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javascript for loop: issues

i came across this problem: Write a program that uses console.log to print all the numbers from 1 to 100, with two exceptions. For numbers divisible by 3, print “Fizz” instead of the number, and for numbers divisible by 5 (and not 3), print “Buzz” instead. When you have that working, modify your program to print “FizzBuzz” for numbers that are divisible by both 3 and 5 (and still print “Fizz” or “Buzz” for numbers divisible by only one of those).
and i tried solving it with the code below:
for(let i = 1; i <= 100; i++){
if(i % 3 ===0) {
console.log("fizz");
} else if ( i % 5 === 0 ) {
console.log("buzz");
} else if (i % 5 === 0 && i % 3 === 0) {
console.log("fizzbuzz");
}
console.log(i);
}
please can anyone tell me what i did wrong because i am not getting result

In your condition, i = 15 should be returned fizzbuzz but it returns fizz because 15 can be divided by 3 and 5 so you first condition i % 3 === 0 getting true so it returned fizz. if your first condition is i % 3 === 0 && i % 5 === 0 then i = 15 should be return fizzbuzz.
for(let i = 1; i <= 100; i++){
if (i % 5 === 0 && i % 3 === 0) {
console.log("fizzbuzz");
} else if(i % 3 ===0) {
console.log("fizz");
} else if ( i % 5 === 0 ) {
console.log("buzz");
}
console.log(i);
}

How to print the right name in the code below?

for (var i = 1; i <= 50; i++) {
if (i % 15 === 0 || i % 10 === 0) {
console.log("Donkey!");
} else if (i % 2 !== 0 && (i - 1) % 10 === 0) {
console.log("Monkey!");
} else if (i % 7 === 0) {
continue;
} else {
console.log(i);
}
}
emphasized textIf the number is not divisible by 2 and the previous number is divisible by 10, How do I print Monkey!?

This a very random question with no context but has a rather simple solution. Use modulus check if the remainder of the current number divided by 2 is not 0 and check if the remainder of the last number divided by 10 is 0:
function check(n) {
if (n % 2 !== 0 && (n - 1) % 10 === 0) {
console.log('Monkey!');
}
}
check(11)

How to print a value with the same criteria - JavaScript

I am trying to print numbers that are divisible by 3 and 5.
For numbers divisible by 3, print out "Fizz".
For numbers divisible by 5, print out "Buzz".
For numbers divisible by both 3 and 5, print out "FizzBuzz" in
the console. Otherwise, just print out the number.
Tried these codes:
var i;
for(i = 1; i <= 20; i++){
if(i % 3 === 0){
console.log("Fizz");
}else if(i % 5 === 0){
console.log("Buzz");
}else if(i % 3 === 0 && i % 5 === 0){
console.log("FizzBuzz");
}else {
console.log(i);
}
}
But it seems it passing out the 3rd else if...
Is there a better way to do this?

You could move the combined comparsion to top of the comparisons, because if both conditions are true, you need not to check the others.
var i;
for (i = 1; i <= 20; i++) {
if (i % 3 === 0 && i % 5 === 0) { // check first, includes
console.log("FizzBuzz");
} else if (i % 3 === 0) { // this comparison and
console.log("Fizz");
} else if (i % 5 === 0) { // this as well.
console.log("Buzz");
} else {
console.log(i);
}
}

Less code for same results:
for(var i = 1; i <= 20; i++) {
var output = '';
if(i % 3 === 0) output += 'Fizz';
if(i % 5 === 0) output += 'Buzz';
console.log(output.length > 0 ? output : i);
}

A number divisible by two numbers must be divisible by their Least common multiple, which in this case is 15. You also have to move this check up, so that it's considered before the other statements.
for (var i = 1; i <= 20; i++) {
if (i % 15 == 0)
console.log('FizzBuzz');
else if (i % 3 === 0)
console.log("Fizz");
else if (i % 5 === 0)
console.log("Buzz");
else
console.log(i);
}

var i;
for (i = 1; i <= 20; i++) {
if (i % 3 === 0 && i % 5 === 0) {
document.write("FizzBuzz");
} else if (i % 3 === 0) {
document.write("Fizz");
} else if (i % 5 === 0) {
document.write("Buzz");
} else {
document.write(i);
}
}

jQuery for loop every third

Why is it only every third when I change i = 0 to i = 1 but then I don't get all results.
$.getJSON('search.php', {q: query, ajax: 'true'}, function(j){
var options = '';
for (var i = 0; i < j.length; i++) {
if(i % 3 == 0) {
// every third
} else {
}
$("#profile-search-results").html(options);
}
});

I think what are trying to do is to get elements at indexes 3, 6, 9... etc but your condition is executed for first, fifth, eighth... etc elements.
The problem is your loop is starting with 0, so 0%3 will return 0... since the element index in jQuery starts with 0, what you need is elements at indexes 2, 5, 8,... etc. So you should check for reminder 3 == 2
for (var i = 0; i < j.length; i++) {
if (i % 3 == 2) {
// every third
} else {
}

% is modulo operator.
0 % 3 = 0
1 % 3 = 1
2 % 3 = 2
3 % 3 = 0
4 % 3 = 1
5 % 3 = 2
6 % 3 = 0
7 % 3 = 1
...
So what you have is normal.

Problems with Modulo in JavaScript

Doing some practice runs on codecademy and came across the following problem: So the objective is to print "Fizz" if the numbers are divisible by 3. "Buzz" if the numbers are divisible by 5. And "FizzBuzz" if the numbers are divisible by both 3 and 5.
Here is my code, and I thought I had it right, but when I run it they tell me that my code is not 100% accurate. Looking to see any alternatives to this code, or what might be the issue...
Code:
for ( i = 0; i < 21; i++)
{
if (i % 3 == 0 )
{
console.log("Fizz");
}
if (i % 5 == 0)
{
console.log ("Buzz");
}
if ( i % 5 == 0 && i % 3 === 0)
{
console.log("FizzBuzz");
}
else
{
console.log(i);
}
}

You need to use else if to stop from other conditions executing:
for (var i = 1; i <= 20; i++) {
if (i % 5 === 0 && i % 3 === 0) {
console.log("FizzBuzz");
} else if (i % 3 === 0) {
console.log("Fizz");
} else if (i % 5 === 0) {
console.log("Buzz");
} else {
console.log(i);
}
}

It can easily be done in a one liner.
for (i = 1; i <= 20; i++) {
console.log(i%3?(i%5?i:'buzz'):(i%5?'fizz':'fizzbuzz'));
};
For a nice formatting also output i on each iteration:
for (i = 1; i < 21; ++i) {
console.log(i+": "+(i%3?(i%5?i:'buzz'):(i%5?'fizz':'fizzbuzz')));
};