Develop Reference

Wikipedia API. File not found Error

I'm trying to make a wikipedia search bar. The idea is to send a new AJAX request every time search input is changed. I'm using https://www.mediawiki.org/wiki/API:Search_and_discovery as a guideline.
var search = $('#search');
search.keyup(function() {
if (search.val() === '') {
result.html('');
}
$.ajax({
url: '//en.wikipedia.org/w/api.php',
data: {
action: 'query',
list: 'search',
format: 'json',
srsearch: search.val()
},
dataType: 'jsonp',
success: function(response) {
console.log("success!");
}
});
});
However, success function is not even triggered.
On any keypress the error I get is this ("d" pressed):
jquery-2.1.1.min.js:4 GET file://en.wikipedia.org/w/api.php?>callback=jQuery21107844703783826772_1484403407494&action=query&list=search&srse>arch=d&format=json&_=1484403407495 net::ERR_FILE_NOT_FOUND
Thank you in advance for any help or guidance!

Well, you're probably trying to do a AJAX request without a local server (opening your file directly in the browser).
First of all, your url options starts with //en... (without the protocol). It indicates that it'll construct your full url using the same protocol you're using. In this case: file://. That's because your browser is trying to reach file://en.wikipedia.org/....
So, you can set your url to https://en.wikipedia.org/w/api.php to make it work.
Just replace:
url: '//en.wikipedia.org/w/api.php',
with:
url: 'https://en.wikipedia.org/w/api.php',

Looks like you're running it from a simple html file located in your filesystem, in other words not running it from a web server (even local).
Try calling the api with
url: 'https://en.wikipedia.org/w/api.php'
or run the file from a web server (can be a local one).

Using the Data-uri-to-img-url service with jquery jsonp not working

I'm trying to use this to get image URL's http://aminariana.github.io/data-uri-to-img-url/ for sharing on facebook.
I just can't work out how to make the post request using jquery:
# Make a POST request with param 'image[data_uri]' set to the above DataURI input.
# This could be from an HTML form with a textarea, or programmatically using an AJAX POST request.
I have setup a JS Fiddle that creates an image in canvas, converts the image to the datauri http://jsfiddle.net/7asutg7c/ it's just the last part of using jsonp in jquery to send the parameter and get the URL back that I am completely lost on.
var url = 'http://data-uri-to-img-url.herokuapp.com/images.json';.
$.ajax({
type: 'POST',
url: url,
async: false,
// data: dataURL,
contentType: "application/json",
dataType: 'jsonp',
success: function(json) {
console.log(json.url);
},
error: function(e) {
console.log(e.message);
}
});
My initial thought was to set data to the dataURI but I get "Failed to load resource: the server responded with a status of 414 (Request-URI Too Large)" ... so I am a little stuck about how I should be sending that dataURI.
Any help would be greatly appreciated.

Create a JavaScript object like this,
var myData = {
image: {
data_uri: your_data_uri_here
}
};
and then pass that as value of the data parameter of the $.ajax call.

How to get a json response from yaler

I create an account with yaler, to comunicate with my arduino yun. It works fine, and i'm able to switch on and off my leds.
Then i created a web page, with a button that calls an ajax function with GET method to yaler (yaler web server accept REST style on the URL)
$.ajax({
url: "http://RELAY_DOMAIN.try.yaler.net/arduino/digital/13/1",
dataType: "json",
success: function(msg){
var jsonStr = msg;
},
error: function(err){
alert(err.responseText);
}
});
This code seem to work fine, infact the led switches off and on, but i expect a json response in success function (msg) like this:
{
"command":"digital",
"pin":13,
"value":1,
"action":"write"
}
But i get an error (error function). I also tried to alert the err.responseText, but it is undefined....
How could i solve the issue? Any suggestions???
Thanks in advance....

If the Web page containing the above Ajax request is served from a different origin, you'll have to work around the same origin policy of your Web browser.
There are two ways to do this (based on http://forum.arduino.cc/index.php?topic=304804):
CORS, i.e. adding the header Access-Control-Allow-Origin: * to the Yun Web service
JSONP, i.e. getting the Yun to serve an additional JS function if requested by the Ajax call with a query parameter ?callback=?
CORS can probably be configured in the OpenWRT part of the Yun, while JSONP could be added to the Brige.ino code (which you seem to be using).

I had the same problem. I used JSONP to solve it. JSONP is JSON with padding. Basically means you send the JSON data with a sort of wrapper.
Instead of just the data you have to send a Java Script function and this is allowed by the internet.
So instead of your response being :
{"command":"digital","pin":13,"value":0,"action":"write"}
It should be:
showResult({command:"analog",pin:13,value:0,action:"write"});
I changed the yunYaler.ino to do this.
So for the html :
var url = 'http://try.yaler.net/realy-domain/analog/13/210';
$.ajax({
type: 'GET',
url: url,
async: false,
jsonpCallback: 'showResult',
contentType: "application/json",
dataType: 'jsonp',
success: function(json) {
console.dir(json.action);
},
error: function(e) {
console.log(e.message);
}
});
};
function showResult(show)
{
var str = "command = "+show.command;// you can do the others the same way.
alert (str);
}
My JSON is wrapped with a showResult() so its made JSONP and its the function I called in the callback.
Hope this helps. If CORS worked for you. Could you please put up how it worked here.

Django ajaxuploader 400 badrequest error

Submitted.html
The JS is also surrounded by a document.ready function
var uploader = new qq.FileUploader({
action: "{% url 'QCOMLTE:imager' %}",
element: $('#file-uploader')[0],
multiple: true,
onComplete: function(id, fileName, responseJSON) {
if(responseJSON.success) {
alert("success!");
} else {
alert("upload failed!");
}
},
onAllComplete: function(uploads) {
// uploads is an array of maps
// the maps look like this: {file: FileObject, response: JSONServerResponse}
alert("All complete!");
},
params: {
'csrf_token': "{{ csrf_token }}",
'csrf_name': 'csrfmiddlewaretoken',
'csrf_xname': 'X-CSRFToken'
}
});
elsewhere in the html body
<div id="file-uploader">
<noscript>
<p>Please enable JavaScript to use file uploader.</p>
</noscript>
</div>
urls.py
urlpatterns = patterns('',
url(r"^Submitted/$", views.HybridDetailView.as_view(), name='Submitted'),
url(r'^(?P<object_type>\w+)/process/$', views.process, name='process'),
url(r'^(?P<object_type>\w+)/$', views.generic_view, name='generic'),
url("$^", views.head, name='head'),
url("uploader", views.upload, name= 'imager'),
)
views.py
#AjaxFileUploader
def upload(request):
response = {'files': []}
script_dir = os.path.dirname(__file__)
# Loop through our files in the files list uploaded
print('request',request)
print(request.FILES)
for item in request.FILES.getlist('files[]'):
file = UploadedFile(item)
with open(script_dir + '/Excel/' + file.name) as destination:
for chunk in file.chunks():
destination.write(chunk)
response['files'].append(file)
print('appended')
return HttpResponse(json.dumps(response), content_type='application/json')
also contains 'ajaxuploader' in the installed apps list
When I try to submit a file through the button it sends the post call but receives a 400 (BAD REQUEST) Error.
It's not even reaching the python from what I can tell, at least not the view code. It seems to form the request URL correctly
http://localhost:8000/QCOMLTE/uploader?qqfile=powered_by.png
And when you go to the URL it sends a message stating that post calls are only allowed.
This is similar to Default django-ajax-uploader with s3 backend gives MalformedXML error
Except that I'm not using any backends, just trying to grab the file/s and save them to a directory.
UPDATE 8/25/14:
Removed the decorator from the view. This results in the error not being sent. After printing the request it becomes evident that the file is being sent to the GET path instead of the FILE path. I don't know how to change this.

After finding this Need a minimal Django file upload example
I preceded to try and imitate it, to find that the FILE and POST requests were actually going through, unlike the ajax/jquery I was using. The JQuery was
$('#uploadform').submit(function (e){
console.log('submitting')
var data = new FormData($('#uploadform').get(0));
$.ajax({
type: 'POST',
url: "{% url 'QCOMLTE:imager' %}",
data: data,
success: function(data){console.log(data)},
error: function(data){console.log(data)},
cache: false,
processData: false,
contentType: false
});
e.preventDefault()
});
except the type was below URL.
I tried changing it to a $.post request and it was trying to post to the wrong URL then...
So I decided to change it back, and this time put type at the top of the ajax call. It then worked... and still does after much testing.

How do I ensure jQuery ajax call does not send a local copy of file?

$.ajax({
type: 'GET',
url: "string.txt",
cache: false,
success: function(str){
alert("Data is: "+ str);
}
});
In this example, string.txt is sent to the cache (\Temporary Internet Files)
How do I ensure that the file is not sent. I do not want copy to be sent.
Only a read from the server. Am I missing an option?
I set cache to false but that does not block it from being sent to client.
For example, ajax POST does not send a local copy.....
Here is some background info to what i am trying to do, but with jQuery.
I am curious as to why the standard ajax post seems to have the desired functionality I am looking for and am unable to do that with jQuery?
Thanks

Or set a no cache header server-side.