Let me try and say this in a way that doesnt get anyone angry or confused.
I have a value that I am outputting into a table.
The value is populated by mysql and php.
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<table>";
echo "<tr>";
echo "<td id='countryDbId'>".$row['country']."</td>";
echo "</tr>";
echo "</table>";
}
$conn->close();
}
?>
Then I try to read all the values that were output with javascript.
<script>
var country = document.getElementById("pp").innerHTML;
console.log(country);
</script>
The output is only the first value even though there are over 100 values in that column.
Any help would be appreciated.
Related
I am trying to make a SQL server table display pivoted in HTML using PHP.
The columns of the HTML table would be the content of the "CONCEPT" column of the SQL table and the content of the HTML columns would be the result of the "DATA" column of the SQL.
Not all records have the same number of "columns" that is, for example the serial number 12345 has the RAM column but the serial number 67890 does not, so the HTML table cell should appear as blank.
This is the tab delimited file: https://pastebin.com/sFJEHJLm
All the concepts of each article have a record with the same value as "LINE", but I don't know how to take advantage of this data to make the painting of the table.
I have tried to load each of the SQL columns in different PHP arrays and then cycle through the array by painting the HTML table but, at the moment a serial number that has a column arrives, the relationship of the results in the HTML table is lost With the correct column.
if ($_REQUEST['accion'] == "abrir_auditoria") {
$array_titulos = array();
$Total = 0;
$Actual = 0;
try
{
$sql = "SELECT * FROM AUDITORIAS_LIN WHERE AUDITORIA = '" . $_REQUEST['id'] . "'";
$q = $pdo->query($sql);
$q->setFetchMode(PDO::FETCH_ASSOC);
while ($r = $q->fetch()):
if (!in_array(htmlspecialchars($r['CONCEPTO']), $array_titulos))
{
array_push($array_titulos, htmlspecialchars($r['CONCEPTO']));
}
endwhile;
echo "<table border=1>";
echo "<tr>";
foreach ($array_titulos as $titulo)
{
echo "<th>$titulo</th>";
}
echo "</tr>";
echo "<tr>";
$q = $pdo->query($sql);
$q->setFetchMode(PDO::FETCH_ASSOC);
$Total = key(array_slice($array_titulos, -1, 1, true));
while ($r = $q->fetch()):
if ($Total != $Actual)
{
echo "<td>" . htmlspecialchars($r['DATO']) . "</td>";
$Actual++;
} else {
echo "</tr><tr>";
echo "<td>" . htmlspecialchars($r['DATO']) . "</td>";
$Actual = 0;
}
endwhile;
echo "</tr>";
echo "</table>";
}
catch(PDOException $pe)
{
die("database connect error：". $pe->getMessage());
}
}
I am trying to update a MySQL database with checkboxes and PHP. I have read a lot of code examples online and read many questions on here but I seem to be stuck at the last hurdle.
My code first queries MySQL to bring back a list of users and then a checkbox (which is either 0 or 1 in MySQL) next to each one, indicating whether or not the user is completed.
What I am wanting to do is when the checkbox is checked, for that to update the MySQL database and update the column with 1, or if it is unchecked, for it to change the column to 2.
Here is my code so far:
HTML Snippet (Checkboxes):
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['Firstname'] . "</td>";
echo "<td>" . $row['Surname'] . "</td>";
echo "<td>" . $row['Department'] . "</td>";
echo "<td>" . $row['RequestedBy'] . "</td>";
echo "<td>" . $row['StartDate'] . "</td>";
echo "<td class='tbl-chk'> <input type='checkbox' name='WSCompleted' value='"; echo $row['ID'] . "'" ; if ($row['WSCompleted']=='1') { echo "checked='checked'";} echo "/></td>";
Here is my jQuery that successfully retrieves the values and IDs and then posts them:
$(document).ready(function(){
$('input[name=WSCompleted]').click(function(){
var wsCompleted = $(this).is(':checked') ? 1 : 0;
var wsCompletedID = $(this).attr('value');
$.ajax({
type: "POST",
url: "/usr-handler.php",
data: {id: wsCompletedID, wsCompleted: wsCompleted},
success: function(){
$('div.success').fadeIn();
}
});
return true;
});
});
And finally here is a snippet of my PHP:
$wsCompleted = $_POST['wsCompleted'];
$id = $_POST['wsCompletedID'];
$query = "UPDATE newusers SET WSCompleted = '$wsCompleted' WHERE id = '$id'";
mysqli_query($con, $query) or die(mysqli_error());
mysqli_close($con);
I am setting the value of the checkbox to what is actually the row ID in MySQL, then I can use the checkbox value to select the correct row in MySQL, and update it.
The problem I am having is that currently, how the code is, I get the following response from FireBug:
Unidentified index: WSCompletedID
After looking online it was suggested to change:
$id = $_POST['wsCompletedID'];
To:
$id = (ISSET($_POST['wsCompletedID']));
But doing so clears the error message, but then doesn't actually update the value on MySQL.
If I manually set the $id to something, the update works, but obviously that isn't right as it would only ever update the ID I have chosen it to.
I am completely stumped as to what is causing the problem. I have tried finding out online but cannot get anywhere with it.
Any help is greatly appreciated.
Thank you
You are loading data here in your javascript AJAX code
data: {id: wsCompletedID, wsCompleted: wsCompleted},
This will create the following $_POST array
id => whatever was in wsCompletedID
wsCompleted => whatever was in wsCompleted
So your PHP code should be looking for $_POST['id'] and $_POST['wsCompleted'] as these are the names you have given in your data:...
$wsCompleted = $_POST['wsCompleted'];
$id = $_POST['id'];
$query = "UPDATE newusers SET WSCompleted = '$wsCompleted' WHERE id = '$id'";
mysqli_query($con, $query) or die(mysqli_error());
mysqli_close($con);
HOWEVER: Your script is at risk of SQL Injection Attack
Have a look at what happened to Little Bobby Tables Even
if you are escaping inputs, its not safe!
Use prepared statement and parameterized statements
I have a php function which displays all the data in my mysql table and allows the user to delete data not needed. I managed to get the data to show in a table, get the delete button to ask for confirmation using javascript, but when i try to get the value in the 2nd cell of the table with the query result (the name) and display it on the confirmation tab, it says undefined. Why is that happening? From what i understand, document.getElementById("myText").value where myText is the id of the cell, should return the value in the cell, correct? Also, how would i call and send that value to another php file that has the delete query?
<?php
$row = mysqli_fetch_array($result);
echo "<table>";
echo "<tr class='header'><td class='header'>Delete</td>";
echo "<td class='header'>Added</td>";
echo "<td class='header'>Name</td>";
echo "<td class='header'>Genre</td>";
echo "<td class='header'>Developer</td>";
echo "<td class='header'>Rating</td></tr>";
?>
<script type="text/javascript">
function ConfirmDelete(){
var name = document.getElementById("name").value;
if (confirm("Delete" +name+"?")){
//send the value and call the php
}
}
</script>
<?php
for ($x=0; $row; $x++) {
echo "<tr><td><input type='button' onclick='ConfirmDelete()' name='deleteGame' value='DELETE'></td><td>$row[Added]</td><td id='name'>$row[Name]</td><td>$row[Genre]</td><td>$row[Developer]</td><td align='right'>$row[Rating]</td></tr>";
$row = mysqli_fetch_array($result);
}
?>
</table>
The question might not really be clear because I could not think of something that could suit my problem, anyway, I am importing some mysql values using php and creating a html table using javascript, however I am having problems with the PHP as well as Javascript part, Also if anyone could tell me how I could just import values from MYSQL database and make a html table with it (That's basically what I am trying to do)
1.) PHP is not importing values from MYSQL correctly
2.) On console it says: "Uncaught SyntaxError: Unexpected token ILLEGAL"
The following is my code,
<?php
$con = mysqli_connect("localhost","root","","human_information");
$result = mysqli_query($con,"SELECT * FROM basic_human_info");
$rows = mysqli_num_rows($result);
$columns = mysqli_num_fields($result);
?>
<body>
<script type="text/javascript">
function createTable(){
var tBody = document.getElementsByTagName("body")[0];
var table = document.createElement("table");
table.style.border=1;
table.style.width='50%';
table.setAttribute('border',1);
var rows = "<?php echo $rows; ?>";
var columns = "<?php echo $columns ?>";
for(var i=0;i<columns;i++){
var tr = document.createElement("tr");
for(var j=0;j<rows;j++){
var td = document.createElement("td");
td.appendChild(document.createTextNode("
<?php
$sql = mysqli_query($con,"SELECT 'First Name' FROM basic_human_info");
echo mysqli_fetch_assoc($sql);
?>
"));
tr.appendChild(td);
}
table.appendChild(tr);
}
tBody.appendChild(table);
}
createTable();
</script>
</body>
You are outputting an array with echo (echo mysqli_fetch_assoc($sql);) which will just print Array in the middle of the Javascript. That leads to the Uncaught SyntaxError.
But the question rather is: Why use Javascript? Try it with HTML first until you get the PHP right, then do what ever you are planning to do with Javascript.
Like this you can try in php directly
while ($row = mysqli_fetch_array($stmt)) {
echo "<tr>";
echo "<td>" . $row["aid"] . "</td>";
echo "<td>" . $row["aname"] . "</td>";
echo "</tr>";
}
How can I collect the data on the row from the table that I select and use it in the result?
Here is the javascript I am using to show the data entry screen, once the function has been called by selecting the row. Now I just need to design a form in PHP that will include (1) some of the data from the row selected and (2) some new data that will be collected.
Here is the Javascript to select the row and call the data entry form
$(document).ready(function () {
$("tr").live('click',function(){
$.post('data_entry_form.php', function(data) {
$('#section2').html(data);
});
});
});
Here is the PHP Script
<?php
require_once "config.php";
$dbh = new PDO($dsn, $dbuser, $dbpass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$result = $dbh->query("SELECT aif_id, fee_source_id, company_name_per_sedar, document_filing_date FROM a_aif ORDER BY aif_id DESC");
$result->setFetchMode(PDO::FETCH_ASSOC);
echo "<table id=\"all_aifs\">";
echo "<tr>";
echo "<th><b>Document ID</b></th>";
echo "<th><b>Pubco Name</b></th>";
echo "<th><b>Filing Date</b></th>";
echo "<th><b>PDF</b></th>";
echo "</tr>";
foreach($result as $index => $row) {
echo "<tr>";
echo "<td>$row[fee_source_id]</td>";
echo "<td>$row[company_name_per_sedar]</td>";
echo "<td>$row[document_filing_date]</td>";
echo "<td>Placeholder</td>";
echo "</tr>";
}
echo "</table>";
echo "<br>";
$dbh = NULL;
?>
The "Correct" answer to this problem is NOT to read from the DOM. Never a good idea. I suggest you pass the record id to the ajax call and have the ajax call return an already-populated form.
//PHP
//place the data attribute in the tr
echo "<tr data-recordId='".$row['id']."'>";
//JS
$(document).ready(function () {
$("tr").live('click',function(){
//Get the ID from the row clicked
var id = $(this).data('recordId');
//short-hand
$('#section2').load('data_entry_form.php?id='+id);
});
});
Then your ajax page would just read $_REQUEST['id'] to get the id of the form being edited.
//Ajax side PHP
$id = (int)$_REQUEST['id'];
//Fetch data and use it to pre-populate form item
You would pre-populate your inputs like this
<input type="text" value="<?php echo $row['value']; ?>" />
or
echo '<input type="text" value="'.$row['value'].'" />';
NOTE: If your values contain quotes, you will want to replace them with the code "
echo '<input type="text" value="'.str_replace('"', '"', $row['value']).'" />';
Within the event handler, this and $(this) refer to your selected row:
$("tr").live('click',function(){
// this.cells[1] is the cell that contains Pubco Name
// You can also use $(this).children("td")[1]
...
});