (xhr, status, error) {
console.log(status + '; ' + error);
}
});
Try this code.
Also try calling this url directly in ur browser and see what it exactly returns, by this way You can understand better what actually happens :).

The jsonpCallback parameter is used for specifying the name of the function in the JSONP response, not the name of the function in your code. You can likely remove this; jQuery will handle this automatically on your behalf.
Instead, you're looking for the success parameter (to retrieve the response data). For example:
$.ajax({
url: url,
crossDomain: true,
type: "POST",
data: {key: key},
contentType: "application/json; charset=utf-8;",
async: false,
dataType: 'jsonp',
success: function(data){
console.log('callback success');
console.log(data);
}
error: function(xhr, status, error) {
console.log(status + '; ' + error);
}
});
You can also likely remove the other JSONP-releated parameters, which were set to jQuery defaults. See jQuery.ajax for more information.