in my CLI users can specify what they want to use:
A user command can look like this:
include=name1,name2,name3
category=name1,name2
category=name1
In another words, a command always consists of 3 parts:
command name: can be just include or category
=: is in every command
name or names of things they want to use, split by ,
How can I test this to get always true but false on everything else.
I am really bad in regex but I tried something like this:
/\category|include=\w/.test(str);
to simply test, at least, the most easy alternative which would be category=name1 but without success.
Can someone help me with this?
You were on the right path. Here's a fixed regex:
/^(category|include)=\w+(,\w+)*$/.test(str);
Note:
the parens around the alternative parts
the + after the \w so that you can have several characters
the optional (,\w+)*
the start and end of string marks (^ and $) in order to check the whole string
You can use this regex for your requorement:
/^(category|include)=(\w+(?:,\w+)*)$/
RegEx Demo
\w+(?:,\w+)*) in the value part after = will allow 1 or more of comma separated words.
I want to match only parent domain name from an email address, which might or might not have a subdomain.
So far I have tried this:
new RegExp(/.+#(:?.+\..+)/);
The results:
Input: abc#subdomain.maindomain.com
Output: ["abc#subdomain.domain.com", "subdomain.maindomain.com"]
Input: abc#maindomain.com
Output: ["abc#maindomain.com", "maindomain.com"]
I am interested in the second match (the group).
My objective is that in both cases, I want the group to match and give me only maindomain.com
Note: before the down vote, please note that neither have I been able to use existing answers, nor the question matches existing ones.
One simple regex you can use to get only the last 2 parts of the domain name is
/[^.]+\.[^.]$/
It matches a sequence of non-period characters, followed by period and another sequence of non-periods, all at the end of the string. This regex doesn't ensure that this domain name happens after a "#". If you want to make a regex that also does that, you could use lazy matching with "*?":
/#.*?([^.]+\.[^.])$/
However,I think that trying to do everything at once tends to make the make regexes more complicated and hard to read. In this problem I would prefer to do things in two steps: First check that the email has an "#" in it. Then you get the part after the "#" and pass it to the simple regex, which will extract the domain name.
One advantage of separating things is that some changes are easier. For example, if you want to make sure that your email only has a single "#" in it its very easy to do in a separate step but would be tricky to achieve in the "do everything" regex.
You can use this regex:
/#(?:[^.\s]+\.)*([^.\s]+\.[^.\s]+)$/gm
Use captured group #1 for your result.
It matches # followed by 0 or more instance of non-DOT text and a DOT i.e. (?:[^.\s]+\.)*.
Using ([^.\s]+\.[^.\s]+)$ it is matching and capturing last 2 components separated by a DOT.
RegEx Demo
With the following maindomain should always return the maindomain.com bit of the string.
var pattern = new RegExp(/(?:[\.#])(\w[\w-]*\w\.\w*)$/);
var str = "abc#subdomain.maindomain.com";
var maindomain = str.match(pattern)[1];
http://codepen.io/anon/pen/RRvWkr
EDIT: tweaked to disallow domains starting with a hyphen i.e - '-yahoo.com'
I have a website structure like this:
/docs/one_of_the_resources/one-of-the-resources.html
/docs/a_complete_different_resource/a-complete-different-resource.html
I want to get rid of all sub-folders in the url and get this:
/one-of-the-resources.html
/a-complete-different-resource.html
Sub-folders should not be affected:
/docs/one_of_the_resources/assets/*
The folder name is always the same as the html file just dashes are swapped with underline and of course there is no suffix.
I'm using grunt-contrib-rewrite and grunt-connect.
Can't wrap my head around it. Is this even possible?
You can use a negated character class
/\/[^/]+$/
[^/]+ Matches anything other than a /. The quantifier + ensures one or more characters.
$ Anchors the regex at the end of the string.
Regex Demo
Example
string = "/docs/one_of_the_resources/one-of-the-resources.html";
console.log(string.match(/\/[^/]+$/)[0]);
// => one-of-the-resources.html
I think I don't really get RegEx stuff, so I need help matching the following simple pattern:
SOME_TEXT _Syn: SYN_TEXT _Ant: ANT_TEXT
quotes are decorative, X_TEXT is any text (that does not contain _Syn: or _Ant: that are special abbreviation), _Syn or _Ant parts are optional
I need to get SOME_TEXT, SYN_TEXT and ANT_TEXT in array
So for example if _Syn part not present (input is SOME_TEXT _Ant: ANT_TEXT) result should be [SOME_TEXT, '', ANT_TEXT]
Tried different approaches with lazy modifiers but fails to implement it.
/(.*?)(?:_Syn:(.*?))?(?:_Ant:(.*?))?$/
The important parts are the ? after the .* which make them reluctant (not greedy) and the $ at the end that forces the match in spite of all of the optional matches.
Use this regex
var n=str.match(/(SOME|SYN|ANT)_TEXT/g);
n would contain an array of matched strings
I have one string, that looks like this:
a[abcdefghi,2,3,jklmnopqr]
The beginning "a" is fixed and non-changing, however the content within the brackets is and can follow a pattern. It will always be an alphabetical string, possibly followed by numbers separate by commas or more strings and/or numbers.
I'd like to be able to break it into chunks of the string and any numbers that follow it until the "]" or another string is met.
Probably best explained through examples and expected ideal results:
a[abcdefghi] -> "abcdefghi"
a[abcdefghi,2] -> "abcdefghi,2"
a[abcdefghi,2,3,jklmnopqr] -> "abcdefghi,2,3" and "jklmnopqr"
a[abcdefghi,2,3,jklmnopqr,stuvwxyz] -> "abcdefghi,2,3" and "jklmnopqr" and "stuvwxyz"
a[abcdefghi,2,3,jklmnopqr,1,9,stuvwxyz] -> "abcdefghi,2,3" and "jklmnopqr,1,9" and "stuvwxyz"
a[abcdefghi,1,jklmnopqr,2,stuvwxyz,3,4] -> "abcdefghi,1" and "jklmnopqr,2" and "stuvwxyz,3,4"
Ideally a malformed string would be partially caught (but this is a nice extra):
a[2,3,jklmnopqr,1,9,stuvwxyz] -> "jklmnopqr,1,9" and "stuvwxyz"
I'm using Javascript and I realize a regex won't bring me all the way to the solution I'd like but it could be a big help. The alternative is to do a lot of manually string parsing which I can do but doesn't seem like the best answer.
Advice, tips appreciated.
UPDATE: Yes I did mean alphametcial (A-Za-z) instead of alphanumeric. Edited to reflect that. Thanks for letting me know.
You'd probably want to do this in 2 steps. First, match against:
a\[([^[\]]*)\]
and extract group 1. That'll be the stuff in the square brackets.
Next, repeatedly match against:
[a-z]+(,[0-9]+)*
That'll match things like "abcdefghi,2,3". After the first match you'll need to see if the next character is a comma and if so skip over it. (BTW: if you really meant alphanumeric rather than alphabetic like your examples, use [a-z0-9]*[a-z][a-z0-9]* instead of [a-z]+.)
Alternatively, split the string on commas and reassemble into your word with number groups.
Why wouldn't a regex bring you all the way to a solution?
The following regex works against the given data, but it makes a few assumptions (at least two alphas followed by comma separated single digits).
([a-z]{2,}(?:,\\d)*)
Example:
re = new RegExp('[a-z]{2,}(?:,\\d)*', 'g')
matches = re.exec("a[abcdefghi,2,3,jklmnopqr,1,9,stuvwxyz]")
Assuming you can easily break out the string between the brackets, something like this might be what you're after:
> re = new RegExp('[a-z]+(?:,\\d)*(?:,?)', 'gi')
> while (match = re.exec("abcdefghi,2,3,jklmnopqr,1,9,stuvwxyz")) { print(match[0]) }
abcdefghi,2,3,
jklmnopqr,1,9,
stuvwxyz
This has the advantage of working partially in your malformed case:
> while (match = re.exec("abcdefghi,2,3,jklmnopqr,1,9,stuvwxyz")) { print(match[0]) }
jklmnopqr,1,9,
stuvwxy
The first character class [a-z] can be modified if you meant for it to be truly alphanumeric.